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ELECTRICAL SYSTEM DESIGN 1
EE- 53
ELECTRICAL PLAN
SUBMITTED BY:ANGELIE M. MOROSCALLOMARK ANTHONY B. ENOY
SUBMITTED TO:
ENGR. URSINO TABILIRAN
2
TABLE OF CONTENTSPAGE
ILLUMINATION DESIGN………………………………………………………...……… 3
FIRST FLOOR………………………………………………………………………. 3
SECOND FLOOR…………………………………………………………………… 7
POWER LOAD…………………………………………………………………………….. 10
CONVENIENCE OUTLET…………………………………………………………. 10
SPECIAL OUTLETS………………………………………………………………... 11
LIGHTING LOAD………...................................................................................................... 13
SUB-FEEDER………………………………………………………………………………. 14
MAIN FEEDER……………………………………………………………………………. 17
3
ILLUMINATION DESIGN
FIRST FLOORA. GARAGE
AREA= 25.5 sq.m.LUX= 150COEFFICIENT OF UTILIZATION= 0.35MAINTENANCE FACTOR= 0.7
1. Total lamp lumensLAMP LUMENS=
2. Using TT-40W; 40W; 3150 LUMENSNo. of Lamps=
B. PORCH
AREA= 20.375 sq.m.LUX= 150COEFFICIENT OF UTILIZATION= 0.35MAINTENANCE FACTOR= 0.6
1. Total lamp lumensLAMP LUMENS=
2. Using TT-40W; 40W; 3150 LUMENSNo. of Lamps=
C. LIVING ROOM
AREA= 26.375 sq.m.LUX= 150COEFFICIENT OF UTILIZATION= 0.45MAINTENANCE FACTOR= 0.8
1. Total lamp lumensLAMP LUMENS=
2. Using TT-40W; 40W; 3150 LUMENSNo. of Lamps=
4
D. DINING ROOM
AREA= 16.75 sq.m.LUX= 150COEFFICIENT OF UTILIZATION= 0.45MAINTENANCE FACTOR= 0.8
1. Total lamp lumensLAMP LUMENS=
2. Using TT-40W; 40W; 3150 LUMENSNo. of Lamps=
E. KITCHEN
AREA= 10.5 sq.m.LUX= 300COEFFICIENT OF UTILIZATION= 0.45MAINTENANCE FACTOR= 0.8
1. Total lamp lumensLAMP LUMENS=
2. Using TT-40W; 40W; 3150 LUMENSNo. of Lamps=
F. BEDROOM 1
AREA= 14 sq.m.LUX= 250COEFFICIENT OF UTILIZATION= 0.35MAINTENANCE FACTOR= 0.8
1. Total lamp lumensLAMP LUMENS=
2. Using TT-40W; 40W; 3150 LUMENSNo. of Lamps=
G. BEDROOM 2
AREA= 14.5 sq.m.LUX= 250
5
COEFFICIENT OF UTILIZATION= 0.35MAINTENANCE FACTOR= 0.8
1. Total lamp lumensLAMP LUMENS=
2. Using TT-40W; 40W; 3150 LUMENSNo. of Lamps=
H. TOILET & BATH (T & B)
AREA= 5 sq.m.LUX= 150COEFFICIENT OF UTILIZATION= 0.25MAINTENANCE FACTOR= 0.7
1. Total lamp lumensLAMP LUMENS=
2. Using TT-36W; 36W; 2900 LUMENSNo. of Lamps=
I. LAUNDRY AREA
AREA= 8 sq.m.LUX= 150COEFFICIENT OF UTILIZATION= 0.35MAINTENANCE FACTOR= 0.7
1. Total lamp lumensLAMP LUMENS=
2. Using TT-40W; 40W; 3150 LUMENSNo. of Lamps=
J. LOFT/ HALLWAY
AREA= 5.4 sq.m.LUX= 150COEFFICIENT OF UTILIZATION= 0.35MAINTENANCE FACTOR= 0.8
6
1. Total lamp lumensLAMP LUMENS=
2. Using TT-18W; 1150 LUMENSNo. of Lamps=
K. STORAGE ROOM
AREA= 2.6 sq.m.LUX= 150COEFFICIENT OF UTILIZATION= 0.25MAINTENANCE FACTOR= 0.6
1. Total lamp lumensLAMP LUMENS=
3. Using TT-40W; 40W; 3150 LUMENSNo. of Lamps=
SECOND FLOOR
A. LIVING ROOM
AREA= 24.9 sq.m.LUX= 150COEFFICIENT OF UTILIZATION= 0.45
7
MAINTENANCE FACTOR= 0.8
1. Total lamp lumensLAMP LUMENS=
2. Using TT-40W; 40W; 3150 LUMENSNo. of Lamps=
STAIRCASES
AREA= 3.6 sq.m.LUX= 150COEFFICIENT OF UTILIZATION= 0.35MAINTENANCE FACTOR= 0.8
1. Total lamp lumensLAMP LUMENS=
2. Using TT-40W; 40W; 3150 LUMENSNo. of Lamps=
B. LOFT
