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Name: ________________________ Class: ___________________ Date: __________ ID: A
1
Accelerated Geometry/Algebra 2 Final Exam Review 2015
Multiple Choice
Identify the choice that best completes the statement or answers the question.
Solve the following system of equations by graphing.
____ 1. y = 11x − 6
y = − 6x + 11
a. (–1, 5) c. (5, 1)
b. (1, 7) d. (1, 5)
____ 2. 2y + 8x = 58
y − 5x = 11
a. (2, 21) c. (4, 20)
b. (21, 2) d. (1, 21)
Graph each system of equations and describe it as consistent and independent, consistent and dependent,
inconsistent, or none of these.
____ 3. 9x − 8y = 15
27x − 24y = 3
a. consistent and independent c. consistent and dependent
b. inconsistent d. none of these
____ 4. 5x − 8y = 6
6x − 6y = 6
a. inconsistent c. consistent and dependent
b. consistent and independent d. none of these
Solve each system of equations by using substitution.
____ 5. 8x + 7y = 18
3x – 5y = 22
a. (–2, 4) c. (4, –2)
b. (3, –2) d. (4, 0)
____ 6. 3r + 3s = 93r −6s =18a. (4, –0.5) c. (4, –1)
b. (5.5, 3) d. (2, –1)
Solve each system of equations by using elimination.
____ 7. 3p + 9q = 6
5p − 5q = 30
a. (6, –1) c. (5, 0.5)
b. (3.75, 2) d. (5, –1)
Name: ________________________ ID: A
2
____ 8. 6a + 6b = 126a − 5b = 12a. (1, 0) c. (3, –0.5)
b. (2, 0) d. (2, 0.25)
Solve the system of inequalities by graphing.
____ 9. x > 2
y > 8
a. c.
b. d.
Name: ________________________ ID: A
3
____ 10. y > x – 6
y|| || ≤ 6
a. c.
b. d.
Find the coordinates of the vertices of the figure formed by each system of inequalities.
____ 11. y + x ≥ −9
y ≥ x − 7
2y + x ≤ 16
a. (–1, –8), (–30, 23), (–34, 25)
b. (–1, 8), (10, 3), (34, 25)
c. (–1, 25), (–34, 3), (10, –8)
d. (–1, –8), (10, 3), (–34, 25)
____ 12. y ≥ −2
2x + y ≤ 2
y ≤ 2x + 6
a. (2, –2), (–4, –2), (–1, 4)
b. (2, 4), (–1, –2), (–4, –2)
c. (2, –2), (4, 2), (1, –4)
d. (2, –2), (4, –2), (0, –8)
Name: ________________________ ID: A
4
____ 13. Graph the system of inequalities showing the feasible region to represent the number of first visits and the
number of follow-ups that can be performed.
a. c.
b. d.
Solve the given system of equations.
____ 14. –3a = 36
10a + 3c = 9
2b + 5c = 23
a. a = –12, b = –96, c = 43 c. a = 12, b = –96, c = 43
b. a = –12, b = 43, c = –96 d. a = 43, b = –12, c = –96
____ 15. 11a + 2c = 10
–2a = 32
8b + 10c = 18
a. a = –16, b = –114, c = 93 c. a = –16, b = 93, c = –114
b. a = 16, b = –114, c = 93 d. a = 93, b = –16, c = –114
Name: ________________________ ID: A
5
____ 16. Consider the quadratic function f x( ) = −2x2
+ 2x + 2. Find the y-intercept and the equation of the axis of
symmetry.
a. The y-intercept is –2.
The equation of the axis of symmetry is x = −1
2.
b. The y-intercept is 1
2.
The equation of the axis of symmetry is x = 2.
c. The y-intercept is + 2.
The equation of the axis of symmetry is x = 1
2.
d. The y-intercept is −1
2.
The equation of the axis of symmetry is x = –2.
Name: ________________________ ID: A
6
____ 17. Graph the quadratic function f(x) = −2x2
+ 2x + 2.
a. c.
b. d.
Determine whether the given function has a maximum or a minimum value. Then, find the maximum or
minimum value of the function.
____ 18. f(x) = x2
− 2x + 2
a. The function has a maximum value. The maximum value of the function is 1.
b. The function has a maximum value. The maximum value of the function is 5.
c. The function has a minimum value. The minimum value of the function is 1.
d. The function has a minimum value. The minimum value of the function is 5.
Name: ________________________ ID: A
7
____ 19. f(x) = −x2
+ 2x + 7
a. The function has a minimum value. The minimum value of the function is 8.
b. The function has a minimum value. The minimum value of the function is 4.
c. The function has a maximum value. The maximum value of the function is 4.
d. The function has a maximum value. The maximum value of the function is 8.
Solve the equation by graphing. If exact roots cannot be found, state the consecutive integers between which
the roots are located.
____ 20. x2
+ 5x + 4 = 0
a.
The solution set is 1, 4{ }.
c.
The solution set is −2.5, − 2.25{ }.
b.
The solution set is −4, − 1{ }.
d.
The solution set is 1, 4{ }.
Name: ________________________ ID: A
8
____ 21. −x2
+ 4x = 0
a.
The solution set is 0, 4{ }.
c.
The solution set is −4, 0{ }.
b.
The solution set is −4 0{ }.
d.
The solution set is 2, 4{ }.
Name: ________________________ ID: A
9
____ 22. x2
+ 4x + 2 = 0
a.
One solution is between 3 and 4, while
the other solution is between 0 and 1.
c.
One solution is between –3 and 0, while
the other solution is between –4 and –1.
b.
One solution is between –3 and –1, while
the other solution is between 0 and –4.
d.
One solution is between –3 and –4, while
the other solution is between 0 and –1.
Name: ________________________ ID: A
10
____ 23. −2x2
+ 3x + 4 = 0
a.
One solution is between 2 and –1, while
the other solution is between 0 and 3.
c.
One solution is between –2 and –3, while
the other solution is between 0 and 1.
b.
One solution is between 2 and 0, while
the other solution is between 3 and –1.
d.
One solution is between 0 and –1, while
the other solution is between 2 and 3.
Name: ________________________ ID: A
11
Write a quadratic equation with the given roots. Write the equation in the form ax2
+ bx + c = 0, where a, b,
and c are integers.
____ 24. –5 and 2
a. x2
− 7x + 10 = 0 c. x2
− 3x + 10 = 0
b. x2
+ 7x + 10 = 0 d. x2
+ 3x − 10 = 0
____ 25. −5
4 and 8
a. 4x2
− 27x − 40 = 0 c. x2
− 27x − 40 = 0
b. 4x2
+ 27x + 40 = 0 d. x2
− 27x + 40 = 0
Solve the equation by factoring.
____ 26. x2
+ 3x − 28 = 0
a. −4, 7{ } c. 4, 7{ }b. −7, 4{ } d. −4, − 7{ }
____ 27. 2x2
+ 3x − 14 = 0
a. {–4, −7
2} c. {–4, 7}
b. {−7
2, 2} d. {2, 7}
Simplify.
____ 28. 196
a. 14 c. 196
b. 14 d. 3 14
____ 29. 245
64
a.7 5
8c.
5
8
b.49
8d.
7 7
8
____ 30. (2i)(−3i)(4i)
a. −24 c. 24i
b. −24i d. 24
____ 31. i7
a. −i c. i
b. 1 d. −1
____ 32. 11 + i( ) + 3 − 15i( )a. 14 − 14i c. 12 − 12i
b. − 4 + 4i d. 14 + 16i
Name: ________________________ ID: A
12
____ 33. 11 − 12i( ) + 21 − 8i( )a. 9 + 19i c. 32 − 4i
b. 32 − 20i d. 29i − i
____ 34. 8 + 10i( )(5 − 8i)
a. 40 − 14i + 80 c. 40 − 14i − 80i2
b. 120 − 14i d. 88 + 50i
____ 35. −4 + 4i( )(−3 − 3i)
a. 16 + 12i c. 24 + 0i
b. 12 + 0i − 12i2
d. 12 + 0i + 12
____ 36. 3
6 + 7i
a.18
85+
21
85i c.
18
13+
21
13i
b.6
85−
7
85i d.
18
85−
21
85i
____ 37. 6 − 3i
8 − 11i
a.81
185+
42
185i c.
6
185−
3
185i
b.15
57+
42
57i d.
81
185−
42
185i
Solve the equation by using the Square Root Property.
____ 38. 16x2
− 48x + 36 = 49
a. {3
2} c. {−
13
4,
1
4}
b. {3
2, 7} d. {−
1
4,
13
4}
____ 39. 100x2
− 80x + 16 = 9
a. {1
10,
7
10} c. {
2
5}
b. {−7
10, −
1
10} d. {
2
5, 3}
Solve the equation by completing the square.
____ 40. x2
+ 2x − 3 = 0
a. −3, 1{ } c. −6, 1{ }b. −6, 2{ } d. −1, 3{ }
____ 41. 2x2
+ 2x = 0
a. −2, 0{ } c. 0{ }b. 0, 1{ } d. −1, 0{ }
Name: ________________________ ID: A
13
Find the exact solution of the following quadratic equation by using the Quadratic Formula.
____ 42. x2
− 8x = 20
a. −10, 2{ } c. −4, 20{ }b. 20, 28{ } d. −2, 10{ }
____ 43. −x2
+ 3x + 7 = 0
a.3 − 37
−2,
3 + 37
−2
Ï
Ì
Ó
ÔÔÔÔÔÔÔÔÔÔÔÔÔ
¸
˝
˛
ÔÔÔÔÔÔÔÔÔÔÔÔÔ
c.−3 − −19
−2,
−3 + −19
−2
Ï
Ì
Ó
ÔÔÔÔÔÔÔÔÔÔÔÔÔ
¸
˝
˛
ÔÔÔÔÔÔÔÔÔÔÔÔÔ
b.−3 − 12
−2,
−3 + 12
−2
Ï
Ì
Ó
ÔÔÔÔÔÔÔÔÔÔÔÔÔ
¸
˝
˛
ÔÔÔÔÔÔÔÔÔÔÔÔÔ
d.−3 − 37
−2,
−3 + 37
−2
Ï
Ì
Ó
ÔÔÔÔÔÔÔÔÔÔÔÔÔ
¸
˝
˛
ÔÔÔÔÔÔÔÔÔÔÔÔÔ
Find the value of the discriminant. Then describe the number and type of roots for the equation.
____ 44. −x2
− 14x + 2 = 0
a. The discriminant is 196. Because the discriminant is greater than 0 and is a perfect
square, the two roots are real and rational.
b. The discriminant is –204. Because the discriminant is less than 0, the two roots are
complex.
c. The discriminant is 204. Because the discriminant is greater than 0 and is not a perfect
square, the two roots are real and irrational.
d. The discriminant is –188. Because the discriminant is less than 0, the two roots are
complex.
____ 45. x2
+ x + 7 = 0
a. The discriminant is –29.
Because the discriminant is less than 0, the two roots are complex.
b. The discriminant is 1.
Because the discriminant is greater than 0 and is a perfect square, the two roots are real
and rational.
c. The discriminant is –27.
Because the discriminant is less than 0, the two roots are complex.
d. The discriminant is 27.
Because the discriminant is greater than 0 and is a perfect square, the two roots are real
and rational.
Name: ________________________ ID: A
14
Write the following quadratic function in vertex form. Then, identify the axis of symmetry.
____ 46. y = −3x2
+ 48x
a. The vertex form of the function is y = 3 x + 8( )2
+ 192.
The equation of the axis of symmetry is x = −192.
b. The vertex form of the function is y = x + 192( )2
+ 8.
The equation of the axis of symmetry is x = −8.
c. The vertex form of the function is y = −3 x − 8( )2
+ 192.
The equation of the axis of symmetry is x = 8.
d. The vertex form of the function is y = −3 x + 8( )2
+ 192.
The equation of the axis of symmetry is x = 192.
Name: ________________________ ID: A
15
Graph the quadratic inequality.
____ 47. y > x2
− 3x + 5
a. c.
b. d.
Name: ________________________ ID: A
16
____ 48. y < 2x2
− 6x + 10
a. c.
b. d.
____ 49. Find the geometric mean between each pair of numbers.
28 and 7
a. 35 c. 14
b. 196 d. 17.5
____ 50. Find the geometric mean between each pair of numbers.
256 and 841
a. 22.5 c. 464
b. 3 5 d. 4 29
Name: ________________________ ID: A
17
____ 51. Find the measure of the BD.
a. 2 30 c. 23
b. 11.5 d. 120
____ 52. Find x.
a. 22 c. 1144
b. 2 286 d. 1594
Determine whether ∆QRS is a right triangle for the given vertices. Explain.
____ 53. Q(–6, –2), R(2, –5), S(–3, 6)
a. no; QR = 73 , QS = 73 , RS = 146 ; QR2 + QS2 ≠ RS2
b. yes; QR = 73 , QS = 73 , RS = 146 ; QR2 + QS2 = RS2
c. yes; QR = 73 , QS = 73 , RS = 146 ; RS2 + QS2 = RQ2
d. no; QR = 73 , QS = 73 , RS = 146 ; RS2 + QS2 ≠ RQ2
____ 54. Q(18, 13), R(17, –3), S(–18, 12)
a. no; QR = 257 , QS = 1297 , RS = 5 58 ; QR2 + QS2 ≠ RS2
b. yes; QR = 257 , QS = 1297 , RS = 5 58 ; RS2 + QS2 = RQ2
c. yes; QR = 257 , QS = 1297 , RS = 5 58 ; QR2 + QS2 ≠ RS2
d. no; QR = 257 , QS = 1297 , RS = 5 58 ; RS2 + QS2 = RQ2
Name: ________________________ ID: A
18
____ 55. The length of a diagonal of a square is 24 2 millimeters. Find the perimeter of the square.
a. 576 millimeters c. 96 millimeters
b. 96 2 millimeters d. 1152 millimeters
____ 56. Find x and y.
a. x = 45°, y = 13.1 c. x = 30°, y = 13.1 2
b. x = 30°, y = 13.1 d. x = 45°, y = 13.1 2
____ 57. Find x and y.
a. x = 24 3, y = 24 c. x = 24, y = 24 3
b. x = 12 3, y = 12 d. x = 12, y = 12 3
____ 58. Find x and y.
a. x = 1.5 3, y = 1.5 c. x = 3, y = 3 3
b. x = 3 3, y = 3 d. x = 1.5, y = 1.5 3
____ 59. Find the measure of the angle to the nearest tenth of a degree.
cos Y = 0.5135a. 30.9 c. 0.5135
b. 59.1 d. 27.2
Name: ________________________ ID: A
19
____ 60. Use the figure to find the trigonometric ratio below. Express the answer as a decimal rounded to the nearest
ten-thousandth.
cos B
AC = 5 5 , CB = 5 , AD = 11, CD = 2, DB = 1
a. 2.2361 c. 0.4472
b. 0.9839 d. 0.8944
____ 61. Lynn is standing at horizontal ground level with the base of the Sears Tower in Chicago. The angle formed
by the ground and the line segment from her position to the top of the building is 15.7°. The height of the
Sears Tower is 1450 feet. Find her distance from the Sears Tower to the nearest foot.
a. 408 ft c. 5159 ft
b. 7 ft d. 5358 ft
____ 62. Dolores is standing on a horizontal ground level with the base of the Statue of Liberty in New York City. The
angle formed by the ground and the line segment from her position to the top of the statue is 26.3°. The
height of the Statue of Liberty is approximately 93 meters. Find her distance from the Statue of Liberty to the
nearest meter.
a. 188 m c. 104 m
b. 0.005 m d. 210 m
____ 63. A rocket ship is two miles above sea level when it begins to climb at a constant angle of 3.5° for the next 40
ground miles. About how far above sea level is the rocket ship after its climb?
a. 2.4 mi c. 653.9 mi
b. 4.4 mi d. 655.9 mi
____ 64. A hot air balloon is one mile above sea level when it begins to climb at a constant angle of 4° for the next 50
ground miles. About how far above sea level is the hot air balloon after its climb?
a. 2.5 mi c. 4.5 mi
b. 3.5 mi d. 716.03 mi
A 60-yard long drawbridge has one end at ground level. The other end is initially at an incline of 5°.
