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2
PR
OD
UC
ED
FLO
WR
AT
E
WE
LL O
UT
FLO
WR
ELA
TIO
NS
HIP
WE
LL I
NF
LOW
(IP
R)
SU
RF
AC
E P
RE
SS
UR
EA
t Wel
lhea
d
Pw
fP
wf
WE
LL F
AC
E
PR
ES
SU
RE
Res
ervo
ir P
ress
ure-
Pr
Req
uire
d P
o to
pro
duce
des
ired
rate
Req
uire
d P
o to
pro
duce
des
ired
rate
Po
Typ
ical
Oil
Wel
l –T
wo
Par
ts
Par
t 1 –
The
Wel
l
Par
t 2 –
The
Res
ervi
or
3
Pr
Pw
f
Pw
hP
sep
� ���P
PI
P
Q� ���
P
� ���P
0
500
1000
1500
2000
2500
3000
3500
050
010
0015
0020
0025
0030
0035
0040
0045
00
Pro
duct
ion
rate
, ST
B/D
Flowing bottomhole pressure, psi
Tubi
ng C
urve
Po
Par
t 1 –
The
Wel
l
Par
t 2 –
The
Res
ervi
or
5
Wel
l Bor
e F
luid
Cal
cula
tions
As
we
can
see
from
the
form
ula’
s th
e m
ost r
elev
ant
para
met
er to
wel
l bor
e ca
lcul
atio
n is
pre
ssur
e. T
here
fore
we
will
spe
nd s
ome
time
look
ing
at th
e ba
sics
of w
hat
pres
sure
is.
Wha
t is
pres
sure
?
Wha
t is
For
ce?
6
Wel
l Bor
e F
luid
Cal
cula
tions
In e
nglis
hun
its:
Mas
s =
lbm
Acc
eler
atio
n =
gra
vity
In E
nglis
h U
nits
lbm
= lb
f
Thi
s is
not
the
case
in m
etric
uni
ts
7
Wel
l Bor
e F
luid
Cal
cula
tions
We
have
dis
cuss
ed fo
rce
–w
hat i
s pr
essu
re?
Pre
ssur
e =
Am
ount
of f
orce
ove
r a
spec
ified
are
a
Thi
s is
ver
y im
port
ant i
n no
t onl
y un
ders
tand
ing
a w
ell,
but
desi
gnin
g ar
tific
ial l
ift. B
ecau
se a
s w
e ha
ve s
een
the
wel
l is
only
con
cern
ed w
ith p
ress
ure,
not
forc
e.
8
Wel
l Bor
e F
luid
Cal
cula
tions
Wha
t exe
rts
mor
e fo
rce?
a. 1
000
ft of
wat
er in
2 3
/8”
tubi
ngb.
100
0 ft
of w
ater
in 2
7/8
” tu
bing
Wha
t exe
rts
mor
e pr
essu
re?
a. 1
000
ft of
wat
er in
2 3
/8”
tubi
ngb.
100
0 ft
of w
ater
in 2
7/8
” tu
bing
9
Wel
l Bor
e F
luid
Cal
cula
tions
As
stat
ed p
ress
ure
is fo
rce
over
a s
peci
fic a
rea,
or:
P =
F /
A
In e
nglis
hun
its w
hen
deal
ing
with
pre
ssur
e no
rmal
ly th
e un
itsus
ed a
re:
F =
lbf
A =
in2
Pre
ssur
e =
lbf/i
n2(k
now
as
a ps
i)
10
Whe
n de
alin
g w
ith fl
uid
in a
tube
wha
t is
the
stan
dard
Pre
ssur
e ca
lcul
atio
n?
P =
For
ce/A
rea
Are
a =
πx
(ID
of T
ubin
g/2)
2=
ID A
rea
For
ce =
Mas
s x
Acc
eler
atio
n
Mas
s =
vol
ume
of fl
uid
x de
nsity
Vol
ume
of F
luid
= ID
Are
a x
HA
ccel
erat
ion
= g
ravi
ty
For
ce =
ID A
rea
x H
x d
ensi
ty x
gra
vity
P =
(ID
Are
a x
H x
den
sity
x g
ravi
ty)/
ID A
rea
= ρ
x g
x h
11
P =
ρ ρρρx
g x
h
For
pur
e w
ater
the
engl
ish
units
are
as
follo
ws:
ρ ρρρ=
62.3
lbm
/ft3
As
men
tione
d 1
lbm
= 1l
bf at
sta
ndar
d gr
avity
So
ρ ρ ρ ρ x
g fo
r w
ater
=
62.
