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SENSORES DETEMPERATURA - RTDS Y
TERMISTORES
Thursday, September 6, 12
Liquido (Mercurio) en la botella
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de banda bi-metalica
�l = �l0 (T � T0)� ⇥ 10�5/⇥C
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Aplicaciones:Termostatos de aire acondicionadoTermómetros de horno (sensor en forma de espiral con “dial” al final)
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Basados en la transmisión de presión en un fluido
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Uso directo de un sensor de presión
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Measurement and Instrumentation Principles 285
Nickel
Copper
Platinum
Tungsten
200 400 600 800 1000 °C
7
6
5
4
3
2
1
RR0
Fig. 14.8 Typical resistance–temperature characteristics of metals.
14.3.2 Thermistors
Thermistors are manufactured from beads of semiconductor material prepared fromoxides of the iron group of metals such as chromium, cobalt, iron, manganese andnickel. Normally, thermistors have a negative temperature coefficient, i.e. the resistancedecreases as the temperature increases, according to:
R D R0e[ˇ!1/T!1/T0"] !14.8"
This relationship is illustrated in Figure 14.9. However, alternative forms of heavilydoped thermistors are now available (at greater cost) that have a positive temperaturecoefficient. The form of equation (14.8) is such that it is not possible to make alinear approximation to the curve over even a small temperature range, and hencethe thermistor is very definitely a non-linear sensor. However, the major advantagesof thermistors are their relatively low cost and their small size. This size advantagemeans that the time constant of thermistors operated in sheaths is small, although thesize reduction also decreases its heat dissipation capability and so makes the self-heating effect greater. In consequence, thermistors have to be operated at generally
Resistance Temperature Detectors (RTDs)
Para Platinoa1 = 0.00392/�C
Metales: resistencia aumenta con aumentos en temperatura
R = R0
�1 + �1T + �2T
2 + �3T3 + · · · + �nTn
⇥
⇥ R0 (1 + �1T )
Thursday, September 6, 12
RTD’S
• Platino
• más común
• más inerte químicamente
• respuesta aprox. lineal
• estable (no cambia con el tiempo)
• más caro que los otros
R(T ) � R0 (1 + �T )
α = coef. de temp. de R
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http://archives.sensorsmag.com/articles/0101/24/index.htm
Sensing Element Materials andTemperature Limits
Material Usable Temperature Range
Platinum –450°F to 1200°F
Nickel –150°F to 600°F
Copper –100°F to 300°F
Nickel/Iron 32°F to 400°F
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• Relación T versus vO
• Auto-calentamiento
• FSH : factor de auto-calentamiento
• error en T = FSH ✕ P
• P = potencia disipada en RTD
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v1
R1
R(1+b)
VREF
¿Cuanto es v1 versus δ?
Thursday, September 6, 12
v1
R1
R(1+b)
VREF
¿Cuanto es v1 versus δ?
Z�:6)*
=6(�+ �)
6� + 6 + �6
=6
6 + 6�� (�+ �)(6 + 6�)
6� + 6 + �6
=6
6 + 6�� 6� + 6 + �6 + �6�
6� + 6 + �6
=6
6 + 6��
��+
�6�6� + 6 + �6
�
=6
6 + 6��
��+
�6�6� + (�+ �)6
�
Thursday, September 6, 12
v1
R1
R(1+b)
VREF
¿Podemos restar el primer término electrónicamente?
Z�:6)*
=6
6 + 6��
�� +
�6�
6� + (� + �)6
�
7M � = �66 << ��
Z�:6)*
=6
6 + 6��
�� +
�6�
6� + 6
�
=6
6 + 6�+
�66�
�66� + 6� + 6��
=6
6 + 6�+
�
� + 66�
+ 6�6
Thursday, September 6, 12
v1
R1
R(1+b)
VREF v2R1
R
-
+
RGvOUT
Circuito puente
Thursday, September 6, 12
v1
R1
R(1+b)
VREF v2R1
R
-
+
RGvOUT
)NIQTPS� 'SRWMHIVI�YR HIXIGXSV�HI�XIQTIVEXYVE�HI�4PEXMRS �4PEXMRYQ�VIWMWXERGI�XIQTIV�EXYVI�HIXIGXSV� S�68( GSR�YR�GSI½GMIRXI�HI�XIQTIVEXYVE � = �.�����/�' ] 6 = ����E ��'� HI�XEP�QSHS�UYI
6(8) = ���� � (� + �8)
�� 'YERXS�IW�PE�VIWMWXIRGME�E�XIQTIVEXYVE�EQFMIRXI�]�E ����'#
�� 7M :6)* = ��: ]�WI�HIWIE�PMQMXEV�PE�TSXIRGME�HMWMTEHE�IR�IP�WIRWSV�TSV�HIFENSHI �.�Q; TEVE�IZMXEV�IVVSVIW�HIFMHS�EP�EYXS�GEPIRXEQMIRXS� HMWIyI�YR�GMVGYMXSGSQS�IP�UYI�WI�QYIWXVE�TEVE�SFXIRIV�YRE�WIRWMXMZMHEH�HI �.�:/�'�
�� )WXMQI�IP�IVVSV�IR�UYI�WI� MRGYVVI�GYERHS 8 = ����' ]�WI�YXMPM^E� PE�IGYEGMzRETVS\MQEHE�TEVE�IWXMQEV�IP�ZSPXENI�HI�WEPMHE�
Thursday, September 6, 12
Ejemplo: Se desea usar un RTD de Platino para medir temperaturas entre 0 y 50℃ con un error debido a auto-calentamiento no mayor a 1℃. Seleccione VCC si
R0 = 100Ω a 0℃α=0.00392/℃ FSH=0.5℃/mW vO+ -
R
R
RT
R0
VCC
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TERMISTORES• Cerámica semiconductoras como Mg, Co, Cu, Fe,
etc)
• ΔR≈kΔT; PTC (k>0) or NTC (k<0)
• Alta sensitividad
• típicamente opera a T<100℃
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Ecuación de Steinhart-Hart1T
= A + B lnR + C(lnR)3
T = temperatura absolutaR = resistencia a temperatura TA, B = Coeficientes que se deben determinar mediante calibración
R(T ) = R0 exp���
�1T� 1
T0
⇥⇥
3000�K < � < 5000�K
R versus T (en °K) para un termistor:
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Calibración: medir R1,R2 y R3 a temperaturas (conocidas)
T1, T2, y T3resolver las tres ecuaciones por A, B y C
Ejemplo: R(273°K) = 16.33kΩR(348°K)=740ΩR(423°K)=92.7Ω
Determine A, B, y C.
Thursday, September 6, 12
<
+ <
+
Vref
R(1+b) R
R1 R1
R2
vOUT
AO1
AO2
Otros circuitos
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<
+
VREFR(1+b)
RR1
R1
Thursday, September 6, 12
< +<
+R(1+b)
VREF
R1
R
R1 R2
vOUT
Thursday, September 6, 12
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