____ 65. How far off the ground is the raised end of the drawbridge in its initial setting?
a. 5.23 yd c. 685.80 yd
b. 59.77 yd d. 688.42 yd
____ 66. During one stage of the drawbridge’s motion, the raised end is 15 yards above the ground. What is the incline
of the drawbridge to the nearest hundredth?
a. 0.004° c. 14.48°
b. 14.04° d. 75.52°
____ 67. A hiker stops to rest and sees a deer in the distance. If the hiker is 48 yards lower than the deer and the angle
of elevation from the hiker to the deer is 15°, find the distance from the hiker to the deer.
a. 18.21 yd c. 179.14 yd
b. 49.69 yd d. 185.46 yd
Name: ________________________ ID: A
20
____ 68. A water slide is 400 yards long with a vertical drop of 36.3 yards. Find the angle of depression of the slide.
a. 5.2° c. 436.3°
b. 84.8° d. 363.7°
____ 69. A tubing run is 150 yards long with a vertical drop of 21.6 yards. Find the angle of depression of the run.
a. 8.2° c. 81.7°
b. 8.3° d. 81.8°
Find each measure using the given measures of ∆KLM . Round measures to the nearest tenth.
____ 70. If m∠L = 48.4, m∠K = 24.5, and l = 37.9, find k.
a. 15.7 c. 28.3
b. 21.0 d. 68.3
____ 71. If m∠L = 47.1, k = 59.6, and l = 52.2, find m∠K.
a. 45.8 c. 56.7
b. 0.8 d. 43.6
____ 72. A playground is situated on a triangular plot of land. Two sides of the plot are 175 feet long and they meet at
an angle of 70°. For safety reasons, a fence is to be placed along the perimeter of the property. How much
fencing material is needed?
a. 110 ft c. 375.8 ft
b. 200.8 ft d. 550.8 ft
____ 73. In ∆ABC, given the following measures, find the measure of the missing side to the nearest tenth..
a = 14.2, c = 13.9, m∠B = 27.7
a. b = 6.7 c. b = 14.5
b. b = 394 d. b = 45.3
____ 74. In ∆DEF, given the lengths of the sides, find the measure of the stated angle to the nearest degree.
d = 5.4, e = 10.5, f = 10.8; m∠F
a. 0.20 c. –2.3
b. 102 d. 78
____ 75. Zack, Rachel, and Maddie are unraveling a huge ball of yarn to see how long it is. As they move away from
each other, they form a triangle. The distance from Zack to Rachel is 3 meters. The distance from Rachel to
Maddie is 2.5 meters. The distance from Maddie to Zack is 4 meters. Find the measures of the three angles in
the triangle.
a. m∠Z = 38.6, m∠R = 92.9, m∠M = 48.5
b. m∠Z = 48.5, m∠R = 38.6, m∠M = 92.9
c. m∠Z = 92.9, m∠R = 48.5, m∠M = 38.6
d. m∠Z = 60, m∠R = 60, m∠M = 60
____ 76. Tomas, Ling, and Daniel are experimenting with a giant rubber band. They each hold the rubber band to
create a triangle. The distance from Tomas to Ling is 24 inches. The distance from Ling to Daniel is 36
inches. The distance from Daniel to Tomas is 20 inches. Find the measures of the three angles in the triangle.
a. m∠L = 31.6, m∠T = 109.5, m∠D = 38.9
b. m∠L = 38.9, m∠T = 31.6, m∠D = 109.5
c. m∠L = 109.5, m∠T = 38.9, m∠D = 31.6
d. m∠L = 60, m∠T = 60, m∠D = 60
Name: ________________________ ID: A
21
____ 77. Tiffany, Lori, and Mika are practicing for an egg-toss contest. The distance from Tiffany to Lori is 17 inches.
The distance from Lori to Mika is 32 inches. The distance from Mika to Tiffany is 28 inches. Find the
measures of the three angles in the triangle.
a. m∠L = 60.9, m∠T = 87, m∠M = 32.1
b. m∠L = 32.1, m∠T = 60.9, m∠M = 87
c. m∠L = 87, m∠T = 32.1, m∠M = 60.9
d. m∠L = 60, m∠T = 60, m∠M = 60
____ 78. Taina, Luther, and Della are tapping a balloon to each other in the air, trying to keep it from touching the
ground. The distance from Taina to Luther is 22 inches. The distance from Luther to Della is 40 inches. The
distance from Della to Taina is 34 inches. Find the measures of the three angles in the triangle.
a. m∠L = 58.1, m∠T = 88.5, m∠D = 33.4
b. m∠L = 33.4, m∠T = 58.1, m∠D = 88.5
c. m∠L = 88.5, m∠T = 33.4, m∠D = 58.1
d. m∠L = 60, m∠T = 60, m∠D = 60
____ 79. Luna created a trash can in the shape of a triangular prism. The sides of the triangle are 1.6 feet, 2.3 feet, and
1.2 feet. Find the measures of the angles of the triangle to the nearest tenth.
a. 109.6, 41.0, 29.4 c. 101.8, 37.1, 41.1
b. 19.6, 49.1, 60.6 d. 60, 60, 60
____ 80. Hoshi is working on an art project in the shape of a triangular prism. The sides of the triangle are 2.4 feet,
1.5 feet, and 1.3 feet. Find the measures of the angles of the triangle to the nearest tenth.
a. 117.8, 33.6, 28.6 c. 25.0, 39.8, 115.2
b. 27.8, 56.4, 95.8 d. 60, 60, 60
The radius, diameter, or circumference of a circle is given. Find the missing measures. Round to the nearest
hundredth if necessary.
____ 81. r = 13.1 km, d = ? , C = ?
a. d = 26.2 km, C = 82.31 km c. d = 6.55 km, C = 82.31 km
b. d = 26.2 km, C = 41.15 km d. d = 6.55 km, C = 41.15 km
____ 82. d = 22.3 km, r = ? , C = ?
a. r = 44.6 km, C = 35.03 km c. r = 11.15 km, C = 70.06 km
b. r = 11.15 km, C = 35.03 km d. r = 44.6 km, C = 70.06 km
____ 83. Find the exact circumference of the circle.
a. 7π cm c. 10π cm
b. 5π cm d. 4π cm
Name: ________________________ ID: A
22
____ 84. Find the exact circumference of the circle.
a. 12π 2 mm c. 12π mm
b. 24π 2 mm d. 6π 2 mm
Use the diagram to find the measure of the given angle.
____ 85. m∠BAC
a. 140 c. 130
b. 120 d. 150
____ 86. m∠BAF
a. 50 c. 130
b. 60 d. 40
____ 87. m∠EAD
a. 180 c. 60
b. 90 d. 30
____ 88. m∠FAE
a. 50 c. 60
b. 40 d. 30
Name: ________________________ ID: A
23
____ 89. m∠CAE
a. 170 c. 150
b. 160 d. 140
____ 90. m∠DAF
a. 110 c. 130
b. 120 d. 140
Use the diagram to find the measure of the given angle.
____ 91. ∠PRS
a. 95° c. 50°
b. 20° d. 85°
____ 92. ∠QRT
a. 95° c. 50°
b. 20° d. 85°
____ 93. ∠PRQ
a. 85° c. 50°
b. 20° d. 95°
____ 94. ∠SRT
a. 85° c. 50°
b. 20° d. 95°
Name: ________________________ ID: A
24
____ 95. In ñO, EC and AB are diameters, and ∠BOD ≅ ∠DOE ≅ ∠EOF ≅ ∠FOA.
Find m arc BC.
a. 270 c. 225
b. 90 d. 315
____ 96. In ñF, ∠CFD ≅ ∠DFE, m∠BFA = 7x, m∠AFE = 5x + 12, and BE and AC are diameters.
Find m arc DC.
a. 56 c. 50
b. 46 d. 49
Name: ________________________ ID: A
25
____ 97. In ñA, AC ≅ AF and AE = 10.
Find mEG.
a. 14 c. 10
b. 12 d. 16
____ 98. In ñU , TS = 15, UQ = US. Find mPR.
a. 28 c. 15
b. 30 d. 39
Name: ________________________ ID: A
26
____ 99.
If m∠BDC = 35, m arc AB = 100, and m arc CD = 100, find m∠1.
a. 45 c. 35
b. 70 d. 90
____ 100.
If m∠1 = 2x + 2, m∠2 = 9x, find m∠1.
a. 72 c. 75
b. 19 d. 18
Name: ________________________ ID: A
27
____ 101. In ñD, AB ≅ CB and m arc CE = 50. Find m∠BCE.
a. 85 c. 117
b. 108 d. 110
____ 102. Quadrilateral ABCD is inscribed in ñZ such that AB Ä DC and m∠BZC = 84. Find m∠DCA.
a. 48 c. 46
b. 44 d. 42
____ 103. Find x. Assume that segments that appear tangent are tangent.
a. 9 c. 12
b. 7 d. 17
Name: ________________________ ID: A
28
____ 104. Find x. Assume that segments that appear tangent are tangent.
a. 7 c. 14
b. 6 d. 5
____ 105. Find x. Assume that segments that appear tangent are tangent.
a. 7 c. 9
b. 5 d. 3
____ 106. Find x. Assume that segments that appear tangent are tangent.
a. 11 c. 13
b. 29 d. 16
Name: ________________________ ID: A
29
Find the measure of the numbered angle.
____ 107.
a. 230 c. 130
b. 115 d. 125
____ 108.
a. 55 c. 75
b. 65 d. 60
Name: ________________________ ID: A
30
____ 109.
a. 62.5 c. 112.5
b. 105 d. 115
____ 110.
a. 60 c. 80
b. 70 d. 65
____ 111.
a. 115 c. 120
b. 125 d. 130
Name: ________________________ ID: A
31
____ 112.
a. 81 c. 94
b. 90 d. 102
____ 113.
a. 92 c. 94
b. 95 d. 90
____ 114.
a. 90 c. 220
b. 180 d. 110
Name: ________________________ ID: A
32
____ 115.
a. 100 c. 90
b. 180 d. 95
____ 116.
a. 70 c. 80
b. 75 d. 85
Name: ________________________ ID: A
33
Find x. Assume that any segment that appears to be tangent is tangent.
____ 117.
a. 15 c. 25
b. 35 d. 45
____ 118.
a. 50 c. 60
b. 40 d. 70
Name: ________________________ ID: A
34
____ 119.
a. 10 c. 12
b. 5 d. 15
____ 120.
a. 65 c. 68
b. 66 d. 62
____ 121.
a. 15 c. 20
b. 30 d. 10
Name: ________________________ ID: A
35
____ 122.
a. 12 c. 8
b. 14 d. 10
____ 123.
a. 22 c. 18
b. 9 d. 11
____ 124.
a. 15 c. 25
b. 20 d. 30
Name: ________________________ ID: A
36
____ 125.
a. 47 c. 44
b. 48 d. 43
____ 126.
a. 35 c. 25
b. 20 d. 30
Name: ________________________ ID: A
37
Find x. Round to the nearest tenth if necessary.
____ 127.
a. 5 c. 3
b. 6 d. 4
____ 128.
a. 2 c. 3
b. 1 d. 4
Name: ________________________ ID: A
38
____ 129.
a. 7 c. 9
b. 8 d. 10
____ 130.
a. 2 c. 2.5
b. 3 d. 3.5
____ 131.
a. 2 c. 3.2
b. 2.4 d. 3.5
Name: ________________________ ID: A
39
____ 132.
a. 10.5 c. 3.2
b. 2.4 d. 3.5
____ 133.
a. 4.2 c. 3.2
b. 3.8 d. 3.7
____ 134.
a. 4 c. 6
b. 5.5 d. 5
Name: ________________________ ID: A
40
____ 135.
a. 6 c. 7
b. 6.5 d. 7.2
____ 136.
a. 6 c. 4
b. 5 d. 3
Name: ________________________ ID: A
41
Find x. Round to the nearest tenth if necessary. Assume that segments that appear to be tangent are tangent.
____ 137.
a. 5 c. 3.5
b. 2.8 d. 4
____ 138.
a. 9 c. 3
b. 2 d. 8
Name: ________________________ ID: A
42
____ 139.
a. 7.2 c. 1.7
b. 4 d. 3
____ 140.
a. 2.3 c. 2.8
b. 0.9 d. 3.4
____ 141.
a. 8.7 c. 5
b. 7 d. 10
Name: ________________________ ID: A
43
____ 142.
a. 8 c. 3
b. 10 d. 4
____ 143.
a. 3 c. 2
b. 7 d. 4
____ 144.
a. 4 c. 6
b. 5 d. 7
Name: ________________________ ID: A
44
____ 145.
a. 3.3 c. 3.1
b. 2.5 d. 4.5
____ 146.
a. 8.5 c. 9.3
b. 9.0 d. 9.6
____ 147. Write an equation for a circle with center at (–6, 10) and diameter 6.
a. (x + 6)2
+ (y − 10)2
= 9 c. (x − 6)2
+ (y + 10)2
= 9
b. (x + 6)2
+ (y − 10)2
= 36 d. (x − 6)2
+ (y + 10)2
= 36
____ 148. Write an equation for a circle with a diameter that has endpoints at (–10, 1) and (–8, 5). Round to the nearest
tenth if necessary.
a. (x − 9)2
+ (y + 3)2
= 20 c. (x + 9)2
+ (y − 3)2
= 5
b. (x − 9)2
+ (y + 3)2
= 5 d. (x + 9)2
+ (y − 3)2
= 20
Name: ________________________ ID: A
45
Graph the equation.
____ 149. x2
+ y2
= 16
a. c.
b. d.
Name: ________________________ ID: A
46
____ 150. (x + 1)2
+ (y + 3)2
= 16
a. c.
b. d.
ID: A
1
Accelerated Geometry/Algebra 2 Final Exam Review 2015
Answer Section
MULTIPLE CHOICE
1. ANS: D
Graph the equations and find their point of intersection.
Feedback
A What is the x-coordinate of the intersection?
B Did you graph both equations correctly?
C Write the coordinates of the intersection carefully.
D Correct!
PTS: 1 DIF: Average REF: Lesson 3-1
OBJ: 3-1.1 Solve systems of linear equations by graphing. NAT: NA 1 | NA 8 | NA 9 | NA 10 | NA 2
STA: 4.3.12 B.2 TOP: Solve systems of linear equations by graphing.
KEY: System of Linear Equations | Graphs
2. ANS: A
Graph the equations and find their point of intersection.
Feedback
A Correct!
B Did you plot the graphs correctly?
C Did you read the intersection of the graphs correctly?
D What is the x-coordinate of the intersection?
PTS: 1 DIF: Average REF: Lesson 3-1
OBJ: 3-1.1 Solve systems of linear equations by graphing. NAT: NA 1 | NA 8 | NA 9 | NA 10 | NA 2
STA: 4.3.12 B.2 TOP: Solve systems of linear equations by graphing.
KEY: System of Linear Equations | Graphs
3. ANS: B
Graph the equations and check the number of solutions.
Feedback
A Did you check the number of solutions?
B Correct!
C Are the y-intercepts equal?
D Did you find the slope of each line?
PTS: 1 DIF: Average REF: Lesson 3-1
OBJ: 3-1.2 Determine whether a system of linear equations is consistent and independent, consistent and
dependent, or inconsistent.
TOP: Determine whether a system of linear equations is consistent and independent, consistent and
dependent, or inconsistent.
KEY: System of Linear Equations | Consistent System | Inconsistent System
ID: A
2
4. ANS: B
Graph the equations and check the number of solutions.
Feedback
A Are the slopes equal?
B Correct!
C Are the y-intercepts equal?
D Did you plot the graphs correctly?