3 lb
f/ft3
Gra
dien
t pre
ssur
e is
pre
ssur
e di
vide
d by
hei
ght
Rea
rran
ging
the
form
ula
P/h
=
ρ ρρρx
g
So
ther
efor
e th
e pr
essu
re g
radi
ent f
or w
ater
is 6
2.3
lbf/f
t3
Doe
s th
at lo
ok r
ight
?
12
We
know
that
P =
psi
= lb
f/ i
n2
We
know
that
1 ft
= 1
2 in
Wat
er G
rad
= 6
2.3
lbf/f
t3
= 6
2.3
lbf
x 1
ft
x 1
ft
(ft3
)
12 in
12 in
= 0
.433
__l
b f__
(in2
x ft)
= 0
.433
psi
/ft
Doe
s th
at s
ound
rig
ht?
13
So
for
Pur
e W
ater
P(p
si)
= 0
.433
x h
(ft)
For
all
othe
r flu
ids
we
use
spec
ific
grav
ity =
sg
Sg
= d
ensi
ty o
f a fl
uid
/ den
sity
of p
ure
wat
er
The
refo
re th
e st
anda
rd in
Eng
lish
is:
P(p
si)
= 0
.433
x s
g x
h(ft)
14
Spe
cific
Gra
vity
Ofte
n sp
ecifi
c gr
avity
com
es in
the
form
of
AP
I, to
cov
ert
the
follo
win
g is
use
d:
sg =
141.
5
131.
5+A
PI
Whe
n tw
o liq
uids
of d
iffer
ent d
ensi
ty m
ake
one
fluid
, the
Spe
cific
gra
vity
is c
alcu
late
d as
follo
ws:
Sp
. G
r. =
wf o
+×
()
γγ
×)
(o
fw
15
For
mul
as S
o fa
r
sg =
141.
5
131.
5+A
PI
Sp
. G
r. =
wf
o+
×(
)γ
γ×
)(
of
w
P(p
si)
= 0
.433
x s
gx
h(ft)
Pre
ssur
e du
e to
flui
d:
AP
I to
sg:
Com
posi
te s
g:
16
Exe
rcis
e 1a
Oil
Den
sity
:
30 A
PI
Wat
er c
ut:
0%W
ater
Den
sity
:1.
026
sgP
res:
3765
psi
gP
whe
ad:
100
psia
PI:
10 s
tb/d
/psi
Bo:
1.33
rb/
stb
TV
D:
9183
feet
Fin
d P
outfl
owfo
r th
e ab
ove
cond
ition
s(a
ssum
e no
fric
tion)
17
Exe
rcis
e 1b
Oil
Den
sity
:
30 A
PI
Wat
er c
ut:
30%
Wat
er D
ensi
ty:
1.02
6 sg
Pre
s:37
65 p
sig
P w
head
:10
0 ps
iaP
I:10
stb
/d/p
siB
o:1.
33 r
b/st
bT
VD
:91
83 fe
et
Fin
d P
outfl
owfo
r th
e ne
w w
ater
cut
18Wel
l Per
form
ance
Pre
ssur
e gr
adie
nt p
lots
Dep
th
Pre
ssur
eP
o (0
%)
Po
(30%
)P
wh
Po
(30%
) R
equi
red
for
100
psi
wel
lhea
d pr
essu
re =
376
1 ps
i
Po
(0%
)Req
uire
d fo
r 10
0 ps
iw
ellh
ead
pres
sure
= 3
582
psi
19
For
this
cou
rse
we
are
goin
g to
mak
e th
e as
sum
ptio
n th
at fl
uid
alw
ays
flow
s fr
om h
igh
pres
sure
tow
ard
low
pre
ssur
e.
Som
e of
you
may
rec
ogni
ze th
at th
is is
not
exa
ctly
tr
ue.
