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Algebra 2 Solution Key • Chapter 7, page 190
CHECK YOUR READINESS page 372
1. (3y - 2)(y - 4) = 3y2- 12y - 2y + 8 =
3y2- 14y + 8 2. (7a + 10)(7a - 10) =
49a2- 70a + 70a - 100 = 49a2
- 1003. (x - 3)(x + 6)(x + 1) =(x - 3)(x2
+ 7x + 6) = x3+ 7x2
+ 6x -
3x2- 21x - 18 = x3
+ 4x2- 15x - 18
4. (3x3)2= 32(x3)2
= 9x6 5. (2b-2)(4b5) = 8b3
6. (xy-3)2= x2(y-3)2
= x2y-6=
7. = 6a2a4= 6a6 8. =
9. x2- 5x - 14 = 0; (x - 7)(x + 2) = 0;
x - 7 = 0 or x + 2 = 0; x = 7 or x = -210. 2x2
- 11x + 15 = 0; (2x - 5)(x - 3) = 0;
2x - 5 = 0 or x - 3 = 0; x = or x = 3 11. 3x2+
10x - 8 = 0; (3x - 2)(x + 4) = 0; 3x - 2 = 0 or x +
4 = 0; x = or x = -4 12. 12x2- 12x + 3 = 0;
4x2- 4x + 1 = 0; (2x - 1)2
= 0; 2x - 1 = 0; x =
13. 8x2- 98 = 0; 4x2
- 49 = 0; (2x - 7)(2x + 7) = 0;
2x - 7 = 0 or 2x + 7 = 0; x = or x = -
14. x4- 14x2
+ 49 = 0; (x2- 7)2
= 0; x2- 7 = 0;
x2= 7; x = 4 � 42.65 15. domain {1, 2, 3, 4},
range {2, 3, 4, 5} 16. domain {1, 2, 3, 4}, range {2}17. domain {all real numbers}, range {all real numbers} 18. domain {all real numbers}, range {all real numbers � 3}19. y = 2x2
- 4 20. y = -3(x2+ 1)
21. y = (x - 3)2+ 1 22. y = -(x + 4)2
- 512
!7
72
72
12
23
52
23ab6
4ab23
6a2b318a2
3a24
x2
y6
23. y = (x + 2)2- 1 24. y = 7 - (5 - x)2
ALGEBRA I REVIEW page 374
1. (3a2)(4a6) = 3(4)a2+ 6= 12a8
2. (-4x2)(-2x-2) = -4(-2)x2- 2= 8x0
= 8(1) = 83. (4x3y5)2
= 42(x3)2(y5)2= 16x6y10 4. (2x-5y4)3
=
23(x-5)3(y4)3= 8x-15y12
= 5. = 4a5- 2=
4a3 6. = 2x7- (-1)y5= 2x8y5 7. =
8. = = 9. (-6m2n2)(3mn) =
-6(3)m2+ 1n2+ 1= -18m3n3 10. (3x4y5)-3
=
= = 11. =
= = 12. x5(2x)3= x5(23)(x3) =
8x5+ 3= 8x8 13. = x4- 2- (-5)
= x7
14. = = = 18y5
15. (4p2q)(p2q3) = 4p2+2q1+3= 4p4q4 16. =
2x3- 1= 2x2 17. (p2)-2
= p-4= 18. =
-5x4-1= -5x3 19. = r2-2 s3-4 t4- (-4)
=
r0 s-1 t8= 20. ? = = 3x2
21. (s2t)3(st) = (s2)3(t3)(st) = s6 t3st = s6+ 1 t3+1=
s7t4 22. (3x-3y-2)-2= 3-2(x-3)-2(y-2)-2
=
x6y4= 23. (h4k5)0
= 1 24. ? =
r3- 1 s2+ 1 t3- 1= r2s3t2 25. Answers may vary.
Sample: 150= 1; = 45- 3
= 42= 16; (2 ? 5)2
=
22 ? 52= 4 ? 25 = 100; = ; 23 ? 25
= 23+ 5=
28; 4-3= = ; (32)3
= 32 ?3= 36
= 729. In (ab)m=
164
143
25
35Q23R5
45
43
sr3
ts2t3
rx6y4
9132
6x2y2
2y26xy2
xy2
2t8
s
r2s3t4
r2s4t24
215x4
3x1
p4
4x3
2x
144x4y12
8x4y7122(x2)2(y6)2
8x4y7(12x2y6)2
8x4y7
x4x22
x25
r8s5
r23s5
222r2s24t0
2rs
(2r21s2t0)22
2rs1
27x12y151
33(x4)3(y5)31
(3x4y5)3
9x4
432(x2)2
22Q3x2
2 R2
12xy5
(4x2)0
2xy56x7y5
3x21
8a5
2a28y12
x15
14
Chapter
7Radical Functions and Rational Exponents pages 372–435
�2 21Ox
y
2
�4
�2 2Oxy
�12
2 4Ox
y12
4
�2�4�6 O xy
�4
�8
�2�6 Ox
y
2
4 6Ox
y
6
4
2
ambm and = , the exponent is distributed to
both factors and to both the numerator and thedenominator.
7-1 Roots and Radical Expressionspages 375–379
Check Skills You’ll Need For complete solutions seeDaily Skills Check and Lesson Quiz Transparencies orPresentation CD-ROM. 1. 52 2. 0.32
3. 4. (x5)2 5. (x2y)2 6. (13x3y6)2
CA Standards Check pp. 376–377 1a. Since 05= 0,
the fifth root of 0 is 0; since (-1)5= -1, the fifth root
of -1 is -1; since 25= 32, the fifth root of 32 is 2.
1b. Since 0.012= 0.0001 and (-0.01)2
= 0.0001, thesquare roots of 0.0001 are 0.01 and -0.01; -1 has no
real square root; since = and = ,
the square roots of are and . 2a. =
= -3 2b. = = 3 2c. =
= 7 3a. = = =
2 Δx« y2 3b. = = =
-3c2 3c. = = =
x2Δy3
« 4a. w = ; 3 = ; d3= 12; d = � 2.29;
2.29 in. 4b. w = ; 5.5 = ; d3= 22; d = �
2.80; 2.80 in. 4c. w = ; 6.25 = ; d3= 25;
d = � 2.92; 2.92 in.
Exercises pp. 378–379 1. 152= 225 and (-15)2
=
225; square roots of 225 are 15 and -15 2. (0.07)2=
0.0049 and (-0.07)2= 0.0049; square roots of 0.0049
are 0.07 and -0.07 3. has no real square roots
4. = and = ; square roots of
are and 5. (-4)3= -64; the cube root of -64
is -4 6. (0.5)3= 0.125; the cube root of 0.125 is 0.5
7. = ; the cube root of is , or
8. (0.07)3= 0.000343; the cube root of 0.000343 is 0.07
9. 24= 16 and (-2)4
= 16; the fourth roots of 16 are 2and -2 10. -16 has no real fourth roots 11. 0.34
=
0.0081 and (-0.3)4= 0.0081; the fourth roots of 0.0081
are 0.3 and -0.3 12. = and =
; the fourth roots of are and
13. = = 6 14. = - = -6
15. ; no real root 16. = = 0.6
17. - = - = -4 18. = =
-4 19. - = - = -3 20. ; no real
root 21. = = = 4Δx«
22. = = = 0.5Δx3«"(0.5x3)2"0.52(x3)2"0.25x6
"(4x)2"42x2"16x2
"4 281"4 34"4 81
"3 (24)3!3264"3 43!3 64
"0.62!0.36!236
"622!36"62!36
2103
103
10,00081
10,00081
Q2103 R
410,00081Q10
3 R4
21223
62 272162 27
216Q236R
3
2 813
813
64169
64169Q2 8
13R264
169Q 813R
2
2 1121
!3 25
d3
4d3
4
!3 22d3
4d3
4
!3 12d3
4d3
4
"4 (x2y3)4"4 (x2)4(y3)4"4 x8y12
"3 (23c2)3"3 (23)3(c2)3"3 227c6
"(2xy2)2"22x2(y2)2"4x2y4"72
!49"4 34!4 81"3 (23)3
!32272 611
611
36121
36121Q2
611R
236121Q 6
11R2
Q27R2
am
bmQabRm
23. = = = x4Δy9
«
24. = = = 8b24
25. = = = -4a
26. = = = 3y2
27. = = = x2Δy3
«
28. = = = 2y2
29. V = pr3; 3V = 4pr3; r3= ; r = ; r =
� 1.34; 1.34 in. 30. r = � 1.68; 1.68 ft
31. r = � 0.48; 0.48 cm 32. r = �
0.08; 0.08 mm 33. x2= 100; 102
= 100 and (-10)2=
100, so x = 10,-10 34. x4= 1; 14
= 1 and (-1)4= 1,
so x = 1,-1 35. x2= 0.25; 0.52
= 0.25 and (-0.5)2=
0.25, so x = 0.5, -0.5 36. x4= ; = and
= , so x = ,- 37. = = -4;
- = - = -(-4) = 4; = = 8;
= = 2; from least to greatest: , ,
- , 38a. K = 1.35 ; 8 = 1.35 ; =
; L = � 35; about 35 ft 38b. K = 1.35 ;
10 = 1.35 ; = ; L = � 55; 55 - 35 =
20; about 20 ft longer 39. = = 0.5
40. = = = 41. =
= 0.2 42. = = 43. =
= 2Δc« 44. = =
3xy2 45. = =
12y2z2ΔxΔ 46. = = y4
47. = = -y4 48. =
= k3 49. = = -k3
50. = Δx + 3« 51. =
= (x + 1)2 52. = Δx«
53. = = x2 54. = =
Δx3« 55. Answers may vary. Sample: ,
- , 56a. true for all positive integers56b. true for all odd positive integers 57. yes,
because 10 is really 101 58. = x2, true for all
values of x, because x2 is always positive 59. =
x3, true for some values of x: x � 0 60. = x2,
true for some values of x: x = -1, 0, 1 61. =
Δx«, true for some values of x: x � 0 62. = Δm«
63. = = m2 64. =
= Δm3« 65. = = m4
66. = m 67. = = m2"n (m2)n"n m2n"n mn
"n (m4)n"n m4n"n (m3)n
"n m3n"n (m2)n"n m2n
!n mn
"3 x3
"3 x8"x6
"x4
"5 232x10"4 16x8
"3 28x6
"2n(x3)2n"2n
x6n"2n(x2)2n"2n
x4n
"2nx2n"f(x 1 1)2g2
"(x 1 1)4"(x 1 3)2
"5 (2k3)5"5 2k15"5 (k3)5
"5 k15"5 (2y4)5"5 2y20
"5 (y4)5"5 y20!xz
"xz(12xy2z2)2"144x3y4z5!3 3
"3 3(3xy2)3"3 81x3y6"4 (2c)4
"4 16c414Å
4 Q14R4
Å4 1
256"4 (0.2)4
!4 0.001613
26Å
3 Q26R3
Å3 8
216
"3 0.53!3 0.125
Q 101.35R
2101.35!L!L
!LQ 81.35R
281.35
!L!L!L!64!3264
!6 64!3264"6 26"6 64
"82!64"3 (24)3!3264
"3 (24)3!326423
23
1681Q22
3R4
1681Q23R
41681
Å3 3(0.002)
4pÅ3 3(0.45)
4p
Å3 3(20)
4pÅ3 3(10)
4p
Å3 3V
4p3V4p
43
"(2y2)5"5 25(y2)5"5 32y10
"4 (x2y3)4"4 (x2)4(y3)4"4 x8y12
"3 (3y2)3"3 33(y2)3"3 27y6
"(24a)3"(24)3a3"3 264a3
"(8b24)2"82(b24)2"64b48
"(x4y9)2"(x4)2(y9)2"x8y18
Algebra 2 Solution Key • Chapter 7, page 191
68. = = m3 69. =
= m4 70. = = x3 is true for only
some values of x since the expression is always positive and the expression x3 is sometimes positive andsometimes negative; the answer is B. 71. The realcomponent of point A is located on the horizontal axis;the imaginary component of point A is located on thevertical axis; the real component is 6; the imaginarycomponent is -5i; the point is (6, -5i); the complexnumber is 6 - 5i; the answer is B. 72. Use the formulaV = lwh; V = (x + 1)(x - 2)(x - 5) = (x2
- x - 2) (x - 5) = x3
- 5x2- x2
+ 5x - 2x + 10 = x3- 6x2
+
3x + 10; the answer is D. 73. (x + y)5= x5
+ 5x4y+ 10x3y2
+ 10x2y3+ 5xy4
+ y5 74. (2 - 3y)4= 24
+
4(2)3(-3y) + 6(2)2(-3y)2+ 4(2)(-3y)3
+ (-3y)4=
16 - 96y + 216y2- 216y3
+ 81y4 75. (3x - 5)6=
(3x)6+ 6(3x)5(-5) + 15(3x)4(-5)2
+ 20(3x)3(-5)3+
15(3x)2(-5)4+ 6(3x)(-5)5
+ (-5)6= 729x6
-
7290x5+ 30,375x4
- 67,500x3+ 84,375x2
- 56,250x +
15,625 76. (2a - b)7= (2a)7
+ 7(2a)6(-b) +21(2a)5(-b)2
+ 35(2a)4(-b)3+ 35(2a)3(-b)4
+
21(2a)2(-b)5+ 7(2a)(-b)6
+ (-b)7= 128a7
-
448a6b + 672a5b2- 560a4b3
+ 280a3b4- 84a2b5
+
14ab6- b7 77. y = 4x3
- 49x = x(4x2- 49) =
x(2x - 7)(2x + 7) 78. y = 81x2+ 36x + 4 =
(9x)2+ 2(9x)(2) + 22
= (9x + 2)2 79. y = 4x3+
8x2+ 4x = 4x(x2
+ 2x + 1) = 4x(x + 1)2
80. y = 12x3+ 14x2
+ 2x = 2x(6x2+ 7x + 1) =
2x(6x + 1)(x + 1) 81. y = 3x2- 7 = 3(x - 0)2
- 782. y = -2x2
+ x - 10 = - 10 =
-2 x2- x + - 10 + =
83. y = + 2x - 1 = (x2+ 8x) - 1 =
(x2+ 8x + 16) - 1 - 4 = (x + 4)2
- 5
7-2 Multiplying and Dividing RadicalExpressions pages 380– 385
Check Skills You’ll Need For complete solutions seeDaily Skills Check and Lesson Quiz Transparencies orPresentation CD-ROM. 1. 6 2. 3 3. 34. x2 5. ab 6. 5a3b4
CA Standards Check pp. 380–383 1a. ? =
= = 6 1b. ? = =
= = -3 1c. ? , not possible
2. = = ? =
5x2 ; = = ? =
x 3. 3 ? 2 = 3 ?
2 = 6 =
6 = 6(7x3y) = 42x3y 4a. =
= = 3 4b. = = ="4x3Å
12x4
3x"12x4
!3x!9Å
24327
!243!27
!3!3"3 ? (7x3y)2
"147(x3)2y2"7 ? x3 ? 21 ? x3 ? y2
"21x3y2"7x3!3 18x
!3 18x "3 x3"3 18 ? x ? x3"3 18x4!2
!2"(5x2)2"2 ? 52 ? (x2)2"50x4!4 24!4 4"3 (23)3!3227
!3 3(29)!329!3 3!36!3 ? 12
!12!3
14
14
14
x2
4
2 79822Qx 2 1
4R21
81
16R12Q
22Qx2 2 12xR
"4 x12x
124"4 x12"n (m4)n
"n m4n"n (m3)n"n m3n= 2x 4c. = =
= = 4x3 5a. =
? = 5b. = = ?
= 5c. = = =
= 6. a = ; at2 = d; t2 = ;
t = = ? =
Exercises pp. 383–385 1. =
2.
3.
4. 5. ,
not possible 6. = 5
7. 8.
9.
10.
11.
12. = = ?
= 13. = =
? 14. =
= ? =
15. =
= ? =
16. = =
? = 17. ? =
= = = 18. ?
= = = ?
= 19. ? = =
= ? =
20. ? = =
= 21. ? =
= =
22. ? = =
= 23. = =
= 10 24. = = =
25. = = = 2x2y2
26. = = = 5x"3 x2y2"3 125x5y2
Å3
250x7y3
2x2y"3 250x7y3
"3 2x2y
!2"8x4y4Å
56x5y5
7xy"56x5y5
!7xy
4xyÅ
16x2
y2Å48x3
3xy2"48x3
"3xy2!100
Å50050
!500!50
22x2y!3 30x22"3 30(x2)3 ? xy3
22"3 30x7y32"3 15x5y2"3 2x2y2
30y2!3 2y6"3 53 ? 2 ? (y2)3 ? y6"3 250y7
2"3 50y43"3 5y340xy!320"22 ? 3 ? x2y2
20"12x2y25"6xy24!2x7x3y4!6y
!6y"(7x3y4)2"72 ? 6 ? (x3)2 ? (y4)2 ? y
"294x6y9"42xy9"7x58y3!5y!5y
"(8y3)2"82 ? 5 ? (y3)2 ? y"320y7"40y2
"8y52!3 12"3 23 ? 12!3 96!3 6 ? 16
!3 16!3 62y "4 4x3y2"4 4x3y2"4 (2y)4
"4 24 ? 4 ? x3 ? y4 ? y2"4 64x3y625x2y"3 2y2
"3 2y2"3 (25x2)3"3 (25)3 ? 2 ? (x2)3 ? y3 ? y2
"3 2250x6y510a3b3!2b
!2b"(10a3b3)2"102 ? 2 ? (a3)2 ? (b3)2 ? b
"200a6b73y3!3 2y!3 2y 5"3 (3y3)3
"3 33 ? 2 ? (y3)3 ? y"3 54y102a"3 4a2"3 4a2
"3 (2a)3"3 23 ? 22 ? a3 ? a2"3 32a55x2!2x
5 "(5x2)2 ? !2x 5"50x5 5 "52 ? 2 ? (x2)2 ? x
3"3 3x2"3 33 ? "3 3x2 5"3 81x2 5 "3 33 ? 3 ? x2 5
2x!5x"22 ? 5 ? x2 ? x 5 "(2x)2 ? !5x 5
"20x3 5!3212(218) 5 !3 216 5 6
!3218 5!3212 ?!3 9 ? !3224 5 !32216 5 26
!325 ? !3225 5 !3 125
!25 ? !5!4 32 5 !4 8 ? 32 5 !4 256 5 4!4 8 ?
!3 9 ? !3281 5 !3 9(281) 5 !32729 5 29
!3 4 ? !3 16 5 !3 4 ? 16 5 !3 64 5 4!256 5 16
!8 ? !32 5 !8 ? 32
!daa
!a!a
!d!aÅ
da
da
dt2
"3 18x2
3xÅ3 2 ? (3x)2
3x ? (3x)2
Å3 2
3xÅ3 4
6x!3 4!3 6x
x!5y5y
!5y!5y
"x2
!5yÅ2x3
10xy"2x3
!10xy!35
5!5!5
!7!5
Å75"4 x2"4 44 ? (x3)4 ? x2"4 256x14
Å4 1024x15
4x"4 1024x15
!4 4x!x"22x2 ? x
Algebra 2 Solution Key • Chapter 7, page 192
27. = ? = 28. = ? =
= 29. = ? =
30. = ? 31. =
? 32.
33.
34.
35. F = ;
Fr2= Gm1m2;
36a.
36b. ?
