AN7522

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ICs for Audio Common Use

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AN7522Dual 3-W BTL audio power amplifier

OverviewAN7522 is an audio power amplifier IC for the stereo

system. In the BTL (balanced transformerless) method,fewer external parts and easier design for applications arerequired.

Features 3-W output (8 ) with supply voltage of 8 V On-chip standby function On-chip volume function

Applications Televisions, audio equipment, personal computers, and

active speakers

Block Diagram

HSIP012-P-0000A

Unit: mm7.7 0.3

(12.5)

19.1 0.321.9 0.3

(1.2)

( 1 0

. 0 )

( 1 0

. 0 ) 2

9 . 6

0

. 3

2 0

. 0 0

. 3

0 . 6

2 8

. 0 0

. 3

2 9

. 7 5

0

. 3 0

3.6

R1.8 0

. 6

( 1 . 2

7 )

( 1

. 2 7 )

( 1

. 3 )

1 2

1

+ 0

. 1 5

0

. 0 5

2 . 5

4

0 . 2

5 1 . 4

5 0

. 1 5

1 . 8

0 0

. 1 5

1 . 2

0

. 1

3 . 5

0

. 3

+ 0

. 1 0

0

. 0 5

1 2 3 4 5 6 7 8 9 1 0 1 1 1 2

V C C

C h . 1 o u

t p u t

C h . 1 o u

t p u t

S t a n

d b y

G N D

( C h . 1 o u

t p u t

)

G N D

( C h . 2 o u

t p u t

)

G N D

C h . 1 i n p u

t

C h . 2 i n p u

t

V o l u m e

C h . 2 o u

t p u t

C h . 2 o u

t p u t

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AN7522 ICs for Audio Common Use

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Parameter Symbol Range Unit

Supply voltage V CC 3.5 to 13.5 V

Parameter Symbol Rating Unit

Supply voltage *2 VCC 14 V

Supply current I CC 2.0 A

Power dissipation *3 PD 1.92 W

Operating ambient temperature *1 Topr 25 to +70 C

Storage temperature *1 Tstg 55 to +150 C

Note) *1: Except for the operating ambient temperature and storage temperature, all ratings are for T a = 25 C.

*2: At no signal.

*3: The power dissipation shown is the value for T a = 70 C.

Pin Descriptions

Absolute Maximum Ratings

Recommended Operating Range

Pin No. Descriptions

7 Ground (input)

8 Ch.2 input

9 Volume (max. volume if this pin is open.)10 Ch.2 output

11 Ground (output ch.2)

12 Ch.2 + output

Pin No. Descriptions

1 Supply voltage

2 Ch.1 + output

3 Ground (output ch.1)4 Ch.1 output

5 Standby (standby state if this pin is open.)

6 Ch.1 input

Electrical Characteristics at V CC = 8.0 V, R L = 8 , f = 1 kHz, T a = 25 C 2C

Parameter Symbol Conditions Min Typ Max Unit

Quiescent circuit current I CQ V IN = 0 mV, Vol. = 0 V 45 100 mA

Standby current I STB V IN = 0 mV, Vol. = 0 V 1 10 A

Output noise voltage * VNO Rg = 10 k , Vol. = 0 V 0.10 0.4 mV[rms]

Voltage gain G V PO = 0.5 W, Vol. = 1.25 V 31 33 35 dB

Total harmonic distortion THD P O = 0.5 W, Vol. = 1.25 V 0.10 0.5 %Maximum output power P O1 THD = 10%, Vol. = 1.25 V 2.4 3.0 W

Ripple rejection ratio * RR R g = 10 k , Vol. = 0 V, 30 50 dBVR = 1 V[rms], f R = 120 Hz

Output offset voltage V OFF Rg = 10 k , Vol. = 0 V 250 0 250 mV

Volume attenuation rate * Att P O = 0.5 W, Vol. = 0 V 70 85 dB

Channel balance 1 CB1 P O = 0.5 W, Vol. = 1.25 V 1 0 1 dB

Channel balance 2 CB2 P O = 0.5 W, Vol. = 0.6 V 3 0 3 dB

Intermediate voltage gain G VM PO = 0.5 W, Vol. = 0.6 V 20.5 23.5 26.5 dB

Channel crosstalk CT P O = 0.5 W, Vol. = 1.25 V 40 55 dB

Note) *: In measuring, the filter for the range of 15 Hz to 30 kHz (12 dB/OCT) is used.

