Allen Aiims Test Paper 27 04 2012 -Paper

(ACADEMIC SESSION 2011-2012)CLASSROOM CONTACT PROGRAMME

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A seat marked with Reg. No. will be alloted to each student. The student should ensure that he/sheoccupies the correct seat only. If any student is found to have occupied the seat of another student,both the students shall be removed from the examination and shall have to accept any other penaltyimposed upon them.

Student can not use log tables and calculators or any other material in the examination hall.

Student must abide by the instructions issued during the examination, by the invigilators or thecentre incharge.

Before attempting the question paper ensure that it contains all the pages and that no question ismissing.

izR;sd fo|kFkhZ dk jftLVªs'ku ua- ds vuqlkj LFkku fu;r gS rFkk os vius fu;r LFkku ij gh cSBsaA ;fn dksbZ fo|kFkhZ fdlh

nwljs fo|kFkhZ ds LFkku ij cSBk ik;k x;k rks nksuksa fo|kfFkZ;ksa dks ijh{kk d{k ls ckgj dj fn;k tk,xk vkSj nksuksa dks dksbZ vU;

tqekZuk Hkh Lohdk;Z gksxkA

fo|kFkhZ ijh{kk d{k esa yksx Vscy]dsYdwysVj ;k fdlh vU;lkexzh dk mi;ksx ugha dj ldrk gSA

ijh{kk ds le; fo|kFkhZ dks ijhoh{kd }kjk fn;s x;s funsZ'kksa dh ikyuk djuk vko';d gSA

iz'u i= gydjus ls igys fo|kFkhZ vk'oLr gks tk, fd blesa lHkh ist layXu gSa vFkok ughaA

izR;sd lgh mÙkjds vad gSa tcfd ,d frgkbZ vad] xyr mÙkj dk ml fo"k;ds dqy vadksa esa ls dedj fy;k tk;sxkA

5. Each correct answer carries 1 marks, while one third mark will be deducted from the total of

individual subject for each incorrect answer.

1

MAJOR TESTDATE : 27 – 04 – 2012ALLEN AIIMS # 01

TARGET : PRE-MEDICAL 2012

LEADER, ACHIEVER & ENTHUSIAST COURSE

Corporate OfficeALLEN CAREER INSTITUTE

“SANKALP”, CP-6, INDRA VIHAR, KOTA-324005PHONE : +91 - 744 - 2436001, Fax : +91-744-2435003

E-mail: [email protected] Website: www.allen.ac.in

Do not open this Test Booklet until you are asked to do so /

(Full Syllabus)

E / H 1/34

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Your Target is to secure Good Rank in Pre-Medical 2012

MAJOR TEST : AIIMS

PRE-MEDICAL : LEADER, ACHIEVER & ENTHUSIAST COURSE

1. In the circuit shown, which of the followingstatements is true –

(1) With S1 closed, V1 = 15 V, V2 = 25V

(2) With S3 closed, V1 = V2 = 25V

(3) With S2 closed, V1 =V2 = 0

(4) With S1 & S3 closed,V1=30V, V2 = 20V

2. Light from a hydrogen discharge tube is incidenton the cathode of a photoelectric cell, the workfunction of the cathode surface is 4.2 eV. In orderto reduce the photo current to zero the voltage ofthe anode relative to the cathode must be made(1) –4.2 V (2) –9.4 V(3) – 17.8 V (4) + 9.4 V

3. The root mean square value of voltage,if an alternating voltage is given bye = e1sinwt + e2coswt is :-

(1) 2 21 2e e

2+

(2) 2 21 2e – e

2

(3) 1 2e e (4) None of these

4. Sixteen beads in a string are placed on a smoothinclined plane of inclination sin–1(1/3) such thatsome of them lie along the incline whereas the resthang over the top of the plane. If acceleration offirst bead is g/2, the arrangement of beads isthat :-

q

(1) 12 hang vertically

(2) 10 lie along inclined plane

(3) 8 lie along inclined plane

(4) 10 hang vertically

1. fp= esa fn;s x;s ifjiFk ds fy;s dkSuls dFku lR; gS –

(1) tc S1 cUn gS, V1 = 15 V, V2 = 25V

(2) tc S3 cUn gS, V1 = V2 = 25V

(3) tc S2 cUn gS, V1 =V2 = 0

(4) tc S1 rFkk S3 cUn gS, V1=30V, V2 = 20V

2. gkbMªkstu foltZu ufydk ls mRlftZr izdk'k] ,d izdk'k

fo|qr lsy ds dSFkksM ij fxjrk gSA lsy ds dSFkksM dk dk;Z

Qyu 4.2 eV gSA izdk'k fo|qr /kkjk dk eku 'kwU; djus

ds fy;s dSFkksM ds lkis{k ,uksM dk foHko gksxk %&(1) –4.2 V (2) –9.4 V

(3) – 17.8 V (4) + 9.4 V

3. ;fn iz R;korh Z foHko e = e1sinwt + e2coswt lsfn;k x;k gS rk s bldk ox Z ek/; ewy eku D;kgksxk :-

(1) 2 21 2e e

2+

(2) 2 21 2e – e

2

(3) 1 2e e (4) buesa ls dksbZ ugha

4. sin–1(1/3) >qdko okys ,d fpdus ur ry ij 16ef.k;ksa dh ,d ekyk bl izdkj j[kh xbZ gS fd buesa lsdqN ef.k;k¡ ur ry ds vuqfn'k fLFkr gS tcfd 'ks"kef.k;k¡ ur ry ds 'kh"kZ ls yVdh gqbZ gSA ;fn igyhef.k dk Roj.k g/2 gS rks ef.k;k¡ bl izdkj O;ofLFkrgS fd :-

q

(1) 12 Å/okZ/kj yVdh gqbZ gS(2) 10 ur ry ds vuqfn'k fLFkr gS(3) 8 ur ry ds vuqfn'k fLFkr gS(4) 10 Å/okZ/kj yVdh gqbZ gS

BEWARE OF NEGATIVE MARKINGHAVE CONTROL ¾® HAVE PATIENCE ¾® HAVE CONFIDENCE Þ 100% SUCCESS

27–04–2012

2/34 E / HYour Target is to secure Good Rank in Pre-Medical 2012

MAJOR TEST : AIIMS


5. The thermo e.m.f. of copper constantantermocouple is 50mV°C–1 at room temperature.A galavanometer of resistance 50 W and capableof detecting currents of the order of 2mA is used.The temperature difference that can be detectedby this galvanometer is :-(1) 20°C (2) 2°C(3) 10°C (4) 0.20°C

6. A static radioactive nucleus undergoes a-emissionto form a stable element. What will be the recoilvelocity of the daughter nucleus if V is the velocityof a-emission and A is the mass number ofradioactive nucleus :-

(1) 4V

A 4-(2)

2VA 4-

(3) 4V

A 4+(4)

2VA 4+

7. A man wants to distinguish between two pillarslocated at a distance of 11 km. What should bethe minimum distance between pillars ?(1) 3.2 m (2) 1.2 m (3) 1.1 m (4) 1.8 m

8. The following diagram represents :-

(1) NOR gate

(2) OR gate A

Bp

(3) AND gate

(4) None

9. The figure below shows two equipotential lines

in XY plane for an electric field. The scales are

marked. The X-component Ex and Y-component

Ey of the electric field in the space between these

equipotential lines are respectively –

(1) +100 V/m, – 200 V/m(2) +200 V/m, +100 V/m(3) –100 V/m, +200 V/m(4) –200 V/m, –100 V/m

5. dkWij&dkaLVsUVu rki oS|qr ; qXe dk dejs ds rki ijfo- ok- cy 50mV°C–1 gSA 50 W izfrjks/k dk ,d /kkjkekih

tks 2mA ds Øe dh /kkjkvksa dks lalwfpr dj ldrk gS]

iz;ksx fd;k tk jgk gS] ml rkikUrj dh x.kuk djks ftls

bl èkkjkekih }kjk lalwfpr fd;k tk ldrk gS :-

(1) 20°C (2) 2°C

(3) 10°C (4) 0.20°C

6. ,d fLFkj jsfM;ks/kehZ ukfHkd LFkkbZ rRo cukus ds fy,

a-mRltZu djrk gSA iq=h ukfHkd dk izfrf{kIr osx D;k gksxk

;fn a-mRltZu dk osx V gks rFkk jsfM;ks/kehZ ukfHkd dh

æO;eku la[;k A gS :-

(1) 4V

A 4-(2)

2VA 4-

(3) 4V

A 4+(4)

2VA 4+

7. ,d O;fDr nks [kEcs tks mlls 11 km nwj gS dks vyx&vyxns[kuk pkgrk gS bu [kEcksa dh chp dh U;wure nwjh D;k gksuhpkfg,A(1) 3.2 m (2) 1.2 m (3) 1.1 m (4) 1.8 m

8. fuEu fp= iznf'kZr djrk gS :-

(1) NOR gate

(2) OR gate A

Bp

(3) AND gate

(4) dksbZ ugha

9. fp=kuqlkj XY ry esa fdlh fo|qr {ks= dh lefoHko js[kk,¡

çnf'kZr gSaA iSekuk fp=kuqlkj gSA bu lefoHko js[kkvksa dse/; fo|qr {ks= ds X ?kVd Ex rFkk Y ?kVd Ey ds ekuØe'k % gS –

(1) +100 oksYV/ehVj, – 200 oksYV/ehVj

(2) +200 oksYV/ehVj, +100 oksYV/ehVj

(3) –100 oksYV/ehVj, +200 oksYV/ehVj

(4) –200 oksYV/ehVj, –100 oksYV/ehVj

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MAJOR TEST : AIIMS


10. An atomic power nuclear reactor can deliver 300MW. The energy released due to fission of eachnucleus of uranium atom U238 is 170 MeV. Thenumber of uranium atoms fissioned per hour will be:-(1) 30 × 1025 (2) 4 × 1022

(3) 10 × 1020 (4) 5 × 1015

11. Two plane mirrors are combined to each other assuch one is in y-z plane and other is in x-z plane.

A ray of light along vector ˆ ˆ î j k+ + is incidenton the first mirror. The unit vector in the directionof emergence ray after successive reflectionsthrough the mirror is :-

(1) 1 1 1ˆ ˆ ˆ– i j k3 3 3

- +

(2) 1 1 1ˆ ˆ ˆ– i j – k3 3 3

-

(3) ˆ ˆ ˆ– i j – k-(4) None of these

12. A variable force (24t2 – 8t) Newton is acting ona particle. The impulse imparted to it in first twoseconds will be :(1) 12 kg-m/s (2) 24 kg-m/s(3) 36 kg-m/s (4) 48 kg-m/s

13. Two identical capacitors 1 and 2 are connected inseries to a battery as shown in figure. Capacitor2 contains a dielectric slab of dielectric constantk as shown. Q1 and Q2 are the charges stored inthe capacitors. Now the dielectric slab is removedand the corresponding charges are Q1' and Q2' . Then

(1) Q

Q

'1

1=kk+1

(2) Q

Q

'22

= k +12

(3) Q

Q

'22

= kk+12

(4) Q

Q

'1

1= k2

14. A radioactive sample of U238 decay to Pb througha process for which half life is 4.5 × 109 years.Theratio of number of nuclei of Pb to U238 after a timeof 1.5 × 109 years (given 21/3 = 1.26) :-(1) 0.12 (2) 0.26 (3) 1.2 (4) 0.37

10. ,d ijek.kq Hkêh 300 MW 'kfDr iznku djrh gSAizR;sd ; wj sfu;e U238 ukfHkd ds fo[k.Mu ls eqDrÅtkZ 170 MeV gSA izfr ?k.Vs fo[kf.Mr ; wj sfu;eijek.kqvksa dh la[;k gS :-(1) 30 × 1025 (2) 4 × 1022

(3) 10 × 1020 (4) 5 × 1015

11. nks lery niZ.k ,d nwljs ls bl rjg tqM+s gS fd ,dy-z ry esa rFkk nwljk x-z ry esa gSA ,d izdk'k fdj.kigys niZ.k ij lfn'k ˆ ˆ î j k+ + ds vuqfn'k vkrh gSA buniZ.k ls Vdjkus ds ckn izdk'k ds fdj.k dh fn'kk esa bdkbZlfn'k D;k gksxk :-

(1) 1 1 1ˆ ˆ ˆ– i j k3 3 3

- +

(2) 1 1 1ˆ ˆ ˆ– i j – k3 3 3

-

(3) ˆ ˆ ˆ– i j – k-

(4) buesa ls dksbZ ugha

12. fdlh d.k ij ,d ifjorhZ cy (24t2 – 8t) U;wVu dk;ZjrgSA izFke nks lsd.M esa mls iznku fd;k x;k vkosxgksxk :(1) 12 fdxzk-eh/ls (2) 24 fdxzk-eh/ls(3) 36 fdxzk-eh/ls (4) 48 fdxzk-eh/ls

13. fp=kuqlkj nks ,d leku la/kkfj= 1 rFkk 2 ,d cSVjh lstksM+s x;s gSaA la/kkfj= 2 esa ijoS|qrkad k dh ijkoS|qrkadifêdk gSA la/kkfj=ksa ij vkos'k Øe'k % Q1 rFkk Q2 gSAvc ijkoS|qr ifêdk gVk ysus ij la/kkfj=ksa ij vkos'k Q1'rFkk Q2' gS] rks

(1) Q

Q

'1

1=kk+1

(2) Q

Q

'22

= k +12

(3) Q

Q

'22

= kk+12

(4) Q

Q

'1

1= k2

14. U238 dk ,d jsfM;kslfØ; uewuk ,d izfØ;k }kjk Pb esafo?kfVr gks tkrk gS] bl izfØ;k ds fy, vðZ&vk;q 4.5 × 109

o"kZ gSA 1.5 × 109 o"kZ ckn Pb ukfHkdksa dh la[;k ,oa U238

ds ukfHkdksa dh la[;k dk vuqikr gksxk (fn;k gS 21/3 =1.26):-(1) 0.12 (2) 0.26 (3) 1.2 (4) 0.37

izR;sd iz'u dks vtqZu cudj djksA

27–04–2012


MAJOR TEST : AIIMS


15. A convergent doublet of separated lens, correctedfor spherical aberration, are separated by 2 cm,and has an equivalent focal length of 10 cm. Thefocal length of its component lenses are :(1) f1 = 18 cm, f2 = 10 cm(2) f1 = 20 cm, f2 = 28 cm(3) f1 = 20 cm, f2 = 18 cm(4) f1 = 24 cm, f2 = 18 cm

16. The variation of velocity of a particle movingalong a straight line is illustrated in the fig. Theratio of avg. speed to avg. vel. is :-

(1) 2 : 1 (2) 1 : 2(3) 1 : 1 (4) 4 : 1

17. An electric dipole consists of two oposite chargeseach of magnitude 1.0mC separated by a distanceof 2.0 cm. The dipole is placed in an external fieldof 1.0 × 105 N/C. The maximum torque on thedipole is :-(1) 0.2 × 10–3 N-m (2) 2.0 × 10–3 N-m(3) 4.0 × 10–3 N-m (4) 1.0 × 10–3 N-m