AREA= 5 sq.m.LUX= 150COEFFICIENT OF UTILIZATION= 0.35MAINTENANCE FACTOR= 0.8
1. Total lamp lumensLAMP LUMENS=
2. Using TT-40W; 40W; 3150 LUMENSNo. of Lamps=
C. MASTER’S BEDROOM
AREA= 25 sq.m.LUX= 250COEFFICIENT OF UTILIZATION= 0.35MAINTENANCE FACTOR= 0.8
1. Total lamp lumensLAMP LUMENS=
8
2. Using TT-40W; 40W; 3150 LUMENSNo. of Lamps=
D. MASTER’S T&B AND COMMON T&B
AREA= 5 sq.m.LUX= 150COEFFICIENT OF UTILIZATION= 0.25MAINTENANCE FACTOR= 0.7
1. Total lamp lumensLAMP LUMENS=
2. Using TT-36W; 36W; 2900 LUMENSNo. of Lamps=
E. MASTER’S BALCONY
AREA= 6 sq.m.LUX= 150COEFFICIENT OF UTILIZATION= 0.35MAINTENANCE FACTOR= 0.6
1. Total lamp lumensLAMP LUMENS=
2. Using TT-40W; 3150 LUMENSNo. of Lamps=
F. BEDROOM 3 & 4
AREA= 20 sq.m.LUX= 250COEFFICIENT OF UTILIZATION= 0.35MAINTENANCE FACTOR= 0.8
1. Total lamp lumensLAMP LUMENS=
2. Using TT-40W; 40W; 3150 LUMENSNo. of Lamps=
9
G. LIBRARY & COMPUTER ROOM
AREA= 19.25 sq.m.LUX= 300COEFFICIENT OF UTILIZATION= 0.45MAINTENANCE FACTOR= 0.8
1. Total lamp lumensLAMP LUMENS=
2. Using TT-40W; 40W; 3150 LUMENSNo. of Lamps=
H. BALCONY
AREA= 16.25 sq.m.LUX= 150COEFFICIENT OF UTILIZATION= 0.35MAINTENANCE FACTOR= 0.6
1. Total lamp lumensLAMP LUMENS=
2. Using TT-40W; 40W; 3150 LUMENSNo. of Lamps=
POWER LOAD
CONVENIENCE OUTLET:
A. For circuit (1, 4 & 5) with 10 outlets Maximum load for convenience outlet= 180W1. Total load
2. Total expected current load
10
3. Size of the branch circuit wireReferring to Table 2-5Use 2 pcs. of 3.5 mm2 TW copper wire
4. Size of conduit pipeReferring to Table 2-9 Use 13 mm diameter conduit pipe
5. Size of the Overcurrent Protection DeviceReferring to Table 4-1Use 1 pc. 30 Ampere trip breaker
B. For circuit (2) with 6 outlets
1.2.3. Use 2 pcs. of 3.5 mm2 TW copper wire4. Use 13 mm diameter conduit pipe5. Use 1 pc. 30 Ampere trip breaker
C. For circuit (3) with 7 outlets1.2.3. Use 2 pcs. of 3.5 mm2 TW copper wire4. Use 13 mm diameter conduit pipe5. Use 1 pc. 30 Amp trip breaker
SPECIAL PURPOSE OUTLET
D. For circuit (6) laundry circuit at 1500 W per circuit (PEC)Total load x demand factor (df)
1. Total Expected Current Load
11
2. Size of the Branch Circuit wireReferring to Table 2-5Use 2pcs. of 3.5 mm2 TW copper wire
3. Size of conduit pipeReferring to Table 2-9Use 13 mm diameter conduit pipe
4. Size of the Overcurrent Protection DeviceReferring to Table 4-1Use 1 pc. 30 Amperes trip breaker
SPECIAL PURPOSE OUTLET
E. For circuit (7 & 8) with 1 unit of air condition at 2.5 HP each1. Total load2.5
2. Total Expected current Load
“Branch circuit conductor supplying a motor shall have an ampacity not less than 125% of the full load current”
3. Size of the branch circuit wire Referring to Table 2-5Use 2 pcs. of 5.5 mm2 TW copper wire
4. Size of conduit pipe Referring to Table 2-5Use 20 mm diameter conduit pipe
5. Size of the Overcurrent Protection Device8.11 x 2.5= 20.275 AReferring to Table 4-1Use 1pc. 60 Amperes trip breaker
F. For circuit (9, 10, 11 & 12) with 1 unit of air conditioner at 3 HP each1. Total load
3 x 746= 2238 W2.