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ICs for Audio Common Use AN7522

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Terminal Equivalent Circuits

Pin No. Pin name Equivalent circuit Voltage

1 V CC 5.0 V

2 Ch.1 + output pin 2.15 V

3 GND 0 V

4 Ch.1 output pin 2.15 V

5 Standby pin 5 V

3

20 k 800

50 200 4

1/2 VCC

VCC

20 k 800

50 200 2

1/2 VCC

VCC

200

30 k

2 k 50 k

33 k 10 k

1/2 V CC

VRF( VCC )

To the constantcurrent circuit

To theshock soundpreventioncircuit

12 k

10 k

5 k

5

VCC

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Terminal Equivalent Circuits (continued)


6 Ch.1 input pin 0 mV to 10 mV

7 GND 0 V

8 Ch.2 input pin 0 mV to 10 mV

9 Volume pin

100 A50 A50 A 30 k

1 k 1 k 500

1 k 6

VCCVREF1 (1.4 V)

7

100 A50 A50 A30 k

1 k 1 k 500

1 k 8

VCCVREF1 (1.4 V)

9

50 A

1 k 12 k

VCC

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Terminal Equivalent Circuits (continued)


10 Ch.2 output pin 2.15 V

11 GND 0 V

12 Ch.2 + output pin 2.15 V

20 k 800

50 200 10

1/2 V CC

VCC

11

20 k 800

50 200 12

1/2 V CC

VCC

Usage Notes Please avoid the short-circuits to V CC , ground, or load short-circuit.

Please connect the cooling fin with the GND potential.

The thermal shutdown circuit operates at about T j = 150 C. However, the thermal shutdown circuit is reset

automatically if the temperature drops.

Please carefully design the heat radiation especially when you take out high power at high V CC .

Please connect only the ground of signal with the signal GND of the amplifier in the previous stage.

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Technical Data P D Ta curves of HSIP012-P-0000A PD T a

2

1

4

3

6

5

8

7

10

9

12

11

13

20C/W heat sink

10C/W heat sink

5C/W heat sink

0 25 150

Ambient temperature Ta (C)

P o w e r d i s s i p a t i o n P D ( m W )

50 7570 100 1250

Independent ICwithout a heat sink R thj-a = 41.7 C/W

Main characteristicsPO VCC ICQ , I STB V CC

0

1

2

3

4

5

6

7

8

0 2 4 6 8 10 12 14

Supply voltage V CC (V)

f = 1 kHzTHD = 10%RL = 8 , 16 400 Hz HPF30 kHz LPFBoth ch. inputRg = 10 k VSTB = 5 VVol. = 1.25 V

O u t p u t p o w e r P O

( W )

Ch.2 (8 )

Ch.1, Ch.2 (16 )Ch.1 (8 )

0

10

20

30

40

50

60

70

0.0

1.0

2.0

3.0

4.0

5.0

6.0

7.0

8.0

9.0

10.0

0 2 4 6 8 10 12 14


RL = 8 Both ch. inputRg = 10 k VSTB = 0 V/5 VVol. = 0 V

S t a n d b y c u r r e n t I S

T B ( A )

ICQ

ISTB Q u i e s c e n t c i r c u i t c u r r e n t I C

Q ( m A )

0.001

0.01

0.1

1

10

1 10 100

100

1 000

Input voltage V IN (mV[rms])

O u t p u t p o w e r P O ( W )

0.01

0.1

1

10

T o t a l h a r m o n i c d i s t o r t i o n T H D ( % )

VCC = 8 Vf = 1 kHzRL = 8 400 Hz HPF30 kHz LPF

Both ch. inputRg = 10 k VSTB = 5 VVol. = 1.25 V

PO (ch.1)

THD (ch.1, 10 kHz)

PO (ch.2)

THD(ch.1, 100 kHz) THD(ch.2, 100 kHz)

THD(ch.1, 1 kHz)

THD (ch.2, 10 kHz)

THD (ch.2, 1 kHz)

VCC = 8 Vf = 1 kHzRL = 8 , 16 400 Hz HPF30 kHz LPF

P o w e r c o n s u m p t i o n P C ( W )

