Upload
vokhuong
View
215
Download
0
Embed Size (px)
Citation preview
3.5 Flow Power
- Naturally, fluid flows form high to low position.
- If we would like flow from low to high position, we need to give power to fluid.
- โPumpโ is a tool to give power to fluid.
๐1๐พ+๐12
2๐+ ๐ง1 + โ๐ =
๐2๐พ+๐22
2๐+ ๐ง2 + โ๐ฟ
When hP = Energy head of pump (m)hL = Energy head of friction loss (m)
Flow power
PF = ๐พQH When PF = flow power (kW)๐พ = Specific weight of fluid (kN/m3)
Q = Flow rate (m3/s)H = Total energy head (m)
๐
๐พ+
๐2
2๐+ z = H
The total energy head can be found by
Ex. Water surface is higher than referent point for 20 m. It has 5 m3/sof flow rate. Find the flow power caused by the water at surface.
3.6 Momentum Equation
The force caused by fluid movement which reacts with obstruction need
to study because it impacts to the equipment. The impact of fluid needs to analyze the direction and amount of its force.
The momentum of fluid mass needs to consider with the impacted Structure. It relates to the 2nd law of Newton.
F = ma
The change of momentum = ma (kg. m/s2 or N)
The change of momentum of fluid mass = ฯQdv when dv = v2 โ v1
The unit of the change of momentum of fluid mass can be found by
ฯQdv = kg/m3 ร m3/s ร m/s = kg.m/s = N
Thus, the equation of force that reacts with obstruction called โmomentum equationโ
F = ฯQdv F = Force of fluid (N)ฯ = Fluid density (kg/m3)Q = Flow rate (m3/s)dv = v2-v1 = different velocity (m/s)
Application of momentum equation
1. Fluid force reacts the planar object surface- Fluid impacts the planar object surface V1, and it makes plain object
Move as V2. The cross section of fluid is A
V1
A
V2Injector
F = ฯQdv = ฯQd(v2 โ v1) It can divided to 2 consideration.
1.1 static planar object
Thus V2 = 0 m/s we have F = -ฯQdv1
(symbol โ - โ means the reaction force of planar object.)
The flow rate (Q) of static planar object: Q = Av1
V1
A
Injector
V2 = 0 m/s
1.2 planar object moves along the flow direction
The momentum equation is F = ฯQdv = ฯQd(v2 โ v1)
Flow rate (Q): Q = A.dv (Use dv = IdvI )
V1
A
V2Injector
1.3 planar object moves opposite the flow direction
V1
A
V2
Injector
The velocity of planar object is โv2 , and velocity of fluid is v1
According to momentum equation F = ฯQdv= ฯQd(v2 โ v1)
Replace v2 as โv2 = ฯQd(-v2 โ v1)So F = -ฯQd(v2 + v1)
Flow rate (Q): Q = A(v2+v1)
2. Fluid force reacts the curve object surface- Fluid impacts the curve object surface V1, and it makes
fluid direction changed along the curve surface.
- The angle occurs in x, y plain as shown in following figure
V1
A
Injector
V1
ฮธ
V1cosฮธ
V1sinฮธ
curve object
ฮฑ
Fy
Fx
F
- Fluid jet which has V1 impacts to curve Surface (no friction force).
- The direction of fluid jet will change along the curve made the ฮธ to y-axis.
F and ฮธ can be separately considered by
2.1 Static curve surfaceF and ฮธ have to consider in x-axis and y-axis
- In x-axis (Fx) From momentum equation
Fx= ฯQ(V2-V1)
Consider only force in x-axis. Thus velocity in x-axis after impact curve surfacecan be found by V1sinฮธ Then
Fx= ฯQ(V1sinฮธ-V1)
Fx= -ฯQV1 (1-sinฮธ) and Q = AV1
- In y-axis (Fy) From momentum equation
Fy= ฯQ(V2-V1)
Consider only force in y-axis. Thus velocity in y-axis after impact curve surfacecan be found by V1cosฮธ Then
*** no velocity of V1 in y-axis then V1 = 0
Fy= ฯQ(V1cosฮธ-0)
Fy= ฯQV1cosฮธ
Summary
Flow rate Q = AV1
Resultant force F = ๐น๐ฅ2 + ๐น๐ฆ
2
Direction of resultant force ๐ผ = ๐ก๐๐โ1๐น๐ฅ
๐น๐ฆ
2.2 Moving curve surface (fluid velocity < 90 degree)
V1-V2
A
Injector
V1-V2
ฮธ
(V1-V2)cosฮธ
(V1-V2)sinฮธ
curve object
ฮฑ
Fy
Fx
F
-Fluid flows from injector, and it impact to curve surface. Then the curve surface moves with V2
-To determine F and ฮฑ, it has to calculate in X axis and Y axis separately.