18. Consider a cycle followed by an engine -

1 2

3

P

V

1 to 2 is isothermal2 to 3 is adiabatic3 to 1 is adiabaticSuch a process does not exist because :(1) three process can not represent a cycle process(2) mechanical energy is completely converted to

heat in this process, which is not possible(3) curves representing two adiabatic processes do

not intersect(4) curves representing an adiabatic process and

an isothermal process do not intersect

15. nks vfHklkjh ysUl tks ,d nwljs ls 2 cm nwj j[ks gS ,d,slk ;qXe cuk jgs gS ftlesa xksyh; foiFku u gks ;fn bl;qXe dh rqY; Qksdl nwjh 10 cm gS rks izR;sd dh Qksdlnwjh D;k gksxh :(1) f1 = 18 cm, f2 = 10 cm(2) f1 = 20 cm, f2 = 28 cm(3) f1 = 20 cm, f2 = 18 cm(4) f1 = 24 cm, f2 = 18 cm

16. ,d lh/kh js[kk ds vuqfn'k xfr djrs gq, d.k ds osx esaifjorZu dk fp= fn;k x;k gS rks vkSlr pky o vkSlr osxdk vuqikr D;k gksxk :-

(1) 2 : 1 (2) 1 : 2(3) 1 : 1 (4) 4 : 1

17. ,d oS|qr f}/kqzo esa foifjr izÏfr ,oa leku ifjek.k 1.0mC

ds nks vkos'k 2.0 lseh- nwjh ij fLFkr gSA bl oS|qr f}èkqzo

dks 1.0 × 105 U;wVu@dwyWke rhozrk ds cká fo|qr {kS=

esa j[kk gSA f}/kqzo ij vf/kdre cyk?kw.kZ gS :-

(1) 0.2 × 10–3 U;wVu&ehVj (2) 2.0 × 10–3 U;wVu&ehVj

(3) 4.0 × 10–3 U;wVu&ehVj (4) 1.0 × 10–3 U;wVu&ehVj

18. ,d b±tu }kjk fuEufyf[kr pØh; izØe fopkj.kh; gS -

1 2

3

P

V

1 ls 2 lerkih;2 ls 3 :¼ks"e3 ls 1 :¼ks"e gS;g ,d izØe ds fy, fl¼ ugha gksrk gS D;ksafd :(1) rhu izØe ,d pØh; izØe dks vfHkO;Dr ugha dj

ldrs gSA(2) bl izØe esa ;kafU=d ÅtkZ iw.kZ :i ls Å"ek esa :ikUrfjr

gks tk;s] vlaHko gSA(3) oØ nks :¼ks"e izØeksa dks vfHkO;Dr djrs gS tks ,d

nwljs dks izfrPNsfnr ugha djrs gSA(4) oØ ,d :¼ks"e vkSj ,d lerkih; izØe dks vfHkO;Dr

djrs gS tks ,d nwljs dks izfrPNsfnr ugha djrs gSA

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MAJOR TEST : AIIMS


19. A particle executing simple harmonic motion hasamplitude of 2m. the equation of displacement ofparticle is if time period is 2 second :-(1) x = 2 sinpt (2) x = 3 sinpt(3) x = 2 sin 3pt (4) x= 4 sin6t

20. A ball is moving with velocity 2 m/s towards aheavy wall moving towards the ball with speed1 m/s. Assuming collision to be elastic the velocityof ball immediately after collision :-(1) 2 m/s (2) 4 m/s (3) 6 m/s (4) 8 m/s

21. A satellite is revolving round the earth with orbitalspeed v0. If it stops suddenly, the speed with whichit will strike the surface of earth would be(ve = escape velocity of a particle on earth's surface)

(1) vve2

0 (2) v0 (3) v ve

202- (4) v ve

2022-

22. Consider two containers A and B containingidentical gases at the same pressure, volume andtemperature. The gas in container A is compressedto half of its original volume isothermally whilethe gas in container B is compressed to half of itsoriginal value adiabatically. The ratio of finalpressure of gas in B to that of gas in A is :

(1) 2g –1 (2) 1

12

g-æ öç ÷è ø

(3) 2

11

æ öç ÷- gè ø

(4) 2

11

æ öç ÷g -è ø

23. In a young's double slit experiment, the fringe

pattern is observed on a screen placed at a distance

D. The slits are separated by d and are illuminated

by light of wavelength l. Find the distance from

the central point where the intensity falls to half

the maximum is :-

(1) lDd4

(2) lDd2

(3) lDd

(4) 23

lDd

24. A man is walking with 5 m/s. Rain drops arefalling vertically but he finds that rain drops arefalling at an angle 45° with vertical the actualspeed of rain will be :-

(1) 5 m/s (2) 5 3 (3) 5

3(4) 4

19. ljy vkorZ xfr djrs gq, d.k dk vk;ke 2m rFkkvkorZ dky 2sec. gS d.k ds foLFkkiu dk lehdj.kgksxk :-(1) x = 2sinpt (2) x = 3sinpt

(3) x = 2 sin 3pt (4) x= 4sin6t

20. 2 m/s ds osx ls xfr'khy ,d xsUn 1 m/s dh pky ls pyjgh ,d Hkkjh nhokj dh vksj xfreku gSA VDdj dksizR;kLFk ekurs gq, VDdj ds Bhd i'pkr~ xsUn dk osxgksxk :-(1) 2 m/s (2) 4 m/s (3) 6 m/s (4) 8 m/s

21. ,d mixzg i`Foh ds pkjksa vksj v0 pky ls ifjØek djjgk gSA ;fn bldks vpkud jksd fn;k tk;s rks ;g i`Fohdh lrg ls fuEu pky ls Vdjk,xk (ve = i`Foh dh lrgls fdlh d.k dk iyk;u osx) :–

(1) vve2

0 (2) v0 (3) v ve

202- (4) v ve

2022-

22. nks ik= A vkSj B leku nkc] vk;ru vkSj rkieku ij le:i

xSl j[krs gSA ik= A esa xSl okLrfod vk;ru dh vk/kh

vk;ru rd lerkih; :i ls leihfM+r dh tkrh gS tcfd

ik= B esa :¼ks"e :i ls okLrfod eku dh vk/ks vk;ru

rd leihfM+r dh tkrh gSA xSl B dk xSl A ds vfUre

nkc ls vuqikr gS :

(1) 2g –1 (2) 1

12

g-æ öç ÷è ø

(3) 2

11

æ öç ÷- gè ø

(4) 2

11

æ öç ÷g -è ø

23. ;ax f}&fLyV iz;ksx esa] fÝat izfr:i D nwjh ij fLFkr insZ

ij izkIr gksrk gSA fLyVksa dks d nwjh ij j[kk gS rFkk mUgsa l

rjax nSè;Z ds izdk'k ls izdkf'kr fd;k x;k gSA dsUæ fcUnq

ls og nwjh Kkr djks] tgk¡ rhozrk vf/kdre rhozrk dh vkèkh

gks %&

(1) lDd4

(2) lDd2

(3) lDd

(4) 23

lDd

24. 5 m/s ls xfr djrs gq, ,d O;fDr dks o"kkZ dh cw¡nsÅ/okZ/kj ls 45° ds dks.k ij vkrh gqbZ izrhr gksrh gSA ;fno"kkZ dh cw¡ns okLrfod :i ls Å/okZ/kj uhps fxj jgh gksrks o"kkZ dh okLrfod pky gksxh :-

(1) 5 m/s (2) 5 3 (3) 5

3(4) 4

27–04–2012


MAJOR TEST : AIIMS


25. In an experiment of potentiometer for determining a

small resistance, the balancing length for the potential

difference across the large resistance is 320 cm. and

the balancing length for the potential difference

across both resistances when connected in series, is

360 cm. The ratio of large and small resistances is :-

(1) 1 : 8 (2) 8 : 1

(3) 8 : 9 (4) 9 : 826. The intensity of radiation emitted by the Sun has

its maximum value at a wavelength of 510 nm andthat emitted by North Star has the maximum valueat 350 nm. If these stars behave like blackbodies,then the ratio of the surface temperatures of theSun and the North Star is :(1) 1.46 (2) 0.69(3) 1.21 (4) 0.83

27. The frequency of oscillation of the system shownin the figure will be :-

(1) 1

2p

kM

(2) 1

2p

2kM

(3) 1

2pkM5

M

KK

K

K

(4) 1

2p

25

kM

28. The K.E. of a body varies directly as the time (t)elapsed. the force acting varies directly as :-(1) t–1 (2) t–1/2 (3) t1/2 (4) t

29. In the following circuit, if total heat dissipated in

the circuit is 18J/s, then what is the heat dissipated

in 5W resistance :-

(1) 18 J

(2) 185

J

(3)365

J

(4) None of these

25. ,d vYi izfrjks/k dks Kkr djus ds foHkoekih iz;ksx esa cM+s

izfrjks/k ds fljksa ij foHkokUrj ds fy, lUrqfyr yEckbZ

320 cm. gSA tc nksuksa izfrjks/k Js.khØe esa tksM+s tkrs gS] rks

muds fljksa ij foHkokUrj ds fy, lUrqfyr yEckbZ 360 cm. gS]

rks cM+s o NksVs izfrjks/kksa dk vuqikr gS-

(1) 1 : 8 (2) 8 : 1

(3) 8 : 9 (4) 9 : 8

26. lw;Z }kjk fofdj.k mRltZu dh rhozrk 510 nm dh rjaxnS/;Z ij vf/kdre eku j[krh gS vkSj /kqzoh rkjk }kjk mRltZu

350 nm ij vf/kdre eku j[krk gSA ;fn ;s rkjs Ïf".kdk

oLrq dh rjg dk;Z djrs gS rks lw;Z vkSj /kqzoh rkjs ds i`"B

dk rkieku dk vuqikr gS :

(1) 1.46 (2) 0.69

(3) 1.21 (4) 0.8327. layXu fp= esa fudk; dh nksyu vkofÙk gksxh :-

(1) 1

2p

kM

(2) 1

2p

2kM

(3) 1

2pkM5

M

KK

K

K

(4) 1

2p

25

kM

28. fdlh oLrq dh xfrt ÅtkZ K.E. le; (t) ij lh/ks fuHkZjdjrh gSA oLrq ij yx jgk cy lh/ks fuHkZj djsxk :-(1) t–1 (2) t–1/2 (3) t1/2 (4) t

29. fuEu ifjiFk esa] ;fn dqy O;f;r ÅtkZ 18J/s gS rks 5W

çfrjks/k esa O;f;r ÅtkZ gksxh :-

(1) 18 J

(2) 185

J

(3)365

J

(4) mijksDr esa ls dksbZ ugha

dksbZ Hkh iz'u Key Filling ls xyr ugha gksuk pkfg,A

E / H 7/34

27–04–2012


MAJOR TEST : AIIMS


30. Two particles A and B of masses mA and mB

respectively and having the same charge aremoving in a plane. A uniform magnetic field existsperpendicular to this plane. The speeds of theparticles are vA and vB respectively and thetrajectories are as shown in the figure. Then :-

BB

A

(1) mAvA < mBvB

(2) mAvA > mBvB

(3) mA < mB and vA < vB

(4) mA = mB and vA = vB

31. If angular velocity

60°t

wv/s time curve of arotating body isrepresented by (fig.)then variation ofangular acceleration with time is properlyrepresentated by :-

(1)

t

a 3

(2)

a

13

t

(3)

t

a

3

(4)

13

a

t

32. A stone thrown at an angle q to the horizontalreaches a maximum height h. The time of theflight of the stone is :-

(1) 2h sin

gq

(2) 2 2h sin

gq

(3) 2h

2g (4)

2hg

30. nks d.k A rFkk B ftuds nzO;eku mA rFkk mB gS rFkk

vko s'k leku gS] ,d ry e s a xfr'k hy g SA

pqEcdh; { k s= ry ds yEcor~ g S d.kk s a ds o sx

Øe' k% vA rFkk vB gS rFkk iFk fp= vuqlkj g S]

rks :-

BB

A

(1) mAvA < mBvB

(2) mAvA > mBvB

(3) mA < mB and vA < vB

(4) mA = mB and vA = vB

31. ;fn ,d ?kw.kZu djrh oLrq

60°t

wdk dk s.kh; osx le;

ds lkFk (fp=) ls n'kkZ;k

tkrk gS rks dks.kh; Roj.k

dk le; ds lkFk ifjorZu

n'kkZus okyk lgh oØ gksxk %&

(1)

t

a 3

(2)

a

13

t

(3)

t

a

3

(4)

13

a

t

32. ,d iRFkj dks {kSfrt ls q dks.k ij iz{ksfir fd;k tkrk gSrFkk og vf/kdre Å¡pkbZ h rd igq¡prk gSA iRFkj ds fy;smM+ku dky gksxk :-

(1) 2h sin

gq

(2) 2 2h sin

gq

(3) 2h

2g (4)

2hg

27–04–2012


MAJOR TEST : AIIMS


33. m lagfr dk ,d bysDVªkWu] tc V foHkokUrj ls Rofjr gksrk

gS] Mh&czksXyh rjaxnS/; Z l j[krk gSA leku foHkokUrj ls Rofjr

M lagfr ds izksVkWu dh Mh&czksXyh rjaxnS/;Z gksxh %&

(1) mM

l (2) mM

l

(3) Mm

l (4) Mm

l

34. nk s p q Ecd ftuds pqEcdh; f}/ k z qo vk?k w .k Z M rFkk

M / 3 gS] ,d nwljs ds yEcor~ ck¡/kdj ,d Øksl cuk jgsg SA ;fn bl ; q Xe dk s ,d leku pq Ecdh; {k s=B es a eqDr :i ls yVdk;k tkrk gS rk s q dk D;k ekugksxk :-

q

M 3Ö

M

(1) q = 30° (2) q = 90°(3) q = 60° (4) q = 45°

35. nks Lofj=ksa P ,oa Q dks ,d lkFk ctk;s tkus ij mRiék foLianksadh la[;k dks ljy js[kk OA }kjk O;Dr djrs gSaA Q dksekse ls Hkkfjr djds iqu% nksuksa dks ,d lkFk ctk;k tk;srks mRiék foLianksa dh la[;k js[kk OB ds }kjk O;fDr djrsgSaA ;fn P dh vko`fÙk 341 Hz gS] rks Q dh vko`fÙkgksxh :-

BA

3

2

1

01 2

Beat

s

t(s)

(1) 341 Hz

(2) 338 Hz

(3) 344 Hz

(4) buesa ls dksbZ ugha

33. An electron of mass m when accelerated througha potential difference V has de-Brogliewavelength l . The de-Broglie wavelengthassociated with a proton of mass M acceleratedthrough the same potential difference will be :-

(1) mM

l (2) mM

l

(3) Mm

l (4) Mm

l

34. M and M / 3 are the magnetic dipole moments

of the two magnets, which are joined to form across figure. The inclination of the system withthe field if their combination is suspended freelyin a uniform external magnetic field B is :-

q

M 3Ö

M

(1) q = 30° (2) q = 90°(3) q = 60° (4) q = 45°

35. Two tuning forks P and Q are vibrated toghether.The number of beats produced are represented bythe straight line OA in the following graph. Afterloading Q with wax again these are vibratedtogether and the beats produced are representedby the line OB. If the frequency of P is 341 Hz,the frequency of Q will be :-

BA

3

2

1

01 2

Bea

ts

t(s)

(1) 341 Hz

(2) 338 Hz

(3) 344 Hz

(4) None of these

Use stop, look and go method in reading the question

E / H 9/34

27–04–2012


MAJOR TEST : AIIMS


36. ,d ljy yksyd fu;r vk;ke (fcuk eanu ds) ls nksyudj jgk gS tc xksyd dk foLFkkiu blds vf/kdre ekuls de gS ml fLFkfr esa bldk Roj.k lfn'k a

r lgh :i

ls fn[kk;k x;k gS :-

(1) a®

(2)

a®

(3) a®

(4)

a®

37. ,d /kkrq ftldk dk;Z Qyu f gS] ds i`"B ij vkifrrrjaxnS/;Z l ds izdk'k }kjk mRlftZr bysDVªkWu dk vf/kdreosx gksxk :-

(1) ( ) 1/ 2

2 hc

m

é ù+ lfê úlë û

(2) ( )2 hc

m

- lf

(3) ( ) 1/ 2

2 hc

m

é ù- lfê úlë û

(4) ( ) 1/ 2

2 h

m

é ùl - fê úë û

38. fp= esa crkbZ dq.Myh esa lkE; voLFkk ij fdruh pqEcdh;ÅtkZ laxzfgr gksxh ?