1.0

1.5

2.0

2.5

3.0

3.5

0.0 1.0 4.03.02.0 5.00.0

0.2

0.4

0.6

0.8

1.0

1.2

1.4

1.6

1.8

S u p p l y c u r r e n t I C

C ( A )

0.0

0.5

Output power (1-ch) P O (W)


PC (8 )

PC (16 )

ICC (8 )

ICC (16 )

PO , THD V IN PC , I CC PO

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Technical Data (continued) Main characteristics (continued)

GV , P O f THD f

GV , THD V CC RR V CC

RR V RIPPLE RR f RIPPLE

25

26

27

28

29

30

31

32

33

34

35

10 100 1 000 10 000 100 0000.0

0.2

0.4

0.6

0.8

1.0

1.2

1.4

1.6

1.8

2.0

GV (ch.2)

Frequency f (Hz)

V o l t a g e g a i n G

V ( d B )

O u t p u t p o w e r P O ( W )



GV (ch.1)

GV(ch.2)

GV(ch.1)

0.01

0.1

1

10

10 100 1 000 10 000 100 000

Frequency f (Hz)


VCC = 8 VPO = 0.5 W

RL = 8 400 Hz HPF30 kHz LPF

Both ch. inputRg = 10 k

VSTB = 5 VVol. = 1.25 V

Ch.1

Ch.2

25

26

27

28

29

30

31

32

33

34

35

0 2 4 6 8 10 12 140.0

0.1

0.2

0.3

0.4

0.5

0.6

0.7

0.8

0.9

1.0

GV (ch.1)

GV (ch.2)

THD (ch.1)

THD (ch.2)


V o l t a g e g a i n G

V ( d B )


PO = 0.5 Wf = 1 kHzRL = 8 400 Hz HPF

30 kHz LPFBoth ch. inputRg = 10 k VSTB = 5 VVol. = 1.25 V

0

10

20

30

40

50

60

70

80

0 2 4 6 8 10 12 14

Spply voltage V CC (V)

R i p p l e r e j e c t i o n r a t i o R R ( d B )

RL = 8 30 kHz LPFRg = 10k VSTB = 5 V

Vol. = 0 V/1.25 VVRIPPLE = 0.5 V[rms]f RIPPLE = 120 Hz

Ch.1 (vol.-max.)

Ch.2 (vol.-max.)

Ch.1, Ch.2

10 100 1 000 10 0000

10

20

30

40

50

60

70

80

Power supply ripple voltage V RIPPLE (mV[rms])


Ch.1, Ch.2

Ch.1 (vol.-max.)

Ch.2 (vol.-max.)

VCC = 8 VRL = 8 30 kHz LPFRg = 10 k

VSTB = 5 VVol. = 0 V/1.25 VVRIPPLE = 0.5 V[rms]f RIPPLE = 120 Hz

0

10

20

30

40

50

60

70

80

Power supply ripple frequency f RIPPLE (Hz)


10 100 1 000 10 000

Ch.1

Ch.2

Ch.1 (vol.-max.)

Ch.2 (vol.-max.)

VCC = 8 VRL = 8 R

g = 10 k

VSTB = 5 VVol. = 0 V/1.25 VV

RIPPLE = 0.5 V[rms]

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RR Vol. CT V CC

CT V IN CT f

VNO VCC VNO Rg

Volume voltage Vol. (V)


0

10

20

30

40

50

60

70

80

0.0 0.5 1.0 1.5

Ch.1

Ch.2

VCC = 8 VRL = 8 30 kHz LPFRg = 10 k

VSTB = 5 VVRIPPLE = 0.5 V[rms]f RIPPLE = 120 Hz

0

10

20

30

40

50

60

70

80

90

0 2 4 6 8 10 12 14


C r o s s t a l k C T ( d B )

Ch.1

Ch.2

PO = 0.5 Wf = 1 kHzRL = 8 400 Hz HPF30 kHz LPFRg = 10 k VSTB = 5 VVol. = 1.25 V

10 100 1 0000

10

20

30

40

50

60

70

80

90


C r o s s t a l k C T ( d B )

VCC = 8 Vf = 1 kHzRL = 8 400 Hz HPF30 kHz LPFRg = 10 k VSTB = 5 VVol. = 1.25 V

Ch.2

Ch.1

0

10

20

30

40

50

60

70

80

90

10 100 1 000 10 000 100 000

Frequency f (Hz)

C r o s s

t a l k C T ( d B )

VCC = 8 VPO = 0.5 WRL = 8 Rg = 10 k VSTB = 5 VVol. = 1.25 V

Ch.1

Ch.2

0

100

200

300

400

500

600

700

800

0 2 4 6 8 10 12 14


O u t p u t n o i s e v o l t a g e V

N O

( V [ r m s ] )

Ch.1, Ch.2

Ch.1 (vol.-max.)

