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4x4 4 X 421 X 3 12 1 1 21 01 31 1 3 X 2 t 3 2 1 1 Xzi 0 X i t 2 0t 23 t l 5 X 1 2 210 1 infighting 3d Ythilhxixil x.tn i3x nosohinJ5b 5Y 2XztXi3a.x 2Xz 5 2X it xz 4xiOZGx.tn 2 i Xi 3 lt h 1 X 2 2 0

4 X 3 ㄨ了 21 3 2 Xzi 0 2 0 t 23 t 1 2 i 210 infighting

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Page 1: 4 X 3 ㄨ了 21 3 2 Xzi 0 2 0 t 23 t 1 2 i 210 infighting

⼉4x4 4 X421X 3 12 1 1 ㄨ了 ⼆了 21 01 31 1

3 X 2 t 3 2 1 1 Xzi 0

X i t 2 0 t 23 t l 5 X1 2

210 了 1

卡 infighting3d Ythilhxixil

x.tni3xnosohinJ5b

5Y2XztXi3a.x2Xz 5 2X it 了 xz4xiOZGx.tn2

i灬Xi

3 lt h 1X 2 2

0

Page 2: 4 X 3 ㄨ了 21 3 2 Xzi 0 2 0 t 23 t 1 2 i 210 infighting

Eli Xz.tl lX46Ezi3Yt3Xs4x476hDEsiXitXztX3t2X46E4iLxH3XztX3t3X4

6y 您壵ht X ⺾ 4⼆ 0 ly 3 3 1044 11xz fftbxiXFZXz.tntx 4⼆0 X F 4

n 1 0

T 1

41 了 11 2

Page 3: 4 X 3 ㄨ了 21 3 2 Xzi 0 2 0 t 23 t 1 2 i 210 infighting

Ill Geometrical interpretation A plane in 3DEuchdimsp.ua

A 了ㄨ了 how system has a solution

off tho thoupluushowulrregtgmangpontoinan.nu to

all of thorn

For honor section

9 bz b ⼆ n_n xia

xibmmbiimbzmimztxzxib.tn 器

Page 4: 4 X 3 ㄨ了 21 3 2 Xzi 0 2 0 t 23 t 1 2 i 210 infighting

oh

ifmimzbzb.IO

bible

as any two limo with dogon shop

have a common point and the pairOf solution represent the

coordinate

of that pointb For two line that has same Shp

theyneed to be the Same liu to

have common point

Page 5: 4 X 3 ㄨ了 21 3 2 Xzi 0 2 0 t 23 t 1 2 i 210 infighting

10 X ⼆0 亿⼆ 0 will satisfy the

equation Thus Sohn Sot is not

empty and thenforce constant

12RE Fia C dig hRRE Fi Gdig2的

is inconsistent

2b x t了y 1 x 4y ⼆⼗

count

Page 6: 4 X 3 ㄨ了 21 3 2 Xzi 0 2 0 t 23 t 1 2 i 210 infighting

2 C xzyt 4221z 3

x 2 y 11

solution 以 y 了

3 a 红 513

3 b Inconsistent misolution

34 Xlt 542 2ㄨ了 ⼆了

ㄨ i 3 12 X 55 X z

3 5⼈ 2 P ⼈ B 6

Page 7: 4 X 3 ㄨ了 21 3 2 Xzi 0 2 0 t 23 t 1 2 i 210 infighting

44 Lead Vari X xyFrau Vari X_X了

作㴺t

iii

t

iii

Page 8: 4 X 3 ㄨ了 21 3 2 Xzi 0 2 0 t 23 t 1 2 i 210 infighting

X了 ⼆ ⼈

xziygt 718 ⼈

X 1 44 114 ⼈

㓹514114.7118 118 ⼈

For honor Scion

I If too plane are part6⽐ they will

have o or ifinning many pointin annan

Lido aid places

If two plan are angled toward ah

other then they intone in a straightline with intoning many pro nut

Thus the sohu.im sat will be

ooriufinitymanyf

Page 9: 4 X 3 ㄨ了 21 3 2 Xzi 0 2 0 t 23 t 1 2 i 210 infighting

10

a

㶁 问

iii

iii

If at 5 and b is arbitrary thou

thou is a unique solution

x ⼀些a 5

Page 10: 4 X 3 ㄨ了 21 3 2 Xzi 0 2 0 t 23 t 1 2 i 210 infighting

If a ⼆ 5

Caso Ii

If b 4 thoua 5 X了⼆0 54

for any Xs there will be

infinitely many solution

Casa Ii

If 呌 4 the equation is

inconsistent

Infinity solution IH ait be 4

inconsistent it at 5 and ⾇4