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The Gatsby Charitable Foundation 1
MEP: Demonstration Project Teacher Support Y9B, P17
Practice Book UNIT 17 Quadratic Functions
17.1 Quadratic Expressions1. (a), (b), (c) graphs
(d) y x y x= = +2 2 3
translation 03
y x y x= = 2 2 2
translation 02
2.
y
x
9
8
7
6
5
4
3
2
1
3 2 1 0 1 2 3
1
2
y = x 2 + 3
y = x 2
y = x 2 2
y
x
9
8
7
6
5
4
3
2
1
3 2 1 0 1 2 3
1
2
3
4
5
6
7
8
9
10
y = 9 x 2
y = 4 x 2
y = 1 x 2
y = x 2
y = 1 x 2
Answers
The Gatsby Charitable Foundation 2
MEP: Demonstration Project Teacher Support Y9B, P17
3.
4.
5. (a)(b) ( 2, 8), (2, 8)
17.1
y
x
10
8
6
4
2
3 2 1 0 1 2 3
1
y = 3 x 2y = 4 x2
y = 34
x2
y = x2
y
x
1
3 2 1 0 1 2 3
1
2
3
4
5
6
7
8
9
y = 14
x2
y = 12
x2
y = 34
x2
y = x 2 y
x
10
8
6
4
2
3 2 1 0 1 2 3
1
y = 2 x 2
y = x2 + 4
Answers
The Gatsby Charitable Foundation 3
MEP: Demonstration Project Teacher Support Y9B, P17
6. (a)
(b) y x y x= = +( )2 21 translation
10
y x y x= = +( )2 23 translation
30
y x y x= = ( )2 22 translation 20
(c)
7. (a) (b)
(c) (d)
17.1
y
x
10
8
6
4
2
3 2 1 0 1 2 34 45
y = x + 3( ) 2
y = x + 1( ) 2
y = x 2( ) 2
y
x
3
2
1
3 2 1 0 1
y = x + 1( ) 2 + 1
x
y
1 2 3 4
1
2
3
4
0
y = x 3( ) 2 + 2
x0 1
y
3
2
1
2 3y = x 2( ) 2 3
x
y
0
3
2
1
12345
y = x + 4( ) 2 3
y
x
6
4
2
3 2 1 0 1 2 34 456 5 6 7
y = x + 4( ) 2 y = x 3( ) 2 y = x 5( ) 2
Answers
The Gatsby Charitable Foundation 4
MEP: Demonstration Project Teacher Support Y9B, P17
17.1
3
y
x012 1
y = x 2 + 2 x
3
y
0124567
y = x 2 + 6 x
9
8. (a), (b)
Lowest point 12
14
, Lowest point ( , )1 1
Lowest point ( 2, 4)
Lowest point of y x b x= +2 is
b b2 4
2
, .
