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1 5. phase diagrams phase – a region in a material that differs in structure and function from other regions phase diagrams – graphical representations of what phases are present in a materials system at different conditions (temperature, pressure and composition) (1) phase diagrams of pure substances pure substance exist as solid, liquid and vapor phases depending on the conditions of temperature and pressure pressure-temperature (PT) phase diagram • water two-phase equilibrium line triple point 4.579 torr

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Page 1: 98materials Phase Diagrams

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5. phase diagramsphase – a region in a material that differs in

structure and function from other regionsphase diagrams – graphical representations of

what phases are present in a materials system at different conditions (temperature, pressure and composition)

(1) phase diagrams of pure substancespure substance exist as solid, liquid and vapor phases depending on the conditions of temperature and pressurepressure-temperature (PT) phase diagram• watertwo-phase equilibrium line triple point

4.579 torr

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• ironthree distinct solid phases: α Fe, γ Fe, δ Fethree triple points

(2) Gibbs phase ruleP + F = C + 2

P: number of phases that coexist in a systemC: number of componentsF: degrees of freedom

ex. water triple point 3 + F = 1 + 2 F = 0L-S freezing curve 2 + F = 1 + 2 F = 1

degrees of freedom indicate number of variables that can be changed without changing number of phases

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(3) cooling curvesused to determine phase transition temperaturetemperature vs. time data of cooling molten material is recorded and plotted

BC – plateaue or region of thermal arrest

• cooling curve for pure Fe

undercooling

freezing

polymorphictransformation

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(4) binary isomorphous alloy systemsbinary alloy – a mixture of two metals isomorphous system – two elements completely soluble in each other in liquid and solid stateusually satisfy one or more Hume-Rothery solid solubility rules

• copper-nickel system

liquidussoliduscomposition of liquid + solid phases at any temperature can be determined by drawing a tie lineex. at 1300oC an alloy of 53% Ni + 47% Cu

in liquid + solid phasecomposition of liquid phase: 45% Nicomposition of solid phase: 58% Ni

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binary equilibrium phase diagramcooling curves equilibrium phase diagram

points of change of slope of cooling curves (thermal arrests) are notedfor metal alloys, solidification begins at a specific temperature (L) and ends at a lower temperature (S)the freezing temperature of a metal alloy is the temperature at which the solidification process is complete

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(5) lever rulethe lever rule gives the weight % of phases in any two phase regions

Xs + Xl = 1 Xs = 1 - Xlconsider 1 g of alloy, weight balance of B:(1 g)(%w0) = (1g)(Xl)(%wl) + (1g)(Xs)(%ws) w0 = Xlwl + Xsws w0 = Xlwl + (1 - Xl)wsw0 = (1 - Xs)wl + Xswsw0 = wl - Xswl + Xsws

w0 – w1Wt fraction of solid phase = Xs = ————ws – w1

w0 = Xlwl + ws - Xlwsws – w0Wt fraction of liquid phase = Xl = ————ws – w1

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the weight fraction of liquid phase is the ratio of OS/LSthe weight fraction of solid phase is the ratio of LO/LSex. Cu-Ni alloy contains 47 wt% Cu and 53

wt% Ni at 1300oCa. what is the wt% of Cu in liquid and in

solid phases?b. what wt% of this alloy is liquid?

a. from the phase diagram,wt% of Ni in liquid is 45% and in solid is 58%wt% of Cu in liquid is 55% and in solid is 42%

b. ws – w0 58 - 53Xl = ———— = ———— = 5/13 = 0.38 38%

ws – w1 58 - 45

w0 – wl 53 - 45Xs = ———— = ———— = 8/13 = 0.62 62%

ws – w1 58 - 45

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ex. calculate the wt% liquid and solid for Ag-Pd phase diagram shown below at 1200oC and 70 wt% Ag.

ws – w0 64 - 70Xl = ———— = ———— = 6/10 = 0.6 60%

ws – w1 64 - 74

w0 – wl 70 - 74Xs = ———— = ———— = 4/10 = 0.4 40%

ws – w1 64 - 74

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(6) nonequilibrium solidification of alloysslowly solidified alloys usuallyhave a cored structure