25V

2W

5W 5H 10W

25W

(1) 21.3 J (2) 42.6 J (3) 'kwU; (4) 213 J

39. fdlh rus gq, ,dleku rkj dh vko`fÙk ,d cUn ikbidh ewy vko`fÙk ds lkFk vuqukfnr gSA ;fn rkj dsruko esa 8N dh o`f¼ dj nh tk;s rks ;g cUn ikni dsizFke vf/kLojd ls vuqukfnr gksrk gSA rkj esa izkjfEHkdruko gS :-

(1) 1 N (2) 4 N (3) 8 N (4) 16 N

40. ,d ur ij j[kk CykWd P rc fQlyuk 'kq: djrk gS tcur ry dk dks.k 37° gSA bl CykWd dks vU; CykWd Qls izfrLFkkfir fd;k x;k ,oa ik;k x;k fd ;g rc fQlyuk'kq: djrk gS tc ur ry dk dks.k 43° gS :-(1) mP > mQ (2) mP < mQ

(3) mP = mQ (4) lHkh rhuksa lEHko gS

36. A simple pendulum is oscillating without dampingwhen the displacement of the bob is less thanmaximum, its acceleration vector a

r is correctly

shown in :-

(1) a®

(2)

a®

(3) a®

(4)

a®

37. The maximum velocity of an electron emitted bylight of wavelength l incident on the surface ofa metal of work function f, is :-

(1) ( ) 1/ 2

2 hc

m

é ù+ lfê úlë û

(2) ( )2 hc

m

- lf

(3) ( ) 1/ 2

2 hc

m

é ù- lfê úlë û

(4) ( ) 1/ 2

2 h

m

é ùl - fê úë û

38. In the circuit shown what is the energy stored inthe coil at steady state ?

25V

2W

5W 5H 10W

25W

(1) 21.3 J (2) 42.6 J (3) Zero (4) 213 J39. The frequency of a stretched uniform wire under

tension is in resonance with the fundamentalfrequency of a closed tube. If the tension in thewire is increased by 8N, it is in resonance withthe first overtone of the closed tube. The initialtension in the wire is :-

(1) 1 N (2) 4 N (3) 8 N (4) 16 N

40. A block P kept on an inclined surface just beginsto slide if the inclination is 37°. The block isreplaced by another block Q and it is found thatit just begins to slide if the inclination is 43° :-(1) mP > mQ (2) mP < mQ

(3) mP = mQ (4) All the three are possible

27–04–2012


MAJOR TEST : AIIMS


41. CH3MgBr +

O

3H O+

¾¾¾® A HBr¾¾¾® B

Mg / ether¾¾¾¾® C3

HCHO

H O+¾¾¾® D

HI¾¾® E

E is

(1) CH3 CH I2

(2) CH CH2 3

I

(3) CH3

I (4) CH3

I

42. In the following reaction sequence, the correctstructures of E, F and G are

O O

Ph OH* Heat¾¾¾® [E] 2I

NaOH¾¾¾® [F] + [G]

[* implies 13C labelled carbon]

(1) E =O

Ph CH3* F =

O

Ph O Na* Å1 G = CHI3

(2) E =

O

Ph CH3* F =

O

Ph O NaÅ1 G = CHI3

(3) E =

O

Ph CH3* F =

O

Ph O NaÅ1 G = 3

*CHI

(4) E =

O

Ph CH3* F =

O

Ph O NaÅ1 G = 3

*CH I

43. A solution of CuSO4 is electrolysed for 10 minwith a current of 1.5 amp. What is the mass ofCu diposited at cathods ? (atomic mass of Cu = 63)

(1) 0.9 g (2) 0.3 g

(3) 4 g (4) 3.8 g

44. Which of the following ion is not coloured ?

(1) Ni(DMG)2

(2) [CO(SCN)4]–2

(3) [Al(OH)4]– (4) [Fe(H

2O)

5(SCN)]+2

41. CH3MgBr +

O

3H O+

¾¾¾® A HBr¾¾¾® B

Mg / ether¾¾¾¾® C3

HCHO

H O+¾¾¾® D

HI¾¾® E

E gS%&

(1) CH3 CH I2

(2) CH CH2 3

I

(3) CH3

I (4) CH3

I

42. fuEufyf[kr vfHkfØ;k esa E, F vkSj G dh lajpuk,¡gS

O O

Ph OH* Heat¾¾¾® [E] 2I

NaOH¾¾¾® [F] + [G]

[* implies 13C labelled carbon]

(1) E =O

Ph CH3* F =

O

Ph O Na* Å1 G = CHI3

(2) E =

O

Ph CH3* F =

O

Ph O NaÅ1 G = CHI3

(3) E =

O

Ph CH3* F =

O

Ph O NaÅ1 G = 3

*CHI

(4) E =

O

Ph CH3* F =

O

Ph O NaÅ1 G = 3

*CH I

43. CuSO4 ds ,d foy;u dks 10 feuV rd fo|qr vi?kfVrfd;k x;k dSFkksM ij fdrus xzke Cu izkIr gk sxk ;fn1.5 amp dh /kkjk izokfgr dh tk;s (Cu = 63)?

(1) 0.9 g (2) 0.3 g

(3) 4 g (4) 3.8 g

44. dkSulk vk;u jaxhu ugha gS ?

(1) Ni(DMG)2

(2) [CO(SCN)4]–2

(3) [Al(OH)4]– (4) [Fe(H

2O)

5(SCN)]+2

Take it Easy and Make it Easy

E / H 11/34

27–04–2012


MAJOR TEST : AIIMS


45. Correct matching is -

List - I List-II(A) Inversion (1) Cis addition

(B) Racemic mixture (2) Trans addition

(C) Alkene BaeyerReagent¾¾¾¾® (3) SN1 reaction

(D) Alkene 2Br¾¾® (4) SN2 reaction

(A) (B) (C) (D)(1) 3 4 2 1

(2) 3 4 1 2

(3) 4 3 1 2

(4) 4 3 2 1

46. The order of reactivity of methyl alcohol(I), isopropyl alcohol (II), tertiary butyl alcohol(III) and ethyl alcohol (IV) for esterification indecreasing order will be:

(1) I > II > III > IV

(2) IV > III > II > I

(3) I > IV > II > III

(4) I > IV > III > II

47. Which is correct expression of Ka for CH3COOHin terms of molar conductivity ?

(1) 2m

m m

c

( )¥l

l -l (2)

2m

m

m

m

c

1

¥

¥

læ ö´ ç ÷lè ølæ ö-ç ÷lè ø

(3) 2mcl (4) c

48. The correct increasing order of adjacent bond

angle among BF3, PF3 and ClF3 :-

(1) BF3 < PF3 < ClF3

(2) PF3 < BF3 < ClF3

(3) ClF3 < PF3 < BF3

(4) BF3 = PF3 = ClF3

49. The correct decreasing order of stability offollowing structures of formic acid is -

H–C–OH H–C–OHH–C=OH H–C–OH

O OO OÅ

Å1

1

(I) (III)(II) (IV)Å

1

(1) I > II > III >IV (2) II > I > III >IV

(3) III > II > IV >I (4) IV > III > I >II

45. fuEu dks lgh lqesfyr djsa -List - I List-II

(A) izrhiu (1) lei{k ;ksx

(B) jslsfed feJ.k (2) foi{k ;ksx

(C) ,sYdhu ¾¾¾¾®cs;jvfHkdeZd

(3) SN1 vfHkfØ;k

(D) ,sYdhu 2Br¾¾® (4) SN2 vfHkfØ;k

(A) (B) (C) (D)(1) 3 4 2 1

(2) 3 4 1 2

(3) 4 3 1 2

(4) 4 3 2 1

46. ,LVjhdj.k ds fy, esfFky ,YdksgkWy (I) vkblksizksfiy,YdksgkWy (II) r`rh;d C;wfVy ,YdksgkWy (III) vkSj ,fFky,YdksgkWy (IV) dh fØ;k'khyrk dk ?kVrk gqvk ØegS:(1) I > II > III > IV

(2) IV > III > II > I

(3) I > IV > II > III

(4) I > IV > III > II

47. CH3COOH dh eksyj pkydrk ds :i esa Ka dk ekuD;k gksxk ?

(1) 2m

m m

c

( )¥l

l -l (2)

2m

m

m

m

c

1

¥

¥

læ ö´ ç ÷lè ølæ ö-ç ÷lè ø

(3) 2mcl (4) c

48. Øekxr ca/k dks.kksa dk lgh c<+rk gqvk Øe gS :-

(1) BF3 < PF3 < ClF3

(2) PF3 < BF3 < ClF3

(3) ClF3 < PF3 < BF3

(4) BF3 = PF3 = ClF3

49. QkfeZd vEy dh fuEu lajpukvksa ds LFkkf;Ro dk ?kVrk

Øe gksxk%&

H–C–OH H–C–OHH–C=OH H–C–OH

O OO OÅ

Å1

1

(I) (III)(II) (IV)Å

1

(1) I > II > III >IV (2) II > I > III >IV

(3) III > II > IV >I (4) IV > III > I >II

27–04–2012


MAJOR TEST : AIIMS


50. Match list -I [ polymers] with List - II [monomers]and choose the correct answer from the codesgiven below the list -

List-I List-II[Polymer] [Monomer]

A. PAN a. ChloroetheneB. Natural rubber b. CaprolactumC. Nylon-6 c. IsopreneD. PVC d. Vinyl cyanideCode is : A B C D(1) d c b a(2) a b c d(3) c d a b(4) b a c d

51. Tyndall effect is not observed in :-(1) Suspension (2) Emulsion(3) Sugar solution (4) Gold sol

52. State of hybridisation of sulphur, carbon-1,

carbon-2 in3 3(1) (2)

F SC CF respectively are :-

(1) sp3, sp3, sp3 (2) sp3, sp2, sp3

(3) sp3d, sp, sp3 (4) sp3, sp, sp3

53. Which of the following is most reactive towardselectrophilic nitration -(1) o- xylene (2) m-xylene(3) p-xylene (4) toulene

54. The oxidation number of carbon is zero in :-(1) HCHO (2) CH2Cl2

(3) C6H12O6 (4) All are correct55. Which one is correct for equilibrium state out of

following ?(a) resultant rate = 0 (b) DG = 0(c) DStotal = 0 (d) QC = KC

(1) a, b (2) a, b, c(3) a, b, d (4) a, b, c, d

56. The extent of crystal field splitting in octahedralcomplexes of the given metal with particular weakfield ligand are such that :-

(1) Fe(III) < Rh(III) < Ir(III)

(2) Rh(III) < Ir(III) < Fe(III)

(3) Ir(III) < Rh(III) < Fe(III)

(4) Fe(III) = Rh(III) < Ir(III)

50. lwph-I [cgqyd] ,oa lwph-II [,dyd] dk slqesfyr dfj;s ,oa fn;s x;s dqVks esa ls lgh dk p;udfj;s %&

lwph-I lwph-II[cgqyd] [,dyd]

A. PAN a. Dyksjks,Fkhu

B. izkd`frd jcj b. dsizksysDVeC. ukbykWu-6 c. vkblksizhu

D. PVC d. okbfuy lk;ukbMdqV gS%& A B C D(1) d c b a(2) a b c d(3) c d a b(4) b a c d

51. fV.My izHkko fdlesa ugha ns[kk x;k :-(1) Ldanu (2) beYlu(3) phuh dk foy;u (4) xksYM lkWy

52.3 3(1) (2)

F SC CF esa lYQj] dkcZu-1 rFkk dkcZu-2 dh lgh

ladj.k voLFkk gS :-

(1) sp3, sp3, sp3 (2) sp3, sp2, sp3

(3) sp3d, sp, sp3 (4) sp3, sp, sp3

53. fuEu esa ls dkSulk ;kSfxd bysDVªkuLusgh ukbVªhdj.k ds izfrlokZf/kd fØ;k'khy gS%&(1) o-tk;yhu (2) m-tk;yhu(3) p-tk;yhu (4) VkWyqbZu

54. dkcZu dk vkWDlhdj.k vad 'kwU; gS :-(1) HCHO (2) CH2Cl2

(3) C6H12O6 (4) lHkh lgh gS55. lkE;koLFkk ij D;k lgh gS ?

(a) ifj.kkeh nj = 0 (b) DG = 0

(c) DSdqy

= 0 (d) QC = KC

(1) a, b (2) a, b, c(3) a, b, d (4) a, b, c, d

56. nh xb Z / k kr qvk s a ds n qc Zy { k s= fyxs.M g sr qv"VQydh; ladqyksa esa fØLVy {ks= foikVu dk lghØe gS :-

(1) Fe(III) < Rh(III) < Ir(III)

(2) Rh(III) < Ir(III) < Fe(III)

(3) Ir(III) < Rh(III) < Fe(III)

(4) Fe(III) = Rh(III) < Ir(III)

fdlh iz'u ij nsj rd :dks ugha A

E / H 13/34

27–04–2012


MAJOR TEST : AIIMS


57. HBO, oxymercuration-demercuration and acidcatalysed hydration will not give same productin

(i) (ii)

(iii) (iv)

(1) i, ii, iii (2) ii, iii, iv(3) i, ii, iv (4) i, iii, iv

58. Half life of an element is x second. In x2

, seconds

the fraction of element decayed (Assume Ist orderreactive) :-(1) 21% (2) 70%(3) 50% (4) 29.3%

59. The occupied space in bcc unit cell is :-

(1) 32

p(2)

6p

(3) 2 2

p(4)

38

p

60. Which one of the following high-spin complexes

has the largest CFSE (Crystal field stabilization

energy) ?