36c. Answers may vary. Sample: First simplify
the denominator. Since = = , to rationalize the denominator, multiply the fraction by
. This yields 37. ?
= = = 10 38. ? =
= 39.
3x6y5
40.
20x2y3 41. ( + 7) =
+ = 10 + 42. 3(5 + ) =
15 + 3 43. ( + ) = + =
5 + 5 44. ? ? = =
= 45.
46.
47.
48.
49.
50.
51. 232 Å
1112x ?
!3x!3x
5Å11x3y12x4y
53"11x3y
22"12x4y5 23
2
"3 2xy2
xy!3 14"3 7x2y
?"3 72xy2
"3 72xy2 5"3 73 ? 2xy2
"3 73x3y3 57"3 2xy2
7xy 5
10"3 5x2 ?
"3 52x"3 52x
5 10!3 25x5x 5 2!3 25x
x"3 3x2
3x
"3 3x2
"3 33x3 51!3 9x
? "3 3x2
"3 3x2 5!7x!7x
5 5!14x3(7x) 5 5!14x
21x
5!23!7x
?!2y!2y
5"10x4y
"4x2y4 5x2!10y
2xy2 5x!10y
2y2
"5x4
"2x2y3 ?"3 27x7 5 "3 33(x2)3x 5 3x2!3 x
"3 3x2 ? "3 x2 ? "3 9x3 52x!3 2"3 23 ? 2 ? x3
"3 16x3"3 2x2!3 4!3 2x!3
!75!25!15!5!5!21
!217!27!2!100
!50!2!y10"22(x2)2(y3)2y 5
5"2xy6 ? 2"2x3y 5 10"4x4y7 5
!2y3"2x12y11 5 3"2(x6)2(y5)2y 5
"x5y5 ? 3"2x7y6 5"3 43 ? 5 5 4!3 5!3 320
!3 80!3 4!2"102 ? 2!200!40
!5!2 ? 2 1 !3 ? 27!2 ? 2
5 2 1 !614 .!2
!2
7!2!2 ? 49!98
!6 1 315
!3!3
5!3(!2 1 !3)
!2255!2 1 !3
!75!6 1 3
15
5!6 1 1575 5!150 1 !225
75 5!75(!2 1 !3)
75 5
!2 1 !3!75
? !75!75
5!Gm1m2F
F
!Gm1m2!F
? !F!F
5
r 5 ÅG1m2
F5r2 5
Gm1m2F
;
Gm1m2
r2x!5y!2
? !2!2
5 x!102yÅ
5x2
2y2 5
Å5x4y2x2y3 5
"5x4y
"2x2y3 5!5y!5y
5!15y
5y!3!5y
?
Å3
5y 5Å3xy2
5xy3 5"3xy2
"5xy3 55x2!55"5x4 5
5Å60x5
12x 515"60x5
3!12x5"4 53
"4 53 5!4 250
5!4 2!4 5
!4 2!4 5
"3 (3x)2
"3 (3x)2 5"3 45x2
3x!3 5!3 3xÅ
3 53x
!3 4x2
"3 22
"3 22!3 x!3 2
!3 x!3 2
!10x4x
!10x"16x2
!2x!2x
!5!8x
!5!8x
!2x2
!2!2
!x!2
!x!2
Algebra 2 Solution Key • Chapter 7, page 193
52. -2( + )= -
53.
54.
55. altitude of 100 mi: v = � 17,498;
altitude of 200 mi: v = � 17,286;
17,498 - 17,286 = 212; about 212 mi/h greater
56.
57. A product of two square roots can be
simplified in this way only if the square roots are real
numbers; and are not. 58. h = 16t2 =
16( )2= 16(18a5) = 288a5; 288a5 ft
59. For some values; it is easy to see that the equation
is true if x = 0 or x = 1. But when x � 0, is not a
real number, although is. 60. Check students’
work. 61. 2xy
62. = 8x3y6; = 2xy2
63. = 20; 64. =
= 65.
66. = =
67.
-a = 2c; a = -2c;
-b = 6d; b = -6d 68. No changes
need to be made; since they are both odd roots, there is no need for absolute value symbols. 69. Use Pascal’striangle to expand (a + b)6; (a + b)6
= a6+ 6a5b +
15a4b2+ 20a3b3
+ 15a2b4+ 6ab5
+ b6; substitute 2a fora and -3b for b into each term; A: 6a5b = 6(2a)5(-3b) =6(32a5)(-3b) = -576a5b; B: 15a4b2
= 15(2a)4(-3b)2=
15(16a4)(9b2) = 2160a4b2; the answer is B.70. The graph of y = 3(x + 3)2
- 2 is a vertical shift 2units down of the graph y = 3(x + 3)2; the answer is A.71. Line 1 has a slope of 1 and a y-intercept of (0, 0);the equation of line 1 is y = x; line 2 has a slope ofand a y-intercept of (0, 3); the equation of line 2 is y = ; write the equations in slope-interceptform; line 1 is y = x and line 2 is 3x + 5y = 15; theanswer is C. 72. Solve the quadratic equation x2
+
3x - 28 = 0 by factoring. x2+ 3x - 28 = 0; (x - 4)
(x + 7) = 0; x = 4 and x = -7; The roots are 4 and -7.The answer is B.
73. = = 11Δa45Δ
74. - = - = -9c24d32
75. = = -4a27
76. = = 2y5 77. ="0.25x6"5 25(y5)5"5 32y25"3 (24)3(a27)3"3 264a81
"92(c24)2(d32)2"81c48d64"112 ? (a45)2"121a90
2 35x 1 3
235
1y6d; 1
y2b 51
y6d;
"yb 5 1y3d; yb 51
x2c; 1x2a 5
1x2c;
"xa 5 1xc; xa 5"6 x4
"6 y3 ?"6 y3
"6 y3 5"6 x4y3
y
Å6 x4
y3Å6
y23
x24Å5
yx4 5
!5 y
"5 x4 ?!5 x!5 x
5!5 xy
x
"5 x24y 51"3 xy2 ?
"3 x2y
"3 x2y5"3 x2y
xyÅ31
xy2
"3 x21y22!20 5 2!5!3 8000
"3 8x3y6"64x6y12
4x2y2; "4x2y2 5"16x4y4 5
"3 x2"x3
"18a5!28!22
20!22 cm25 !8800 5 "202 ? 22 5 20!22; !440 (!20)
Å1.24 3 1012
3950 1 200
Å1.24 3 1012
3950 1 100
!3 2 !2!8
? !2!2
5 !6 2 !4!16
5 !6 2 24
3!5 1 55
3 1 !5!5
? !5!5
55 24!3 4 2 6!3 22"3 33 ? 2
22"3 23 ? 4!3 54!3 3223!33x12x 5 2!33x
4x
= 0.5Δx3Δ 78. =
= x2y5 79 =
= 2Δx9Δy24
80. = = 0.08x20
81. y2- 4y + 16
y3+ 4y2
-4y2+ 0y
-4y2- 16y
16y - 6416y + 64
-128quotient: y2
- 4y + 16, R -128; not a factor
82. x2- 3x + 9
x3+ 3x2
-3x2+ 0x
-3x2- 9x
9x + 279x + 27
0quotient: x2
- 3x + 9; factor
83.
quotient: 3a2- a, R 4; not a factor
84.
quotient: 2x3+ x2
+ 2x, R 10; not a factor
85. 86.
87. 88.
89. 90.
91. 92.
7-3 Binomial Radical Expressions pages 386–390
Check Skills You’ll Need For complete solutions seeDaily Skills Check and Lesson Quiz Transparencies orPresentation CD-ROM. 1. 15x2
+ 2x - 82. -24x2
+ 71x - 35 3. x2- 16 4. 16x2
- 255. x2
+ 10x + 25 6. 4x2- 36x + 81
Q 35(2) R
25 9
100Q2 34(2) R
25 9
64
Q0.32 R
25 (0.15)2 5 0.0225Q2 1
3(2) R25 1
36
Q2112 R2 5 121
4Q112 R
25 121
4
Q2102 R2 5 (25)2 5 25Q10
2 R25 52 5 25
x3 1 0x2
x3 2 2x2
2x2 2 4x 2x2 2 4x 0 1 10
2x3 1 x2 1 2xx 2 2 q 2x4 2 3x3 1 0x2 2 4x 1 10 2x4 2 4x3
22a2 2 a22a2 2 a 0 1 4
3a2 2 a2a 1 1 q 6a3 1 a2 2 a 1 4 6a3 1 3a2
x 1 3qx3 1 0x2 1 0x 1 27
y 1 4qy3 1 0y2 1 0y 2 64
"(0.08)2(x20)2"0.0064x40
"4 24(x9)4(y24)4"4 16x36y96"7 (x2)7(y5)7
"7 x14y35"(0.5)2(x3)2 CA Standards Check pp. 386–388 1a. + =
(2 + 3) = 1b. - ; cannot
combine 1c. + = (4 + 5) =
2. height = 2(6 ) = ; length = 3( ) =18 ; perimeter = 2( + ) = 2(30 ) =60 , or about 84.9 in. 3. + -
5 = + - = +
- = (5 + 12 - 15) =
4. ( - )( - ) = - 2( )( ) +
( ) = 2 - 2 + 3 = 5 - 25. ( + )( - ) = ( )2
- ( )2=
5 - 2 = 3 6. ? =
Exercises pp. 388–390 1. + = (5 + 1) =
= 2. - = (6 - 2) =
3. + ; cannot combine 4. - =
(3 - 5) = -2 5. 14 + ; cannot
combine 6. - = (7 - 2) =
7. + = + = +
= (18 + 15) = 8. -
= - = - =
(28 - 15) 9. + = +
= 3 + 4 = (3 + 4) = 7
10. + = + = 3 +
2 = (3 + 2) = 5 11. 3 - 2 =
3 - 2 = 9 - 6 12. +
= + = 2 + 213. (3 + )(1 + ) = 3 + 3 + 1 + 5 =
8 + 4 14. (2 + )(1 + 3 ) = 2 + 6 +
1 + 21 = 23 + 7 15. (3 - 4 )(5 - 6 ) =15 - 18 - 20 + 48 = 63 - 3816. ( + )2
= ( + )( + ) =3 + 2 + 5 = 8 + 2 17. ( + 6)2
=
( + 6)( + 6) = 13 + 12 + 36 =
49 + 12 18. (2 + 3 )2=
(2 + 3 )(2 + 3 ) = 20 + 12 + 18 =
38 + 12 19. (5 - )(5 + ) =25 - 11 = 14 20. (4 - 2 )(4 + 2 ) =16 - 12 = 4 21. (2 + 8)(2 - 8) = 24 - 64 =
-40 22. ( + )( - ) = 3 - 5 = -223. ? = = =
-2 + 2 24. ? = =
25. ? = =
13 + 7 26. ? = =
= =
27. + + = 6 + 4 + 3 =
(6 + 4 + 3) = 13 28. + 2 - 5 =
5 + 8 - 5 = 8 29. 5 + 4 =!98x!32x!3!3!3!3!3!48!75!2!2
!2!2!2!18!32!72
11 1 8!2214
22 1 16!2228
22 1 8!8228
6 1 8!8 1 164 2 32
2 1 2!82 1 2!8
3 1 !82 2 2!8
!3
10 1 7!3 1 34 2 3
2 1 !32 1 !3
5 1 !32 2 !3
12!3 1 823
12!3 1 827 2 4
3!3 1 23!3 1 2
43!3 2 2
!3
4 2 4!322
4 2 4!31 2 3
1 2 !31 2 !3
41 1 !3
!5!3!5!3!6!6
!3!3!11!11!10!10!2!5!2!5
!2!5!13!13!13!13!13!15!15
!5!3!5!3!5!3!2!2!2
!2!2!7!7!7!7!7!5
!5!5!5!5!4 3!4 2"4 24 ? 3"4 24 ? 2!4 48
!4 32!3 2!3 3"3 33 ? 2"3 33 ? 3
!3 54!3 81!3 2!3 2!3 2
!3 2"3 23 ? 2"3 33 ? 2!3 16!3 54
!2!2!2!2"42 ? 2
"32 ? 2!32!1813!5!5 5
15!528!53"52 ? 514"22 ? 53!125
14!2033!2!215!2
18!23"52 ? 26"32 ? 23!506!18
5"3 x2"3 x22"3 x27"3 x23!y!x!x!x
5!x3!x4!3 34!3
4!3 3!3 32!3 36!3 36!6!6
!6!65!6
39 1 10!1524 1 6!15 1 4!15 1 1516 2 15 5
4 1 !154 1 !15
6 1 !154 2 !15
!2!5!2!5!2!5!6!6!3!3
!3!2!2(!2)!3!2!3!22!2!215!212!2
5!25"32 ? 23"42 ? 2"52 ? 2!18
3!32!50!2!218!212!2!2
6!212!2!29!xy!xy5!xy4!xy
2!3 57!4 55!7!7
3!72!7
Algebra 2 Solution Key • Chapter 7, page 194
20 + 28 = (20 + 28) = 4830. - 4 + 2 = 5 - 12 + 8 =
5 + (-12 + 8) = 5 - 4 31. 4 +
3 = 4(6y) + 3(3y) = 24y + 9y =
(24y + 9y) = 33y 32. 3 - 4 +
= 3(2) - 4(3) + 8 =
(6 - 12 + 8) = -233. ( - )( + 2 ) = 3 + 2 -
- 14 = -11 +
34. (2 + 3 )(5 - 7 ) = 50 - 14 +
15 - 42 = 8 +
35. (1 + )(5 + ) = 5 + + 5 +
= 5 + + 30 + 12 = 17 + 3136. (2 - )(3 + ) = 6 + 2 - 3 -
= 6 + 6 - 21 - 42 = -36 - 1537. ( + )( + 2 ) = x + 2 +
+ 6 = x + 3 + 6 38. (2 - 3 )(4 -
5 ) = 8y - 10 - 12 + 30 = 8y -
22 + 30 39. = ? =
= 40. ?
= =
= =
- 41. ? =
=
= =
42. ? = =
43. ? = =
44. ? = = =
- 45. Golden Ratio = reciprocal
of Golden Ratio = = =
= = = ;
the difference between the Golden Ratio and its
reciprocal = -
= = = 1 46. +
= + possibilities for a: 2(12), 2(22),2(32), . . . ; a must be twice a perfect square.47. Answers may vary. Sample: Without simplifyingfirst, you must estimate three separate square roots, andthen add the estimates. If they are first simplified, thenthey can be combined as 13 Then only one square !2.
!a;6!2
!a!7222
1 1 !5 1 1 2 !52
1 1 !5 2 (21) 2 !52
21 1 !52 ;1 1 !5
2
21 1 !52
1 2 !522
2(1 2 !5)24
2(1 2 !5)1 2 5
2(1 2 !5)(1 1 !5)(1 2 !5)
21 1 !5
1 1 !52 ;!3 122!3 2
8!3 2 2 4!3 124
4!3 16 2 2!3 964
"3 42
"3 424 2 2!3 6!3 4
x 1 5"4 x3
x5"4 x3 1 x
x"4 x3
"4 x35 1 !4 x!4 x
2 1 3!3 42
3!3 4 1 22
"3 22
"3 223 1 !3 2!32
!3 2 !72
22!3 1 4!724
5!3 1 5!7 2 3!7 2 7!324
5!3 1 5!7 2 !63 2 !1473 2 7
!3 1 !7!3 1 !7
5 2 !21!3 2 !7
!22!3
22!3 1 !221
4!2 2 4!3 1 2!3 2 3!221
4!2 2 4!3 1 !12 2 !182 2 3
!2 2 !3!2 2 !3
4 1 !6!2 1 !3
89 1 42!32239
8 1 36!3 1 6!3 1 814 2 243
2 1 9!32 1 9!3
4 1 3!32 2 9!3
4 1 !272 2 3!27
!2y
!2y!2y!2!y!2!y!3x!3x
!3x!3!x!3!x!2!2!2!1764
!98!18!18!98!2!2!2!144
!72!2!2!72!10!10
!10!2!5!2!5!21!21
!21!7!3!7!3!3 2!3 2
!3 2!3 2!3 2!3 128
!3 54!3 16!6!6!6!6!6!6"54y2
"216y2!2!3!2!3!2!2!3!32!18!75
!2x!2x!2x!2x root need be estimated. 48. d = rt; t = =
= = = , or
about 4.53 s 49. Answers may vary. Sample: ( + 2)( )(2 + )(2 - ) 50. A = /w;A = (3 + )x(1 + 2 )y = (3x + x)(y + 2 y)= 3xy + 6 xy + xy + 10xy = 13xy + 7 xy =
(13 + 7 )xy = the answer is D.
51. + = +
= = = -
52. - = -
= =
= 4 53. (a = 0 and b � 0) or (b = 0 and a � 0) 54. In the second step the exponentwas incorrectly distributed: (a - b)x 2 ax
- bx.55a. m and n can be any positive integers. 55b. m mustbe even or n must be odd. 55c. m must be even, and ncan be any positive integer. 56. = = |x| is truefor all values of x since the expression is alwayspositive and the expression |x| is always positive; theanswer is A. 57. (8 - 5i)2
= (8 - 5i)(8 - 5i) = 64 -80i + 25i2 = 64 - 80i + 25(-1) = 64 - 80i - 25 = 39- 80i; the answer is B. 58. Find factors with product4(-4) = -16 and sum 15: 16 and -1; 4x2
+ 16x - x -4; 4x(x + 4) - 1(x + 4); (x + 4)(4x - 1); the answer is D.59. The x-coordinate of the vertex = = =
-8; the y-coordinate of the vertex is y = -(-8)2-
16(-8) - 62, y = 2; the vertex is (-8, 2); the vertex liesin the second quadrant; the answer is C.
60. ? = = = 361. ? = = x
62. = = = 4 63. = =
= = 64. ? = =
= 2x 65. ? = = 7x2
66. = = ? =
67. ? = 68. 2x3- 16 =
0; x3- 8 = 0; x3
- 23= 0; (x - 2)(x2
+ 2x + 4) = 0;
x = 2 or x = = =
= -1 69. x3+ 1000 = 0; x3
+
103= 0; (x + 10)(x2
- 10x + 100) = 0; x = -10 or
x = = =10 4 !2300
22(210) 4 "(210)2 2 4(1)(100)
2(1)
4 i!322 4 2i!32
22 4 !2122
22 4 "22 2 4(1)(4)2(1)
"3 100x2
5x"3 (5x)2
"3 (5x)2!3 4!3 5xÅ
3 45x 5
!3nn
!n!n
!3!nÅ
6m2mn 5 Å
3n
!6m!2mn
!2"98x4"14x3!7x"3 (2x)3
"3 8x3!3 4x"3 2x2!933
2!936
!3726
!62 ? !6!6 ? !6
!62!6
!16Å322
!32!2
!15"15x2!5x!3x!3 2"3 33 ? 2!3 54!3 18!3 3
2 S 2162 ? 21 T2 b
2a
"4 x4x
44"4 x4
!38!32
4!5 1 4!3 2 4!5 1 4!35 2 3
4(!5 2 !3)(!5 1 !3)(!5 2 !3)
4(!5 1 !3)(!5 2 !3)(!5 1 !3)
4!5 1 !3
4!5 2 !3
12
224
1 1 !5 1 1 2 !51 2 5
1(1 2 !5)(1 1 !5)(1 2 !5)
1(1 1 !5)(1 2 !5)(1 1 !5)
11 1 !5
11 2 !5
!5!5!5!5
!5!5!5!5!5!2!5!2!7 2 2
!7
60 2 20!27
60 2 20!29 2 2
20(3 2 !2)(3 1 !2)(3 2 !2)
203 1 !2
dr
Algebra 2 Solution Key • Chapter 7, page 195
= 5 70. 125x3- 1 = 0; (5x)3
-
13= 0; (5x - 1)(25x2
+ 5x + 1) = 0; 5x - 1 = 0 or
25x2+ 5x + 1 = 0; x = or x = =
= = 71. x4-
14x2+ 49 = 0; (x2
- 7)2= 0; x2
- 7 = 0; x2= 7;
x = 72. 25x4- 40x2
+ 16 = 0; (5x2)2-
2(5x2)(4) + 42= 0; (5x2
- 4)2= 0; 5x2
- 4 = 0;
5x2= 4; x2
= x = = = ? =
73. 81x4- 1 = 0; (9x2
- 1)(9x2+ 1) = 0;
9x2- 1 = 0 or 9x2
+ 1 = 0; x2= or x2
= -
x = or x =
CHECKPOINT QUIZ 1 page 390
1. = = 2. =
= xy2 3. = = -a
4. = = -y2 5. =
+ 3(8) = + 24 6. ? =
= 12x3y 7. - =
- 8. ? = =
= 9. =
5 - 12 = -7 10. ? = =
7-4 Rational Exponents pages 391–396
Check Skills You’ll Need For complete solutions seeDaily Skills Check and Lesson Quiz Transparencies orPresentation CD-ROM.
