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(ACADEMIC SESSION 2011-2012)

CLASSROOM CONTACT PROGRAMME

1.

2.

3.

4.

A seat marked with Reg. No. will be alloted to each student. The student should ensure that he/she

occupies the correct seat only. If any student is found to have occupied the seat of another student,

both the students shall be removed from the examination and shall have to accept any other penalty

imposed uponthem.

Student can notuse log tables and calculators or any other material in the examination hall.

Student must abide by the instructions issued during the examination, by the invigilators or the

centre incharge.

Before attempting the question paper ensure that it contains all the pages and that no question is

missing.

izR;sd fo|kFkhZ dk jftLVs'ku ua- ds vuqlkj LFkku fu;r gS rFkk os vius fu;r LFkku ij gh cSBsaA ;fn dksbZ fo|kFkhZ fdlh

nwljs fo|kFkhZ ds LFkku ij cSBk ik;k x;k rks nksuksa fo|kfFkZ;ksa dks ijh{kk d{k ls ckgj dj fn;k tk,xk vkSj nksuksa dks dksbZ vU

tqekZuk Hkh Lohdk;Z gksxkA

fo|kFkhZ ijh{kk d{k esa yksx Vscy] dsYdwysVj ;k fdlh vU; lkexzh dk mi;ksx ugha dj ldrk gSA

ijh{kk ds le; fo|kFkhZ dks ijhoh{kd }kjk fn;s x;s funsZ'kksa dh ikyuk djuk vko';d gSA

iz'u i= gydjus ls igys fo|kFkhZ vk'oLr gks tk, fd blesalHkh ist layXu gSa vFkok ughaA

izR;sd lghmkj ds vad gSa tcfd ,dfrgkbZ vad] xyr mkj dkml fo"k; ds dqy vadksa esa ls de dj fy;k tk;sxkA

5. Each correct answer carries 1 marks, while one third mark will be deducted from the total of

individual subject for each incorrect answer.

MAJOR TEST

DATE : 27 04 2012ALLEN AIIMS # 01

TA R G E T : P R E - M E D I C A L 2 0 1 2

LEADER, ACHIEVER & ENTHUSIAST COURSE

Corporate Office

ALLEN CAREER INSTITUTESANKALP, CP-6, INDRA VIHAR, KOTA-324005

PHONE : +91 - 744 - 2436001, Fax : +91-744-2435003

E-mail: [email protected] Website: www.allen.ac.in

Do not open this Test Bookl et until you are asked to do so /

(Full Syllabus)

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Your Target is to secure Good Rank in Pre-Medical 2012

MAJOR TEST : AIIMS

PRE-MEDICAL : LEADER, ACHIEVER & ENTHUSIAST COURSE

1. In the circuit shown, which of the following

statements is true

(1) With S1closed, V1= 15 V, V2= 25V

(2) With S3closed, V1= V2 = 25V

(3) With S2 closed, V1=V2 = 0

(4) With S1& S3 closed,V1=30V, V2= 20V

2. Light from a hydrogen discharge tube is incident

on the cathode of a photoelectric cell, the work

function of the cathode surface is 4.2 eV. In order

to reduce the photo current to zero the voltage of

the anode relative to the cathode must be made

(1) 4.2 V (2) 9.4 V

(3) 17.8 V (4) + 9.4 V

3. The root mean square value of voltage,

if an alternating voltage is given by

e = e1sinwt + e2coswt is :-

(1)2 21 2e e

2+ (2)

2 21 2e e

2

(3) 1 2e e (4) None of these

4. Sixteen beads in a string are placed on a smooth

inclined plane of inclination sin1(1/3) such that

some of them lie along the incline whereas the rest

hang over the top of the plane. If acceleration of

first bead is g/2, the arrangement of beads is

that :-

q

(1) 12 hang vertically

(2) 10 lie along inclined plane

(3) 8 lie along inclined plane

(4) 10 hang vertically

1. fp esa fn;sx;s ifjiFk ds fy;sdkSulsdFku lR gS

(1)tcS1cUn gS, V1 = 15 V, V2= 25V

(2)tcS3cUn gS, V1= V2= 25V

(3)tcS2cUn gS, V1 =V2 = 0

(4)tcS1rFkkS3cUn gS, V1=30V, V2 = 20V

2. gkbMkstu foltZu ufydk lsmRlftZr izdk'k

d izdk'kfo|qr lsy ds dSFkksM ij fxjrk gSA lsy dsdSFkksM dk dk;Z

Qyu4.2 eVgSA izdk'k fo|qrkkjk dk eku 'kwUdjus

ds fy;s dSFkksM dslkis{kuksM dk foHko gksxk (1) 4.2 V (2) 9.4 V

(3) 17.8 V (4) + 9.4 V

3. ;fn iz R; korh Z foHko e = e1sinwt + e2coswt lsfn; k x; k gS rk s bld k ox Z ek e wy eku D;kgksxk :-

(1)2 21 2e e

2+ (2)

2 21 2e e

2

(3) 1 2e e (4)buesalsdksbZ ugha

4. sin 1(1/3) >qdko okysd fpdus ur ry ij 16ef.k;ksa dhd ekyk bl izdkj j[kh xbZ gS fd buesa lsdqN ef.k;k ur ry ds vuq fn'k fLFkr gStcfd 'ks"kef.k;k ur ry ds 'kh" kZ ls yVdh gqb Z gSA fn igyhef.k dk Roj.kg/2 gSrks ef.k;k bl izdkj O;ofLFkrgS fd :-

q

(1) 12/okZ/kj yVdh gqbZ gS(2) 10ur ry dsvuqfn'k fLFkr gS(3) 8ur ry dsvuqfn'k fLFkr gS(4) 10/okZ/kj yVdh gqbZ gS

BEWARE OF NEGATIVE MARKING

HAVE CONTROL HAVE PATIENCE HAVE CONFIDENCE100% SUCCESS

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2/34 E / HYour Target is to secure Good Rank in Pre-Medical 2012

MAJOR TEST : AIIMS

TARGET : PRE-MEDICAL 2012

5. The thermo e .m.f . of copper cons tantan

termocouple is 50mVC1at room temperature.A galavanometer of resistance 50 Wand capableof detecting currents of the order of 2mA is used.

The temperature difference that can be detectedby this galvanometer is :-

(1) 20C (2) 2C

(3) 10C (4) 0.20C

6. A static radioactive nucleus undergoes a-emissionto form a stable element. What will be the recoil

velocity of the daughter nucleus if V is the velocity

of a-emission and A is the mass number ofradioactive nucleus :-

(1)

4V

A 4- (2)

2V

A 4-

(3)4V

A 4+(4)

2V

A 4+

7. A man wants to distinguish between two pillars

located at a distance of 11 km. What should be

the minimum distance between pillars ?

(1) 3.2 m (2) 1.2 m (3) 1.1 m (4) 1.8 m

8. The following diagram represents :-

(1) NOR gate

(2) OR gate A

Bp

(3) AND gate

(4) None

9. The figure below shows two equipotential lines

in XY plane for an electric field. The scales are

marked. The X-component Exand Y-component

Eyof the electric field in the space between these

equipotential lines are respectively

(1) +100 V/m, 200 V/m

(2) +200 V/m, +100 V/m

(3) 100 V/m, +200 V/m

(4) 200 V/m, 100 V/m

5. dkWij&dkaLVsUVu rki oS|qr qXe dk dejs ds rki ijfo- ok- cy50mVC1gSA50 Wizfrjks/k dkdkkjkekih

tks2mAds e dh kkjkvksa dkslalwfpr dj ldrk gS

iz;ksx fd;k tk jgk gS ml rkikUrj dh x.kuk djks ftls

bl kkjkekih kjk lalwfpr fd;k tk ldrk gS :-(1) 20C (2) 2C

(3) 10C (4) 0.20C

6. ,d fLFkj jsfM;ks/kehZ ukfHkd LFkkbZ rRo cukus ds fy

a-mRltZu djrk gSA iq=h ukfHkd dk izfrf{kIr osx D;k gksxk

;fna-mRltZu dk osxVgksrFkk jsfM;ks/kehZ ukfHkd dh

O;eku lakAgS :-

(1)

4V

A 4- (2)

2V

A 4-

(3)4V

A 4+(4)

2V

A 4+

7. ,d O;fDr nkskEcstksmlls11 kmnwj gSdksvyx&vyxns[kuk pkgrk gSbukEcksa dh chp dh U;wure nwjh D;k gksuhpkfg,A(1) 3.2 m (2) 1.2 m (3) 1.1 m (4) 1.8 m

8. fuEu fp iznf'kZr djrk gS :-

(1) NOR gate

(2) OR gate A

Bp

(3) AND gate

(4) dksbZ ugha

9. fp=kuqlkjXYry esa fdlh fo|qrksdh lefoHko js[kk,

nf'kZr gSaA iSekuk fp=kuqlkj gSA bu lefoHko js[kkvksa ds

efo|qrksdsX?kVdExrFkkY?kVdEydseku

e'k gS

(1) +100 oksYV/ehVj, 200oksYV/ehVj

(2) +200 oksYV/ehVj, +100oksYV/ehVj

(3) 100oksYV/ehVj, +200oksYV/ehVj

(4) 200oksYV/ehVj, 100oksYV/ehVj

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10. An atomic power nuclear reactor can deliver 300

MW. The energy released due to fission of each

nucleus of uranium atom U238is 170 MeV. The

number of uranium atoms fissioned per hour will be:-

(1) 30 1025

(2) 4 1022

(3) 10 1020 (4) 5 1015

11. Two plane mirrors are combined to each other as

such one is in y-z plane and other is in x-z plane.

A ray of light along vector i j k+ + is incidenton the first mirror. The unit vector in the direction

of emergence ray after successive reflections

through the mirror is :-

(1)1 1 1 i j k3 3 3

- +

(2)1 1 1 i j k3 3 3

-

(3) i j k-

(4) None of these

12. A variable force (24t2 8t) Newton is acting on

a particle. The impulse imparted to it in first two

seconds will be :

(1) 12 kg-m/s (2) 24 kg-m/s

(3) 36 kg-m/s (4) 48 kg-m/s

13. Two identical capacitors 1 and 2 are connected in

series to a battery as shown in figure. Capacitor

2 contains a dielectric slab of dielectric constant

k as shown. Q1and Q2 are the charges stored in

the capacitors. Now the dielectric slab is removed

and the corresponding charges are Q1' and Q2' . Then

(1)

=

+ (2)

=+

(3)

=

+

(4)

=

14. A radioactive sample of U238decay to Pb through

a process for which half life is 4.5 10 9years.The

ratio of number of nuclei of Pb to U238after a time

of 1.5 109years (given 21/3= 1.26) :-

(1) 0.12 (2) 0.26 (3) 1.2 (4) 0.37

10. ,d ijek.k q Hkh 300 MW 'kfDr iznku djrh gSAizR;sd wj sfu;e U238ukfHkd ds fo[k.Mu ls eqDrtk Z 170 MeV gSA izfr k.V s fo[kf.Mr wj sfu;eijek.kqvksa dh lak gS :-

(1) 30 1025

(2) 4 1022

(3) 10 1020 (4) 5 1015

11. nks lery niZ.kd nwljs ls bl rjg tqM+ s gS fddy-zry esa rFkk nwljkx-zry esa gSAd izdk'k fdj.k

igysniZ.k ij lfn'k i j k+ + dsvuqfn'k vkrh gSA buniZ.k ls Vdjkusds ckn izdk'k ds fdj.k dh fn'kk esa bdkbZlfn'k D;k gksxk :-

(1)1 1 1 i j k3 3 3

- +

(2) 1 1 1 i j k3 3 3

-

(3) i j k-

(4)buesa lsdksbZ ugha

12. fdlh d.k ijd ifjorhZ cy(24t2 8t)U;wVu dk;ZjrgSA iz Fke nk s lsd.M esa ml s izn ku fd;k x;k vko sxgksxk :(1) 12fdxzk-eh/ls (2) 24fdxzk-eh/ls(3) 36fdxzk-eh/ls (4) 48fdxzk-eh/ls

13. fp=kuqlkj nksd leku la/kkfj 1rFkk2,d cSVjh lstksM+sx;sgSaA la/kkfj 2esa ijoS|qrkadkdh ijkoS|qrkadifdk gSA la/kkfj=ksa ij vkos'k e'k Q1rFkkQ2gSAvc ijkoS|qr ifdk gVk ysusij la/kkfj=ksa ij vkos'kQ1'rFkk Q2' gS rks

(1)

=

+ (2)

=+

(3)

=

+

(4)