70% Cu-30% Ni alloy

rapid cooling (nonequilibrium) delays solidification

homogenization: as-cast ingots are heated to elevated temperature to accelerate solid-state diffusion and to eliminate the cored structuretemperature of homogenization must be lower than lowest melting point of any of the alloy components

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(7) binary eutectic alloy systemsin some binary alloy systems, components have limited solid solubility – eutectic systemex. Pb-Sn system

• terminal solid solutions with restricted solid solubility α (Pb-rich) and β (Sn-rich) phases

• eutectic composition freezes at lower temperature than all other compositions, this lowest temperature is called eutectic temperature

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eutectic reactioneutectic temperature

liquid α solid solution + β solid solutioncooling

eutectic reaction is an invariant reaction –degree of freedom F = 0• slow cooling of a Pb-Sn alloy of eutectic composition

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• slow cooling of 60% Pb – 40% Sn alloy

a. liquid at 300oC b. at about 245oC first solid solution α (12%

Sn) forms – primary or proeutectic αc. slightly above 183oC composition of alpha

follows solidus and composition of Snvaries from 12% to 19.2%, composition of liquid phase varies from 40% to 61.9%

d. at eutectic temperature, all the remaining liquid solidifies

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ex. make phase analysis at the following points in Pb-Sn phase diagram:

(a) at eutectic composition just below 183oC(b) point c at 40% Sn and 230oC(c) point d at 40% Sn and 183oC + ΔT(d) point e at 40% Sn and 183oC - ΔT

(a) α phase (19.2% Sn) + β phase (97.5% Sn)97.5 – 61.9 61.9 – 19.2

wt% (α) = ————— wt% (β) = —————97.5 – 19.2 97.5 – 19.2

= 45.5% = 54.5%

(b) α phase (15% Sn) + liquid (48% Sn)48 – 40 40 – 15

wt% (α) = ———— wt% (L) = ————48 – 15 48 – 15

= 24% = 76%

(c) α phase (19.2% Sn) + liquid (61.9% Sn)61.9 – 40 40 – 19.2

wt% (α) = ————— wt% (L) = —————61.9 – 19.2 61.9 – 19.2

= 51% = 49%

(d) α phase (19.2% Sn) + β phase (97.5% Sn)97.5 – 40 40 – 19.2

wt% (α) = ————— wt% (β) = —————97.5 – 19.2 97.5 – 19.2

= 73% = 27%

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ex. an alloy of 70% Pb + 30% Sn is slowly cooled from 300oC, calculate the following:

(a) wt% of the liquid and proeutectic α form at 250oC

(b) wt% of the liquid + proeutectic α formjust above eutectic temperature (183oC)

(c) wt% of the α and β phases formed by the eutectic reaction

(a) α phase (12% Sn) + liquid(40% Sn)40 – 30 30 – 12

wt% (α) = ———— wt% (L) = ————40 – 12 40 – 12

= 36% = 64%

(b) α phase (19.2% Sn) + liquid (61.9% Sn)61.9 – 30 30 – 19.2

wt% (α) = ————— wt% (L) = —————61.9 – 19.2 61.9 – 19.2

= 74.7% = 25.3%(c) α phase (19.2% Sn) + β phase (97.5% Sn)

97.5 – 30 30 – 19.2wt% (α) = ————— wt% (β) = —————

97.5 – 19.2 97.5 – 19.2 = 86.2% = 13.8%

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ex. a Pb-Sn alloy contains 64 wt% proeutecticα and 36 wt% eutectic α + β at 183oC - ΔTcalculate the average composition of this alloy

assume x wt% Sn in this alloysince 64 wt% proeutectic α exists, the alloymust be hypoeutectic and 19.2 < x < 61.9

61.9 – xwt% = ————— = 64%

61.9 – 19.2x = 34.6

this alloy consists of 34.6 wt% Sn and 65.4 wt% Pb

• in a binary eutectic reaction two solid phases (α and β) can have various morphologies