Ch.1 (FLAT)Ch.2 (FLAT)

Ch.2 (vol.-max.)

RL = 8 Rg = 10 k Din audio filterVSTB = 5 VVol. = 0 V/1.25 V

10 100 1 000 10 000 100 0000

100

200

300

400

500

600

700

800

Input impedance R g ()


N O

( V [ r m s ] )

Ch.1 (FLAT), Ch.2 (FLAT)

Ch.1, Ch.2

Ch.1 (vol.-max.)

Ch.2 (vol.-max.)

VCC = 8 VRL = 8 Din audio filterVSTB = 5 VVol. = 0 V/1.25 V

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VNO Vol. I CQ V STB

Att V CC Att V IN

Att f Att Vol.

0

200

400

600

800

1 000

1 200

0.0



N O

( V [ r m s ] )

0.2 0.4 0.6 0.8 1.21.0 1.4

Ch.1 (FLAT)Ch.2 (FLAT)

Ch.1, Ch.2

VCC = 8 VRL = 8 Rg = 10 k Din audio filterVSTB = 5 V

0.00

0.01

0.02

0.03

0.04

0.05

0.06

0.07

0.08

0.09

0.10

0 1 2 3 4 5

Standby voltage V STB (V)

Q u i e s c e n t c i r c u i t c u r r e n t I C

Q ( A )

ICQ

VCC = 8 VRL = 8 Rg = 10 k

Vol. = 0 V

PO = 0.5 Wf = 1 kHzRL = 8 400 Hz HPF30 kHz LPFRg = 10 k VSTB = 5 VVol. = 0 V

20 4 6 8 10 12 14


40

50

60

70

80

90

100

V o l u m e a t t e n u a t i o n A t t ( d B )

Ch.1, Ch.2

40

50

60

70

80

90

100

1 10 100 1 000



Ch.1

Ch.2

VCC = 8 Vf = 1 kHzRL = 8 400 Hz HPF30 kHz LPFRg = 10 k VSTB = 5 VVol. = 0 V

50

55

60

65

70

75

80

85

90

95

100

10 100 1 000 10 000 100 000

Frequency f (Hz)


Ch.1, Ch.2

VCC = 8 VPO = 0.5 WRL = 8 Rg = 10 k VSTB = 5 VVol. = 0 V

90

80

70

60

50

40

30

20

10

0


V o l u m e a t

t e n u a t

i o n

A t t ( d B )

0.0 0.2 0.4 0.6 0.8 1.0 1.41.2

Ch.1, Ch.2

VCC = 8 VPO = 0.5 Wf = 1 kHzRL = 8 400 Hz HPF30 kHz LPFRg = 10 k VSTB = 5 V

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Application Circuit Example


THD Vol. G V V IN

0.01

0.1

1

10


Ch.1, Ch.2


0.0 0.2 0.4 0.6 1.00.8 1.2 1.4

VCC = 8 VPO = 0.5 Wf = 1 kHzRL = 8

400 Hz HPF30 kHz LPFRg = 10 k VSTB = 5 V

1

10

100

1 10 100 1 000 10 000


V o

l t a g e g a i n

G V

( d B )

Ch.1, Ch.2



Example of PCB pattern

GND

GND (input)VIN (ch.2)Mute/VolumeVIN (ch.1)Standby

VCC 4 5 6 71 2 3 8 9 10 11 12

Ch.2 out +

Ch.2 out

Ch.1 out +

Ch.1 out

8

Out 2

8

Out 110 F

6 8 k

1 0

k

2 7 0 k

Standby VIN1

470 F

VCC

1.0 F 1.0 F

1 0

k

VIN2 Volume

1 2 3 4 5 6 7 8 9 1 0 1 1 1 2

Documents

AN7522