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第五部分 选择结构程序设计. 0x1C. 0x18. 0x14. 0x10. 0x0C. 0x08. 0x04. 0x00. 提纲. 第五章 选择结构程序设计. if 语句. 1. Switch 语句. 2. 3. 程序举例. FIQ. IRQ. (Reserved). Data Abort. Prefetch Abort. Software Interrupt. Undefined Instruction. Reset. ARM Vector Table. 5.1 C 控制 语句. if( )~else~ switch - PowerPoint PPT Presentation
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ARM Vector TableFIQIRQ(Reserved)Data AbortPrefetch AbortSoftware InterruptUndefined InstructionReset132Switch if
(95.1 C
5.2
5.2
5.2
5.2
A,B,A1.An5.2
ififif (expression) statementif (x>y) printf(%d,x);5.3 if
if (x>y) printf(%d,x);if (expression) statement1 else statement2if (x>y) max=x; else max=y;/**/ if (x>y) {max = x; } else {max = y; }5.3 if
if ( expr1 ) statement1else if (expr2 ) statement2else if (expr3 ) statement3...[ else statementn ] 5.3 if
if (salary>1000) {index=0.4;} else if (salary>800) index=0.3; else if (salary>600) index=0.2; else if (salary>400) index=0.1; else index=0; 5.3 if
if(a==b&&x==y) printf(a=b,x=y); if(3) printf(OK); if(a) printf(%d,a);if if(x) if(x!=0) if(!x) if(x==0)
: #include main() { int x,y; scanf(%d,%d,&x,&y); if(x>y) x=y; y=x; else x++; y++; printf(%d,%d\n,x,y); }{},Compile Error!5.3 if
/*ch5_1.c*/#include main(){ int x,y; printf("Enter an integer:"); scanf("%d",&x); y=x; if(yabsolute value :125.3
/*ch5_2.c*/#include main(){ int a,b; printf("Enter integer a:"); scanf("%d",&a); printf("Enter integer b:"); scanf("%d",&b); if(a==b) printf("a==b\n"); else printf("a!=b\n");} Enter integer a:12 Enter integer b:12 a==b Enter integer a:12 Enter integer b:9 a!=b 5.3
if5.3
if ~ else { }elseif5.3 if
if (a==b) if(b==c) printf(a==b==c); else printf(a!=b); if (a==b) { if(b==c) printf(a==b==c); } else printf(a!=b);if ~ else { }5.3
switch( ){ case E1: 1; break; case E2: 2; break; . case En: n; break; [default: ;;]} switch5.3
5.3 switch
E1,E2,En,breakcase{ }switchcase case A: case B: case C: printf(score>60\n); break; ..5.3 switch
switch(score) { case 5: printf(Very good!); case 4: printf(Good!); case 3: printf(Pass!); case 2: printf(Fail!); default : printf(data error!); }score5 Very good! Good! Pass! Fail! data error!
5.3 switch
void main() { int x=1,y=0,a=0,b=0; switch(x) { case 1: switch(y) { case 0: a++; break; case 1: b++; break; } /*break;*/ case 2: a++;b++; break; case 3: a++;b++; } printf(\na=%d,b=%d,a,b); }a=2,b=15.3 switch
/*ch5_5.c*/#include main(){ int c; printf("Enter m or n or h or other:"); c=getchar(); switch(c) { case 'm': printf("\nGood morning!\n");break; case 'n': printf("\nGood night!\n"); break; case 'h': printf("\nHello!\n"); break; default : printf("\n????????\n"); break; }} switch
main( ){int a,b,c; scanf(%d%d%d,&a,&b,&c); if(a>b) if(b>c) printf(%d,%d,%d,a,b,c); else if(a>c) printf(%d,%d,%d,a,c,b); else printf(%d,%d,%d,c,a,b); else if(a>c) printf(%d,%d,%d,b,a,c); else if(b>c) printf(%d,%d,%d,b,c,a); else printf(%d,%d,%d,c,b,a); }3,55
main(){ int y,m,d,date,flag=1; printf(input year,month,day:); scanf(%d,%d,%d,&y,&m,&d); 1.(),55
switch(m) { case 1:date=0;break; case 2:date=31;break; case 3:date=31+28;break; case 4:date=31+28+31;break; case 5:date= 31+28+31+3 0;break; case 6:date= 31+28+31+30+31;break; case 7:date= 31+28+31+30+31 +30;break; case 8:date= 31+28+31+30+31 +30+31;break; case 9:date= 31+28+31+30+31 +30+31 +31;break; case 10:date= 31+28+31+30+31 +30+31 +31 +30;break; case 11:date= 31+28+31+30+31 +30+31 +31 +30 +31;break; case 12:date= 31+28+31+30+31 +30+31 +31 +30 +31 +30;break; default: printf(input error of month!);flag=0; }
if((m>2)&&((y%4==0)&&(y%100!=0)||(y%400==0))) date++; /*2*/date+=d; /**/if(flag==1) printf(year=%d,month=%d,date=%d--no=%d\n, y, m, d, date);}
#includemain(){ float a,b,c,s,area; scanf(%f%f%f,&a,&b,&c); if(a+b>c&&b+c>a&&c+a>b) //3.,
if(a+b>c&&b+c>a&&c+a>b) { s=0.5*(a+b+c); area=sqrt(s*(s-a)*(s-b)*(s-c)); printf(area=%6.2f,area); if(a==b&&b==c) { printf();} elseif(a==b||b==c||a==c) {printf();} elseif((a*a+b*b==c*c)||(a*a+c*c==b*b) ||(b*b+c*c==a*a)) {printf();} else {printf();} } else {printf() ;}}
main(){ float value1,value2,value3; char op; printf(\nType in your expression:); scanf(%f%c%f,&value1,&op,&value2); // 4.number1 operator number2,operator+,-*,/,numberfloat
switch(op){ case+:value3=value1+value2; break; case-:value3=value1-value2; break; case*:value3=value1+value2; break; case/:if(value2==0) {printf(\nDivision by zero!); exit(1); } value3=value1/value2; break; default:printf(Unknown operator !); exit(0);}printf(Tsis is%6.2f%c%6.2f\n, value1,op,value2,value3 );}
55( P1001045.55.7:5.35.10
,ARM