(1) [Mn(H2O)6]2+ (2) [Cr(H2O)6]

2+

(3) [Mn(H2O)6]3+ (4) [Cr(H2O)6]

3+

61. 2,2,6,6-tetramethyl cyclohexanol is treated withan acid. An alkene is formed. The structure of thealkene is

(1) (2)

(3) (4)

62. The radioactive element X, decays by thesequence

X 1k¾¾® P + a ; Half life = 30 min

P 2k¾¾® Q + 2b ; Half life = 24 hrs.The incorrect statement is :-(1) Disintegration constant k1 < k2

(2) X and Q are isotopes.(3) Mass number of X is more than P(4) P and Q has same atomic number

57. gkbMªk sck sjhuhdj.k vkDlhdj.k] vkDlhejD;qfjdj.kfoejD;wjhdj.k rF kk vEy mRizsfjr ty;kstu ij leku mRiknizkIr ugha gksrs gS%&

(i) (ii)

(iii) (iv)

(1) i, ii, iii (2) ii, iii, iv

(3) i, ii, iv (4) i, iii, iv

58. ,d izFke dksfV dh vfHkfØ;k dh v/kZvk;q x lSd.M gSx2

lSd.M esa fdruk % Hkkx [kpZ gks tk;sxk :-

(1) 21% (2) 70%(3) 50% (4) 29.3%

59. bcc bZdkbZ lsy esa ijek.kqvksa }kjk ?ksjk x;k LFkku D;k gS:-

(1) 32

p(2)

6p

(3) 2 2

p(4)

38

p

60. fuEu esa fdl mPp pØ.k ladqy gsrw CFSE dk ekuvfèkdre gksxk

(1) [Mn(H2O)6]2+ (2) [Cr(H2O)6]

2+

(3) [Mn(H2O)6]3+ (4) [Cr(H2O)6]

3+

61. 2,2,6,6-VsVªkesfFky lkbDyksgsDlsukWy dks vEy ls vfHkdr

fd;k tkrk gS] rks ,d ,sYdhu curh gS ftldh lajpuk gksxh%&

(1) (2)

(3) (4)

62. ,d jsfM;ks/kehZ rRo x fuEu izdkj ls fo?kfVr gksrk gS

X 1k¾¾® P + a ; v/kZ vk;q = 30 min

P 2k¾¾® Q + 2b ; v/kZ vk;q = 24 hrs.

fuEu esa ls dkSulk vlR; gS :-

(1) fo?kVu fLFkjkad k1 < k2

(2) X rFkk Q leLFkkfud gS

(3) X dk nzO;eku la[;k P ls vf/kd gS

(4) P rFkk Q dk ijek.kq Øekad leku gS

27–04–2012


MAJOR TEST : AIIMS


63. The ionisation energy of the hydrogen atom isXKJ. The energy required for an electron to jumpfrom 3rd orbit to the 4th orbit will be :-

(1) X6

(2) 5X (3) 7.2X (4) 5X36

64. Which of the following will be most covalent:-(1) NaCl (2) Na2S(3) MgCl2 (4) MgS

65. Which of the following statement is wrong:

(1) Carbonyl compounds CH3– C| |O

–R give a

positive iodoform test(2) All secondary alcohols give iodoform

reaction

(3) Alkanols CH3CH(OH)–R give iodoformreaction.

(4) The only aldehyde given iodoform reaction isacetaldehyde.

66. The law of reciprocal proportion is applicablefor :-

(1) SO3, H2S, H2O (2) HCl, Cl2O7, NO2

(3) PH3, P2O5, N2O5 (4) H2SO4, SO3, H2O

67. Calculate the partial pressure of carbon monoxidefrom the following :-

CaCO3(s) � CaO(s) + CO2(g) ; KP = 8 × 10–2

CO2(g) + C(s) � 2CO(g) ; KP = 2

(1) 0.2 (2) 0.4

(3) 1.6 (4) 4

68. In which of the following set do all the threecompounds have bonds that are mainly ionic:-

(1) NaCl, NCl3, CCl4 (2) CsBr, BaBr2, SrO

(3) CsF, BF3, NH3 (4) Al2O3, CaO, SO2

69. Consider the given reaction:

CH3 – CH = CH – CH2 – OH N

HBrS 1'

¾¾¾® [P]

In the given reaction the product [P] is:

(1) CH3 – CH = CH – CH2 – Br

(2) CH3–

Br|CH – CH = CH2

(3) CH2 = CH – CH = CH2

(4) CH3 –

Br|CH – CH2 – CH2 – OH

63. gkbMªkstu ijek.kq dh vk;uu ÅtkZ XKJ gSA ,d bysDVªkWudks 3rd d{kk ls 4th d{kk esa igq¡pkus ds fy, vko';d ÅtkZD;k gksxh :-

(1) X6

(2) 5X (3) 7.2X (4) 5X36

64. fuEu esa ls lokZf/kd lgla;kstd ;kSfxd gS(1) NaCl (2) Na2S(3) MgCl2 (4) MgS

65. fuEu esa ls dkSulk dFku xyr gS%&

(1) dkcksZfuy ;kSfxd CH3– C| |O

–R vk;ksMksQkeZ ijh{k.k

n'kkZrs gS

(2) lHkh f}rh;d ,sYdksgkWy vk;ksMksQkeZ ijh{k.k n'kkZrs gS

(3) ,sYdsukWy CH3CH(OH)–R vk;ksMksQkeZ vfHkfØ;knsrs gS

(4) ,sfYMgkbMks esa dsoy ,flVksfYMgkbM vk;ksMksQkeZ

vfHkfØ;k nsrk gS

66. O;qRØekuqikrh dk fu;e fdlds fy, lgh gS :-

(1) SO3, H2S, H2O (2) HCl, Cl2O7, NO2

(3) PH3, P2O5, N2O5 (4) H2SO4, SO3, H2O

67. fuEufyf[kr ls dkcZu eksuk sDlkbM dk vkaf'kd nkcgksxk :-

CaCO3(s) � CaO(s) + CO2(g) ; KP = 8 × 10–2

CO2(g) + C(s) � 2CO(g) ; KP = 2

(1) 0.2 (2) 0.4

(3) 1.6 (4) 468. ;k Sfxdk s dk dk Sulk le qPp; eq[;r% vk;fud

gS :-(1) NaCl, NCl3, CCl4 (2) CsBr, BaBr2, SrO(3) CsF, BF3, NH3 (4) Al2O3, CaO, SO2

69. fuEu vfHkfØ;k ij fopkj dfj;s%&

CH3 – CH = CH – CH2 – OH N

HBrS 1'

¾¾¾® [P]

nh xbZ vfHkfØ;k esa mRikn [P] gS%&

(1) CH3 – CH = CH – CH2 – Br

(2) CH3–

Br|CH – CH = CH2

(3) CH2 = CH – CH = CH2

(4) CH3 –

Br|CH – CH2 – CH2 – OH

E / H 15/34

27–04–2012


MAJOR TEST : AIIMS


70. What will be mole fraction of 46% ofC2H5OH (w/w) :-(1) 0.75 (2) 0.25(3) 0.35 (4) 0.1

71. The initial pressure of COCl2 is 1000 torr. The totalpressure of the system becomes 1500 torr, when

the equilibrium COCl2(g)��CO(g) + Cl2(g) is

attained at constant temperature. The value of KP

of a reaction is :-(1) 1500 (2) 1000 (3) 2500 (4) 500

72. Ti and Zr can be purified by :-

(1) Mond's process

(2) Zone refining

(3) Van Arkel process

(4) Distillation73. For the given reaction

R – C – X

R1

R2

HOH¾¾¾® R – C – OH

R1

R2

Which substrate will give maximumracemisation?

(1) C H – C – Br6 5

CH3

C H2 5

(2) C H – C 6 5

Br

OCH3

CH3

(3) CH = CH – C – Br 2

CH3

C H2 5

(4)

C H – C 6 5

Br

NO2

NH3Å

70. 46% C2H5OH (w/w) dk ek sy i zHk kt D;kgksxk :-(1) 0.75 (2) 0.25(3) 0.35 (4) 0.1

71. COCl2 dk izkjfEHkd nkc 1000 torr gSA fLFkj rki ijtc lkE; COCl2(g)

�� CO(g) + Cl2(g) LFkkfirgk srk gS rc ra= dk dqy nkc 1500 torr gk srk g SAvfHkfØ;k ds fy, KP dk eku gksxk :-(1) 1500 (2) 1000(3) 2500 (4) 500

72. Ti rFkk Zr dk 'kqf¼dj.k fd;k tk ldrk gS :-

(1) ek.M izØe }kjk(2) tksu ifj"dj.k }kjk(3) oku vdZy fof/k }kjk(4) vklou }kjk

73. nh xbZ vfHkfØ;k ds fy;s %&

R – C – X

R1

R2

HOH¾¾¾® R – C – OH

R1

R2

dkSulk lcLVªsV vf/kdre jslsehdj.k nsrk gS\

(1) C H – C – Br6 5

CH3

C H2 5

(2) C H – C 6 5

Br

OCH3

CH3

(3) CH = CH – C – Br 2

CH3

C H2 5

(4)

C H – C 6 5

Br

NO2

NH3Å

27–04–2012


MAJOR TEST : AIIMS


74. Volume of NH3 gas obtained at 27°C and 1 atmpressure by complete hydrolysis of 100 gmof Mg3N2 ? (given molecular mass of Mg3N2 = 100)(1) 24.6 lit (2) 49.2 lit(3) 22.4 lit (4) 100 lit

75. How much volume of 0.2M solution of acetic acidshould be added to 100ml of 0.2M solution ofsodium acetate to prepare a buffer solution of pH5.00, pKa for acetic acid is 4.7 :-

(1) 100 mL (2) 50 mL

(3) 45 mL (4) 200 mL

76. In which of the following F-atom occupies thathybrid orbital which has maximum relatives-character :-

(1) CH3F (2) CH

2F

2(3) CHF

3(4) CF

4

77.

NH2

3CH Iexcess¾¾¾® A 2Ag O

moist¾¾¾® B D¾¾® C

In this reaction, C is -

(1)

I

(2) (3)

OH

(4)

78. 9.8% weight by volume H2SO4 and 3.65% weightby volume HCl is mixed. What will be normalityof resultant mixture ?

(1) 3

N2

(2) N20

(3) N50

(4) N

100

79. Incorrect set :

(I) Oxidising nature (I2 > Br2 > Cl2 > F2)

(II) IE1 (Na < Li < B < Be

(III) EA1 (N < P < O < S)

(IV) aq. ion radius (Na+ < Mg+2 < Al+3)

(1) Only I (2) I, II

(3) I, II, III (4) I, III

80. Iodine is formed when KI reacts with a solutionof :-

(1) ZnSO4

(2) CuSO4

(3) FeSO4

(4) (NH4)

2SO

4

74. 27°C rki rFkk 1 atm nkc ij 100 gm Mg3N2 dks tyvi?kVu l s NH3 dk vk;ru fdruk feysxk ?(fn;k gS Mg3N2 dk v.kqHkkj 100 gS)(1) 24.6 lit (2) 49.2 lit(3) 22.4 lit (4) 100 lit

75. pH 5.00 ; qDr cQj foy;u fufeZr djus ds fy;s100ml, 0.2M ,lhfVd vEy dk fdruk vk;rufeykuk gksxk\ ,lhfVd vEy ds fy;s pKa dk eku4.7 gS :-

(1) 100 mL (2) 50 mL

(3) 45 mL (4) 200 mL

76. dkSulk F-ijek.k q ml ladfjr d{kd lscU/k cukrk ftlesa lkis{k :i ls vf/kdre s-y{k.kgS :-

(1) CH3F (2) CH

2F

2(3) CHF

3(4) CF

4

77.

NH2

3CH Iexcess¾¾¾® A 2Ag O

moist¾¾¾® B D¾¾® C

bl vfHkfØ;k esa C gS%&

(1)

I

(2) (3)

OH

(4)

78. 9.8% (w/v) lY¶;wfjd vEy rFkk 3.65% (w/v) HCldks feyku s ij ifj.kkeh foy;u dh uke Zyrk D;kgksxh ?

(1) 3

N2

(2) N20

(3) N50

(4) N

100

79. vlR; leqPp; gS :

(I) Oxidising nature (I2 > Br2 > Cl2 > F2)

(II) IE1 (Na < Li < B < Be

(III) EA1 (N < P < O < S)

(IV) aq. ion radius (Na+ < Mg+2 < Al+3)

(1) Only I (2) I, II

(3) I, II, III (4) I, III

80. fdlds foy;u ds lkFk KI dh vfHkfØ;k djokus ijvk;ksMhu izkIr gksrk gS :-

(1) ZnSO4

(2) CuSO4

(3) FeSO4

(4) (NH4)

2SO

4

LoLFk jgks ] eLr jgks rFkk i <+kbZ esa O;Lr jgks A

E / H 17/34

27–04–2012


MAJOR TEST : AIIMS


81. In given demonstration of osmosis which of the

following not assist to create equilibrium :-

Pressure

(a) (b)

Sucrosesolution

Membrance

Water

(1) Rise in water level is funnel solution.

(2) Rise of hydrostatic pressure in funnel

solution

(3) Rise of solute concentration in funnel

solution.

(4) If sucrose diffuse out the funnel solution.

82. In the progenies of any cross, presence of

recombinants is due to:-

(1) Crossing over

(2) Linkage

(3) Lack of independent assortment

(4) All of the above

83. Select the correct match :-

Disease Pathogen

(A) Brown rust of (i) Virus

wheat

(B) Black rot of (ii) Bacteria

crucifers

(C) Turnip mosaic (iii) Fungi

(1) A – iii, B – i, C – ii

(2) A – i, B – ii, C – iii

(3) A – ii, B – iii, C – i

(4) A – iii, B – ii, C – i

81. fn;s x;s ijklj.k ds izn'kZu esa fuEu esa ls dkSu lkE;koLFkk

dh LFkkiuk esa lgk;d ugha gS :-

Pressure

(a) (b)

Sucrosesolution

Membrance

Water

(1) Quy foy;u esa ty Lrj dk c<+uk

(2) Quy foy;u esa æoLFkSfrd nkc dk c<+uk

(3) Quy foy;u esa foys; dh lkUærk dk c<+uk

(4) ;fn Quy foy;u ls 'kdZjk folfjr gks dj ckgj vk

tk;sA

82. fdlh ØkWl dh larfr;ksa esa iquZ;ksth;ksa dh mifLFkrh fdldsdkj.k gksrh gS\

(1) thu fofue;

(2) lgyXurk

(3) LorU= viO;wgu dh vuqifLFkrh

(4) mijksDr lHkh

83. lgh feyku dk p;u dhft, %&

jksx jksxtud

(A) xsgw¡ dk Hkwjk fdê (i) fo"kk.kq

(B) ØwlhQsjh dk dkyk (ii) thok.kq

fdê

(C) VuhZi ekstsd (iii) dod

(1) A – iii, B – i, C – ii

(2) A – i, B – ii, C – iii

(3) A – ii, B – iii, C – i

(4) A – iii, B – ii, C – i

J ges'kk eqLdjkrs jgs a A

27–04–2012


MAJOR TEST : AIIMS


84. Consider the following statements (A) – (D)each with one or two blanks :-

(A) In the cell envelope of the prokaryotes outermost .... . . . .(i).... . . . . . followed by the..... . . .(ii)... . . . . . . and then the plasmamembrane.

(B) Typically mitochondria having a diameter........(iii)......... .

(C) ........(iv)......... store carbohydrates whereas........(v)......... store proteins.

(D) Golgi apparatus consist of many flat, discshaped sacs or cisternae of ........(vi).........diameter.