1. 2. 3. 4. 5. 6.
CA Standards Check pp. 391–394 1a. = =
= 2 1b. ? = = 2
1c. ? = = = 4 2a. = =
; z0.4= = = 2b. = ;
= 2c. If m is negative, then = ,
and if a = 0, then the denominator of the fractionwould be zero. Since this cannot happen, a 2 0.
3. N = � 0.270 revolutions per second, or
about 16 revolutions per minute 4a. =
= = 4b. = = = 823(!5 32)332351
125153
1(!25)3
25232
4.90.5
2p(1.7)0.5
1(!n a)2ma
mny
32(!y)3
x23"3 x2"5 z2z
25z
4101
"8 y3
1y
38
y238!16!2 ? !88
122
12
!2 ? !22122
12"4 24
!4 161614
b2
16a616b12
a812
1125x6y3
19x2
116
20!7 2 2587
20!7 2 25112 2 25
4!7 2 54!7 2 5
54!7 1 5
(!5 2 2!3)(!5 1 2!3)4!10x45x
4y!10x45xy
4"10xy2
9(5xy)!5y!5y
4!2xy
9"5x2y9!3 212!3 3
3!3 544!3 81!356"140x6y2
3"28x3y22"5x38!3!192
!8(!24 1 3!8)"5 (2y2)5"5 2y10
"3 (2a)3"3 2a3"5 (x)5(y2)5
"5 x5y10u b uc2"4 (b)4(c2)4"4 b4c8
4i34
13
19;1
9
42!5
5
!5!5
42!5
42!5
4Å45
45;
4!7
21 4 i!310
25 4 5i!350
25 4 !27550
25 4 "52 2 4(25)(1)2(25)
15
4 5i!310 4 10i!32
4c. = = = 16 5. =
? = ? =
Exercises pp. 394–396 1. = = = 6
2. = = = 3 3. = = = 74. ? = ? = 10 5. ? ?
= ? ? = = -3
6. ? = ? = = = 6
7. ? = ? = = = 8
8. ? = ? = = = = 3
9. ? = ? = = =
= 3 10. = 11. = 12. =
or 13. = or 14. =
or 15. = or 16. =
= or 17. = = or
18. = 19. = or
20. = = 21. =
= 22. = = 23. =
= 24. = = 25. =
= (5xy)2 or 25x2y2 26. �
72.8; about 72.8 m 27. � 15.1;
about 15.1 m 28. � 7.9; about 7.9 m
29. � 1.6; about 1.6 m
30. = = 22= 4 31. = = 42
=
16 32. = = (-2)2= 4 33. =
= (-2)6= 64 34. = = =
35. = = = 23= 8 36. =
= = 43= 64 37. 10,0000.75
= =
= 103= 1000
38. = = 39. = =
40. = 41. = 42. =
= 43. = =
44. = = = 45. =
= or = =
46. = = 47. =
= 48. = = x3y9
49. = = 50. = =
= -7 51. = = =
-3 52. 321.2= = = 26
= 64(!5 32)63265
"5 (23)5!52243(2243)15"3 (27)3
!32343(2343)13
y5
x10x210
y25ax223
y213b
15
x3
y29a x14
y234b
12y2
x8x28y2
Ax23y2
16B212y4
x3x23y4Ax12y2
23B26
x4!3 x"3 (x4)3 ? x"3 x13x133(x13)
13
Q x2
x211R131
xx21(x4)214Q x3
x21R21
4
22y3(232)15y3(232y15)
152 3
x322713x23
(227x29)135
x23
5Ax23B211
3x23
A3x23B21
1x4x24Ax24
7B71x2x22Ax2
3B23
(!4 10,000)3
10,00034(!16)316
32
161.5(!4)343241.51
16
124
1(!5 32)4322
45(!5232)6
(232)65(!328)2(28)
23
(!3 64)264 23(!3 8)28
23
h 50.00252(25)2.27
2.3
h 50.00252(50)2.27
2.3
h 50.00252(50)2.27
1.2
h 50.00252(100)2.27
1.2f(5xy)6g13
"3 (5xy)6c12(c2)
14"4 c2a
23Aa1
3B2(!3 a)2a
23(a2)
13"3 a2(7x)
32A7x
12B3
(!7x)3(7x)32(7x3)
12"(7x)3
x327
12(7x3)
12"7x3(210)
12!210
(!5 y)6"5 y6y65y1.2(!x)3"x3x
32
x1.51(!4 t)3
1"4 t3t2
341
(!8 y)91"8 y9
y298(!5 y)2"5 y2y
25(!7 x)2"7 x2
x27!5 xx
15!6 xx
16"4 34
!4 81!4 3 ? 27!4 27!4 327143
14
"3 33!3 27!3 3 ? 9!3 9!3 39133
13
!64!2 ? 32!32!232122
12
!36!3 ? 12!12!312123
12
(!323)3!323!323!323(23)13
(23)13(23)
13!10!1010
1210
12
"72!494912"3 33!3 2727
13
"62!363612
12x5
1x5
1!3 8
x258213
(8x15)213(22)4(!5232)4(232)
45
Algebra 2 Solution Key • Chapter 7, page 196
53. 2431.2= = = 36
= 72954. 643.5
= = = 87= 2,097,152
55. 1004.5= = = 109 or 1,000,000,000
56. 32-0.4= = = = 57. 64-0.5
=
= = 58. = =
= 59. = = 2(2)3= 16
60. = = =
61. = = = 101= 10
62. = � 78%; = � 61%;
= � 37% 63. � 636;
the answer is A. 64. = = =
6(2)7= 768 65. ? = = = =
66. ? = = = = 67. �
= = = = 68. � = =
= = 69. = =
70. = = =
71. = = 72. =
= 73. � = ? � =
= = = 74. ?
= = = =
75. = = = 76. -1=
-= = 77. The cube root of -64
is -4, which equals . The square root of -64 is
not a real number, but = -8.
78. The exponent applies only to the 5, not to the 25.
79. Answers may vary. Sample: Let a = 4 - , then
a = = 16 - 5 = 11, which is
rational; a = , a = a = ; no
80a. ? ? ? = x ? x = x2, so =
80b. = = = =
81. = 72= 49 82. =
= 32= 9 83. = x4p-2p
= x2p
84. ? = ? = =
50= 1 85. = = = =
86. = = 34- 2= 32
= 93(21!2)(22!2)(321!2)22!2
3!232!2
232!2(32)
1!29
1!2
52!322!3(52)2!352!3252!352!3
x4p
x2p331!52(11!5)
331!5
311!5(7!2)!2!x
x12x
24(x2)
14"4 x2!x
"4 x2!x!x!x!x
4 2 512
22Q4 1 512R,4 2 5
12
Q4 1 512RQ4 2 5
12RQ4 1 5
12R
512
12
2(64)12 5 2!64
2(64)13
1xy
12
y212x2
12
13Ax3
2y32B
C("x3 y3)13D1
x13
x213(x21)
13C Ax21
2B2D13
1x
724
x2724x
18242
21242
424x
342
782
16x2
16
Ax34 4 x
78B1
x1336
x21336x
6361
5362
2436x
161
5362
23
x23x
536x
16x
23Ax1
2 ? x5
12B139y8
4x681
12y8
1612x6
a81y16
16x12b124x7
9y916
12x7
8112y9
a16x14
81y18b12
1x
14y
56
x214 y2
56x
122
34 y2
132
12
x12 y2
13
x34 y
12
x16y
14y2
141
12x
232
12
x23 y2
14
x12 y2
12
y12y
714y
10142
314
y572
314y
314y
57x
12x
510x
6102
110x
352
110
x110x
35y
45y
810y
5101
310y
121
310y
310y
12
x12x
714x
4141
314x
271
314x
314x
27
6(!5 32)76(32)75PV
75
0.036(46 3 104)34(2.7)2
80008033R
A
(2.7)240008033R
A(2.7)220008033R
A
104
103(!3 1000)4
(!100)31000
43
10032
2 181
21(23)4
21(!3227)42(227)2
43
2(!4 16)32(16)341
361
(26)2
1(!32216)2(2216)2
231
81!64
64212
14
122
1(!5 32)2322
25
(!100)910092
(!64)76472
(!5 243)624365 87. -20 = 35.74 + 0.6215(5) - 35.75V0.16
+
0.4275(5)V0.16; -20 = 38.8475 - 35.75V0.16+
2.1375V0.16- 58.8475 = -33.6125V0.16; V0.16
=
; = ; V � 33.13; 33.13 mph
88. = = = = n�5;
the answer is D. 89. a-m= is true for all real
number values of a, m, and n; a-m= represents a
property of exponents; the answer is B.90. The parent function is y = |x|; the graph of y - 2 =2|x - 2| or y = 2|x - 2| + 2, is translated 2 units right,2 units up and is stretched by a factor of 2; the answer is C. 91. - = (6 - 2) =
92. + = + =
+ = (9 + 12) =
93. = = 1 +
94. = =
+ 7 = 95. =
= =
96. =
= =
= 97. 4x3- 8x2
+
16x = 4x(x2- 2x + 4) 98. x2
+ 4x + 4 = (x + 2)2
99. x2- 18x + 81 = (x - 9)2 100. 16a2
- 9b2=
(4a)2- (3b)2
= (4a - 3b)(4a + 3b) 101. 25x2-
40xy + 16y2= (5x)2
- 2(5x)(4y) + (4y)2= (5x - 4y)2
102. 9x2+ 48x + 64 = (3x)2
+ 2(3x)(8) + 82=
(3x + 8)2
7-5 Solving Square Root and OtherRadical Equations pages 397–402
Check Skills You’ll Need For complete solutions seeDaily Skills Check and Lesson Quiz Transparencies orPresentation CD-ROM. 1. -3, 2 2. -2, 7
3. 1, 4. , 2 5. , 6. ,
CA Standards Check pp. 397–399 1. -6= 0; = 6; 5x + 1 = 36; 5x = 35; x = 7
2. = 54; = 27; = ;
x + 3 = 9; x = 6 3. r = ; 20 = ; 400
= ; P = 400(0.02p); P = 25.1; about 25.1 watts; it isabout 4 times the power of a 10-cm cell.4. + 3 = x; = x - 3; 5x - 1 =
(x - 3)2; 5x - 1 = x2- 6x + 9; x2
- 11x + 10 = 0;(x - 10)(x - 1) = 0; x - 10 = 0 or x - 1 = 0; x = 10or x = 1; check x = 10: + 3 0 10, +
3 0 10, 7 + 3 = 10; check x = 1: + 3 0 1,+ 3 0 1, 2 + 3 2 1; the only solution is 10.!4
!5(1) 2 1!49!5(10) 2 1
!5x 2 1!5x 2 1
P0.02p
% P0.02p% P
0.02p
2723C(x 1 3)
32D 23(x 1 3)
322(x 1 3)
32
!5x 1 1!5x 1 1
3222
31225
221323
2
10 2 8!27
6 2 2!2 2 6!2 1 47
6 2 2!2 2 3!8 1 !169 2 2
(22 1 !8)(23 1 !2)(23 2 !2)(23 1 !2)
22 1 !823 2 !2
4 1 6!5 1 2!10 1 15!2241
4 1 6!5 1 2!10 1 3!504 2 45
(2 1 !10)(2 1 3!5)(2 2 3!5)(2 1 3!5)
2 1 !102 2 3!5
15 2 4!148 2 2!56
(!8 2 !7)(!8 2 !7)(!8 2 !7)23!5
1!5 2 45 1 4!5 2(!5 2 1)(!5 1 4)
21!2!212!29!2
2"62 ? 23"32 ? 22!723!18
4!3 3!3 32!3 36!3 3
1a
m
1a
m
n53 ?2
31an
53b23
an(322(21
6))b23An3
2 4 n216B23
Q258.8475233.6125R
10016(V0.16)
10016258.8475
233.6125
Algebra 2 Solution Key • Chapter 7, page 197
5. - = 0; = ;3x + 2 = 2x + 7; x = 5; check x = 5: -
0 0, - 0 0, 0 = 0; the solution is 5.
Activity p. 400 1a. x = + 5; x - 5 =
; (x - 5)2= x + 7; x2
- 10x + 25 = x + 7;x2
- 11x + 18 = 0; (x - 9)(x - 2) = 0; x - 9 = 0 orx - 2 = 0; x = 9 or x = 2; 2 solutions 1b. 1 point ofintersection 1c. Yes, 2 is an extraneous solution1d. check x = 2: 2 0 + 5, 2 0 3 + 5, 2 2 8;check x = 9: 9 0 + 5, 9 0 4 + 5, 9 = 9; yes2a. 1 point of intersection, so 1 solution 2b. 1 pointof intersection, so 1 solution 2c. 2 points ofintersection, so 2 solutions
Exercises pp. 400–402 1. + 3 = 15; = 12;= 4; x = 42
= 16 2. - 1 = 3; = 4;
= 1; x = 12= 1 3. = 5; x + 3 = 52;
x = 25 - 3 = 22 4. = 4; 3x + 4 = 42;3x + 4 = 16; 3x = 12; x = 4 5. - 7 = 0;
= 7; 2x + 3 = 72; 2x + 3 = 49; 2x = 46; x =
23 6. - 2 = 0; = 2; 6 - 3x = 22;
6 - 3x = 4; 3x = 2; 7. = 4; x + 5 =
; x + 5 = 48; x = 3 or x = -13 8. = 9;x - 2 = ; x - 2 = 427; x = 29 or x = -25
9. = 24; = 8; x - 2 = ; x - 2 =
16; x = 18 10. = 81; = 27; x + 3
= ; x + 3 = 81; x = 78 11. - 2 = 25;
= 27; x + 1 = ; x + 1 = 9; x = 8
12. 3 + = 11; = 8; 4 - x = ;
4 - x = 4; x = 0 13. V = d3; 15,000 = d3;
d3= ; d = � 30.6; about 30.6 ft
14. Q = ? = ; v = ?
= ; A = pr2; Q = Av; 86,400 = pr2(7200);
r2= = ; r = � 1.95; d = 2r � 3.9; 4 in.
15. - 2x = 0; = 2x; 11x + 3 =
(2x)2; 11x + 3 = 4x2; 4x2- 11x - 3 = 0;
(4x + 1)(x - 3) = 0; 4x + 1 = 0 or x - 3 = 0;
x = (extraneous) or x = 3 16. - 3x = 0;
= 3x; 5x + 4 = (3x)2; 5x + 4 = 9x2;
9x2- 5x - 4 = 0; (9x + 4)(x - 1) = 0; 9x + 4 = 0
or x - 1 = 0; x = (extraneous) or x = 1
17. - 5 = x; = x + 5; 3x +
13 = (x + 5)2; 3x + 13 = x2+ 10x + 25; x2
+ 7x +
12 = 0; (x + 3)(x + 4) = 0; x + 3 = 0 or x + 4 = 0;x = -3 or x = -4 18. + 5 = x; =
x - 5; x + 7 = (x - 5)2; x + 7 = x2- 10x + 25;
x2- 11x + 18 = 0; (x - 2)(x - 9) = 0; x - 2 = 0
or x - 9 = 0; x = 2 (extraneous) or x = 9
19. - 1 = x; = x + 1; x + 3 =(x 1 3)12(x 1 3)
12
!x 1 7!x 1 7
!3x 1 13!3x 1 13
249
(5x 1 4)12
(5x 1 4)1221
4
!11x 1 3!11x 1 3Å
12p
12p
86,4007200p
7200 in.min
12 in.1 ft
600 ftmin
86,400 in.3minQ12 in.
ft R350 ft3
min
Q90,000p R
13
15,000(6)p
p6
p6
823(4 2 x)
32(4 2 x)
32
2723(x 1 1)
32
(x 1 1)3227
43
(x 1 3)343(x 1 3)
34
843(x 2 2)
343(x 2 2)
34
932
(x 2 2)234
32
(x 1 5)23x 5 2
3
!6 2 3x!6 2 3x!2x 1 3
!2x 1 3!3x 1 4!x 1 3!x
4!x4!x!x3!x3!x
!9 1 7!2 1 7
!x 1 7
!x 1 7
!17!17!2(5) 1 7!3(5) 1 2
!2x 1 7!3x 1 2!2x 1 7!3x 1 2 (x + 1)2; x + 3 = x2+ 2x + 1; x2
+ x - 2 = 0;(x + 2)(x - 1) = 0; x = -2 (extraneous) or x = 1
20. = x + 1; 5 - x = (x + 1)2; 5 - x =
x2+ 2x + 1; x2
+ 3x - 4 = 0; (x + 4)(x - 1) = 0;
x = -4 (extraneous) or x = 1 21. = ;
3x = x + 6; 2x = 6; x = 3 22. - =
0; = ; = ;
(x + 5)2= 5 - 2x; x2
+ 10x + 25 = 5 - 2x; x2+
12x + 20 = 0; (x + 10)(x + 2) = 0; x + 10 = 0 or x + 2 = 0; x = -10 (extraneous) or x = -2
23. = ; 7x + 6 = 9 + 4x; 3x = 3;
x = 1 24. = x - 1; 3x + 7 = (x - 1)2;
3x + 7 = x2- 2x + 1; x2
- 5x - 6 = 0;(x + 1)(x - 6) = 0; x + 1 = 0 or x - 6 = 0;x = -1 (extraneous) or x = 6 25. - x = 1;
= x + 1; x + 7 = (x + 1)2; x + 7 = x2+
2x + 1; x2+ x - 6 = 0; (x + 3)(x - 2) = 0;
x + 3 = 0 or x - 2 = 0; x = -3 (extraneous) or x = 226. = x + 3; -3x - 5 = (x + 3)2;-3x - 5 = x2
+ 6x + 9; x2+ 9x + 14 = 0;
(x + 7)(x + 2) = 0; x + 7 = 0 or x + 2 = 0; x = -7
(extraneous) or x = -2 27. - =
0; = ; 3x + 2 = 2x + 7; x = 5
28. x + 8 = ; (x + 8)2= x2
+ 16;
x2+ 16x + 64 = x2
+ 16; 16x = -48; x = -3
29. = ; 2x = x + 5; x = 5
30. 1 = ; 12= 3 + x; x = 1 - 3 = -2
31a. y1 = - x; 31b. y1 = ;y2 = 1 y2 = x + 1
31c. y1 = - x - 1;y2 = 0
31d. The graph of each pair consistsof two straight lines, one of which ishorizontal. They intersect at differentpoints, but these points have thesame x-value, about 1.236.
