10 12 Physics CBSE Paper Solution

8/13/2019 10 12 Physics CBSE Paper Solution

1/20

1111.. 1617, 1

& 2, 20, .

: 6544444, 3910727, 5025027, 9216144327

2013 :

3

Q1. B

.

S.

= , &

E.K

2

2= E.K2 =

K.E = 2 =

2

=

Q2. T .

I , .

S. T BC

Q3. T +4Q Q (, 0) (3, 0) .

2 ?

S. =00

Q4

+=

C

(A)

()

A

B

C

Q +4Q

O(3, 0) (2, 0) (2, 0)(, 0)


2/20

2222

: 3

.. 1617, 1& 2, 20, .

: 6544444, 3910727, 5025027, 9216144327

Q4. T

. I , ?

S. T & .

Q5. T , E, ,

R. ?

S. AB

RR

I

==

RI =

Q6. H

() D

() N ?

S. ()

.

() ,

l

ANNM 210

= N1& N2 .

Q7. D . S.I. .

S. T

. I N .

NR =

.

I S.I B (B) 1 1.

Q8.

. N .

S.

. R ()

4 1014H 8 1014H.

Q9. I , .

A

B

A'

B'

'

AB

C

FE

D

R


3/20

3333

: 3

.. 1617, 1& 2, 20, .

: 6544444, 3910727, 5025027, 9216144327

S. T

A B A' B' ' = A' + B' = '

0

1

0

1

1

0

0

1

1

0

1

0

0

1

1

0

1

1

1

0

0

0

0

1

A B & AND

= A B

Q10. E . H

D , ,

.

S. () : I

.

L . I

(). S

I = ..(1)

S

l=

I .

=

S N = .

S = N

F (1)

NI =

l

l I = =

L AB & E0

() E1

Er


4/20

4444

: 3

.. 1617, 1& 2, 20, .

: 6544444, 3910727, 5025027, 9216144327

R K .

L E1:

E1= 1l ..(1)

Now close key K and calculate balance length for V.

V = k 2l ..(2)

From (1) & (2)

2

11

E

l

l= ..(3)

= E1 I = I R

)R(R

E1 +=

= 1R

2

1

l

l

Q11. A 450

1.5 . I 3

. C

S. = 450 , D = 1.5

F 1= 3 = 3 103

D :

1= 10215

10103 33

=

, 1= = 1

1= , 1 1

3

9

1 102

10450

=

= 225.0

2

10450

6

=

=

Q12. I AM , ,

A B. .

S. B A B B B .

F (A) :

R

1

0

A B

G

A B

AM

()()

M

S

C


5/20

5555

: 3

.. 1617, 1& 2, 20, .

: 6544444, 3910727, 5025027, 9216144327

I () = B() + C2() B C

F (B) B : () B

, 2 2C , C+

)(2

A

)(2

A

MA)(

+

+=

Q13. A 1 2. F

.

. 1 .

2 .

S

21

1

1

1+= 2=

12

21

21

1

1

1

=

+=

Q14. D CE . S

.

S. :T ()

(IC) (I):

.. :I

. I R.

0I

I

R

=

=

Q15. A K

2/3, . F

.

S. A 2/3

.

N C1 C2

& .

I= 200 A

I= 150 A

I= 100 A

I= 50 A2.5

I

3.0

7.5

() CE0.5 1.0 1.5 2.0 2.5 3.0 3.5


6/20

6666

: 3

.. 1617, 1& 2, 20, .

: 6544444, 3910727, 5025027, 9216144327

/6 2/3 /6

A A

L (L)

S1

S2

PQ

IC

R

C1 & /3.

C2 & 2/3

21 C

1

C

1

C+=

1

A

3/2

A

3/

C

1

00 +

=

A3

2

A3

C

1

00 +

=

A3

)2(

C

1

0

+=

)2(

A3C 0

+

=

Q16. A , A ,

. S

.

S. C / IC

C / ID

C R

T IC= ID

EI 0D

=

I & E . A

.

A

E

0=

( ) =00

AA

=

I

0

0D =

=

ID= (1)

.

IC= ..(2)

F (1) & (2)

IC= ID

S1 S2. C S1

S2. S1 L IC S2 L ICS2

.

