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7/29/2019 2 d Finite Elements
1/15
CCOORRNNEELLLLU N I V E R S I T Y 1MAE 4700
FE Analys is for Mechanical & Aerosp ace Design
N. Zabaras (10/18/2012)
Fini te Element Analysis forMechanical and Aerospace Design
Prof. Nicholas Zabaras
Materials Process Design and Control LaboratorySibley School of Mechanical and Aerospace Engineering
101 Frank H. T. Rhodes Hall
Cornell University
Ithaca, NY 14853-3801
Email: [email protected]
URL: http://mpdc.mae.cornell.edu/
mailto:[email protected]://mpdc.mae.cornell.edu/http://mpdc.mae.cornell.edu/mailto:[email protected]7/29/2019 2 d Finite Elements
2/15
CCOORRNNEELLLLU N I V E R S I T Y 2MAE 4700
FE Analys is for Mechanical & Aerosp ace Design
N. Zabaras (10/18/2012)
Isoparametr ic f in i te elements
The basis functions used in the definition of the
mapping Te, do not have to be the same as those
used for the approximation of functions.
Let Mbe the number of basis functions used to define
Te and let Ne be the number of basis functions
(nodes) used in the approximation of functions. Polynomials used to define geometry can be of higher
order (M>Ne), equal (M=Ne) or lower (M
7/29/2019 2 d Finite Elements
3/15
CCOORRNNEELLLLU N I V E R S I T Y 3MAE 4700
FE Analys is for Mechanical & Aerosp ace Design
N. Zabaras (10/18/2012)
Sub -, iso - and super-parametr ic f in i te elements
7/29/2019 2 d Finite Elements
4/15
CCOORRNNEELLLLU N I V E R S I T Y 4MAE 4700
FE Analys is for Mechanical & Aerosp ace Design
N. Zabaras (10/18/2012)
Quadri lateral elements : B i-l inear
We use tensor product of
polynomials as discussed in
1D (Lagrange family)
1
2
3
4
1( , ) (1 )(1 )
4
1( , ) (1 )(1 )4
1( , ) (1 )(1 )
4
1( , ) (1 )(1 )
4
N
N
N
N
7/29/2019 2 d Finite Elements
5/15
CCOORRNNEELLLLU N I V E R S I T Y 5MAE 4700
FE Analys is for Mechanical & Aerosp ace Design
N. Zabaras (10/18/2012)
Quadr i lateral elemen ts: B i-quadrat ic
We use tensor product of
polynomials as discussed in
1D (Lagrange family)
Note that here we have one
internal node (9).
2 2 2 21 5
2 2 2 22 6
2 2 2 23 7
2 2 2 24 8
2 29
1 1( , ) ( )( ), ( , ) (1 )( )
4 2
1 1( , ) ( )( ), ( , ) ( )(1 )
4 21 1
( , ) ( )( ), ( , ) (1 )( )4 2
1 1( , ) ( )( ), ( , ) ( )(1 )
4 2
( , ) (1 )(1 )
N N
N N
N N
N N
N
7/29/2019 2 d Finite Elements
6/15
CCOORRNNEELLLLU N I V E R S I T Y 6MAE 4700
FE Analys is for Mechanical & Aerosp ace Design
N. Zabaras (10/18/2012)
Quadrat ic eigh t node element
These type of elements
are not derived from
tensor product of 1D
polynomials. They are
called serendipity
elements.
To derive the shape
function for node 1, we
need a polynomial that
vanishes on thefollowing lines:
1 ,1 ,1
21 5
22 6
23 7
24 8
1 1( , ) (1 )(1 )( 1 ), ( , ) (1 )(1 )
4 2
1 1( , ) (1 )(1 )( 1 ), ( , ) (1 )(1 )4 2
1 1( , ) (1 )(1 )( 1 ), ( , ) (1 )(1 )
4 2
1 1( , ) (1 )(1 )( 1 ), ( , ) (1 )(1 )
4 2
N N
N N
N N
N N
7/29/2019 2 d Finite Elements
7/15
CCOORRNNEELLLLU N I V E R S I T Y 7MAE 4700
FE Analys is for Mechanical & Aerosp ace Design
N. Zabaras (10/18/2012)
Quadratu re ru les
Quadrature rules are defined from the 1D Gauss rules
presented earlier as follows:
Here we re-labeled
(m,n) with a single
index
'
1 11 1
1 1 1
( , ) ( , )
( , ) ( , )i i l
N N N
n m n m l l l m n l
G d d G d d
G w w G w
1l
7/29/2019 2 d Finite Elements
8/15
CCOORRNNEELLLLU N I V E R S I T Y 8MAE 4700
FE Analys is for Mechanical & Aerosp ace Design
N. Zabaras (10/18/2012)
Triangu lar elemen ts
We first consider triangular with straight sides. We
consider the mapping from a right-isosceles master
triangle. By inspection, we can write the basis
functions as:
The coordinate mapping is then defined from:
1
2
3
( , ) 1
( , )
( , )
N
N
N
3
1
3
1
( , )
( , ) ,
jjj
jjj
x x N
y y N
7/29/2019 2 d Finite Elements
9/15
CCOORRNNEELLLLU N I V E R S I T Y 9MAE 4700
FE Analys is for Mechanical & Aerosp ace Design
N. Zabaras (10/18/2012)
Triangu lar elemen ts
Inverting this mapping gives:
Can you recognize these as the linear shape functions of
the 4 node quadrilateral element? (take nodes )
1
2
3
( , ) 1
( , )
( , )
N
N
N
3
1
3
1
( , )
( , ) ,
jjj
jjj
x x N
y y N
3 1 1 3 1 1
2 1 1 2 1 1
1( )( ) ( )( )2
1( )( ) ( )( )
2
e
e
e
areaof
y y x x x x y yA
y y x x x x y yA
2
3
1
( , )
( , )
1 ( , )
e
e
e
N x y
N x y
N x y
Using these, one can now easily compute
and thus the element stiffness and load
, , , ,| |Jx y x y
3 4
7/29/2019 2 d Finite Elements
10/15
CCOORRNNEELLLLU N I V E R S I T Y 10MAE 4700
FE Analys is for Mechanical & Aerosp ace Design
N. Zabaras (10/18/2012)
Area coo rdinates
The expressions for can
easily be interpreted as ratios of
areas. We will see this interpretation
to be useful in deriving higher order
triangular elements.