Ox
y
3
1
1 3
!5
!5!5
(3 1 x)12
(x 1 5)12(2x)
12
Ax2 1 16B12!2x 1 7!3x 1 2
(2x 1 7)12(3x 1 2)
12
!23x 2 5
!x 1 7!x 1 7
!3x 1 7
(9 1 4x)12(7x 1 6)
12
C(5 2 2x)14D4C(x 1 5)
12D4(5 2 2x)
14(x 1 5)
12
(5 2 2x)14(x 1 5)
12
!x 1 6!3x
(5 2 x)12
Algebra 2 Solution Key • Chapter 7, page 198
2 4Ox
y4
2
Ox
y4
2 4
32a. ; 2A = ;
? = ; s = =
32b. � 8.8; about 8.8 in. 32c. �
8.8 � 15.2; about 15.2 in. 33. A = s2; s = ; s == 4 , or about 5.7 m; the answer is B.
34. 3 - 3 = 9; 3 = 12; =
4; 2x = 42; 2x = 16; x = 8 35. + 1 = 5;
= 4; = 2; 2x = 23; 2x = 8; x = 436. - 3 = 0; = 3; 2x - 1 = 32;2x - 1 = 9; 2x = 10; x = 5 37. + 7 = 0;
= -7; 2x + 3 = (-7)2; 2x + 3 = 49;2x = 46; x = 23 (extraneous); no real solution
38. = x + 1; x2+ 3 = (x + 1)2; x2
+ 3 =
x2+ 2x + 1; 2 = 2x; x = 1 39. - 3 = 5;
= 8; 2x + 3 = ; 2x + 3 = 16; 2x = 13;x = 6.5 40. + 4 = 36; = 32;
= 16; x - 1 = ; x - 1 = -8 or x - 1 = 8;x = -7 or x = 9 41. - = 2; - 2 =
; ( - 2)2= ( )2; x - 4 + 4 =
x - 5; -4 = -9; (-4 )2= (-9)2; 16x = 81;
x = 42. = + 2; - 2 = ;
= x - 8; x + 4 + 4 = x - 8; 4 =
-12; = -3; x = (-3)2= 9
43. The solution is x = 2.
Check: -
= 0 ✓
44. The solution is x = -1and x = -6.Check: +
= 5 ✓;
+
= 5 ✓
45. The solution is x = 2.
Check: =
✓8f3(2) 1 2g212
f3(2) 1 2g12
X Y1 Y21.7 2.6646 3.00231.8 2.7203 2.94091.9 2.7749 2.8832 2.8284 2.82842.1 2.881 2.77682.2 2.9326 2.7282.3 2.9833 2.6816
X =
X Y1 Y2-6.3 4.9731 5-6.2 4.9825 5-6.1 4.9915 5-6 5 5-5.9 5.0081 5-5.8 5.0159 5-5.7 5.0232 5
X =
!3 2 (26)
!(26) 1 10
!3 2 (21)
!(21) 1 10
X Y1 Y2-1.3 5.0232 5-1.2 5.0159 5-1.1 5.0081 5-1 5 5-.9 4.9915 5-.8 4.9825 5-.7 4.9731 5
X =
!4(2) 1 3
!5(2) 1 1X Y1 Y21.7 -.0483 01.8 -.0315 01.9 -.0154 02 0 02.1 .01478 02.2 .02899 02.3 .04268 0
X =
!x!x!x(!x 1 2)2
!x 2 8!x!x 2 8!x8116
!x!x!x!x 2 5!x!x 2 5!x(x 2 5)
12x
12
1634(x 2 1)
43
2(x 2 1)432(x 2 1)
43
843(2x 1 3)
34
(2x 1 3)34
"x2 1 3
(2x 1 3)12
(2x 1 3)12
!2x 2 1!2x 2 1(2x)
132(2x)
13
2(2x)13
!2x!2x!2x!2!32
!A!3
s!3s 5"2(200)!3
3
"2!3A3Å
2!3A9
2A!39
!3!3
s2 5 2A3!3
3s2!3A 5 3s2!32
46. The solution is x = 7.
Check: =
3 ✓
47. The solution is x = 25.
Check: + 1
= ✓
48. The solution is x = 10.
Check: -
2 = 0 ✓
49. The solution is x = -1.
Check: =
✓
50. The solution is x = 1.25
or .
Check: [2(1.25) - 1) =
[(1.25) + 1) ✓
51. v = ; v2= 64d; d = 52. Answers may
vary. Sample: = 53. +
= ; ( + )2= ( ;
x + 1 + 2 + 2x = 5x + 3; 2 =
2x + 2; = x + 1; 2x(x + 1) = (x + 1)2;2x2
+ 2x = x2+ 2x + 1; x2
= 1; x = -1 (extraneous)
or x = 1 54. = ; = 2x;= x; 2x = x2; x2
- 2x = 0; x(x - 2) = 0; x = 0
or x - 2 = 0; x = 0 or x = 2 55. = 2;
= 22; = 4 - x; 2x = (4 - x)2; 2x = 16- 8x + x2; x2
- 10x + 16 = 0; (x - 8)(x - 2) = 0;x - 8 = 0 or x - 2 = 0; x = 8 (extraneous) or x = 2
56. = ; = x + 5; x + 25= (x + 5)2; x + 25 = x2
+ 10x + 25; x2+ 9x = 0;
x(x + 9) = 0; x + 9 = 0 or x = 0;x = -9 (extraneous) or x = 0 57. Plan 1: Use acalculator to evaluate + 2 and store the result asx. Evaluate and store the result as x. Continuethis procedure about seven times, until it becomes clearthat the values are approaching 2. Plan 2: The given
!x 1 2!2
!x 1 25!x 1 5"!x 1 25
!2xx 1 !2x
"x 1 !2x
!2xx 1 !2x!2x"x 1 !2x
!2x(x 1 1)
!2x(x 1 1)!2x(x 1 1)
!5x 1 3)2!2x!x 1 1!5x 1 3!2x
!x 1 1!3x 1 5!x 2 3
v2
64!64d
g16
g13
54
X Y1 Y2.95 .96549 1.11771.05 1.0323 1.12711.15 1.0914 1.13611.25 1.1447 1.14471.35 1.1935 1.1531.45 1.2386 1.16111.55 1.2806 1.1688
X =
f2 1 3(21)g13
f2(21) 1 1g13
X Y1 Y2-1.3 -1.17 -1.239-1.2 -1.119 -1.17-1.1 -1.063 -1.091-1 -1 -1-.9 -.9283 -.8879-.8 -.8434 -.7368-.7 -.7368 -.4642
X =
!5(10) 2 25
!10(10)X Y1 Y29.7 .1535 09.8 .10154 09.9 .05038 010 0 010.1 -.0496 010.2 -.0985 010.3 -.1467 0
X =
(25)12
f(25) 2 9g12
X Y1 Y224.7 4.9623 4.969924.8 4.9749 4.9824.9 4.9875 4.9925 5 525.1 5.0125 5.0125.2 5.0249 5.0225.3 5.0373 5.0299
X =
!(7) 2 5
!4(7) 2 10X Y1 Y26.7 4.0988 3.91156.8 4.1473 4.02496.9 4.1952 4.13527 4.2426 4.24267.1 4.2895 4.34747.2 4.3359 4.44977.3 4.3818 4.5497
X =
Algebra 2 Solution Key • Chapter 7, page 199
equation is equivalent to x = Solve thisequation to find that x = 2. 58a. A counterexample isa = 3, b = -3. 58b. A counterexample is a = -5,b = 3. 59. A: x2
+ 5x - 36 = 0; (x + 9)(x - 4) = 0;x + 9 = 0 or x - 4 = 0; x = -9 or x = 4; the answer isA. 60. (6a3b4)(-2a-3b2) = (6)(-2)a(3-3)b(4+2)
=
-12(1)b6= -12b6; the answer is C. 61. Congruent
figures have the same size and shape. Since y = 3x2- 1
is a vertical stretch of y = x2 transposed down 1 and y = x2
- 1 is y = x2 transposed down 1, their graphs are not congruent.The answer is B. 62. =
2=
2= 42
= 16 63. 251.5= = ( )3
= 53= 125
64. ? = (6 ? 12 = = = = 6
65. ? = (8 ? 40 = = = =
8 66. ? = (3 ? 18 = = = =
= 3 67. 81-0.25= = = =
68. 43.5= = )7
= 27= 128
69. 125 ? = = = =
= 52= 25 70. 32 ? = = = 2
71. ? = ? = ? =
72. 7P1 = = = = 7 73. 7P3 =
= = = 7 ? 6 ? 5 = 210
74. 5P3 = = = = 5 ? 4 ? 3 =
60 75. 8P4 = = = =
8 ? 7 ? 6 ? 5 = 1680 76. 4P4 = = = =
4 ? 3 ? 2 ? 1 = 24 77. 5C2 = = =
= = 10 78. 7C5 = = =
= = 21 79. 5C5 = = =
= 1 80. 6C5 = = = = 6
81. 7C1 = = = = 7 82. x2-
7x + 12 = 0; (x - 3)(x - 4) = 0; x - 3 = 0 or x - 4 = 0; x = 3 or x = 4 83. x2
- 8x + 15 = 0;(x - 3)(x - 5) = 0; x - 3 = 0 or x - 5 = 0; x = 3 orx = 5 84. x2
+ 9x + 20 = 0; (x + 5)(x + 4) = 0;x + 5 = 0 or x + 4 = 0; x = -5 or x = -4 85. 3x2
+
8x + 4 = 0; (3x + 2)(x + 2) = 0; 3x + 2 = 0 or x + 2 = 0; x = - or x = -2 86. 9x2
+ 15x +
4 = 0; (3x + 1)(3x + 4) = 0; 3x + 1 = 0 or 3x + 4 =
0; x = - or x = 87. 4x2+ 11x + 6 = 0;
(4x + 3)(x + 2) = 0; 4x + 3 = 0 or x + 2 = 0;x = - or x = -2
GEOMETRY REVIEW page 403
1–4. Estimates may vary. 1a. Let d = diameter ofcylinder, then d2
= e2+ e2
= 2e2, and d = e . Then !2
34
243
13
23
7 ? 6!1 ? 6!
7!1! 6!
7!1!(7 2 1)!
6 ? 5!5! ? 1
6!5! 1!
6!5!(6 2 5)!
5!5! ? 1
5!5! 0!
5!5!(5 2 5)!
7 ? 62 ? 1
7 ? 6 ? 5!5! ? 2!
7!5! 2!
7!5!(7 2 5)!
5 ? 42 ? 1
5 ? 4 ? 3!2! ? 3!
5!2! 3!
5!2!(5 2 2)!
4!1
4!0!
4!(4 2 4)!
8 ? 7 ? 6 ? 5 ? 4!4!
8!4!
8!(8 2 4)!
5 ? 4 ? 3 ? 2!2!
5!2!
5!(5 2 3)!
7 ? 6 ? 5 ? 4!4!
7!4!
7!(7 2 3)!
7 ? 6!6!
7!6!
7!(7 2 1)!
1106
1103
1103QÅ 1
100R31
(!100)30.01321002
32
3216
32!256
256212("3 53)2
(!3 125)2125231251 2
131252
13
(!4472
13
1"4 34
1!4 81
1810.25!3 2"3 33 ? 2
"3 33 ? 2!3 545413)
1318
133
13!5
"82 ? 5!32032012)
1240
128
12
!2"62 ? 2!727212)
1212
126
12
!252532("3 43)
(!3 64)6423
!2 1 x. r = radius of cylinder =
Height of cylinder = e. =
= = about 57% more
volume 1b. =
= =
= � 1.26; about 26% more
surface area 2. = =
= = � 1.57; about 57% more surface
area 3. Let s = side length of square, then d =
diagonal of square = diameter of circle = =
= . So, r = radius of circle = .
= = = � 1.57;
= = = �
1.11. The area of the circle exceeds the area of thesquare by about 57%. The circumference of the circleexceeds the perimeter of the square by about 11%.4. The small sphere has a diameter of e, and a radius of
. = = =
3 � 5.20; about 420% more volume
7-6 Function Operations pages 404–410
Check Skills You’ll Need For complete solutions seeDaily Skills Check and Lesson Quiz Transparencies orPresentation CD-ROM. 1. domain: {0, 2, 4};range: {-5, -3, -1} 2. domain: {-1, 0, 1}; range: {0}3. domain: all real numbers; range: all real numbers4. domain: all real numbers; range: all real numbers � 0 5. 10 6. 28
CA Standards Check pp. 404–406 1. f (x) = 5x2-
4x, g(x) = 5x + 1; (f + g)(x) = 5x2- 4x + 5x + 1 =
5x2+ x + 1, domain: all real numbers; (f - g)(x) =
5x2- 4x - (5x + 1) = 5x2
- 9x - 1, domain: all realnumbers 2. f(x) = 6x2
+ 7x - 5, g(x) = 2x - 1;(f ? g)(x) = (6x2
+ 7x - 5)(2x - 1) = 12x3+ 14x2
-
10x - 6x2- 7x + 5 = 12x3
+ 8x2- 17x + 5,
domain: all real numbers; = =
= 3x + 5, domain: all real numbers
except 3a. ( f + g)(x) = f(g(x)) = f(x2) = x2- 2;
( f + g)(-5) = (-5)2- 2 = 25 - 2 = 23 3b. No; the
12
(3x 1 5)(2x 2 1)2x 2 1
6x2 1 7x 2 52x 2 1QfgR(x)
!3
3e3!3 ? 88 ~ e
3
43pQ
e!32 R3
43pQ
e2R
3Volume of large sphereVolume of small sphere
e2
p!24
s ? p!24s
2pQs!22 R
4sCircumference of circle
Perimeter of square
p2
2ps2
4s2
pQs!22 R2
s2Area of circle
Area of square
s!22s!2"2s2
"s2 1 s2
p2
3pe2
6e2
4p ? 3e2
46e2
4pQe!32 R2
6e2Surface area of sphereSurface area of cube
p 1 p!26
pe2 1 p!2e2
6e2
4pe2
4 1 2!2pe2
26e2
2pQe!22 R2 1 2pQe!2
2 Re6e2
Surface area of cylinderSurface area of cube
p2 < 1.57;2pe3
4e3
pQe!22 R2e
e3
Volume of cylinderVolume of cube
e!22 .