=

14. U238dkd jsfM;kslf uewukd izf;kkjkPbesafo?kfVr gkstkrk gSbl izf;k dsfy vZ&vk;q4.5 109

o"kZ gSA1.5 109o"kZ cknPbukfHkdksadh lakoaU238

dsukfHkdksa dh lak dk vuqikr gksxk(fn;k gS21/3=1.26):-(1) 0.12 (2) 0.26 (3) 1.2 (4) 0.37

izR;sd iz'u dks vtqZu cudj djksA

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15. A convergent doublet of separated lens, corrected

for spherical aberration, are separated by 2 cm,

and has an equivalent focal length of 10 cm. The

focal length of its component lenses are :

(1) f1= 18 cm, f2= 10 cm(2) f1= 20 cm, f2= 28 cm

(3) f1= 20 cm, f2= 18 cm

(4) f1= 24 cm, f2= 18 cm

16. The variation of velocity of a particle moving

along a straight line is illustrated in the fig. The

ratio of avg. speed to avg. vel. is :-

(1) 2 : 1 (2) 1 : 2

(3) 1 : 1 (4) 4 : 1

17. An electric dipole consists of two oposite charges

each of magnitude 1.0mC separated by a distanceof 2.0 cm. The dipole is placed in an external field

of 1.0 105

N/C. The maximum torque on thedipole is :-

(1) 0.2 103N-m (2) 2.0 103 N-m

(3) 4.0 103N-m (4) 1.0 103 N-m

18. Consider a cycle followed by an engine -

1 2

3

P

V

1 to 2 is isothermal

2 to 3 is adiabatic

3 to 1 is adiabatic

Such a process does not exist because :

(1) three process can not represent a cycle process

(2) mechanical energy is completely converted to

heat in this process, which is not possible

(3) curves representing two adiabatic processes do

not intersect

(4) curves representing an adiabatic process andan isothermal process do not intersect

15. nksvfHklkjh ysUl tksd nwljsls2 cmnwj j[ks gSd,slkqXe cuk jgsgSftlesa xksyhfoiFku u gksfn bl;qXe dh rqYQksdl nwjh10 cmgSrksizR;sd dh Qksdlnwjh D;k gksxh :

(1) f1= 18 cm, f2= 10 cm(2) f1= 20 cm, f2= 28 cm

(3) f1= 20 cm, f2= 18 cm

(4) f1= 24 cm, f2= 18 cm

16. ,d lh/kh js[kk dsvuqfn'k xfr djrsgqd.k dsosx esaifjorZu dk fpfn;k x;k gSrksvkSlr pky o vkSlr osxdk vuqikr D;k gksxk :-

(1) 2 : 1 (2) 1 : 2

(3) 1 : 1 (4) 4 : 1

17. ,d oS|qr fkqzo esa foifjr izfroa leku ifjek.k1.0mC

ds nksvkos'k2.0lseh- nwjh ij fLFkr gSA bl oS|qr f}kqzo

dks1.0 105U;wVu@dwyWke rhozrk dsck fo|qrkS

esa j[kk gSA fkqzo ij vf/kdre cyk?kw.kZ gS :-(1) 0.2 103U;wVu&ehVj (2) 2.0 103U;wVu&ehVj

(3) 4.0 103U;wVu&ehVj (4) 1.0 103U;wVu&ehVj

18. ,d btukjk fuEufyf[kr ph ize fopkj.khgS-

1 2

3

P

V

1ls2lerkih2ls3:ks"e3ls1:ks"e gS;gd ize ds fy fl ugha gksrk gSD;ksafd :(1)rhu i zed ph ize dks vfHkO;Dr ugha dj

ldrs gSA(2)bl ize esakafU=d tkZ iw.kZi ls"ek esaikUrfjr

gkstk;s vlaHko gSA(3)o nksks"e izeksa dksvfHkO;Dr djrsgStksd

nwljsdksizfrPNsfnr ugha djrs gSA

(4)odks"e vkSjd lerkihize dks vfHkO;Drdjrs gStksd nwljsdksizfrPNsfnr ugha djrs gSA

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19. A particle executing simple harmonic motion has

amplitude of 2m. the equation of displacement of

particle is if time period is 2 second :-

(1) x = 2 sinpt (2) x = 3 sinpt

(3) x = 2 sin 3pt (4) x= 4 sin6t20. A ball is moving with velocity 2 m/s towards a

heavy wall moving towards the ball with speed

1 m/s. Assuming collision to be elastic the velocity

of ball immediately after collision :-

(1) 2 m/s (2) 4 m/s (3) 6 m/s (4) 8 m/s

21. A satellite is revolving round the earth with orbital

speed v0. If it stops suddenly, the speed with which

it will strike the surface of earth would be

(ve= escape velocity of a particle on earth's surface)

(1)

(2) v0 (3)

- (4)

-

22. Consider two containers A and B containing

identical gases at the same pressure, volume and

temperature. The gas in container A is compressed

to half of its original volume isothermally while

the gas in container B is compressed to half of its

original value adiabatically. The ratio of final

pressure of gas in B to that of gas in A is :

(1) 2g 1 (2)

11

2

g-

(3)

21

1

- g

(4)

21

1

g -

23. In a young's double slit experiment, the fringe

pattern is observed on a screen placed at a distance

D. The slits are separated by d and are illuminated

by light of wavelength l. Find the distance from

the central point where the intensity falls to halfthe maximum is :-

(1)l

(2)

l

(3)l

(4)

l

24. A man is walking with 5 m/s. Rain drops are

falling vertically but he finds that rain drops are

falling at an angle 45 with vertical the actual

speed of rain will be :-

(1) 5 m/s (2)5 3

(3)5

3(4) 4

19. ljy vkorZ xfr djrs gq d.k dk vk;ke2m rFk kvkorZ dky2sec. gSd.k ds foLFkkiu dk lehdj.kgksxk :-(1) x = 2sinpt (2) x = 3sinpt

(3) x = 2 sin 3pt (4) x= 4sin6t20. 2 m/sdsosx lsxfr'khyd xsUn1 m/sdh pky lspy

jghd Hkk jh nhokj dh vksj xfreku gSA VDdj dksizR;kLFk ekurs gq VDdj ds Bhd i'pkr~ xsUn dk osxgksxk :-(1) 2 m/s (2) 4 m/s (3) 6 m/s (4) 8 m/s

21. ,d mixzg i`Foh ds pkjksa vksjv0pky ls ifjek djjgk gSAfn bldks vpkud jk sd fn;k tk;srksg i`Fohdh lrg ls fuEu pky ls Vdjk,xk(ve=i`Foh dh lrgls fdlh d.k dk iyk;u osx) :

(1)

(2) v0 (3)

- (4)

-

22. nksik A vkSjBleku nkc vk;ru vkSj rkieku ij le:i

xSl j[krsgSA ik Aesa xSl okLrfod vk;ru dh vk/kh

vk;ru rd lerkih i lsleihfM+r dh tkrh gStcfd

ik Besaks"ei lsokLrfod eku dh vk/ksvk;ru

rd leihfM+r dh tkrh gSA xSlBdk xSlAdsvfUre

nkc lsvuqikr gS :

(1) 2g 1 (2)

1

12

g-

(3)

21

1

- g

(4)

21

1

g -

23. ;ax ffLyV iz;ksx esafat izfr:iDnwjh ij fLFkr insZ

ij izkIr gksrk gSA fLyVksa dksdnwjh ij j[kk gSrFkk mUgsal

rjax nS;Zds izdk'k ls izdkf'kr fd;k x;k gSA dsU fcUnq

ls og nwjh Kkr djkstgkrhozrk vf/kdre rhozrk dh vkkh

gks

(1)l

(2)

l

(3)l

(4)

l

24. 5 m/s ls xfr djrs gq d O;fDr dks o"kk Z dh cwns/okZ/kj ls45dsdks.k ij vkrh gqbZ izrhr gksrh gSAfno"kkZ dh cwnsokLrfodi ls /okZ/kj uhps fxj jgh gksrkso"kkZ dh okLrfod pky gksxh :-

(1) 5 m/s (2) 5 3 (3)

5

3 (4) 4

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25. In an experiment of potentiometer for determining a

small resistance, the balancing length for the potential

difference across the large resistance is 320 cm. and

the balancing length for the potential difference

across both resistances when connected in series, is

360 cm. The ratio of large and small resistances is :-

(1) 1 : 8 (2) 8 : 1

(3) 8 : 9 (4) 9 : 8

26. The intensity of radiation emitted by the Sun has

its maximum value at a wavelength of 510 nm and

that emitted by North Star has the maximum value

at 350 nm. If these stars behave like blackbodies,

then the ratio of the surface temperatures of the

Sun and the North Star is :

(1) 1.46 (2) 0.69

(3) 1.21 (4) 0.83

27. The frequency of oscillation of the system shown

in the figure will be :-

(1)1

2p

k

M

(2)1

2p

2k

M

(3)1

2pk

M5

M

KK

K

K

(4)1

2p

2

5

k

M

28. The K.E. of a body varies directly as the time (t)

elapsed. the force acting varies directly as :-

(1) t1 (2) t1/2 (3) t1/2 (4) t

29. In the following circuit, if total heat dissipated in

the circuit is 18J/s, then what is the heat dissipatedin 5W resistance :-

(1) 18 J

(2)

J

(3)

J

(4) None of these

25. ,d vYi izfrjks/k dks Kkr djus ds foHkoekih iz;ksx esa cM+s

iz frjks/ k ds fljksa ij foHkokUrj ds fylUrq fyr yEck bZ

320 cm.gSA tc nksuksa izfrjks/k Js.khe esa tksM+s tkrsgSrks

mudsfljksaij foHkokUrj dsfy

lUrqfyr yEckbZ360 cm.

gS

rkscM+so NksVsizfrjks/kksa dk vuqikr gS-

(1) 1 : 8 (2) 8 : 1

(3) 8 : 9 (4) 9 : 8

26. lw;Zkjk fofdj.k mRltZu dh rhozrk510 nmdh rjax

nSZ ij vf/kdre eku j[krh gSvkSjkqzoh rkjkkjk mRltZu

350 nmij vf/kdre eku j[krk gSAfns rkjsf".kdk

oLrq dh rjg dk;Z djrs gSrkslw;Z vkSjkqzoh rkjsds i`"B

dk rkieku dk vuqikr gS :

(1) 1.46 (2) 0.69

(3) 1.21 (4) 0.83

27. layXu fp esa fudk dh nksyu vko`fk gksxh :-

(1)1

2p

k

M

(2)1

2p

2k

M

(3)1

2pk

M5

M

KK

K

K

(4)1

2p

2

5

k

M

28. fdlh oLrq dh xfrt tkZK.E.le (t)ij lh/ksfuHkZjdjrh gSA oLrq ij yx jgk cy lh/ks fuHkZj djsxk :-(1) t1 (2) t1/2 (3) t1/2 (4) t

29. fuEu ifjiFk esa fn dqy O;f;r tkZ18J/sgSrks5W

frjks/k esa O;f;r tkZ gksxh :-

(1) 18 J

(2)

J

(3)

J

(4)mijksDr esa ls dksbZ ugha

dksbZ Hkh iz'u ls xyr ugha gksuk pk g,A

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30. Two particles A and B of masses mA and mBrespectively and having the same charge are

moving in a plane. A uniform magnetic field exists

perpendicular to this plane. The speeds of the

particles are vA and vB respectively and thetrajectories are as shown in the figure. Then :-

B

B

A

(1) mAvA< mBvB

(2) mAvA> mBvB

(3) mA< mBand vA< vB

(4) mA= mBand vA= vB

31. If angular velocity

60

t

wv/s t ime curve of a

rotating body is

represented by (fig.)

then variation of

angular acceleration with time is properly

representated by :-

(1)

t

a3

(2)

a

1

3

t

(3)

t

a

3

(4)

1

3

a

t

32. A stone thrown at an angle q to the horizontalreaches a maximum height h. The time of the

flight of the stone is :-

(1)2hsin

g

q(2)

2 2h sin

g

q

(3)

2h2

g (4)

2h

g

30. nks d.k A rFkk B ftuds nzO;eku mArFkk mBgS rFkk

vkos'k leku gS d ry es a xfr' k hy g SA

pq Ecdh ks ry ds yEcor~ g S d. kk sa ds os x

e' k vArF kk vBgS rF kk iFk fp vuqlkj gS

rks :-

B

B

A

(1) mAvA< mBvB

(2) mAvA> mBvB

(3) mA< mBand vA< vB

(4) mA= mBand vA= vB

31. ;fn d kw.kZu djrh oLrq

60

t

wdk dk s.kh osx le

ds lkFk fp ls n'kkZ;k

tkrk gS rks dks.kh Roj.k

dk le dslkFk ifjorZu

n'kkZus okyk lgh o gksxk

(1)

t

a3

(2)

a

1

3

t

(3)

t

a

3

(4)

1

3

a

t

32. ,d iRFkj dkskSfrt lsqdks.k ij iz{ksfir fd;k tkrk gSrFkk og vf/kdre pkbZhrd igqprk gSA iRFkj dsfy;smM+ku dky gksxk :-

