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A scientist has studied the amount of PTC tasters in a population. PTC tasting is dominant. From one population, 500 individuals were sampled. The scientist found the following individuals: AA = 110, Aa = 350; aa = 40.
Calculate the genotypic and allelic frequencies for the PTC gene at this population.
Determine the genotypic and allelic frequencies expected at Hardy-Weinberg equilibrium using the homozygous recessive. Is this population in Hardy-Weinberg equilibrium? Is the population evolving?
Bellringer-March 23, 2015
AA = 110, Aa = 350; aa = 40. AA = 110/500 = 0.22; Aa=350/500 = 0.70 ; aa=
40/500= 0.08 A=110 + 110 + 350 = 570/1000 = 0.57; a = 40 + 40 + 350 = 160/1000 = 0.43
A) Actual population
p=A= PTC taster q= a = PTC non-taster 40/500= 0.08 = PTC non-taster = aa= q2
√0.08=√q2
q = 0.28 then p = 0.72 RR = p2 = (0.72)2 = 0.52 = 52.00% Rr = 2pq = 2(0.72)(0.28) = 0.40= 40.00% rr = q2 = (0.28)2 = 0.08 = 8.00%
b) Hardy-weinberg
Green color (G) is dominant to white color (g) in turtles.
In a population of 200 turtles, 13% are white.
A) What are the allele frequencies?B) What percentage of each genotype are in
this population? C) How many turtles are heterozygous?
Problem #2
G= Green g= white White = 13% = 0.13 = gg= q2
√0.13=√q2
A) q = 0.36 then p = 0.64B) GG = p2= (0.64)2=0.4096= 40.96% Gg = 2pq= 2(0.64)(0.36)=0.4608= 46.08% gg = q2= (0.36)2= 0.1296= 12.96%C) (.4608)(200) = 92 turtles are heterozygous
ANSWER KEY
1. Geographic isolation2. Reproductive barriers (isolation)3. Change in chromosome numbers
through mutation4. Adaptive radiation (example of
divergent evolution)
Speciation = formation of NEW species
Why don’t similar species interbreed??
Two general modes of speciation determined by the way gene flow among populations is initially
interrupted:Geographic and Reproductive Isolation
Speciation can occur in two ways:◦Geographic: Allopatric speciation (means
“other”) a genetic isolation WITH a geographical
barrier; new group isolated from its parent population
◦Reproductive: Sympatric speciation (means “together”) genetic isolation WITHOUT a geographical
barrier; a reproductive barrier isolates population in SAME habitat
Allopatric speciation Sympatric speciation
http://bcs.whfreeman.com/thelifewire/content/chp24/2402001.html
http://www.pbs.org/wgbh/nova/evolution/evolution-action-salamanders.html
Reproductive Isolationbiological factors (barriers) that stop 2 species from producing viable, fertile hybrids
Two types of barriers◦Postzygotic “after the zygote” Zygote can NOT develop
◦Prezygotic “before the zygote” Sperm and egg can not fuse
2 species encounter each other rarely, or not at all, because they live in different habitats, even though not isolated by physical barriers
Sympatric: Habitat Isolation
Species that breed at different times of the day, different seasons, or different years cannot mix their gametes
Sympatric: Temporal Isolation
Late WinterLate Summer
Courtship rituals and other behaviors unique to a species are effective barriers
Sympatric: Behavioral Isolation
http://wps.aw.com/bc_campbell_biology_7/26/6661/1705356.cw/index.html
Morphological differences can prevent successful mating
Related species may attempt to mate but CAN’T anatomically incompatible
Sperm = transfer
Sympatric: Mechanical Isolation
Mating organs don’t fit
Sperm of one species may not be able to fertilize eggs of another species
Ex: specific molecules on egg coat adhere to specific molecules on sperm
Sympatric: Gametic Isolation
Genes of the different parent species may interact and impair the hybrid’s development
Hybrids are very weak and/or underdeveloped
Reduced Hybrid Viability
Salamander hybrid shows
incomplete development