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4.4 THE FUNDAMENTAL THEOREM OF
CALCULUSRizzi – Calc BC
Recall…
Integrals represent an accumulated rate of change over an interval
The gorilla started at 150 metersThe accumulated rate of change was 55 meters Final position was 95 meters
In other words:
The Fundamental Theorem of Calculus
We can write this in another way:
The fundamental theorem of calculus looks at accumulated rates of change:
FTC Practice
Evaluate the integral:
FTC Practice
Evaluate the integral:
FTC Graphically
Recall the MVT
What did the MVT tell us?
How is it represented graphically?
Mean Value Theorem for Integrals
The MVT for Integrals says: somewhere in the interval [a, b] there is a f(c) value that accurately approximates the area of the curve under the interval.
MVT for Integrals Practice
Find the value of c guaranteed by the Mean Value Theorem for Integrals over the given interval
4.4 THE SECOND FUNDAMENTAL THEOREM
OF CALCULUSRizzi – Calc BC
Review: MVT for Integrals
The MVT for Integrals says: somewhere in the interval [a, b] there is a f(c) value that accurately approximates the area of the curve under the interval.
Average Value of a Function
You will NEED this for the AP exam Average value determines the average y-
value for a functionAverage Value Formula:
MVT:
Practice
Find the average value of on the interval [1, 4].
Average Value Formula:
Second FTC
The derivative of the integral of f(x) is f(x)
But why?
Second FTC Practice
Find F’(x)
More Second FTC Practice
But what about this?
Net Change Theorem
Essentially the same as FTC #1
Net Change Theorem Practice
A chemical flows into a storage tank at a rate of 180 + 3t liters per minute, where 0 ≤ t ≤ 60. Find the amount of the chemical that flows into the tank during the first 20 minutes.
4200 liters
Particle Motion Revisited
When calculating the total distance traveled by the particle, consider the intervals where v(t) ≤ 0 and the intervals where v(t) ≥ 0.
When v(t) ≤ 0, the particle moves to the left, and when v(t) ≥ 0, the particle moves to the right.
To calculate the total distance traveled, integrate the absolute value of velocity |v(t)|.
Net Change Theorem Applied
So, the displacement of a particle and the total distance traveled by a particle over [a, b] is
and the total distance traveled by the particle on [a, b] is
Practice Particle Motion Problem
The velocity (in feet per second) of a particle moving along a line is
v(t) = t3 – 10t2 + 29t – 20 where t is the time in seconds.
a. What is the displacement of the particle on the time interval 1 ≤ t ≤ 5?
b. What is the total distance traveled by the particle on the time interval 1 ≤ t ≤ 5?
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