Chem Unit5

Back to Moles

• • number of atoms in exactly 12 grams carbon-12

Avogadro’s Number• There are 6.02 x 1023 particles in a

mole of any substance.

Molar Mass

• Mass of one MOLE of pure substance

• Helium: 4.00 grams -------> 4 grams per mole

• Lithium 6.94 grams ---------> 6.94 grams per mole

• Mercury 200.59 grams -------> 200.59 grams per mole

0.1 Moles of Uranium

•(0.1 moles) x 238 grams/mole

= 23.8 grams

0.1 moles Uranium

•How many atoms?

• 6.022 x 1023 atoms/mole x 0.1 moles

= 6.022 x 1022 atoms

Molecules

•5 moles of CO2

= 5 moles x 6.022 x 1023 molecules/mole

= 3.1 x 1024 molecules of CO2

Molar Mass

•Mass in grams of one moleof the substance

CO2: mass C + 2 (mass O)

= 12 + 2(16) = 44 grams

Mass -> Moles

•Converting from g to moles:

For 112 grams of C2H4:

Grams of SubstanceGrams of

Substance Molar mass MOLES

Mass -> Moles•Converting from g to moles:

For 112 grams of C2H4:

112 g x 1 mole/28 g = 4 moles

Grams of SubstanceGrams of

Substance Molar mass MOLES

Moles -> Molecules• Converting from moles to Molecules

For 4 moles of C2H4:4 moles x 6.02 x 1023 molecules/mole = 2.41 x 1024

molecules

MolesMolesAvogadro’s Number molecules

Law of Definite Proportions

• Joseph Proust

• Regardless of the source, a compound always has the same proportion of elements

Law of Definite Proportions

•Copper (II) Carbonate

CuCO3 -> Copper + Carbon + Oxygen

51.36% 9.72% 38.85%

Percent Composition

•CO CO2

28 g/mole 44 g/mole

C: 12/28 = 42.86% C: 12/44 = 27.27%O: 16/28 = 57.14% O: 32/44 = 72.73%

Two different compound with different percentcompositions and different properties

Empirical Formula

• Smallest whole number ratio of atoms in a compound

• CaffeineMolecular formulaC8H10N4O2

Empirical formulaC4H5N2O

Percent Composition -> Empirical Formula

•Vinegar

•C: 40%H: 6.67%

•O: 53.33%

•Vinegarassume 100 g

C: 40 gramsH: 6.67 gramsO: 53.33 grams

C: 40 g x 1mole/12g = 3.33 moles

H: 6.67 g x 1 mole/1g = 6.67 moles

O: 53.33 g x 1 mole/16 g = 3.33 moles

H: 6.67 g x 1 mole/1g = 6.67 moles

O: 53.33 g x 1 mole/16 g = 3.33 moles

Empirical Formula:

H: 6.67 g x 1 mole/1g = 6.67 moles

O: 53.33 g x 1 mole/16 g = 3.33 moles

Actual Formula:

C2H4O2

H: 6.67 g x 1 mole/1g = 6.67 moles

O: 53.33 g x 1 mole/16 g = 3.33 moles

Actual Formula:

C2H4O2

Empirical Formula-> Molecular Formula

Empirical Formula: CH2O

Molecular Formula: C2H4O2

Molecular Formula is a whole number multiple of empirical formula

Butyric Acid = butter flavor Empirical formula = C2H4O

Molar mass = 88 g/mole

Molecular formula =

Molar mass = 88 g/mole Mass of emp. formula = 44 Molecular formula =

Molar mass = 88 g/mole Mass of emp. formula = 44 Molecular formula = C4H8O2

Formula -> Percent Composition

Empirical formula Butyric Acid: C2H4O

Molar mass C x 2 = 12 x 2 = 24 Molar mass H x 4 = 1 x 4 = 4

Molar mass O = 16

44 g/mole

Formula -> Percent Composition

Empirical formula Butyric Acid: C2H4O

C = 24/44 = 0.545 = 54.5% H = 4/44 = 0.091 = 9.1%

O = 16/44 = 0.364 = 36.4%

Chemical VS. Physical Change

Physical Chemical

Chemical VS. Physical Change

Physical Chemical• change in phase • atomic rearrangement

• change in appearance, • energy change

shape (absorption or release)

Chemical Equations

Shorthand symbols:(s), (l), (g) = solid, liquid, gas phases

(aq) = substance in aqueous solution

--> = reaction event AX -> BY

<=> reaction in equilibrium (reversible)

Chemical Equations

Silicon tetrachloride and water react to form silicon dioxide and hydrochloric acid

Chemical Equations

SiCl4 + H2O SiO2 + HCl

Reactants Products

Chemical Equations

SiCl4 + 2 H2O SiO2 + 4 HCl

Balanced

Balancing Chemical Equations

Conservation of Matter:

H2 + O2 ---------------> H2O

Conservation of Matter:

2 H2 + O2 ---------------> 2 H2O

propane gas + oxygen gas -> carbon dioxide gas + water vapor

C3H8(g) O2(g) -> CO2(g) H2O(g)

C3H8(g) O2(g) -> 3 CO2(g) H2O(g)

C3H8(g) O2(g) -> 3 CO2(g) 4 H2O(g)

RULES:

•Identify reactants and products

•Count atoms

•Insert coefficients

•Check your work

aluminum metal and iron (II) nitrate react to form aluminum nitrate and iron metal

Al + Fe(NO3)2 Al(NO3)3 + Fe

2 Al + 3 Fe(NO3)2 2 Al(NO3)3 + 3 Fe

Balanced

Types of Chemical Equations

1. Combustion

2. Synthesis

3. Decomposition

4. Single Displacement

5.Double Displacement

6.Acid – Base*

Combustion

Reaction of a carbon-based compound with oxygen

2 C4H10 + 13 O2 8 CO2 + 10 H2O

butane

Combustion

Alcohol lamp

C2H5OH + 3 O2 2 CO2 + 3 H2O

Synthesis

Forming a single compound from two or more reactants

H2 + O2 H2O

Synthesis

Forming a single compound from two or more reactants

2 Na + Cl2 2 NaCl

Decomposition

Breakdown of a single compound(Opposite of synthesis)

2 NaN3 2 Na + 3N2

Decomposition

Breakdown of a single compound(Opposite of synthesis)

NH4NO3 N2O + 2 H2O

Single Displacement

A single element reacts with a Compound and displaces another element from that compound

Zn + 2 HCl ZnCl2 + H2

Single Displacement

A single element reacts with a Compound and displaces another element from that compound

2 K + 2 H2O 2 KOH + H2

Activity Series

Element ReactivityK

React with cold water and acids to replace hydrogen; react with oxygen to form oxides

MgAlZnFe

React with steam (not cold water) and acids to replace hydrogen; react with oxygen to form oxides

Do not react with water; react with acids to replace hydrogen; react with oxygen to form oxides

Cu React with oxygen to form oxides

AgAu Unreactive; form oxides only indirectly

Activity Series

What will happen if iron (steel wool) is added to a copper(II) sulfate solution?

Activity Series

Fe(s) + CuSO4 (aq) -> Cu(s) + FeSO4(aq)

Double Displacement

Two compounds exchange ions andForm new compounds

Pb(NO3)2 + KI PbI2(s) + 2 KNO3

Net Ionic Equations

When aqueous solutions are mixed, new ionic combinationsare made.

Mass and Charge must beconserved.

Na2SO4(aq) + Sr(NO3)2(aq) SrSO4(s) + 2 NaNO3(aq)

precipitate

Net Ionic Equations

Precipitate = insoluble solid thatSeparates from solution

precipitate

Net Ionic Equations

Na2SO4 - > 2 Na+ + SO42-

Sr(NO3)2 - > Sr2+ + 2 NO3-

NaNO3 - > Na+ + NO3-

precipitate

Net Ionic Equations

Na2SO4 - > 2 Na+ + SO42-

Sr(NO3)2 - > Sr2+ + 2 NO3-

NaNO3 - > Na+ + NO3-

2 Na+ + SO42- + Sr2+ + 2 NO3

- SrSO4(s) + 2 Na+ + 2 NO3-

spectator ions precipitate

Solubility Rules

All alkali metal and NH4+ salts are

soluble;

All nitrates (NO3) are soluble;

All Halides (F, Cl, Br, I) are solubleexcept Ag+ and Pb2+

Sulfates(SO4), except for Ca2+, Ba2+, Sr2+, Pb2+ are soluble

Carbonates (CO3) are insoluble except for alkali metal and NH4.

Net Ionic Equations

Li2CO3 + BaBr2 BaCO3 + 2 LiBr

Net Ionic Equations

Li2CO3 -> 2 Li+ + CO32-

BaBr2 -> Ba2+ + 2 Br-

Li2CO3 + BaBr2 BaCO3 + 2 LiBr

precipitate

Unit 5 Review

Molar Mass g <-> atoms/molecules <-> moles

Percent Composition Empirical and Molecular Formula

Chemical equations: Word Equations, Balancing

Chem Unit5

Technology

MT202 unit5

Unit5 student-edition

Wt4603 unit5 week7

Chem Unit5 Ans

Unit5 java

Wt4603 unit5 week6

Unit5 : pengorganisasian

UNIT5 Notes

Checkpoint Unit5

Unit5 stage

Unit5 Welcome to the unit Unit5 Welcome to the unit

Ch 5 Unit5

El172 unit5

Unit5 Task2

Unit5 Chap14

Unit5 biological evolution

Unit5 Prac

Unit5-Day4-LaBctp.cm.utexas.edu/.../ch302/slides/Unit5-Day4-LaB.pdf · Unit5-Day4-LaB Wednesday, January 22, 2014 9:11 AM Unit5-Day4-LaB Page 1

Cert unit5 jan211

Unit5 text1