The
exa
ctly
true
exp
ress
ion
is fl
uid
alw
ays
flow
s fr
om h
igh
pote
ntia
l tow
ard
low
pot
entia
l.
Wel
l Pro
duct
ivity
20
The
diff
eren
ce b
etw
een
"pre
ssur
e" a
nd "
pote
ntia
l" is
th
e el
evat
ion
(or
heig
ht)
and
the
elev
atio
n po
tent
ial c
an b
e ca
lcul
ated
from
the
equa
tion
−−
ρ ∗
g *
h.
We
have
alre
ady
seen
how
pr
essu
re in
crea
ses
with
the
dept
h in
a c
olum
n of
flui
d.
6"
14.7
psi
14.9
psi
Wel
l Pro
duct
ivity
21
Inflo
w –
Dar
cy’s
Exp
erim
ents
The
rel
atio
nshi
p be
twee
n pr
essu
re a
nd F
low
rate
was
firs
t st
udie
d ex
tens
ivel
y by
the
scie
ntis
t Hen
ry D
arcy
(1
803-
1858
).H
e cr
eate
d pr
essu
re d
iffer
entia
ls a
cros
s a
poro
us m
edia
and
m
easu
red
the
resu
lting
flow
rat
es th
at r
esul
ted
from
thos
e pr
essu
res.
His
exp
erim
ents
res
ulte
d in
wha
t is
now
kno
wn
as ‘
Dar
cy’s
La
w’ (
1856
) an
d ar
e th
e be
nchm
ark
for
perm
eabi
lity.
In
fact
, th
e un
it of
per
mea
bilit
y is
cal
led
the
‘Dar
cy’ (
D).
P0
P1
Dire
ctio
n of
Flo
wPer
mea
ble
Med
ium
: A
rea,
Len
gth,
Per
mea
bilit
yF
luid
Pro
pert
ies:
Vis
cosi
ty, V
olum
e F
acto
r
22
Dar
cy’s
Law
For
gen
eral
flow
thro
ugh
poro
us M
edia
:
01
**
()
*
kA
PP
QL
µ−
=
But
we’
re w
orki
ng w
ith o
il re
serv
oirs
, not
gen
eral
po
rous
med
ia…
23
Dar
cy's
Law
for
radi
al fl
ow in
to a
wel
lbor
e:
Pw
f
Pr
Pr
Pr Q
=?
Res
ervo
ir O
uter
"dr
aina
ge"
boun
dary
Flu
id F
low
Flu
id F
low
Flui
d Fl
ow
Fluid Flow
Flui
d Fl
ow
24
Dar
cy's
Law
for
radi
al fl
ow in
to a
wel
lbor
e:
For
the
syst
em ju
st d
escr
ibed
, Dar
cy's
Law
look
s lik
e:
qo
= flo
w r
ate
k
o=
effe
ctiv
e pe
rmea
bilit
yh
= e
ffect
ive
feet
of p
ay
µ µµµo
= av
erag
e vi
scos
ityP
r=
rese
rvoi
r pr
essu
re
P
wf
= w
ellb
ore
pres
sure
re=
drai
nage
rad
ius
r
w=
wel
lbor
e ra
dius
Bo
= fo
rmat
ion
volu
me
fact
or
Not
e: (
Pr
-P
wf)
is th
e dr
awdo
wn
pres
sure
qk
hP
P
Br
o
or
wf
oo
e
w
=7.
08 x
10
S
-3 ln
()
µr
25Dar
cy's
Law
for
radi
al fl
ow in
to a
wel
lbor
e:
If w
e m
ake
the
assu
mpt
ion
that
ko,
h, r
e, r
w, B
o a
nd
µοar
e co
nsta
nt fo
r a
part
icul
ar w
ell t
he e
quat
ion
beco
mes
:
qk
kP
P
kk
o
1r
wf
54
6
7
=ln
kk2
3k
k8
()
Sim
plify
ing.