Which one of the following options, gives thecorrect fill ups for the respectives blanksnumbers from (i) to (vi) in the statements :-

(1) (i) Glycocalyx (iii) 0.5 to 1 mm

(v) Amyloplast

(2) (ii) Cell wall (v) Aleuroplast

(vi) 0.5 to 1Å

(3) (ii) Glycocalyx (iii) 1.0 to 4.1 Å

(iv) Aleuroplast

(4) (ii) Cell wall (iv) Amyloplast

(vi) 0.5 to 1 mm

85. In Mineral nutrition of plants, C, H & O is obtainfrom :-

(1) Soil (2) Air

(3) Water (4) both (2) & (3)

86. The methods of DNA fingerprinting involvesthe use of :-

(1) Restriction enzymes

(2) Taq polymerase

(3) Oligonucleotide primers

(4) All the above

87. In a protein chain, the first amino acid is alsocalled :-

(1) N-terminal amino acid

(2) C-terminal amino acid

(3) Both of them

(4) None of the above

84. uhps fn, x, dFku (A) – (D) ij fopkj dhft;s ftuesa ,d

;k nks LFkku fjDr gSa :-

(A) izk sdsfj;ksfVd ds dksf'kdk vkoj.k es a cká ijr

. . . . . . . .(i).... . . . . . gk s ftlds i'pkr Øe'k%

........(ii)......... o thoæO; f>Yyh gksrh gSA

(B) ,d izk:ih ekbVksdksfMªa;k dk O;kl ........(iii).........

gksrk gSA

(C) ........(iv)......... esa dkcksZgkbMªsV lafpr gksrk gS tcfd

........(v)......... esa izksVhu lafpr gksrs gSaA

(D) xkWYth midj.k cgqr lkjh piVh fMLd vkdkj dh FkSyh

;k dq aM ls feydj cuh gk srh g S ftudk O;kl

........(vi)......... gksrk gSA

uhps fn;k x;k dkSulk ,d fodYi fjDr la[;k (i) ls (vi)

ds fy, mi;qZDr gSA

(1) (i) Glycocalyx (iii) 0.5 to 1 mm

(v) Amyloplast

(2) (ii) Cell wall (v) Aleuroplast

(vi) 0.5 to 1Å

(3) (ii) Glycocalyx (iii) 1.0 to 4.1 Å

(iv) Aleuroplast

(4) (ii) Cell wall (iv) Amyloplast

(vi) 0.5 to 1 mm

85. ikniksa ds [kfut iks"k.k esa ikni C, H o O fuEu esa ls fdlls

izkIr djrk gS :-(1) e`nk (2) ok;q

(3) ty (4) (2) o (3) nksuksa

86. DNA fingerprinting dh fof/k esa mi;ksx fd;k tkrk gS%&

(1) jsLVªhD'ku ,.MksU;wfDy,t dk

(2) Taq ikWyhejst dk

(3) vksfyxksU;wfDy;ksVkbM izkbej dk

(4) mijksDr lHkh dk

87. ,d izksVhu Ükà[kyk esa izFke vehuks vEy dks ; s Hkh dgrs

gSa %&

(1) N-terminal amino acid

(2) C-terminal amino acid

(3) mijksDr nksuksa

(4) mijksDr esa ls dksbZ ugha

viuh {kerk dks iwjk olwyus dk iz;kl djsa A

E / H 19/34

27–04–2012


MAJOR TEST : AIIMS


88. Identify the next stage of this figure and theirrespective events :-

(1) Anaphase ® Chromosome move toopposite pole

(2) Metaphase ® Initiation of assembly ofmitotic spindle

(3) Telophase ® Chromosome lost theiridentity

(4) None of these89. In this given diagram, Rubisco, NADPH + H+

and ATP are involved in which of followingsteps :-

X

Y

Z

Reductionb

a

cRegeneration

CO + H O2 2

Atmosphere

Carboxylation

Sucrose, starch(1)(a), (b) & (c) respectively(2) (a), (c) & (b) respectively(3) (c), (b) & (a) respectively(4) (c), (a) & (b) respectively

90. If probability of a Rh+ child is 50% by a couple,if they have five children, then find out theprobability of two Rh+ and three Rh– children:

(1) 1064

(2) 5

16

(3) 1

32(4)

14

88. fp= esa nh xbZ voLFkk dh vxyh voLFkk o mlls lEcfUèkr

?kVuk ds lkFk igpkfu;s :-

(1) i'pkoLFkk ® xq.klw= dk foijhr /kzqoksa dh vksj tkuk

(2) e/;koLFkk ® lelw=h rdqZ ds tekoM+s dh izfØ;k izkjaHk

gksuk

(3) vR;koLFkk ® xq.klw=ksa dh igpku dk lekIr gksuk

(4) fuEu esa ls dksbZ ughaA

89. fn;s x;s fp= esa Rubisco, NADPH + H+ rFkk ATPfuEu esa fdl pj.k esa lfEefyr gksrs gS :-

X

Y

Z

vip;ub

a

ciqu#n~Hkou

CO + H O2 2

ok;qe.My

dkcksZDlhys'ku

lqØkst] e.M(1) (a), (b) & (c) Øe'k%(2) (a), (c) & (b) Øe'k%(3) (c), (b) & (a) Øe'k%(4) (c), (a) & (b) Øe'k%

90. ;fn ,d tksM+s esa Rh+ cPpk gksus dh izkf;drk 50% gSa ;fnmuds ik¡p cPps gksa] rks nks ds Rh+ ,oa rhu ds Rh– gksus dhizkf;drk crkb;s :

(1) 1064

(2) 5

16

(3) 1

32(4)

14

27–04–2012


MAJOR TEST : AIIMS


91. In the structure of DNA molecule at each stepof ascent, the strand turns :-(1) 36° (2) 20°(3) 40° (4) 75°

92. The respiratory process is regulated byrespiratory rhythm centre present in medulla ofthe brain, which is ?(1) Stimulated by lower O2 and H+ concentration

in aortic arch(2) Inhibited by higher O2 and H+ concentration(3) Stimulated by higher CO2 and higher H+

concentration.(4) Stimulated by lower O2 and H+ concentration

in carotid artery.93. In Glycolysis how many steps are capable to

perform substrate level phosphorylation :-(1) 1 (2) 2 (3) 3 (4) 4

94. In genetic engineering, Agrobacterium and retrovirus are used as a vector for cloning genes inplants and animals, because :-

(1) They have ability to transform normal cellinto a tumour and cancerous cells

(2) They are easily available

(3) They infect all plant and animal cells

(4) They are pathogen

95. Highest cranial capacity is present in :-(1) Homosapians sapians (modern man)(2) Cromagnon man(3) Peking man(4) Neanderthal man

96. Which one of the following pairs of foodcomponents in humans reaches the stomachtotally undigested?(1) Starch and cellulose(2) Protein and starch(3) Starch and fat (4) Fat and cellulose

97. From systematics point of view select out theodd one :-(1) Dryopteris (2) Pteris(3) Adiantum (4) Selaginella

98. In which of the following group similar type ofepithelium is not found ?(1) Fallopian tubes and nasal passage(2) Buccal cavity and cornea of eye(3) Stomach and gall bladder(4) Thyroid follicles and peritoneum

91. DNA v.kq dh lajpuk esa fl<h ds izR;sd in ij LVªs.M dk?kqeko gksrk gS %&(1) 36° (2) 20°(3) 40° (4) 75°

92. 'olu izfØ;k dk fu;a=.k ef"r"d ds esM~;wyk esa mifLFkr'olu rky dsUnz ds }kjk gksrk gS] tks %&(1) /keuh pki esa mifLFkr O2 ,oa H+ dh de lkUnzrk ds

}kjk izsfjr gksrh gSA(2) mPp O2 ,oa H+ lkUnzrk ds }kjk vojksf/kr gksrh gSA(3) mPp CO2 ,oa mPp H+ lkUnzrk ds }kjk izsfjr gksrh

gSA(4) xzhok /keuh esa de O2 ,oa H+ lkUnzrk ds }kjk izsfjr

gksrh gSA93. Xykbdksykbfll ds nkSjku fdrus pj.k fØ;k/kkj Lrj

QkLQksfjyhdj.k dh ;ksX;rk j[krs gS :-(1) 1 (2) 2 (3) 3 (4) 4

94. vkuqokaf'kd vfHk;kafU=dh esa ,xzkscSDVhfj;e rFkk fjVªksokbjldk mi;ksx ikniksa rFkk tUrqvksa esa thu dh Dyksfuax ds fy,fd;k tkrk gS] D;ksafd %&

(1) buesa lkekU; dksf'kdk dks V~;wej esa rFkk dSUljdksf'kdkvksa esa :ikUrfjr djus dh {kerk gksrh gSA

(2) ;s vklkuh ls miyC/k gksrs gSaA

(3) ;s lHkh ikni rFkk tUrq dksf'kdkvksa dks laØfer djrs gSaA

(4) ;g jksx dkjd gSA

95. mPpre diky {kerk fdlesa mifLFkr gS %&(1) gkseks lsfi;Ul lsfi;Ul (vk/kqfud ekuo)(2) ØksesXuu ekuo(3) isfdax ekuo(4) fu,UMjFky ekuo

96. ekuoksa esa fuEufyf[kr esa ls fdl ,d tksM+s ds [kk| ?kVd

vkek'k; esa fcYdqy fcuk ips igq¡prs gSa ?

(1) LVkpZ vkSj lsyqykst (2) izksVhu vkSj LVkpZ

(3) LVkpZ vkSj olk (4) olk vkSj lsyqykst

97. ofxZdh; n`f"Vdks.k ls fo"ke dk pquko djs &

(1) Mªk;ksIVsfjl (2) Vsfjl

(3) ,sfM,sUVe (4) flysftuSyk

98. fuEu esa ls fdl lewg esa leku izdkj dh midyk ughaik;h tkrh gS ?(1) v.Mokfguh rFkk uklk ekxZ(2) eq[k xqgk rFkk us= ds dkfuZ;k(3) vkek'k; rFkk fiÙkk'k;(4) FkkbjkbM iqfVdk rFkk isjhVksfu;e

E / H 21/34

27–04–2012


MAJOR TEST : AIIMS


99. All birds and Mammals and a very few lowervertebrate and invertebrate species are:-(1) Regulator's(2) Conformers(3) ensures constant body temperature,

constant osmotic concentration(4) Both 1 and 3

100. Proenzyme pepsinogen is secreted by :-

(1) Oxyntic cells

(2) Goblet cells

(3) Parietal cells

(4) Chief cells

101. Aflatoxins are highly toxic carcinogenicchemicals produced by :-

(1) Drosophila of plant kingdom

(2) Ergot fungi

(3) Certain dinoflagellates

(4) Aspergillus102. The placenta are located inside the :-

(1) Stigma (2) Style

(3) Ovarian cavity (4) Ovule

103. Choose the incorrect pair:-

(1) Snails, fish - Aestivation

(2) Polar bears - Hibernation

(3) Zooplaktons - Diapause

(4) humming bird - Conformers

104. Which one of the following groups ofstructures/organs have similar function :-

(1) Typhlosole in earthworm, intestinal villi inrat and contractile vacuole in Amoeba

(2) Nephridia in earthworm, Malpighian tubulesin cockroach and urinary tubules in rat

(3) Antennae of cockroach, tympanum of frogand clitellum of earthworm

(4) Incisors of rat, gizzard (proventriculus) ofcockroach and tube feet of starfish

105. In India, most of the herbaria are arrangedaccording to which system of classification :-

(1) Engler and Prantl

(2) A.W. Eichler

(3) John Hutchinson

(4) Bentham and Hooker

99. lHkh i{kh rFkk Lru/kkjh o cgqr de fuEUk d'ks:dh rFkkvd'ks:dh tkfr;kWa gksrh gSa:-(1) fu;ked(2) l:aid(3) tks viuk rki fu;r cuk;s j[krs gSa rFkk ijklj.kh lkUæ.k

vkfn fLFkj j[krs gSaaA(4) mijksDr 1 o 3

100. izks,Utkbe isfIlukstu dk L=o.k gksrk gS :-(1) vkfDlf.Vsd dksf'kdkvksa }kjk(2) xkWCysV dksf'kdkvksa }kjk(3) iSjkbVy dksf'kdkvksa }kjk(4) phQ dksf'kdkvksa }kjk

101. ,sQykVªksfDlu] tks fd vR;f/kd fo"kSyk dsaljdkjd jlk;u

gS] mRiék fd;k tkrk gS &

(1) ikni txr ds MªkslksfQyk ls

(2) bjxksV dod ls

(3) dqN Mk;uks¶ysftysV~l ls

(4) ,liftZyl ls102. chtk.Mklu (vijk) fLFkr gksrk gS :-

(1) ofrZdkxz esa (2) ofrZdk esa(3) xHkkZ'k;h xqgk¡ esa (4) chtk.M esa

103. xyr ; qXe dks igpkfu;s:-(1) Lusy, eNyh - xzh"e fuæk(2) /kzqoh; Hkkyq - 'khr fuæk(3) tUrqIyod - mijfr(4) humming bird - la:id

104. fuEufyf[kr lajpukvksa@vaxks ds fdl ,d lewg esa lHkh dkdk;Z leku gS :-(1) dsapq, dk fV¶ykslksy] pwgs ds vka=&vadqj vkSj vehck

dh ladqapu'khy /kkuh(2) dsapq, ds o`Ddd (usfÝfM;k)] dkdjksp dh ekYih>h

ufydk,a vkSj pwgs dh ew= ufydk,a(3) dkdjksp ds ,s aVsuk] esa<+d dh d.kZiVg vkSj dsapw, dk

DykbVsye(4) pwgs ds Ïard] dkdjksp dk fxtMZ (izksosafVªdqyl) vkSj

LVkjfQ'k ds uyikn

105. Hkkjr esa] vf/kdka'kr% gjcsZfj;k dks fdl oxhZdj.k dh i¼fr

ds vuqlkj O;ofLFkr fd;k tkrk gS &

(1) ,Uxyj o izkUVy

(2) ,- MCY;w vkbdyj

(3) tkWu gfpulu

(4) csUFke o gqdj

Time Management is Life Management

27–04–2012


MAJOR TEST : AIIMS


106. Example of phloem fibres are :-(1) Jute (2) Flax(3) Hemp (4) All of the above

107. Among the following organism of whichcatagries face the maximum threat ofextinction:-(1) Mammals (2) amphibian(3) Birds (4) Fishes

108. What is difference between Hepatitis–B andAIDS ?(1) Mode of transmission(2) Pathogenecity(3) Genom(4) Both (2) and (3)

109. What is common in wheat, mammals, dogs andanimals :-(1) These are all taxa at different levels(2) These are taxa belong to same category(3) These are all taxa at same level in Linnaeus

hierarchy(4) These are all categories at different levels

110. Edible part of banana is :-

(1) Epicarp and Mesocarp

(2) Well developed mesocarp and lessdeveloped endocarp

(3) Less developed mesocarp and developedendocarp

(4) Epicarp and Endocarp

111. Who is a potent force in organic evolution:-

(1) Inter specific competition

(2) Inera specific competition

(3) Both 1 and 2

(4) None

112. NK-cell kills the target cells byreleasing :-

(1) Lymphokines

(2) Interleukins

(3) Specific lymphotoxins

(4) Nonspecific perforin

113. Which of the following trait is related to Turtle ?

(1) It is a garden Tortoise

(2) Fertilization is always internal

(3) Body is covered with glandular skin

(4) They do not have copulatory organs.

106. ¶yks,e js'kksa dk mnkgj.k gS :-(1) twV (2) ¶ysDl(3) gsEi (4) mijksDr lHkh

107. fuEufyf[kr Jsf.k;ksa esa ls fdldk lcls T;knk yqIr gksus dkladV gSa:-

(1) Lru/kkjh (2) mHk;pjh

(3) i{kh (4) eNfy;k108. ,M~l vkSj fgisVkbfVl–ch ds chp fHkUurk D;k gS ?