(1)2hsin

g

q(2)

2 2h sin

g

q

(3)

2h2

g (4)

2h

g

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33. mlagfr dkd bysDVkWutcVfoHkokUrj lsRofjr gksrk

gSMh&czksXyh rjaxnSZlj[krk gSA leku foHkokUrj lsRofjr

Mlagfr dsizksVkWu dh Mh&czksXyh rjaxnSZ gksxh

(1)m

Ml (2)

m

Ml

(3)M

ml (4)

M

ml

34. nk s p qEcd ftud s pqEcdh fkz qo vk? kw .k ZMrFk k

M / 3 gS d nwljsdsyEcor~ ck/kdjd ksl cuk jgsgS A fn bl q Xe dk s d leku pqEc dh k sBesa eqDri l s yVdk;k tkrk gS r ks qdk D;k ekugksxk:-

q

M 3

M

(1) q = 30 (2) q= 90

(3) q= 60 (4) q= 4535. nksLofj=ksaP,oaQdksd lkFk ctk;stkusij mRik foLianksa

dh lak dks ljy js[kkOA}kjk O;Dr djrs gSaAQdksekse ls Hkkfjr djdsiqunksuksa dksd lkFk ctk;k tk;srks mRik foLianksa dh lak js[kkOBdskjk O;fDr djrsgSaAfnP dh vko`f k341 Hz gS rksQ dh vko` fkgksxh :-

BA

3

2

1

01 2

Beats

t(s)

(1) 341 Hz

(2) 338 Hz

(3) 344 Hz

(4)buesa lsdksbZ ugha

33. An electron of mass m when accelerated through

a potential difference V has de-Broglie

wavelength l . The de-Broglie wavelengthassociated with a proton of mass M accelerated

through the same potential difference will be :-

(1)m

Ml (2)

m

Ml

(3)M

ml (4)

M

ml

34. M and M / 3 are the magnetic dipole moments

of the two magnets, which are joined to form a

cross figure. The inclination of the system with

the field if their combination is suspended freely

in a uniform external magnetic field B is :-

q

M 3

M

(1) q = 30 (2) q= 90

(3) q= 60 (4) q= 4535. Two tuning forks P and Q are vibrated toghether.

The number of beats produced are represented by

the straight line OA in the following graph. After

loading Q with wax again these are vibrated

together and the beats produced are represented

by the line OB. If the frequency of P is 341 Hz,

the frequency of Q will be :-

BA

3

2

1

01 2

Beats

t(s)

(1) 341 Hz

(2) 338 Hz

(3) 344 Hz

(4) None of these

Use stop, look and go method in reading the question

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36. ,d ljy yksyd fu;r vk;kefcuk eanu dsls nksyudj jgk gStc xksyd dk foLFkkiu bldsvf/kdre ekuls de gSml fLFkfr esa bldk Roj.k lfn'k a

r

lghils fn[kk;k x;k gS :-

(1)

a

(2)

a

(3)a (4)

a

37. ,dkkrq ftldk dk;Z Qyuf gS dsi`"B ij vkifrrrjaxnSZ lds izdk'kkjk mRlftZr bysDVkWu dk vf/kdreosx gk sxk :-

(1)( )

1/ 2

2 hc

m

+ lf l

(2)( )2 hc

m

- lf

(3)( )

1/ 2

2 hc

m

- lf l

(4)( )

1/ 2

2 h

m

l - f

38. fpesa crkbZ dq.Myh esa lkE voLFkk ij fdruh pqEcdhtkZ laxzfgr gksxh ?

25V

2W

5W 5H 10W

25W

(1) 21.3 J (2) 42.6 J (3)'kwU (4) 213 J39. fdlh rusgq dleku rkj dh vko`fk d cUn ikbi

dh ewy vko` fk ds lkFk vu quk fnr gSA fn rkj ds

ruko esa8Ndh o`f dj nh tk;srksg cUn ikni ds

izFke vf/kLojd lsvuqukfnr gksrk gSA rkj esa izkjfEHkd

ruko gS :-

(1) 1 N (2) 4 N (3) 8 N (4) 16 N

40. ,d ur ij j[kk CykWdPrc fQlyuk 'kqdjrk gStcur ry dk dks.k37gSA bl CykWd dks vUCykWdQlsizfrLFkkfir fd;k x;koa ik;k x;k fdg rc fQlyuk'kq djrk gStc ur ry dk dks.k43gS :-(1) m

P> m

Q (2) m

P< m

Q

(3) mP= m

Q (4)lHkh rhuksa lEHko gS

36. A simple pendulum is oscillating without damping

when the displacement of the bob is less than

maximum, its acceleration vector ar

is correctly

shown in :-

(1)

a

(2)

a

(3)a (4)

a

37. The maximum velocity of an electron emitted by

light of wavelength lincident on the surface ofa metal of work function f, is :-

(1)( )

1/ 2

2 hc

m

+ lf l

(2)( )2 hc

m

- lf

(3)( )

1/ 2

2 hc

m

- lf l

(4)( )

1/ 2

2 h

m

l - f

38. In the circuit shown what is the energy stored in

the coil at steady state ?25V

2W

5W 5H 10W

25W

(1) 21.3 J (2) 42.6 J (3) Zero (4) 213 J

39. The frequency of a stretched uniform wire under

tension is in resonance with the fundamental

frequency of a closed tube. If the tension in the

wire is increased by 8N, it is in resonance with

the first overtone of the closed tube. The initial

tension in the wire is :-

(1) 1 N (2) 4 N (3) 8 N (4) 16 N

40. A block P kept on an inclined surface just begins

to slide if the inclination is 37. The block is

replaced by another block Q and it is found that

it just begins to slide if the inclination is 43 :-

(1) mP> m

Q (2) m

P< m

Q

(3) mP= m

Q (4) All the three are possible

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41. CH3MgB r +

O

3H O+

A HBr B

Mg/ ether C3

HCHO

H O+ D HI E

E is

(1)CH3 CH I2

(2)CH CH2 3

I

(3)CH3

I (4)CH 3

I

42. In the following reaction sequence, the correct

structures of E, F and G are

O O

Ph OH* Heat [E] 2

I

NaOH [F] + [G]

[* implies 13C labelled carbon]

(1) E =

O

Ph CH3* F =

O

Ph O Na* 1 G = CHI3

(2) E =

O

Ph CH3* F =

O

Ph O Na1 G = CHI3

(3) E =

O

Ph CH3* F =

O

Ph O Na1 G = 3

*CHI

(4) E =

O

Ph CH 3* F =

O

Ph O Na1 G = 3*CH I

43. A solution of CuSO4

is electrolysed for 10 min

with a current of 1.5 amp. What is the mass of

Cu diposited at cathods ? (atomic mass of Cu= 63)

(1) 0.9 g (2) 0.3 g

(3) 4 g (4) 3.8 g

44. Which of the following ion is not coloured ?

(1) Ni(DMG)2

(2) [CO(SCN)4]2

(3) [Al(OH)4]

(4) [Fe(H2O)5(SCN)]+2

41. CH 3MgB r +

O

3H O+

A HBr B

Mg/ ether C3

HCHO

H O+ D HI E

E gS

(1)CH3 CH I2

(2)CH CH2 3

I

(3) CH3I (4) CH3

I

42. fuEufyf[kr vfHkf;k esaE, F vkSj G dh lajpuk,gS

O O

Ph OH* Heat [E] 2

I

NaOH [F] + [G]

[* implies 13C labelled carbon]

(1) E =

O

Ph CH3* F =

O

Ph O Na* 1 G = CHI3

(2) E =

O

Ph CH3* F =

O

Ph O Na1 G = CHI3

(3) E =

O

Ph CH3* F =

O

Ph O Na1 G = 3

*CHI

(4) E =

O

Ph CH3* F =

O

Ph O Na1 G = 3*CH I

43. CuSO4dsd foy;u dks10feuV rd fo|qr vi?kfVr

fd;k x;k dSFkksM ij fdrus xz keCu izk Ir gksxk fn1.5 ampdhkkjk izokfgr dh tk;s(Cu = 63)?

(1) 0.9 g (2) 0.3 g

(3) 4 g (4) 3.8 g

44. dkSulk vk;u jaxhu ugha gS?

(1) Ni(DMG)2

(2) [CO(SCN)4]2

(3) [Al(OH)4] (4) [Fe(H

2O)

5(SCN)]+2

Take it Easy and Make it Easy

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45. Correct matching is -

List - I List-II

(A) Inversion (1) Cisaddition

(B) Racemic mixture (2) Transaddition

(C) AlkeneBaeyer

Reagent (3) SN1 reaction

(D) Alkene 2Br (4) SN2reaction

(A) (B) (C) (D)

(1) 3 4 2 1

(2) 3 4 1 2

(3) 4 3 1 2

(4) 4 3 2 1

46. The order of reactivity of methyl alcohol

(I), isopropyl alcohol (II), tertiary butyl alcohol(III) and ethyl alcohol (IV) for esterification in

decreasing order will be:

(1) I > II > III > IV

(2) IV > III > II > I

(3) I > IV > II > III

(4) I > IV > III > II

47. Which is correct expression of Ka for CH3COOH

in terms of molar conductivity ?

(1)

2m

m m

c

( )l

l -l (2)

2

m

m

m

m

c

1

l l l

- l

(3) 2mcl (4) c

48. The correct increasing order of adjacent bond

angle among BF3, PF3and ClF3 :-

(1) BF3< PF3< ClF3

(2) PF3< BF3< ClF3

(3) ClF3< PF3< BF3

(4) BF3= PF3= ClF349. The correct decreasing order of stability of

following structures of formic acid is -

HCOH HCOHHC=OH HCOH

O OO O

1

1

(I) (III)(II) (IV)

1

(1) I > II > III >IV (2) II > I > III >IV(3) III > II > IV >I (4) IV > III > I >II

45. fuEu dks lgh lqesfyr djsa -

List - I List-II

(A) izrhiu (1) lei{k ksx

(B) jslsfed feJ.k (2) foi{kksx

(C) ,sYdhu cs;jvfHkdeZd

(3) SN1 vfHkf;k

(D) ,sYdhu 2Br (4) SN2vfHkf;k

(A) (B) (C) (D)

(1) 3 4 2 1

(2) 3 4 1 2

(3) 4 3 1 2

(4) 4 3 2 1

46. ,LVjhdj.k ds fy esfFky YdksgkWy (I) vkblksizksfiy

,YdksgkWy(II)r`rh;d C;wfVyYdksgkWy(III) vkSjfFky,YdksgkWy (IV) dh f;k'khyrk dk kVrk gqvk egS:(1) I > II > III > IV

(2) IV > III > II > I

(3) I > IV > II > III

(4) I > IV > III > II

47. CH3COOHdh eksyj pkydrk dsi esaKadk eku

D;k gksxk ?

(1)

2m

m m

c

( )l

l -l (2)

2

m

m

m

m

c

1

l l l

- l

(3) 2mcl (4) c

48. ekxr ca/k dks.kksa dk lgh crk gqvk e gS :-

(1) BF3< PF3< ClF3

(2) PF3< BF

3< ClF

3

(3) ClF3< PF3< BF3

(4) BF3= PF3= ClF3

49. QkfeZd vEy dh fuEu lajpukvksa ds LFkkf;Ro dkkVrk

e gksxk

HCOH HCOHHC=OH HCOH

O OO O

1

1

(I) (III)(II) (IV)

1

(1) I > II > III >IV (2) II > I > III >IV(3) III > II > IV >I (4) IV > III > I >II

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50. Match list -I [ polymers] with List - II [monomers]

and choose the correct answer from the codes

given below the list -

List-I List-II

[Polymer] [Monomer]A. PAN a. Chloroethene

B. Natural rubber b. Caprolactum

C. Nylon-6 c. Isoprene

D. PVC d. Vinyl cyanide

Code is :

A B C D

(1) d c b a

(2) a b c d

(3) c d a b

(4) b a c d

51. Tyndall effect is not observed in :-

(1) Suspension (2) Emulsion

(3) Sugar solution (4) Gold sol

52. State of hybridisation of sulphur, carbon-1,

carbon-2 in3 3(1) (2)

F S C C F respectively are :-

(1) sp3, sp3, sp3 (2) sp3, sp2, sp3

(3) sp3d, sp, sp3 (4) sp3, sp, sp3

53. Which of the following is most reactive towardselectrophilic nitration -

(1) o- xylene (2) m-xylene

(3) p-xylene (4) toulene

54. The oxidation number of carbon is zero in :-

(1) HCHO (2) CH2Cl

2

(3) C6H

12O

6(4) All are correct

55. Which one is correct for equilibrium state out of

following ?