Algebra 2 Solution Key • Chapter 7, page 200
order in which operations are performed changesbetween ( f + g) and (g + f ), which changes what eachcomposition equals. 4a. Let f(x) = 0.9x and g(x) =0.75x. Then (g + f )(x) = g(0.9x) = 0.75(0.9x).4b. ( f + g)(x) = f (0.75x) = 0.9(0.75x) 4c. It makesno difference.Exercises pp. 406–410 1. f(x) + g(x) = 3x + 5 +
x2= x2
+ 3x + 5 2. g(x) - f(x) = x2- (3x + 5) =
x2- 3x - 5 3. f(x) - g(x) = 3x + 5 - x2
= -x2+
3x + 5 4. f(x) ? g(x) = (3x + 5)(x2) = 3x3+ 5x2
5. = 6. = 7. ( f + g)(x) =
f(x) + g(x) = 3x + 5 + x2= x2
+ 3x + 58. ( f - g)(x) = f(x) - g(x) = 3x + 5 - x2
= -x2+
3x + 5 9. (g - f )(x) = g(x) - f(x) = x2- (3x + 5) =
x2- 3x - 5 10. ( f ? g)(x) = f(x) ? g(x) =
(3x + 5)(x2) = 3x3+ 5x2
11. = = 12. = =
13. f(x) + g(x) = 2x2+ x - 3 + x - 1 =
2x2+ 2x - 4; domain: all real numbers 14. g(x) -
f(x) = x - 1 - (2x2+ x - 3) = -2x2
+ 2; domain:all real numbers 15. f (x) - g(x) = 2x2
+ x - 3 -
(x - 1) = 2x2- 2; domain: all real numbers
16. f(x) ? g(x) = (2x2+ x - 3)(x - 1) = 2x3
- 2x2+
x2- x - 3x + 3 = 2x3
- x2- 4x + 3;
domain: all real numbers 17. = =
= 2x + 3; domain: all real numbers
except 1 18. = = =
; domain: all real numbers except 1 and
19. (f ? g)(x) = f(x) ? g(x) = 9x(3x) = 27x2, domain:
all real numbers; = = = 3; domain: all
real numbers except 0 20. (g ° f )(x) = g(f(x)) =g(2x) = 2x + 3; (g + f )(3) = 2(3) + 3 = 9;(g + f )(-2) = 2(-2) + 3 = -1 21. (g ° f )(x) =g(f(x)) = g(x2) = Δx2
+ 5Δ = x2+ 5; (g + f )(3) =
Δ32+ 5Δ = Δ14Δ = 14; (g + f )(-2) = Δ(-2)2
+ 5Δ =Δ9Δ = 9 22. (h ° g)(1) = h(g(1)) = h(2 ? 1) = h(2) =22
+ 4 = 8 23. (h + g)(-5) = h(g(-5)) = h(2(-5)) =h(-10) = (-10)2
+ 4 = 104 24. (h + g)(-2) =h(g(-2)) = h(2(-2)) = h(-4) = (-4)2
+ 4 = 2025. (g ° h)(-2) = g(h(-2)) = g((-2)2
+ 4) = g(8) =2(8) = 16 26. (g + h)(0) = g(h(0)) = g(02
+ 4) =g(4) = 2(4) = 8 27. (g + h)(-1) = g(h(-1)) =g((-1)2
+ 4) = g(5) = 2(5) = 10 28. (g + g)(3) =g(g(3)) = g(2 ? 3) = g(6) = 2 ? 6 = 1229. (h + h)(2) = h(h(2)) = h(22
+ 4) = h(8) =82
+ 4 = 68 30. (h + h)(-4) = h(h(-4)) =h((-4)2
+ 4) = h(20) = 202+ 4 = 404
31. (g + f )(-2) = g( f(-2)) = g((-2)2) = g(4) =4 - 3 = 1 32. ( f + g)(-2) = f(g(-2)) = f(-2 - 3) =f(-5) = (-5)2
= 25 33. (g + f )(0) = g(f(0)) =
9x3x
f(x)g(x)QfgR(x)
232
12x 1 3
x 2 1(2x 1 3)(x 2 1)
x 2 12x2 1 x 2 3
g(x)f(x)
(2x 1 3)(x 2 1)x 2 1
2x2 1 x 2 3x 2 1
f(x)g(x)
x2
3x 1 5
g(x)f(x)QgfR(x)3x 1 5
x2f(x)g(x)QfgR(x)
x2
3x 1 5g(x)f(x)
3x 1 5x2
f(x)g(x)
g(02) = g(0) = 0 - 3 = -3 34. (f + g)(0) = f(g(0)) =f(0 - 3) = f(-3) = (-3)2
= 9 35. (g + f)(3.5) =g(f(3.5)) = g((3.5)2) = g(12.25) = 12.25 - 3 = 9.2536. (f + g)(3.5) = f(g(3.5)) = f(3.5 - 3) = f(0.5) =
(0.5)2= 0.25 37. (f + g) = = =
= = = 6.25 38. (g ° f) = g =
= = = -2.75 39. (f + g)(c) =
f(g(c)) = f(c - 3) = (c - 3)2= c2
- 6c + 940. (g + f )(c) = g(f(c)) = g(c2) = c2
- 341. ( f ° g)(-a) = f (g(-a)) = f(-a - 3) = (-a - 3)2
=
a2+ 6a + 9 42. (g + f )(-a) = g(f (-a)) =
g((-a)2) = g(a2) = a2- 3 43a. f (x) = 0.9x
43b. g(x) = x - 2000 43c. g(f(18,000)) =g(0.9(18,000)) = g(16,200) = 16,200 - 2000 = 14,200;$14,200 43d. f(g(18,000)) = f(18,000 - 2000) =f(16,000) = 0.9(16,000) = 14,400; $14,40044a. (g + f )(x) = g( f(x)) = g(0.12x) = 9.14(0.12x) =1.0968x 44b. (g + f )(15) = 1.0968(15) = 16.452;16.452 pesos 45. f (x) + g(x) = 2x + 5 + x2
- 3x +
2 = x2- x + 7 46. 3f(x) - 2 = 3(2x + 5) - 2 =
6x + 15 - 2 = 6x + 13 47. g(x) - f(x) = x2- 3x +
2 - (2x + 5) = x2- 5x - 3 48. -2g(x) + f(x) =
-2(x2- 3x + 2) + 2x + 5 = -2x2
+ 6x - 4 + 2x +
5 = -2x2+ 8x + 1 49. f(x) - g(x) + 10 = 2x + 5 -
(x2- 3x + 2) + 10 = 2x + 5 - x2
+ 3x - 2 + 10 =
-x2+ 5x + 13 50. 4f(x) + 2g(x) = 4(2x + 5) +
2(x2- 3x + 2) = 8x + 20 + 2x2
- 6x + 4 = 2x2+
2x + 24 51. -f(x) + 4g(x) = -(3x2+ 2x - 8) +
4(x + 2) = -3x2- 2x + 8 + 4x + 8 = -3x2
+ 2x +
16; domain: all real numbers 52. f (x) - 2g(x) = 3x2+
2x - 8 - 2(x + 2) = 3x2+ 2x - 8 - 2x - 4 =
3x2- 12; domain: all real numbers 53. f(x) ? g(x) =
(3x2+ 2x - 8)(x + 2) = 3x3
+ 6x2+ 2x2
+ 4x - 8x -
16 = 3x3+ 8x2
- 4x - 16; domain: all real numbers54. -3f(x) ? g(x) = -3(3x2
+ 2x - 8)(x + 2) =(-9x2
- 6x + 24)(x + 2) = -9x3- 6x2
+ 24x -
18x2- 12x + 48 = -9x3
- 24x2+ 12x + 48; domain:
all real numbers 55. = =
= 3x - 4; domain: all real numbers
except -2 56. = =
= 5(3x - 4) = 15x - 20; domain:
all real numbers except -2 57. Answers may vary.Sample: (g + f )(3) means g(f(3)), so first evaluate f (3) = 2(3) = 6; then evaluate g(6) = 6 + 1 = 7.58. f(g(1)) = f(3(1) + 2) = f(5) = = 1
59. g( f (-4)) = g = g(-2) = 3(-2) + 2 = -4
60. f(g(0)) = f(3(0) + 2) = f(2) = = 0
61. g(f(2)) = g = g(0) = 3(0) + 2 = 2Q2 2 23 R
2 2 23
Q24 2 23 R
5 2 23
5(3x 2 4)(x 1 2)x 1 2
5(3x2 1 2x 2 8)x 1 2
5f(x)g(x)
(3x 2 4)(x 1 2)x 1 2
3x2 1 2x 2 8x 1 2
f(x)g(x)
14 2 3gQ14RgQQ12R
2RQfQ12RRQ12R
254Q52R
2fQ52R
fQ12 2 3RfQgQ12RRQ12R
Algebra 2 Solution Key • Chapter 7, page 201
62a. (A + r)(x) when x = 2: A(r(2)) = A(12.5(2)) =A(25) = p ? 252
= 625p � 1963; the area after 2seconds is about 1963 in.2 62b. A(r(4)) = A(12.5(4)) =A(50) = p ? 502
= 2500p � 7854; about 7854 in.2
63. f(g(x)) = f (x2) = 3(x2) = 3x2; g(f(x)) = g(3x) =(3x)2
= 9x2 64. f(g(x)) = f(x - 5) = x - 5 + 3 =
x - 2; g(f(x)) = g(x + 3) = x + 3 - 5 = x - 265. f(g(x)) = f(2x) = 3(2x)2
+ 2 = 12x2+ 2;
g( f(x)) = g(3x2+ 2) = 2(3x2
+ 2) = 6x2+ 4
66. f(g(x)) = f(2x - 3) = = =
x - 3; g(f(x)) = g = 2 - 3 = x -
3 - 3 = x - 6 67. f(g(x)) = f(4x) = -4x - 7;g(f(x)) = g(-x - 7) = 4(-x - 7) = -4x - 28
68. f(g(x)) = f(x2) = ; g( f (x)) = g =
= 69. Answers may vary.Sample: 69a. g(x) = 0.12x 69b. f(x) = 9.50x69c. (g + f )(x) = 1.14x; your savings will be $1.14 foreach hour you work. 70a. f(x) and g(x) 70b. 0, 15,30; 3, 28, 103 70c. (f + g)(x) = f(g(x)) = f(x2
+ 3) =3(x2
+ 3) = 3x2+ 9 70d. 3*A1^2 + 9, 9, 84, 309
70e. (g + f )(x) = g(f(x)) = g(3x) = (3x)2+ 3 =
9x2+ 3 70f. 9*A1^2 + 3, 3, 228, 903 71a. P(x) =
I(x) - C(x) = 5995x - (1000 + 700x) = 5295x - 100071b. P(30) = 5295(30) - 1000 = 157,850; $157,85072a. g(x) is the bonus earned when x is the amount ofsales over $5000. h(x) is the excess of x sales over $5000.72b. (g + h)(x) because you first need to find the excesssales over $5000 to calculate bonus.73. ( f + g)(x) = f(x) + g(x) Def. of Function
Addition= 3x - 2 + (x2
+ 1) Substitution= x2
+ 3x - 2 + 1 Commutative Prop.of Addition
= x2+ 3x - 1 Arithmetic
74. ( f - g)(x) = f(x) - g(x)) Def. of Function Subtraction
= 3x - 2 - (x2+ 1) Substitution
= 3x - 2 - x2- 1 Opposite of a Sum
Property= -x2
+ 3x - 2 - 1 Commutative Prop.of Addition
= -x2+ 3x - 3 Arithmetic
75. (f + g)(x) = f(g(x)) Def. of Composition of Functions
= f(x2+ 1) Substitution
= 3(x2+ 1) - 2 Substitution
= 3x2+ 3 - 2 Distributive Property
= 3x2+ 1 Arithmetic
76a. f(x) = x + 10; g(x) = 1.09x 76b. f(g(x)) meanseach grade is increased 9% before adding the 10-pointbonus; f(g(75)) = f(1.09(75)) = f(81.75) = 81.75 +
10 = 91.75 76c. g( f(x)) means the 10-point bonus isadded, then the sum is increased by 9%; g( f(75)) =g(75 + 10) = g(85) = 1.09(85) = 92.65 76d. no
77. f(x) ? g(x)
x2 1 10x 1 254Qx 1 5
2 R2Qx 1 5
2 Rx2 1 52
Qx 2 32 RQx 2 3
2 R
2x 2 62
2x 2 3 2 32
= (x3- 3x2
- 5x + 15)= x7
- 3x6- 5x5
+ 15x4
+ 2x6- 6x5
- 10x4+ 30x3
-5x5+ 15x4
+ 25x3- 75x2
-10x4+ 30x3
+ 50x2- 150x
= x7- x6
-16x5+ 10x4
+ 85x3- 25x2
- 150x;
domain: all real numbers 78. =
= =
= =
= ; domain: all real numbers except 3,
, and - 79. = =
= =
= = ; domain: all real
numbers except 0, -2, , and - 80. f( f(x)) =
f = = ? = x 81. f( f( f(x))) =
= f(x) = 82. f(f(f(x))) = =
= = =
= = =
= 83. =
= =
= 2 84. =
=
= 4 85. The total cost is p(x) + c(x) = 1.5x + 3 +
0.75x + 2 = 2.25x + 5; the answer is B. 86. f(x) - g(x)= 2(x - 2)2
- (x2- 5x + 4 = 2(x2
- 4x + 4) - (x2-
5x + 4 = 2x2- 8x + 8 - x2
+ 5x - 4 = x2- 3x + 4;
the answer is D. 87. At 2 hours, the handymen chargethe same amount. After 2 hours, Tim’s cost is less thanAndy’s cost. The answer is D. 88. =
x + 1; x2+ 3 = (x + 1)2; x2
+ 3 = x2+ 2x + 1; 2x =
2; x = 1 89. x + 8 = ; (x + 8)2= x2
+
16; x2+ 16x + 64 = x2
+ 16; 16x = -48; x = -390. = x + 1; x2
+ 9 = (x + 1)2; x2+ 9 =
x2+ 2x + 1; 2x = 8; x = 4 91. - x = -3;(x2 2 9)
12
"x2 1 9
(x2 1 16)12
"x2 1 3
4hh
4a 1 4h 2 1 2 4a 1 1h
4(a 1 h) 2 1 2 (4a 2 1)h 5
f(a 1 h) 2 f(a)h
2hh
2 1 2h 2 3 2 2 1 3h
2(1 1 h) 2 3 2 (2(1) 2 3)h
f(1 1 h) 2 f(1)h
6 2 x8
8 2 2 2 x8
2 2 2 1 x4
21 22 1 x
42fQ2 1 x
4 R
fa1 1 x2
2bfa2 2 1 1 x
22
bfa1 21 2 x
22
b
fQfQ1 2 x2RR1
xfQfQ1xRR
x1
11
11x
Q1xR!5!5
x 2 3x2 1 2x
x 2 3x(x 1 2)
(x2 2 5)(x 2 3)
x(x2 2 5)(x 1 2)
x2(x 2 3) 2 5(x 2 3)
x(x2(x 1 2) 2 5(x 1 2))x3 2 3x2 2 5x 1 15
x(x3 1 2x2 2 5x 2 10)
x3 2 3x2 2 5x 1 15x4 1 2x3 2 5x2 2 10x
g(x)f(x)!5!5
x2 1 2xx 2 3
x(x 1 2)x 2 3
x(x2 2 5)(x 1 2)
(x2 2 5)(x 2 3)
x(x2(x 1 2) 2 5(x 1 2))
x2(x 2 3) 2 5(x 2 3)
x(x3 1 2x2 2 5x 2 10)
x3 2 3x2 2 5x 1 15x4 1 2x3 2 5x2 2 10xx3 2 3x2 2 5x 1 15
f(x)g(x)
(x4 1 2x3 2 5x2 2 10x)
Algebra 2 Solution Key • Chapter 7, page 202
= x - 3; x2- 9 = (x - 3)2; x2
- 9 = x2-
6x + 9; 6x = 18; x = 3 92. - 2 = x;
= x + 2; x2+ 12 = (x + 2)2; x2
+ 12 =
x2+ 4x + 4; 4x = 8; x = 2 93. ;
3x = x + 6; 2x = 6; x = 3 94. (x + 4)8= x8
+
8x7(4) + 28x6(4)2+ 56x5(4)3
+ 70x4(4)4+ 56x3(4)5
+
28x2(4)6+ 8x(4)7
+ (4)8= x8
+ 32x7+ 448x6
+
3584x5+ 17,920x4
+ 57,344x3+ 114,688x2
+ 131,072x +
65,536 95. (x + y)6= x6
+ 6x5y + 15x4y2+ 20x3y3
+
15x2y4+ 6xy5
+ y6 96. (2x - y)4= (2x)4
+
4(2x)3(-y) + 6(2x)2(-y)2+ 4(2x)(-y)3
+ (-y)4=
16x4- 32x3y + 24x2y2
- 8xy3+ y4
97. (2x - 3y)7= (2x)7
+ 7(2x)6(-3y) +21(2x)5(-3y)2
+ 35(2x)4(-3y)3+ 35(2x)3(-3y)4
+
21(2x)2(-3y)5+ 7(2x)(-3y)6
+ (-3y)7= 128x7
-
1344x6y + 6048x5y2- 15,120x4y3
+ 22,680x3y4-
20,412x2y5+ 10,206xy6
- 2187y7
98. (9 - 2x)5= 95
+ 5(9)4(-2x) + 10(9)3(-2x)2+
10(9)2(-2x)3+ 5(9)(-2x)4
+ (-2x)5= 59,049 -
65,610x + 29,160x2- 6480x3
+ 720x4- 32x5
99. (4x - y)5= (4x)5
+ 5(4x)4(-y) + 10(4x)3(-y)2+
10(4x)2(-y)3+ 5(4x)(-y)4
+ (-y)5= 1024x5
-
1280x4y + 640x3y2- 160x2y3
+ 20xy4- y5
100. (x2+ x)4
= (x2)4+ 4(x2)3(x) + 6(x2)2(x)2
+
4(x2)(x)3+ (x)4
= x8+ 4x7
+ 6x6+ 4x5
+ x4
101. (x2+ 2y3)6
= (x2)6+ 6(x2)5(2y3) +
15(x2)4(2y3)2+ 20(x2)3(2y3)3
+ 15(x2)2(2y3)4+
6(x2)(2y3)5+ (2y3)6
= x12+ 12x10y3
+ 60x8y6+
160x6y9+ 240x4y12
+ 192x2y15+ 64y18
102. = (2 - 3(2i)) +(4 + 2(4i)) = 2 - 6i + 4 + 8i = 6 + 2i103. =
= = -2 +
104. - = -
= =
105. = =
10 - 30i - 6i + 18i2= 10 - 18 - 30i - 6i = -8 - 36i
CHECKPOINT QUIZ 2 page 410
1. = = (-3x)4=
81x4 2. = = =
= 3. -
4 = 0; = 4; 3x + 1 = 42; 3x + 1 = 16; 3x =
15; x = 5 4. ; ; 5x + 2 =
27; x = 5 or x = - 5. - 3 = 3x;= 3x + 3; 3x + 3 = (3x + 3)2; 3x + 3 =
9x2+ 18x + 9; 9x2
+ 15x + 6 = 0; 3x2+ 5x + 2 = 0;
(3x + 2)(x + 1) = 0; 3x + 2 = 0 or x + 1 = 0; x =
or x = -1 6. (2 - x)0.5- x = 4; (2 - x)0.5
=223
!3x 1 3!3x 1 329
54
5x 1 2 5 932(5x 1 2)
23 5 9
!3x 1 1
!3x 1 11(2y)2 5
14y2
1("5 32y5)2 5
1("5 (2y)5)2
1(32y5)
25
1(32y5)0.4(32y5)20.4
("3 (23x)3 )
45 ("3 227x3
)4
(227x3)43
(5 2 3i)(2 2 6i)(5 2 !29)(2 2 !236)13 1 5i!56 1 2i!5 1 7 1 3i!5(27 2 3i!5)
(6 1 2i!5)(27 2 !245)(6 1 !220)19i!215i!2 2 2 1 4i!2(2 2 4i!2)
3(5i!2) 23!250 2 (2 2 !232)
(2 2 3!24) 1 (4 1 2!216)
(3x)12 5 (x 1 6)
12
"x2 1 12
"x2 1 12
"x2 2 9 x + 4; 2 - x = (x + 4)2; 2 - x = x2+ 8x + 16; x2
+
9x + 14 = 0; (x + 7)(x + 2) = 0; x + 7 = 0 or x + 2 =
0; x = -7 (extraneous) or x = -2 7.
+ 3 + = 1 + 3 + =
8. (f ? g)(1) = f(1) ? g(1) = (2(1) + 3) =
5(0) = 0 9.
10. ( f + g)(5) = f(g(5)) = = f(20) = 2(20)
+ 3 = 43
GUIDED PROBLEM SOLVING page 411
1. (C + r)(x) when x = 3: C(r(3)) = C(12.5(3)) =C(37.5) = 2p(37.5) = 75p; 3 seconds after it isformed a ripple will have a circumference of 75p in.,or about 236 in. 2. (A + d)(x) when x = 10.5:A(d(10.5)) = A(2.3(10.5)) = A(24.15) = p(24.15)2
< 687.09; 687.09 km2
7-7 Inverse Relations and Functions pages 412– 418
Check Skills You’ll Need For complete solutions seeDaily Skills Check and Lesson Quiz Transparencies orPresentation CD-ROM.1. 2.
3. 4.
5. 6.
�2 2 4Ox
y
2
�2
�4
x
y
2 4 6O
4
2
�2
�2 2O x
y
2
�22 4O
x
y
4
2
�6 2 8O x
y
8
2�4 4O x
y
4
�4
38
f(52 2 5)
2(2) 1 3
22 2 25 7
2QfgR(2) 5f(2)g(2) 5
(12 2 1)
154
14 2
12QQ12R
22 1
2R2Q12R(f 1 g)Q12R 5
Algebra 2 Solution Key • Chapter 7, page 203
Activity p. 412 1a. f(10) = 2(10) - 8 = 12;
g( f(10)) = g(12) = 1b. f(0) = 2(0) -
8 = -8; g(f(0)) = g(-8) = 1c. f(-7) =
2(-7) - 8 = -22; g( f(-7)) =
1d. g( f(-1496)) = -1496 2a. g(6) = ;
f(g(6)) = f(7) = 2(7) - 8 = 6 2b. g(0) = ;
f(g(0)) = f(4) = 2(4) - 8 = 0 2c. g(-32) =
; f(g(-32)) = f(-12) = 2(-12) - 8 =
-32 2d. f(g(p)) = p 3a. x = 2y - 8; 2y = x + 8;
3b. y = 2x - 8 and y =
They are reflections of each other in the line y = x.
CA Standards Check pp. 413–415 1a. The line y =
x is the perpendicular bisector of each segmentconnecting a point in s to the corresponding point in theinverse of s. The graph of the inverse of s is a reflectionin the line y = x of the graph of s. 1b. yes; no2a. Yes; no; for every x-value except 3 in the domain ofthe inverse there are two y-values. 2b. x = 3y - 10;
3y = x + 10; ; yes, it is a function becausefor each value of x there is only one y-value.3. y = 3x - 10; inverse: x = 3y - 10; 3y = x + 10;
4a. domain: all real numbers; range: all real numbers4b. f(x) = 10 - 3x, or y = 10 - 3x; inverse: x = 10 -
3y, 3y = -x + 10, y = , f -1(x) =
4c. domain: all real numbers; range: all real numbers
4d. f-1( f (3)) = f-1(10 - 3(3)) = f-1(1) =
4e. = =
5. ; 64d = v2; v =
8 � 44; about 44 ft/s!d 5 8!30
d 5 v2
64fQ83R 5 10 2 3Q83R 5 2
fQ22 1 103 Rf(f21(2))21 1 10
3 5 3
2x 1 103
2x 1 103
y 5 13x 1 10
3
y 5 13x 1 10
3
12x 1 4
y 5 x 1 82
232 1 82 5 212
0 1 82 5 4
6 1 82 5 7
222 1 82 5 27
28 1 82 5 0
12 1 82 5 10
6. + (777) = 777; + (-5802) = -5802
Exercises pp. 416–418
1.