PTS: 1 DIF: Average REF: Lesson 3-1
OBJ: 3-1.2 Determine whether a system of linear equations is consistent and independent, consistent and
dependent, or inconsistent.
TOP: Determine whether a system of linear equations is consistent and independent, consistent and
dependent, or inconsistent.
KEY: System of Linear Equations | Consistent System | Inconsistent System
5. ANS: C
By using the method of substitution, solve one equation for one variable in terms of the other variable. Then,
substitute this expression for the variable in the other equation.
Feedback
A Did you calculate the values correctly?
B Recalculate the value of x.
C Correct!
D Recalculate the value of y.
PTS: 1 DIF: Average REF: Lesson 3-2
OBJ: 3-2.1 Solve systems of linear equations by using substitution.
NAT: NA 1 | NA 6 | NA 7 | NA 9 | NA 2 TOP: Solve systems of linear equations by using substitution.
KEY: System of Linear Equations | Substitution
6. ANS: C
By using the method of substitution, solve one equation for one variable in terms of the other variable. Then,
substitute this expression for the variable in the other equation.
Feedback
A Recalculate the value of s.
B Did you calculate correctly?
C Correct!
D Recalculate the value of r.
PTS: 1 DIF: Average REF: Lesson 3-2
OBJ: 3-2.1 Solve systems of linear equations by using substitution.
NAT: NA 1 | NA 6 | NA 7 | NA 9 | NA 2 TOP: Solve systems of linear equations by using substitution.
KEY: System of Linear Equations | Substitution
ID: A
3
7. ANS: D
Use the method of elimination to obtain the required answer.
Feedback
A Recalculate the value of p.
B Did you calculate the values correctly?
C Recalculate the value of q.
D Correct!
PTS: 1 DIF: Average REF: Lesson 3-2
OBJ: 3-2.2 Solve systems of linear equations by using elimination.
NAT: NA 1 | NA 6 | NA 7 | NA 9 | NA 2 TOP: Solve systems of linear equations by using elimination.
KEY: System of Linear Equations | Elimination
8. ANS: B
Use the method of elimination to obtain the required answer.
Feedback
A Recalculate the value of a.
B Correct!
C Did you calculate the values correctly?
D Recalculate the value of b.
PTS: 1 DIF: Average REF: Lesson 3-2
OBJ: 3-2.2 Solve systems of linear equations by using elimination.
NAT: NA 1 | NA 6 | NA 7 | NA 9 | NA 2 TOP: Solve systems of linear equations by using elimination.
KEY: System of Linear Equations | Elimination
9. ANS: C
Both the inequalities should be plotted and the region common to both should be shaded.
Feedback
A You have plotted the first inequality incorrectly.
B You have plotted the second inequality incorrectly.
C Correct!
D You have plotted the inequalities incorrectly.
PTS: 1 DIF: Average REF: Lesson 3-3
OBJ: 3-3.1 Solve systems of inequalities by graphing. NAT: NA 1 | NA 6 | NA 9 | NA 10 | NA 2
TOP: Solve systems of inequalities by graphing. KEY: System of Inequalities | Graphs
ID: A
4
10. ANS: D
Plot the first inequality. Then, plot the positive and negative values of y and shade the common region.
Feedback
A What is the y-intercept of the first related equation?
B Did you plot the second equation correctly?
C Did you plot all the equations?
D Correct!
PTS: 1 DIF: Average REF: Lesson 3-3
OBJ: 3-3.1 Solve systems of inequalities by graphing. NAT: NA 1 | NA 6 | NA 9 | NA 10 | NA 2
TOP: Solve systems of inequalities by graphing. KEY: System of Inequalities | Graphs
11. ANS: D
Solve the system of inequalities by graphing the inequalities on the same coordinate plane. The solution set is
represented by the intersection of the graphs.
Feedback
A Did you plot the inequalities correctly?
B Did you check the sign of the coordinates?
C You have interchanged the coordinates.
D Correct!
PTS: 1 DIF: Advanced REF: Lesson 3-3
OBJ: 3-3.2 Determine the coordinates of the vertices of a region formed by the graph of a system of
inequalities. NAT: NA 1 | NA 6 | NA 9 | NA 10 | NA 2
TOP: Determine the coordinates of the vertices of a region formed by the graph of a system of inequalities.
KEY: System of Inequalities | Graphs
12. ANS: A
Solve the system of inequalities by graphing the inequalities on the same coordinate plane. The solution set is
represented by the intersection of the graphs.
Feedback
A Correct!
B You have interchanged the coordinates.
C Did you check the sign of the coordinates?
D Did you plot the inequalities correctly?
PTS: 1 DIF: Advanced REF: Lesson 3-3
OBJ: 3-3.2 Determine the coordinates of the vertices of a region formed by the graph of a system of
inequalities. NAT: NA 1 | NA 6 | NA 9 | NA 10 | NA 2
TOP: Determine the coordinates of the vertices of a region formed by the graph of a system of inequalities.
KEY: System of Inequalities | Graphs
ID: A
5
13. ANS: A
Write the system of inequalities and then plot the graph.
Feedback
A Correct!
B Did you check the values of the inequalities?
C Did you use the correct sign in plotting the inequalities?
D Did you check the intercept of the inequalities?
PTS: 1 DIF: Advanced REF: Lesson 3-4
OBJ: 3-4.2 Solve real-world problems using linear programming.
NAT: NA 1 | NA 6 | NA 8 | NA 10 | NA 2
TOP: Solve real-world problems using linear programming.
KEY: Linear Programming | Real-World Problems
14. ANS: A
Solve three equations simultaneously.
Feedback
A Correct!
B Check whether the values of the variables have been interchanged.
C Only two of the values are correct.
D The values of a, b, and c are interchanged.
PTS: 1 DIF: Average REF: Lesson 3-5
OBJ: 3-5.1 Solve systems of linear equations in three variables.
NAT: NA 1 | NA 7 | NA 9 | NA 10 | NA 2
TOP: Solve systems of linear equations in three variables.
KEY: System of Equations | Three Variables
15. ANS: A
Solve three equations simultaneously.
Feedback
A Correct!
B Only two of the values are correct.
C Check whether the values of the variables have been interchanged.
D The values of a, b, and c are interchanged.
PTS: 1 DIF: Average REF: Lesson 3-5
OBJ: 3-5.1 Solve systems of linear equations in three variables.
NAT: NA 1 | NA 7 | NA 9 | NA 10 | NA 2
TOP: Solve systems of linear equations in three variables.
KEY: System of Equations | Three Variables
ID: A
6
16. ANS: C
For the quadratic equation ax2
+ bx + c, the y-intercept is c and the equation of axis of
symmetry is x =−b
2a.
Feedback
A Did you check the signs?
B Did you interchange the y-intercept and the x-coordinate of the vertex?
C Correct!
D Did you use the correct formulas for the y-intercept and the x-coordinate of the vertex?
PTS: 1 DIF: Average REF: Lesson 5-1 OBJ: 5-1.1 Graph quadratic functions.
NAT: NA 2 | NA 6 | NA 8 | NA 10 | NA 3 TOP: Graph quadratic functions.
KEY: Quadratic Functions | Graph Quadratic Functions
17. ANS: B
First, choose integer values for x. Then evaluate the function for each x value. Graph the resulting coordinate
pairs and connect the points with a smooth curve.
Feedback
A Graph ordered pairs that satisfy the function.
B Correct!
C Did you plot the graph correctly?
D When the coefficient of x2 is less than 0, the graphs opens down.
PTS: 1 DIF: Advanced REF: Lesson 5-1 OBJ: 5-1.1 Graph quadratic functions.
NAT: NA 2 | NA 6 | NA 8 | NA 10 | NA 3 TOP: Graph quadratic functions.
KEY: Quadratic Functions | Graph Quadratic Functions
18. ANS: C
The y-coordinate of the vertex of a quadratic function is the maximum or minimum value obtained by the
function.
Feedback
A The coefficient of x2 is greater than zero.
B The graph of this function opens up.
C Correct!
D What is the value of the y-coordinate of the vertex?
PTS: 1 DIF: Average REF: Lesson 5-1
OBJ: 5-1.2 Find and interpret the maximum and minimum values of a quadratic function.
NAT: NA 2 | NA 6 | NA 8 | NA 10 | NA 3
TOP: Find and interpret the maximum and minimum values of a quadratic function.
KEY: Maximum Values | Minimum Values | Quadratic Functions
ID: A
7
19. ANS: D
The y-coordinate of the vertex of a quadratic function is the maximum or minimum value obtained by the
function.
Feedback
A The graph of the function opens down.
B The coefficient of x2 is less than zero.
C What is the value of the y-coordinate of the vertex?
D Correct!
PTS: 1 DIF: Average REF: Lesson 5-1
OBJ: 5-1.2 Find and interpret the maximum and minimum values of a quadratic function.
NAT: NA 2 | NA 6 | NA 8 | NA 10 | NA 3
TOP: Find and interpret the maximum and minimum values of a quadratic function.
KEY: Maximum Values | Minimum Values | Quadratic Functions
20. ANS: B
The zeros of the function are the x-intercepts of its graph. These are the solutions of the related quadratic
equation because f(x) = 0 at those points.
Feedback
A What are the x-intercepts of the graph?
B Correct!
C Find the zeros of the function, not the vertex.
D The zeros of the function are the solutions of the related equation.
PTS: 1 DIF: Advanced REF: Lesson 5-2
OBJ: 5-2.1 Solve quadratic equations by graphing. NAT: NA 1 | NA 6 | NA 9 | NA 10 | NA 2
STA: 4.3.12 B.3 TOP: Solve quadratic equations by graphing.
KEY: Quadratic Equations | Solve Quadratic Equations
21. ANS: A
The zeros of the function are the x-intercepts of its graph. These are the solutions of the related quadratic
equation because f(x) = 0 at those points.
Feedback
A Correct!
B The zeros of the function are the solutions of the related equation.
C What are the x-intercepts of the graph?
D Find the zeros of the function, not the vertex.
PTS: 1 DIF: Advanced REF: Lesson 5-2
OBJ: 5-2.1 Solve quadratic equations by graphing. NAT: NA 1 | NA 6 | NA 9 | NA 10 | NA 2
STA: 4.3.12 B.3 TOP: Solve quadratic equations by graphing.
KEY: Quadratic Equations | Solve Quadratic Equations
ID: A
8
22. ANS: D
When exact roots cannot be found by graphing, you can estimate solutions by stating the consecutive integers
between which the roots are located.
Feedback
A Is the coefficient of x2 less than zero?
B Did you graph the function correctly?
C When the coefficient of x2 is greater than 0, the graph opens up.
D Correct!
PTS: 1 DIF: Advanced REF: Lesson 5-2
OBJ: 5-2.2 Estimate solutions of quadratic equations by graphing.
NAT: NA 1 | NA 6 | NA 9 | NA 10 | NA 2 STA: 4.3.12 B.2
TOP: Estimate solutions of quadratic equations by graphing.
KEY: Quadratic Equations | Solve Quadratic Equations
23. ANS: D
When exact roots cannot be found by graphing, you can estimate solutions by stating the consecutive integers
between which the roots are located.
Feedback
A Did you graph the function correctly?
B When the coefficient of x2 is less than 0, the graph opens down.
C Is the coefficient of x2 greater than 0?
D Correct!
PTS: 1 DIF: Advanced REF: Lesson 5-2
OBJ: 5-2.2 Estimate solutions of quadratic equations by graphing.
NAT: NA 1 | NA 6 | NA 9 | NA 10 | NA 2 STA: 4.3.12 B.2
TOP: Estimate solutions of quadratic equations by graphing.
KEY: Quadratic Equations | Solve Quadratic Equations
24. ANS: D
A quadratic equation with roots p and q can be written as (x − p)(x − q) = 0, which can be further simplified.
Feedback
A Did you verify the answer by substituting the values?
B Did you calculate the coefficients correctly?
C Did you check the signs of the coefficients?
D Correct!
PTS: 1 DIF: Average REF: Lesson 5-3
OBJ: 5-3.1 Write quadratic equations in intercept form. NAT: NA 1 | NA 3 | NA 7 | NA 8 | NA 2
TOP: Write quadratic equations in intercept form.
KEY: Quadratic Equations | Roots of Quadratic Equations
ID: A
9
25. ANS: A
A quadratic equation with roots p and q can be written as (x − p)(x − q) = 0, which can be further simplified.
Feedback
A Correct!
B Did you check the signs of the coefficients?
C Did you calculate the coefficients correctly?
D Did you verify the answer by substituting the values?
PTS: 1 DIF: Average REF: Lesson 5-3
OBJ: 5-3.1 Write quadratic equations in intercept form. NAT: NA 1 | NA 3 | NA 7 | NA 8 | NA 2
TOP: Write quadratic equations in intercept form.
KEY: Quadratic Equations | Roots of Quadratic Equations
26. ANS: B
For any real numbers a and b, if ab = 0, then either a = 0, b − 0, or both a and b are equal to zero.
Feedback
A Did you use the Zero Product Property correctly?
B Correct!
C Did you verify the answer by substituting the values?
D Did you factor the binomial correctly?
PTS: 1 DIF: Average REF: Lesson 5-3
OBJ: 5-3.2 Solve quadratic equations by factoring. NAT: NA 1 | NA 3 | NA 7 | NA 8 | NA 2
STA: 4.3.12 D.2 TOP: Solve quadratic equations by factoring.
KEY: Quadratic Equations | Solve Quadratic Equations | Factoring
27. ANS: B
For any real numbers a and b, if ab = 0, then either a = 0, b = 0, or both a and b are equal to zero.
Feedback
A Did you use the Zero Product Property correctly?
B Correct!
C Did you factor the binomial correctly?
D Did you verify the answer by substituting the values?
PTS: 1 DIF: Average REF: Lesson 5-3
OBJ: 5-3.2 Solve quadratic equations by factoring. NAT: NA 1 | NA 3 | NA 7 | NA 8 | NA 2
STA: 4.3.12 D.2 TOP: Solve quadratic equations by factoring.
KEY: Quadratic Equations | Solve Quadratic Equations | Factoring
ID: A
10
28. ANS: A
For any numbers a, b, and c, abc = a ⋅ b ⋅ c . Also, −1 = i2
= i.
Feedback
A Correct!
B Check for the radical sign.
C Take the square root of the number.
D Check your calculation.
PTS: 1 DIF: Basic REF: Lesson 5-4 OBJ: 5-4.1 Find square roots.
NAT: NA 1 | NA 7 | NA 9 | NA 10 | NA 2 TOP: Find square roots.
KEY: Square Roots
29. ANS: A
a
b=
a
b
Feedback
A Correct!
B Check the numerator.
C Check the square root of the numerator.
D Check your calculation.
PTS: 1 DIF: Average REF: Lesson 5-4 OBJ: 5-4.1 Find square roots.
NAT: NA 1 | NA 7 | NA 9 | NA 10 | NA 2 TOP: Find square roots.
KEY: Square Roots
30. ANS: C
Multiply the real numbers and imaginary numbers separately.
Feedback
A Check your calculation.
B Check the sign.
C Correct!
D Multiply the imaginary numbers again.
PTS: 1 DIF: Average REF: Lesson 5-4
OBJ: 5-4.2 Perform operations with pure imaginary numbers. NAT: NA 1 | NA 3 | NA 7 | NA 10 | NA 2
TOP: Perform operations with pure imaginary numbers. KEY: Imaginary Numbers
ID: A
11
31. ANS: A
Multiply the real numbers and imaginary numbers separately.
Feedback
A Check your calculation.
B Check the sign.
C Correct!
D Compute again.
PTS: 1 DIF: Average REF: Lesson 5-4
OBJ: 5-4.2 Perform operations with pure imaginary numbers. NAT: NA 1 | NA 3 | NA 7 | NA 10 | NA 2
TOP: Perform operations with pure imaginary numbers. KEY: Imaginary Numbers
32. ANS: A
Combine the real and imaginary parts of the complex numbers to add them.
