응축터빈을 이용한 증기사이클[1]

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- 1. www.aew.kr () .2. .1. - 1: P1=5.0 kPa, v1f=0.00101 m3/kg h1f=137.606 kJ/kg, h1g=2561.5 kJ/kg - 2: h2=h1+v1(P2-P1)=137.606+0.00101(1600-5.0) = 139.2 kJ/kg - 3: P3=1.6 MPa, T3=201.4 () h3=2794.0 kJ/kg s3=6.4218 kJ/kgK - 4 ( ) P4=5.0 kPa, s4=s1f+x4(s1fg) ( 25%) h4=h4f+x4(h4fg)=137.606+0.751(2561.5-137.606) =1957.95 -------------------------------------------- Wcomp = h2-h1 = 139.2-137.6 = 1.61 kJ/kg Qin = h3-h2 = 2794.0-139.2 = 2654.8 kJ/kg Wexp = h3-h4 = 2794.0-1957.95 = 836.05 kJ/kg Wnet = Wexp-Wcomp = 836.05-1.61 = 834.44 kJ/kg = Wnet/Qin = 834.44/2654.8 = 0.314 (31.4%) ---------------------------------------------- (MPa) () (%) (h4) (kJ/kg) Wexp=h3-h4 (kJ/kg) (kJ/kg.K) 0.005 32.9 10 2319.1 474.9 7.60 0.005 32.9 20 2076.7 717.3 6.810.005 32.9 24.9 1958.0 836.0 6.42 0.005 32.9 30 1834.3 959.7 6.020.005 32.9 50 1349.5 1444.5 4.440.005 32.9 70 864.8 1929.2 2.850.005 32.9 90 380.0 2414.0 1.270.005 32.9 100 137.6 2656.4 0.48(kJ) - (%)473.3 17.8715.7 27.0834.4 31.4958.1 36.11442.9 54.31927.6 72.62412.4 90.92654.8 1002. - 1: P1=0.005 MPa 1-a : v1f=0.00101 m3/kg h1-a=137.606 kJ/kg 1-b : + 25% h1-b=2561.5+0.25 kJ/kg - 2: P2=1.6 MPa 2-a : h2-a=h1+v1(P2-P1)=137.606+0.00101(1600-5.0) = 139.2 kJ/kg 2-b(): + 1/3 1.6 Mpa h2-b=0.75*2561.5+0.25*137.6 = 1957.95 kJ/kg - 3: P3=1.6 MPa, T3=201.4 () h3=2794.0 kJ/kg s3=6.4218 kJ/kgK - 4 ( ) P4=5.0 kPa, s4=s1f+x4(s1fg) ( 25%) h4=h4f+x4(h4fg)=137.606+0.751(2561.5-137.606) =1957.95 (MPa) () (%) (h4) (kJ/kg) Wexp=h3-h4 (kJ/kg) (kJ/kg.K) 0.005 40.3 10 2319.1 474.9 7.60 0.005 40.3 20 2076.7 717.3 6.810.005 40.3 24.9 1958.0 836.0 6.42 0.005 40.3 30 1834.3 959.7 6.020.005 40.3 50 1349.5 1444.5 4.440.005 40.3 70 864.8 1929.2 2.850.005 40.3 90 380.0 2414.0 1.270.005 40.3 100 137.6 2656.4 0.48 (kJ) - Qin (%) -836.0 0 0 -779.3 180.4 180.5 100557.3 887.2 886.7 100334.9 1594.3 1594.2 100112.7 2301.3 2301.3 1001.61 2654.8 2654.8 100