(1) laØe.k dk rjhdk

(2) jksxtudrk

(3) ftukse

(4) (2) vkSj (3) nksuksa

109. xsgw¡] Lru/kkjh] dqÙkk o tUrq esa D;k leku gS &

(1) ;s lHkh vyx&vyx Lrj ds oxZd gSA

(2) ;s lHkh oxZd ,d gh Js.kh ls lEcfU/kr gSA

(3) ;s lHkh oxZd fyfu;e inkuqØe esa leku Lrj ds gSA

(4) ;s lHkh vyx&vyx Lrj dh Js.kh;k¡ gSaA

110. dsys dk [kkus ;ksX; Hkkx gS :-

(1) cká fHkfÙk o e/; fHkfÙk

(2) lqfodflr e/; fHkfÙk o de fodflr vUr% fHkfÙk

(3) de fodflr e/; fHkfÙk o lqfodflr vUr% fHkfÙk

(4) cká fHkfÙk o vUr% fHkfÙk

111. dkSu tSo fodkl esa ,d 'kfDr'kkyh cy gSa:-(1) varjtkfr; Li/kkZ(2) varjktkfr; Li/kkZ(3) 1 o 2 nksuksa(4) dksbZ ugha

112. NK-dksf'kdk y{; dksf'kdkvksa dks] ds }kjk eqä djds ekjrhgS %&(1) fyEQksdkbUl(2) bUVjY;wdhUl(3) fof'k"V fyEQksVkWfDlu(4) vfof'k"V ijQksfju

113. fuEu esa ls dkSulk xq.k VVZy ls lEcfUèkr gS\(1) ;g ,d xkMZu dNqvk gSA(2) fu"kspu ges'kk vkUrfjd gksrk gSA(3) 'kjhj xzfUFky peZ ls <+dk jgrk gSA(4) buesa eSFkqukax ugha gksrs gSaA

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MAJOR TEST : AIIMS


114. What is the root of any plant breedingprogramme :-

(1) Selection

(2) Hybridisation

(3) Genetic variability

(4) Germplasm collection

115. The source of somatostatin is same as that of

(1) Thyroxine and calcitonin

(2) Insulin and glucagon

(3) Somatotropin and prolactin

(4) Vasopresin and oxytocin

116. Which type of germ cells are not present inpuberty to meno pause :-

(1) Oogonia

(2) Primary oocyte

(3) Secondary oocyte

(4) Ovum

117. Protochordates are those primary Chordateswhich posses

(1) Unpaired appendages

(2) Cranium and vertebrae

(3) Paired appendages

(4) Jaws and exoskeleton

118. 'Saccharum barberi' is the variety of sugarcanwith low sugar content and low yield. It ismainly grown in :-

(1) South India

(2) North India

(3) East India

(4) West India

119. A feeling of pain in one's stomach would bedue :-

(1) Exteroceptors

(2) Teloreceptor

(3) Proprioceptors

(4) Interoceptors

120. Log phase of S-shaped / sigmoid growth curveof human contains :-

(1) +ve acceleration

(2) –ve acceleration

(3) Exponential phase

(4) All

114. fdlh Hkh ikni iztuu dk;ZØe dk ewy vk/kkj gS %&

(1) p;u

(2) ladj.k

(3) tufud fofHkUurk

(4) tuuæO; laxzg.k

115. lkseSVksLVSfVu dk L=ksr ogh gS] tks :-(1) FkkbjkWDlhu rFkk dSfYlVksfuu dk gS(2) balqfyu rFkk XywdSxkWu dk gS(3) lkSesVksVªksfiu rFkk izksySfDVu dk gS(4) oslksizsflu rFkk vkWDlhVkslhu dk gS

116. dkSuls izdkj dh teZ dksf'kdk;s ehuksikWt ls ySafxd O;Ldrkesa mifLFkr ugha gksrh gS %&(1) Åxksfu;k(2) izkFkfed ÅlkbV(3) f}rh; ÅlkbV(4) v.Mk.kq

117. izksVksdksMsZV~l os izkFkfed dkMZsV gS] ftuesa ik;k tkrkgSA(1) v;qfXer mikax(2) diky o d'ks:d(3) ;qfXer mikax(4) tcMs+ o ckº; dadky

118. 'lSdsje ckjcsjh* xUus dh fdLe gS ftlesa 'kdZjk ?kVd fuEugksrk gS o mRiknu Hkh de gSA ;g eq[;r% mxk;k tkrkgS %&(1) nf{k.k Hkkjr(2) mÙkj Hkkjr(3) iwohZ Hkkjr(4) if'peh Hkkjr

119. fdlh ,d O;fDr dks vek'k; esa nnZ dk ,glkl gks jgk gS]rks ;g fdlds dkj.k gksxk :-(1) ,DlfVjkslsIVlZ(2) VsyksfjlsIVlZ(3) izksfizvkslsIVlZ(4) bUVhjkslsIVlZ

120. euq"; ds S-vkdkj/ flxek,M o`f¼ oØ esa ykSx izoLFkk esagksrk gS :-(1) /kukRed Roj.k(2) ½.kkRed Roj.k(3) pj?kkrkadh izoLFkk(4) mijksDr lHkh

27–04–2012


MAJOR TEST : AIIMS


DIRECTIONS FOR Q. NO. 121 TO 180

These questions consist of two statements each,printed as Assertion and Reason.Whileanswering these Questions you are required tochoose any one of the following four responses.

A. If both Assertion & Reason are True & theReason is a correct explanation of the Assertion.

B. If both Assertion & Reason are True but Reasonis not a correct explanation of the Assertion.

C. If Assertion is True but the Reason is FalseD. If both Assertion & Reason are false.

121. Assertion :- Electric lines are always straightand continuous.Reason :- Electric lines represents electric field.(1) A (2) B (3) C (4) D

122. Assertion :- In Telescope we use objective lenswith large apertureReason :- Lerge aperture of objective lensreduces spherical afferative.

(1) A (2) B (3) C (4) D123. Assertion :- If the ice cap of the pole melts,

the day length will shortenReason :- On melting ice will flow towards theequator and decrease the moment of inertia ofthe earth. This increase the frequency of rotationof the earth(1) A (2) B (3) C (4) D

124. Assertion :- Early rise of sun is due to totalinternal reflection.Reason :- Lower atmosphere has density morethan upper atmosphere.(1) A (2) B (3) C (4) D

125. Assertion : A domestic electrical applianceworking on a three pin, will continue workingeven if the top pin is removedReason : The third pin is used only as a safetydevice.(1) A (2) B (3) C (4) D

126. Assertion :- Compass needle shows magneticmeridian (except magnetic poles).Reason :- Axis of Rotation of earth passesthrough Geographical North-south pole.(1) A (2) B (3) C (4) D

127. Assertion :- Electric potential energy of anypositive charge is always positive.Reason :- Potential energy is a relative quantity.(1) A (2) B (3) C (4) D

iz'u la[;k 121 ls 180 ds fy, funs Z'k

izR;sd iz'u es a dFku rFkk dkj.k fn, x;s gSaA iz'uks a

dks gy djrs le; uhps fn, x, pkjks a fodYiks a es als lgh fodYi dks pqfu,A

A. ;fn dFku ,oa dkj.k nksuks a lR; ga S rFkk dkj.k dFkudk lgh Li"Vhdj.k gSA

B. ;fn dFku ,oa dkj.k nksuks a lR; gaS] ysfdu dkj.k] dFkudk lgh Li"Vhdj.k ugha gSA

C. ;fn dFku lR; gS] ysfdu dkj.k vlR; gSAD. dFku o dkj.k nksuks a vlR; gSaA121. dFku :- fo|qr cy j s[kk;s a lnSo lh/kh ,oa lrr~

gksrh gSA

dkj.k :- fo|qr cy js[kk;sa fo|qr {ks= dks crkrh gSA(1) A (2) B (3) C (4) D

122. dFku :- nwjn'khZ esa vfHkn';d ySal dk }kjd cM+k gksrkgSAdkj.k :- vfHkn`';d dk }kjd cM+k gksus ls xksyh; oxZfoiFku de gks tkrk gSA(1) A (2) B (3) C (4) D

123. dFku :- ;fn /kzqoksa dh cQZ fi?kyrh gS rks fnu dh yEckbZde gks tk,sxh Adkj.k :- cQZ fi?kyus ij Hkwe/; js[kk dh vksj izokfgr gksxhrFkk i`Foh dk tM+Ro vk?kw.kZ ?kVsxkA ;g i`Foh ds ?kw.kZu dhvko`fr c<+krk gSA(1) A (2) B (3) C (4) D

124. dFku :- lw;Z ds tYnh mxus dk dkj.k iw.kZ vkUrfjd ijkorZugSAdkj.k :- ok;qe.My ds uhpys Lrj dk ?kuRo Åijh Lrjds ?kuRo ls T;knk gksrk gSA(1) A (2) B (3) C (4) D

125. dFku :– ,d ?kjsyw oS|qr ; qfä 3-fiu ij dk;Z dj jghgS] ;fn mijh fiu dks gVk fn;k tk; rks Hkh oS|qr ; qfä dk;Zdjrh jgsxhA

dkj.k : rhljh fiu lqj{kk dh n`f"V ls yxkbZ tkrh gSA(1) A (2) B (3) C (4) D

126. dFku :- dEikl lqbZ pqEcdh; ;ke;ksÙkj dks iznf'kZr djrhgSA (pqEcdh; /kzqoksa dks NksM+ dj)Adkj.k :- i`Foh dk ?kw.kZu v{k HkkSxksfyd mÙkj&nf{k.k èkzqols xqtjrk gSA(1) A (2) B (3) C (4) D

127. dFku :- fdlh /kukRed vkos'k dh fo|qr fLFkfrt ÅtkZges'kk /kukRed gksrh gSAdkj.k :- fLFkfrt ÅtkZ ,d lkis{k jkf'k gSA(1) A (2) B (3) C (4) D

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MAJOR TEST : AIIMS


128. Assertion : A particle executing SHM takes lesstime to travel distance from x = 0 to x = A/2 as compare to time taken in travelling thedistance from x = A/2 to x = A.

Reason : As the particle comes near to the meanposition of SHM, its velocity increases.

(1) A (2) B (3) C (4) D

129. Assertion :- Soft and hard X-rays differ infrequency as well as in velocity.

Reason :- The penetrating power of hard X-raysis less than the penetrating power of soft X-rays.

(1) A (2) B (3) C (4) D

130. Assertion :- If mass of the bob of simplependulum increases then restoring torqueincreases.Reason :- Restoring torque a mass of bob.

(1) A (2) B (3) C (4) D131. Assertion :- Hydrogen atom consists of only

one electron but its emission spectrum hasmany lines.Reason :- Only Lyman series is found in theabsorption spectrum of hydrogen atomwhereas in the emission spectrum, all the seriesare found.(1) A (2) B (3) C (4) D

132. Assertion :- When range of a projectile ismaximum its angle of projection may be 45°or 135°Reason :- Whether q is 45° or 135°, value ofrange remains the same, only the sign charges

(1) A (2) B (3) C (4) D133. Assertion :- Radioactivity of 108 undecayed

radioactive nuclei of half life of 50 days is equalto that of 1.2 × 108 number of undecayednuclei of some other material with half life of60 daysReason :- Radioactivity is proportional to half-life.(1) A (2) B (3) C (4) D

134. Assertion :- The average and instantaneousvelocities have same value in a uniform motion.Reason :- In uniform motion the velocity ofan object increases uniformly.

(1) A (2) B (3) C (4) D

128. dF ku : ljy vkorZ xfr dj jgs ,d d.k dk sx = 0 ls x = A/2 rd tkus es a yxus okyk le;x = A/2 ls x = A rd tkus esa yxus okys le; ls degksrk gSA

dkj.k : tSls&tSls d.k SHM dh ek/;koLFkk ds fudVigq¡prk gS mldk osx c<+rk tkrk gSA

(1) A (2) B (3) C (4) D

129. dFku :- e`nq ,oa dBksj X-fdj.ksa vkofÙk vkSj osx esa ,d nwljsls vyx gksrh gSaA

dkj.k :- dBksj X-fdj.kksa dh Hksnu {kerk e`nq X-fdj.kksa dhHksnu {kerk ls de gksrh gSA

(1) A (2) B (3) C (4) D

130. dFku :- ;fn ljy yksyd ds xksyd dk æO;eku c<+s rks

izR;ku;u cyk?kw.kZ c<+rk gSA

dkj.k :- izR;ku;u cyk?kw.kZ a nksyd dk æO;ekuA

(1) A (2) B (3) C (4) D

131. dFku :- gkbMªkstu ijek.kq esa dsoy ,d bysDVªkWu gksrk gS ijUrq

blds mRltZu LisDVªe esa dbZ js[kk;sa gksrh gSA

dkj.k :- gkbMªkstu ijek.kq ds vo'kks"k.k LisDVªe esa dsoy

ykbeu Js.kh izkIr gksrh gS tcfd mRltZu LisDVªe esa lHkh

Jsf.k;k¡ izkIr gksrh gSA

(1) A (2) B (3) C (4) D

132. dFku :- tc iz{ksI; dh ijkl vf/kdre gksrh gS] bldsiz{ksi.k dks.k 45° vFkok 135° gksrs gSAdkj.k :- ;fn q = 45° vFkok 135° gks] ijkl dkeku leku jgrk gS] rFkk dsoy fpUg~ esa vUrj vkrkgSA(1) A (2) B (3) C (4) D

133. dFku :- vðZ vk;q 50 fnu okys 108 vfo?kfVr jsfM;kslfØ;

ukfHkdksa dh jsfM;kslfØ;rk vðZ&vk;q 60 fnu okys

1.2 × 108 vfo?kfVr vU; jsfM;kslfØ; ukfHkdks a dh

lfØ;rk ds rqY; gSA

dkj.k :- jsfM;kslfØ;rk vðZ&vk;q ds vuqØekuqikrh gksrh gSA

(1) A (2) B (3) C (4) D

134. dFku :- ,d leku xfr esa vkSlr ,oa rkR{kf.kd osxksa dsleku eku gksrs gSAdkj.k :- ,d leku xfr esa oLrq dk osx ,dleku :ils c<+rk gSA(1) A (2) B (3) C (4) D

27–04–2012


MAJOR TEST : AIIMS


135. Assertion :- An adiabitic curve is steeper thanan isothermal curve.

Reason :- In an adiabatic process, change ininternal energy is equal to work done on orby the gas.

(1) A (2) B (3) C (4) D

136. Assertion :- According to Newton's third law"to each action there is equal and oppositereaction".

Reason :- Action is the cause and reaction isits effect.

(1) A (2) B (3) C (4) D

137. Assertion :- In pressure-temperature (P-T)phase diagram of water, the slope of meltingcurve is found to be negative.

Reason :- Ice contracts on melting.

(1) A (2) B (3) C (4) D

138. Assertion :- Inertia is the property by virtue ofwhich the body is unable to change by itselfthe state of rest only.Reason :- In uniform circular motion velocityremains constant.

