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1
Six Sigma: The Statistical Tool Box
Advanced Six-Sigma Statistical Tools
ASQ-RS Meeting, March 2003
Dr. Joseph G. VoelkelCQAS, [email protected]/~jgvcqa for material
Rev: 3/25/03 2CQAS
BB Six-Sigma Statistical Tools
ExamplesGage R&R StudiesControl ChartsExperimental DesignTaguchi/RobustAnalysis of VarianceRegression
Basic Level, mostly
Short/LongX-bar/R, p, c2k, 2k–p, simple RSMcontrol, noise, S/None-, two-wayone or two predictors
www.rit.edu/~jgvcqa for material
2
Rev: 3/25/03 3CQAS
Why Are We Here?
Show example problems where basic Black Belt tools do not perform well.Second, show methods that might be used to solve such problems.Third, show how the methods can indeed solve such problems.
Rev: 3/25/03 4CQAS
People Solve Problems
Good methodsprovide insight, often visualquantify the extent of the problemmay predict results of improvements
3
Rev: 3/25/03 5CQAS
Case Study 1: Reducing Dimensional Variation in Radiator Cores
Radiator CoreWant dimensional stability across the core (“positions”)
Not being achievedControl factors
CS, PSNoise factors
Position, Frame
Rev: 3/25/03 6CQAS
Radiator-Core Experiment
Fr
CS PS
CoreTwo cores tested, for each CS/PS/Frame combination
PosEach core measured at 3 positions
Each position measured twice
Meas
Seven frames used
Taguchi Approach?
4
Rev: 3/25/03 7CQAS
Radiator-Core: Taguchi ApproachTaguchi approach
After averaging data over two measurements
Noise FactorsFrame
Control Factors 1 2 7Pos s
CS PS Rep 1 2 3 1 2 3 … 1 2 31 1 1 Y Y Y Y Y Y Y Y Y 0.436 0.0411 1 2 Y Y Y Y Y Y Y Y Y 0.432 0.0422 1 1 Y Y Y Y Y Y Y Y Y 0.434 0.0442 1 2 Y Y Y Y Y Y Y Y Y 0.430 0.0451 2 1 Y Y Y Y Y Y Y Y Y 0.429 0.0411 2 2 Y Y Y Y Y Y Y Y Y 0.436 0.0392 2 1 Y Y Y Y Y Y Y Y Y 0.429 0.0392 2 2 Y Y Y Y Y Y Y Y Y 0.426 0.042
Y
Rev: 3/25/03 8CQAS
Radiator-Core: Taguchi ApproachMain Effect Plots
PSCS
2121
0.4332
0.4324
0.4316
0.4308
0.4300
Yba
r
PSCS
2121
0.0429
0.0423
0.0417
0.0411
0.0405
sd
Y
s
5
Rev: 3/25/03 9CQAS
Radiator-Core: Taguchi ApproachANOVA/Regression and % contributions
s Term Coef T P %Contr Constant 0.041552 89.70 0.000 CS -0.001329 -2.87 0.046 50 PS 0.000818 1.77 0.152 19 CS*PS -0.000453 -0.98 0.383 6 Error 25
Y Term Coef T P %Contr Constant 0.431497 398.44 0.000 CS 0.001604 -1.48 0.213 23 PS 0.001807 -1.67 0.171 29 CS*PS 0.000884 -0.82 0.460 7 Error 41