..
qK
PP
or
wf
=−
()
26Dar
cy's
Law
for
radi
al fl
ow in
to a
wel
lbor
e:
Q -
Flow
Rat
e (B
PD
)
Pre
ssur
e -
PS
I Inte
rcep
t = P
r
Slo
pe =
-1/
K
0
0
Pw
f
27Dar
cy's
Law
for
radi
al fl
ow in
to a
wel
lbor
e:
The
Pro
duct
ivity
Inde
x (P
I) is
equ
al to
the
flow
ra
te d
ivid
ed b
y th
e "d
raw
dow
n":
PI
q o=
PP r
wf
−(
)
PI
xq o
=P
P rw
f−
()
28Exa
mpl
eD
arcy
's L
aw fo
r ra
dial
flow
into
a w
ellb
ore:
Con
side
r th
e fo
llow
ing
exam
ple:
Pr=
2,3
00 p
si, a
nd
Pw
f=
1,2
00 p
si @
qo
= 1
,150
bpd
Wha
t is
the
Pro
duct
ivity
Inde
x (P
I) o
f the
wel
l?
PI =
23
00
-12
00
()
11
50
= 1
.046
bbl
/day
/psi
29Dar
cy's
Law
for
radi
al fl
ow in
to a
wel
lbor
e:
Wha
t is
the
max
imum
flow
rat
e th
e w
ell w
ill p
rodu
ce?
T
he m
axim
um fl
ow r
ate
occu
rs a
t the
max
imum
dr
awdo
wn
(Pw
f = 0
).
PI
=q m
ax 0
P r−
()
orq m
ax
P rP
I=
x
23
00
x1.
046
= 2
40
6 B
PD
q ma
x=
30Dar
cy's
Law
for
radi
al fl
ow in
to a
wel
lbor
e:
The
str
aigh
t-lin
e P
I wor
ks g
reat
for
sing
le p
hase
flui
d (i.
e. w
ater
, oil,
or
wat
er/o
il*)
flow
ing
into
a w
ellb
ore,
but
w
hat h
appe
ns if
gas
com
es "
out o
f sol
utio
n" in
the
rese
rvoi
r?
* E
ven
thou
gh w
ater
and
oil
are
two
sepa
rate
pha
ses,
th
ey a
re c
onsi
dere
d si
ngle
pha
se s
ince
they
are
bot
h liq
uid.
31Dar
cy's
Law
for
radi
al fl
ow in
to a
wel
lbor
e:
Wha
t hap
pens
whe
n th
e ga
s co
mes
out
of s
olut
ion?
D
arcy
's la
w w
orks
just
as
wel
l for
a s
ingl
e ph
ase
gas
as it
doe
s fo
r a
sing
le p
hase
oil.
Let's
look
qua
litat
ivel
y at
wha
t will
hap
pen
to th
e flo
w
rate
of g
as.
qk
hP
P
Br
g
gr
wf
gg
e
w
=7.
08 x
10
0.75
-3 lnµ
r
33Dar
cy's
Law
for
radi
al fl
ow in
to a
wel
lbor
e:
Q -
Flow
Rat
e (B
PD
)
Pre
ssur
e -
PS
I
00
Pw
f
Gra
phic
ally
it w
ould
look
like
this
:
Pr
< P
b
Dar
cy's
law
pred
icte
dQ
max
Act
ual
Qm
ax
34
We
use
inst
ead
Vog
el's
IPR
cur
ve.
The
equ
atio
n is
:
whe
re q
o(m
ax)
is th
e m
axim
um fl
ow r
ate
the
wel
l ca
n pr
oduc
e.
Inflo
w P
erfo
rman
ce R
elat
ions
hip
-IP
R:
Q(m
ax)
=1
-0.
2-
0.8
2
Pwf r
PQ
Pwf r
P
35
Con
side
r ou
r pr
evio
us e
xam
ple…
Pr=
2,30
0 ps
iP
wf=
1,20
0 ps
i @ q
o=
1,15
0 bp
d
Inflo
w P
erfo
rman
ce R
elat
ions
hip
-IP
R:
36
Firs
t we
need
to c
alcu
late
Q/Q
max
:
Inflo
w P
erfo
rman
ce R
elat
ions
hip
-IP
R:
Q(m
ax)=
1 -
0.2
-0.
82
1200
2300
1200
2300
1150
-bpd
= 1
696
bpd
Q(m
ax)
=1
-0.