(a) resultant rate = 0 (b) DG = 0

(c) DStotal= 0 (d) QC= KC(1) a, b (2) a, b, c

(3) a, b, d (4) a, b, c, d

56. The extent of crystal field splitting in octahedral

complexes of the given metal with particular weak

field ligand are such that :-

(1) Fe(III) < Rh(III) < Ir(III)

(2) Rh(III) < Ir(III) < Fe(III)

(3) Ir(III) < Rh(III) < Fe(III)

(4) Fe(III) = Rh(III) < Ir(III)

50. lw ph-I [cg qyd] ,o a lw ph-II [,dyd] dk slqesfyr dfj;s oa fn;s x;s dqVks esa ls lgh dk p;udfj;s

lwph

-Ilwph

-II

[cgqyd] [,dyd]A. PAN a.Dyksjks,Fkhu

B.izkd`frd jcj b.dsizksysDVe

C.ukbykWu-6 c. vkblksizhu

D. PVC d.okbfuy lk;ukbM

dqV S

A B C D

(1) d c b a

(2) a b c d

(3) c d a b

(4) b a c d

51. fV.My izHkko fdlesa ugha ns[kk x;k :-(1)Ldanu (2)beYlu(3)phuh dk foy;u (4)xksYM lkWy

52.3 3(1)(2)

F S C C F esa lYQj dkc Zu-1rFkk dkcZu-2 dh lgh

ladj.k voLFkk gS :-

(1) sp3, sp3, sp3 (2) sp3, sp2, sp3

(3) sp3d, sp, sp3 (4) sp3, sp, sp3

53. fuEu esa lsdkSulkkSfxd bysDVkuLusgh ukbVhdj.k dsizfrlokZf/kd f;k'khy gS(1) o-tk;yhu (2) m-tk;yhu(3) p-tk;yhu (4)VkWyqbZu

54. dkcZu dk vkWDlhdj.k vad 'kwU gS :-(1) HCHO (2) CH

2Cl

2

(3) C6H

12O

6(4)lHkh lgh gS

55. lkE;koLFkk ij D;k lgh gS ?

(a)ifj.kkeh nj= 0 (b) DG = 0

(c) DSdqy= 0 (d) QC= KC(1) a, b (2) a, b, c

(3) a, b, d (4) a, b, c, d

56. nh xb Z kk rqvks a ds nq c Zy k s fyx s.M gs r qv"VQydh ladqyksa esa fLVy ks foikVu dk lghe gS :-

(1) Fe(III) < Rh(III) < Ir(III)

(2) Rh(III) < Ir(III) < Fe(III)

(3) Ir(III) < Rh(III) < Fe(III)

(4) Fe(III) = Rh(III) < Ir(III)

fdlh iz'u ij nsj rd

dks u ha A

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57. HBO, oxymercuration-demercuration and acid

catalysed hydration will not give same product

in

(i) (ii)

(iii) (iv)

(1) i, ii, iii (2) ii, iii, iv

(3) i, ii, iv (4) i, iii, iv

58. Half life of an element is x second. Inx

2, seconds

the fraction of element decayed (Assume Istorder

reactive) :-(1) 21% (2) 70%

(3) 50% (4) 29.3%

59. The occupied space in bcc unit cell is :-

(1)3

2

p(2)

6

p(3)

2 2

p(4)

3

8

p

60. Which one of the following high-spin complexes

has the largest CFSE (Crystal field stabilization

energy) ?

(1) [Mn(H2O)6]2+ (2) [Cr(H2O)6]2+

(3) [Mn(H2O)

6]3+ (4) [Cr(H

2O)

6]3+

61. 2,2,6,6-tetramethyl cyclohexanol is treated with

an acid. An alkene is formed. The structure of the

alkene is

(1) (2)

(3) (4)

62. The radioactive element X, decays by the

sequence

X 1k P + a ; Half life = 30 min

P 2k Q + 2b ; Half life = 24 hrs.

The incorrect statement is :-

(1) Disintegration constant k1< k

2

(2) X and Q are isotopes.

(3) Mass number of X is more than P(4) P and Q has same atomic number

57. gkbM ksck sjhuhdj.k vkDlhdj.k vkDlhejD;qfjdj.kfoejD;wjhdj.k rFkk vEy mRizsfjr ty;kstu ij leku mRiknizkIr ugha gksrs gS

(i) (ii)

(iii) (iv)

(1) i, ii, iii (2) ii, iii, iv

(3) i, ii, iv (4) i, iii, iv

58. ,d izFke dksfV dh vfHkf;k dh v/kZvk;qxlSd.M gSx

2lSd.M esa fdruk% HkkxkpZ gks tk;sxk :-

(1) 21% (2) 70%

(3) 50% (4) 29.3%

59. bccbZdkbZ lsy esa ijek.kqvksakjkksjk x;k LFkku D;k gS:-

(1)3

2

p(2)

6

p(3)

2 2

p(4)

3

8

p

60. fuEu esa fdl mPp p.k ladqy gsrwCFSE dk ekuvfkdre gksxk

(1) [Mn(H2O)

6]2+ (2) [Cr(H

2O)

6]2+

(3) [Mn(H2O)

6]3+ (4) [Cr(H

2O)

6]3+

61. 2,2,6,6-VsVkesfFky lkbDyksgsDlsukWy dksvEy lsvfHkd`r

fd;k tkrk gSrksdsYdhu curh gSftldh lajpuk gksxh

(1) (2)

(3) (4)

62. ,d jsfM;ks/kehZ rRox fuEu izdkj ls fo?kfVr gksrk gS

X 1k P + a ; v/kZ vk;q= 30 min

P 2k Q + 2b ; v/kZ vk;q= 24 hrs.

fuEu esa lsdkSulk vlR gS :-

(1)fo?kVu fLFkjkadk1< k

2

(2) XrFkkQleLFkkfud gS

(3) Xdk nzO;eku lakPlsvf/kd gS(4) PrFkkQdk ijek.kq ekad leku gS

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63. The ionisation energy of the hydrogen atom is

XKJ. The energy required for an electron to jump

from 3rdorbit to the 4thorbit will be :-

(1)

X

6 (2) 5X (3) 7.2X (4)

5X

36

64. Which of the following will be most covalent:-

(1) NaCl (2) Na2S

(3) MgCl2

(4) MgS

65. Which of the following statement is wrong:

(1) Carbonyl compounds CH3 C| |O

R give a

positive iodoform test

(2) All secondary alcohols give iodoform

reaction(3) Alkanols CH3CH(OH)R give iodoform

reaction.

(4) The only aldehyde given iodoform reaction is

acetaldehyde.

66. The law of reciprocal proportion is applicable

for :-

(1) SO3, H

2S, H

2O (2) HCl, Cl

2O

7, NO

2

(3) PH3, P

2O

5, N

2O

5(4) H

2SO

4, SO

3, H

2O

67.Calculate the partial pressure of carbon monoxidefrom the following :-

CaCO3(s) CaO(s) + CO2(g) ; KP= 8 10

2

CO2(g) + C(s) 2CO(g) ; KP= 2

(1) 0.2 (2) 0.4

(3) 1.6 (4) 4

68. In which of the following set do all the three

compounds have bonds that are mainly ionic:-

(1) NaCl, NCl3, CCl

4(2) CsBr, BaBr

2, SrO

(3) CsF, BF3, NH3 (4) Al2O3, CaO, SO269. Consider the given reaction:

CH3 CH = CH CH2 OH NHBr

S 1' [P]

In the given reaction the product [P] is:

(1) CH3 CH = CH CH2 Br

(2) CH3

Br|CH CH = CH2

(3) CH2= CH CH = CH2

(4) CH3

Br|CH CH2 CH2 OH

63. gkbMkstu ijek.kq dh vk;uu tkZXKJgSAd bysDVkWudks3rdd{kk ls4thd{kk esa igqpkus ds fy vko';d tkZD;k gksxh :-

(1)

X

6 (2) 5X (3) 7.2X (4)

5X

36

64. fuEu esa lslokZf/kd lgla;kstdkSfxd gS(1) NaCl (2) Na

2S

(3) MgCl2

(4) MgS

65. fuEu esa lsdkSulk dFku xyr gS

(1)dkcksZfuykSfxdCH3 C| |O

R vk;ksMksQkeZ ijh{k.k

n'kkZrs gS

(2)lHkh f}rh;dsYdksgkWy vk;ksMksQkeZ ijh{k.k n'kkZrsgS

(3),sYdsukWyCH3CH(OH)R vk;ksMksQkeZ vfHkf;k

nsrs gS

(4) ,sfYMgkbMks esa dsoyflVksfYMgkbM vk;ksMksQkeZ

vfHkf;k nsrk gS

66. O;qRekuqikrh dk fu;e fdldsfy lgh gS :-

(1) SO3, H

2S, H

2O (2) HCl, Cl

2O

7, NO

2

(3) PH3, P

2O

5, N

2O

5(4) H

2SO

4, SO

3, H

2O

67. fuEufyf[kr ls dkcZu ek suk sDlkbM dk vk af'kd nkcgksxk :-

CaCO3(s) CaO(s) + CO2(g) ; KP= 8 10

2

CO2(g) + C(s) 2CO(g) ; KP= 2

(1) 0.2 (2) 0.4

(3) 1.6 (4) 4

68. ;k Sfxdks dk dk Sulk le qPp eqr vk;fudgS :-(1) NaCl, NCl

3, CCl

4(2) CsBr, BaBr

2, SrO

(3) CsF, BF3, NH

3(4) Al

2O

3, CaO, SO

2

69. fuEu vfHkf;k ij fopkj dfj;s

CH3 CH = CH CH2 OH NHBr

S 1' [P]

nh xbZ vfHkf;k esa mRikn [P]gS

(1) CH3 CH = CH CH2 Br

(2) CH3

Br|CH CH = CH2

(3) CH2= CH CH = CH2

(4) CH3

Br|CH CH2 CH2 OH

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70. What will be mole fraction of 46% of

C2H

5OH (w/w) :-

(1) 0.75 (2) 0.25

(3) 0.35 (4) 0.1

71. The initial pressure of COCl2is 1000 torr. The totalpressure of the system becomes 1500 torr, when

the equilibrium COCl2(g)CO(g) + Cl2(g) is

attained at constant temperature. The value of KP

of a reaction is :-

(1) 1500 (2) 1000 (3) 2500 (4) 500

72. Ti and Zr can be purified by :-

(1) Mond's process

(2) Zone refining

(3) Van Arkel process

(4) Distillation

73. For the given reaction

R C X

R1

R2

HOH R C OH

R1

R2

Which substrate will give maximumracemisation?

(1) C H C Br6 5

CH3

C H2 5

(2) C H C6 5

Br

OCH3

CH3

(3) CH = CH C Br2

CH3

C H2 5

(4)

C H C6 5

Br

NO 2

NH3

70. 46% C2H

5OH (w/w) dk ek sy i zHk kt D;k

gksxk :-(1) 0.75 (2) 0.25

(3) 0.35 (4) 0.1

71. COCl2dk izkjfEHkd nkc1000 torrgSA fLFkj rki ijtc lkECOCl2(g) CO(g) + Cl2(g)LFk kfir

gk srk gS rc ra dk dqy nkc1500 torr gk srk gSAvfHkf;k ds fy K

Pdk eku gksxk :-

(1) 1500 (2) 1000

(3) 2500 (4) 500

72. TirFkkZrdk 'kqfdj.k fd;k tk ldrk gS :-

(1)ek.M izekjk

(2)tksu ifj"dj.kkjk

(3)oku vdZy fof/kkjk

(4) vkloukjk

73. nh xbZ vfHkf;k ds fy;s

R C X

R1

R2

HOH R C OH

R1

R2

dkSulk lcLVsV vf/kdre jslsehdj.k nsrk gS\

(1) C H C Br6 5

CH3

C H2 5

(2) C H C6 5

Br

OCH3

CH 3

(3) CH = CH C Br2

CH3

C H2 5

(4)

C H C6 5

Br

NO 2

NH3

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74. Volume of NH3gas obtained at 27C and 1 atm

pressure by complete hydrolysis of 100 gm

of Mg3N

2? (given molecular mass of Mg

3N

2= 100)

(1) 24.6 lit (2) 49.2 lit

(3) 22.4 lit (4) 100 lit75. How much volume of 0.2M solution of acetic acid

should be added to 100ml of 0.2M solution of

sodium acetate to prepare a buffer solution of pH

5.00, pKa for acetic acid is 4.7 :-

(1) 100 mL (2) 50 mL

(3) 45 mL (4) 200 mL

76. In which of the following F-atom occupies that

hybrid orbital which has maximum relative

s-character :-

(1) CH3F (2) CH

2F

2(3) CHF

3(4) CF

4

77.