Let us join the points and (x,y)with the vertices of the triangles
and respectively. We denote
as the areas of the subtriangles
opposite node in and We define the area coordinates on
as: where is the
area of the master element.
, ,1
( , )
,e
,i ia a
,,e
, 1,2,3,iia i
A 1/ 2A
respectively.
1
2
3
1
7/29/2019 2 d Finite Elements
11/15
CCOORRNNEELLLLU N I V E R S I T Y 11MAE 4700
FE Analys is for Mechanical & Aerosp ace Design
N. Zabaras (10/18/2012)
Area coo rdinates
Since |J| is constant (the ratio of the
areas of and ), the map Te
transforms areas uniformly, thus:
This is only true for triangles withstraight sides.
1
2
3
1
,e ,
, 1,2,3,i i
ie
aai
AA
7/29/2019 2 d Finite Elements
12/15
CCOORRNNEELLLLU N I V E R S I T Y 12MAE 4700
FE Analys is for Mechanical & Aerosp ace Design
N. Zabaras (10/18/2012)
Area coo rdinates
tani cons t
0, 1,2,3.i i
Several interesting properties
of area coordinates are
shown in the figures.
At a given point, the line
is parallel to the
side of the elementopposite node i.
The boundary segments of
the element are defined by
The vertices of the triangle
are (1,0,0), (0,1,0) and
(0,0,1).
7/29/2019 2 d Finite Elements
13/15
CCOORRNNEELLLLU N I V E R S I T Y 13MAE 4700
FE Analys is for Mechanical & Aerosp ace DesignN. Zabaras (10/18/2012)
Higher-degree shape functions
The area coordinates on can be used to
determine higher degree shape functionsi ,
( ).i
Quadratic shape
functions
Cubic shape
functions
1 41 1 1 2
2 52 2 2 3
3 63 3 3 1
12 ( ), 4
2
12 ( ), 4
2
12 ( ), 4
2
N N
N N
N N
1 1 1 1
4 1 2 1
5 1 2 2
10 1 2 3
9 2 1( )( )
2 3 3
27 1( )2 3
27 1( )
2 3
27
N
N
N
N
7/29/2019 2 d Finite Elements
14/15
CCOORRNNEELLLLU N I V E R S I T Y 14MAE 4700
FE Analys is for Mechanical & Aerosp ace DesignN. Zabaras (10/18/2012)
Shape func t ions on tr iangles using area coord inates
The coordinate transformation is now having the form:
The calculations here defer from those used in
quadrilaterals because of the redundant areacoordinate
Calculation of derivatives proceeds as:
Alternatively, one can use and
proceed exactly as was done before for quadrilaterals.
1 2 3 1 2 31
1 2 3 1 2 31
( , ) ( , , ) ( , , )
( , ) ( , , ) ( , , ),
e
e
N
jjj
N
jjj
x x x N
y y y N
1 2 31 .
1 1 1 1 31 2
1 2 3
N N N N
x x x x
1 2 3 2 31 , , ,
7/29/2019 2 d Finite Elements
15/15
CCOORRNNEELLLLU N I V E R S I T Y 15MAE 4700
FE Analys is for Mechanical & Aerosp ace DesignN. Zabaras (10/18/2012)
Quadrature integrat ion form ulas for tr iang les
We use particular quadrature rules appropriate for the
area coordinates introduced earlier.int
1 2 3 2 3 1 2 3 1 2 31
intint s in
( , , ) ( 1 ) ( , , )N
l l l l l
egrationquadratureweightspo
G d d note G w
Linear Quadratic CubicPolynomials
up to thisdegree are
integrated
exactly