2.
3.
4.
5. y = 3x + 1; inverse: x = 3y + 1; 3y = x - 1;; yes 6. y = 2x - 1; inverse: x = 2y - 1;
2y = x + 1; ; yes 7. y = 4 - 3x; inverse:
x = 4 - 3y; 3y = -x + 4; ; yes 8. y =
5 - 2x2; inverse: x = 5 - 2y2; 2y2= 5 - x; ;
y = no 9. y = x2+ 4; inverse: x = y2
+ 4;
y2= x - 4; ; no 10. y = 3x2
- 5;
inverse: x = 3y2- 5; 3y2
= x + 5; y2=
no 11. y = (x + 1)2; inverse: x =
(y + 1)2; ; ; no12. y = (3x - 4)2; inverse: x = (3y - 4)2; =
3y - 4; ; ; no
13. y = (1 - 2x)2+ 5; inverse: x = (1 - 2y)2
+ 5;x - 5 = (1 - 2y)2; = 1 - 2y;
2y = ; ; no
14. y = 2x - 3; inverse:x = 2y - 3; 2y = x + 3;
x 5 12x 1 3
2
y 5 1 4 !x 2 521 4 !x 2 5
4!x 2 5
y 5 4!x 1 433y 5 4!x 1 4
4!xy 5 4!x 2 14!x 5 y 1 1
y 5 4Åx 1 5
3 ;
x 1 53 ;
y 5 4!x 2 4
4Å5 2 x
2 ;
y2 5 5 2 x2
y 5 2 13x 1 4
3
y 5 12x 1 1
2
y 5 13x 2 1
3
�2 Ox
y2
�2
✘✘✘✘
yx 2 2
022
�3 �2 �1
Ox✘
✘✘
✘
y8
4
4 8
yx
0 1 20 4
391
Ox✘
✘✘
✘y
4
2
2 4
yx
1 2 30 2
431
Ox✘
✘✘
✘y
4
2
2 4
yx
1 2 30 0
421
f21)(ff)(f21
Algebra 2 Solution Key • Chapter 7, page 204
�2 2 4O x
y
4
2
�2
�4 2 6�8 Ox
y
6
2
�4
�8
�2 2O x
y
2
�2
15. y = 3 - 7x; inverse:x = 3 - 7y; 7y = -x + 3;
16. y = -x; inverse:x = -y; y = -x
17. y = 3x2; inverse:x = 3y2; ; y =
18. y = -x2; inverse:x = -y2; y2
= -x;y =
19. y = 4x2- 2; inverse:
x = 4y2- 2; 4y2
= x + 2;
y2= ;
y =
20. y = (x - 1)2;inverse: x = (y - 1)2;
= y - 1;
21. y = (2 - x)2;inverse: x = (2 - y)2;
= 2 - y;y 5 2 4 !x4!x
y 5 1 4 !x4!x
4Åx 1 2
4 5 4!x 1 2
2
x 1 24
4!2x
4Åx3y2 5 x
3
y 5 217x 1 3
7
22. y = (3 - 2x)2- 1;
inverse: x = (3 - 2y)2-
1; x + 1 = (3 - 2y)2;
;
23. f (x) = 3x + 4, or y = 3x + 4; inverse: x = 3y + 4;
3y = x - 4; ; ; domain
and range for both f and f-1 are all real numbers; f-1 isa function. 24. f (x) = , or y = ;inverse: x = ; x2
= y - 5; y = x2+ 5;
f-1(x) = x2+ 5, x � 0; domain of f {xΔ x � 5}, range
of f {yΔy � 0}; domain of f-1 {xΔx � 0}, range of f-1 {yΔy � 5}; f-1 is a function. 25. ,or ; inverse: ; x2
= y + 7; y =
x2- 7; f-1(x) = x2
- 7, x � 0; domain of f {xΔx � -7},range of f { yΔy � 0}; domain of f-1 {xΔx � 0},range of f-1 {yΔy � -7}; f-1 is a function.26. , or ; inverse:
; x2= -2y + 3; 2y = 3 - x2;
y = , x � 0; domain of f
xΔx � , range of f {yΔy � 0}; domain of f-1
{xΔx � 0}, range of f-1 yΔy � ; f-1 is a function.
27. f(x) = 2x2+ 2, or y = 2x2
+ 2; inverse: x = 2y2+
2; 2y2= x - 2; y2
= ; y = f-1(x) =
, x � 2; domain of f { all real numbers}, range
of f { yΔy � 2}; domain of f-1 {xΔx � 2}, range of f-1
{all real numbers}; f-1 is not a function. 28. f(x) =-x2
+ 1, or y = -x2+ 1; inverse: x = -y2
+ 1;y2
= 1 - x; ; f-1(x) = , x � 1;domain of f {all real numbers}, range of f {yΔy � 1};domain of f-1 {xΔx � 1}, range of f-1 {all real numbers};f-1 is not a function.
29a. ; solve for ;
; yes 29b.
30a. ; solve for r: ;
r = yes 30b. r = � 20.29; 20.29 ft
31. (f-1 + f )(10) = 10 32. (f + f-1)(-10) = -1033. (f-1 + f )(0.2) = 0.2 34. ( f + f-1)(d) = d35. f (x) = 1.5x2
- 4, or y = 1.5x2- 4;
inverse: x = 1.5y2- 4; 1.5y2
= x + 4; ;
no
36. , or ; inverse: ; 4x = 3y2;
; f-1(x) = no42Åx3;y 5 4Å
43x 5 42Å
x3;y2 5 4
3x
x 53y2
4y 5 3x2
4f(x) 5 3x2
4
f21(x) 5 4Å2x 1 8
3 ;y 5 4Å2x 1 8
3 ;
y2 52(x 1 4)
3
Å3 3(35,000)
4pÅ3 3V
4p ;
r3 5 3V4pV 5 4
3pr323.898F
F 5 59(25 2 32) < 23.89;F 5 5
9(C 2 32)
F: 95F 5 C 2 32C 5 95F 1 32
4!1 2 xy 5 4!1 2 x
4Åx 2 2
2
4Åx 2 2
2 ;x 2 22
32VU
32VU
3 2 x2
2 ; f21(x) 5 3 2 x2
2
x 5 !22y 1 3y 5 !22x 1 3f(x) 5 !22x 1 3
x 5 !y 1 7y 5 !x 1 7f(x) 5 !x 1 7
!y 2 5!x 2 5!x 2 5
f21(x) 5 x 2 43y 5 x 2 4
3
y 5 3 4 !x 1 12
2y 5 3 4!x 1 14!x 1 1 5 3 2 2y;
Algebra 2 Solution Key • Chapter 7, page 205
2 4Ox
y4
2
�2
�2 2O x
y
2
�2
x
y
4O
4
2
�2
�2�4�6O x
y2
�2
�4
2 4�2O x
y4
2
�2
8Ox
y8
4
4Ox
y
4
4 6Ox
y
6
4
37. f (x) = , or ; inverse:
; ; (x - 3)2=
2y - 1; 2y = x2- 6x + 9 + 1; ;
, x � 3; yes 38. f (x) = (x + 1)2,
or y = (x + 1)2; inverse: x = (y + 1)2; ;
; f-1(x) = ; no39. f (x) = (2x - 1)2, or y = (2x - 1)2; inverse: x =
(2y - 1)2; 2y - 1; ; ;
; no 40. f (x) = (x + 1)2- 1, or
y = (x + 1)2- 1; inverse: x = (y + 1)2
- 1; x + 1 =
(y + 1)2; = y + 1; y = -1 ;f-1(x) = -1 ; no 41. f (x) = x3, or y = x3;inverse: x = y3; y = ; f-1(x) = ; yes
42. f (x) = x4, or y = x4; inverse: x = y4; = y;
f-1(x) = ; no 43. , or
, inverse: ; ;
5(x - 1) = 2y2; y2= ;
no 44. ; v2= 2gx;
; flow is 40 ft/s: x = ;
flow is 20 ft/s: x = = 6.25; 6.25 ft 45. The range ofthe inverse is the domain of f, which is the set of all realnumbers x � 1. 46. 2 and 5 47. f(x) = , or
; inverse: ; ; y = x2;
f-1(x) = x2, x � 0; domain of f {xΔx � 0}, range of f{yΔy � 0}; domain of f-1 {xΔx � 0}, range of f-1
{yΔy � 0}; f-1 is a function. 48. f (x) = , or
; inverse: ; ;
y = (x - 3)2; f-1(x) = (x - 3)2, x � 3; domain of f{xΔx � 0}, range of f {yΔy � 3}; domain of f-1
{xΔx � 3}, range of f-1 {yΔy � 0}; f-1 is a function.
49. f (x) = , or ; inverse:
; x2= -y + 3; y = 3 - x2; f-1(x) =
3 - x2, x � 0; domain of f {xΔx � 3}, range of f{yΔ y � 0}; domain of f-1 {xΔx � 0}, range of f-1
{yΔy � 3}; f-1 is a function. 50. f (x) = ,
or ; inverse: ; x2= y + 2;
y = x2- 2; f-1(x) = x2
- 2, x � 0; domain of f
{xΔx � -2}, range of f {yΔy � 0}; domain of f-1
{xΔx � 0}, range of f-1 {yΔy � -2}; f -1 is a function.
51. f (x) = , or ; inverse: ; 2x = y2;
; f-1(x) = , x � 0; domain of f{all real numbers}, range of f {yΔy � 0}; domain of f -1
{xΔx � 0}, range of f-1 {all real numbers}; f-1 is not a
function. 52. f (x) = , or ; inverse: ;
xy2= 1; ; , x � 0; domain f21(x) 5 1
!xy 5 Å
1x;y2 5 1
x
x 5 1y2y 5 1
x21x2
4!2xy 5 4!2x
x 5y2
2y 5 x2
2x2
2
x 5 !y 1 2y 5 !x 1 2
!x 1 2
x 5 !2y 1 3
y 5 !2x 1 3!2x 1 3
x 2 3 5 !yx 5 !y 1 3y 5 !x 1 3
!x 1 3
2x 5 !yx 5 2!yy 5 2!x2!x
202
64
402
64 5 25; 25ftx 5 v2
2g 5v2
2(32) 5v2
64
v 5 !2gxf21(x) 5 4Å5x 2 5
2 ;
y 5 4Å5x 2 5
2 ;5x 2 52
x 2 1 52y2
5x 52y2
5 1 1y 5 2x2
5 1 1
f(x) 5 2x2
5 1 14!4 x
4!4 x
!3 x!3 x4 !x 1 1
4 !x 1 14!x 1 1
f21(x) 5 1 4 !x2
y 5 1 4 !x22y 5 1 4 !x4!x 5
4!x 2 1y 5 4!x 2 1
4!x 5 y 1 1
f21(x) 5 x2 2 6x 1 102
y 5 x2 2 6x 1 102
x 2 3 5 !2y 2 1x 5 !2y 2 1 1 3
y 5 !2x 2 1 1 3!2x 2 1 1 3 of f {xΔx 2 0}, range of f {yΔy � 0}; domain of f-1
{xΔx � 0}, range of f-1 {yΔy 2 0}; f-1 is not a function.53. f (x) = (x - 4)2, or y = (x - 4)2; inverse: x =
(y - 4)2; ; ; f-1(x) =; domain of f {all real numbers}, range of f
{yΔy � 0}; domain of f-1 {xΔx � 0}, range of f-1
{all real numbers}; f-1 is not a function. 54. f (x) =(7 - x)2, or y = (7 - x)2; inverse: x = (7 - y)2;
; ; f-1(x) = , x � 0;domain of f {all real numbers}, range of f {yΔy � 0};domain of f-1 {xΔx � 0}, range of f-1 {all real numbers};
f-1 is not a function. 55. f (x) = , or
; inverse: ; x(y + 1)2= 1;
(y + 1)2= y + 1 =
, x � 0; domain of f {xΔx 2 -1},
range of f {yΔy � 0}; domain of f-1 {xΔx � 0}, range of f-1 { yΔy 2 -1}; f-1 is not a function. 56. f (x) =
, or y = ; inverse: x = ;
x - 4 = ; ; y = ;
f-1(x) = , x � 4; domain of f {xΔx � 0},
range of f {yΔy � 4}; domain of f-1 {xΔx � 4}, range
of f-1 {yΔy � 0}; f-1 is a function. 57. f (x) = , or
y = ; inverse: x = ; = 3; ; 2;
f-1(x) = , x � 0; domain of f {xΔx � 0}, range of f
{yΔy � 0}; domain of f-1 {xΔx � 0}, range of f-1
{yΔy � 0}; f-1 is a function. 58. f (x) = , or
inverse: x = ;
; -2y ; ; f-1(x) = ,
x � 0; domain of f {xΔx � 0}, range of f {yΔy � 0};domain of f-1 {xΔx � 0}, range of f-1 {yΔy � 0};f-1 is a function.
59a. Answers may vary. Sample:
59b. Answers may vary. Sample:
60. r is not a function because there are two y-valuesfor one x-value. r-1 is a function because each of its x-values has one y-value. 61. s2
+ s2= h2; h2
= 2s2;; ; inverse (solve for s): ;s!2 5 hh 5 s!2h 5 "2s2
212Q
1xR
2y 5 21
2Q1xR
25 Q1xR
2!22y 5 1x
x!22y 5 1;1!22y
y 5 1!22x
;
1!22x
Q3xR2
y 5 Q3xR!y 5 3xx!y3
!y3!x
3!x
Q2 x 2 42 R2
Q2 x 2 42 R2!y 5 2x 2 4
222!y
4 2 2!y4 2 2!x4 2 2!x
f21(x) 5 4Å1x 2 1
4Å1x; y 5 4Å
1x 2 1;1
x;
x 5 1(y 1 1)2y 5 1
(x 1 1)2
1(x 1 1)2
7 4 !xy 5 7 4 !x4!x 5 7 2 y
4!x 1 4y 5 4!x 1 44!x 5 y 2 4
Algebra 2 Solution Key • Chapter 7, page 206
�2024
04
16
059
�4�2
04
; ; hypotenuse of 6 in.:
� 4.2; about 4.2 in. 62. Check students’ work.
63. , or ; inverse: ; y3= 5x;
; f -1(x) = ; yes 64. f (x) = , or
y = ; inverse: x = ; x3= y - 5; y =
x3+ 5; f-1(x) = x3
+ 5; yes 65. f(x) = , or y =
; inverse: x = ; 3x = ; (3x)3= y; f-1(x) =
27x3; yes 66. f(x) = (x - 2)3, or y = (x - 2)3;
inverse: x = (y - 2)3; = y - 2; y = 2 + ;
; yes 67. , or ;
inverse: ; x4= y; f-1(x) = x4, x � 0; yes
68. f(x) = 1.2x4, or y = 1.2x4; inverse: x = 1.2y4;
; y = ; no
69. (f ° g)(x) + h(x) = 4 x + 7 + |-2x + 4| =
2x + 28 + |-2x + 4|; the answer is C. 70. Since f-1
and f are inverses, (f -1° f)(x) = x for all values of x;(f -1° f)(10) = 10; the answer is B. 71. Use Pascal’sTriangle to expand (a + b)4
= a4+ 4a3b + 6a2b2
+
4ab3+ b4; substitute x3 for a and x for b; (x3)4
+
4(x3)3(x) + 6(x3)2(x)2+ 4(x3)(x)3
+ (x)4= x12
+ 4x10
+ 6x8+ 4x6
+ x4; the answer is A.
72. ( f ° g)(x) = f(g(x)) = f + 7 = 4 + 7 =
2x + 28 73. (g ° f )(x) = g( f (x)) = g(4x) = (4x) +
7 = 2x + 7 74. (h ° g)(x) = h(g(x)) = h + 7 =
= Δ-x - 14 + 4Δ = Δ-x - 10Δ
75. g(x) + g(x) = + 7 + + 7 = x + 14
76. (h ° (g ° f))(x) = h(g( f (x))) = h(g(4x)) =
h + 7 = h(2x + 7) = Δ-2(2x + 7) + 4Δ =
Δ-4x - 14 + 4Δ = Δ-4x - 10Δ 77. ( f ° g)(x) +
h(x) = f(g(x)) + h(x) = f x + 7 + h(x) =
4 + Δ-2x + 4Δ = 2x + 28 + Δ-2x + 4Δ
78. = = 2 79. - = - = -2
80. ; not a real number 81. = = 3
82. - = - = -3 83. =
= -3 84. = = 0.4
85. = = 30
86. 2x3+ 3x2
- 8x - 12 = 0; possible rational roots:
41, 42, 43, 44, 46, 412, 4 , 4 ;
Test 1: 2(1)3+ 3(1)2
- 8(1) - 12 = -15 2 0;Test 2: 2(2)3
+ 3(2)2- 8(2) - 12 = 0, so 2 is a root.
2 3 -8 -124 14 12
2 7 6 0
2;
32
12
"4 304!4 810,000
"3 (0.4)3!3 0.064"5 (23)5
!52243"5 35!5 243
"5 35!5 243!4 216
"4 24!4 16"4 24!4 16
Q12x 1 7RRQ12
RQ12(4x)
12x1
2x
P22Q12x 1 7R 1 4 PRQ12x
12
RQ12xRQ12x
R12Q
4Å4 5x
6y4 5 5x6
x 5 !4 y
y 5 !4 xf(x) 5 !4 xf21(x) 5 2 1 !3 x
!3 x!3 x
!3 y!y3
3!x3
3
!x3
3
!3 y 2 5!3 x 2 5
!3 x 2 5!3 5xy 5 !3 5x
x 5 15y3y 5 1
5x3f(x) 5 15x3
3!2
s 5 6!22 5s 5 h!2
2s 5 h!2
2x2+ 7x + 6 = 0; (2x + 3)(x + 2) = 0; 2x + 3 = 0
or x + 2 = 0; x = - or x = -2; roots are 2, -2, -
87. 3x3- 5x2
- 4x + 4 = 0; possible rational roots:41, 42, 44, 4 , 4 , 4 ;
Test 1: 3(1)3- 5(1)2
- 4(1) + 4 = -2;Test -1: 3(-1)3
- 5(-1)2- 4(-1) + 4 = 0, so -1
is a root.3 -5 -4 4
-3 8 -43 -8 4 0
3x2- 8x + 4 = 0; (3x - 2)(x - 2) = 0; 3x - 2 = 0 or
x - 2 = 0; x = or x = 2; roots are -1, 2,
88. 3x3+ 10x2
- x - 12 = 0; possible rational roots:41, 42, 43, 44, 46, 412, 4 , 4 , 4 ;
Test 1: 3(1)3+ 10(1)2
- 1 - 12 = 0, so 1 is a root.3 10 -1 -12
3 13 123 13 12 0
3x2+ 13x + 12 = 0; (3x + 4)(x + 3) = 0; 3x + 4 = 0
or x + 3 = 0; x = - or x = -3; roots are 1, -3, -
89. 2x3- 11x2
- x + 30 = 0; possible rational roots:
41,42,43,45,46,410,415,430,4 ,4 ,4 ,4 ;
Test 1: 2(1)3- 11(1)2
- 1 + 30 = 20 2 0;Test 2: 2(2)3
- 11(2)2- 2 + 30 = 0, so 2 is a root.