(1) A (2) B (3) C (4) D139. Assertion :- In generator when we rotate a coil

in magnetic field we get electrical energy.Reason :- Magnetic energy converts intoelectrical energy in this case

(1) A (2) B (3) C (4) D140. Assertion :- If momentum of a body is increases

by 50%. Its kinetic energy is increased by125%.Reason :- Kinetic energy is proportional tosquare of velocity.(1) A (2) B (3) C (4) D

141. Assertion :- Glucose and fructose are functionalisomers of each otherReason :- Glucose is aldehydic sugar with 6Cwhile fructose is ketonic sugar with 6C(1) A (2) B (3) C (4) D

142. Assertion :- In 1 mol of H2SO4 solution thenumber of equivalent of H+ is equal to number

of equivalent of 2–4SO

Reason :- The ions follows law of equivalence(1) A (2) B (3) C (4) D

135. dFku :- ,d :¼ks"e oØ ,d lerkih; oØ ls vf/kd [kM+kgksrk gSA

dkj.k :- :¼ks"e izØe esa] xSl ij ;k }kjk fd;k x;kdk; Z vkUrfjd Åtk Z es a ifjorZu ds cjkcj gk srhgSA

(1) A (2) B (3) C (4) D

136. dFku :- U;wVu ds rhljs fu;e ds vuqlkj ^îzR;sd fØ;k

dh leku ,oa foijhr izfrØ;k gksrh gS**

dkj. k :- fØ;k dkj.k g S ,oa i z frfØ;k mldk

izHkkoA

(1) A (2) B (3) C (4) D

137. dFku :- ikuh dk nkc&rkieku (P–T) voLFkk oØ eas

xyu oØ dk <ky ½.kkRed gksrk gSA

dkj.k :- fi?kyus ij cQZ fldqM+rh gSA

(1) A (2) B (3) C (4) D

138. dFku :- tM+Ro oLrq dk og xq.k gS ftlds dkj.k oLrqdsoy viuh fojkekoLFkk esa ifjorZu djus esa vleFkZ gksrhgSAdkj.k :- ,d leku o`Ùkh; xfr es a osx fu;r gksrkgSA(1) A (2) B (3) C (4) D

139. dFku :- tfu= esa tc ge dq.Myh dks pqEcdh; {ks= esa?kqekrs gS rks fo|qr ÅtkZ izkIr gksrh gSAdkj.k :- bl fLFkfr esa pqEcdh; ÅtkZ] fo|qr ÅtkZ esa ifjofrZrgks tkrh gSA(1) A (2) B (3) C (4) D

140. dFku :- ;fn fdlh oLrq ds laosx esa 50% dh o`f¼ gksrh

gS rks mldh xfrt esa 125% dh o`f¼ gksrh gSA

dkj.k :- xfrt ÅtkZ osx ds oxZ ds vuqØekuqikrh gksrh

gSA(1) A (2) B (3) C (4) D

141. dFku :- Xywdksl ,oa ÝDVksl ,d nwljs ds fØ;kRedleko;oh gksrs gSdkj.k :- Xywdksl 6C ;qDr ,fYMgkbfMd 'kdZjk gS tcfdÝDVksl 6C ;qDr dhVksuhd 'kdZjk gksrh gS(1) A (2) B (3) C (4) D

142. dFku :- 1 eksy H2SO4 foy;u esa H+ ds rqY;kadksa dh la[;k2–4SO ds rqY;kadksa dh la[;k ds leku gSA

dkj.k :- vk;uksa dh la[;k rqY;rk ds fu;e dk vuqlj.kdjrs gSA(1) A (2) B (3) C (4) D

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MAJOR TEST : AIIMS


143. Assertion :- O

O

D¾¾®+

(Major)

Reason :- 2-Butene is more stable than1-butene as it having more a a – H

(1) A (2) B (3) C (4) D

144. Assertion :- 2.5 mol NaCl and 5 mol glucosehave same colligative properties.Reason :- Colligative properties depends onnumber of particle of solute.(1) A (2) B (3) C (4) D

145. Assertion :- Ethyl acetate is more reactive thanacetamide towards nucleophilic substitutionreaction.

Reason :- 2NH

1 ion is less basic than RO1 ion

(1) A (2) B (3) C (4) D146. Assertion :- A particle present at corner of the

unit cell contributes its 1

th8

part to the unit cell.

Reason :- In any space lattice, the corner ofthe unit cell is always shared by the eightunit cells.(1) A (2) B (3) C (4) D

147. Assertion :- The –OH group attached tobenzene ring activates it towards electrophillicsubstitutionReason :- The –OH group is an electron-releasing group(1) A (2) B (3) C (4) D

148. Assertion :- If KC > 10–3 then productspredominate over reactants.Reason :- Large value of K indicates thatproducts are less stable.(1) A (2) B (3) C (4) D

149. Assertion :- p-nitrophenol boil at hightemperature than o-nitrophenol

Reason :- In p-nitrophenol, the –OH group ofone molecule forms hydrogen bond with the–NO2 group of the other molecule(1) A (2) B (3) C (4) D

150. Assertion :- PbI4 is a Stable compound.Reason :- Iodide stabilizes higher oxidationstate.(1) A (2) B (3) C (4) D

143. dFku :- O

O

D¾¾®+

( )eq[;

dkj.k :- vf/kd a – H gksus ds dkj.k 2-C;wVhu] 1-C;wVhuls vf/kd LFkk;h gksrh gS(1) A (2) B (3) C (4) D

144. dFku :- 2.5 eksy NaCl vkSj 5 eksy Xywdkst dhv.kqla[;d xq.k/keZ leku gksxsaAdkj.k :- v.kqla[;d xq.k/keZ foys; ds d.kksa dh la[;kij fuHkZj djrk gSA(1) A (2) B (3) C (4) D

145. dFku :- ukfHkd LU ksgh izfrLFkkiu vfHkfØ;k esa ,fFky,flVsV],flVkekbM dh rqyuk esa vf/kd fØ;k'khy gSA

dkj.k :- 2NH

1 vk;u RO1 dh rqyuk esa de {kkjh; gksrk

gS(1) A (2) B (3) C (4) D

146. dFku :- ,d vUr% dsfUær bdkbZ dksf'kdk ds dksuksa ij fLFkr

ijek.kq dk izfr bdkbZ dksf'kdk esa ;ksxnku 18

gksrk gSA

dkj.k :- fdlh Hkh tkyd lajpuk esa bdkbZ dksf'kdk ds dksusij fLFkr ijek.kq ges'kk 8 bdkbZ dksf'kdk esa ;ksxnku djrkgSA(1) A (2) B (3) C (4) D

147. dFku :- casthu oy; ij fLFkr –OH lewg oy; dks

bysDVªkuLusgh izfrLFkkiu ds fy;s lfØ; cukrk gS

dkj.k :- –OH lewg ,d bysDVªkWu fod"khZ lewg gS

(1) A (2) B (3) C (4) D

148. dFku :- ;fn KC > 10–3 gks rks mRikn] vfHkdeZdksa ds vis{kkvf/kd gksrs gSAdkj.k :- K dk vf/kd eku n'kkZrk gS dh mRikn de LFkk;hgSA(1) A (2) B (3) C (4) D

149. dFku :- p-ukbVªksQhukWy o-ukbVªksQhukWy dh rqyuk esa mPprki ij mcyrk gS

dkj.k :- p-ukbVªksQhukWy esa] ,d v.kq dk –OH lewg nwljsv.kq ds –NO2 lewg ds lkFk H-ca/k cukrk gS

(1) A (2) B (3) C (4) D

150. dFku :- PbI4 ,d LFkk;h ;kSfxd gSAdkj.k :- vk;ksMkbM] mPp vkWDlhdj.k voLFkk dks LFkk;hj[krk gSA(1) A (2) B (3) C (4) D

27–04–2012


MAJOR TEST : AIIMS


151. Assertion :- Chloral is more reactive thanformaldehyde towards NAR

Reason :- IUPAC name of chloral istrichloronitromethane

(1) A (2) B (3) C (4) D

152. Assertion :- SiF6–2 is known but SiCl6

–2 is not.Reason :- Size of F is small and the ion pairof electron present interact with d orbital of Sistrongly.(1) A (2) B (3) C (4) D

153. Assertion :- CH3–I is less reactive than

CH3–F

Reason :- The bond dissociation energy of

C–I is greater than C–F

(1) A (2) B (3) C (4) D154. Assertion :- SeCl4 does not have a tetrahydral

shape.Reason :- Se in SeCl4 has two lone pairs ofelectrons.(1) A (2) B (3) C (4) D

155. Assertion :- heat of neutralization of HF(aq.)and NaOH is less than 13.7 kcal. in anexothermic reaction.

Reason :- Some heat is used for ionization ofweak acid.

(1) A (2) B (3) C (4) D

156. Assertion :- Trans-[COCl2(en)2]+ is optically

active.

Reason :- It is an octahydral complex.

(1) A (2) B (3) C (4) D

157. Assertion :- Physiosorption is a multilayeredprocess.

Reason :- It is non specific in nature.

(1) A (2) B (3) C (4) D

158. Assertion :- In aqueous solution, Mohr's saltgives NH+

4, Fe+2 and SO4–2 ions.

Reason :- It is a double salt.

(1) A (2) B (3) C (4) D

159. Assertion :- 1 amu is equal to A

1N

g

Reason :- It is known as unified

(1) A (2) B (3) C (4) D

151. dFku :- NAR ds fy;s Dyksjy] QkesZfYMgkbM dh rqyuk

esa vf/kd fØ;k'khy gksrk gSdkj.k :- Dyksjy dk IUPAC uke VªkbDyksjksukbVªksesFksu gksrk

gS(1) A (2) B (3) C (4) D

152. dFku :- SiF6–2 Kkr gS ijUrq SiCl6

–2 ughaA

dkj.k :- F vkdkj NksVk gS rFkk Si ds fjDr d-d{kd ds

lkFk blds lp izcy vUrfØZ;k djrs gSA

(1) A (2) B (3) C (4) D

153. dFku :- CH3–I, CH3–F dh rqyuk esa de fØ;k'khy gksrk

gSdkj.k :- C–I dh ca/k fo;kstu ÅtkZ C–F ls vf/kd gksrh

gS(1) A (2) B (3) C (4) D

154. dFku :- SeCl4 dh vkÏfr prq"Qydh; ugha gk srhgSAdkj.k :- SeCl4 esa Se ds ikl nks ,dkadh bysDVªkWu ;qXegSA(1) A (2) B (3) C (4) D

155. dFku :- NaOH vkSj HF(aq.) dh mnklhuhdj.k Å"ekdk eku 13.7 kcal. ls de gksrk gS tks fd ,d Å"ek {ksihvfHkfØ;k gSA

dkj.k :- nqcZy vEy ds vk;uhdj.k esa dqN Å"ek [kpZgks tkrh gSA

(1) A (2) B (3) C (4) D

156. dFku :- foi{k-[COCl2(en)2]+ izdkf'kd lfØ;

gSA

dkj.k :- ;g ,d v"VQydh; ladqy gSA

(1) A (2) B (3) C (4) D

157. dFku :- HkkSfrd vf/k'kks"k.k ,d cgqirhZ; vf/k'kks"k.k gSA

dkj.k :- HkkSfrd vf/k'kks"k.k fof'k"V izÏfr dk ughagSA

(1) A (2) B (3) C (4) D

158. dFku :- tyh; foy;u esa eksgj yo.k NH+4, Fe+2 rFkk

SO4–2 vk;u nsrk gSA

dkj.k :- ;g ,d f}d yo.k gSA

(1) A (2) B (3) C (4) D

159. dFku :- 1 amu ; A

1N

g ds leku gSA

dkj.k :- 1 amu dks gh ; wuhQkbM ds uke ls tkurs gSA

(1) A (2) B (3) C (4) D

E / H 29/34

27–04–2012


MAJOR TEST : AIIMS


160. Assertion :- The inner transition elements areplaced in III B group.

Reason :- The most stable oxidation state ofinner transition elements is +3.

(1) A (2) B (3) C (4) D

161. Assertion :- Like growth in plants,differentiation is also open.

Reason :- In plants meristematic cell productscan take part in determinate or indeterminategrowth.

(1) A (2) B (3) C (4) D

162. Assertion :– Plant having odd number of setsof chromosomes are fertile.

Reason :– Plant having even number of sets ofchromosomes are sterile.

(1) A (2) B (3) C (4) D

163. Assertion :- All the cofactors are alwayscoenzymes.

Reason :- Cofactors are always nonproteinaceous organic substanes which regulatecatalytic activity of an enzyme.

(1) A (2) B (3) C (4) D

164. Assertion :– Colchicine induces polyploidy.

Reason :– Colchicine causes disjuncton ofchromosomes.

(1) A (2) B (3) C (4) D

165. Assertion :- Sporophyte of mosses is partialparasite over gametophyte.

Reason :- Sporophyte of mosses is ofphotosynthetic nature but absorbs water andminerals from gametophyte.

(1) A (2) B (3) C (4) D

166. Assertion :– Change in structure of chromosomeis called chromosomal aberration.

Reason :– Substitution is an example ofchromosomal aberration

(1) A (2) B (3) C (4) D

167. Assertion :- Protists can reproduce sexually ascompared to monerans.

Reason :- In Protists well developed and distinctsex organs are present.

(1) A (2) B (3) C (4) D

160. dFku :- vUr% laØe.k rRoksa dks III B oxZ esa j[kk x;kgSA

dkj.k :- vUr% laØe.k rRoksa dh LFkk;h vkWDlhdj.k voLFkk+3 gksrh gSA

(1) A (2) B (3) C (4) D

161. dFku :- ikniksa esa o`fð dh rjg gh] foHksnu Hkh [kqys izdkjdk gksrk gSA

dkj. k :- iknik s a e s a foHkT;k srd dk s f'kdk dsmRikn fu/kkZfjr vFkok vfu/kkZfjr ofð esa Hkkx ys ldrsgSA

(1) A (2) B (3) C (4) D

162. dFku :– fo"ke la[;k okys xw.klw=h lsV j[kus okys iknituu{ke gksrs gaSA

dkj.k :– le la[;k okys xw.klw=h lsV j[kus okys ikni caè;gksrs gSaA

(1) A (2) B (3) C (4) D

163. dFku :- lHkh lg dkjd lnSo dks,Utkbe gksrs gSA

dkj.k :- lg dkjd lnSo vizk sVhuh; izÏfr dsdkc Zfud jlk;u gk sr s g S a tk s ,d ,Utkbedh mRi z sjdh; fØ;k'khyrk dk s fu/k k Z fjr djrsgSA

(1) A (2) B (3) C (4) D

164. dFku :– dksYphlhu cgqxq.khrk izsfjr djrk gSA

dkj.k :– dksYphlhu xw.klw=ksa dk foikVu djrk gSA

(1) A (2) B (3) C (4) D

165. dFku :- ekWl dk chtk.kqn~fHkn ;qXedksn~fHkn ij vkaf'kdijthoh gksrk gSA

dkj.k :- ekWl dk chtk.kqn~fHkn izdk'kla'ys"kh izdfr dk gksrkgS ysfdu ty o feujy dks ;qXedksn~fHkn ls vo'kksf"kr djrkgSA

(1) A (2) B (3) C (4) D

166. dFku :– xw.klw=ksa dh ljapuk esa ifjorZu gksuk xw.klw=h foiFkudgykrk gSA

dkj.k :– izfrLFkkiu xw.klw=h foiFku dk mnkgj.k gksrkgSA

(1) A (2) B (3) C (4) D

167. dFku :- izksfVLVk eksusjk dh rqyuk esa ySafxd tuu }kjk tuudj ldrs gSaA

dkj.k :- izksfVLVk esa vR;f/kd fodflr o Li"V ySafxd vaxik;s tkrs gSaA

(1) A (2) B (3) C (4) D

27–04–2012


MAJOR TEST : AIIMS


168. Assertion :- The morphological and anatomicalfeature of parasites are greatly simplified ofparasite while emphasising their reproductivepotentialReason :- The life cycles of endoparasites aremore complex(1) A (2) B (3) C (4) D

169. Assertion :- Many cnidarians like polyps giverise to medusae by vegetative budding.Reason :- Many cnidarians like Obelia passthrough both polyp and medusae.(1) A (2) B (3) C (4) D

170. Assertion :- The evoluton of the flower and itspollinator species are tightly linked with oneanother there is a tight one to one relationship.Reason :- The mutually beneficial system is safeguarded against cheaters.(1) A (2) B (3) C (4) D

171. Assertion :- In Antirrhinum incompletedominance is found.Reason :- Heterozygous red [Rr] flowered plant,when crossed with white [r r] flowered plant,produces all pink flowered offsprings.(1) A (2) B (3) C (4) D

172. Assertion :- Diabetes insipidus is marked byexcessive urination and too much thirst forwater.

Reason :- Anti-diuretic hormone (ADH) issecreted by the posterior lobe of pituitary gland.

