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ELECTRICAL SYSTEM DESIGN 1 EE- 53 ELECTRICAL PLAN SUBMITTED BY: ANGELIE M. MOROSCALLO MARK ANTHONY B. ENOY SUBMITTED TO: ENGR. URSINO TABILIRAN

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Page 1: Apartment design

ELECTRICAL SYSTEM DESIGN 1

EE- 53

ELECTRICAL PLAN

SUBMITTED BY:ANGELIE M. MOROSCALLOMARK ANTHONY B. ENOY

SUBMITTED TO:

ENGR. URSINO TABILIRAN

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TABLE OF CONTENTSPAGE

ILLUMINATION DESIGN………………………………………………………...……… 3

FIRST FLOOR………………………………………………………………………. 3

SECOND FLOOR…………………………………………………………………… 7

POWER LOAD…………………………………………………………………………….. 10

CONVENIENCE OUTLET…………………………………………………………. 10

SPECIAL OUTLETS………………………………………………………………... 11

LIGHTING LOAD………...................................................................................................... 13

SUB-FEEDER………………………………………………………………………………. 14

MAIN FEEDER……………………………………………………………………………. 17

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ILLUMINATION DESIGN

FIRST FLOORA. GARAGE

AREA= 25.5 sq.m.LUX= 150COEFFICIENT OF UTILIZATION= 0.35MAINTENANCE FACTOR= 0.7

1. Total lamp lumensLAMP LUMENS=

2. Using TT-40W; 40W; 3150 LUMENSNo. of Lamps=

B. PORCH

AREA= 20.375 sq.m.LUX= 150COEFFICIENT OF UTILIZATION= 0.35MAINTENANCE FACTOR= 0.6

1. Total lamp lumensLAMP LUMENS=

2. Using TT-40W; 40W; 3150 LUMENSNo. of Lamps=

C. LIVING ROOM

AREA= 26.375 sq.m.LUX= 150COEFFICIENT OF UTILIZATION= 0.45MAINTENANCE FACTOR= 0.8

1. Total lamp lumensLAMP LUMENS=

2. Using TT-40W; 40W; 3150 LUMENSNo. of Lamps=

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D. DINING ROOM

AREA= 16.75 sq.m.LUX= 150COEFFICIENT OF UTILIZATION= 0.45MAINTENANCE FACTOR= 0.8

1. Total lamp lumensLAMP LUMENS=

2. Using TT-40W; 40W; 3150 LUMENSNo. of Lamps=

E. KITCHEN

AREA= 10.5 sq.m.LUX= 300COEFFICIENT OF UTILIZATION= 0.45MAINTENANCE FACTOR= 0.8

1. Total lamp lumensLAMP LUMENS=

2. Using TT-40W; 40W; 3150 LUMENSNo. of Lamps=

F. BEDROOM 1

AREA= 14 sq.m.LUX= 250COEFFICIENT OF UTILIZATION= 0.35MAINTENANCE FACTOR= 0.8

1. Total lamp lumensLAMP LUMENS=

2. Using TT-40W; 40W; 3150 LUMENSNo. of Lamps=

G. BEDROOM 2

AREA= 14.5 sq.m.LUX= 250

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COEFFICIENT OF UTILIZATION= 0.35MAINTENANCE FACTOR= 0.8

1. Total lamp lumensLAMP LUMENS=

2. Using TT-40W; 40W; 3150 LUMENSNo. of Lamps=

H. TOILET & BATH (T & B)

AREA= 5 sq.m.LUX= 150COEFFICIENT OF UTILIZATION= 0.25MAINTENANCE FACTOR= 0.7

1. Total lamp lumensLAMP LUMENS=

2. Using TT-36W; 36W; 2900 LUMENSNo. of Lamps=

I. LAUNDRY AREA

AREA= 8 sq.m.LUX= 150COEFFICIENT OF UTILIZATION= 0.35MAINTENANCE FACTOR= 0.7

1. Total lamp lumensLAMP LUMENS=

2. Using TT-40W; 40W; 3150 LUMENSNo. of Lamps=

J. LOFT/ HALLWAY

AREA= 5.4 sq.m.LUX= 150COEFFICIENT OF UTILIZATION= 0.35MAINTENANCE FACTOR= 0.8

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1. Total lamp lumensLAMP LUMENS=

