3.6.1 Fertilizer Materials

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    Fertilizer Materialsand Calculation

    Nutrient Management

    Part 1: Understanding the PalayCheck Sy

    stem

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    Fertilizerany substance which is added to the soil

    or applied to the plant to supply the elements

    essential for plant nutrition

    Fertilizer gradethe guaranteed percentage of total

    nitrogen (N), available phosphorus (P2O5), and water

    soluble potassium (K2O), in that order, in a fertilizer

    material

    FERTILIZER TERMINOLOGIES

    16% N

    20% P2O5

    0% K2O16-20-0

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    Total plant foodthe total percentage of nutrients

    (usually of N,P,K and S) in a fertilizer material

    17-0-17-12 = 46% total plant food14-14-14-12 = 54% total plant food

    Carriera material that is necessary to hold the

    fertilizer element in a form suitable for use

    100%46% total plant food = 54% carrier

    FERTILIZER TERMINOLOGIES

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    Fillera material used to provide the fertilizer with the

    desired amount of nutrient per unit of weight, to make

    application easier, or to reduce the absorption of water

    from the air

    Fertilizer recommendationthe amount (kg) of N,P2O5,

    and K2O recommended per hectare

    90+30+60 = 90 kg N, 30 kg P2O5, and 60 kg K2O per

    hectare application

    FERTILIZER TERMINOLOGIES

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    Classification of Fertilizer Materials

    According to form

    Natural organic

    Chemical or inorganic

    Natural chemical

    Synthetic chemical

    According to fertilizerelements present

    Single

    Incomplete

    Complete

    Mixed

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    1. Natural organicany fertilizer of plant and/or animalorigin that has undergonedecomposition.

    Examples:Commercial organic fertilizer (OF),

    compost, chicken manure

    Organic

    Matter (%) C:N Ratio

    Moisture

    Content (%)

    N+P2O5+K2

    O (%)

    Pure Organic 20 12:1 35 7

    Fortified

    Organic 20 12:1 35 > 7

    According to form

    Commercial OF may either be pure organic or fortified organic:

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    2. Chemical or inorganicany fertilizer material which isnatural or synthetic product of chemical reaction of

    certain raw materials.

    Natural chemicalrock phosphate, Chilean nitrate

    of soda, most potassium materials

    Synthetic chemicalammonium sulfate, ordinary

    superphosphate, ammonium phosphate, complete

    fertilizer; Urea is synthetic but in organic form.

    According to form

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    1. Single fertilizerscontain only one of the 3 majorfertilizer elements (N,P, and K)

    Examples:Urea, Ammonium sulfate, ordinary

    superphosphate, muriate of potash, sulfate of potash

    2. Incomplete fertilizerscontain 2 of the 3 major

    fertilizer elements

    Examples:ammonium phosphate, 17-0-17, potassium

    nitrate, potassium phosphate, urea superphosphate

    (20-10-0)

    According to number of fertilizer elements present

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    3. Complete fertilizerscontain all the 3 major fertilizerelements

    Examples:14-14-14; 17-7-17; 10-15-15; 12-12-12

    4. Mixed fertilizerscontain 2 or more of the major

    fertilizer elements that are supplied by 2 or more

    fertilizer materials

    Examples:ammonium phosphate + muriate of potash;

    urea superphosphate (20-10-0)

    According to number of fertilizer elements present

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    Why study fertilizer grades

    and fertilizer computation?

    Consider this:

    If Shane needs a teaspoon of sugar to sweeten her

    juice but there is no sugar available, can she use honey

    instead?

    If Aling Mena does not have enough soy sauce for the

    adobe shes cooking, can she add salt? How much?

    If Mang Ado needs to apply fertilizer at a recommended

    rate of 90+30+60 but no complete fertilizer is available,

    what other fertilizers and how much of it should he use

    to meet the recommendation?

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    50 kg

    Complete fertilizer

    14% nitrogen

    14% phosphorus

    14% potassium

    50 kg sack:

    7 kg nitrogen

    7 kg phosphorus

    7 kg potassium

    Common fertilizer grades in the market

    50 kg

    Ammonium phosphate

    16% nitrogen

    20% phosphorus

    0% potassium

    50 kg sack:

    8kg nitrogen

    10kg phosphorus

    0kg potassium

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    50 kg

    Urea

    46% nitrogen0% phosphorus

    0% potassium

    50 kg sack:

    23 kg nitrogen0 kg phosphorus

    0 kg potassium

    Other common fertilizers:

    Ammonium sulfate (21-0-0)

    Solophos (0-18-0)

    Muriate of potash (0-0-60)Urea superphosphate (21-10-0)

    46% x 50 kg

    100

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    Fertilizer Calculation

    Amount of Fertilizer

    Material (kg)

    Recommended Rate (kg nutrient/ha) x Area (ha)=

    Percent Nutrient in Fertilizer Material

    If Mang Ado needs to apply fertilizerat a recommended rate of

    90+30+60 but no complete fertilizer

    is available, what other fertilizers

    and how much of it should he use tomeet the recommendation?