2-
0.8
2
Pwf r
PQ
Pwf r
P
Q(m
ax)
=Q
=
0.67
8
0.67
8T
hen…
37
Com
pare
this
to th
e Q
max
we
got f
rom
Dar
cy's
equ
atio
n of
240
6 bp
d. T
he w
ell h
as lo
st 7
10 b
pd (
~-30
%)
in c
apab
ility
due
to g
as
inte
rfer
ence
.
Inflo
w P
erfo
rman
ce R
elat
ions
hip
-IP
R:
Vo
gel vs
. P
I fo
r g
iven
test
po
int
0
50
0
10
00
15
00
20
00
25
00
05
00
10
00
15
00
20
00
25
00
30
00
Q (
bp
d)
Pwf (psi)
38
We
saw
that
we
coul
d us
e D
arcy
's la
w w
hen
gas
was
not
a
prob
lem
(P
wf >
Pb)
.
We
also
saw
how
to u
se V
ogel
's IP
R fo
r ca
ses
whe
re P
wf <
P
b.
Wha
t abo
ut a
cas
e w
here
Pr
is a
bove
Pb
and
Pw
fis
less
th
an P
b?
Com
bine
d IP
R
39
All
we
have
to d
o in
this
cas
e is
use
Dar
cy's
law
for
Pr
> P
wf >
Pb
and
Vog
el's
IPR
for
the
port
ion
whe
re P
b >
Pw
f > 0
.
Let's
say
, for
our
pro
blem
, we
have
a P
b of
180
0 ps
i.
Gra
phic
ally
it w
ould
look
like
:
Com
bine
d IP
R
40Com
bine
d IP
R:
0
500
1000
1500
2000
2500
050
010
0015
0020
00
Flo
w R
ate
-B
PD
Pre
ssur
e -
psi
Pr=
2300
Pb=
1800
We
use
a st
raig
ht li
ne P
I abo
ve P
b
We
use
VO
GE
L be
low
Pb
Qto
t-m
ax =
Qb
+ Q
v
Qv
Qb
Qb
= P
I x (
Pr-
Pb)
Qv
= P
I x P
b / 1
.8
Pw
f =0
.125
x P
b {-
1+[8
1-80
(q-q
b)/(
qtm
x-qb
)]^.
5}
41
Vog
el's
rel
atio
nshi
p w
orks
rea
sona
bly
wel
l for
wat
er
cuts
bel
ow 5
0%.
For
hig
her
wat
er c
uts,
a m
etho
d ha
s be
en d
evel
oped
w
hich
take
s an
arit
hmet
ic a
vera
ge o
f the
PI a
nd IP
R
equa
tions
to y
ield
a "
com
posi
te IP
R“.
For
a g
iven
PW
F, t
here
fore
, Com
posi
te p
redi
cts
mor
e flo
w th
an V
ogel
but
less
flow
than
str
aigh
t-lin
e P
I.
Com
posi
te V
ogel
IPR
:
42
q o(m
ax)
Flo
w R
ate
-B
PD
Pre
ssur
e
Wat
er P
I
Oil
IPR
Com
posi
teIP
R
q w(m
ax)
q t(m
ax)
�F
inal
ly, w
e ca
n co
nsid
er b
oth
com
bine
d (s
trai
ght-
line
plus
cur
ve)
and
com
posi
te o
n th
e sa
me
IPR
.
�G
raph
ical
ly it
wou
ld lo
ok li
ke th
is, w
here
qtis
the
com
posi
te fl
ow:
Com
posi
te a
nd C
ombi
ned
IPR
:
The
“S
kin”
effe
ct(v
an E
verd
inge
n&
Hur
st)
Ski
n is
a w
ellb
ore
phen
omen
on, t
hat c
ause
s an
add
ition
al p
ress
ure
drop
in
the
near
-wel
lbor
e re
gion
:
Sh
k
Bq
S hkq
po
oo
oosk
inµ
πµ2.
141
2)
(=
=∆
44Dar
cy's
Law
for
radi
al fl
ow in
to a
wel
lbor
e:
In s
ome
case
s, th
e P
I can
als
o be
impr
oved
slig
htly
by
acid
izin
gor
frac
turin
g. A
cidi
zing
clea
ns u
p "s
kin"
on
the
perf
orat
ions
and
can
impr
ove
poro
sity
in li
mes
tone
re
serv
oirs
by
mak
ing
larg
er h
oles
for
oil f
low
.