2. Using TT-18W; 1150 LUMENSNo. of Lamps=

K. STORAGE ROOM

AREA= 2.6 sq.m.LUX= 150COEFFICIENT OF UTILIZATION= 0.25MAINTENANCE FACTOR= 0.6

1. Total lamp lumensLAMP LUMENS=

3. Using TT-40W; 40W; 3150 LUMENSNo. of Lamps=

SECOND FLOOR

A. LIVING ROOM

AREA= 24.9 sq.m.LUX= 150COEFFICIENT OF UTILIZATION= 0.45

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MAINTENANCE FACTOR= 0.8

1. Total lamp lumensLAMP LUMENS=

2. Using TT-40W; 40W; 3150 LUMENSNo. of Lamps=

STAIRCASES

AREA= 3.6 sq.m.LUX= 150COEFFICIENT OF UTILIZATION= 0.35MAINTENANCE FACTOR= 0.8

1. Total lamp lumensLAMP LUMENS=

2. Using TT-40W; 40W; 3150 LUMENSNo. of Lamps=

B. LOFT

AREA= 5 sq.m.LUX= 150COEFFICIENT OF UTILIZATION= 0.35MAINTENANCE FACTOR= 0.8

1. Total lamp lumensLAMP LUMENS=

2. Using TT-40W; 40W; 3150 LUMENSNo. of Lamps=

C. MASTER’S BEDROOM

AREA= 25 sq.m.LUX= 250COEFFICIENT OF UTILIZATION= 0.35MAINTENANCE FACTOR= 0.8

1. Total lamp lumensLAMP LUMENS=

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2. Using TT-40W; 40W; 3150 LUMENSNo. of Lamps=

D. MASTER’S T&B AND COMMON T&B

AREA= 5 sq.m.LUX= 150COEFFICIENT OF UTILIZATION= 0.25MAINTENANCE FACTOR= 0.7

1. Total lamp lumensLAMP LUMENS=

2. Using TT-36W; 36W; 2900 LUMENSNo. of Lamps=

E. MASTER’S BALCONY

AREA= 6 sq.m.LUX= 150COEFFICIENT OF UTILIZATION= 0.35MAINTENANCE FACTOR= 0.6

1. Total lamp lumensLAMP LUMENS=

2. Using TT-40W; 3150 LUMENSNo. of Lamps=

F. BEDROOM 3 & 4

AREA= 20 sq.m.LUX= 250COEFFICIENT OF UTILIZATION= 0.35MAINTENANCE FACTOR= 0.8

1. Total lamp lumensLAMP LUMENS=

2. Using TT-40W; 40W; 3150 LUMENSNo. of Lamps=

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G. LIBRARY & COMPUTER ROOM

AREA= 19.25 sq.m.LUX= 300COEFFICIENT OF UTILIZATION= 0.45MAINTENANCE FACTOR= 0.8

1. Total lamp lumensLAMP LUMENS=

2. Using TT-40W; 40W; 3150 LUMENSNo. of Lamps=

H. BALCONY

AREA= 16.25 sq.m.LUX= 150COEFFICIENT OF UTILIZATION= 0.35MAINTENANCE FACTOR= 0.6

1. Total lamp lumensLAMP LUMENS=

2. Using TT-40W; 40W; 3150 LUMENSNo. of Lamps=

POWER LOAD

CONVENIENCE OUTLET:

A. For circuit (1, 4 & 5) with 10 outlets Maximum load for convenience outlet= 180W1. Total load

2. Total expected current load

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3. Size of the branch circuit wireReferring to Table 2-5Use 2 pcs. of 3.5 mm2 TW copper wire

4. Size of conduit pipeReferring to Table 2-9 Use 13 mm diameter conduit pipe

5. Size of the Overcurrent Protection DeviceReferring to Table 4-1Use 1 pc. 30 Ampere trip breaker

B. For circuit (2) with 6 outlets

1.2.3. Use 2 pcs. of 3.5 mm2 TW copper wire4. Use 13 mm diameter conduit pipe5. Use 1 pc. 30 Ampere trip breaker

C. For circuit (3) with 7 outlets1.2.3. Use 2 pcs. of 3.5 mm2 TW copper wire4. Use 13 mm diameter conduit pipe5. Use 1 pc. 30 Amp trip breaker

SPECIAL PURPOSE OUTLET

D. For circuit (6) laundry circuit at 1500 W per circuit (PEC)Total load x demand factor (df)

1. Total Expected Current Load

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2. Size of the Branch Circuit wireReferring to Table 2-5Use 2pcs. of 3.5 mm2 TW copper wire

3. Size of conduit pipeReferring to Table 2-9Use 13 mm diameter conduit pipe

4. Size of the Overcurrent Protection DeviceReferring to Table 4-1Use 1 pc. 30 Amperes trip breaker

SPECIAL PURPOSE OUTLET

E. For circuit (7 & 8) with 1 unit of air condition at 2.5 HP each1. Total load2.5

2. Total Expected current Load

“Branch circuit conductor supplying a motor shall have an ampacity not less than 125% of the full load current”

3. Size of the branch circuit wire Referring to Table 2-5Use 2 pcs. of 5.5 mm2 TW copper wire

4. Size of conduit pipe Referring to Table 2-5Use 20 mm diameter conduit pipe

5. Size of the Overcurrent Protection Device8.11 x 2.5= 20.275 AReferring to Table 4-1Use 1pc. 60 Amperes trip breaker

F. For circuit (9, 10, 11 & 12) with 1 unit of air conditioner at 3 HP each1. Total load

3 x 746= 2238 W2.

