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8/8/2019 17253054 Math Integration
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LEARNING OBJECTIVESLEARNING OBJECTIVES
To understand the virtual loss of GM andTo understand the virtual loss of GM andthe calculations.the calculations.
To calculate the maximum trim allowedTo calculate the maximum trim allowedto maintain a minimum stated GM.to maintain a minimum stated GM.
To understand the safe requirements forTo understand the safe requirements fora ship prior enter into dry dock.a ship prior enter into dry dock. ToTo
understand the critical period during dryunderstand the critical period during drydocking process.docking process.
Font: Verdana, bold
Size: Min. 24
Slide design & Background:
Clear & Contrast
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Course Outline
Name of Course :Chief and Second
Engineer 3000 kW or more (Unlimited
Voyage) Course Code/Module : ECSU , Part
A
Subject : Mathematics and
Engineering Drawing
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Course Outline
Module Aims
To provide students with the familiarization to the fundamentals of calculus Mathematicsrequired for engineering practice and problem solving.
General Learning Objective - GLO
Recognize that integration is the inverse process of differentiation, and apply this knowledgeto determine the area/volume/work done.
Specific Learning Objectives - SLO Recognize that integration can be considered the reverse of differentiation
process.
Explain the integration of x, trigo. functions, 1/x, exponential functions.
Evaluate the constant of integration.
Perform the definite Integral.
Apply integration to find:
a. Area under curves. Volume of solid revolution
Work done
Mean & root mean square (rms) values
Centroid
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Course outline Instructional Hours
Lecture : 40 hours
Topics Hours
Integration as reverse of differentiation 2
Integration of functions: x,Trig,1/x, Exponential 8
Evaluation of constant of integration 4
Definite integral 6
Application of integral calculus to: 20
a. Area under curves.
b. Volume of solid revolutionc. Work done
d. Mean & root mean square (rms)
e. valuesCentroid20
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Course Outline
Integration as the Process of Summation
Integration as the Reverse of Differentiation
Integration of functions Applications of Integration : Areas Bounded
by Curves and Volumes of Revolution
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Teaching Methods -
Combination of combination of methods as necessary -lectures, practice
Assessment Methods
Lecturer Class Assessment 1 20 % Lecturer Class Assessment 2 20 %
Lecturer Class Assessment 3 20 %
Final Exam 40 %
RecommendedT
exts K A Stroud (1992), Engineering Mathematics ProgrammesAnd Problems
G.S.Sharma & I.J.S.Sarna (1992), Engineering Mathematics
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We know how to find the area of simple
geometric shapes such as the triangle below
Integration : Concept and Theory
y
x
21
1
2
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But how do we find the are of geometric object
which do not have straight edges ?
ba
x
y
f(x)
Integration : Concept and Theory
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So, how do we go about finding the area under
the curve f(x), between x=a and x=b ?
Well, we can divide the area under the curve into
separate rectangles «
« find the area of each rectangle «
« and then sum these areas in order to find an
approximate answer to area under curve
Integration : Concept and Theory
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Find area of each rectangle «
« then sum all areas between x=a and x=b
Integration : Concept and Theory
ba
x
y
f(x)
h
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Process of Integration
Integration is reverse of differentiation
In differentiation, if f(x)= then f`(x)= 4x . Thus the integral of
integration is the process of moving from f (̀x) to f(x). By similar
reasoning, the integral of.
Integration is a process of summation or adding parts together and an
elongated S, shown as, is used to replace the words µthe integral of¶. Hence,
from above,
µc¶ is called the arbitrary constant of integration
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Integrationis the reverse process of differentiation.
Power series integration,
increase the exponent by one
- (P NO2 )-n+1
and divide by the
new exponent.
-n+1
k t
1
= + C
Constant
of integration
- (P NO2 )-n dP NO2 = k dt
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The Fundamental Theorem of Calculus
If then f x dx F b F aa
b ( ) = ( ) − ( )∫ .
F x f x' ,( ) = ( )
If we know an anti-derivative, we can use it to find the
value of the definite integral.
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Integration of function
The general solution of integrals of the form
axnd x, where a and n are constants is given by:
This rule is true when n is f r actional, zero, or a
positive or negative integer , with the exception of n = -1.
).1( 1
1
{!
´ nC n
x
dx x
n
n
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Standard Integrals
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The integral of constant K is kx+c. for
example
Integr al of sever al terms = Sum of integr al of the separ ate terms
f or exemple
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Problems