Rev: 3/25/03 10CQAS
2 CS × 2 PS × 2 Reps × 7 Frames × 3 Pos = 168 data pointsSo, 168 d.f.
Radiator-Core: Critique of Taguchi Approach
Noise FactorsFrame
Control Factors 1 2 7Pos df s df
CS PS Rep 1 2 3 1 2 3 … 1 2 31 1 1 Y Y Y Y Y Y Y Y Y 0.436 1 0.041 201 1 2 Y Y Y Y Y Y Y Y Y 0.432 1 0.042 202 1 1 Y Y Y Y Y Y Y Y Y 0.434 1 0.044 202 1 2 Y Y Y Y Y Y Y Y Y 0.430 1 0.045 201 2 1 Y Y Y Y Y Y Y Y Y 0.429 1 0.041 201 2 2 Y Y Y Y Y Y Y Y Y 0.436 1 0.039 202 2 1 Y Y Y Y Y Y Y Y Y 0.429 1 0.039 202 2 2 Y Y Y Y Y Y Y Y Y 0.426 1 0.042 20
8 160
Y
df are grouped—less information
In Taguchi approach:
6
Rev: 3/25/03 11CQAS
Radiator-Core: ANOVA ApproachSplit apart d.f.—More InformationStep 1: ESD (Extended Structure Diagram) tool used
CSTF(2) PSTF(2) FrameTF(7)
SectionUA(1)
PosCF(3)CoreUA(2)
MeasCA(2)
CS PS
Rev: 3/25/03 12CQAS
Radiator-Core: ANOVA Approach
Step 2: translate this to an ANOVA model
CSTF(2) PSTF(2) FrameTF(7)
SectionUA(1)SectionUA(1)
PosCF(3)CoreUA(2)CoreUA(2)
MeasCA(2)MeasCA(2)
Y=CS | PS | FrCore (CS PS Fr)PosPos*CoreError [Meas(Core Pos)]
7
Rev: 3/25/03 13CQAS
Radiator-Core: ANOVA ApproachStep 3a: Run the ANOVA model
Source DF SS MS F PCS 1 0.0008646 0.0008646 5.20 0.030PS 1 0.0010966 0.0010966 6.60 0.016Fr 6 0.2531569 0.0421928 253.80 0.000Pos 2 0.0367108 0.0183554 74.95 0.000CS*PS 1 0.0002625 0.0002625 1.58 0.219CS*Fr 6 0.0024635 0.0004106 2.47 0.048CS*Pos 2 0.0010048 0.0005024 2.05 0.138PS*Fr 6 0.0029055 0.0004842 2.91 0.025PS*Pos 2 0.0025371 0.0012685 5.18 0.009Fr*Pos 12 0.2212360 0.0184363 75.28 0.000CS*PS*Fr 6 0.0016036 0.0002673 1.61 0.182CS*PS*Pos 2 0.0011605 0.0005802 2.37 0.103CS*Fr*Pos 12 0.0065032 0.0005419 2.21 0.023PS*Fr*Pos 12 0.0045778 0.0003815 1.56 0.132CS*PS*Fr*Pos 12 0.0029688 0.0002474 1.01 0.452Core(CS PS Fr) 28 0.0046549 0.0001662 3.74 0.000Pos*Core(CS PS Fr) 56 0.0137153 0.0002449 5.51 0.000Error 168 0.0074635 0.0000444Total 335 0.5648860
Rev: 3/25/03 14CQAS
Radiator-Core: ANOVA ApproachStep 3b: FindComponentsof Variance
Full ModelSource MS 10000*VC %CS 0.000865 0.021 0%PS 0.001097 0.028 0%Fr 0.042193 7.505 44%Pos 0.018355 1.078 6%CS*PS 0.000263 0.003 0%CS*Fr 0.000411 0.044 0%CS*Pos 0.000502 0.015 0%PS*Fr 0.000484 0.057 0%PS*Pos 0.001269 0.061 0%Fr*Pos 0.018436 6.497 38%CS*PS*Fr 0.000267 0.018 0%CS*PS*Pos 0.000580 0.020 0%CS*Fr*Pos 0.000542 0.106 1%PS*Fr*Pos 0.000382 0.049 0%CS*PS*Fr*Pos 0.000247 0.001 0%Core(CS PS Fr) 0.000166 0.203 1%Pos*Core(CS PS Fr) 0.000245 1.003 6%Error 0.000044 0.444 3%
17.151 100%
8
Rev: 3/25/03 15CQAS
Radiator-Core: ANOVA Approach
Step 3b:FindComponentsof Variance
Full Model
Source MS10000
*VC %Fr 0.042193 7.5 44%Pos 0.018355 1.1 6%Fr*Pos 0.018436 6.5 38%Pos*Core 0.000245 1.0 6%Error 0.000044 0.4 3%Rest 0.0 2%
16.5 100%
Rev: 3/25/03 16CQAS
Radiator-Core: ANOVA Approach
How come we didn’t see this using the Taguchi approach?Taguchi approach depends totally on control (CS, PS) & control x noiseeffects
Full Model
Source MS10000
*VC %Fr 0.042193 7.5 44%Pos 0.018355 1.1 6%Fr*Pos 0.018436 6.5 38%Pos*Core 0.000245 1.0 6%Error 0.000044 0.4 3%Rest 0.0 2%
16.5 100%
This is what the Taguchi approach analyzed !!!
9
Rev: 3/25/03 17CQAS
Radiator-Core: ANOVA Approach
Step 4. Graph the results of the analysisWhat graph(s) should we make?
Full Model
Source MS10000
*VC %Fr 0.042193 7.5 44%Pos 0.018355 1.1 6%Fr*Pos 0.018436 6.5 38%Pos*Core 0.000245 1.0 6%Error 0.000044 0.4 3%Rest 0.0 2%
16.5 100%
Rev: 3/25/03 18CQAS
Radiator-Core: Interaction PlotCan’t we do better?