NH2

3CH Iexcess

A 2Ag Omoist

B D C

In this reaction, C is -

(1)

I

(2) (3)

OH

(4)

78. 9.8% weight by volume H2SO

4and 3.65% weight

by volume HCl is mixed. What will be normality

of resultant mixture ?

(1)3

N2

(2)N

20(3)

N

50(4)

N

100

79. Incorrect set :

(I) Oxidising nature (I2> Br2> Cl2> F2)

(II) IE1 (Na < Li < B < Be

(III) EA1(N < P < O < S)

(IV) aq. ion radius (Na+< Mg+2< Al+3)

(1) Only I (2) I, II

(3) I, II, III (4) I, III

80. Iodine is formed when KI reacts with a solution

of :-

(1) ZnSO4

(2) CuSO4

(3) FeSO4 (4) (NH4)2SO4

74. 27Crki rFkk1 atmnkc ij100 gm Mg3N

2dksty

vi?kVu l s NH3dk vk;ru fdruk fey sx k ?

(fn;k gSMg3N

2dk v.kqHkkj100gS)

(1) 24.6 lit (2) 49.2 lit

(3) 22.4 lit (4) 100 lit75. pH 5.00 qDr cQj foy;u fufeZr djus ds fy;s

100ml, 0.2M ,lh fVd vEy dk fdruk vk;rufeykuk gksxk\ lhfVd vEy ds fy;s pKa dk eku4.7 gS :-

(1) 100 mL (2) 50 mL

(3) 45 mL (4) 200 mL

76. dk Sulk F-ijek .k q ml ladf jr d{kd lscU/k cukrk ftlesa lkis{ki ls vf/kdre s-y{k.kgS :-

(1) CH3F (2) CH

2F

2(3) CHF

3(4) CF

4

77.

NH2

3CH Iexcess

A 2Ag Omoist

B D C

bl vfHkf;k esaCgS

(1)

I

(2) (3)

OH

(4)

78. 9.8% w/v)lY;wfjd vEy rFkk3.65% (w/v) HCldk s feykus ij ifj.k keh foy;u dh uke Zyrk D; kgksxh ?

(1)3

N2

(2)N

20(3)

N

50(4)

N

100

79. vlR leqPpgS :

(I) Oxidising nature (I2> Br2> Cl2> F2)

(II) IE1 (Na < Li < B < Be

(III) EA1(N < P < O < S)

(IV) aq. ion radius (Na+< Mg+2< Al+3)

(1) Only I (2) I, II

(3) I, II, III (4) I, III

80. fdlds foy;u ds lkFkKI dh vfHkf;k djokus ijvk;ksMhu izkIr gksrk gS :-

(1) ZnSO4

(2) CuSO4

(3) FeSO4 (4) (NH4)2SO4

LoLFk j ks eLr j ks rFkk i kbZ esa O;Lr j ks A

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81. In given demonstration of osmosis which of the

following not assist to create equilibrium :-

Pressure

(a) (b)

Sucrose

solution

Membrance

Water

(1) Rise in water level is funnel solution.

(2) Rise of hydrostatic pressure in funnel

solution

(3) Rise of solute concentration in funnel

solution.

(4) If sucrose diffuse out the funnel solution.

82. In the progenies of any cross, presence of

recombinants is due to:-(1) Crossing over

(2) Linkage

(3) Lack of independent assortment

(4) All of the above

83. Select the correct match :-

Disease Pathogen

(A) Brown rust of (i) Virus

wheat(B) Black rot of (ii) Bacteria

crucifers

(C) Turnip mosaic (iii) Fungi

(1) A iii, B i, C ii

(2) A i, B ii, C iii

(3) A ii, B iii, C i

(4) A iii, B ii, C i

81. fn;s x;sijklj.k dsizn'kZu esa fuEu esa ls dkSu lkE;koLFkk

dh LFkkiuk esa lgk;d ugha gS:-

Pressure

(a) (b)

Sucrose

solution

Membrance

Water

(1)Quy foy;u esa ty Lrj dk cuk

(2)Quy foy;u esa oLFkSfrd nkc dk cuk

(3)Quy foy;u esa foysdh lkUrk dk cuk

(4);fn Quy foy;u ls'kdZjk folfjr gksdj ckgj vk

tk;sA

82. fdlh kWl dh larfr;ksa esa iquZ;ksth;ksa dh mifLFkrh fdlds

dkj.k gksrh gS\(1)thu fofue

(2)lgyXurk

(3)LorU viO;wgu dh vuqifLFkrh

(4)mijksDr lHkh

83. lgh feyku dk p;u dhft

jksx jksxtud

(A)xsgw dk Hkwjk fd (i) fo"kk.kq

(B)wlhQsjh dk dkyk (ii) thok.kq

fd

(C)VuhZi ekstsd (iii) dod

(1) A iii, B i, C ii

(2) A i, B ii, C iii

(3) A ii, B iii, C i

(4) A iii, B ii, C i

Jes'kk eqLdjkrs jgs a A

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84. Consider the following statements (A) (D)

each with one or two blanks :-

(A) In the cell envelope of the prokaryotes outermost ........(i)......... followed by the

........(ii)......... and then the plasmamembrane.

(B) Typically mitochondria having a diameter........(iii)......... .

(C) ........(iv)......... store carbohydrates whereas........(v)......... store proteins.

(D) Golgi apparatus consist of many flat, disc

shaped sacs or cisternae of ........(vi).........diameter.

Which one of the following options, gives thecorrect fill ups for the respectives blanksnumbers from (i) to (vi) in the statements :-

(1) (i) Glycocalyx (iii) 0.5 to 1 mm

(v) Amyloplast

(2) (ii) Cell wall (v) Aleuroplast

(vi) 0.5 to 1

(3) (ii) Glycocalyx (iii) 1.0 to 4.1

(iv) Aleuroplast

(4) (ii) Cell wall (iv) Amyloplast(vi) 0.5 to 1 mm

85. In Mineral nutrition of plants, C, H & O is obtainfrom :-

(1) Soil (2) Air

(3) Water (4) both (2) & (3)

86. The methods of DNA fingerprinting involvesthe use of :-

(1) Restriction enzymes

(2) Taq polymerase(3) Oligonucleotide primers

(4) All the above

87. In a protein chain, the first amino acid is also

called :-

(1) N-terminal amino acid

(2) C-terminal amino acid

(3) Both of them

(4) None of the above

84. uhpsfnxdFku(A) (D)ij fopkj dhft;sftuesad

;k nks LFkku fjDr gSa:-

(A) iz ksd sfj;ks fVd ds dks f'kdk vkoj.k esa ck ijr

........(i)......... gks ftld s i'p kr e'k

........(ii).........o thoO f>Yyh gksrh gSA

(B),d izk:ih ekbVksdksfMa;k dk O;kl........(iii).........

gksrk gSA

(C) ........(iv).........esa dkcksZgkbMsV lafpr gksrk gStcfd

........(v).........esa izksVhu lafpr gksrs gSaA

(D)xkWYth midj.k cgqr lkjh piVh fMLd vkdkj dh FkSyh

;k dq aM ls feydj cuh gksrh g S ftudk O;kl

........(vi)......... gksrk gSA

uhpsfn;k x;k dkSulkd fodYi fjDr lak(i)ls(vi)

dsfymi;qZDr gSA

(1) (i) Glycocalyx (iii) 0.5 to 1 mm

(v) Amyloplast

(2) (ii) Cell wall (v) Aleuroplast

(vi) 0.5 to 1

(3) (ii) Glycocalyx (iii) 1.0 to 4.1

(iv) Aleuroplast

(4) (ii) Cell wall (iv) Amyloplast

(vi) 0.5 to 1 mm

85. ikniksa dskfut iks"k.k esa ikniC, HoOfuEu esa lsfdlls

izkIr djrk gS:-

(1)e`nk (2)ok;q

(3)ty (4) (2)o (3)nksuksa

86. DNA fingerprintingdh fof/k esa mi;ksx fd;k tkrk gS

(1)jsLVhD'kuMksU;wfDy,t dk

(2) TaqikWyhejst dk

(3) vksfyxksU;wfDy;ksVkbM izkbej dk

(4)mijksDr lHkh dk

87. ,d izksVhu k` a[kyk esa izFke vehuksvEy dkssHkh dgrs

gSa

(1) N-terminal amino acid

(2) C-terminal amino acid

(3)mijksDr nksuksa

(4)mijksDr esa lsdksbZ ugha

viuh kerk dks iwjk olwyus dk iz;kl djs a A

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88. Identify the next stage of this figure and theirrespective events :-

(1) Anaphase Chromosome move toopposite pole

(2) Metaphase Initiation of assembly ofmitotic spindle

(3) Telophase Chromosome lost theiridentity(4) None of these

89. In this given diagram, Rubisco, NADPH + H+

and ATP are involved in which of followingsteps :-

X

Y

Z

Reductionb

a

cRegeneration

CO + H O2 2

Atmosphere

Carboxylation

Sucrose, starch

(1)(a), (b) & (c) respectively(2) (a), (c) & (b) respectively(3) (c), (b) & (a) respectively(4) (c), (a) & (b) respectively

90. If probability of a Rh+child is 50% by a couple,if they have five children, then find out theprobability of two Rh+ and three Rh children:

(1)10

64(2)

5

16

(3)1

32(4)

14

88. fpesa nh xbZ voLFkk dh vxyh voLFkk o mllslEcfUkr

?kVuk ds lkFk igpkfu;s:-

(1)i'pkoLFkkxq.klwdk foijhrkzqoksa dh vksj tkuk

(2)ekoLFkklelw=h rdqZ dstekoM+sdh izf;k izkjaHk

gksuk

(3) vR;koLFkkxq.klw=ksa dh igpku dk lekIr gksuk

(4)fuEu esa lsdksbZ ughaA

89. fn;sx;s fpesaRubisco, NADPH + H+rFkkATPfuEu esa fdl pj.k esa lfEefyr gksrsgS:-

X

Y

Z

vip;ub

a

ciqu#n~Hkou

CO + H O2 2

ok;qe.My

kcksZDlhys'ku

lqkste.M(1)(a), (b) & (c) e'k(2) (a), (c) & (b) e'k(3) (c), (b) & (a)e'k(4) (c), (a) & (b) e'k

90. ;fnd tksM+sesaRh+cPpk gksusdh izkf;drk50%gSafnmudsikp cPpsgksarksnksdsRh+,oa rhu dsRhgksusdhizkf;drk crkb;s:

(1)10

64(2)

5

16

(3)1

32(4)

14

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91. In the structure of DNA molecule at each stepof ascent, the strand turns :-(1) 36 (2) 20(3) 40 (4) 75

92. The respiratory process is regulated byrespiratory rhythm centre present in medulla ofthe brain, which is ?(1) Stimulated by lower O2and H

+concentrationin aortic arch

(2) Inhibited by higher O2and H+concentration

(3) Stimulated by higher CO2and higher H+

concentration.(4) Stimulated by lower O2and H

+concentrationin carotid artery.

93. In Glycolysis how many steps are capable toperform substrate level phosphorylation :-(1) 1 (2) 2 (3) 3 (4) 4

94. In genetic engineering,Agrobacteriumand retrovirus are used as a vector for cloning genes inplants and animals, because :-

(1) They have ability to transform normal cellinto a tumour and cancerous cells

(2) They are easily available

(3) They infect all plant and animal cells

(4) They are pathogen

95. Highest cranial capacity is present in :-(1) Homosapians sapians (modern man)(2) Cromagnon man(3) Peking man(4) Neanderthal man

96. Which one of the following pairs of foodcomponents in humans reaches the stomachtotally undigested?

(1) Starch and cellulose(2) Protein and starch(3) Starch and fat (4) Fat and cellulose97. From systematics point of view select out the

odd one :-(1) Dryopteris (2) Pteris(3) Adiantum (4) Selaginella

98. In which of the following group similar type ofepithelium is not found ?(1) Fallopian tubes and nasal passage(2) Buccal cavity and cornea of eye

(3) Stomach and gall bladder(4) Thyroid follicles and peritoneum

91. DNA v.kq dh lajpuk esa fl

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99. All birds and Mammals and a very few lowervertebrate and invertebrate species are:-(1) Regulator's(2) Conformers

(3) ensures constant body temperature,constant osmotic concentration(4) Both 1 and 3

100. Proenzyme pepsinogen is secreted by :-

(1) Oxyntic cells

(2) Goblet cells

(3) Parietal cells

(4) Chief cells

101. Aflatoxins are highly toxic carcinogenicchemicals produced by :-

(1) Drosophila of plant kingdom

(2) Ergot fungi

(3) Certain dinoflagellates

(4) Aspergillus102. The placenta are located inside the :-

(1) Stigma (2) Style

(3) Ovarian cavity (4) Ovule

103. Choose the incorrect pair:-

(1) Snails, fish - Aestivation

(2) Polar bears - Hibernation(3) Zooplaktons - Diapause

(4) humming bird - Conformers

104. Which one of the following groups ofstructures/organs have similar function :-

(1) Typhlosole in earthworm, intestinal villi inrat and contractile vacuole in Amoeba