“Branch circuit conductor supplying a motor shall have an ampacity not less than 125% of the full load current”
3. Use 2 pcs. of 8.0 mm2 THW copper wire
12
4. Use 30 mm diameter conduit pipe5. 9.73 x 2.5= 24.33 A
Referring to Table 4-1Use 1pc. 70 Amperes trip breaker
SPECIAL PURPOSE OUTLET
G. For circuit (13) cooking unit at 5,100 WTotal load x Demand Factor (df); 5,100 x 0.8= 4,080 W1. Total Expected Current Load
2. Size of the branch circuit wire
Referring to Table 2-5Use 2 pcs. of 5.5 mm2
3. Size of conduit pipe Referring to Table 2-9Use 20 mm diameter conduit pipe
4. Size of the Overcurrent Protection DeviceReferring to Table 4-1Use 1 pc. 30 Amperes trip
LIGHTING LOAD
H. For circuit (14, 19 & 20) with 11 lighting outletsMaximum Load for lighting outlet= 100 W1. Total load
11 x 100= 1100 W2. Total Expected Current Load
3. Size of the branch circuit wire
13
Referring to Table 2-5Use 2 pcs. of 2.0 mm2 TW copper wire
4. Size of conduit pipe Referring to Table 5-7Use 13 mm diameter conduit pipe
5. Size of the Overcurrent Protection DeviceReferring to Table 5-2Use 1 pc. 15 Amperes trip breaker
I. For circuit (15, 16 & 20) with 8 lighting outlets1. 8 x 100= 800 W2.3. Use 2 pcs. of 2.0 mm2 TW copper wire4. Use 13 mm diameter conduit pipe5. Use 1 pc. 15 amperes trip breaker
J. For circuit (17) with 9 lighting outlets1. 9 x 100= 900W2.3. Use 2 pcs. of 2.0 mm2 TW copper wire4. Use 13 mm diameter conduit pipe5. Use 1 pc. 15 amperes trip breaker
K. For circuit (18) with 10 lighting outlets1. 10 x 100= 1000 W2.3. Use 2 pcs. of 2.0 mm2 TW copper wire4. Use 13 mm diameter conduit pipe5. Use 1 pc. 15 amperes trip breaker
SUB-FEEDER
For circuits 1 to 21:
1. Total connected loadFor circuits 1, 4 & 5------------------------------------------------------------------------10800 WFor circuits 2---------------------------------------------------------------------------------3240 WFor circuits 3---------------------------------------------------------------------------------2520 WFor circuits 6---------------------------------------------------------------------------------1500 WFor circuits 13--------------------------------------------------------------------------------5100 WFor circuits 14, 19 & 21---------------------------------------------------------------------3300 W
14
For circuits 15, 16 & 20---------------------------------------------------------------------2400 WFor circuits 17--------------------------------------------------------------------------------900 WFor circuits 18--------------------------------------------------------------------------------1000 W
TOTAL (excluding the Aircon Unit)------------------------ 30.760 W
From Table 4-4, optional calculation for Dwelling Unit, apply Demand Factor (df)For the first 10,000 Watts at 100% df--------------------------------------------------------10,000 WattsFor the remaining load apply 40% df
30,760- 10,000= 20, 760 Watts at 40% (df)----------------------------------------- 8304 WattsFor circuit 7 to 8: Aircon units at 100% Demand Factor (df)
2- units at 1865 Watts-------------------------------------------------------------------3730 WattsFor circuit 9 to 12: Aircon units at 100% Demand Factor (df)
4- units at 2238 Watts-------------------------------------------------------------------8952 Watts TOTAL=
30,986 Watt
2. Total Line Current
3. Size of sub-feeder wireReferring to Table 4-2Use 2 pcs. of 80 mm2 TW copper wire
4. Size of conduit pipeReferring to Table 2-9Use 32 mm diameter conduit pipe
5. Size of the Overcurrent DeviceReferring to Table 4-1Use 1pc. 175 amperes trip breaker
SPECIAL PURPOSE OUTLET
For circuit (22) with 1 unit of Motor Pump @ 3 HPTotal Load
3 x 746= 2238 WattsTotal expected Current Load
“ Branch circuit conductor supplying a motor shall have an ampacity not less than 125% of full load current”
15
9.73 x 125%= 12.16 A
1. Size of the branch circuit wireReferring to Table 2.5Use 2pcs. of 8.0 mm2 TW copper wire
2. Size of conduit pipeReferring to Table 2-9Use 30 mm diameter conduit pipe
3. Size of the Overcurrent Protection Device 9.73 x 2.5= 24.33 AReferring to Table 4-1Use 1 pc. 70 amperes trip breaker
MAIN FEEDER
Total current load of 2 dwelling units at 134.72 A----------------------------------------------269.44 AMotor unit at 100% Demand Factor (df)
1-unit at 9.73 A-------------------------------------------------------------------------9.73 ATOTAL-----------------------------------------------------------------------------279.17 A
At 125% of Full Load Current279.17 x 1.25= 348.96 A
16
1. Size of the branch circuit wireReferring to Table 2-5Use 2 pcs. of No. 600 AWG MCM
2. Size of Conduit PipeReferring to Table 2-9Use 80 mm diameter conduit pipe
3. Size of the Overcurrent Protection DeviceReferring to Table 4-1Use 1 pc. 450 amperes trip breaker