Feedback
A Correct!
B Combine the real parts and then combine the imaginary parts.
C Add the real and imaginary parts of the two numbers separately.
D Did you combine the similar terms correctly?
PTS: 1 DIF: Average REF: Lesson 5-4
OBJ: 5-4.3 Perform addition and subtraction operations with complex numbers.
NAT: NA 1 | NA 3 | NA 7 | NA 10 | NA 2
TOP: Perform addition and subtraction operations with complex numbers.
KEY: Complex Numbers | Add Complex Numbers | Subtract Complex Numbers
33. ANS: B
Combine the real and imaginary parts of the complex numbers to add them.
Feedback
A Combine the real parts and then combine the imaginary parts.
B Correct!
C Combine the similar terms correctly.
D Add the real and imaginary parts of the two numbers separately.
PTS: 1 DIF: Average REF: Lesson 5-4
OBJ: 5-4.3 Perform addition and subtraction operations with complex numbers.
NAT: NA 1 | NA 3 | NA 7 | NA 10 | NA 2
TOP: Perform addition and subtraction operations with complex numbers.
KEY: Complex Numbers | Add Complex Numbers | Subtract Complex Numbers
ID: A
12
34. ANS: B
Use the FOIL method to multiply the complex numbers and use the formula i2
= −1. Combine the real parts
and then the imaginary parts of the two numbers.
Feedback
A Did you combine the real parts?
B Correct!
C Use the value of i2.
D Did you use the FOIL method to find the product?
PTS: 1 DIF: Average REF: Lesson 5-4
OBJ: 5-4.4 Perform multiplication operations with complex numbers.
NAT: NA 1 | NA 3 | NA 7 | NA 10 | NA 2
TOP: Perform multiplication operations with complex numbers.
KEY: Complex Numbers | Multiply Complex Numbers
35. ANS: C
Use the FOIL method to multiply the complex numbers and use the formula i2
= −1. Combine the real parts
and then the imaginary parts of the two numbers.
Feedback
A Use the FOIL method to find the product.
B Use the value of i2.
C Correct!
D Combine the real parts.
PTS: 1 DIF: Average REF: Lesson 5-4
OBJ: 5-4.4 Perform multiplication operations with complex numbers.
NAT: NA 1 | NA 3 | NA 7 | NA 10 | NA 2
TOP: Perform multiplication operations with complex numbers.
KEY: Complex Numbers | Multiply Complex Numbers
36. ANS: D
Multiply the numerator as well as the denominator by the conjugate of the denominator. Use the FOIL
method and the difference of squares to simplify the given expression.
Feedback
A Multiply the numerator with the conjugate of the denominator.
B Have you multiplied the constant in the numerator with its conjugate of the
denominator?
C Did you multiply the conjugates correctly in the denominator?
D Correct!
PTS: 1 DIF: Average REF: Lesson 5-4
OBJ: 5-4.5 Perform division operations with complex numbers.
NAT: NA 1 | NA 3 | NA 7 | NA 10 | NA 2
TOP: Perform division operations with complex numbers.
KEY: Complex Numbers | Divide Complex Numbers
ID: A
13
37. ANS: A
Multiply the numerator as well as the denominator by the conjugate of the denominator. Use the FOIL
method and the difference of squares to simplify the given expression.
Feedback
A Correct!
B Did you multiply the conjugates correctly in the denominator?
C Multiply the numerator also with the conjugate of the denominator.
D Did you combine the similar terms correctly?
PTS: 1 DIF: Average REF: Lesson 5-4
OBJ: 5-4.5 Perform division operations with complex numbers.
NAT: NA 1 | NA 3 | NA 7 | NA 10 | NA 2
TOP: Perform division operations with complex numbers.
KEY: Complex Numbers | Divide Complex Numbers
38. ANS: D
For any real number n, if x2
= n, then x = ± n .
Feedback
A Did you use the Square Root Property correctly?
B Did you verify the answer by substituting the values?
C Did you factor the perfect square trinomial correctly?
D Correct!
PTS: 1 DIF: Average REF: Lesson 5-5
OBJ: 5-5.1 Solve quadratic equations by using the Square Root Property.
NAT: NA 1 | NA 3 | NA 7 | NA 10 | NA 2 STA: 4.3.12 D.2
TOP: Solve quadratic equations by using the Square Root Property.
KEY: Quadratic Equations | Solve Quadratic Equations | Square Root Property
39. ANS: A
For any real number n, if x2
= n, then x = ± n .
Feedback
A Correct!
B Did you factor the perfect square trinomial correctly?
C Did you use the Square Root Property correctly?
D Did you verify the answer by substituting the values?
PTS: 1 DIF: Average REF: Lesson 5-5
OBJ: 5-5.1 Solve quadratic equations by using the Square Root Property.
NAT: NA 1 | NA 3 | NA 7 | NA 10 | NA 2 STA: 4.3.12 D.2
TOP: Solve quadratic equations by using the Square Root Property.
KEY: Quadratic Equations | Solve Quadratic Equations | Square Root Property
ID: A
14
40. ANS: A
To complete the square for any quadratic expression of the form x2
+ bx, find half of b, and square the result.
Then, add the result to x2
+ bx.
Feedback
A Correct!
B Did you make the quadratic expression a perfect square?
C Did you verify the answer by substituting the values?
D Did you check the signs of the roots?
PTS: 1 DIF: Average REF: Lesson 5-5
OBJ: 5-5.2 Solve quadratic equations by completing the square.
NAT: NA 1 | NA 3 | NA 7 | NA 10 | NA 2 STA: 4.3.12 D.2
TOP: Solve quadratic equations by completing the square.
KEY: Quadratic Equations | Solve Quadratic Equations | Completing the Square
41. ANS: D
To complete the square for any quadratic expression of the form x2
+ bx, find half of b, and square the result.
Then, add the result to x2
+ bx.
Feedback
A Did you make the quadratic expression a perfect square?
B Did you check the signs of the roots?
C Find both the solutions.
D Correct!
PTS: 1 DIF: Average REF: Lesson 5-5
OBJ: 5-5.2 Solve quadratic equations by completing the square.
NAT: NA 1 | NA 3 | NA 7 | NA 10 | NA 2 STA: 4.3.12 D.2
TOP: Solve quadratic equations by completing the square.
KEY: Quadratic Equations | Solve Quadratic Equations | Completing the Square
42. ANS: D
The solution of a quadratic equation of the form ax2
+ bx + c = 0, where a ≠ 0, is obtained by using the
formula x =−b ± b
2− 4ac
2a.
Feedback
A Did you check the signs of the solution?
B Did you use the correct formula?
C Did you substitute the values of a, b, and c correctly in the formula?
D Correct!
PTS: 1 DIF: Average REF: Lesson 5-6
OBJ: 5-6.1 Solve quadratic equations by using the Quadratic Formula.
NAT: NA 1 | NA 6 | NA 8 | NA 9 | NA 2 STA: 4.3.12 D.2
TOP: Solve quadratic equations by using the Quadratic Formula.
KEY: Quadratic Equations | Solve Quadratic Equations | Quadratic Formula
ID: A
15
43. ANS: D
The solution of a quadratic equation of the form ax2
+ bx + c = 0, where a ≠ 0, is obtained by using the
formula x =−b ± b
2− 4ac
2a.
Feedback
A Did you substitute the values of a, b, and c correctly in the formula?
B Did you evaluate the discriminant correctly?
C Did you use the correct formula?
D Correct!
PTS: 1 DIF: Average REF: Lesson 5-6
OBJ: 5-6.1 Solve quadratic equations by using the Quadratic Formula.
NAT: NA 1 | NA 6 | NA 8 | NA 9 | NA 2 STA: 4.3.12 D.2
TOP: Solve quadratic equations by using the Quadratic Formula.
KEY: Quadratic Equations | Solve Quadratic Equations | Quadratic Formula
44. ANS: C
If b2
− 4ac > 0 and b2
− 4ac is a perfect square, then the roots are rational.
If b2
− 4ac > 0 and b2
− 4ac is not a perfect square, then the roots are real and irrational.
Feedback
A Did you use the correct formula for the discriminant?
B Did you check the sign of the answer?
C Correct!
D Did you use the correct order of operations while evaluating the discriminant?
PTS: 1 DIF: Basic REF: Lesson 5-6
OBJ: 5-6.2 Use the discriminant to determine the number and types of roots of a quadratic equation.
NAT: NA 1 | NA 6 | NA 8 | NA 9 | NA 2 STA: 4.3.12 D.2
TOP: Use the discriminant to determine the number and types of roots of a quadratic equation.
KEY: Quadratic Equations | Roots of Quadratic Equations | Discriminates
45. ANS: C
If b2
− 4ac < 0, then the roots are complex.
Feedback
A Did you use the correct order of operations while evaluating the discriminant?
B Did you use the correct formula for the discriminant?
C Correct!
D Did you check the sign of the answer?
PTS: 1 DIF: Basic REF: Lesson 5-6
OBJ: 5-6.2 Use the discriminant to determine the number and types of roots of a quadratic equation.
NAT: NA 1 | NA 6 | NA 8 | NA 9 | NA 2 STA: 4.3.12 D.2
TOP: Use the discriminant to determine the number and types of roots of a quadratic equation.
KEY: Quadratic Equations | Roots of Quadratic Equations | Discriminates
ID: A
16
46. ANS: C
The vertex form of a quadratic function is y = a(x − h)2
+ k .
The equation of the axis of symmetry of a parabola is x = h.
Feedback
A Did you use the correct equation of the axis of symmetry?
B Did you check the x-coordinate of the vertex?
C Correct!
D Did you identify the coordinates of the vertex correctly?
PTS: 1 DIF: Basic REF: Lesson 5-7
OBJ: 5-7.1 Analyze quadratic functions in the form y = a(x - h)^2 + k.
NAT: NA 2 | NA 7 | NA 8 | NA 10 | NA 6 STA: 4.3.12 B.2
TOP: Analyze quadratic functions in the form y = a(x - h)^2 + k.
KEY: Quadratic Functions | Axis of Symmetry
47. ANS: A
Graph the related quadratic equation. Because the inequality symbol is >, the parabola should be dashed. Test
a point (x1 , y1) inside the parabola. If (x1 , y1) is the solution of the inequality, shade the region inside the
parabola. If (x1 , y1) is not a solution, shade the region outside the parabola.
Feedback
A Correct!
B What is the inequality symbol used in the equation?
C Did you test a point inside the parabola correctly?
D Did you shade correctly?
PTS: 1 DIF: Advanced REF: Lesson 5-8
OBJ: 5-8.1 Graph quadratic inequalities in two variables. NAT: NA 2 | NA 6 | NA 9 | NA 10 | NA 3
STA: 4.3.12 B.1 TOP: Graph quadratic inequalities in two variables.
KEY: Quadratic Inequalities | Graph Quadratic Inequalities
48. ANS: A
Graph the related quadratic equation. Since the inequality symbol is <, the parabola should be dashed. Test a
point (x1 , y1) inside the parabola. If (x1 , y1) is the solution of the inequality, shade the region inside the
parabola. If (x1 , y1) is not a solution, shade the region outside the parabola.
Feedback
A Correct!
B Did you test a point inside the parabola correctly?
C Did you shade correctly?
D What is the inequality symbol used in the equation?
PTS: 1 DIF: Advanced REF: Lesson 5-8
OBJ: 5-8.1 Graph quadratic inequalities in two variables. NAT: NA 2 | NA 6 | NA 9 | NA 10 | NA 3
STA: 4.3.12 B.1 TOP: Graph quadratic inequalities in two variables.
KEY: Quadratic Inequalities | Graph Quadratic Inequalities
ID: A
17
49. ANS: C
Find the product of the given numbers. Find the square root of the product.
Feedback
A How do you find the geometric mean?
B Remember to take the square root of the product.
C Correct!
D This is the arithmetic mean not geometric mean.
PTS: 1 DIF: Basic REF: Lesson 8-1
OBJ: 8-1.1 Find the geometric mean between two numbers. NAT: NCTM GM.1 | NCTM GM.1b
TOP: Find the geometric mean between two numbers. KEY: Geometric Mean
50. ANS: D
Find the product of the given numbers. Find the square root of the product.
Feedback
A This is the arithmetic mean not geometric mean.
B How do you find the geometric mean?
C Remember to take the square root of the product.
D Correct!
PTS: 1 DIF: Basic REF: Lesson 8-1
OBJ: 8-1.1 Find the geometric mean between two numbers. NAT: NCTM GM.1 | NCTM GM.1b
TOP: Find the geometric mean between two numbers. KEY: Geometric Mean
51. ANS: A
The altitude is the geometric mean between the measures of the two segments of the hypotenuse.
Feedback
A Correct!
B This is the arithmetic mean not geometric mean.
C How do you find the geometric mean?
D Remember to take the square root of the product.
PTS: 1 DIF: Average REF: Lesson 8-1
OBJ: 8-1.2 Solve problems involving relationships between parts of a right triangle and the altitude
hypotenuse. NAT: NCTM GM.1 | NCTM GM.1b STA: 4.2.12 E.1
TOP: Solve problems involving relationships between parts of a right triangle and the altitude hypotenuse.
KEY: Triangles | Altitudes | Hypotenuse
ID: A
18
52. ANS: B
The sum of the squares of the two sides is equal to the square of the hypotenuse.
Feedback
A Remember to square the numbers.
B Correct!
C Remember to find the square root.
D Which side is the hypotenuse?
PTS: 1 DIF: Basic REF: Lesson 8-2
OBJ: 8-2.1 Use the Pythagorean Theorem. NAT: NCTM GM.1 | NCTM GM.1b
STA: 4.2.12 A.1 | 4.2.12 E.1 TOP: Use the Pythagorean Theorem.
KEY: Pythagorean Theorem
53. ANS: B
Use the distance formula to determine the lengths of the sides. If the sum of the squares of the two shorter
sides is equal to the square of the third side, the triangle is a right triangle.
Feedback
A What is the converse of the Pythagorean Theorem?
B Correct!
C Check the Pythagorean Theorem.
D Check the Pythagorean Theorem.
PTS: 1 DIF: Average REF: Lesson 8-2
OBJ: 8-2.2 Use the converse of the Pythagorean Theorem. NAT: NCTM GM.1 | NCTM GM.1b
STA: 4.2.12 A.1 | 4.2.12 E.1 TOP: Use the converse of the Pythagorean Theorem.
KEY: Converse of Pythagorean Theorem
54. ANS: A
Use the distance formula to determine the lengths of the sides. If the sum of the squares of the two shorter
sides is equal to the square of the third side, the triangle is a right triangle.
Feedback
A Correct!
B Check the Pythagorean Theorem.
C What is the converse of the Pythagorean Theorem?
D Check the Pythagorean Theorem.
PTS: 1 DIF: Average REF: Lesson 8-2
OBJ: 8-2.2 Use the converse of the Pythagorean Theorem. NAT: NCTM GM.1 | NCTM GM.1b
STA: 4.2.12 A.1 | 4.2.12 E.1 TOP: Use the converse of the Pythagorean Theorem.
KEY: Converse of Pythagorean Theorem
ID: A
19
55. ANS: C
To find the leg of a 45°-45°-90° triangle when the hypotenuse is given, divide the hypotenuse by 2 . To
find the perimeter of the square, find the sum of all the sides.
Feedback
A This is the area, not the perimeter of the square.
B Is the number given the length of a side or the diagonal?
C Correct!
D Before the perimeter can be found, first find the length of each side.
PTS: 1 DIF: Average REF: Lesson 8-3
OBJ: 8-3.1 Use properties of 45º-45º-90º triangles. NAT: NCTM GM.1 | NCTM GM.1d
STA: 4.2.12 E.1 TOP: Use properties of 45º-45º-90º triangles.
KEY: Triangles | 45-45-90 Triangles
56. ANS: D
The length of the hypotenuse is equal to the length of a leg times 2 . The diagonal of a square bisects the
angle.