(2) Nephridia in earthworm, Malpighian tubulesin cockroach and urinary tubules in rat

(3) Antennae of cockroach, tympanum of frogand clitellum of earthworm

(4) Incisors of rat, gizzard (proventriculus) ofcockroach and tube feet of starfish

105. In India, most of the herbaria are arrangedaccording to which system of classification :-

(1) Engler and Prantl

(2) A.W. Eichler

(3) John Hutchinson

(4) Bentham and Hooker

99. lHkh i{kh rFkk Lru/kkjh o cgqr de fuEUk d'ks:dh rFkkvd'ks:dh tkfr;kWa gksrh gSa:-(1) fu;ked(2) l:aid

(3) tksviuk rki fu;r cuk;sj[krsgSa rFkk ijklj.kh lkU.kvkfn fLFkj j[krsgSaaA(4) mijksDr1o3

100. izks,Utkbe isfIlukstu dk L=o.k gksrk gS:-(1) vkfDlf.Vsd dksf'kdkvksakjk(2)xkWCysV dksf'kdkvksakjk(3)iSjkbVy dksf'kdkvksakjk(4)phQ dksf'kdkvksakjk

101. ,sQykVksfDlutks fd vR;f/kd fo"kSyk dsaljdkjd jlk;u

gSmRik fd;k tkrk gS

(1)ikni txr ds MkslksfQyk ls

(2)bjxksV dod ls

(3)dqN Mk;uksysftysV~l ls

(4) ,liftZylls102. chtk.MkluvijkfLFkr gksrk gS:-

(1)ofrZdkxz esa (2)ofrZdk esa(3)xHkkZ'k;h xqgk esa (4)chtk.M esa

103. xyrqXe dksigpkfu;s:-(1)Lusy, eNyh -xzh"e fuk

(2) /kzqoh Hkkyq -'khr fuk(3)tUrqIyod -mijfr(4) humming bird -la:id

104. fuEufyf[kr lajpukvksa@vaxksds fdld lewg esa lHkh dkdk;Z leku gS:-(1)dsapqdk fVykslksypwgs ds vkavadqj vkSjvehck

dh ladqapu'khykkuh(2)dsapqds o`DddusffM;kdkdjksp dh ekYih>h

ufydk,a vkSj pwgsdh ewufydk,a

(3)dkdjksp dssaVsukesad dh d.kZiVg vkSj dsapwdkDykbVsye(4)pwgsds arddkdjksp dk fxtMZizksosafVdqyl vkSj

LVkjfQ'k dsuyikn

105. Hkkjr esa vf/kdka'krgjcsZfj;k dks fdl oxhZdj.k dh ifr

ds vuqlkj O;ofLFkr fd;k tkrk gS

(1),Uxyj o izkUVy

(2),- MCY;w vkbdyj

(3)tkWu gfpulu

(4)csUFke o gqdjTime Management is Life Management

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106. Example of phloem fibres are :-(1) Jute (2) Flax(3) Hemp (4) All of the above

107. Among the following organism of which

catagries face the maximum threat ofextinction:-(1) Mammals (2) amphibian(3) Birds (4) Fishes

108. What is difference between HepatitisB andAIDS ?(1) Mode of transmission(2) Pathogenecity(3) Genom(4) Both (2) and (3)

109. What is common in wheat, mammals, dogs andanimals :-(1) These are all taxa at different levels(2) These are taxa belong to same category(3) These are all taxa at same level in Linnaeus

hierarchy(4) These are all categories at different levels

110. Edible part of banana is :-

(1) Epicarp and Mesocarp

(2) Well developed mesocarp and less

developed endocarp(3) Less developed mesocarp and developed

endocarp(4) Epicarp and Endocarp

111. Who is a potent force in organic evolution:-

(1) Inter specific competition

(2) Inera specific competition

(3) Both 1 and 2

(4) None

112. NK-cell kills the target cells byreleasing :-

(1) Lymphokines

(2) Interleukins

(3) Specific lymphotoxins

(4) Nonspecific perforin

113. Which of the following trait is related to Turtle?

(1) It is a garden Tortoise

(2) Fertilization is always internal

(3) Body is covered with glandular skin(4) They do not have copulatory organs.

106. yks,e js'kksa dk mnkgj.k gS:-(1)twV (2)ysDl(3)gsEi (4)mijksDr lHkh

107. fuEufyf[kr Jsf.k;ksa esa ls fdldk lclsT;knk yqIr gksusdk

ladV gSa:-(1)Lru/kkjh (2)mHk;pjh

(3)i{kh (4)eNfy;k108. ,M~l vkSj fgisVkbfVlch dschp fHkUurk D;k gS?

(1)lae.k dk rjhdk

(2)jksxtudrk

(3)ftukse

(4) (2) vkSj(3)nksuksa

109. xsgwLru/kkjhdqkk o tUrq esa D;k leku gS(1);slHkh vyx&vyx Lrj dsoxZd gSA

(2);slHkh oxZdd gh Js.kh lslEcfU/kr gSA

(3);slHkh oxZd fyfu;e inkuqe esa leku Lrj dsgSA

(4);s lHkh vyx&vyx Lrj dh Js.kh;k gSaA

110. dsysdkkkusksX Hkkx gS:-

(1)ck fHkfk o efHkfk

(2)lqfodflr efHkfk o de fodflr vUrfHkfk(3)de fodflr efHkfk o lqfodflr vUrfHkfk

(4)ck fHkfk o vUrfHkfk

111. dkSu tSo fodkl esad 'kfDr'kkyh cy gSa:-

(1) varjtkfrLi/kkZ

(2) varjktkfrLi/kkZ

(3) 1o2nksuksa

(4)dksbZ ugha

112. NK-dksf'kdk ydksf'kdkvksa dksdskjk eq djds ekjrhgS

(1)fyEQksdkbUl

(2)bUVjY;wdhUl

(3)fof'k"V fyEQksVkWfDlu

(4) vfof'k"V ijQksfju

113. fuEu esa ls dkSulk xq.k VVZy ls lEcfUkr gS\

(1);gd xkMZu dNqvk gSA

(2)fu"kspu ges'kk vkUrfjd gksrk gSA

(3)'kjhj xzfUFky peZ lsdk jgrk gSA(4)buesa eSFkqukax ugha gksrs gSaA

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114. What is the root of any plant breedingprogramme :-

(1) Selection

(2) Hybridisation

(3) Genetic variability(4) Germplasm collection

115. The source of somatostatin is same as that of

(1) Thyroxine and calcitonin

(2) Insulin and glucagon

(3) Somatotropin and prolactin

(4) Vasopresin and oxytocin

116. Which type of germ cells are not present inpuberty to meno pause :-

(1) Oogonia(2) Primary oocyte

(3) Secondary oocyte

(4) Ovum

117. Protochordates are those primary Chordateswhich posses

(1) Unpaired appendages

(2) Cranium and vertebrae

(3) Paired appendages

(4) Jaws and exoskeleton118. 'Saccharum barberi' is the variety of sugarcan

with low sugar content and low yield. It ismainly grown in :-

(1) South India

(2) North India

(3) East India

(4) West India

119. A feeling of pain in one's stomach would be

due :-(1) Exteroceptors

(2) Teloreceptor

(3) Proprioceptors

(4) Interoceptors

120. Log phase of S-shaped / sigmoid growth curveof human contains :-

(1) +ve acceleration

(2) ve acceleration

(3) Exponential phase(4) All

114. fdlh Hkh ikni iztuu dk;Ze dk ewy vk/kkj gS

(1)p;u

(2)ladj.k

(3)tufud fofHkUurk(4)tuuO laxzg.k

115. lkseSVksLVSfVu dk L=ksr ogh gStks:-

(1) FkkbjkWDlhu rFkk dSfYlVksfuu dk gS

(2)balqfyu rFkk XywdSxkWu dk gS

(3)lkSesVksVksfiu rFkk izksySfDVu dk gS

(4)oslksizsflu rFkk vkWDlhVkslhu dk gS

116. dkSuls izdkj dh teZ dksf'kdk;s ehuksikWt lsySafxd O;Ldrkesa mifLFkr ugha gksrh gS

(1)xksfu;k(2)izkFkfed lkbV

(3)f}rh lkbV

(4) v.Mk.kq

117. izksV ksdksM sZV~l os izkFk fed dkMZsV gS ftuesa ik;k tkrkgSA

(1) v;qfXer mikax

(2)diky o d'ks:d

(3);qfXer mikax

(4)tcMso ckdadky118. 'lSdsje ckjcsjh* xUusdh fdLe gSftlesa 'kdZjkkVd fuEu

gksrk gSo mRiknu Hkh de gSAg eqr mxk;k tkrkgS

(1)nf{k.k Hkkjr

(2)mkj Hkkjr

(3)iwohZ Hkkjr

(4)if'peh Hkkjr

119. fdlhd O;fDr dks vek'kesa nnZ dkglkl gks jgk gS

rksg fdlds dkj.k gksxk:-(1),DlfVjkslsIVlZ

(2)VsyksfjlsIVlZ

(3)izksfizvkslsIVlZ

(4)bUVhjkslsIVlZ

120. euq"dsS-vkdkj/flxek,M o`f o esa ykSx izoLFkk esagksrk gS:-

(1) /kukRed Roj.k

(2).kkRed Roj.k

(3)pj?kkrkadh izoLFkk(4)mijksDr lHkh

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DIRECTIONS FOR Q. NO. 121 TO 180

These questions consist of two statements each,

printed as Assertion and Reason.While

answering these Questions you are required to

choose any one of the following four responses.A. If both Assertion & Reason are True & the

Reason is a correct explanation of the Assertion.

B. If both Assertion & Reason are True but Reason

is not a correct explanation of the Assertion.

C. If Assertion is True but the Reason is False

D. If both Assertion & Reason are false.

121. Assertion :- Electric lines are always straightand continuous.Reason :- Electric lines represents electric field.

(1) A (2) B (3) C (4) D122. Assertion :- In Telescope we use objective lens

with large apertureReason :- Lerge aperture of objective lensreduces spherical afferative.

(1) A (2) B (3) C (4) D123. Assertion :- If the ice cap of the pole melts,

the day length will shortenReason :-On melting ice will flow towards theequator and decrease the moment of inertia of

the earth. This increase the frequency of rotationof the earth(1) A (2) B (3) C (4) D

124. Assertion :- Early rise of sun is due to totalinternal reflection.Reason :- Lower atmosphere has density morethan upper atmosphere.(1) A (2) B (3) C (4) D

125. Assertion : A domestic electrical applianceworking on a three pin, will continue workingeven if the top pin is removedReason: The third pin is used only as a safetydevice.(1) A (2) B (3) C (4) D

126. Assertion :- Compass needle shows magneticmeridian (except magnetic poles).Reason :- Axis of Rotation of earth passesthrough Geographical North-south pole.(1) A (2) B (3) C (4) D

127. Assertion :- Electric potential energy of anypositive charge is always positive.

Reason :- Potential energy is a relative quantity.(1) A (2) B (3) C (4) D

iz'u la

k

121ls180 ds y unsZ'k

izR;sd iz'u esa dFku rFkk

d .

n

x;s gSaA iz'uksa

dks gy djrs le

uhps n

x

pkjks a odYiks a es a

ls lgh odYi dks pq u,A

A.; n dFku

oa

d .

nksuksa lR

gaS rFkk

d .

dFku

dk lgh Li"Vhdj.k gSA

B.; n dFku

oa

d .

nksuksa lR

ga S

ys du

d .

dFku

dk lgh Li"Vhdj.k ugha gSA

C.; n dFku lR

gS

ys du

d .

vlR

gSA

D.dFku o

d .

nksuks a vlR

gSaA

121. dF u:-fo|q r cy js[k k; sa ln So lh/k hoa lrr~gk srh gSA

d . :- fo|qr cy js[kk;sa fo|qrks dkscrkrh gSA

(1) A (2) B (3) C (4) D122. dF u:-nwjn'khZ esa vfHkn`';d ySal dkkjd cM+k gksrk

gSAd . :- vfHkn`';d dkkjd cM+k gksus lsxksyh oxZfoiFku de gks tkrk gSA(1) A (2) B (3) C (4) D

123. dF u:-;fnkzqoksa dh cQZ fi?kyrh gSrks fnu dh yEckbZde gks tk,sxh Ad . :-cQZ fi?kyus ij Hkwejs[kk dh vksj izokfgr gksxhrFkk i`Foh dk tM+Ro vk?kw.kZkVsxkAg i`Foh dskw.kZu dh

vko`fr ckrk gSA(1) A (2) B (3) C (4) D

124. dF u:-lw;Z ds tYnh mxusdk dkj.k iw.kZ vkUrfjd ijkorZugSAd . :-ok;qe.My dsuhpys Lrj dkkuRo ijh Lrjds kuRo ls T;knk gksrk gSA(1) A (2) B (3) C (4) D

125. dF u :,dkjsyw oS|qrqf3-fiu ij dk;Z dj jghgS fn mijh fiu dksgVk fn;k tkrks Hkh oS|qrqf dk;Zdjrh jgsxhA

d . : rhljh fiu lqj{kk dh n`f"V lsyxkbZ tkrh gSA(1) A (2) B (3) C (4) D

126. dF u:-dEikl lqbZ pqEcdh ke;kskj dks iznf'kZr djrhgSApqEcdh kzqoksa dksNksM dj)Ad . :-i`Foh dkkw.kZu v{k HkkSxksfyd mkj&nf{k.k kzqolsxqtjrk gSA(1) A (2) B (3) C (4) D

127. dF u:-fdlhkukRed vkos'k dh fo|qr fLFkfrt tkZges'kk kukRed gksrh gSAd . :-fLFkfrt tkZd lkis{k jkf'k gSA(1) A (2) B (3) C (4) D

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128. Assertion :A particle executing SHM takes lesstime to travel distance from x = 0 to x = A/2 as compare to time taken in travelling thedistance from x = A/2 to x = A.

