Click here to load reader

ΔΙΑΛΕΞΗ 9 Θεμελιώσεις με πασσάλους Αξονική φέρουσα ικανότητα έγχυτων πασσάλων

  • View
    57

  • Download
    0

Embed Size (px)

DESCRIPTION

ΔΙΑΛΕΞΕΙΣ ΤΟΥ ΜΑΘΗΜΑΤΟΣ « ΘΕΜΕΛΙΩΣΕΙΣ » 7ο Εξ. ΠΟΛ-ΜΗΧ. ΕΜΠ - Ακαδ. Ετος 200 7 - 0 8. ΔΙΑΛΕΞΗ 9 Θεμελιώσεις με πασσάλους Αξονική φέρουσα ικανότητα έγχυτων πασσάλων. 6. 2 .200 8. 2. Αξονική φέρουσα ικανότητα μεμονωμένου πασσάλου 2.2 Εγχυτοι πάσσαλοι (φρεατοπάσσαλοι). - PowerPoint PPT Presentation

Text of ΔΙΑΛΕΞΗ 9...

  • 9 7 . -. - . 2007 - 086.2.2008

  • 2. 2.2 () : ( )1.1 DIN 40141.2 AASHTO1.3 2.

  • DIN 4014 :fsu = qpu = : : :1. (qpu ) : 1.1 - (qc = CPT) :* :qc = 2.5m 3D (D=)

    qc (MPa)qpu (MPa) 100 ()102153203.5 254

  • qc / N (qc MPa) Burland and Burbridge 1. (qpu ) : 1.1 - (qc = CPT) : CPT, qc SPT ( ) qc / N (qc MPa) DIN 4014

    qc / N 0.3 0.4 0.5 0.6 0.5 1.0 0.8 1.0

  • 1. (qpu ) : 1.2. (cu = ) :* 2. ( fsu ) : 2.1. - :* :cu = 2.5m 3D (D=)qc = CPT

    cu (kPa)qpu (MPa)001000.8 2001.5

    qc (MPa)fsu (kPa)005401080 15120

  • 2. ( fsu ) : 2.2. (cu = ) :* 3. (qpu ) ( fsu ) (qu = ) : * : D

    cu (kPa)fsu (kPa)252510040 20060

    qu (MPa)fsu (kPa)qpu (MPa)< 0.5 0.5801.5550052050010

  • DIN 4014 : : : : fsu = 45 kPa : qc = 0.5 N = 0.5 x 45 = 22.5 MPa fsu = 120 kPa qpu = 3.75 MPa : :Qsu = 3.14 x 0.80 x (45 x 12 + 120 x 3) = 1356.5 + 904.3 = 2261 kNAp = 3.14 x 0.82 / 4 = 0.5024 m2Qpu = 0.5024 x 3750 = 1884 kN : Qu = Qsu + Qpu = 2261 + 1884 = 4145 kN : , = 18 kN/m3 : cu = 125 kPa : , = 20 kN/m3 SPT N = 45

  • 2. 2.2 () : ( )1.1 DIN 40141.2 AASHTO (2002)2. 1. (qpu ) : 1.1 - :1.2 :cu = L = = ( ) : AASHTO (2002) :qpu : MPaN = SPT : = 20 qpu = 1.17 MPa

  • 2. ( fsu ) : 2.2 - & :2.1 :cu = v = fsu AASHTO (2002) :

    z (m) 0 1.5m1.201.5 26m 26m0.25

    Chart2

    0

    1

    1.5

    2

    3

    4

    5

    6

    7

    8

    9

    10

    12

    14

    16

    18

    20

    22

    24

    26

    28

    30

    40

    z ( m)

    Sheet1

    01.2

    11.2

    1.51.2

    21.1535176772

    31.0756475521

    41.01

    50.9521633455

    60.899875013

    70.8517909288

    80.8070353544

    90.765

    100.7252419733

    120.6512951043

    140.5832939402

    160.52

    180.4605530317

    200.404326691

    220.3508481388

    240.299750026

    260.2507402192

    280.25

    300.25

    400.25

    Sheet1

    0

    0

    0

    0

    0

    0

    0

    0

    0

    0

    0

    0

    0

    0

    0

    0

    0

    0

    0

    0

    0

    0

    0

    z ( m)

    Sheet2

    Sheet3

  • 3. (qpu ) ( fsu ) (qu = ) : O ( fsu ) (qu)ci = GSI = RMR : ci = 20 MPa, GSI = 40 qu = 1.92 MPa fsu = 317 kPa qpu = 3 qu = 3 x 1.92 qpu = 5.76 MPaO (qpu) :qpu = 3 qu AASHTO (2002) :

  • AASHTO : : : , = 18 kN/m3 : cu = 125 kPa : , = 20 kN/m3 SPT N = 45 : : fsu = 0.55 cu = 69 kPa : : :Qsu = 3.14 x 0.80 x (69 x 12 + 147.6 x 3) = 2080 + 1112 = 3192 kNAp = 3.14 x 0.82 / 4 = 0.5024 m2Qpu = 0.5024 x 2637 = 1325 kN : Qu = Qsu + Qpu = 3192 + 1325 = 4517 kNqpu = 58.6 N = 58.6 x 45 =2637 kPa

  • 2.2 :1.3. (qpu) Meyerhof (1976) :qpu ( ) = ( 0.33 0.50 ) qpu ( ) 1.2. (fsu) Meyerhof (1976) :fsu ( ) = ( 0.33 0.50 ) fsu ( ) 1.1. (fsu) Touma & Reese (1974) : : = 0.7 = ( ) , ( = ) 1. :

  • 2.1. (qpu) Meyerhof (1976) : ( ), , . : . ( Meyerhof) :2.2 :2. () : = 0 : 0 :

  • 2.2. / ( 0) Meyerhof (1976) :2.2 : :OCR = - = 15 - 20 = 2. () :

  • 2.3. ( = 0) Weltman & Healy (1978) :cu = 2.2 :2. () : 20%

  • QQsQsnQp :1. (.. :2. ( ) : (Q) ( ) : , (Q) ( )

  • (FS) Qu = QsQp (Qmax) Qu : (.. , ) :FS = (> 1) :

  • (FS) :E :1. Tomlinson : :2. (DIN 1045) : ( ) : FS = 2 ( ) : FS = 1.5 , (.. ) : FS = 1.03. FS AASHTO :*

    2.25 3.50 *2.00 2.502.00

Search related