Feedback
A Multiply by the square root of two to find the length of the hypotenuse.
B Check the length of the hypotenuse and the size of the angle.
C The diagonal of a square bisects the angle.
D Correct!
PTS: 1 DIF: Basic REF: Lesson 8-3
OBJ: 8-3.1 Use properties of 45º-45º-90º triangles. NAT: NCTM GM.1 | NCTM GM.1d
STA: 4.2.12 E.1 TOP: Use properties of 45º-45º-90º triangles.
KEY: Triangles | 45-45-90 Triangles
57. ANS: D
The shorter leg is half the length of the hypotenuse. The longer leg is 3 times the length of the shorter leg.
Feedback
A How do you find the length of the side opposite the 60° angle?
B Switch the x and y values.
C How do you find the length of the side opposite the 30° angle?
D Correct!
PTS: 1 DIF: Basic REF: Lesson 8-3
OBJ: 8-3.2 Use properties of 30º-60º-90º triangles. NAT: NCTM GM.1 | NCTM GM.1d
STA: 4.2.12 E.1 TOP: Use properties of 30º-60º-90º triangles.
KEY: Triangles | 30-60-90 Triangles
ID: A
20
58. ANS: D
The shorter leg is half the length of the hypotenuse. The longer leg is 3 times the length of the shorter leg.
Feedback
A Switch the x and y values.
B How do you find the length of the side opposite the 60° angle?
C How do you find the length of the side opposite the 30° angle?
D Correct!
PTS: 1 DIF: Average REF: Lesson 8-3
OBJ: 8-3.2 Use properties of 30º-60º-90º triangles. NAT: NCTM GM.1 | NCTM GM.1d
STA: 4.2.12 E.1 TOP: Use properties of 30º-60º-90º triangles.
KEY: Triangles | 30-60-90 Triangles
59. ANS: B
In trigonometry, you can find the measure of an angle by using the inverse of sine, cosine, or tangent.
Feedback
A Which trigonometric ratio should be used?
B Correct!
C This is the ratio not the angle.
D Which trigonometric ratio should be used?
PTS: 1 DIF: Basic REF: Lesson 8-4
OBJ: 8-4.1 Find trigonometric ratios using right triangles. NAT: NCTM GM.1 | NCTM GM.1d
STA: 4.2.12 E.1 TOP: Find trigonometric ratios using right triangles.
KEY: Trigonometric Ratios | Right Triangles
60. ANS: C
Determine the ratio associated with the given trigonometric term. Divide the numerator by the denominator.
Feedback
A Check the setup of the ratio.
B Which trigonometric ratio are you asked to find?
C Correct!
D Which trigonometric ratio are you asked to find?
PTS: 1 DIF: Average REF: Lesson 8-4
OBJ: 8-4.1 Find trigonometric ratios using right triangles. NAT: NCTM GM.1 | NCTM GM.1d
STA: 4.2.12 E.1 TOP: Find trigonometric ratios using right triangles.
KEY: Trigonometric Ratios | Right Triangles
ID: A
21
61. ANS: C
Draw a picture of the situation. Determine which trigonometric ratio should be used to solve. Substitute the
numbers given. Solve for the answer.
Feedback
A Check the trigonometric ratio.
B Which trigonometric ratio should be used?
C Correct!
D Which trigonometric ratio should be used?
PTS: 1 DIF: Average REF: Lesson 8-4
OBJ: 8-4.2 Solve problems using trigonometric ratios. NAT: NCTM GM.1 | NCTM GM.1d
STA: 4.2.12 E.1 TOP: Solve problems using trigonometric ratios.
KEY: Trigonometric Ratios | Solve Problems
62. ANS: A
Draw a picture of the situation. Determine which trigonometric ratio should be used to solve. Substitute the
numbers given. Solve for the answer.
Feedback
A Correct!
B Check the trigonometric ratio.
C Which trigonometric ratio should be used?
D Which trigonometric ratio should be used?
PTS: 1 DIF: Average REF: Lesson 8-4
OBJ: 8-4.2 Solve problems using trigonometric ratios. NAT: NCTM GM.1 | NCTM GM.1d
STA: 4.2.12 E.1 TOP: Solve problems using trigonometric ratios.
KEY: Trigonometric Ratios | Solve Problems
63. ANS: B
Draw a picture of the situation. Determine which trigonometric ratio should be used to solve. Substitute the
numbers given. Solve for the answer.
Feedback
A Remember to include the initial height of two miles.
B Correct!
C Which trigonometric ratio should be used?
D Which trigonometric ratio should be used?
PTS: 1 DIF: Average REF: Lesson 8-4
OBJ: 8-4.2 Solve problems using trigonometric ratios. NAT: NCTM GM.1 | NCTM GM.1d
STA: 4.2.12 E.1 TOP: Solve problems using trigonometric ratios.
KEY: Trigonometric Ratios | Solve Problems
ID: A
22
64. ANS: C
Draw a picture of the situation. Determine which trigonometric ratio should be used to solve. Substitute the
numbers given. Solve for the answer.
Feedback
A Do not subtract the initial height of the balloon.
B Remember to include the initial height of one mile.
C Correct!
D Which trigonometric ratio should be used?
PTS: 1 DIF: Basic REF: Lesson 8-4
OBJ: 8-4.2 Solve problems using trigonometric ratios. NAT: NCTM GM.1 | NCTM GM.1d
STA: 4.2.12 E.1 TOP: Solve problems using trigonometric ratios.
KEY: Trigonometric Ratios | Solve Problems
65. ANS: A
Draw a picture of the situation. Determine which trigonometric ratio should be used to solve. Substitute the
numbers given. Solve for the answer.
Feedback
A Correct!
B Do not use the cosine ratio.
C What is the sine ratio?
D What is the sine ratio?
PTS: 1 DIF: Basic REF: Lesson 8-5
OBJ: 8-5.1 Solve problems involving angles of elevation. NAT: NCTM GM.1 | NCTM GM.1d
STA: 4.2.12 A.1 | 4.2.12 E.1 TOP: Solve problems involving angles of elevation.
KEY: Angle of Elevation
66. ANS: C
Draw a picture of the situation. Determine which trigonometric ratio should be used to solve. Substitute the
numbers given. Solve for the answer.
Feedback
A Did you use the inverse sine to solve.
B Do not use the tangent ratio.
C Correct!
D Do not use the cosine ratio.
PTS: 1 DIF: Average REF: Lesson 8-5
OBJ: 8-5.1 Solve problems involving angles of elevation. NAT: NCTM GM.1 | NCTM GM.1d
STA: 4.2.12 A.1 | 4.2.12 E.1 TOP: Solve problems involving angles of elevation.
KEY: Angle of Elevation
ID: A
23
67. ANS: D
Draw a picture of the situation. Determine which trigonometric ratio should be used to solve. Substitute the
numbers given. Solve for the answer.
Feedback
A Do not use inverse sine to solve.
B Do not use the cosine ratio.
C Do not use the tangent ratio.
D Correct!
PTS: 1 DIF: Average REF: Lesson 8-5
OBJ: 8-5.1 Solve problems involving angles of elevation. NAT: NCTM GM.1 | NCTM GM.1d
STA: 4.2.12 A.1 | 4.2.12 E.1 TOP: Solve problems involving angles of elevation.
KEY: Angle of Elevation
68. ANS: A
Draw a picture of the situation. Determine which trigonometric ratio should be used to solve. Substitute the
numbers given. Solve for the answer.
Feedback
A Correct!
B Do not use the cosine ratio.
C Do not add together the numbers given.
D Do not subtract the numbers given.
PTS: 1 DIF: Average REF: Lesson 8-5
OBJ: 8-5.2 Solve problems involving angles of depression. NAT: NCTM GM.1 | NCTM GM.1d
STA: 4.2.12 A.1 | 4.2.12 E.1 TOP: Solve problems involving angles of depression.
KEY: Angle of Depression
69. ANS: B
Draw a picture of the situation. Determine which trigonometric ratio should be used to solve. Substitute the
numbers given. Solve for the answer.
Feedback
A Do not use the tangent ratio.
B Correct!
C Do not use the cosine ratio.
D Do not use the tangent ratio.
PTS: 1 DIF: Average REF: Lesson 8-5
OBJ: 8-5.2 Solve problems involving angles of depression. NAT: NCTM GM.1 | NCTM GM.1d
STA: 4.2.12 A.1 | 4.2.12 E.1 TOP: Solve problems involving angles of depression.
KEY: Angle of Depression
ID: A
24
70. ANS: B
Substitute the given values into the Law of Sines. Cross multiply. Divide each side by sinL.
Feedback
A Remember to divide both sides by the sine of angle L.
B Correct!
C Check the setup of the proportion.
D Check the Law of Sines to determine the setup of the ratios.
PTS: 1 DIF: Average REF: Lesson 8-6
OBJ: 8-6.1 Use the Law of Sines to solve triangles. NAT: NCTM GM.1 | NCTM GM.1d
STA: 4.2.12 E.1 | 4.5.12 E.1 TOP: Use the Law of Sines to solve triangles.
KEY: Law of Sines | Solve Triangles
71. ANS: C
Substitute the given values into the Law of Sines. Cross multiply. Divide each side by the length of side l.
Feedback
A Check the Law of Sines to determine the setup of the ratios.
B Remember to take the inverse of sine to solve for the angle.
C Correct!
D Remember to divide both sides by the length of side l.
PTS: 1 DIF: Average REF: Lesson 8-6
OBJ: 8-6.1 Use the Law of Sines to solve triangles. NAT: NCTM GM.1 | NCTM GM.1d
STA: 4.2.12 E.1 | 4.5.12 E.1 TOP: Use the Law of Sines to solve triangles.
KEY: Law of Sines | Solve Triangles
72. ANS: D
Draw a picture of the situation. Use the Law of Sines to solve. Substitute the numbers given. Solve for the
missing side. Find the perimeter.
Feedback
A This is the sum of the other two angles of the triangle.
B This is the length of one side of the triangle.
C Remember to include all three sides.
D Correct!
PTS: 1 DIF: Average REF: Lesson 8-6
OBJ: 8-6.2 Solve problems by using the Law of Sines. NAT: NCTM GM.1 | NCTM GM.1d
STA: 4.2.12 E.1 | 4.5.12 E.1 TOP: Solve problems by using the Law of Sines.
KEY: Law of Sines | Solve Problems
ID: A
25
73. ANS: A
Substitute the given values into the Law of Cosines. Simplify the equation. Find the square root of both sides.
Feedback
A Correct!
B Check the equation for the Law of Cosines.
C Should sine or cosine be used to solve the problem?
D Remember to find the square root of this number.
PTS: 1 DIF: Average REF: Lesson 8-7
OBJ: 8-7.1 Use the Law of Cosines to solve triangles. NAT: NCTM GM.1 | NCTM GM.1d
STA: 4.2.12 E.1 | 4.5.12 E.1 TOP: Use the Law of Cosines to solve triangles.
KEY: Law of Cosines | Solve Triangles
74. ANS: D
Substitute the given values into the Law of Cosines. Simplify the equation. Find the measure of the stated
angle by using inverse cosine.
Feedback
A Remember to find the inverse cosine.
B Do not subtract the angle from 180.
C Check the work for this equation.
D Correct!
PTS: 1 DIF: Average REF: Lesson 8-7
OBJ: 8-7.1 Use the Law of Cosines to solve triangles. NAT: NCTM GM.1 | NCTM GM.1d
STA: 4.2.12 E.1 | 4.5.12 E.1 TOP: Use the Law of Cosines to solve triangles.
KEY: Law of Cosines | Solve Triangles
75. ANS: A
Substitute the given values into the Law of Cosines. Simplify the equation. Find the measure of the stated
angle by using inverse cosine.
Feedback
A Correct!
B Which angle goes with each vertex?
C Which angle goes with each vertex?
D The triangle is not equilateral.
PTS: 1 DIF: Average REF: Lesson 8-7
OBJ: 8-7.2 Solve problems by using the Law of Cosines.
NAT: NCTM PS.1 | NCTM PS.2 | NCTM PS.3 STA: 4.2.12 E.1 | 4.5.12 E.1
TOP: Solve problems by using the Law of Cosines. KEY: Law of Cosines | Solve Problems
ID: A
26
76. ANS: A
Substitute the given values into the Law of Cosines. Simplify the equation. Find the measure of the stated
angle by using inverse cosine.
Feedback
A Correct!
B Which angle goes with each vertex?
C Which angle goes with each vertex?
D The triangle is not equilateral.
PTS: 1 DIF: Average REF: Lesson 8-7
OBJ: 8-7.2 Solve problems by using the Law of Cosines.
NAT: NCTM PS.1 | NCTM PS.2 | NCTM PS.3 STA: 4.2.12 E.1 | 4.5.12 E.1
TOP: Solve problems by using the Law of Cosines. KEY: Law of Cosines | Solve Problems
77. ANS: A
Substitute the given values into the Law of Cosines. Simplify the equation. Find the measure of the stated
angle by using inverse cosine.
Feedback
A Correct!
B Which angle goes with each vertex?
C Which angle goes with each vertex?
D The triangle is not equilateral.
PTS: 1 DIF: Average REF: Lesson 8-7
OBJ: 8-7.2 Solve problems by using the Law of Cosines.
NAT: NCTM PS.1 | NCTM PS.2 | NCTM PS.3 STA: 4.2.12 E.1 | 4.5.12 E.1
TOP: Solve problems by using the Law of Cosines. KEY: Law of Cosines | Solve Problems
78. ANS: A
Substitute the given values into the Law of Cosines. Simplify the equation. Find the measure of the stated
angle by using inverse cosine.
Feedback
A Correct!
B Which angle goes with each vertex?
C Which angle goes with each vertex?
D The triangle is not equilateral.
PTS: 1 DIF: Average REF: Lesson 8-7
OBJ: 8-7.2 Solve problems by using the Law of Cosines.
NAT: NCTM PS.1 | NCTM PS.2 | NCTM PS.3 STA: 4.2.12 E.1 | 4.5.12 E.1
TOP: Solve problems by using the Law of Cosines. KEY: Law of Cosines | Solve Problems
ID: A
27
79. ANS: A
Substitute the given values into the Law of Cosines. Simplify the equation. Find the measure of the stated
angle by using inverse cosine.
Feedback
A Correct!
B Use the cosine ratio not sine ratio to solve.
C Use the cosine ratio not the tangent ratio to solve.
D The triangle is not equilateral.
PTS: 1 DIF: Average REF: Lesson 8-7
OBJ: 8-7.2 Solve problems by using the Law of Cosines.
NAT: NCTM PS.1 | NCTM PS.2 | NCTM PS.3 STA: 4.2.12 E.1 | 4.5.12 E.1
TOP: Solve problems by using the Law of Cosines. KEY: Law of Cosines | Solve Problems
80. ANS: A
Substitute the given values into the Law of Cosines. Simplify the equation. Find the measure of the stated
angle by using inverse cosine.
Feedback
A Correct!
B Use the cosine ratio not sine ratio to solve.
C Use the cosine ratio not the tangent ratio to solve.
D The triangle is not equilateral.
PTS: 1 DIF: Average REF: Lesson 8-7
OBJ: 8-7.2 Solve problems by using the Law of Cosines.
NAT: NCTM PS.1 | NCTM PS.2 | NCTM PS.3 STA: 4.2.12 E.1 | 4.5.12 E.1
TOP: Solve problems by using the Law of Cosines. KEY: Law of Cosines | Solve Problems
81. ANS: A
diameter = 2 × radius
Circumference = (2 × radius × π) or (diameter × π)
Feedback
A Correct!
B Check your circumference calculation.
C Check your diameter calculation.
D Check both your diameter and circumference calculations.
PTS: 1 DIF: Basic REF: Lesson 10-1
OBJ: 10-1.1 Identify and use parts of circles. NAT: NCTM ME.2
STA: 4.2.12 A.3 TOP: Identify and use parts of circles. KEY: Circles | Parts of Circles
ID: A
28
82. ANS: C
radius = diameter ÷ 2
Circumference = (2 × radius × π) or (diameter × π)
Feedback
A Check both your radius and circumference calculations.