- In x-axis (Fx) From momentum equation
Fx= ฯQ(V2-V1)
V2 = out coming velocity = (V1-V2)sinฮธV1 = incoming velocity = (V1-V2)
Then
V1-V2
A
Injector
V1-V2
ฮธ
(V1-V2)cosฮธ
(V1-V2)sinฮธ
curve object
ฮฑ
Fy
Fx
F
Fx= ฯQ[(V1-V2)sin ฮธ โ (V1-V2)]
Fx= ฯQ(V1-V2)(sin ฮธ - 1)
Fx= -ฯQ(V1-V2)(1 - sin ฮธ)
Flow rate => Q = A(V1 โ V2) when V1, V2 are Vfluid and Vcurve object Respectively
Power => P = Fx.V2
- In y-axis (Fy) From momentum equation
Fy= ฯQ(V2-V1)
V2 = out coming velocity = (V1-V2)cosฮธ
V1 = incoming velocity = (V1-V2) = โ0โ
Then Fy= ฯQ[(V1-V2)cos ฮธ โ (V1-V2)]
Fy= ฯQ[(V1-V2)cos ฮธ โ 0]
Fy= ฯQ(V1-V2)cos ฮธ
V1-V2
A
Injector
V1-V2
ฮธ
(V1-V2)cosฮธ
(V1-V2)sinฮธ
curve object
ฮฑ
Fy
Fx
F
0
Flow rate => Q = A(V1 โ V2) when V1, V2 are Vfluid and Vcurve object Respectively
Resultant Force => ๐น = ๐น๐2 โ ๐น๐ฆ
2 ฮฑ = ๐ก๐๐โ1๐น๐ฅ๐น๐ฆ
2.3 Moving curve surface (fluid velocity > 90 degree)
V1-V2Injector
-(V1-V2)
ฮธ
-(V1-V2)cosฮธ
-(V1-V2)sinฮธ
curve object
ฮฑ
Fy
Fx
F
x
y
- In x-axis (Fx) From momentum equation
Fx= ฯQ(V2-V1)
V2 = out coming velocity = -(V1-V2)sinฮธV1 = incoming velocity = (V1-V2)
Then Fx= ฯQ[-(V1-V2)sin ฮธ โ (V1-V2)]
Fx= -ฯQ[(V1-V2)sin ฮธ + (V1-V2)]
Fx= -ฯQ(V1-V2)(sin ฮธ + 1)
Flow rate => Q = A(V1 โ V2) when V1, V2 are Vfluid and Vcurve object Respectively
Power => P = Fx.V2
- In y-axis (Fy) From momentum equation
Fy= ฯQ(V2-V1)
V2 = out coming velocity = -(V1-V2)cosฮธ
V1 = incoming velocity = (V1-V2) = โ0โ
Then Fy= ฯQ[[-(V1-V2)cos ฮธ โ (V1-V2)]
Fy= ฯQ[-(V1-V2)cos ฮธ โ 0]
Fy= -ฯQ(V1-V2)cos ฮธ
V1-V2Injector
-(V1-V2)
ฮธ
-(V1-V2)cosฮธ
-(V1-V2)sinฮธ
curve object
ฮฑ
Fy
Fx
F
x
y
0
Flow rate => Q = A(V1 โ V2) when V1, V2 are Vfluid and Vcurve object Respectively
Resultant Force => ๐น = ๐น๐2 โ ๐น๐ฆ
2 ฮฑ = ๐ก๐๐โ1๐น๐ฅ๐น๐ฆ