2 -11 -1 304 -14 -30
2 -7 -15 02x2
- 7x - 15 = 0; (2x + 3)(x - 5) = 0; 2x + 3 = 0 or
x - 5 = 0; x = - or x = 5; roots are 2, 5, -
90. x3- 6x2
+ 11x - 6 = 0; possible rational roots:41, 42, 43, 46;Test 1: 13
- 6(1)2+ 11(1) - 6 = 0, so 1 is a root.
1 -6 11 -61 -5 6
1 -5 6 0x2
- 5x + 6 = 0; (x - 3)(x - 2) = 0; x - 3 = 0 or x - 2 = 0; x = 3 or x = 2; roots are 1, 2, 391. x3
+ 3x2- 4x - 12 = 0; possible rational roots:
41, 42, 43, 44, 46, 412;Test 1: 13
+ 3(1)2- 4(1) - 12 = -12 2 0;
Test 2: 23+ 3(2)2
- 4(2) - 12 = 0, so 2 is a root.1 3 -4 -12
2 10 121 5 6 0
x2+ 5x + 6 = 0; (x + 3)(x + 2) = 0; x + 3 = 0 or
x + 2 = 0; x = -3 or x = -2; roots are 2, -2, -3
2;
1;
32
32
2;
152
52
32
12
43
43
1;
43
23
13
23
23
21;
43
23
13
32
32
Algebra 2 Solution Key • Chapter 7, page 207
ACTIVITY LAB page 419
1. y = x2- 5
2. y = (x - 3)2
3. y = 0.01x4
4. y = 0.5x3- 3
5. The third graph would be the same as the first.Interchanging the pairs twice restores the original pairs.6. The graph is the reflection of the first graph in the x-axis. 7. Answers may vary. Sample: Usingparametric equations, you only have to change Y1T tosee a new function and its inverse.
7-8 Graphing Square Root and OtherRadical Functions pages 420–425
Check Skills You’ll Need For complete solutions seeDaily Skills Check and Lesson Quiz Transparencies orPresentation CD-ROM.
1. 2.
642Ox
y
4
2
�2�4�6 Ox
y
4
3. 4.
5. 6.
CA Standards Check pp. 421–423
1. y = - 3 and y =
2. y = and y =
3. y = - 4
4. y = 3 - !3 x 1 1
14!x 2 2
!x 1 4!x 2 1
!x 1 3!x
�2 2Ox
y
2
�4 Ox
y
�2
�4
2
�2 2Oxy
�2
�4
�2�4�6 O xy
�2
�4
�6
Algebra 2 Solution Key • Chapter 7, page 208
1 3�3 Ox
y3
1
�1
�3
84Ox
y8
4
2�2 Ox
y
2
�2
2�2�4 Ox
y
�2
�4
�6
642O xy
�2
�4
�6
2 4 6�2�4 Ox
y5
3
1
2 4Ox
y4
2
�2
�1 1 3�3O x
y3
1
5. Graph Y1 = and Y2 = 3.5. Use theIntersect feature to find the x-coordinate of theintersection.
The height for 3.5-seconds isabout 60 m. This is about theheight of the 7-second fall.
6. y = + 3 = + 3 =
+ 3; the graph of y = + 3 is the
graph of y = translated 3 units right and 3 units up.
Exercises pp. 423–425
1. y = + 1 2. y = - 2
3. y = - 4 4. y = + 5
5. y = 6. y =
7. y = 8. y =
9. y = 10. y = -0.25!x3!x
!x 2 4!x 1 6
!x 1 1!x 2 3
!x!x
!x!x
2!3 x
2!3 x 2 32!3 x 2 3
!3 8(x 2 3)!3 8x 2 24
14
IntersectionX�60.08625 Y�3.5
!(2X>9.81) 11. y = 12. y =
13. y = -5 + 2 14. y = -0.75 + 3
15. y = + 2
16. y = - 1 17. y = 3 + 4
18. y =
19. y = !3 x 2 4
!3 x 1 5
!x 1 114!x 1 2
2!x 2 3
642O x
y
2
44 8
O xy
!x!x 2 3
2!x 2 113!x
Algebra 2 Solution Key • Chapter 7, page 209
642Ox
y6
4
24O x
y4
2
�2
�4
2 4O x
y
642Ox
y
6
4
2
642Ox
y
2
642Ox
y
2
�2�4�6 Ox
y3
1
6 842Ox
y
2
642Ox
y6
4
2
21O x
y
�1
1Ox
y
1
642Oxy
�2
�4
1284Ox
y
12
8
4
642Ox
y
�2
2
642Oxy
�1
2�2�4 Ox
y
�2
1
2 6Ox
y2
�2
20. y = - 7 21. y = - 1
22. y = - 9 23. y = + 3
24a. y = 117.75
24b. Trace the graph to x = 40, 80, and 130; �745 ft,�1053 ft, �1343 ft
25. The intersection is at x = 147, so the solutionis 147.
26. The intersection is at x = 9.5, so the solutionis 9.5.
27. The intersection is at x = -8.11, so thesolution is -8.11.
28. no solution; The left-hand side is never negative andthe right-hand side is always negative.
IntersectionX�-8.111111 Y�10
IntersectionX�7.5 Y�4
IntersectionX�147 Y�12
!x
12!
3 x 2 12!3 x 2 6
2!3 x 1 3!3 x 1 2 29. The intersection is at x = 5, so the solution is 5.
30. The intersection is at x = -1, so the solutionis -1.
31. y = = = ; the graph of y = is the graph of y =
translated 1 unit to the right. 32. y = - =
- = -4 ; the graph of y =
is the graph of y = -4 translated 2 units to the left. 33. y = -2 =
-2 = ; the graph of y =
-14 is the graph of y = -14 translated 1
unit to the left. 34. y = = =
; the graph of y = is the graph of
translated 2 units to the left.
35. y = - 3 = - 3 =
- 3; the graph of y = - 3 is the
graph of y = translated 2 units to the right and
3 units down. 36. y = + 1 =
+ 1 = + 1; the graph of
y = + 1 is the graph of y = translated 2units to the right and l unit up.
37. y = + 7
domain: x � 0; range: y � 7
38. y = - 6
domain: x � 0;range: y � -6
39. y =
domain: x � 6;range: y � 0
!x 2 6
!x
!x
3!3 x3!3 x 2 2
3!3 x 2 2!3 27(x 2 2)
!3 27x 2 54
8!x
8!x 2 28!x 2 2
!64(x 2 2)!64x 2 128
4!3 x
4!3 x 1 24!3 x 1 2
!3 64(x 1 2)!3 64x 1 128
!x!x 1 1214!x 1 1!49(x 1 1)
!49x 1 49!x24!x 1 2
!x 1 2!16(x 1 2)!16x 1 32
3!x3!x 2 13!x 2 1!9(x 2 1)!9x 2 9
IntersectionX -1 Y 1.7320508
IntersectionX 5 Y 6
Algebra 2 Solution Key • Chapter 7, page 210
1208040 160OA
1200
800
400
l
O xy
2�2�6 Ox
y
�2
�4
2
2 4 6 8Oxy
�4
�8�2 2O x
y4
2
1284 16Ox
y4
2
1284Ox
y12
8
4
642 8Oxy
�2
�4
�6
40. y = -3 + 2
domain: x � 0;range: y � 2
41. y =
domain: x � 0;range: y � 0
42. y = 7 -
domain: x � ;
range: y � 7
43. y = + 1
domain: all real numbers;range: all real numbers
44. y = + 3
domain: x � 1;range: y � 3
45. y = - 3
domain: all real numbers;range: all real numbers
23!3 x 2 4
12!x 2 1
4!3 x 2 2
12
!2x 2 1
245!x
!x 46. y = -
domain: x � ;
range: y � 0
47. y = + 5
domain: all real numbers;range: all real numbers
48. y =
domain: all real numbers; range:all real numbers
49. y =
domain: x � -5;range: y � -1
50. y =
domain: all real numbers;range: all real numbers
51. y = + 7
domain: x � ;
range: y � 7
34
23Åx 2 34
4 2 !3 x 1 2.5
21 2 !4x 1 20
22!3 x 2 4
2!3 8x
212
Åx 1 12
Algebra 2 Solution Key • Chapter 7, page 211
642 8Ox
y
�2
�4
�6
2
642 8Oxy
�1
�2
642 8Ox
y
6
4
2
4Ox
y
4
2
�2
642 8 10Ox
y4
2
128Ox
y
�4
�8
�4
4
1284 16Oxy
�2
�4
�2 2 4�4 Ox
y8
4
2
62 8Ox
y
�2
�4
4
2
�2 2 4�4 Oxy
�2
�4
�6
�2�4 Ox
y
4
2
642Ox
y6
4
2
52a. y = 1.11
52b. t = 1.11 � 4.3; about 4.3 s;t = 1.11 � 6.1; about 6.1 s53a. y = - 2
53b. domain: x � 2; range: y � -2 53c. (2, -2)53d. The domain is based on the x-coordinate of thatpoint, and the range is based on the y-coordinate.54a. y = - 2 54b. y = -
2 - 3; y = - 5
55a. y = + 1 and y = - + 1
55b. Both domains are x � 2. The range of y =
+ 1 is y � 1. The range of y = - + 1
is y � 1. 56. y = - 1; y =
- 1; y = 5 - 1; the graph is the
same as y = 5 , translated 4 units right and 1 unit
down. 57. y = + 4; y = 36 +
4; y = + 4; the graph is the graph of y =
, translated 3 units left and 4 units up. 58. y =
- ; y = ;
the graph is the graph of y = - , translated unit
right. 59. y = - 2; y = - 2;
y = - 2; the graph is the same as y = ,
translated 1 unit right and 2 units down. 60. y = 10 -
; y = 10 - ; y = 10 - ;
the graph is the same as y = - , translated 3 units
left and 10 units up. 61. y = + 5; y =
+ 5; y = + 5; the graph is the
same as y = , translated 9 units left and 5 units up.
62. Answers may vary. Sample: y = !3 x 2 2 1 4
"x13
13!x 1 9Å
19(x 1 9)
Åx9 1 1
13!
3 x
13!
3 x 1 3Å3 1
27(x 1 3)Å3 x 1 3
27
12!x1
2!x 2 1
Å14 (x 2 1)Å
x 2 14
142!3 x
y 5 22"3 x 2 14;2Å
3 8Qx 2 14R!3 8x 2 2
6!x
6!x 1 3
!x 1 3!36x 1 108
!x
!x 2 4!25(x 2 4)
!25x 2 100
!x 2 2!x 2 2
!x 2 2!x 2 2
!x 2 1!x 2 5 1 4!x 2 5
!x 2 2!30
!15
!x 63a. y =
63b. d = = = 20; 20 in. 64. If a � 0,the graph is stretched vertically by a factor of a. If a � 0, the graph is reflected over the x-axis andstretched vertically by a factor of ΔaΔ. 65. y =
- ; y = - ; y = - ; the graph is the graph of y = - translated 4 units tothe left; domain: x � -4, range: y � 0 66. y =
- ; y = - ; y = - ;
y = - ; the graph is the graph of y = -
translated units to the right; domain: x � , range: y � 0
67. y = + 6; y = + 6;
y = ? + 6; the graph is the graph of
y = , translated units right and 6 units up;
domain: x � , range: y � 6 68. y = -3 - ;
y = -3 - ; y = - ? - 3;
the graph is the graph of y = - , translated units
left and 3 units down; domain: x � - , range: y � -3
69a.
69b. The graph of y = is a reflection of the
graph of y = in the line x = h. 70. for all
odd positive integers 71. Since the absolute value of
-3 is greater than , the graph of y = -3x2 is
narrower than y = x2. Also, the sign is negative so the
graph will open downward instead of upward. Theanswer is C. 72. The parent function of the graph is y = x2; the graph shows a horizontal translation of 1, avertical translation of 2 and a vertical stretch by a factorof ; the equation of the graph is y = (x - 1)2
+ 2; thevertex of the graph is (1, 2); the answer is B. 73.f(g(x)) = f(x + 3) = 2(x + 3)2
- 5 = 2(x2+ 6x + 9) -
5 = 2x2+ 12x + 18 - 5 = 2x2
+ 12x + 13; the answeris B. 74. f(x) = 4x - 1, or y = 4x - 1; inverse: x =
4y - 1; 4y = x + 1; ; yes 75. f(x) = ,
or y = ; inverse: x = ; = x + 3;
y = ; yes 76. f(x) = 2.4x2+ 1, or y =
2.4x2+ 1; inverse: x = 2.4y2
+ 1; 2.4y2= x - 1;
3(x 1 3)2
23y2
3y 2 323x 2 3
23x 2 3y 5 x 1 1
4
13
13
12
12
!x 2 h
!h 2 x
�4�6�8 �2 Ox
y4
2 2 � xy �
1 � xy �
�xy �
32
32!12x
Åx 1 32!12Å12Qx 1 3
2R!12x 1 185
3
53!3x
Åx 2 53!3
Å3Qx 2 53R!3x 2 5
34
34
!8xÅx 2 34!8
Å8Qx 2 34R!8x 2 6!2(4x 2 3)
!2x!x 1 4!2!2(x 1 4)!2x 1 8
!400!2(200)
!2x
Algebra 2 Solution Key • Chapter 7, page 212
642O t
y4
2
2 6O x
y
�2
8Ox
y
2
�2
642O A
d4
2
y2- ; y = ; no 77. f(x) = -
4, or y = - 4; inverse: x = - 4;
x + 4 = ; (x + 4)2= y + 3; y = (x + 4)2
-
3; yes 78. f (x) = (2x + 1)2, or y = (2x + 1)2;
inverse: x = (2y + 1)2; = 2y + 1;
2y = -1 ; y = ; no 79. f (x) = 2x3, or
y = 2x3, inverse: x = 2y3; y3= ; y = ; yes
80. = = 81. =
= 82. = ? =
83. = =
84. 5x2+ x = 3; 5x2
+ x - 3 = 0; x =
= 85. 3x2+
9x = 27; 3x2+ 9x - 27 = 0; x2
+ 3x - 9 = 0;
x = = =
86. x2- 9x + 15 = 0; x =
=
87. x2+ 10x + 11 = 0; x = =
= = 88. x2-
12x + 25 = 0; x = =
= = 89. 8x2+ 2x -
15 = 0; x = = =
; x = = or x = =
ACTIVITY LAB page 426-427
Activity 11. The domain of y = is x � 0. 2a. the differencebetween a number and its square root 2b. Y3 valuesincrease 3a. x-values are less than values. 3b.negative values 4a-c. Check students’ work.
Activity 25a. x � 3; x � 7 5b. 3 � x � 7 5c. 3 � x � 55d. Check students’ work. 6. yes, x � 3; When x � 3,
is an imaginary number.Activity 37. Check students’ work. 8. The screen shows ahorizontal segment at y = 1; 3 � x � 5; yes 9. 5 � x� 7; the graph does not show y = 1 for these x-values.10a-b. 1 � x � 5 10c. Check students’ work.11a. 3 � x � 5.4 11b. - � ;
x - 2 + x - 3 = 6 - x; -2 = 9"x2 2 3x"x2 2 3x
!6 2 x!x 2 3!x
!x 2 3
!x
!x
232
22 2 2216
54
22 1 2216
22 4 2216
22 4 !48416
22 4 "22 2 4(8)(215)2(8)
6 4 !1112 4 2!112
12 4 !442
2(212) 4 "(212)2 2 4(1)(25)2(1)
25 4 !14210 4 2!142
210 4 !562
210 4 "102 2 4(1)(11)2(1)
9 4 !212
2(29) 4 "(29)2 2 4(1)(15)2(1)
23 4 3!52
23 4 !452
23 4 "32 2 4(1)(29)2(1)
21 4 !6110
21 4 "12 2 4(5)(23)2(5)
"5 48x3y4
2yÅ5
3x3 ? (2y)4
2y ? (2y)4Å5 3x3
2y!3 9xy2
3y
"3 (3y)2
"3 (3y)2!3 x!3 3y
!3 x!3 3y
"3 12xy2
2yÅ3 3x ? (2y)2
2y ? (2y)2
Å3 3x
2y"3x2 5 x!3Å36x312x
"36x3
!12x
Å3 x
2x2
21 4 !x24 !x
4!x
!y 1 3
!y 1 3!x 1 3
!x 1 34Åx 2 1
2.4x 2 1
2.4- x; 4(x2
- 3x) = 81 - 54x + 9x2; 4x2- 12x = 9x2
- 54x + 81; 0 = 5x2- 42x + 81; x =
= =
= = = 5.4 or = 3; 3 � x � 5.4
11c. Answers may vary. Sample: it is difficult to find theendpoint of the true section of the graph. 12a. Theserestrictions ensure the radicands are nonnegative.12b. The graph will show part of y = 1 above thedomain of the inequality. 12c. The solution will be x-values for which Y2 is beneath Y3, within the intervalshown by Y1.
TEST-TAKING STRATEGIES page 428
1. I: = ( )x; = ( )2
is true; = ( )-2
is true; II: = ; = is true; =
is not true; III: = ΔxΔ+ 1; =
Δ2Δ+ 1 is not true; = Δ-2Δ+ 1 is not true;
only statement I is true for both values of x.
2. = ( )x; = ( )0
is true; = ( )1
is true; II: = ; = ; is true;
= is true; III: = ΔxΔ+ 1;
= Δ0Δ+ 1 is true; = Δ1Δ+ 1 is not true; since
III is not true when x = 1, choice B, D, and E could be
eliminated as correct answers.3. Check each equation with the value x = 1; I: =
x; = x is true; II: = x; = 1 is true; III:
= x; = 1 is true; all three expressions are
equal to x when x = 1; the correct answer would be E.
4. I: ( )8= = = 31
= 3; statement I
is true; II:
( )8= = = � 3; statement II is
not true; III: = � ; statement III is not true;
the answer is A.
CHAPTER REVIEW pages 429– 431
1. In the expression , 8 is called the radicand. 2. In
the expression , 3 is called the index. 3. When yourewrite an expression so there are no radicals in anydenominator and no denominators in any radical, yourationalize the denominator. 4. The expressions
and are not examples of like radicals. 5. The
definition of rational exponents allows us to write =
. 6. If g(x) = x - 4 and h(x) = x2, (g + h)(x) =x2
- 4 is a composite function. 7. To multiplyexpressions you sometimes add rational exponents.8. If f and f -1 are inverse functions, then (f ° f-1(x)) =
x and ( f-1 + f )(x) = x. 9. + 2 = x is an(x 2 7)12
"3 727
23
!5 x
!x
!3 8
!3 8
53
1Q53R1
1Q35R21
3343
12 ? 14 ? 16aQ31
2R14b
6
"3 "3
312 ? 14 ? 81aQ31
2R14b
8
"3 "3
"3 14
"3 1"3 x4
"3 x
"3 13"3 x3"12"x2
"12 1 1
"02 1 1"x2 1 1"3 13"12"3 03"02"3 x3"x2
"3 2"3 21"3 2"3 20"3 2"3 2x
"(22)2 1 1
"22 1 1"x2 1 1"3 (22)3"(22)2"3 23"22"3 x3"x2
"3 2"3 222"3 2"3 22"3 2"3 2x
3010
5410
42 4 1210
42 4 !14410
42 4 !1764 2 162010
2(242) 4 "(242)2 2 4(5)(81)2(5)
Algebra 2 Solution Key • Chapter 7, page 213
example of a radical equation. 10. The positive even
root of a number is called the principal root.