F S1 ID = 0 S1 IC.


7/20

7777

: 3

.. 1617, 1& 2, 20, .

: 6544444, 3910727, 5025027, 9216144327

C

A B

D

4A

6A

1

)II(.B DC0L

+= l )0I(.B C0L

+= l = 0IC ..(3)

F S2: IC = 0 S2 ID.

S, )II(.B DC0L

+= l D0L

I.B = l ..(4)

F (3) & (4)

IC= ID

Q17. A AB 6 A . A CD 4A

AB 1 . F CD

. G CD

AB. (T = 10 2)

S. L AB +

C AB = 6A

C CD = 4A

S = 1 = 103

T CD . F CD

AB .

L CD L

)B(IFr

lr=

( Br

) AB =3

AB0

10

I2

4

L410

I

4F

3

AB0CD

2

=

F CD =

3

0

10

L462

4

=

1010

41210

L

3

7

=

108.41048L

15 ==

A CD AB.

Q18. () F .., = , R

R2

1 2

.

() A 125 250 .. . C .

S. () = , ,

P = I , R =

I .. & I = 1

H, = 0


8/20

8888

: 3

.. 1617, 1& 2, 20, .

: 6544444, 3910727, 5025027, 9216144327

0IP = 2

=

22

P

=

2

I =

2

P = ..(1)

= R

S (1)

R2

P

2= ,

() P = 125 , = 250

P P &

R

P

2

=

R = 125

250250= 500

Q19. D I . A , .

()

.

() .

S.

() I

() I . A

.

, . E

&

. T

.

I

K

K

IF R


9/20

9999

: 3

.. 1617, 1& 2, 20, .

: 6544444, 3910727, 5025027, 9216144327

6

4

9

R1

G

& P .

Q20. D . SI . F

3 .

, R1/R2.

S. : C

. I :

C =

NBA

I=

I S.I. A1

I G

9

6

R

4

1

= 66

94R1 =

=

R1= 6

12

8

6

R2 = R2= =

4

12

816

R =2

3

4

6

R

R

2

1 ==

Q21. A LMNO 0.5 T. T

. MN 20

10 1, . G

5 ( ) .

8

R2

12

6

G

R2

6

8

12

G

3

G

4 R1

6 9

60

3.0

R2

6

8

12

G

3.0

1.20


10/20

10101010

: 3

.. 1617, 1& 2, 20, .

: 6544444, 3910727, 5025027, 9216144327

OR

A 8 50 120 /

E . T E

0.4 G 60. C

. H ?

S. = S.B = O

S.B=

=

B =

l B = 0.5 T, = 10 1

B l= = 20 = 20 102, R = 5

= B 210201010

5 = 1

= 1 R

I=

A2.05

1I == I = 0.2 A

O

N = 8

L = 50 102

= 120 = 2

B = 0.4 104T

A , = = 0

A =2

2

0 =

+

= B= l

2

B

= B= 0.4 10450 102 2105027

22

= 6.2 105

A . S

L

ON

M

Br


11/20

11111111

: 3

.. 1617, 1& 2, 20, .

: 6544444, 3910727, 5025027, 9216144327

Q22. () ? D .

() P. H

P ?

S. () L : L

.

S ,

. P

() L I0

I1 2

I0 . N

. T

I = I12( M)

I = 2.

Q23. D . D

.

.

S. M P: I

.

**M

N

II= I0/2 III= II2P

Q

P

Q

M

N

A

P

**I I0

I0/2P


12/20

12121212

: 3

.. 1617, 1& 2, 20, .

: 6544444, 3910727, 5025027, 9216144327

, =

F A'B'C A'B'C'

C'A

'B'A =

'C'A

'B'A =

A

=M C'A

'B'A

'C'A

'B'A

M =

0

'C'A

C'AM == ..(1)

F . S (1)

0

M =

L:

() I

() A .

Q24. E

.

B .

S. E

20

2

1 += .

0

2

2

1

20

2

1 +=

T

F O

E A'

0

C

C'

B'


13/20

13131313

: 3

.. 1617, 1& 2, 20, .