• structure depends on factors like minimization of free energy at α /β interface

• manner in which two phases nucleate and grow also affects structures

ex. lamellar eutectic structure of Pb-Sn alloy

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(8) binary peritectic alloy systemperitectic reaction – liquid phase reacts with a solid phase to form a new and different solid phase

liquid + α βcooling

peritectic reaction occurs when a slowly cooled alloy

ex. Fe-Ni phase diagram

δ phase – Ni in BCC-Fe γ phase – Ni in FCC-FeFe-4.3 wt% Ni passes through peritectictemperature of 1517oC

1517oCliquid (5.4 wt% Ni) + δ (4.0 wt% Ni) γ (4.3 wt% Ni)

cooling

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ex. Pt-Ag phase diagram

the peritectic reaction occurs at 42.4 wt% Ag and 1186oCex. make phase analysis at the following:a. at 42.4% Ag and 14000Cb. at 42.4% Ag and 11860C + ΔTc. at 42.4% Ag and 11860C −ΔTd. at 60% Ag and 1150oCa. phases present liquid α

composition 55% Ag 7%Agamount of phases 42.4 –7 55-42.4

──── ────55 – 7 55 - 7

= 74% = 26%

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b. phases present liquid αcomposition 66.3% Ag 10.5%Agamount of phases 42.4 – 10.5 66.3 – 42.4

───── ─────66.3 – 10.5 66.3 – 10.5 = 57% =43%

c. phase present β onlycomposition 42.4% Agamount of phase 100%

d. phases present liquid βcomposition 77% Ag 48%Agamount of phases 60 – 48 77-60

─── ─────77 - 48 77 – 48 = 41% = 59%

very slow cooling of an alloy of peritecticcomposition through the peritectic temperature

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surrounding or encasement – during rapid solidification of alloy through peritecticreaction, the β phase created surrounds primary αβ creates diffusion barrier resulting in coring

cast 60% Ag-40% Pt hyperperitctic alloy

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(9) binary monotectic systemsmonotectic reaction – liquid phase transforms into solid phase and another liquid

coolingL1 α + L2

two liquids are immiscibleex. Cu-Pb system at 955oC and 36% Pb

Cu-rich portion

Pb-rich portion20

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(10) invariant reactionszero degree of freedom at the reaction points

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(11) phase diagrams with intermediate phases and compounds

terminal phases – phases occur at the end of phase diagramsintermediate phases – phases occur in a composition range inside phase diagram.ex. Cu-Zn diagram has both terminal and

intermediate phases.

• α and η –terminal phases

• β, γ, δ, ε –intermediate phases

• five invariant peritectic points +one eutectic point

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ex. Al2O2 – SiO2 system

an intermediate phase called mullite is formed, which includes the compound 3Al2O3.2SiO2

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in some phase diagrams, intermediate compound are formed – stoichiometricpercent ionic/covalent bond depends on electronegativenessex. Mg-Ni phase diagram contains two

intermetallic compounds:MgNi2 - congruently melting compoundMg2Ni - incongruently melting compound

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(12) ternary phase diagramsthree components phase diagrams constructed by using a equilateral triangle as base• pure components at each end of triangle binary

alloy composition represented on edges• temperature can be represented as uniform

throughout the whole diagram – isothermal section

to determine the composition of a ternary alloy: • draw a perpendicular line from a pure metal

corner to the side of the triangle opposite that corner

• measure the distance from the side to the corner along the perpendicular line

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ex. determine the wt% of metals A, B, C for ternary alloy at points x and yon thefollowing phase diagram

draw three perpendicular lines AD, BE, CFfor point x(i) on AD line 40% A(ii) on BE line 40% B(iii) on CF line 20% C for point y(i) on AD line 20% A(ii) on BE line 30% B(iii) on CF line 50% C

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ex. Fe-Cr-Ni phase diagrams.

• isothermal reaction at 650oC for this system• the most important stainless steel has a

composition essentially of 74% Fe, 18% Cr, and 8% Ni

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