Reason :As the particle comes near to the meanposition of SHM, its velocity increases.

(1) A (2) B (3) C (4) D

129. Assertion :- Soft and hard X-rays differ infrequency as well as in velocity.

Reason :-The penetrating power of hard X-raysis less than the penetrating power of soft X-rays.

(1) A (2) B (3) C (4) D

130. Assert ion :- If mass of the bob of simple

pendulum increases then restoring torqueincreases.Reason :- Restoring torque a mass of bob.

(1) A (2) B (3) C (4) D131. Assertion :- Hydrogen atom consists of only

one electron but its emission spectrum hasmany lines.

Reason :- Only Lyman series is found in theabsorption spectrum of hydrogen atomwhereas in the emission spectrum, all the series

are found.(1) A (2) B (3) C (4) D

132. Assertion :- When range of a projectile ismaximum its angle of projection may be 45or 135Reason :- Whether q is 45 or 135, value ofrange remains the same, only the sign charges

(1) A (2) B (3) C (4) D133. Assertion :- Radioactivity of 108 undecayed

radioactive nuclei of half life of 50 days is equal

to that of 1.2 10 8 number of undecayednuclei of some other material with half life of60 days

Reason :-Radioactivity is proportional to half-life.(1) A (2) B (3) C (4) D

134. Assertion :- The average and instantaneousvelocities have same value in a uniform motion.Reason :- In uniform motion the velocity ofan object increases uniformly.

(1) A (2) B (3) C (4) D

128. dF u :ljy vk or Z xf r dj jgs d d.k dksx = 0 ls x = A/2 rd tkus esa yxus okyk lex = A/2lsx = Ard tkusesa yxusokyslelsdegksrk gSA

d . :tSls&tSlsd.kSHMdh ekkoLFkk ds fudVigqprk gSmldk osx crk tkrk gSA

(1) A (2) B (3) C (4) D

129. dF u:-e`nqoadBksjX-fdj.ksa vko`fk vkSj osx esad nwljslsvyx gksrh gSaA

d . :-dBksjX-fdj.kksa dh Hksnukerk e`nqX-fdj.kksadhHksnukerk lsde gksrh gSA

(1) A (2) B (3) C (4) D

130. dF u:-;fn ljy yksyd ds xksyd dk O;eku csrks

izR;ku;u cyk?kw.kZ crk gSAd . :-izR;ku;u cyk?kw.kZanksyd dk O;ekuA

(1) A (2) B (3) C (4) D

131. dF u:-gkbMkstu ijek.kq esadsoyd bysDVkWu gksrk gSijUrq

bldsmRltZu LisDVe esa dbZ js[kk;sa gksrh gSA

d . :-gkbMkstu ijek.kq ds vo'kks"k.k LisDVe esa dsoy

ykbeu Js.kh izkIr gksrh gStcfd mRltZu LisDVe esa lHkh

Jsf.k;k izkIr gksrh gSA

(1) A (2) B (3) C (4) D

132. dF u :-tc iz{ksI dh ijkl vf/kdre gksrh gS bldsiz{ksi.k dks.k 45 vFkok 135 gksrs gSAd . :- ;fnq = 45 vFkok 135 gks ijkl dkeku leku jgrk gS rFkk dsoy fpUg~ esa vUrj vkrkgSA(1) A (2) B (3) C (4) D

133. dF u:- vZ vk;q50fnu okys108vfo?kfVr jsfM;kslf

ukf Hkdk sa dh jsfM;k slf;rk vZ&vk; q 60 fnu oky s

1.2 108vfo?kfVr vU jsfM;k slf ukfHkdk sa dh

lf;rk ds rqYgSA

d . :-jsfM;kslf;rk vZ&vk;qdsvuqekuqikrh gksrh gSA

(1) A (2) B (3) C (4) D

134. dF u:-,d leku xfr esa vkSlroa rkR{kf.kd osxksa dsleku eku gksrs gSAd . :-,d leku xfr esa oLrq dk osxdlekuilscrk gSA

(1) A (2) B (3) C (4) D

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135. Assertion :-An adiabitic curve is steeper thanan isothermal curve.

Reason :- In an adiabatic process, change ininternal energy is equal to work done on or

by the gas.(1) A (2) B (3) C (4) D

136. Assertion :- According to Newton's third law"to each action there is equal and oppositereaction".

Reason :- Action is the cause and reaction isits effect.

(1) A (2) B (3) C (4) D

137. Assertion :- In pressure-temperature (P-T)

phase diagram of water, the slope of meltingcurve is found to be negative.

Reason :- Ice contracts on melting.

(1) A (2) B (3) C (4) D

138. Assertion :- Inertia is the property by virtue ofwhich the body is unable to change by itselfthe state of rest only.Reason :- In uniform circular motion velocityremains constant.

(1) A (2) B (3) C (4) D139. Assertion :- In generator when we rotate a coilin magnetic field we get electrical energy.Reason :- Magnetic energy converts intoelectrical energy in this case

(1) A (2) B (3) C (4) D140. Assertion :- If momentum of a body is increases

by 50%. Its kinetic energy is increased by125%.Reason :- Kinetic energy is proportional to

square of velocity.(1) A (2) B (3) C (4) D141. Assertion :-Glucose and fructose are functional

isomers of each otherReason :-Glucose is aldehydic sugar with 6Cwhile fructose is ketonic sugar with 6C(1) A (2) B (3) C (4) D

142. Assertion :- In 1 mol of H2SO4 solution thenumber of equivalent of H+ is equal to number

of equivalent of 24SO

Reason :-The ions follows law of equivalence(1) A (2) B (3) C (4) D

135. dF u:-,dks"e od lerkiho lsvf/kdkM+kgksrk gSA

d . :-:ks"e ize esa xSl ijkkjk fd;k x;kdk; Z vk Ur fjd t k Z es a ifjorZ u ds cjk cj gk sr h

gSA(1) A (2) B (3) C (4) D

136. dF u:-U;wVu dsrhljsfu;e dsvuqlkj ^^izR;sd f;k

dh lekuoa foijhr izfr;k gksrh gS**

d . :- f;k dkj. k gS oa iz frf; k mldk

izHkkoA

(1) A (2) B (3) C (4) D

137. dF u :-ikuh dk nkc&rkieku(PT) voLFkk o eas

xyu o dkky .kkRed gksrk gSA

d . :-fi?kyus ij cQZ fldqM+rh g SA

(1) A (2) B (3) C (4) D

138. dF u :-tM+Ro oLrq dk og xq.k gS ftldsdkj.k oLrqdsoy viuh fojkekoLFkk esa ifjorZu djusesa vleFkZ gksrhgSAd . :- ,d leku o`k h xfr esa osx fu;r gk srkgSA

(1) A (2) B (3) C (4) D139. dF u:-tfuesa tc ge dq.Myh dkspqEcdh ksesa?kqekrs gSrks fo|qr tkZ izkIr gksrh gSAd . :-bl fLFkfr esapqEcdhtkZfo|qr tkZesaifjofrZrgkstkrh gSA(1) A (2) B (3) C (4) D

140. dF u:-;fn fdlh oLrqdslaosx esa50%dh of gksrh

gS rks mldh xfrt esa 125%dh o`f gksrh gSA

d . :-xfrt tkZ osx ds oxZ dsvuqekuqikrh gksrh

gSA(1) A (2) B (3) C (4) D

141. dF u :-Xywdksloa DVk sld nwljs ds f;kRedleko;oh gksrsgSd . :-Xywdksl6C;qDrfYMgkbfMd 'kdZjk gStcfdDVksl6C;qDr dhVksuhd 'kdZjk gksrh gS(1) A (2) B (3) C (4) D

142. dF u:-1eksyH2SO4foy;u esaH+dsrqY;kadksa dh lak

24SO ds rqY;kadksa dh lak ds leku gSA

d . :-vk;uksa dh lak rqY;rk ds fu;e dk vuqlj.k

djrs gSA(1) A (2) B (3) C (4) D

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143. Assertion :-O

O

D+

(Major)

Reason :-

2-Butene is more stable than1-butene as it having more a a H

(1) A (2) B (3) C (4) D

144. Assertion :- 2.5 mol NaCl and 5 mol glucosehave same colligative properties.Reason :- Colligative properties depends onnumber of particle of solute.(1) A (2) B (3) C (4) D

145. Assertion :-Ethyl acetate is more reactive thanacetamide towards nucleophilic substitution

reaction.

Reason :-2NH

1

ion is less basic than RO1ion

(1) A (2) B (3) C (4) D146. Assertion :-A particle present at corner of the

unit cell contributes its1

th8

part to the unit cell.

Reason :- In any space lattice, the corner ofthe unit cell is always shared by the eight

unit cells.(1) A (2) B (3) C (4) D147. As se rt ion :- The OH group attached to

benzene ring activates it towards electrophillicsubstitutionRea son :- The OH group is an electron-releasing group(1) A (2) B (3) C (4) D

148. As se rt ion :- If KC > 103 then products

predominate over reactants.Reason :- Large value of K indicates that

products are less stable.(1) A (2) B (3) C (4) D

149. As se rt ion :- p-nitrophenol boil at hightemperature than o-nitrophenol

Reason :- In p-nitrophenol, the OH group ofone molecule forms hydrogen bond with theNO2 group of the other molecule

(1) A (2) B (3) C (4) D

150. Assertion :- PbI4 is a Stable compound.Reason :- Iodide stabilizes higher oxidation

state.(1) A (2) B (3) C (4) D

143. dF u :-O

O

D+

( )e q

d . :-

vf/kda Hgksusds dkj.k2-C;wVhu 1-C;wVhuls vf/kd LFkk;h gksrh gS(1) A (2) B (3) C (4) D

144. dF u :- 2.5 ek sy NaCl vkSj5 ek sy Xy wdkst dhv.kqlad xq.k/keZ leku gksxsaAd . :-v.kqlad xq.k/keZ foys ds d.kksa dh lakij fuHkZj djrk gSA(1) A (2) B (3) C (4) D

145. dF u:-ukfHkd LUksgh izfrLFkkiu vfHkf;k esafFky,flVsV,flVkekbM dh rqyuk esa vf/kd f;k'khy gSA

d . :-2NH

1

vk;uRO1dh rqyuk esa dekkjhgksrk

gS(1) A (2) B (3) C (4) D

146. dF u:-,d vUrdsfUr bdkbZ dksf'kdk dsdksuksa ij fLFkr

ijek.kq dk izfr bdkbZ dksf'kdk esaksxnku1

8gksrk gSA

d . :-fdlh Hkh tkyd lajpuk esa bdkbZ dksf'kdk ds dksusij fLFkr ijek.kq ges'kkbdkbZ dksf'kdk esaksxnku djrk

gSA(1) A (2) B (3) C (4) D

147. dF u :-casthu oy ij fLFkrOH lewg oy dks

bysDVkuLusgh izfrLFkkiu dsfy;s lfcukrk gS

d . :- OH lewg d bysDVkWu fod"khZ lewg gS

(1) A (2) B (3) C (4) D

148. dF u:-;fnKC> 103gksrksmRikn vfHkdeZdksa dsvis{kk

vf/kd gksrsgSAd . :-Kdk vf/kd eku n'kkZrk gSdh mRikn de LFkk;h

gSA(1) A (2) B (3) C (4) D

149. dF u:-p-ukbVksQhukWyo-ukbVksQhukWy dh rqyuk esa mPp

rki ij mcyrk gS

d . :-p-ukbVksQhukWy esa d v.kq dkOHlewg nwljs

v.kq dsNO2lewg dslkFkH-ca/k cukrk gS

(1) A (2) B (3) C (4) D

150. dF u :- PbI4d LFkk;hkSfxd gSAd . :- vk;ksMkbMmPp vkWDlhdj.k voLFkk dks LFkk;h

j[krk gSA(1) A (2) B (3) C (4) D

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151. Assertion :- Chloral is more reactive thanformaldehyde towards NAR

Reason :- IUPAC name of chloral istrichloronitromethane

(1) A (2) B (3) C (4) D152. Assertion :- SiF6

2 is known but SiCl62 is not.