Ski
n D
amag
eA
cid
Bef
ore
Afte
r
45Dar
cy's
Law
for
radi
al fl
ow in
to a
wel
lbor
e:
Fra
ctur
ing
can
also
impr
ove
perm
eabi
lity
by m
akin
g la
rge
crac
ks n
ear
the
wel
lbor
e.
Bef
ore
Afte
r
47Wel
l Per
form
ance
Pre
ssur
e gr
adie
nt p
lots
Dep
th
Pre
ssur
eP
o (0
%)
Po
(30%
)P
wh
Po
(30%
) R
equi
red
for
100
psi
wel
lhea
d pr
essu
re =
376
1 ps
i
Po
(0%
)Req
uire
d fo
r 10
0 ps
iw
ellh
ead
pres
sure
= 3
582
psi
Thi
s is
out
flow
Now
let’s
incl
ude
inflo
w
Pre
s
48
If th
e de
sire
d flo
w r
ate
is 1
000
BP
D d
o w
e ne
ed a
rtifi
cial
lift?
Cal
cula
te P
wfa
t 100
0 B
PD
49
Rem
embe
r ou
r D
ata
-E
xerc
ise
1aO
il D
ensi
ty:
30
AP
IW
ater
cut
:0%
Wat
er D
ensi
ty:
1.02
6 sg
Pre
s:37
65 p
sig
P w
head
:10
0 ps
iaP
I:10
stb
/d/p
siB
o:1.
33 r
b/st
bT
VD
:91
83 fe
et
Fin
d P
wfat
a fl
ow ra
te o
f 100
0 B
PD
(ass
ume
no fr
ictio
n)
50Wel
l Per
form
ance
Pre
ssur
e gr
adie
nt p
lots
Dep
th
Pre
ssur
eP
res
Po
(0%
)P
o (3
0%)
Pw
h
Po
(30%
) R
equi
red
for
100
psi
wel
lhea
d pr
essu
re =
376
1 ps
i
Po
(0%
)Req
uire
d fo
r 10
0 ps
iw
ellh
ead
pres
sure
= 3
582
psi
Pw
fava
ilabl
e at
100
0 B
PD
=
366
5 ps
i
Pw
f
52
Art
ifici
al L
ift O
ptio
ns
ES
P-C
reat
es h
ead
(� ���
P)
to lo
wer
Pw
f
GA
S L
IFT
-R
educ
es fl
uid
colu
mn
grad
ient
to lo
wer
Pw
f
PC
P-C
reat
es h
ead
(� ���
P)
to lo
wer
Pw
f
JET
PU
MP
-pro
vide
s pr
essu
re d
rop
in v
entu
rito
low
er
Pw
f
RO
D P
UM
P-I
nter
mitt
ently
suc
ks fl
uid
from
wel
l bor
e lo
wer
ing
Pw
f
ALL
INC
RE
AS
E D
RA
WD
OW
N T
O P
RO
DU
CE
FLO
W
53
Cash Flow Cash Flow
Tim
eT
ime
Art
ifici
al
Art
ifici
al
Lift
Lift
••M
ake
good
wel
ls b
ette
rM
ake
good
wel
ls b
ette
r
••G
ener
ate
mor
e re
venu
e ea
rlier
in th
e lif
e G
ener
ate
mor
e re
venu
e ea
rlier
in th
e lif
e of
a p
roje
ctof
a p
roje
ct
Fie
ld D
evel
opm
ent
54
Cash Flow Cash Flow
Tim
eT
ime
Art
ifici
al
Art
ifici
al
Lift
Lift
Pro
duct
ion
Pro
duct
ion
Opt
imiz
atio
nO
ptim
izat
ion
••D
ata
enab
led
syst
ems
Dat
a en
able
d sy
stem
s
••In
form
atio
n to
dec
isio
n m
aker
sIn
form
atio
n to
dec
isio
n m
aker
s
Pro
duct
ion
Opt
imiz
atio
n