1 2 3
7654321
0.50
0.45
0.40
0.35
Fr
Pos
Mea
n
Make graph connect more to physical reality
10
Rev: 3/25/03 19CQAS
Radiator-Core: Interaction Plot
76543210
0.53
0.51
0.49
0.47
0.45
0.43
0.41
0.39
0.37
0.35
Fr/Pos
Y
Rev: 3/25/03 20CQAS
Radiator-Core: One More Plot
Full Model
Source MS10000
*VC %Fr 0.042193 7.5 44%Pos 0.018355 1.1 6%Fr*Pos 0.018436 6.5 38%Pos*Core 0.000245 1.0 6%Error 0.000044 0.4 3%Rest 0.0 2%
16.5 100%
76543210
0.53
0.51
0.49
0.47
0.45
0.43
0.41
0.39
0.37
0.35
Fr/Pos
Y
11
Rev: 3/25/03 21CQAS
Radiator-Core: One More Plot
76543210
0.55
0.45
0.35
Frame1
Y
Rev: 3/25/03 22CQAS
Radiator-Core: Lessons Learned Push the Taguchi button?Run ANOVA that reflects your design !Pull apart those degrees of freedom!
Push the Interaction-Graph button?Make up problem-specific graphs !
76543210
0.53
0.51
0.49
0.47
0.45
0.43
0.41
0.39
0.37
0.35
Fr/Pos
Y
12
Rev: 3/25/03 23CQAS
Case Study 2Unbalance: 2D Gauge R&R Studies
Rev: 3/25/03 24CQAS
Unbalance
13
Rev: 3/25/03 25CQAS
Unbalance
Unbalance
0.750.75 1.501.50 2.252.25
3.00 oz, 0.5 in0.75 oz, 2.0 in
* 1.00 oz, 1.5 in
Unitsoz-in (1.5 oz-in)g-mm
CoordinatesPolar (r, θ)Cartesian (X,Y)
Rev: 3/25/03 26CQAS
UnbalanceAnother measure
Unbalance= 1.5 oz-inTake weight of impeller into account
Eccentricitye=U / munits: in or mm
Center of Axis of Rotation
Center of Mass of Rotating Body
Light impellerHeavy impeller
14
Rev: 3/25/03 27CQAS
Unbalance: 2D Gauge R&R
0.750.75 1.501.50 2.252.25
20 repeat measurements of unbalance — 1 impeller, appraiser, machineHow would you summarize the variability in these measurements?
Rev: 3/25/03 28CQAS
Unbalance: 2D Gauge R&R
One approach that’s been usedMeasure r from origin for each pointUse regular gauge R&R measures
0.750.75 1.501.50 2.252.25
15
Rev: 3/25/03 29CQAS
1D Analysis of 2D Data
Now estimate range where 99% of values would beFind s = sample standard deviation = 0.42Find 5.15s = 2.17 = EV
Rev: 3/25/03 30CQAS
1D Analysis of 2D Data
But consider(X,Y)(X+1,Y+1)
90° rotation *All have same variation
0.750.75 1.501.50 2.252.25
16
Rev: 3/25/03 31CQAS
1D Analysis of 2D Data
0.0 0.5 1.0 1.5 2.0 2.5 3.0r
(X+1,Y+1). EV=1.40
90 deg rotation. EV=3.67
(X,Y). EV=2.17
0.750.75 1.501.50 2.252.25
What is a better way?
Rev: 3/25/03 32CQAS
Extending 1D Summaries to 2D
Fundamental point:engineering tolerance is a circleThe proposed two-dimensional method
repeatability (equip-ment variation) EVEV ≡ diameter of circle capturing p = 99% of such readings.
0.750.75 1.501.50 2.252.25
17
Rev: 3/25/03 33CQAS
Comparison of 2D to 1D Summary
EV = 2.17, 1.40, 3.67?
0.750.75 1.501.50 2.252.250.750.75 1.501.50 2.252.25
EV = 3.73
Rev: 3/25/03 34CQAS
Example
3 appraisers measured each of 10 parts twice (3 × 10 × 2 = 60).For more validity, they did this at each of two time periods (60 × 2 = 120)Will sometimes act here as if 6 appraisers instead (6 × 10 × 2 = 120). This is (pretty much) OK.We will see how this technique can summarize variation, just as in the 1D case
18
Rev: 3/25/03 35CQAS
Example. Step 1: Set up ESD
Appraiser(3) Parts(10)
Time(2)
Meas(2)
Rev: 3/25/03 36CQAS
Example: All 3 Appraisers
-0.0008
-0.0006
-0.0004
-0.0002
0
0.0002
0.0004
0.0006
0.0008
-0.0008
-0.0006
-0.0004
-0.0002
0.0000
0.0002
0.0004
0.0006
0.0008
X
Y
6 “appraiser’s” × 10 impellers × 2 trials = 120
Adjust data (graphs) to meanof (0,0) for each impeller.