B Check your circumference calculation.
C Correct!
D Check your radius calculation.
PTS: 1 DIF: Basic REF: Lesson 10-1
OBJ: 10-1.1 Identify and use parts of circles. NAT: NCTM ME.2
STA: 4.2.12 A.3 TOP: Identify and use parts of circles. KEY: Circles | Parts of Circles
83. ANS: B
The circumference formula is diameter × π. The diameter shown also happens to be the hypotenuse of the
right triangle inscribed in the circle, so it can be found by using the Pythagorean Theorem.
Feedback
A Use the Pythagorean Theorem.
B Correct!
C How did you find the diameter?
D Use the Pythagorean Theorem.
PTS: 1 DIF: Average REF: Lesson 10-1
OBJ: 10-1.2 Solve problems involving the circumference of a circle.
NAT: NCTM GM.1 | NCTM GM.1a | NCTM ME.2 STA: 4.5.12 E.1
TOP: Solve problems involving the circumference of a circle. KEY: Circles | Circumference
84. ANS: A
The circumference formula is diameter × π. The diameter shown also happens to be the diagonal of a square,
so it can be found by multiplying the side of the square by 2 .
Feedback
A Correct!
B Check your diameter again.
C You need a 2 in your answer.
D You need to double your radius.
PTS: 1 DIF: Average REF: Lesson 10-1
OBJ: 10-1.2 Solve problems involving the circumference of a circle.
NAT: NCTM GM.1 | NCTM GM.1a | NCTM ME.2 STA: 4.5.12 E.1
TOP: Solve problems involving the circumference of a circle. KEY: Circles | Circumference
ID: A
29
85. ANS: C
∠BAC forms a linear pair with ∠CAD, so their sum is 180.
Feedback
A Check your subtraction.
B How many degrees are in a linear pair?
C Correct!
D Check your subtraction.
PTS: 1 DIF: Basic REF: Lesson 10-2
OBJ: 10-2.1 Recognize major arcs, minor arcs, semicircles, and central angles, and their measures.
TOP: Recognize major arcs, minor arcs, semicircles, and central angles, and their measures.
KEY: Major Arcs | Minor Arcs | Semicircles | Central Angles
86. ANS: A
∠BAF is a vertical angle with ∠BAC, so they are congruent.
Feedback
A Correct!
B Remember vertical angles.
C How are vertical angles related?
D Remember vertical angles.
PTS: 1 DIF: Basic REF: Lesson 10-2
OBJ: 10-2.1 Recognize major arcs, minor arcs, semicircles, and central angles, and their measures.
TOP: Recognize major arcs, minor arcs, semicircles, and central angles, and their measures.
KEY: Major Arcs | Minor Arcs | Semicircles | Central Angles
87. ANS: B
∠EAD is a right angle, so its measure is 90.
Feedback
A It's a right angle.
B Correct!
C It's a right angle.
D What is the measure of a right angle?
PTS: 1 DIF: Basic REF: Lesson 10-2
OBJ: 10-2.1 Recognize major arcs, minor arcs, semicircles, and central angles, and their measures.
TOP: Recognize major arcs, minor arcs, semicircles, and central angles, and their measures.
KEY: Major Arcs | Minor Arcs | Semicircles | Central Angles
ID: A
30
88. ANS: B
∠FAE is complementary with ∠BAF.
Feedback
A Did you subtract carefully?
B Correct!
C With what angle is it complementary?
D What is the measure of angle BAE?
PTS: 1 DIF: Average REF: Lesson 10-2
OBJ: 10-2.1 Recognize major arcs, minor arcs, semicircles, and central angles, and their measures.
TOP: Recognize major arcs, minor arcs, semicircles, and central angles, and their measures.
KEY: Major Arcs | Minor Arcs | Semicircles | Central Angles
89. ANS: D
∠CAE is equal to the sum of ∠CAD and ∠EAD.
Feedback
A Add the two angles that make up this angle.
B Add the two angles that make up this angle.
C What is the measure of angle DAE?
D Correct!
PTS: 1 DIF: Average REF: Lesson 10-2
OBJ: 10-2.1 Recognize major arcs, minor arcs, semicircles, and central angles, and their measures.
TOP: Recognize major arcs, minor arcs, semicircles, and central angles, and their measures.
KEY: Major Arcs | Minor Arcs | Semicircles | Central Angles
90. ANS: C
∠DAF is equal to the sum of ∠DAE and ∠FAE..
Feedback
A Add the two angles that make up this angle.
B Add the two angles that make up this angle.
C Correct!
D What two angles did you add together?
PTS: 1 DIF: Average REF: Lesson 10-2
OBJ: 10-2.1 Recognize major arcs, minor arcs, semicircles, and central angles, and their measures.
TOP: Recognize major arcs, minor arcs, semicircles, and central angles, and their measures.
KEY: Major Arcs | Minor Arcs | Semicircles | Central Angles
ID: A
31
91. ANS: A
∠PRS and ∠QRT are vertical angles and are therefore congruent. So, set the two expressions equal and solve
for x.
Feedback
A Correct!
B That's the answer for x, you need the measure of ∠PRS .
C Did you use vertical angles?
D How are vertical angles related?
PTS: 1 DIF: Average REF: Lesson 10-2
OBJ: 10-2.1 Recognize major arcs, minor arcs, semicircles, and central angles, and their measures.
TOP: Recognize major arcs, minor arcs, semicircles, and central angles, and their measures.
KEY: Major Arcs | Minor Arcs | Semicircles | Central Angles
92. ANS: A
∠PRS and ∠QRT are vertical angles and are therefore congruent. So, set the two expressions equal and solve
for x.
Feedback
A Correct!
B That's the answer for x, you need the measure of ∠QRT.
C How are vertical angles related?
D Did you use vertical angles?
PTS: 1 DIF: Average REF: Lesson 10-2
OBJ: 10-2.1 Recognize major arcs, minor arcs, semicircles, and central angles, and their measures.
TOP: Recognize major arcs, minor arcs, semicircles, and central angles, and their measures.
KEY: Major Arcs | Minor Arcs | Semicircles | Central Angles
93. ANS: A
∠PRQ and ∠QRT are a linear pair and are therefore supplementary. First find m∠QRT. ∠PRS and ∠QRT
are vertical angles and are therefore congruent. So, set the two expressions equal and solve for x.
Feedback
A Correct!
B That's the answer for x, you need the measure of ∠PRQ.
C Check over your work.
D How many degrees are in a linear pair?
PTS: 1 DIF: Average REF: Lesson 10-2
OBJ: 10-2.1 Recognize major arcs, minor arcs, semicircles, and central angles, and their measures.
TOP: Recognize major arcs, minor arcs, semicircles, and central angles, and their measures.
KEY: Major Arcs | Minor Arcs | Semicircles | Central Angles
ID: A
32
94. ANS: A
∠SRT and ∠PRS are a linear pair and are therefore supplementary. First find m∠PRS . ∠PRS and ∠QRT are
vertical angles and are therefore congruent. So, set the two expressions equal and solve for x.
Feedback
A Correct!
B That's the answer for x, you need the measure of ∠SRT.
C Did you use vertical angles?
D Did you use a linear pair?
PTS: 1 DIF: Average REF: Lesson 10-2
OBJ: 10-2.1 Recognize major arcs, minor arcs, semicircles, and central angles, and their measures.
TOP: Recognize major arcs, minor arcs, semicircles, and central angles, and their measures.
KEY: Major Arcs | Minor Arcs | Semicircles | Central Angles
95. ANS: B
Since the diameters EC and AB are perpendicular, they form right angles which measure 90. Additionally,
since ∠BOD ≅ ∠DOE ≅ ∠EOF ≅ ∠FOA, all of those angles are 1
290°( ) which is 45°. The measure of an arc
is equal to the measure of its central angle, so add any angles that are necessary to find the measure of the
given angle and its intercepted arc.
Feedback
A What are the measures of the four smaller angles?
B Correct!
C All large angles are 90° and small ones are 45°.
D All large angles are 90° and small ones are 45°.
PTS: 1 DIF: Average REF: Lesson 10-2 OBJ: 10-2.2 Find arc length.
NAT: NCTM GM.1 | NCTM GM.1b STA: 4.2.12 A.3 TOP: Find arc length.
KEY: Arcs | Arc Length
96. ANS: D
Since BE is a diameter, m∠BFA + m∠AFE = 180. Solve the equation, then substitute the value of x to find
m∠BFA. Since ∠BFA and ∠EFC are vertical angles, they are congruent. Additionally, use the fact that
m arc DC = m∠CFD =1
2m∠CFE =
1
2m∠BFA.
Feedback
A m∠BFA + m∠AFE = 180
B Did you make use of vertical angles?
C Did you solve for x?
D Correct!
PTS: 1 DIF: Average REF: Lesson 10-2 OBJ: 10-2.2 Find arc length.
NAT: NCTM GM.1 | NCTM GM.1b STA: 4.2.12 A.3 TOP: Find arc length.
KEY: Arcs | Arc Length
ID: A
33
97. ANS: B
Since AF, EF and AE form a right triangle, you can use the Pythagorean Theorem to find mEF. Since CF is
a segment that passes through the center of the circle and is perpendicular to chord EG, it also bisects EG.
That means mEG = 2 × mEF.
Feedback
A You need to double the length of EF.
B Correct!
C The hypotenuse is not the solution.
D Use the other leg of triangle AFE.
PTS: 1 DIF: Average REF: Lesson 10-3
OBJ: 10-3.1 Recognize and use relationships between arcs and chords.
NAT: NCTM GM.1 | NCTM GM.1b | NCTM ME.2 STA: 4.2.12 A.3
TOP: Recognize and use relationships between arcs and chords.
KEY: Arcs | Chords | Diameters
98. ANS: B
Since UQ and US are congruent and perpendicular to separate chords, the chords PR and TR must also be
congruent. Additionally, UQ and US bisect these chords, so TS = RS. So take the given measure of TS and
double it. That will be the measure of TR and also PR.
Feedback
A What is the relationship between PR and TS?
B Correct!
C Isn't PR longer than TS?
D What is the relationship between PR and TS?
PTS: 1 DIF: Average REF: Lesson 10-3
OBJ: 10-3.1 Recognize and use relationships between arcs and chords.
NAT: NCTM GM.1 | NCTM GM.1b | NCTM ME.2 STA: 4.2.12 A.3
TOP: Recognize and use relationships between arcs and chords.
KEY: Arcs | Chords | Diameters
ID: A
34
99. ANS: A
The measure of BC is 2 × m∠BDC. Since the full circle measures 360, then mAD is
360 – (mAB + mBC + mCD). Finally, since ∠1 is an inscribed angle for AD, its measure is 1
2mAD.
Feedback
A Correct!
B Focus on AD.
C Can you find the measure of AD?
D Inscribed angles are half the measure of the arc.
PTS: 1 DIF: Average REF: Lesson 10-4
OBJ: 10-4.1 Find measures of inscribed angles.
NAT: NCTM GM.1 | NCTM GM.1b | NCTM ME.2 STA: 4.2.12 A.3
TOP: Find measures of inscribed angles. KEY: Inscribed Angles | Measure of Inscribed Angles
100. ANS: D
m∠B = 90 since it is inscribed in a semicircle. Since the sum of the angles in any triangle is 180°,
m∠1 + m∠2 = 90. Substitute the given values for ∠1 and ∠2 into that equation. Then substitute the value
found for x into the expression for ∠1.
Feedback
A You are looking for ∠1.
B ∠1 + ∠2 = 90°.
C Did you find the value of x?
D Correct!
PTS: 1 DIF: Average REF: Lesson 10-4
OBJ: 10-4.1 Find measures of inscribed angles.
NAT: NCTM GM.1 | NCTM GM.1b | NCTM ME.2 STA: 4.2.12 A.3
TOP: Find measures of inscribed angles. KEY: Inscribed Angles | Measure of Inscribed Angles
101. ANS: D
m∠BCE = m∠BCA + m∠ACE, so begin by finding the measures of ∠BCA and ∠ACE. Since ∆ABC and
∆AEC are both inscribed in semicircles, they are right triangles (∠B and ∠E are right angles). Additionally,
since AB ≅ CB, ∆ABC is isosceles. That makes m∠BCA = 45. Now for ∠ACE. Since ∠CAE is an inscribed
angle, its measure is one-half its intercepted arc (arc CE). That makes ∠ACE = 90° − ∠CAE. Finally, add the
measures of the two angles to get the final answer.
Feedback
A How do you find the measure of and inscribed angle?
B ∆ABC is an isosceles right triangle; ∠ACE = 90° − ∠CAE.
C Did you subtract carefully when finding the measure of ∠CAE?
D Correct!
PTS: 1 DIF: Average REF: Lesson 10-4
OBJ: 10-4.2 Find measures of angles of inscribed polygons. NAT: NCTM GM.1 | NCTM GM.1a
STA: 4.2.12 A.3 TOP: Find measures of angles of inscribed polygons.
KEY: Inscribed Polygons | Measure of Inscribed Angles
ID: A
35
102. ANS: D
First note that m arc BC = m∠BZC because a central angle of a circle is always congruent to its intercepted
arc. Secondly, m∠BAC is one-half m arc BC, as the measure of an inscribed angle is half the measure of its
intercepted arc. Since AB Ä DC, ∠DCA ≅ ∠BAC because alternate interior angles are congruent. So
m∠DCA = m∠BAC.
Feedback
A Look for alternate interior angles.
B Look for alternate interior angles.
C Did you find the measure of ∠BAC?.
D Correct!
PTS: 1 DIF: Average REF: Lesson 10-4
OBJ: 10-4.2 Find measures of angles of inscribed polygons. NAT: NCTM GM.1 | NCTM GM.1a
STA: 4.2.12 A.3 TOP: Find measures of angles of inscribed polygons.
KEY: Inscribed Polygons | Measure of Inscribed Angles
103. ANS: C
The triangle shown is a right triangle since the tangent segment, CB, intersects a radius, AB, which always
results in a right angle. So to solve for x, use the Pythagorean Theorem.
Feedback
A Did you use the Pythagorean Theorem?
B Use the Pythagorean Theorem.
C Correct!
D Is the triangle a right triangle?
PTS: 1 DIF: Average REF: Lesson 10-5 OBJ: 10-5.1 Use properties of tangents.
NAT: NCTM GM.1 | NCTM GM.1a STA: 4.2.12 A.3 TOP: Use properties of tangents.
KEY: Tangents
104. ANS: B
The triangle shown is a right triangle since the tangent segment, FE, intersects a radius, DE, which always
results in a right angle. So to solve for x, use the Pythagorean Theorem. Note that mDE = x since they are
both radii of the same circle.
Feedback
A Use the Pythagorean Theorem and mDE = x.
B Correct!
C Is the triangle a right?
D Use the Pythagorean Theorem and mDE = x.
PTS: 1 DIF: Average REF: Lesson 10-5 OBJ: 10-5.1 Use properties of tangents.
NAT: NCTM GM.1 | NCTM GM.1a STA: 4.2.12 A.3 TOP: Use properties of tangents.
KEY: Tangents
ID: A
36
105. ANS: B
Recall that two tangents from the same external point are congruent. So, for example, mHN = mHJ and
mKJ = mKL. Those two equalities, plus the fact that mHK = mHJ + mJK allows us to make the equality
mHK = mHN + mKL. Substitute the appropriate values into that equation and solve for x.
Feedback
A Are two tangents to a circle from the same external point congruent?
B Correct!
C The mKJ = mKL and mHN = mHJ .
D The mKJ = mKL and mHN = mHJ .
PTS: 1 DIF: Average REF: Lesson 10-5
OBJ: 10-5.2 Solve problems involving circumscribed polygons.
