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11.1 Antiderivatives and Indefinite Integrals A. Let’s figure out the formula. B. Those with rational or negative exponents C. Those that need expanding D. Those that need simplifying E. Word Problems

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Page 1: 125 11.1

11.1 Antiderivatives and Indefinite Integrals

A. Let’s figure out the formula.B. Those with rational or negative

exponentsC. Those that need expandingD. Those that need simplifying

E. Word Problems

Page 2: 125 11.1

A. Let’s figure out the formula.

.it of integral" indefinite"

get the and 4 the take to tryingbe willnext task Our

constant.any is C where,4

:say could I is, ermconstant t t thematter what doesn'it Since

4122 47 413

:ones basic heseConsider t

: thislike went sderivativefor rulepower theRecall

4

3

34

343434

1n

Cx

x

xCx

xxxxxx

nxx n

+

→+

→+→+→+

→ −

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? to4 fromget can we How 43 Cxx +

Cx

Cx

Cx

x

+=

+=

++

→+

4

4

133

4

4

13

44

First add one to its exponent. Then, divide the term by its new exponent. Last, add the + C.

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This is sort of undoing differentiation!

• It’s like we are answering the riddle: “What is the function whose derivative is this?”

++

=

+==

+

Cn

xdxx

Cxxdxx

nn

1

4 of integral indefinite" 4

1

433

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∫ ∫ dxxdxx 32 12 :You try 6

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( )

Cxxxx

Cxxxx

dx

dxdxxdxxdxx

dxxxx

++−+=

++−+

+−+

+−+

∫∫ ∫∫∫

76

73

3

4

4

6

7x.Answer 7?plain just of derivative a

have ouldfunction w What .7 is last term theNotice

sks.smaller ta 4 like each term, of integral the takei.e.,

734 as same theis

734

:by term Term

346

346

235

235

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+−+− dx

xxxx 14

3

223 :You try

5678

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B. Those with rational or negative exponents

• As you have seen before, sometimes it is necessary to REWRITE the problem in exponential form without negative exponents BEFORE using the rules.

• Examples of rewriting:

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∫∫ ∫

+⋅

34 3

4 32

6

3 3

4x

dxdx

xxdx

xx

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∫∫ ∫

+⋅

43 2

3 22

2

4 7

6

:You try

u

dudx

xxdt

tt

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C. Those that need expanding

• You know that you can integrate term-by-term. Sometimes you have to EXPAND things (F.O.I.L., distribute, etc.) before you can do the term-by-term thing.

• “Terms” are only connected to each other by plus signs. Nothing else.

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( ) ( )∫ ∫ −+ dxxdxx 33 1 :You try 2

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( ) ( )∫ ∫ −+ dxxxdxxx 322 1 :You try 2

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∫∫+−+++−

dxx

xxxxdx

x

xxxx 645 :You try

1464 245234

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D. Those that need simplifying

( ) ( ) ( ) Cxx

dxxdxx

xx ++=+=+

++∫ ∫ 3

23

5

53 2

•FACTOR TOP AND BOTTOM

•CANCEL VERTICALLY IF POSSIBLE

•INTEGRATE TERM BY TERM

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dxx

xx∫ −

−−1

23 :You try

2

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E. Word Problems

quantity for thefunction the change of rate

velocityon accelerati

distance velocity

curve theofequation the line tangent theof slope

functionsenue/cost profit/rev marginals

change of rate quantity any

onaccelerativelocity

velocity distance

line tangent theof slope curve

enue/costprofit/rev marginal enue/cost profit/rev

→→

→→

→→→

→→

:opposite the does nIntegratio So

:this does ationDifferenti

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( )function.cost theFind $1000. iscost fixed

theand 6 isfunction cost marginal scompany'A xxMC =

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zero.] ?production

zerofor in brought is revenuemuch How :C findingfor [Hint

function. revenue theFind units. ofnumber theis x where

,812 isfunction revenue marginal scompany'A 3 xxMR +=

Page 20: 125 11.1

zero.] minutes? zeroin

memorized becan many words How :C findingfor [Hint minutes. in

memorized becan that wordsofnumber totalfor the formula a Find

minute.per words3

of rate at the wordsmemorizecan person A

t

t

Page 21: 125 11.1

The marginal cost for producing x units of a product is modeled by 32 0.04 .

It costs $50 to produce one unit. Find the total cost of producing 200 units.

dCx

dx= −