Lowest point ( 3, 9)
(c)
(d) b b2 4
2
,
x012 1
y = x 2 + x
0 x
y
1 2y = x 2 4 x
3 40 x
y
1 2
y = x 2 x
x
y
0 1 2 3 4 5 6 7
y = x 2 6 x
x3
y
x012 145
y = x 2 + 4 x
Answers
The Gatsby Charitable Foundation 5
MEP: Demonstration Project Teacher Support Y9B, P17
17.1
9. (a)
(b) (0, 1) (0, 2)(c) (0, c)(d) ( 1, 1) ( 1, 1)(e) ( 1, c a )
10. (a)
(b)
ba
ac ba2
44
2
,
11. (a) c is the y-intercept (or value of y when x = 0 ) and graph shows y = 10 when x = 0
(b) a = 130
; b = 2
y
x
2
1
3 2 1 0 1
1y = 2 x 2 + 4 x + 1
y
x
2
1
3 2 1 0 1
1
3
y = 3 x 2 + 6 x + 2
x
y
12345
y = 2 x 2 + 8 x 1
0
6
4
2
8
10
x
y
1 2 3 4
2
4
6
8
0
y = 3 x 2 9 x + 7
x
y
0
3
2
1
12345
4
5y = x2 + 5 x + 1
Answers
The Gatsby Charitable Foundation 6
MEP: Demonstration Project Teacher Support Y9B, P17
17.2
17.2 Quadratic Equations: Factorisation1. (a) 3 7x +( ) (b) 5 4x ( ) (c) x x ( )1
(d) x x +( )6 (e) x x2 1( ) (f) 4 2 5x x+( )(g) 2 2 15x x( ) (h) x x5 16+( ) (i) x x2 2 1+( )
2. (a) x x+( ) +( )1 3 (b) x x( ) ( )1 2 (c) x x( ) +( )7 2(d) x x( ) ( )20 1 (e) x x+( ) +( )5 7 (f) x ( )5 2(g) x x( ) ( )5 6 (h) x x( ) +( )9 7 (i) x x( ) ( )6 8
3. (a) 0, 4 (b) 0, 3 (c) 0, 7
(d) 0, 14
(e) 0, 73
(f) 0, 52
4. (a) 2, 6 (b) 4, 2 (c) 3, 2(d) 4, 1 (e) 3, 5 (f) 2, 9(g) 3, 9 (h) 3, 7 (i) 1, 17(j) 5, 12
5. (a) 0, 8 (b) 0, 43
(c) 5, 10(d) 7, 10 (e) 8, 7 (f) 3, 17
6. (a)
(b) Graph crosses x-axis at two points, which are the x-values that give y = 0 .
y
x
3
2
1
3 2 1 0 14 2
4
1
2
3
4
3
y = x 2 + 2 x 3
Answers
The Gatsby Charitable Foundation 7
MEP: Demonstration Project Teacher Support Y9B, P17
17.2
7. (a) (b) One
(c) x +( ) =1 02so x +( ) =1 0 x = 1
8.
Graph does not cross x-axis, so there are no x-values forwhich y = 0 .
9. (c) w = 2 5 or (d) cannot have width = 5 (e) 2 cm by 5 cm
10. 4 cm 3
11. y y= =5 or 1
17.3 Quadratic Equations: Completing the Square1. (a) x +( ) 3 92 (b) x +( ) 2 42 (c) x +( ) 4 162
(d) x ( ) 5 252 (e) x +( ) 3 5 12 252. . (f) x ( ) 2 5 6 252. .2. (a) x +( ) 3 82 (b) x ( ) 4 132 (c) x +( ) 5 372
(d) x +( ) 6 282 (e) x ( ) 2 32 (f) x ( ) 3 122(g) x +( ) 2 5 3 252. . (h) x +( ) 1 5 6 252. .(i) x +( ) 0 5 2 252. . (j) x ( ) +0 5 2 752. .
3. (a) 4, 2 (b) 3, 1 (c) 6, 2(d) 1, 4 (e) 3, 5 (f) 7, 4
4. (a) 3.45, 1.45 (b) 4.24, 0.24(c) 6.74, 0.74 (d) 0.10, 10.10(e) 2.30, 1.30 (f) 0.38, 2.62(g) 5.70, 0.70 (h) 4.19, 1.19
5. (a) x x +( ) =4 20 (b) 2.9 cm6. (a) x ( ) + =4 2 02 (b) x ( )4 2 cannot be negative
y
x012 1
1
2
y = x 2 + 2 x + 1
y
x012 1
1
2
y = x 2 + 2 x + 2
Answers
The Gatsby Charitable Foundation 8
MEP: Demonstration Project Teacher Support Y9B, P17
17.3
7. (a) x x2 5 2 0+ = ; 5.37, 0.37(b) x x2 2 3 0 + = ; no solutions(c) x x2 2 3 0+ = ; 3, 1(d) x x2 6 3 0 = ; 0.46, 6.46
8. (a) 20 (b) t t= =1 3 or 9. 310. 53.0 cm11. 4.44948974, 0.44948974