NAT: NCTM GM.1 | NCTM GM.1b | NCTM ME.2 STA: 4.2.12 A.3
TOP: Solve problems involving circumscribed polygons. KEY: Circumscribed Polygons
106. ANS: A
Recall that two tangents from the same external point are congruent. So, for example, mPW = mPQ and
mRQ = mRS . Those two equalities, plus the fact that mPR = mPQ + mRQ, lead us to the equation
mPR = mPW + mRS . Substitute the appropriate values into this equation and solve for x.
Feedback
A Correct!
B Are two tangents to a circle from the same external point congruent?
C PW=PQ and RQ=RS.
D PW=PQ and RQ=RS.
PTS: 1 DIF: Average REF: Lesson 10-5
OBJ: 10-5.2 Solve problems involving circumscribed polygons.
NAT: NCTM GM.1 | NCTM GM.1b | NCTM ME.2 STA: 4.2.12 A.3
TOP: Solve problems involving circumscribed polygons. KEY: Circumscribed Polygons
107. ANS: B
When two secants intersect in the interior of a circle, then the measure of an angle formed by this intersection
is equal to one-half the sum of the measures of the arcs intercepted by the angle and its vertical angle.
Feedback
A Did you add the intercepted arcs?
B Correct!
C Add the intercepted arcs and divide by 2.
D Did you divide correctly?
PTS: 1 DIF: Basic REF: Lesson 10-6
OBJ: 10-6.1 Find measures of angles formed by lines intersecting on or inside a circle.
NAT: NCTM GM.1 | NCTM GM.1b | NCTM ME.2 STA: 4.2.12 A.3
TOP: Find measures of angles formed by lines intersecting on or inside a circle.
KEY: Measure of Angles | Circles
ID: A
37
108. ANS: B
When two secants intersect in the interior of a circle, then the measure of an angle formed by this intersection
is equal to one-half the sum of the measures of the arcs intercepted by the angle and its vertical angle.
Feedback
A What is the relationship between the two angles formed when two secants intersect in
the interior of a circle?
B Correct!
C Add the intercepted arcs and divide by 2.
D Be careful with division.
PTS: 1 DIF: Basic REF: Lesson 10-6
OBJ: 10-6.1 Find measures of angles formed by lines intersecting on or inside a circle.
NAT: NCTM GM.1 | NCTM GM.1b | NCTM ME.2 STA: 4.2.12 A.3
TOP: Find measures of angles formed by lines intersecting on or inside a circle.
KEY: Measure of Angles | Circles
109. ANS: C
When two secants intersect in the interior of a circle, then the measure of an angle formed by this intersection
is equal to one-half the sum of the measures of the arcs intercepted by the angle and its vertical angle. In this
diagram, the measure of one of the intercepted arcs for ∠5 is not given, but it can be found since the sum of
all of the arcs must be 360. Subtracting the sum of the other 3 arcs from 360, leaves 110.
Feedback
A Did you use the correct arcs?
B Add the intercepted arcs and divide by 2.
C Correct!
D Did you find the measure of the unlabeled arc?
PTS: 1 DIF: Basic REF: Lesson 10-6
OBJ: 10-6.1 Find measures of angles formed by lines intersecting on or inside a circle.
NAT: NCTM GM.1 | NCTM GM.1b | NCTM ME.2 STA: 4.2.12 A.3
TOP: Find measures of angles formed by lines intersecting on or inside a circle.
KEY: Measure of Angles | Circles
ID: A
38
110. ANS: A
When two secants intersect in the interior of a circle, then the measure of an angle formed by this intersection
is equal to one-half the sum of the measures of the arcs intercepted by the angle and its vertical angle. In this
diagram, the measures of the intercepted arcs for ∠3 are not given, but they must have a sum of 120° since
the arcs shown have a sum of 240 (360 – 240 = 120).
Feedback
A Correct!
B Did you use the correct arcs?
C Add the intercepted arcs and divide by 2.
D Did you divide correctly?
PTS: 1 DIF: Average REF: Lesson 10-6
OBJ: 10-6.1 Find measures of angles formed by lines intersecting on or inside a circle.
NAT: NCTM GM.1 | NCTM GM.1b | NCTM ME.2 STA: 4.2.12 A.3
TOP: Find measures of angles formed by lines intersecting on or inside a circle.
KEY: Measure of Angles | Circles
111. ANS: B
When two secants intersect in the interior of a circle, then the measure of an angle formed by this intersection
is equal to one-half the sum of the measures of the arcs intercepted by the angle and its vertical angle. In this
diagram, the measures of the intercepted arcs for ∠6 are not given, but they have a sum of 250 since the arcs
shown have a sum of 110 (360 – 110 = 250).
Feedback
A Add the intercepted arcs and divide by 2.
B Correct!
C Did you divide correctly?
D How do you find the measures of the other two arcs?
PTS: 1 DIF: Average REF: Lesson 10-6
OBJ: 10-6.1 Find measures of angles formed by lines intersecting on or inside a circle.
NAT: NCTM GM.1 | NCTM GM.1b | NCTM ME.2 STA: 4.2.12 A.3
TOP: Find measures of angles formed by lines intersecting on or inside a circle.
KEY: Measure of Angles | Circles
ID: A
39
112. ANS: A
When two secants intersect in the interior of a circle, then the measure of an angle formed by this intersection
is equal to one-half the sum of the measures of the arcs intercepted by the angle and its vertical angle. In this
diagram the measures of the intercepted arcs for ∠4 are not given. However, the full circle measures 360°, so
3a° + 4a° +6a° +7a° = 360°. Solving this equation, a = 18. So the intercepted arcs for ∠4 are 54° and 108°.
Feedback
A Correct!
B What is the sum of the measures of the arcs intercepted by ∠4 and its vertical angle?
C Add the intercepted arcs and divide by 2.
D Did you find the value of a?
PTS: 1 DIF: Average REF: Lesson 10-6
OBJ: 10-6.1 Find measures of angles formed by lines intersecting on or inside a circle.
NAT: NCTM GM.1 | NCTM GM.1b | NCTM ME.2 STA: 4.2.12 A.3
TOP: Find measures of angles formed by lines intersecting on or inside a circle.
KEY: Measure of Angles | Circles
113. ANS: D
When two secants intersect in the interior of a circle, then the measure of an angle formed by this intersection
is equal to one-half the sum of the measures of the arcs intercepted by the angle and its vertical angle. In this
diagram the measures of the intercepted arcs for ∠7 are not given. However, the full circle measures 360°, so
2x° + 2x° +4x° +4x° = 360°. Solving this equation, x = 30°. So the intercepted arcs for ∠7 are 60° and 120°.
Feedback
A What are the measures of the intercepted arcs of ∠7 and its vertical angle?
B Did you find the value of x?.
C Add the intercepted arcs and divide by 2.
D Correct!
PTS: 1 DIF: Average REF: Lesson 10-6
OBJ: 10-6.1 Find measures of angles formed by lines intersecting on or inside a circle.
NAT: NCTM GM.1 | NCTM GM.1b | NCTM ME.2 STA: 4.2.12 A.3
TOP: Find measures of angles formed by lines intersecting on or inside a circle.
KEY: Measure of Angles | Circles
ID: A
40
114. ANS: D
When a secant intersects a tangent at the point of tangency, then the measure of the angle formed is one-half
the measure of the intercepted arc. In this diagram, the measure of the intercepted arc for ∠8 is 220.
Feedback
A How is the measure of the angle related to the measure of the intercepted arc?
B Find half the measure of the intercepted arc.
C Should you have divided by two?
D Correct!
PTS: 1 DIF: Average REF: Lesson 10-6
OBJ: 10-6.1 Find measures of angles formed by lines intersecting on or inside a circle.
NAT: NCTM GM.1 | NCTM GM.1b | NCTM ME.2 STA: 4.2.12 A.3
TOP: Find measures of angles formed by lines intersecting on or inside a circle.
KEY: Measure of Angles | Circles
115. ANS: C
When a secant intersects a tangent at the point of tangency, then the measure of the angle formed is one-half
the measure of the intercepted arc. In this diagram, the measure of the intercepted arc for ∠9 is 180 because
the chord is also a diameter of the circle.
Feedback
A Find half the measure of the intercepted arc.
B Should you have divided by two?
C Correct!
D Find half the measure of the intercepted arc.
PTS: 1 DIF: Average REF: Lesson 10-6
OBJ: 10-6.1 Find measures of angles formed by lines intersecting on or inside a circle.
NAT: NCTM GM.1 | NCTM GM.1b | NCTM ME.2 STA: 4.2.12 A.3
TOP: Find measures of angles formed by lines intersecting on or inside a circle.
KEY: Measure of Angles | Circles
116. ANS: A
When a secant intersects a tangent at the point of tangency, then the measure of the angle formed is one-half
the measure of the intercepted arc. In this diagram, the measure of the intercepted arc for ∠10 is 140 since
360 – 220 = 140.
Feedback
A Correct!
B Find half the measure of the intercepted arc.
C How are the measures of the angle and the intercepted arc related?
D Find half the measure of the intercepted arc.
PTS: 1 DIF: Average REF: Lesson 10-6
OBJ: 10-6.1 Find measures of angles formed by lines intersecting on or inside a circle.
NAT: NCTM GM.1 | NCTM GM.1b | NCTM ME.2 STA: 4.2.12 A.3
TOP: Find measures of angles formed by lines intersecting on or inside a circle.
KEY: Measure of Angles | Circles
ID: A
41
117. ANS: C
When two secants intersect in the exterior of a circle, then the measure of the angle formed is equal to
one-half the positive difference of the measures of the intercepted arcs.
Feedback
A Check your subtraction.
B Use subtraction, not addition.
C Correct!
D Did you subtract carefully?
PTS: 1 DIF: Average REF: Lesson 10-6
OBJ: 10-6.2 Find measures of angles formed by lines intersecting outside the circle.
NAT: NCTM GM.1 | NCTM GM.1b | NCTM ME.2 STA: 4.2.12 A.3
TOP: Find measures of angles formed by lines intersecting outside the circle.
KEY: Measure of Angles | Circles
118. ANS: B
When two secants intersect in the exterior of a circle, then the measure of the angle formed is equal to
one-half the positive difference of the measures of the intercepted arcs.
Feedback
A Did you subtract carefully?
B Correct!
C Use subtraction, not addition.
D Did you find one-half of the positive difference?
PTS: 1 DIF: Average REF: Lesson 10-6
OBJ: 10-6.2 Find measures of angles formed by lines intersecting outside the circle.
NAT: NCTM GM.1 | NCTM GM.1b | NCTM ME.2 STA: 4.2.12 A.3
TOP: Find measures of angles formed by lines intersecting outside the circle.
KEY: Measure of Angles | Circles
119. ANS: D
When two secants intersect in the exterior of a circle, then the measure of the angle formed is equal to
one-half the positive difference of the measures of the intercepted arcs.
Feedback
A What is the measure of the intercepted arc nearest the angle?
B Check your subtraction.
C Check your subtraction.
D Did you find the positive difference of the measures of the intercepted arcs?
PTS: 1 DIF: Average REF: Lesson 10-6
OBJ: 10-6.2 Find measures of angles formed by lines intersecting outside the circle.
NAT: NCTM GM.1 | NCTM GM.1b | NCTM ME.2 STA: 4.2.12 A.3
TOP: Find measures of angles formed by lines intersecting outside the circle.
KEY: Measure of Angles | Circles
ID: A
42
120. ANS: A
When two secants intersect in the exterior of a circle, then the measure of the angle formed is equal to
one-half the positive difference of the measures of the intercepted arcs.
Feedback
A Correct!
B What is the measure of the other intercepted arc?
C Check your subtraction.
D Did you find the positive difference of the measures of the intercepted arcs?
PTS: 1 DIF: Average REF: Lesson 10-6
OBJ: 10-6.2 Find measures of angles formed by lines intersecting outside the circle.
NAT: NCTM GM.1 | NCTM GM.1b | NCTM ME.2 STA: 4.2.12 A.3
TOP: Find measures of angles formed by lines intersecting outside the circle.
KEY: Measure of Angles | Circles
121. ANS: A
When two secants intersect in the exterior of a circle, then the measure of the angle formed is equal to
one-half the positive difference of the measures of the intercepted arcs.
Feedback
A Correct!
B Did you take one-half of the positive difference of the measures of the intercepted arcs?
C Check your subtraction.
D Did you subtract carefully?
PTS: 1 DIF: Average REF: Lesson 10-6
OBJ: 10-6.2 Find measures of angles formed by lines intersecting outside the circle.
NAT: NCTM GM.1 | NCTM GM.1b | NCTM ME.2 STA: 4.2.12 A.3
TOP: Find measures of angles formed by lines intersecting outside the circle.
KEY: Measure of Angles | Circles
122. ANS: D
When two secants intersect in the exterior of a circle, then the measure of the angle formed is equal to
one-half the positive difference of the measures of the intercepted arcs.
Feedback
A How are the angle and the intercepted arcs related?
B Check your subtraction.
C Did you subtract carefully?
D Correct!
PTS: 1 DIF: Average REF: Lesson 10-6
OBJ: 10-6.2 Find measures of angles formed by lines intersecting outside the circle.
NAT: NCTM GM.1 | NCTM GM.1b | NCTM ME.2 STA: 4.2.12 A.3
TOP: Find measures of angles formed by lines intersecting outside the circle.
KEY: Measure of Angles | Circles
ID: A
43
123. ANS: A
When a secant and tangent intersect in the exterior of a circle, then the measure of the angle formed is equal
to one-half the positive difference of the measures of the intercepted arcs.
Feedback
A Correct!
B Did you subtract carefully?
C What is the relationship between the angle and the intercepted arcs?
D Check your subtraction.
PTS: 1 DIF: Average REF: Lesson 10-6
OBJ: 10-6.2 Find measures of angles formed by lines intersecting outside the circle.
NAT: NCTM GM.1 | NCTM GM.1b | NCTM ME.2 STA: 4.2.12 A.3
TOP: Find measures of angles formed by lines intersecting outside the circle.
KEY: Measure of Angles | Circles
124. ANS: C
When a secant and tangent intersect in the exterior of a circle, then the measure of the angle formed is equal
to one-half the positive difference of the measures of the intercepted arcs.
Feedback
A What is the relationship between the angle and the intercepted arcs?
B Check your subtraction.
C Correct!
D Check your subtraction.
PTS: 1 DIF: Average REF: Lesson 10-6
OBJ: 10-6.2 Find measures of angles formed by lines intersecting outside the circle.
NAT: NCTM GM.1 | NCTM GM.1b | NCTM ME.2 STA: 4.2.12 A.3
TOP: Find measures of angles formed by lines intersecting outside the circle.
KEY: Measure of Angles | Circles
125. ANS: D
When a secant and tangent intersect in the exterior of a circle, then the measure of the angle formed is equal
to one-half the positive difference of the measures of the intercepted arcs.
Feedback
A Did you subtract carefully?
B Check your subtraction.
C Were you careful with subtraction?
D Correct!
PTS: 1 DIF: Average REF: Lesson 10-6
OBJ: 10-6.2 Find measures of angles formed by lines intersecting outside the circle.
NAT: NCTM GM.1 | NCTM GM.1b | NCTM ME.2 STA: 4.2.12 A.3
TOP: Find measures of angles formed by lines intersecting outside the circle.
KEY: Measure of Angles | Circles
ID: A
44
126. ANS: C
When a secant and tangent intersect in the exterior of a circle, then the measure of the angle formed is equal
to one-half the positive difference of the measures of the intercepted arcs.
Feedback
A Check your subtraction.
B Did you subtract carefully?
C Correct.
D Check your subtraction.
PTS: 1 DIF: Average REF: Lesson 10-6
OBJ: 10-6.2 Find measures of angles formed by lines intersecting outside the circle.
NAT: NCTM GM.1 | NCTM GM.1b | NCTM ME.2 STA: 4.2.12 A.3
TOP: Find measures of angles formed by lines intersecting outside the circle.
