SINDA Teaching Whole Numbers Conceptually

Teaching Whole Numbers

Conceptually S INDA Marc h 2012

yeap ban har marshall cavendish institute

This is part of a 12-hour course on

teaching whole numbers.

Teaching Whole Numbers

Conceptually S INDA Marc h 2012

yeap ban har marshall cavendish institute

Part 1 of the session emphasize the

importance of metacognition, looking for

patterns, visualization and number sense.

Part 2 looks at selected operations and a

challenging problems that includes whole

number operations.

Singapore Ministry of Education 1992, 2001, 2007, 2013

Problem

Arrange the ten cards so

that you can do what is

shown to you.

Method 1 – by drawing

Method 2 – by using the cards

Scarsdale Teachers’ Institute, New York

Some participants tried

to solve the Dutch-

version of the problem.

Teaching Whole Numbers

Conceptually S INDA Marc h 2012

Addition

Tom has 9 sweets.

Jerry has 5 sweets more than Tom.

How many sweets does Jerry have?

9

5

Tom

Jerry

9 + 5 = 14

Jerry has 14 sweets.

543 + 274 =

543 + 274 =

543 + 274 =

543 + 274 =

543 + 274 =

543 + 274 =

Teaching Whole Numbers

Conceptually S INDA Marc h 2012

Division

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Teaching Whole Numbers

Conceptually S INDA Marc h 2012

Multiplication

Math in Focus

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Math in Focus

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Math in Focus

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Math in Focus

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Math in Focus

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Math in Focus

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Math in Focus

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Math in Focus

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Math in Focus

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Math in Focus

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Math in Focus

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Da Qiao Primary School, Singapore

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See Ho, S. Y. & Yeap, B. H. (2011). Development of Visualization Skills in Singapore Primary

School Mathematics Textbooks. Paper presented at PME-35 Angkara, Turkey.

See also Yeap, B. H. (2011). The Emphasis of Primary-Level Textbooks in Singapore on

Higher-Order Thinking Skills. Paper presented at International Conference on School

Mathematics Textbooks Shanghai, China.

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Primary Mathematics (Third Edition)

Visuals are used to teach

concepts – distributive

property of multiplication

– without using formal

terms.

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Primary Mathematics (Third Edition)

Teaching Whole Numbers

Conceptually S INDA Marc h 2012

Word Problem

$837 - $648 = $189

$189 x 3 = $570 - $3 = $567

$837 - $567 = $837 - $537 - $30 = $270

$270 3 = $90

$90 x 4 = $360

$837 - $270 - $360 =