-8.00E-04
-6.00E-04
-4.00E-04
-2.00E-04
0.00E+00
2.00E-04
4.00E-04
6.00E-04
8.00E-04
-8.00E-04
-6.00E-04
-4.00E-04
-2.00E-04
0.00E+00
2.00E-04
4.00E-04
6.00E-04
8.00E-04
X
Y
19
Rev: 3/25/03 37CQAS
Example. Step 2:ANOVA-based Diameter Summaries
-0.002
-0.001
0
0.001
0.002
-0.002 -0.001 0 0.001 0.002
X
Y
%D.tol %TotalD.tol 100% 114%
R&R 58% 66%Reprocibility 56% 63% Oper/Time Oper/Time*ImpRepeatability 17% 20%Impeller 66% 75%Total 88% 100%
Data adjusted to a mean of (0,0) for each impeller.
6 “appraiser’s” × 10 impellers × 2 trials = 120
±0.0013"
Rev: 3/25/03 38CQAS
Step 3: Analysis. Matt Only
-0.002
-0.001
0
0.001
0.002
-0.002 -0.001 0 0.001 0.002
X
Y
%D.tol %TotalD.tol 100% 137%
R&R 37% 51%Reprocibility 34% 46% Oper/Time Oper/Time*ImpRepeatability 16% 22%Impeller 64% 87%Total 73% 100%
20
Rev: 3/25/03 39CQAS
Step 3: Analysis. Tom Only
-0.002
-0.001
0
0.001
0.002
-0.002 -0.001 0 0.001 0.002
X
Y
%D.tol %TotalD.tol 100% 118%
R&R 40% 48%Reprocibility 32% 38% Oper/Time Oper/Time*ImpRepeatability 24% 29%Impeller 75% 88%Total 85% 100%
Rev: 3/25/03 40CQAS
Step 3: Analysis. Ben Only
-0.002
-0.001
0
0.001
0.002
-0.002 -0.001 0 0.001 0.002
X
Y
%D.tol %TotalD.tol 100% 147%
R&R 14% 20%Reprocibility 10% 15% Oper/Time Oper/Time*ImpRepeatability 9% 13%Impeller 67% 99%Total 68% 100%
21
Rev: 3/25/03 41CQAS
Step 4: Graphical Analysis. TomData = Averages (N=2) of each Part-Time combination
0.50.5 1.01.0
Time 1Time 2
EV
Tom
R&R = 40%AV = 32%EV = 24%
Rev: 3/25/03 42CQAS
Step 4: Graphical Analysis. BenData = Averages (N=2) of each Part-Time combination
0.50.5 1.01.0
Time 1Time 2
EV
Ben
R&R = 14%AV = 10%EV = 9%
22
Rev: 3/25/03 43CQAS
Results
Standardization was done based on Ben’s techniques.Measurement variation greatly reduced
Good methodsprovide insight, often visualquantify the extent of the problemmay predict results of improvements
Good methodsprovide insight, often visualquantify the extent of the problemmay predict results of improvements
Rev: 3/25/03 44CQAS
Case Study 3:Multivariate Methods: Experimental Design
Many experiments: Multiple ResponsesMultiple Responses=Multivariate CaseExample: L18 Film Experiment
4 Factors24 Responses
Many are MD/TD typesEmphasis in this talk: Responses only
See how the responses are associated“How many different features exist among the responses?”
23
Rev: 3/25/03 45CQAS
Multivariate Methods: Exp’l Design
The Responses Microsoft Excel Worksheet
How are the responses associated?How would you try to find this out?
Good methodsprovide insight, often visualquantify the extent of the problemmay predict results of improvements
Good methodsprovide insight, often visualquantify the extent of the problemmay predict results of improvements
Minitab Worksheet
1. Correlations2. Matrix Plot3. Add Col #’s4. CorrCode5. PC’s6. Plots
Minitab
Rev: 3/25/03 46CQAS
Case Study 4: SPC with a Twist
Consider this Process data40 subgroupsDimensional measurementSubgroup size 6. Six parts in a row sampled from a machine
How would you look at these data?
Minitab Worksheet
Minitab
Microsoft Excel Worksheet
24
Rev: 3/25/03 47CQAS
Case Study 4: SPC with a TwistBut here is the real situation
40 subgroups, Subgroup size 6.Six parts sampled from a Six-Cavity machine
1 2 3
Now, how would you analyze these data?Minitab ProjectMinitab
Rev: 3/25/03 48CQAS
The Actual Mold
Good methodsprovide insight, often visualquantify the extent of the problemmay predict results of improvements
Good methodsprovide insight, often visualquantify the extent of the problemmay predict results of improvements