(1) A (2) B (3) C (4) D

173. Assertion :- Citric acid is obtained fromAcetobacter.

Reason :- By fermentation of acetaldehyde,Acetobacter produces citric acid.

(1) A (2) B (3) C (4) D

174. Assertion :- Piameter forms telochoroidea, inventricle.Reason :- Piameter is highly vascular.(1) A (2) B (3) C (4) D

175. Assertion :- Frog will die in few days if it isstopped forcibly to come on the surface ofwater.Reason :- Frog will unable to respire or feedproperly.(1) A (2) B (3) C (4) D

168. dFku :- ijthfo;ksa ds vkdkfjdh; rFkk 'kkdkfjd y{k.k

vR;f/kd ljyhd`r gSa] tcdh mudh tuu {kerk vf/kd gSaA

dkj.k :- vUrijthfo;k dk thou pØ vR;f/kd tfVy

gksxkA

(1) A (2) B (3) C (4) D

169. dFku :- dbZ fuMsfj;u] tSls iksfyi dkf;d tuu }kjk esMqqlkmRiUu djrk gSAdkj.k :- dbZ fuMsfj;u] tSls vkscsfy;k ikfyi o esMqlk nksuksavoLFkkvksa ls xqtjrk gSA(1) A (2) B (3) C (4) D

170. dFku :- iq"i vkSj blds ijkx.kdkjh tkfr;ksa ds fodkl ,d

nwljs ls etcwrh ls tqMs gq,s gSaA

dkj.k :- ijLij ykHkdkjh rFkk /kks[ksckth ls j{kk ds fy,

gksrk gSaA

(1) A (2) B (3) C (4) D

171. dFku :- Antirrhinum esa viw.kZ izHkkfork ikbZ tkrh gSA

dkj.k :- fo"ke;qXeh yky [Rr] iq"i okys ikni dk tc

lQsn iq"i [r r] okys ikni ls ØkWl fd;k tkrk gS] tks lkjh

larfr;k¡ xqykch iq"i okyh mRiUu gksrh gS

(1) A (2) B (3) C (4) D

172. dFku :- Mk;fcVht buflfiMl dh [kkl igpku gS fdblesa T;knk is'kkc vkrk gS vkSj ikuh dh I;kl cgqr yxrhgSAdkj.k :- ADH dk L=ko.k ih;w"k xzafFk dh i'p ikfy lsgksrk gSA(1) A (2) B (3) C (4) D

173. dFku :- flVªhd vEy ,lhVkscSDVj ls izkIr fd;k tkrk gS

dkj.k :- ,lhVkscSDVj ,lhVYMhgkbM ds fd.ou }kjk flVªhd

vEy mRiUu djrk gS

(1) A (2) B (3) C (4) D

174. dFku :- ik;ehVj fuy; esa VhyksØksjksMh;k cukrh gSA

dkj.k :- ik;ehVj vf/kd laoguh; gksrh gSA

(1) A (2) B (3) C (4) D

175. dFku :- ;fn esa<+d dks cyiwoZd ty ds lrg ij vkus ls

jksd fn;k tk;s rks dqN fnuksa esa bldh e`R;q gks tk,xhA

dkj.k :- esa<+d lkekU; :i ls 'olu ;k Hkkstu ugha dj

ik;sxkA

(1) A (2) B (3) C (4) D

E / H 31/34

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MAJOR TEST : AIIMS


176. Assertion :- The anatomical setup of lungs inthorax in such that any change in the volumeof the thoracic cavity will be reflected in thelung (pulmonary) cavity.

Reason :- We cannot directly alter thepulmonary volume.

(1) A (2) B (3) C (4) D

177. Assertion :- Genetically similar type of plantsare formed in apomixis.

Reason :- A population of plants producedfrom single parent is called ramet .

(1) A (2) B (3) C (4) D

178. Assertion :- A fall in glomerular blood flow canactivate the JG cells to release renin.

Reason :- Angiotensin II, decreases theglomerular blood pressure and thereby GFR.

(1) A (2) B (3) C (4) D

179. Assertion :– Tracheids are always perforated.

Reason :– Vessels are always imperforated.

(1) A (2) B (3) C (4) D

180. Assertion :- GIFT technique is used fortreatment of infertility.

Reason :- This method may be used in fertilefemale.

(1) A (2) B (3) C (4) D

181. In human beings, the function of spleen is :-

(1) to assist kidneys

(2) to control blood pressure

(3) filtration of blood

(4) temporarily storage of blood

182. The Quit India Resolution was passed on :-

(1) Aug. 7, 1942 (2) Aug. 8, 1942

(3) Oct. 8, 1942 (4) Oct. 7, 1942

183. India celebrates February 28, every year, as"National Science Day" because on this day :-

(1) Vikram Sarabhai was born

(2) In 1928, C.V. Raman discovered what waslater called the 'Raman effect'

(3) Nehru laid the foundation of sciencelaboratories all over India

(4) First Indian spacecraft was launched

184. Which is the biggest river island in the World?

(1) Pulau (2) Srirangam

(3) Majuli (4) Manpura

176. dFku :- o{k esa QsaQM+s dh 'kkjhfjd O;oLFkk , slhgk srh g S fd o{k x qgk d s vk;ru es a dk sb Z HkhifjorZu QsaQM+s (Qq¶Qqlh;) dh xqgk esa izfrcaf/kr gkstk;sxkAdkj.k :- ge yksx lh/ks QsaQM+k s dk vk;ru ugha cnyldrsA(1) A (2) B (3) C (4) D

177. dFku :- vlaxtuu esa vkuqokaf'kd rkSj ij leku çdkj dsikniksa dk fuekZ.k gksrkdkj.k :- ,d gh tud ls mRiék ikniksa dh vkcknh dks jsfeVdgrs gSaA(1) A (2) B (3) C (4) D

178. dFku :- Xykses:yj jDr izokg esa fxjkoV JG cells dks jsfuuds L=ko gsrq lfØ; djrh gSAdkj.k :- ,fUtvksVsfUlu II, Xykses:yj jDr nkc rFkk GFRdks ?kVkrk gSA(1) A (2) B (3) C (4) D

179. dFku :– VªsfdM~l ges'kk fNfær gksrh gSAdkj.k :– okfgdk,a ges'kk vfNfær gksrh gSaA(1) A (2) B (3) C (4) D

180. dFku :- fx¶V rduhd buQVhZyhVh ds bZykt ds fy;s iz;qDrfd;k tkrk gSAdkj.k :- ;g rjhdk tufud eknk esa iz;qDr fd;k tk ldrkgSA(1) A (2) B (3) C (4) D

181. euq"; esa] Iyhgk dk D;k dk;Z gS :-(1) o`Ddh; dk;ks± esa lgk;d(2) jDr pki dks fu;af=r djuk(3) jDr dks Nkuuk(4) dqN le; ds fy, jDr dk laxzg.k

182. Hkkjr NksM+ks izLrko dc ikfjr fd;k x;k Fkk ?(1) 7 vxLr 1942 (2) 8 vxLr 1942

(3) 8 vDVwcj 1942 (4) 7 vDVwcj 1942

183. Hkkjr esa izR;sd o"kZ 28 Qjojh dks jk"Vªh; foKku fnol ds:i esa euk;k tkrk gS] D;ksafd bl fnu :-

(1) foØe lkjkHkkbZ dk tUe gqvk Fkk

(2) 1928 esa lh- oh- jeu us jeu izHkko dh [kkst dh Fkh

(3) usg: th us lEiw.kZ Hkkjr esa foKku iz;ksx'kkykvksa dh vk/kkjf'kyk j[kh Fkh

(4) izFke Hkkjrh; varfj{k ;ku dks iz{ksfir fd;k x;k Fkk

184. fo'o esa lcls cM+k unh }hi dgk¡ fLFkr gS \(1) iqykm (2) Jhjaxe(3) ektwyh (4) ekuiqjk

27–04–2012


MAJOR TEST : AIIMS


185. Which of the following countries has the largestarea in the world ?

(1) China (2) Russia

(3) Canada (4) USA186. Which one of the following has been denoted

as 'Green Fuel' :-

(1) LPG (2) Gobar gas

(3) CNG (4) Unleaded petrol187. Which one of the following pair is correctly

matched ?

(1) Patanjali – Mahabhashya

(2) Kalidasa – Setubandhana(3) Ashvaghosa – Malavikagnimitra

(4) Pravarasena – Buddha charita188. Which of the following books was written by

Gandhiji ?(1) Discovery of India

(2) India wins Freedom(3) Freedom at Midnight

(4) My Experiments with Truth

189. Among the following the only person whoresigned his Prime Ministership is :-(1) Indira Gandhi

(2) Lal Bahadur Shastri

(3) Morarji Desai(4) Jawaharlal Nehru

190. The first President of India to die in Harnessis

(1) Zakir Hussain

(2) S. Radhakrishnan

(3) Fakhruddin Ali Ahmed

(4) Justice Hidayatullah

191. The famous first sermon, the Dharma –Chakra– Parvartana, or setting in motion thewheel of the law, was delivered by Buddha inthe Deer Park at :-(1) Bodhgaya (2) Rajagriha

(3) Sarnath (4) Sanchi

192. Buddhism was divided into Mahayana andHinayana during the reign of :-(1) The Mauryas

(2) Kanishka

(3) Harshavardhana(4) The Sungas

185. {ks=Qy dh n`f"V ls fo'o esa lcls cM+k ns'k dkSulkgS ?

(1) phu (2) :l(3) dukMk (4) la;qDr jkT; vesfjdk

186. fuEu esa ls fdls ^gfjr b ±/ku* dgk tkrk gS ?

(1) LPG (2) xkscj xSl

(3) CNG (4) ySM jfgr isVªksy

187. fuEu esa ls dkSulk ;qXe lqesfyr gS ?

(1) iratfy – egkHkk";

(2) dkfynkl & lsrqca/ku

(3) v'o?kks"k – ekyfodkfXufe=

(4) izolsZu & cq¼ pfj=188. fuEu esa ls dkSulh iqLrd dh jpuk xk¡/khth us dh Fkh \

(1) Hkkjr dh [kkst

(2) bafM;k foUl ÝhMe

(3) ÝhMe ,V feMukbV

(4) lR; ds lkFk esjs iz;ksx189. fuEu esa ls os ,dek= O;fDr dkSu gS ftUgksusa iz/kkuea=h in

ls R;kxi= fn;k Fkk :-(1) bafnjk xk¡/kh(2) yky cgknqj 'kkL=h(3) eksjkjth nslkbZ(4) tokgj yky usg:

190. Hkkjr ds og izFke jk"Vªifr dkSu Fks ftudk vius dk;Zdkyds nkSjku fu/ku gks x;k Fkk \(1) tkfdj gqlSu(2) ,l- jk/kkÏ".ku(3) Q[k:íhu vyh vgen(4) U;k;ewfrZ fgnk;rqYyk

191. cq¼ us viuk izFke /keksZins'k] /keZ&pØ ifjorZu fuEu esa fdl

LFkku ij fn;k Fkk ?

(1) cks/kx;k (2) jktx`g

(3) lkjukFk (4) lk¡ph

192. fuEu esa ls fdlds 'kkludky ds nkSjku ckS¼ /keZ dks nks 'kk[kkvksaghu;ku o egk;ku esa foHkkftr fd;k x;k Fkk ?(1) ekS;Z(2) dfu"d(3) g"kZo/kZu(4) 'kqax

E / H 33/34

27–04–2012


MAJOR TEST : AIIMS


193. Who among the following was the first BritishViceroy as well as Governor General of India?(1) Lord Bentick(2) Lord Canning(3) Lord Dalhousie(4) Lord Warren Hastings

194. A resolution asking for complete independence(Poorna Swaraj) of India was passed in thesession of the Indian National Congress held at:-(1) Lahore (2) Bombay(3) Calcutta (4) Surat

195. Who raised the slogan "Dilli Chalo" ?(1) Tilak (2) Netaji(3) Bipin Chandra Pal (4) S. Banerjee

196. Swarajya Party was formed by :-(1) C.R. Das (2) Annie Besant(3) Gandhiji (4) Jawaharlal Nehru

197. Name the place where India's First MarineSanctuary is situated :-(1) Kovalam (2) Gulf of Kutch(3) Vishakhapatnam (4) Gahirmatha

198. Which one of the following pairs is correctlymatched ?(1) Kanpur – Paper manufacturing(2) Coimbatore – Textile industry(3) Ahmedabad – Leather industry(4) Murshidabad – Copper smelting

199. The term 'Yorker' is associated with :-(1) Cricket (2) Badminton(3) Boxing (4) Golf

200. Which of the following is a diagnostic technique?(1) TEM and SEM (2) ELISA(3) Both (1) and (2) (4) None

193. Hkkjr ds izFke fczfV'k ok;ljk; rFkk xouZj tujy dkSuFks?(1) ykWMZ csfUVd(2) ykWMZ dSfuax(3) ykWMZ MygkSth(4) ykWMZ okWjsu gsfLVaXl

194. Hkkjr ds iw.kZ Lojkt ds izLrko dks ikfjr djus okyk Hkkjrh;jk"Vªh; dkaxzsl dk vf/kos'ku fuEu esa ls dgk¡ ij gqvkFkk\(1) ykgkSj (2) cEcbZ(3) dydÙkk (4) lwjr

195. ^^fnYyh pyks** ;g ukjk fdlus fn;k Fkk \(1) fryd (2) usrkth(3) fcfiu pUæ iky (4) ,l- cSuthZ

196. LojkT; ikVhZ ds laLFkkid dkSu Fks :-(1) lh- vkj- nkl (2) ,uh cslsUV(3) xk¡/khth (4) tokgj yky usg:

197. Hkkjr dk izFke leqæh vHk;kj.; dgk¡ fLFkr gS ?

(1) dksoye (2) dPN dh [kkM+h

(3) fo'kk[kkiV~ue (4) xghjekFkk

198. fuEufyf[kr esa ls dkSulk ; qXe lqesfyr gS ?

(1) dkuiqj & dkxt fuekZ.k m|ksx

(2) dks;EcVwj – oL= m|ksx

(3) vgenkckn – peM+k m|ksx

(4) eq'khZnkckn – rk¡ck xykus dk m|ksx199. ^;kWdZj* 'kCn fdl [ksy ls lacaf/kr gS :-

(1) fØdsV (2) cSMfeUVu(3) eqDdsckth (4) xksYQ

200. fuEufyf[kr esa ls dkSulh ,d funku i¼fr gS ?(1) TEM rFkk SEM (2) ELISA(3) (1) rFkk (2) nksuksa (4) dksbZ ugha

Your moral dutyis that to prove ALLEN is ALLEN

27–04–2012


MAJOR TEST : AIIMS


SPACE FOR ROUGH WORK / jQ dk;Z ds fy;s txg

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Allen Aiims Test Paper 27 04 2012 -Paper