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Chemguide – questions HESS'S LAW AND SIMPLE ENTHALPY CALCULATIONS 1. State Hess's Law. 2. The standard enthalpy of formation of pentane relates to the equation: The standard enthalpy changes of combustion for the three substances in the equation are: C (s) -394 kJ mol -1 H 2(g) -286 kJ mol -1 C 5 H 12(l) -3509 kJ mol -1 Calculate the standard enthalpy of formation of pentane. 3. Use the values for standard enthalpy of formation to calculate the standard enthalpy change for the reaction: ΔH f (NH 3(g) ) = -46.1 kJ mol -1 ΔH f (HCl (g) ) = -92.3 kJ mol -1 ΔH f (NH 4 Cl (s) ) = -314.4 kJ mol -1 www.chemguide.co.uk 5C (s) + 6H 2(g) C 5 H 12(l) NH 4 Cl (s) NH 3(g) + HCl (g)

57135408 Chemistry 5070 Complete Notes for O Level

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  • C h e m g u i d e q u e s t i o n s

    HESS'S LAW AND SIMPLE ENTHALPY CALCULATIONS

    1. State Hess's Law.

    2. The standard enthalpy of formation of pentane relates to the equation:

    The standard enthalpy changes of combustion for the three substances in the equation are:

    C(s) -394 kJ mol-1H2(g) -286 kJ mol-1C5H12(l) -3509 kJ mol-1

    Calculate the standard enthalpy of formation of pentane.

    3. Use the values for standard enthalpy of formation to calculate the standard enthalpy change for the reaction:

    Hf(NH3(g)) = -46.1 kJ mol-1Hf(HCl(g)) = -92.3 kJ mol-1Hf(NH4Cl(s)) = -314.4 kJ mol-1

    www.chemguide.co.uk

    5C(s) + 6H2(g) C5H12(l)

    NH4Cl(s)NH3(g) + HCl(g)