: 6544444, 3910727, 5025027, 9216144327

1. P 0

2. . : () S > 0 K.E.

. I ,

.

() I>0 0=2

1 2 K.E. .

()


14/20

14141414

: 3

.. 1617, 1& 2, 20, .

: 6544444, 3910727, 5025027, 9216144327

EB

+ A B

2

EA

P

EA

EB

EB

EA

()S Q27. () D . I ? D

.

() D . L

.

G

R () () .

P > R < R. (

.)

S. () E : I

lr 2 = , lr 2)( =

A .

L . P

.

EA EB + P BA EEErrr

+=

L BA E&Err

. EA EB

+= EEE BA

rrr

= ( ) + EE BArr

=2222

0

.

)(

4

12

++

2/3220

2/3220 )(4

)(4

2E

+=

+=

r

() P

BA += 0)(

)(

2222

=+

++

=

2

+


15/20

15151515

: 3

.. 1617, 1& 2, 20, .

: 6544444, 3910727, 5025027, 9216144327

S

() : C R O. L +

. T P OP = ,

S, O . G

.

A

0S

S.E

=

rr

0S

S

=

20 4

E

= 204

E

=

r

E

I : A . S

0

S.E

= , 0E=

r

() < R Er

& = R E

> R E

2

1E

2

E

+

E

r

= R

2

1E =

O

Er


16/20

16161616

: 3

.. 1617, 1& 2, 20, .

: 6544444, 3910727, 5025027, 9216144327

Q28. B ,

( ) ,

(). = 4 = 3, 2, 1,

O

()D (BE/A) A. .

() .() .

?

S. ,

= 1 = 2

.

& . S

1E = E 1 ,

E2= 2 .

= E2 E122

1

4222

222

4222

K2

K2 +

=

=

22

21

2

4222

1

1

K2

=

22

21

3

4222

1

1

K2

21 &

=

2

2

C

3

4222

1

1

K2

A

=

2

2

3

4222

1

1

K2

I = 4 = 1 L . I = 4 = 2 B . I = 4 = 3 P .


17/20

17171717

: 3

.. 1617, 1& 2, 20, .

: 6544444, 3910727, 5025027, 9216144327

/ / . .

1. A . T .

2. F 2 20, 2H4, 6C12, 8O16 . T

.

() R :

() ,

. T

/ .

() S, ,

. T

/ .

I .

() I B ,

01

11

10 H

++

D

.

Q29. () BS

.

() ? F N

I. S

.

()D . E . H

.

()A .() C ? G .

H2

H3

L6

H6C12

N14

O16

O18

S32

MO100I127 184

A197

238

B

/N(M)

50 100 150 200 250M (A)


18/20

18181818

: 3

.. 1617, 1& 2, 20, .

: 6544444, 3910727, 5025027, 9216144327

() ,

.

S. C . P

O. ,

. T M

N. C ldi M.

30

r

rdi

4Bd

rlr

r

=

A lr

d , rdr

lr . T

Bd r . T

220

20

xa

d

4

i

r

d

4

idB

+

=

=

ll

T ;2/322

0

)xa(4

diacosdB

+

=

l

N N.

B . T

M N . D

, P . T

P , , (), ..

+

= ld)xa(4

iaB

2/3220 = a2

)xa(4

ia2/322

0 +

B =2/322

20

)xa(2

ia

+

T .

() A . L I

C ( II) .

L ( II) Br

. L .

I.B 0L

= lrr

P

rr

0

M

N

B

B

l


19/20

19191919

: 3

.. 1617, 1& 2, 20, .

: 6544444, 3910727, 5025027, 9216144327

B2 = 02 I

B = 0I

L ( I) B1, 1 P

.

IB 0L

1

1

= lrr

I = L.

0B0.B ==r

l

rr

S, ( III) 2Br

. D L2 2

Q. N .

IB 0L

2

2

= lr

A I = 0

. S

I = 0 (1)

0B

2L2 =

l 0B

2=

r

() :T

,

, , K.E.

() A 2H4 1H1.

() C 2

BT1

==

N,

.

T2

1=

T

1=


20/20

: 3

()

B=

&

H,2

B

4

B2==

=

.

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10 12 Physics CBSE Paper Solution