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3
Stemplots
• Start by exploring the data with Exploratory Data Analysis (EDA)
• A popular univariate EDA technique is the stem-and-leaf plot
• The stem of the stemplot is an number-line (axis)
• Each leaf represents a data point
You can observe a lot by looking – Yogi Berra
4
Stemplot: Illustration• 10 ages (data sequenced as an ordered array)
05 11 21 24 27 28 30 42 50 52 • Draw the stem to cover the range 5 to 52:
0| 1| 2| 3| 4| 5| ×10 axis multiplier
• Divide each data point into a stem-value (in this example, the tens place) and leaf-value (the ones-place, in this example)
• Place leaves next to their stem value• Example of a leaf: 21 (plotted)
1
5
Stemplot illustration continued …
• Plot all data points in rank order:
0|5 1|1 2|1478 3|0 4|2 5|02 ×10
• Here is the plot horizontally
8 7 4 25 1 1 0 2 0------------0 1 2 3 4 5------------Rotated stemplot
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Shape• “Shape” refers to the distributional pattern• Here’s the silhouette of our data
X X X X X X X X X X ----------- 0 1 2 3 4 5 -----------
• Mound-shaped, symmetrical, no outliers • Do not “over-interpret” plots when n is small
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Shape (cont.)Consider this large data set of IQ scores
An density curve is superimposed on the graph
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Kurtosis (steepness)
Mesokurtic (medium) Platykurtic (flat)
Leptokurtic (steep)
skinny tails
fat tails
Kurtosis is not be easily judged by eye
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Gravitational Center (Mean)• Gravitational center ≡
arithmetic mean • “Eye-ball method” visualize
where plot would balance on see-saw “– around 30 (takes practice)
• Arithmetic method = sum values and divide by nsum = 290n = 10
mean = 290 / 10 = 29
8 7 4 25 1 1 0 2 0------------0 1 2 3 4 5 ------------ ^ Grav.Center
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Central location: Median• Ordered array:
05 11 21 24 27 28 30 42 50 52
• The median has depth (n + 1) ÷ 2 • n = 10, median’s depth = (10+1) ÷ 2 = 5.5 • → falls between 27 and 28 • When n is even, average adjacent values
Median = 27.5
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Spread: Range• For now, report the
range (minimum and maximum values)
• Current data range is “5 to 52”
• The range is the easiest but not the best way to describe spread (better methods described later)
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Stemplot – Second Example• Data: 1.47, 2.06, 2.36, 3.43, 3.74, 3.78, 3.94, 4.42
• Stem = ones-place
• Leaves = tenths-place• Truncate extra digit
(e.g., 1.47 1.4)
|1|4|2|03|3|4779|4|4(×1)
Center: median between 3.4 & 3.7 (underlined) Spread: 1.4 to 4.4 Shape: mound, no outliers
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Third Illustrative Example (n = 25)
• Data: 14, 17, 18, 19, 22, 22, 23, 24, 24, 26, 26, 27, 28, 29, 30, 30, 30, 31, 32, 33, 34, 34, 35, 36, 37, 38
• Regular stemplot:|1|4789|2|223466789|3|000123445678×10
• Too squished to see shape
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Third Illustration; Split Stem • Split stem-values into two ranges, e.g., first “1”
holds leaves between 0 to 4, and second “1” will holds leaves between 5 to 9
• Split-stem|1|4|1|789|2|2234|2|66789|3|00012344|3|5678×10
• Negative skew now evident)
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How many stem-values?
• Start with between 4 and 12 stem-values
• Then, use trial and error using different stem multipliers and splits → use plot that shows shape most clearly
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Data range from 100 to 260 lbs:
×100 axis multiplier only two stem-values (1×100 and 2×100) too few
×100 axis-multiplier w/ split stem 4 stem values might be OK(?)
×10 axis-multiplier 16 stem values next slide
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Fourth Stemplot Example (n = 53)
10|016611|00912|003457813|0035914|0815|0025716|55517|00025518|00005556719|24520|321|02522|023|24|25|26|0(×10)
Shape: Positive skewhigh outlier (260)
Central Location: L(M) = (53 + 1) / 2 = 27 Median = 165 (underlined)
Spread: from 100 to 260
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Quintuple-Split Stem Values
1*|00001111t|2222222333331f|44555551s|6667777771.|8888888889992*|01112t|22f|2s|6(×100)
Codes for stem values:* for leaves 0 and 1 t for leaves two and threef for leaves four and fives for leaves six and seven. for leaves eight and nine
For example, 120 is: 1t|2(x100)
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SPSS Stemplot, n = 654
Frequency Stem & Leaf
2.00 3 . 0 9.00 4 . 0000 28.00 5 . 00000000000000 37.00 6 . 000000000000000000 54.00 7 . 000000000000000000000000000 85.00 8 . 000000000000000000000000000000000000000000 94.00 9 . 00000000000000000000000000000000000000000000000 81.00 10 . 0000000000000000000000000000000000000000 90.00 11 . 000000000000000000000000000000000000000000000 57.00 12 . 0000000000000000000000000000 43.00 13 . 000000000000000000000 25.00 14 . 000000000000 19.00 15 . 000000000 13.00 16 . 000000 8.00 17 . 0000 9.00 Extremes (>=18)
Stem width: 1 Each leaf: 2 case(s)
Because n large, each leaf represents 2 observations
3 . 0 means 3.0 years
Frequency counts
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Frequency Table
• Frequency ≡ count
• Relative frequency ≡ proportion
• Cumulative [relative] frequency ≡ proportion less than or equal to current value
AGE | Freq Rel.Freq Cum.Freq.
------+----------------------- 3 | 2 0.3% 0.3% 4 | 9 1.4% 1.7% 5 | 28 4.3% 6.0% 6 | 37 5.7% 11.6% 7 | 54 8.3% 19.9% 8 | 85 13.0% 32.9% 9 | 94 14.4% 47.2%10 | 81 12.4% 59.6%11 | 90 13.8% 73.4%12 | 57 8.7% 82.1%13 | 43 6.6% 88.7%14 | 25 3.8% 92.5%15 | 19 2.9% 95.4%16 | 13 2.0% 97.4%17 | 8 1.2% 98.6%18 | 6 0.9% 99.5%19 | 3 0.5% 100.0%------+-----------------------Total | 654 100.0%
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Class Intervals
• When data sparse, group data into class intervals
• Classes intervals can be uniform or non-uniform
• Use end-point convention, so data points fall into unique intervals: include lower boundary, exclude upper boundary
• (next slide)
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Class Intervals Freq Table
Class Freq Relative Freq. (%)
Cumulative Freq (%)
0 – 9 1 10% 10%
10 – 19 1 10 20
20 – 29 4 40 60
30 – 39 1 10 70
40 – 44 1 10 80
50 – 59 2 20 100%
Total 10 100% --
Data: 05 11 21 24 27 28 30 42 50 52