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    Use a combination of

    incomplete and single

    fertilizer materials

    Use a combination of 3

    single fertilizers

    Use a combination of

    complete and single

    fertilizer materialsOPTIONS

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    Option 1. To calculate the amount of fertilizer

    materials for 1 ha at the recommended

    rate of 90 + 30 + 60 using acombination of single fertilizers:

    21-0-0 (ammonium sulfate)

    0-18-0 (ordinary superphosphate) 0-0-60 (muriate of potash or potassium chloride)

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    Therefore, Mang Ado must apply 428.6 kg 21-

    0-0, 166.7 kg 0-18-0, and 100.0 kg 0-0-60 to

    satisfy the recommended rate of 90 + 30 + 60.

    Amount of 21-0-0 (kg) 90 kg N/ha x 1 ha

    0.21= = 428.6

    Amount of 0-18-0 (kg) 30 kg P2O5/ha x 1 ha

    0.18= = 166.7

    Amount of 0-0-60 (kg)

    60 kg K2O/ha x 1 ha

    0.60= = 100.0

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    16-20-0 (ammonium phosphate 46-0-0 (urea)

    0-0-60 (muriate of potash)

    Option 2. To calculate the amount of fertilizer

    materials for 1 ha at the recommended

    rate of 90 + 30 + 60 using a

    combination of incomplete and single

    fertilizers:

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    Amount of 16-20-0 (kg) 30 kg P2O5/ha x 1 ha

    0.20= = 150.0

    Amount of 46-0-0 (kg) 90 kg Nkg N from 150 kg 16-20-0/ha x 1 ha0.46

    =

    90(150 x 0.16)

    0.46= 9024

    0.46= 66

    0.46=

    = 143.5

    Amount of 0-0-60 (kg)60 kg K2O/ha x 1 ha

    0.60= = 100.0

    Therefore, he must apply 150.0 kg 16-20-0, 143.5

    kg 46-0-0, and 100.0 kg 0-0-60 to satisfy the

    recommended rate of 90 + 30 + 60

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    Amount of 14-14-14 (kg)30 kg P2O5/ha x 1 ha

    0.14= = 214.3

    Therefore, he must apply 214.3 kg 14-14-14,

    130.4 kg 46-0-0, and 50.0 kg 0-0-60 to satisfy the

    recommended rate of 90 + 30 + 60

    Amount of 46-0-0 (kg) 90 kg N

    kg N from 214.3 kg 14-14-14/ha x 1 ha0.46

    =

    90(214.3 x 0.14)

    0.46= 9030

    0.46= 60

    0.46= 130.4=

    Amount of 0-0-60 (kg) 60 kg K2Okg K2O from 214.3 kg 14-14-14/ha x 1 ha

    0.60=

    60(214.3 x 0.14)

    0.60

    =6030

    0.60

    =30

    0.60

    = 50.0=

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    Determine the least

    expensive fertilizer

    combination that can

    satisfy the recommended

    rate (90 + 30 + 60).

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    21-0-0428.6 kg

    50 kg/bag= = P 4,714.60x P 550/bag

    0-18-0166.7 kg

    50 kg/bag= = P 1,833.70x P 550/bag

    0-0-60

    100.0 kg

    50 kg/bag= = P 1,650.00x P 825/bag

    TOTAL COST = P 8,198.30

    Cost of option 1. combination of single fertilizers:

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    16-20-0150.0 kg

    50 kg/bag= = P 2,460.00x P 820/bag

    46-0-0143.5 kg

    50 kg/bag= = P 2,554.30x P 890/bag

    0-0-60100.0 kg

    50 kg/bag= = P 1,650.00x P 825/bag

    TOTAL COST = P 6,664.30

    Cost of option 2. combination of

    incomplete and

    single fertilizers:

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    14-14-14214.3 kg

    50 kg/bag= = P 3,471.66x P 810/bag

    46-0-0130.4 kg

    50 kg/bag= = P 2,321.12x P 890/bag

    0-0-60

    50.0 kg

    50 kg/bag= = P 825.00x P 825/bag

    TOTAL COST = P 6,617.78

    Cost of option 3. combination of complete

    and single fertilizers:

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    Use a combination of

    incomplete and single

    fertilizer materials

    Use a combination of 3

    single fertilizers

    Use a combination