KEY: Measure of Angles | Circles
127. ANS: D
The products of the segments for each intersecting chord are equal.
Feedback
A Use multiplication, not addition.
B Multiply the segments and set them equal to each other.
C Multiply the segments and set them equal to each other.
D Correct!
PTS: 1 DIF: Basic REF: Lesson 10-7
OBJ: 10-7.1 Find measures of segments that intersect in the interior of a circle.
NAT: NCTM GM.1 | NCTM GM.1b | NCTM ME.2 STA: 4.2.12 A.3
TOP: Find measures of segments that intersect in the interior of a circle.
KEY: Circles | Interior of Circles
128. ANS: A
The products of the segments for each intersecting chord are equal.
Feedback
A Correct!
B Use multiplication, not addition.
C Multiply the segments and set them equal to each other.
D Multiply the segments and set them equal to each other.
PTS: 1 DIF: Basic REF: Lesson 10-7
OBJ: 10-7.1 Find measures of segments that intersect in the interior of a circle.
NAT: NCTM GM.1 | NCTM GM.1b | NCTM ME.2 STA: 4.2.12 A.3
TOP: Find measures of segments that intersect in the interior of a circle.
KEY: Circles | Interior of Circles
ID: A
45
129. ANS: C
The products of the segments for each intersecting chord are equal.
Feedback
A Use multiplication, not addition.
B Multiply the segments and set them equal to each other.
C Correct!
D Multiply the segments and set them equal to each other.
PTS: 1 DIF: Basic REF: Lesson 10-7
OBJ: 10-7.1 Find measures of segments that intersect in the interior of a circle.
NAT: NCTM GM.1 | NCTM GM.1b | NCTM ME.2 STA: 4.2.12 A.3
TOP: Find measures of segments that intersect in the interior of a circle.
KEY: Circles | Interior of Circles
130. ANS: B
The products of the segments for each intersecting chord are equal.
Feedback
A Use multiplication, not addition.
B Correct!
C Multiply the segments and set them equal to each other.
D Multiply the segments and set them equal to each other.
PTS: 1 DIF: Basic REF: Lesson 10-7
OBJ: 10-7.1 Find measures of segments that intersect in the interior of a circle.
NAT: NCTM GM.1 | NCTM GM.1b | NCTM ME.2 STA: 4.2.12 A.3
TOP: Find measures of segments that intersect in the interior of a circle.
KEY: Circles | Interior of Circles
131. ANS: C
The products of the segments for each intersecting chord are equal.
Feedback
A Use multiplication, not addition.
B Multiply the segments and set them equal to each other.
C Correct!
D Multiply the segments and set them equal to each other.
PTS: 1 DIF: Basic REF: Lesson 10-7
OBJ: 10-7.1 Find measures of segments that intersect in the interior of a circle.
NAT: NCTM GM.1 | NCTM GM.1b | NCTM ME.2 STA: 4.2.12 A.3
TOP: Find measures of segments that intersect in the interior of a circle.
KEY: Circles | Interior of Circles
ID: A
46
132. ANS: A
The products of the segments for each intersecting chord are equal.
Feedback
A Correct!
B Multiply the segments and set them equal to each other.
C Multiply the segments and set them equal to each other.
D Multiply the segments and set them equal to each other.
PTS: 1 DIF: Basic REF: Lesson 10-7
OBJ: 10-7.1 Find measures of segments that intersect in the interior of a circle.
NAT: NCTM GM.1 | NCTM GM.1b | NCTM ME.2 STA: 4.2.12 A.3
TOP: Find measures of segments that intersect in the interior of a circle.
KEY: Circles | Interior of Circles
133. ANS: B
The products of the segments for each intersecting chord are equal.
Feedback
A Multiply the segments and set them equal to each other.
B Correct!
C Multiply the segments and set them equal to each other.
D Multiply the segments and set them equal to each other.
PTS: 1 DIF: Basic REF: Lesson 10-7
OBJ: 10-7.1 Find measures of segments that intersect in the interior of a circle.
NAT: NCTM GM.1 | NCTM GM.1b | NCTM ME.2 STA: 4.2.12 A.3
TOP: Find measures of segments that intersect in the interior of a circle.
KEY: Circles | Interior of Circles
134. ANS: D
The products of the segments for each intersecting chord are equal.
Feedback
A Did you factor correctly?
B Multiply the segments and set them equal to each other.
C Use multiplication, not addition.
D Correct!
PTS: 1 DIF: Average REF: Lesson 10-7
OBJ: 10-7.1 Find measures of segments that intersect in the interior of a circle.
NAT: NCTM GM.1 | NCTM GM.1b | NCTM ME.2 STA: 4.2.12 A.3
TOP: Find measures of segments that intersect in the interior of a circle.
KEY: Circles | Interior of Circles
ID: A
47
135. ANS: A
The products of the segments for each intersecting chord are equal.
Feedback
A Correct!
B Use multiplication, not addition.
C Multiply the segments and set them equal to each other.
D Multiply the segments and set them equal to each other.
PTS: 1 DIF: Average REF: Lesson 10-7
OBJ: 10-7.1 Find measures of segments that intersect in the interior of a circle.
NAT: NCTM GM.1 | NCTM GM.1b | NCTM ME.2 STA: 4.2.12 A.3
TOP: Find measures of segments that intersect in the interior of a circle.
KEY: Circles | Interior of Circles
136. ANS: D
The products of the segments for each intersecting chord are equal.
Feedback
A Multiply the segments and set them equal to each other.
B Did you factor correctly?
C Use multiplication, not addition.
D Correct!
PTS: 1 DIF: Average REF: Lesson 10-7
OBJ: 10-7.1 Find measures of segments that intersect in the interior of a circle.
NAT: NCTM GM.1 | NCTM GM.1b | NCTM ME.2 STA: 4.2.12 A.3
TOP: Find measures of segments that intersect in the interior of a circle.
KEY: Circles | Interior of Circles
137. ANS: D
When a secant segment and a tangent segment intersect in the exterior of a circle, set the product of each
external part of the secant segment and the entire secant segment equal to the square of the tangent segment.
Feedback
A Check your multiplication.
B You need to multiply, not add.
C Check the segments in your multiplication.
D Correct!
PTS: 1 DIF: Average REF: Lesson 10-7
OBJ: 10-7.2 Find measures of segments that intersect in the exterior of a circle.
NAT: NCTM AL.2 | NCTM AL.2c | NCTM RE.2 STA: 4.2.12 A.3
TOP: Find measures of segments that intersect in the exterior of a circle.
KEY: Circles | Exterior of Circles
ID: A
48
138. ANS: A
When a secant segment and a tangent segment intersect in the exterior of a circle, set the product of each
external part of the secant segment and the entire secant segment equal to the square of the tangent segment.
Feedback
A Correct!
B Check the segments in your multiplication.
C You need to multiply, not add.
D Check your multiplication.
PTS: 1 DIF: Average REF: Lesson 10-7
OBJ: 10-7.2 Find measures of segments that intersect in the exterior of a circle.
NAT: NCTM AL.2 | NCTM AL.2c | NCTM RE.2 STA: 4.2.12 A.3
TOP: Find measures of segments that intersect in the exterior of a circle.
KEY: Circles | Exterior of Circles
139. ANS: B
When a secant segment and a tangent segment intersect in the exterior of a circle, set the product of each
external part of the secant segment and the entire secant segment equal to the square of the tangent segment.
Feedback
A Check the segments in your multiplication.
B Correct!
C You need to multiply, not add.
D Check your multiplication.
PTS: 1 DIF: Average REF: Lesson 10-7
OBJ: 10-7.2 Find measures of segments that intersect in the exterior of a circle.
NAT: NCTM AL.2 | NCTM AL.2c | NCTM RE.2 STA: 4.2.12 A.3
TOP: Find measures of segments that intersect in the exterior of a circle.
KEY: Circles | Exterior of Circles
140. ANS: A
When a secant segment and a tangent segment intersect in the exterior of a circle, set the product of each
external part of the secant segment and the entire secant segment equal to the square of the tangent segment.
Feedback
A Correct!
B Check the segments in your multiplication.
C You need to multiply, not add.
D Check your multiplication.
PTS: 1 DIF: Average REF: Lesson 10-7
OBJ: 10-7.2 Find measures of segments that intersect in the exterior of a circle.
NAT: NCTM AL.2 | NCTM AL.2c | NCTM RE.2 STA: 4.2.12 A.3
TOP: Find measures of segments that intersect in the exterior of a circle.
KEY: Circles | Exterior of Circles
ID: A
49
141. ANS: D
When a secant segment and a tangent segment intersect in the exterior of a circle, set the product of each
external part of the secant segment and the entire secant segment equal to the square of the tangent segment.
Feedback
A Check the segments in your multiplication.
B Check your multiplication.
C You need to multiply, not add.
D Correct!
PTS: 1 DIF: Average REF: Lesson 10-7
OBJ: 10-7.2 Find measures of segments that intersect in the exterior of a circle.
NAT: NCTM AL.2 | NCTM AL.2c | NCTM RE.2 STA: 4.2.12 A.3
TOP: Find measures of segments that intersect in the exterior of a circle.
KEY: Circles | Exterior of Circles
142. ANS: A
When two secant segments intersect in the exterior of a circle, set an equality between the product of each
external segment and the entire segment.
Feedback
A Correct!
B Check your multiplication.
C Check the segments in your multiplication.
D You need to multiply, not add.
PTS: 1 DIF: Average REF: Lesson 10-7
OBJ: 10-7.2 Find measures of segments that intersect in the exterior of a circle.
NAT: NCTM AL.2 | NCTM AL.2c | NCTM RE.2 STA: 4.2.12 A.3
TOP: Find measures of segments that intersect in the exterior of a circle.
KEY: Circles | Exterior of Circles
143. ANS: A
When two secant segments intersect in the exterior of a circle, set an equality between the product of each
external segment and the entire segment.
Feedback
A Correct!
B Check your multiplication.
C You need to multiply, not add.
D Check the segments in your multiplication.
PTS: 1 DIF: Average REF: Lesson 10-7
OBJ: 10-7.2 Find measures of segments that intersect in the exterior of a circle.
NAT: NCTM AL.2 | NCTM AL.2c | NCTM RE.2 STA: 4.2.12 A.3
TOP: Find measures of segments that intersect in the exterior of a circle.
KEY: Circles | Exterior of Circles
ID: A
50
144. ANS: C
When two secant segments intersect in the exterior of a circle, set an equality between the product of each
external segment and the entire segment.
Feedback
A Check your multiplication.
B Check the segments in your multiplication.
C Correct!
D Check your multiplication.
PTS: 1 DIF: Average REF: Lesson 10-7
OBJ: 10-7.2 Find measures of segments that intersect in the exterior of a circle.
NAT: NCTM AL.2 | NCTM AL.2c | NCTM RE.2 STA: 4.2.12 A.3
TOP: Find measures of segments that intersect in the exterior of a circle.
KEY: Circles | Exterior of Circles
145. ANS: D
When two secant segments intersect in the exterior of a circle, set an equality between the product of each
external segment and the entire segment. .
Feedback
A Check the segments in your multiplication.
B You need to multiply, not add.
C Check your multiplication.
D Correct!
PTS: 1 DIF: Average REF: Lesson 10-7
OBJ: 10-7.2 Find measures of segments that intersect in the exterior of a circle.
NAT: NCTM AL.2 | NCTM AL.2c | NCTM RE.2 STA: 4.2.12 A.3
TOP: Find measures of segments that intersect in the exterior of a circle.
KEY: Circles | Exterior of Circles
146. ANS: D
When two secant segments intersect in the exterior of a circle, set an equality between the product of each
external segment and the entire segment.
Feedback
A You need to multiply, not add.
B Check the segments in your multiplication.
C Check your multiplication.
D Correct!
PTS: 1 DIF: Average REF: Lesson 10-7
OBJ: 10-7.2 Find measures of segments that intersect in the exterior of a circle.
NAT: NCTM AL.2 | NCTM AL.2c | NCTM RE.2 STA: 4.2.12 A.3
TOP: Find measures of segments that intersect in the exterior of a circle.
KEY: Circles | Exterior of Circles
ID: A
51
147. ANS: A
The equation of a circle is (x − h)2
+ (y − k)2
= r2 where (h, k) is the center and r is the radius. In this
problem, the center is given, but not the radius. The radius is one-half the diameter, so first divide the given
diameter by 2 to get the radius.
Feedback
A Correct!
B You need to square the radius, not the diameter.
C You need the opposite signs on your center coordinates.
D You need the opposite signs on your center coordinates and you need to square the
radius, not the diameter.
PTS: 1 DIF: Average REF: Lesson 10-8
OBJ: 10-8.1 Write the equation of a circle. NAT: NCTM GM.2 | NCTM GM.2a
STA: 4.5.12 E.1 TOP: Write the equation of a circle. KEY: Circles | Equation of Circles
148. ANS: C
The equation of a circle is (x − h)2
+ (y − k)2
= r2 where (h, k) is the center and r is the radius. The center is
the midpoint of the endpoints of the diameter. Use the distance formula to find the diameter, which is the
distance between the endpoints. The radius is one-half the diameter, so the divide the diameter by 2 to get the
radius.
Feedback
A You need the opposite signs on your center coordinates and you need to square the
radius, not the diameter.
B You need the opposite signs on your center coordinates.
C Correct!
D You need to square the radius, not the diameter.
PTS: 1 DIF: Average REF: Lesson 10-8
OBJ: 10-8.1 Write the equation of a circle. NAT: NCTM GM.2 | NCTM GM.2a
STA: 4.5.12 E.1 TOP: Write the equation of a circle. KEY: Circles | Equation of Circles
149. ANS: A
The graph of an equation of the form x2
+ y2
= r2 will be a circle centered at (0, 0) and with radius r.
Feedback
A Correct!
B Check your radius.
C Check your radius.
D Check your radius.
PTS: 1 DIF: Basic REF: Lesson 10-8
OBJ: 10-8.2 Graph a circle on the coordinate plane.
NAT: NCTM PS.1 | NCTM PS.2 | NCTM PS.3 STA: 4.5.12 E.1
TOP: Graph a circle on the coordinate plane.
KEY: Circles | Graph Circles | Coordinate Plane
ID: A
52
150. ANS: D
The graph of an equation of the form (x − h)2
+ (y − k)2
= r2 will be a circle centered at (h,k) and with radius
r.
Feedback
A Check the signs of your center coordinates.
B Reverse your center coordinates.
C Check the signs of your center coordinates and reverse the x and y coordinates.
D Correct!
PTS: 1 DIF: Average REF: Lesson 10-8
OBJ: 10-8.2 Graph a circle on the coordinate plane.
NAT: NCTM PS.1 | NCTM PS.2 | NCTM PS.3 STA: 4.5.12 E.1
TOP: Graph a circle on the coordinate plane.
KEY: Circles | Graph Circles | Coordinate Plane
ID: A Accelerated Geometry/Algebra 2 Final Exam Review 2015 [Answer Strip]
_____ 1.D
_____ 2.A
_____ 3.B
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ID: A Accelerated Geometry/Algebra 2 Final Exam Review 2015 [Answer Strip]
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ID: A Accelerated Geometry/Algebra 2 Final Exam Review 2015 [Answer Strip]
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ID: A Accelerated Geometry/Algebra 2 Final Exam Review 2015 [Answer Strip]
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ID: A Accelerated Geometry/Algebra 2 Final Exam Review 2015 [Answer Strip]
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ID: A Accelerated Geometry/Algebra 2 Final Exam Review 2015 [Answer Strip]
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_____103.C
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ID: A Accelerated Geometry/Algebra 2 Final Exam Review 2015 [Answer Strip]
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ID: A Accelerated Geometry/Algebra 2 Final Exam Review 2015 [Answer Strip]
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ID: A Accelerated Geometry/Algebra 2 Final Exam Review 2015 [Answer Strip]
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ID: A Accelerated Geometry/Algebra 2 Final Exam Review 2015 [Answer Strip]
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