第七章 状态变量分析法

• View
123

0

Embed Size (px)

DESCRIPTION

Text of 第七章 状态变量分析法

PowerPoint 2 xif(t)
(7.1-5)
(7.1-9)
(7.1-11)
(7.1-12)
(7.1-13)
(7.1-14)

nmf1 ,f2 , … ,fmLy1 ,y2 , … ,yL

Axxaijjxjixi
Bf(t)x biixi
1

MATLAB

z p k=tf2zp(b,a) %
A B C D=zp2ss(z p k) %

KVL
8.1-10 8.1-4

(8.2-6)

(8.2-6)
(8.2-8)
B=8/3 -3/2 -1/6;
C=1 1 1;
D=0; num,den=ss2tf(A,B,C,D)
A(s)=det(sI-A) (8.2-9)

p1=-1, p2=-2p1p2AN×NNdet(zI-A)A(s)MATLABAA(s)
8.2-3 A ,
eig(A)% [WTHZ]A[WTBZ]
ans =
-3
-4
-1
(8.3-3)
(8.3-5)w1(n)w2(n)… , wN(n)x(n)8.3-1(8.3-6)y(n)w1(n)w2(n)…, wN(n)7.3-1n+1n

y(n)
(8.3-9)
(8.3-10)

(8.3-11)
(8.3-12)

Aw(n)w(n+1)aijjwjiwi(n+1)
Bx(n)w(n+1)biiwi(n+1)

8.3-2 MATLAB

8.3-2
MATLAB
sos =8 -1.5196 0 1 -0.25 0;1 -0.31 1.3161 1 -1 0.5;
A B C D=sos2ss(sos)

(8.3-13)
(4) Dh(0)

H(z)

Wi(z)=Zwi(n)X(z)=Zx(n)Y(z)=Zy(n)

(8.4-10)
(7.4-10)
(8.4-11)
B=1 0 0′;
C=6 5 -1;
D=8; num,den=ss2tf(A,B,C,D)
A=1.25 -0.75 0.125; 1 0 0; 0 1 0;
B=1 0 0′;
C=6 5 -1;
8.3-2
A(z)AA AH(z)A1
(8.4-12)
z1=1z2>1
8.4-3 ,
A MATLAB
eig(A)% A
AB
nLTI
rankM=n
rankM=n
B1=0 1′; %8.5-2(1)B
B2=1 0′; %8.5-2(2)B
B3=1 2′; %8.5-2(3)B
nLTI

1

a=-1 0 0;1 -4 0;1 -1 -3;
b=1 0 0′;
c=1 -1 1;
MATLAB
A=-1 0 0;1 -4 0;1 -1 -3; B =1 0 0′;
C=1 -1 1;

P1,A1=eig(A) %A
P1()0 0 3;0 1 1;1 1 1 P()
P1=0,0,3;0,1,1;1,1,1; % P1
inv(P1)*A*P1
(8.2-5)Px(t)w(t)

Documents
Documents
Documents
Documents
Documents
Documents
Documents
Documents
Documents
Technology
Documents
Documents
Documents
Documents
Documents
Documents
Documents
Documents
Documents
Documents
Documents
Documents
Documents
Documents
Documents
Documents