Reason :- Size of F is small and the ion pairof electron present interact with d orbital of Sistrongly.(1) A (2) B (3) C (4) D

153. As se rt ion :- CH3I is less reactive than

CH3F

Reason :- The bond dissociation energy of

CI is greater than CF(1) A (2) B (3) C (4) D154. Assertion :- SeCl4 does not have a tetrahydral

shape.Reason :- Se in SeCl4 has two lone pairs ofelectrons.(1) A (2) B (3) C (4) D

155. Assertion :- heat of neutralization of HF(aq.)and NaOH is less than 13.7 kcal. in anexothermic reaction.

Reason :- Some heat is used for ionization ofweak acid.

(1) A (2) B (3) C (4) D

156. Assertion :- Trans-[COCl2(en)2]+ is optically

active.

Reason :- It is an octahydral complex.

(1) A (2) B (3) C (4) D

157. Assertion :-Physiosorption is a multilayeredprocess.

Reason :- It is non specific in nature.(1) A (2) B (3) C (4) D

158. Assertion :- In aqueous solution, Mohr's saltgives NH+4, Fe

+2 and SO42 ions.

Reason :- It is a double salt.

(1) A (2) B (3) C (4) D

159. Assertion :- 1 amu is equal toA

1N

g

Reason :- It is known as unified(1) A (2) B (3) C (4) D

151. dF u:-NARdsfy;s DyksjyQkesZfYMgkbM dh rqyuk

esa vf/kd f;k'khy gksrk gS

d . :-Dyksjy dkIUPACuke VkbDyksjksukbVksesFksu gksrk

gS

(1) A (2) B (3) C (4) D152. dF u:- SiF6

2Kkr gSijUrqSiCl62 ughaA

d . :-Fvkdkj NksVk gSrFkkSidsfjDrd-d{kd ds

lkFk blds lpizcy vUrfZ;k djrsgSA

(1) A (2) B (3) C (4) D

153. dF u:-CH3I, CH3Fdh rqyuk esa de f;k'khy gksrk

gS

d . :-CIdh ca/k fo;kstu tkZCFlsvf/kd gksrh

gS(1) A (2) B (3) C (4) D

154. dF u :- SeCl4dh vkfr prq"Qydh ugh a gksrhgSAd . :-SeCl4esaSedsikl nksdkadh bysDVkWuqXegSA(1) A (2) B (3) C (4) D

155. dF u:-NaOH vkSjHF(aq.)dh mnklhuhdj.k "ekdk eku13.7 kcal.lsde gksrk gStksfdd "ekksihvfHkf;k gSA

d . :-nqcZy vEy ds vk;uhdj.k esa dqN "ekkpZgkstkrh gSA

(1) A (2) B (3) C (4) D

156. dF u :- foi{ k-[COCl2(en)2]+ izdkf'kd lf

gSA

d . :-;g d v"VQydh ladqy gSA

(1) A (2) B (3) C (4) D

157. dF u:-HkkSfrd vf/k'kks"k.kd cgqirhZ vf/k'kks"k.k gSA

d . :- HkkSfrd vf/k'kk s"k.k fof'k"V izfr dk ugha

gSA(1) A (2) B (3) C (4) D

158. dF u:-tyhfoy;u esa eksgj yo.kNH+4, Fe+2rFkk

SO42vk;u nsrk gSA

d . :- ;g d f}d yo.k gSA

(1) A (2) B (3) C (4) D

159. dF u :-1 amu ;A

1N

gds leku gSA

d . :-1 amudks ghwuhQkbM ds uke ls tkursgSA(1) A (2) B (3) C (4) D

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160. Assertion :- The inner transition elements areplaced in III B group.

Reason :- The most stable oxidation state ofinner transition elements is +3.

(1) A (2) B (3) C (4) D161. As se rt ion :- Like growth in plants,

differentiation is also open.

Reason :- In plants meristematic cell productscan take part in determinate or indeterminategrowth.

(1) A (2) B (3) C (4) D

162. Assertion : Plant having odd number of setsof chromosomes are fertile.

Reason : Plant having even number of sets ofchromosomes are sterile.

(1) A (2) B (3) C (4) D

163. As se rtion :- All the cofactors are alwayscoenzymes.

Reason :- Cofactors are always nonproteinaceous organic substanes which regulatecatalytic activity of an enzyme.

(1) A (2) B (3) C (4) D

164. Assertion : Colchicine induces polyploidy.Reason : Colchicine causes disjuncton ofchromosomes.

(1) A (2) B (3) C (4) D

165. Assertion :-Sporophyte of mosses is partialparasite over gametophyte.

Reason :- Sporophyte of mosses is ofphotosynthetic nature but absorbs water andminerals from gametophyte.

(1) A (2) B (3) C (4) D166. Assertion :Change in structure of chromosome

is called chromosomal aberration.

Reason : Substitution is an example ofchromosomal aberration

(1) A (2) B (3) C (4) D

167. Assertion :-Protists can reproduce sexually ascompared to monerans.

Reason :-In Protists well developed and distinct

sex organs are present.(1) A (2) B (3) C (4) D

160. dF u:- vUrlae.k rRoksa dksIII BoxZ esa j[kk x;kgSA

d . :- vUrlae.k rRoksa dh LFkk;h vkWDlhdj.k voLFkk+3 gksrh gSA

(1) A (2) B (3) C (4) D161. dF u:-ikniksa esa o`f dh rjg ghfoHksnu Hkhkqys izdkj

dk gksrk gSA

d . :- ikni ks a es a foH kT; k srd dk sf 'kdk dsmRikn fu/kkZfjr vFkok vfu/kkZfjr o`f esa Hkkx ys ldrsgSA

(1) A (2) B (3) C (4) D

162. dF u:fo"ke lak okysxw.klw=h lsV j[kusokys iknituu{ke gksrsgaSA

d . :le lak okysxw.klw=h lsV j[kusokysikni cagksrsgSaA

(1) A (2) B (3) C (4) D

163. dF u :-lHkh lg dkjd lnSo dks,Utkbe gksrs gSA

d . :- lg dkjd ln So vi zk sV huh izfr dsdkc Zf ud jl k;u gks rs gS a tk s d Utk bedh mRi z sjdh f; k'k hyrk dk s fu/ k k Zf jr djr sgSA

(1) A (2) B (3) C (4) D

164. dF u:dksYphlhu cgqxq.khrk izsfjr djrk gSAd . :dksYphlhu xw.klw=ksa dk foikVu djrk gSA

(1) A (2) B (3) C (4) D

165. dF u:-ekWl dk chtk.kqn~fHknqXedksn~fHkn ij vkaf'kdijthoh gksrk gSA

d . :-ekWl dk chtk.kqn~fHkn izdk'kla'ys"kh izdfr dk gksrkgSysfdu ty o feujy dksqXedksn~fHkn ls vo'kksf"kr djrkgSA

(1) A (2) B (3) C (4) D166. dF u:xw.klw=ksa dh ljapuk esaifjorZu gksuk xw.klw=h foiFku

dgykrk gSA

d . : izfrLFkkiu xw.klw=h foiFku dk mnkgj.k gksrkgSA

(1) A (2) B (3) C (4) D

167. dF u:-izksfVLVk eksusjk dh rqyuk esa ySafxd tuukjk tuudj ldrsgSaA

d . :-izksfVLVk esa vR;f/kd fodflr o Li"V ySafxd vax

ik;stkrsgSaA(1) A (2) B (3) C (4) D

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168. Assertion :-The morphological and anatomicalfeature of parasites are greatly simplified ofparasite while emphasising their reproductivepotential

Reason :-The life cycles of endoparasites aremore complex(1) A (2) B (3) C (4) D

169. Assertion :- Many cnidarians like polyps giverise to medusae by vegetative budding.Reason :- Many cnidarians like Obelia passthrough both polyp and medusae.

(1) A (2) B (3) C (4) D170. Assertion :-The evoluton of the flower and its

pollinator species are tightly linked with one

another there is a tight one to one relationship.Reason :-The mutually beneficial system is safeguarded against cheaters.(1) A (2) B (3) C (4) D

171. As se rt ion :- In Ant irrhinu m incompletedominance is found.Reason :-Heterozygous red [Rr] flowered plant,when crossed with white [rr] flowered plant,produces all pink flowered offsprings.

(1) A (2) B (3) C (4) D

172. Assertion :-Diabetes insipidus is marked byexcessive urination and too much thirst forwater.

Reason :- Anti-diuretic hormone (ADH) issecreted by the posterior lobe of pituitary gland.

(1) A (2) B (3) C (4) D

173. As se rt ion :- Citric acid is obtained fromAcetobacter.

Reason :- By fermentation of acetaldehyde,

Acetobacter produces citric acid.(1) A (2) B (3) C (4) D

174. Assertion :- Piameter forms telochoroidea, inventricle.

Reason :-Piameter is highly vascular.(1) A (2) B (3) C (4) D

175. Assertion :-Frog will die in few days if it isstopped forcibly to come on the surface ofwater.Reason :-Frog will unable to respire or feed

properly.(1) A (2) B (3) C (4) D

168. dF u:-ijthfo;ksa ds vkdkfjdhrFkk 'kkdkfjd y{k.k

vR;f/kd ljyhd`r gSatcdh mudh tuukerk vf/kd gSaA

d . :-vUrijthfo;k dk thou p vR;f/kd tfVy

gksxkA

(1) A (2) B (3) C (4) D

169. dF u:-dbZ fuMsfj;utSls iksfyi dkf;d tuukjk esMqqlkmRiUu djrk gSAd . :-dbZ fuMsfj;utSlsvkscsfy;kikfyi o esMqlk nksuksavoLFkkvksa lsxqtjrk gSA(1) A (2) B (3) C (4) D

170. dF u:-iq"i vkSj blds ijkx.kdkjh tkfr;ksa dsfodkld

nwljslsetcwrh lstqMsgq,sgSaA

d . :-ijLij ykHkdkjh rFkkkks[ksckth ls j{kk dsfy

gksrk gSaA

(1) A (2) B (3) C (4) D

171. dF u:-Antirrhinumesa viw.kZ izHkkfork ikbZ tkrh gSA

d . :-fo"ke;qXeh yky[Rr]iq"i okys ikni dk tc

lQsn iq"i[rr]okysikni ls kWl fd;k tkrk gStks lkjh

larfr;k xqykch iq"i okyh mRiUu gksrh gS

(1) A (2) B (3) C (4) D

172. dF u

:-Mk;fcVht buflfiMl dhkkl igpku gSfdblesa T;knk is'kkc vkrk gSvkSj ikuh dh I;kl cgqr yxrhgSAd . :-ADHdk L=ko.k ih;w"k xzafFk dh i'p ikfy lsgksrk gSA(1) A (2) B (3) C (4) D

173. dF u:-flVhd vEylhVkscSDVj lsizkIr fd;k tkrk gS

d . :-,lhVkscSDVjlhVYMhgkbM ds fd.oukjk flVhd

vEy mRiUu djrk gS

(1) A (2) B (3) C (4) D

174. dF u :-ik;ehVj fuyesa VhyksksjksMh;k cukrh gSA

d . :-ik;ehVj vf/kd laoguhgksrh gSA

(1) A (2) B (3) C (4) D

175. dF u:-;fn esad dks cyiwoZd ty dslrg ij vkusls

jksd fn;k tk;srks dqN fnuksa esa bldh e`R;q gkstk,xhA

d . :-esad lkekU i ls'oluk Hkkstu ugha dj

ik;sxkA(1) A (2) B (3) C (4) D

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176. Assertion :-The anatomical setup of lungs inthorax in such that any change in the volumeof the thoracic cavity will be reflected in thelung (pulmonary) cavity.

Reason :- We cannot directly alter thepulmonary volume.

(1) A (2) B (3) C (4) D

177. Assertion :- Genetically similar type of plantsare formed in apomixis.

Reason :- A population of plants producedfrom single parent is called ramet .

(1) A (2) B (3) C (4) D

178. Assertion :-A fall in glomerular blood flow canactivate the JG cells to release renin.

Reason :- Angiotensin II, decreases theglomerular blood pressure and thereby GFR.

(1) A (2) B (3) C (4) D

179. Assertion : T

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