11. = = 12 12. =
= -0.4 13. = 7 14. =
= 0.5 15. = = -3
16. = = 7Δxy5Δ
17. = = -4y3 18. =
= (a - 1)2 19. = =
3x3 20. = = (y + 3)2
21. = =
4x4y2 22. ? = = =
= 20 23. ? = = =
= 24. ? =
= = 10x2y
25. ? = = =
7x2 26. ? = =
= 15x3y2 27. ?
= = =
3(2xy) = 6xy 28. = = =
= 4 29. = = =
= 2y 30. = = =
= 5x 31. = =
= = 6xy
32. = = =
= 3a2b 33. ? =
= = 34. ? = =
= 35. ? = =
36. = = ? =
37. = = ? =
38. + - = + 5 - 2 =
(3 + 5 - 2) = 6 39. (5 + )(2 - ) =10 - 5 + 2 - 3 = 7 - 340. (7 - )(7 + ) = 49 - 6 = 4341. - + = -
2 + 3 = 2
42. ? = =42 2 12!3
49 2 12(7 2 2!3)(7 2 2!3)
6(7 1 2!3)
!2x!2x!2x!2x!18x!8x!2x
!6!6!3!3!3
!3!3!3!3!3!33!3!12!75!27
y!3 150x10x2
!3 25x!325x
y!3 6
2x"3 5x2Å3 6y3
5x512
"3 6x2y4
2"3 5x7y
a3!ab4b
!b!b
a3!a4!bÅ
a7
16b"2a7b2
"32b3
"3 5x2
x2"3 5x2
"3 x6"3 x2
"3 x2!3 5"3 x4
x!6x4
x2!6x4x
"6x5
"16x2!2!2
"3x5
"8x22!3
34!3
6!48
6
!6!6
!8!6
!3 b"3 33 ? (a2)3 ? b3 ? b
"3 27a6b4
Å3 81a8b5
3a2b"3 81a8b5
"3 3a2b
!3x"62 ? 3 ? x2 ? x ? y2"108x3y2
Å216 x3y2
2"216x3y2
!2"(5x)2
"25x2Å
75x33x
"75x3
!3x!3 y"3 23 ? y3 ? y
"3 8y4Å3 56y5
7y"3 56y5
!3 7y"42
!16Å128
8!128!8
!4 2y!4 2y
3"4 24 ? 2 ? x4 ? y4 ? y3"4 32x4y5"4 8xy5
3"4 4x3!x"152(x3)2 ? x ? (y2)2
"225x7y4"45x3y"5x4y3!2
"72 ? 2 ? (x2)2"98x4!14x"7x3
"3 12y210"3 12(x2)3y3 ? y210"3 12x6y5
5"3 6x4y42"3 2x2y6!3 2"3 63 ? 2
!3 432!3 12 ? 36!3 36!3 12"202
!400!10 ? 40!40!10!2xy
"2 ? 42 ? x ? (x4)2 ? y ? (y2)2"32x9y5
"3 f(y 1 3)2g3"3 (y 1 3)6
"5 (3x3)5"5 243x15"f(a 2 1)2g2"(a 2 1)4"3 (24y3)3"3 264y9
"72x2(y5)2"49x2y10
2"3 332!3 27"0.52
!0.25"4 74"3 (20.4)3
!320.064"122!144
43. ? = =
= - 44. = 45. =
46. = = 47. 30.2= =
48. p-2.25= = = 49. =
4= 34
= 81 50. = ( )3= 63
= 216
51. = x1= x 52. ? = =
53. = x-6y4= 54. = -5;
3x + 1 = (-5)3; 3x + 1 = -125; 3x = -126; x = -4255. = x + 1; x + 7 = (x + 1)2; x + 7 =
x2+ 2x + 1; x2
+ x - 6 = 0; (x + 3)(x - 2) = 0; x =
-3 (extraneous) or x = 2 56. - 3 = 8; = 11;x = 121 57. ( f + g)(x) = f(x) + g(x) = 2x + 5 +
x2- 3x + 2 = x2
- x + 7 58. f(x) - g(x) = 2x +
5 - (x2- 3x + 2) = -x2
+ 5x + 3 59. g(x) ? f(x) =(x2
- 3x + 2)(2x + 5) = 2x3+ 5x2
- 6x2-
15x + 4x + 10 = 2x3- x2
- 11x + 1060. (g - f)(x) = g(x) - f(x) = x2
- 3x + 2 -
(2x + 5) = x2- 5x - 3 61. = ,
62. (g + f )(-x) = g( f(-2)) = g((-2)2) =
g(4) = 4 - 3 = 1 63. ( f + g)(-2) = f(g(-2)) =f(-2 - 3) = f(-5) = (-5)2
= 25 64. ( f + g)(0) =f(g(0)) = f(0 - 3) = f(-3) = (-3)2
= 9
65. (g + g)(7) = g(g(7)) = g(7 - 3) = g(4) =
4 - 3 = 1 66. ( f + g)(c) = f(g(c)) = f(c - 3) =
(c - 3)2= c2
- 6c + 9 67. y = 6x + 2;inverse: x = 6y + 2; 6y = x - 2; y = x - ; yes
68. y = 2x3+ 1; inverse: x = 2y3
+ 1; 2y3= x - 1;
y3= ; y = ; yes 69. y = (x - 2)4;
inverse: x = (y - 2)4; 4 = y - 2; y = 4 + 2;no 70. y = ; inverse: x = ; x2
= y +
2; y = x2- 2, x � 0; yes 71. (f -1 + f )(5) = 5
72. (f -1 + f )(-5) = -5 73. ( f-1 + f )(6) = 6
74. (f-1 + f )(t) = t
75. y = + 3 76. y =
77. y = 78. y = !x 1 7 2 22 3!x 1 6
!x 2 1!x
!y 1 2!x 1 2!4 x!4 x
Qx 2 12 R1
3x 2 12
13
16
x 2 252
x2 2 3x 1 22x 1 5
g(x)f(x)
!xx12
!x 1 7
!3 3x 1 1y4
x6Ax23
8y14B16
x56x
161
23x
23x
16Ax3
4B43!3636
32A!5 243B
24345Å
4 1p9
1"4 p9p2
94
!5 3315Å
4 18
1"4 2322
34"3 x2
x23!5 33
15!2 1 !10
4!2 1 !10
24
!2 1 !101 2 5
(1 1 !5)(1 1 !5)
!2(1 2 !5)
42 2 12!337
Algebra 2 Solution Key • Chapter 7, page 214
42Ox
y6
4
2 �4�8 O x
y
4
42Ox
y
4
2
42O x
y
4
2
CHAPTER TEST page 432
1. = -0.3 2. =
= 3�x � y2
3. =
-2x2y4 4. = (x - 2)2
5. =
6. =
= 6x3y4
7. = = ? = =
8.
9.
=
10.
11.
=
-17 - 4 12. (7 + )(3 + 5 ) = 21 + 35 +
= 13.
= = =
14. = =
15. = =
16. = 17. =
= = = =
18. ; x - 3 = (x - 5)2;
x - 3 = x2- 10x + 25; x2
- 11x + 28 = 0;(x - 7)(x - 4) = 0; x - 7 = 0 or x - 4 = 0; x = 7or x = 4 (extraneous); x = 7 19. ;x + 4 = 3x; 2x = 4; x = 2 20. ;
3x + 4 = (-5)3; 3x + 4 = -125; 3x = -129; x = -4321. x - 6 = ; (x - 6)2
= x - 4; x2- 12x +
36 = x - 4; x2- 13x + 40 = 0; (x - 8)(x - 5) = 0;
x - 8 = 0 or x - 5 = 0; x = 8 or x = 6 (extraneous);x = 8 22. g(x) - f(x) = x2
- 3x + 2 - (x - 2) =x2
- 4x + 4; domain: all real numbers 23. -2g(x) +f(x) = -2(x2
- 3x + 2) + x - 2 = -2x2+ 6x - 4 +
x - 2 = -2x2+ 7x - 6; domain: all real numbers
24. = = = x - 1;
domain: all real numbers x 2 2 25. -f (x) ? g(x) =-(x - 2)(x2
- 3x + 2) = (2 - x)(x2- 3x + 2) =
2x2- 6x + 4 - x3
+ 3x2- 2x = -x3
+ 5x2- 8x + 4;
domain: all real numbers 26. f (g(x)) = f (4x + 1) =
(x 2 2)(x 2 1)x 2 2
x2 2 3x 1 2x 2 2
g(x)f(x)
(x 2 4)12
(3x 1 4)13 5 25
!x 1 4 5 !3x
!x 2 3 5 x 2 54x4"3 x2
9y6
4"3 (x4)3 ? x2
9y64"3 x14
9y622x624
3
32y6(!3 8)2x6y2
(!3 27)2x43y8
a 8x9y3
27x2y12b23
x161
13 5 x
12x
16 ? x
131
52 51
25
1("3 125)2(125)2
233 1 !2 1 !3 1 !6
!3 1 !2 1 3 1 !63 2 2
1 1 !3(!3 2 !2)
?(!3 1 !2)(!3 1 !2)
21 2 23!615 1 10!6
21515 1 10!6
9 2 24
(3 1 2!6)(3 1 2!6)
5(3 2 2!6)
?36 1 38!33!3 1 15
!3!3!3!5
3 2 6!5 1 2!5 2 20 52!5 2 2!1003!20 1
(1 2 !20) 5 3 2(3 1 2!5)12!2 2 !5
7!2 1 5!2 2 !5 5!5 5!98 1 !50 210!3 1 10!3 5 24!34!3 15(2!3)
4!3 1 2(5!3) 15!12 52!75 1!48 1
!6x 2 3x!26x
!6x!6x
5 !6x 2 "18x2
6x 51 2 !3x!6x
?
x!xy3y
"x3y3y
!y!yÅ
x39yÅ
7x4y63xy2
"7x4y
"63xy2
!2y"62 ? 2 ? (x3)2 ? (y4)2 ? y
"72x6y9 5"3y3 ? "4xy4 ? "6x5y2
7x2!2"(7x2)2 ? 2 5"7x3 ? !14x 5 "98x4
"(x 2 2)4 5 C(x 2 2)4D12"5 2x4
"5 264x14y20 5 "5 (22)5 ? 2 ? (x2)5 ? x4 ? (y4)5
!6xy"32 ? 6 ? x2 ? x ? (y2)2 ? y
"54x3y5!320.027 5 "3 (20.3)3
(4x + 1)2- 2 = 16x2
+ 8x + 1 - 2 = 16x2+ 8x - 1;
g(f(x)) = g(x2- 2) = 4(x2
- 2) + 1 = 4x2- 8 + 1 =
4x2- 7 27. f (g(x)) = f(-3x - 1) = 2(-3x - 1)2
+
(-3x - 1) - 7 = 2(9x2+ 6x + 1) - 3x - 1 - 7 =
18x2+ 12x + 2 - 3x - 8 = 18x2
+ 9x - 6; g( f (x)) =g(2x2
+ x - 7) = -3(2x2+ x - 7) - 1 = -6x2
- 3x +
21 - 1 = -6x2- 3x + 20 28. The sixth power of a
real number is always nonnegative. 29a. f(x) = 0.5x29b. g(x) = 0.75x 29c. g(g(x)) = g(0.75x) =0.75(0.75x) = 0.5625x 29d. The cashier’s solution istoo high by 6.25% of the original price.30. y = - 1; y = - 1; y =
4 - 1; the graph of y = 4 - 1 is thegraph of y = 4 , translated 5 units left and 1 unit
down. 31. y = ; y = ; y =
; the graph of y = is the graph of y =
3 , translated unit left.
32. y = 2 + 3
domain: real numbers � 0;range: real numbers � 3
33. y =
domain: real numbers � - ;
range: real numbers � 0
34. y = -
domain: real numbers � 4;range: real numbers � 0
35. y = - 4
domain: real numbers � - ;
range: real numbers � -436. f (g(-2)) = f (7(-2) - 4) = f (-18) = (-18)3
+
1 = -5831 37. g(f(3)) = g(33+ 1) = g(28) =
7(28) - 4 = 192 38. f(g(0)) = f (7(0) - 4) =
f (-4) = (-4)3+ 1 = -63 39. f(x) = 3x3
- 2,
or y = 3x3- 2; inverse: x = 3y3
- 2; 3y3= x + 2;
y3= ; y = ; ; yes f21(x) 5 Å
3 x 1 23Å
3 x 1 23
x 1 23
32
!x 1 3
!x 2 412
32
!2x 1 3
!x
13!x
3Åx 1 133Åx 1 1
3
Å9Qx 1 13R!9x 1 3
!x!x 1 5!x 1 5
!16(x 1 5)!16x 1 80
Algebra 2 Solution Key • Chapter 7, page 215
Ox
y
4
2
2 4
�2 2O x
y
2
�2
2O x
y
2
�2
�4 2Ox
y2
�4
�8
40. g(x) = - 1, or y = - 1;
inverse: x = - 1; = x + 1; y + 3 =
(x + 1)2; y = (x + 1)2- 3; g-1(x) = (x + 1)2
- 3; yes
41. g(x) = , or y = ;
inverse: x = ; x2= 2y + 1; 2y = x2
- 1;
y = ; g-1(x) = ; yes 42. f (x) = x4, or
y = x4; inverse: x = y4; 4x = y4; y = 4 ;
f-1(x) = 4 ; no 43a. V = p ? 43= �
268.08; about 268.08 in.3 43b. V = pr3; 3V = 4pr3;
= r3; r = , or r = 43c. r = �
2.88; about 2.88 in. 44. Check students’ work.
45. t = 0.2 � 0.6; about 0.6 seconds;
t = 0.2 � 0.9; about 0.9 seconds
CA STANDARDS MASTERY pages 433–435
Vocabulary ReviewA. III; radicand: the number under the radical sign in aradical expression B. II; index: the degree of the rootin a radical expression C. I; composite function: thecombination of two functions such that the output fromthe first becomes the input for the second D. V;inverse function: the range of one function is thedomain of the other and vice versa E. IV; radicalfunction: a function that can be written in the form f(x)= a + k
Multiple Choice
1. = ; this is true for w = 1, but false for w
= –1; the answer is B. 2. (x + 1)2= x2
+ 1; substitute
0 for x: (0 + 1)2= 0 + 1 is a true statement; substitute 1
for x: (1 + 1)2= 12
+ 1 is not a true statement; the
answer is B. 3. y = = ; A: when x � 0 and n �
0, y � 0 is valid for real values of y; the answer is A. 4.
= = = ; the answer is
C. 5. = 27; x + 2 = ( ; x + 2 = 34; x +
2 = 81; x = 79; the answer is C. 6. A: = ( ; B:
= ( = 32= 9; the answer is B. 7.
= ) ; the answer is A. 8. A: From 0 to 12
months, the dotted line representing Elbac cable is
below the solid line representing StableCable; Elbac
would cost less than StableCable if Lucinda used fewer
than 12 channels per month; the answer is B.9. (1) 2x + 3y - z = -2, (2) x - 4y + 2z = 18, (3) 5x +2y - 6z = 8; multiply (1) by 2 and add (2) to eliminatez:
(b32)"5 (1296a8
(b3)12(6a2)
45"3 27)227
23
"3 90)29023
"3 27)4(x 1 2)34
(3xy2)43y
23(3x)
23"3 9x2y4"6 81x4y8
x1n"n x
(w3)13(w4)
14
"3 x 2 h
!20
!10
Q3(100)4p R
13Q3V
4p R13
Å3 3V
4p3V4p
43
256p3
43!4 4x
!4 4x14
14
14
x2 2 12
x2 2 12
!2y 1 1
!2x 1 1!2x 1 1
!y 1 3!y 1 3
!x 1 3!x 1 3 2x + 3y - z = -2 u 4x + 6y - 2z = -4 x - 4y + 2z = 18 u x - 4y + 2z = 18
(4) 5x + 2y = 14
Multiply (1) by -6 and add (3) to eliminate z:2x + 3y - z = -2 u -12x - 18y + 6z = 12 5x + 2y - 6z = 8 u 5x + 2y - 6z = 8
(5) -7x - 16y = 20
Multiply (4) by 8 and add equations (4) and (5) toeliminate y:
5x + 2y = 14 u 40x + 16y = 112-7x - 14y = 20 u -7x - 16y = 20
33x = 132 x = 4
Substitute 4 for x into (4) and solve for y: 5(4) + 2y =14; 20 + 2y = 14; 2y = -6; y = -3; substitute 4 for xand -3 for y into (2): (4) -4(-3) + 2z = 18; 4 + 12 +2z = 18; 16 + 2z = 18; 2z = 2; z = 1; the answer is C.10. x = 5y − 1; x + 1 = 5y; y = ; the answer is B.
11. Use composition of functions to check each answer:
A: f(x) = x - 4; (f o g)(x) = (x - 3) - 4 = x - 7; B:
f(x) = x - 1; (f o g)(x) = (x - 3) - 1 = x - 4; C: f(x) =
x2- 1; (f o g)(x) = (x - 3)2
- 1 = x2 − 6x + 9 - 1 = x2
− 6x + 9 + 8; the answer is C. 12. g(1) = (1) – 3 = -2;
h(-2) = (–2)2+ 6 = 4 + 6 = 10; the answer is D. 13.
The florist has = 11,440 ways to choose the 6
of the 21 carnations; the answer is C. 14. There are
= 55 ways to choose 2 of the 11 pens, and
there are = 210 ways to choose 4 of the 10
pencils; 55 � 210 = 265 ways to choose pens and
pencils for class; the answer is C. 15. (x3)4+ (x2)3
=
x12+ (x2)3
= x12+ x6; step 2 is incorrect; the answer is B.
16. = ? ? = x3 ? ? = x3 ?
y2 ? ; step 3 is incorrect; the answer is C.17. f(x) − g(x) = 3x2 − 5x + 3 − (x − 1)2
= 3x2 − 5x + 3− x2
+ 2x − 1 = 2x2 − 3x + 2; the answer is A.18. f(g(x)) = (2x − 3)2 − 1 = 4x2 − 12x + 9 − 1 = 4x2 −12x + 8; the answer is D. 19. (1) 2x − y = 4 and (2) y =2 − x; substitute 2 − x for y in (1) and solve for x; 2x − (2 −x) = 4; 3x − 2 = 4; 3x = 6; x = 2; substitute 3 for x in (2)and solve for y; y = 2 − (2) = 0; (x, y) = (2, 0); the answeris B. 20. 3 + (x − 1) = 30; (x − 1) = 27; x − 1 =( ; x − 1 = 34; x − 1 = 81; x = 82; the answer is D.21. Check each ordered pair; A: (3, 0): 2(3) − 0 � 3 and2(3) + 0 ≥ 5; 6 � 3 and 6 � 5; B: (6, 1): 2(6) − 1 � 3 and2(6) + 1 ≥ 5; 11 � 3 and 13 � 5; C: (4, −1): 2(4) − (−1) � 3and 2(4) + (−1) � 5; 9 � 3 and 7 � 5; D: (0, −3): 2(0) −(−3) � 3 and 2(0) + (−3) � 5; 5 � 3 and −1 � 3; (0, –3) isnot a solution of the system; the answer is D. 22. x = y2
− 3; x + 3 = y2; y = ± ; the answer is C."x 1 3
"3 27)4
34
34
"3 z"3 z"3 y6"3 z"3 y6"3 x9"3 x9y6z
10!(10 2 4)!4!
11!(11 2 2)!2!
16!(16 2 9)!9!
x 1 15
Algebra 2 Solution Key • Chapter 7, page 216