“Branch circuit conductor supplying a motor shall have an ampacity not less than 125% of the full load current”

3. Use 2 pcs. of 8.0 mm2 THW copper wire

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4. Use 30 mm diameter conduit pipe5. 9.73 x 2.5= 24.33 A

Referring to Table 4-1Use 1pc. 70 Amperes trip breaker

SPECIAL PURPOSE OUTLET

G. For circuit (13) cooking unit at 5,100 WTotal load x Demand Factor (df); 5,100 x 0.8= 4,080 W1. Total Expected Current Load

2. Size of the branch circuit wire

Referring to Table 2-5Use 2 pcs. of 5.5 mm2

3. Size of conduit pipe Referring to Table 2-9Use 20 mm diameter conduit pipe

4. Size of the Overcurrent Protection DeviceReferring to Table 4-1Use 1 pc. 30 Amperes trip

LIGHTING LOAD

H. For circuit (14, 19 & 20) with 11 lighting outletsMaximum Load for lighting outlet= 100 W1. Total load

11 x 100= 1100 W2. Total Expected Current Load

3. Size of the branch circuit wire

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Referring to Table 2-5Use 2 pcs. of 2.0 mm2 TW copper wire

4. Size of conduit pipe Referring to Table 5-7Use 13 mm diameter conduit pipe

5. Size of the Overcurrent Protection DeviceReferring to Table 5-2Use 1 pc. 15 Amperes trip breaker

I. For circuit (15, 16 & 20) with 8 lighting outlets1. 8 x 100= 800 W2.3. Use 2 pcs. of 2.0 mm2 TW copper wire4. Use 13 mm diameter conduit pipe5. Use 1 pc. 15 amperes trip breaker

J. For circuit (17) with 9 lighting outlets1. 9 x 100= 900W2.3. Use 2 pcs. of 2.0 mm2 TW copper wire4. Use 13 mm diameter conduit pipe5. Use 1 pc. 15 amperes trip breaker

K. For circuit (18) with 10 lighting outlets1. 10 x 100= 1000 W2.3. Use 2 pcs. of 2.0 mm2 TW copper wire4. Use 13 mm diameter conduit pipe5. Use 1 pc. 15 amperes trip breaker

SUB-FEEDER

For circuits 1 to 21:

1. Total connected loadFor circuits 1, 4 & 5------------------------------------------------------------------------10800 WFor circuits 2---------------------------------------------------------------------------------3240 WFor circuits 3---------------------------------------------------------------------------------2520 WFor circuits 6---------------------------------------------------------------------------------1500 WFor circuits 13--------------------------------------------------------------------------------5100 WFor circuits 14, 19 & 21---------------------------------------------------------------------3300 W

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For circuits 15, 16 & 20---------------------------------------------------------------------2400 WFor circuits 17--------------------------------------------------------------------------------900 WFor circuits 18--------------------------------------------------------------------------------1000 W

TOTAL (excluding the Aircon Unit)------------------------ 30.760 W

From Table 4-4, optional calculation for Dwelling Unit, apply Demand Factor (df)For the first 10,000 Watts at 100% df--------------------------------------------------------10,000 WattsFor the remaining load apply 40% df

30,760- 10,000= 20, 760 Watts at 40% (df)----------------------------------------- 8304 WattsFor circuit 7 to 8: Aircon units at 100% Demand Factor (df)

2- units at 1865 Watts-------------------------------------------------------------------3730 WattsFor circuit 9 to 12: Aircon units at 100% Demand Factor (df)

4- units at 2238 Watts-------------------------------------------------------------------8952 Watts TOTAL=

30,986 Watt

2. Total Line Current

3. Size of sub-feeder wireReferring to Table 4-2Use 2 pcs. of 80 mm2 TW copper wire

4. Size of conduit pipeReferring to Table 2-9Use 32 mm diameter conduit pipe

5. Size of the Overcurrent DeviceReferring to Table 4-1Use 1pc. 175 amperes trip breaker

SPECIAL PURPOSE OUTLET

For circuit (22) with 1 unit of Motor Pump @ 3 HPTotal Load

3 x 746= 2238 WattsTotal expected Current Load

“ Branch circuit conductor supplying a motor shall have an ampacity not less than 125% of full load current”

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9.73 x 125%= 12.16 A

1. Size of the branch circuit wireReferring to Table 2.5Use 2pcs. of 8.0 mm2 TW copper wire

2. Size of conduit pipeReferring to Table 2-9Use 30 mm diameter conduit pipe

3. Size of the Overcurrent Protection Device 9.73 x 2.5= 24.33 AReferring to Table 4-1Use 1 pc. 70 amperes trip breaker

MAIN FEEDER

Total current load of 2 dwelling units at 134.72 A----------------------------------------------269.44 AMotor unit at 100% Demand Factor (df)

1-unit at 9.73 A-------------------------------------------------------------------------9.73 ATOTAL-----------------------------------------------------------------------------279.17 A

At 125% of Full Load Current279.17 x 1.25= 348.96 A

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1. Size of the branch circuit wireReferring to Table 2-5Use 2 pcs. of No. 600 AWG MCM

2. Size of Conduit PipeReferring to Table 2-9Use 80 mm diameter conduit pipe

3. Size of the Overcurrent Protection DeviceReferring to Table 4-1Use 1 pc. 450 amperes trip breaker