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- Data Put Markers and Trait Data into box below OR Composite Interval Mapping Program
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Simulation
- Type of Study
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Composite Interval Mapping Program
F2
Backcross
- Genetic Design
- Data and Options
Means sigma^2
QTL positionsin each group
N
Haldane
KosambiMap Function
Parameters Here for Simulation Study Only
QTL Searching Step cM
H2
Calculate H2 or Sigma2 Back
Cumulative Marker Distance (cM)
Composite Interval Mapping Program
- Data
Back
Put Markers and Trait Data into box below OR Simulate Data
Composite Interval Mapping Program
- Analyze Data
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Analyze
Regression ModelMixture Model
Composite Interval Mapping Program
For CIM, Controlled Background Markers by Within cM Or Markers
- Profile
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LR
IM CIM1 CIM2 CIM3 CIM4 CIM5
Composite Interval Mapping Program
Help True Pars Save
- Permutation Test
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#Tests
Test
Cut Off Point atLevel Is Based on Tests.
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Composite Interval Mapping Program
Backcross Population – Two Point
Freq Qq qq
Mm 1/2 (1-r)/2 r/2
mm 1/2 r/2 (1-r)/2
Backcross Population – Three Point
Freq Qq qq
Mm Nn (1-r)/2 (1-r1)(1-r2) r1*r2
Mm nn r/2 (1-r1)r2 r1 (1-r2)
mm Nn r/2 r1 (1-r2) (1-r1)r2
mm nn (1-r)/2 r1*r2 (1-r)/2
M Q N
F2 Population – Two Point
Freq QQ Qq qq
MM 1/4 (1-r)2/4 (1-r)r/2 r2/4
Mm 1/2 (1-r)r/2 ½-(1-r)r (1-r)r/2
mm 1/4 r2/4 (1-r)r/2 (1-r)2/4
F2 Population – Three PointFreq QQ Qq qq
MM NN (1-r)2/4 1/4(1-a)2(1-b)2 1/2a(1-a)b(1-b) 1/4a2b2
Nn (1-r)r/2 1/2(1-a)2b(1-b) 1/2a(2b2-2b+1)(1-a)
1/2a2b(1-b)
nn r2/4 1/4(1-a)2b2 1/2a(1-a)b(1-b) 1/4a2(1-b)2
Mm NN (1-r)r/2 1/2a(1-a)(1-b)2 1/2b(1-2a+2a2)(1-b)
1/2a(1-a)b2
Nn ½-(1-r)r a(1-a)b(1-b) 1/2(2b2-2b+1)(1-2a+2a2)
a(1-a)b(1-b)
Nn (1-r)r/2 1/2a(1-a)b2 1/2b(1-2a+2a2)(1-b)
1/2a(1-a)(1-b)2
mm NN r2/4 1/4a2(1-b)2 1/2a(1-a)b(1-b) 1/4(1-a)2b2
Nn (1-r)r/2 1/2a2b(1-b) 1/2a(2b2-2b+1)(1-a)
1/2(1-a)2b(1-b)
nn (1-r)2/4 1/4a2b2 1/2a(1-a)b(1-b) 1/4(1-a)2(1-b)2
M a Q b Nr=a+b-2ab
Composite model for interval mapping and regression analysis
yi = + a* zi + km-2bkxik + ei
Expected means:Qq: + a* + kbkxik = a* + XiB
qq: + kbkxik = XiB
Xi = (1, xi1, xi2, …, xi(m-2))1x(m-1)
B = (, b1, b2, …, bm-2)T
zi: QTL genotypexik: marker genotype
M1 x1
M1m1 1 +b1
m1m1 0
zi – conditional probability of Qq given markers of individual i and QTL positionxik – coding for ‘effect’ of k-th marker of i
Backcross: xik =1 if k-th marker of i is Mm =0 or –1 if k-th marker of i is mm
km-2 – summation over all markers except
two markers of current interval
We want estimate a* and test if abs(a*) is big enough to claim that there is a QTL at the given location in an interval. The estimate B is not very important
Likelihood based CIML(y,M|) = i=1
n[1|if1(yi) + 0|if0(yi)]log L(y,M|) = i=1
n log[1|if1(yi) + 0|if0(yi)]
f1(yi) = 1/[(2)½]exp[-½(y-1)2], 1= a*+XiBf0(yi) = 1/[(2)½]exp[-½(y-0)2], 0= XiB
Define1|i = 1|if1(yi)/[1|if1(yi) + 0|if0(yi)] (1)0|i = 0|if1(yi)/[1|if1(yi) + 0|if0(yi)] (2)
a* = i=1n1|i(yi-a*-XiB)/ i=1
n1|i (3) = 1 (Y-XB)´/c
B = (X´X)-1X´(Y-1a*) (4)
2 = 1/n (Y-XB)´(Y-XB) – a*2 c (5)
= (i=1n21|i +i=1
n30|i)/(n2+n3) (6)
Y = {yi}nx1, = {1|i}nx1, c = i=1n1|i
Hypothesis testH0: a*=0 vs H1: a*0
L0 = i=1nf(yi) B = (X´X)-1X´Y, 2=1/n(Y-XB)´(Y-XB)
L1= i=1n[1|if1(yi) + 0|if0(yi)]
LR = -2(lnL0 – lnL1)LOD = -(logL0 – logL1)
Likelihood based CIM for BC and F2L(y,M|) = i=1
n k=1g [k|ifk(yi)]
log L(y,M|) = i=1n log[k=1
g k|ifk(yi)] g=2 for BC, 3 for F2fk(yi) = 1/[(2)½]exp[-½(y-k)2], k= g
k +XiB k=1,…,g
Define
k|i = k|if1(yi)/[k=1g k|if1(yi)] (1)
B = k=1g k(X´X)-1X´(Y- g
k ) (2)
gk = i=1
nk|i(yi-XiB)/ i=1nk|i (3)
2 = 1/n i=1n k=1
g k|i(yi-XiB - gk )2 (4)
Y = {yi}nx1, k = {k|i}nx1