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Momentum and Momentum Conservation
• Momentum • Impulse• Conservation
of Momentum• Collision in 1-D• Collision in 2-D
So What’s Momentum ?• Momentum = mass x velocity
• This can be abbreviated to : . momentum = mv
• Or, if direction is not an important factor : . . momentum = mass x speed
• So, A really slow moving truck and an extremely fast roller skate can have the same momentum.
Question :
• Under what circumstances would the roller skate and the truck have the same momentum ?
• The roller skate and truck can have the same momentum if the ratio of the speed of the skate to the speed of the truck is the same as the ratio of the mass of the truck to the mass of the skate.
• A 1000 kg truck moving at 0.01 m/sec has the same momentum as a 1 kg skate moving at 10 m/sec. Both have a momentum of 10 kg m/sec. ( 1000 x .01 = 1 x 10 = 10 )
Linear Momentum• A new fundamental quantity, like force, energy• The linear momentum p of an object of mass
m moving with a velocity is defined to be the product of the mass and velocity:
– The terms momentum and linear momentum will be used interchangeably in the text
– Momentum depend on an object’s mass and velocity
v
vmp
Newton’s Law and Momentum• Newton’s Second Law can be used to relate the
momentum of an object to the resultant force acting on it
• The change in an object’s momentum divided by the elapsed time equals the constant net force acting on the object
t
vm
t
vmamFnet
)(
netFt
p
interval time
momentumin change
• If momentum changes, it’s because mass or velocity change.
• Most often mass doesn’t change so velocity changes and that is acceleration.
• And mass x acceleration = force • Applying a force over a time interval to an
object changes the momentum• Force x time interval = Impulse • Impulse = F t or Ft = mv
Impulse and Momentum
Ft = mv
Impulse-Momentum Theorem
• The theorem states that the impulse acting on a system is equal to the change in momentum of the system
if vmvmpI
ItFp net
FO
RC
E
• An object at rest has no momentum, why?• Because anything times zero is zero• (the velocity component is zero for an object at rest)• To INCREASE MOMENTUM,
apply the greatest force possible for as long as possible.
• Examples : • pulling a sling shot • drawing an arrow in a bow all the way back • a long cannon for maximum range• hitting a golf ball or a baseball
. (follow through is important for these !)
TIME
MOMENTUM
MOMENTUM
• SOME VOCABULARY : • impulse : impact force X time (newton.sec)
. Ft = impulse
• impact : the force acting on an object (N) . usually when it hits something.
• impact forces : average force of impact
• Decreasing Momentum • Which would it be more safe to hit in a car ?
• Knowing the physics helps us understand why hitting a soft object is better than hitting a hard one.
MOMENTUM
mv
mv
Ft
Ft
• In each case, the momentum is decreased by the same amount or impulse (force x time)
• Hitting the haystack extends the impact time (the time in which the momentum is brought to zero).
• The longer impact time reduces the force of impact and decreases the deceleration.
• Whenever it is desired to decrease the force of impact, extend the time of impact !
MOMENTUM
DECREASING MOMENTUMDECREASING MOMENTUM
• If the time of impact is increased by 100 times (say from .01 sec to 1 sec), then the force of impact is reduced by 100 times (say to something survivable).
• EXAMPLES :• Padded dashboards on cars• Airbags in cars or safety nets in circuses• Moving your hand backward as you catch a fast-moving ball
with your bare hand or a boxer moving with a punch.• Flexing your knees when jumping from a higher place to the
ground. or elastic cords for bungee jumping• Using wrestling mats instead of hardwood floors.• Dropping a glass dish onto a carpet instead of a sidewalk.
EXAMPLES OF DECREASING MOMENTUM
• Bruiser Bruno on boxing …
• Increased impact time reduces force of impact• Barbie on bungee Jumping …
Ft = change in momentum
Ft = change in momentum
Ft = Δmv applies here.
mv = the momentum gained before the cord begins to stretch that we wish to change.
Ft = the impulse the cord supplies to reduce the momentum to zero.
Because the rubber cord stretches fora long time the average force on the jumper is small.
Questions : • When a dish falls, will the impulse be less if it lands on a
carpet than if it lands on a hard ceramic tile floor ? • The impulse would be the same for either surface
because there is the same momentum change for each. It is the force that is less for the impulse on the carpet because of the greater time of momentum change. There is a difference between impulse and impact.
• If a boxer is able to increase the impact time by 5 times by “riding” with a punch, by how much will the force of impact be reduced?
• Since the time of impact increases by 5 times, the force of impact will be reduced by 5 times.
BOUNCING
• IMPULSES ARE GREATER WHEN AN OBJECT BOUNCES
• The impulse required to bring an object to a stop and then to throw it back upward again is greater than the impulse required to merely bring the object to a stop.
• When a martial artist breaks boards,• does their hand bounce?• Is impulse or momentum greater ?
• Example : • The Pelton Wheel.
Calculating the Change of Momentum
0 ( )p m v mv
( )
after before
after before
after before
p p p
mv mv
m v v
For the teddy bear
For the bouncing ball
( ) 2p m v v mv
How Good Are the Bumpers? In a crash test, a car of mass 1.5103 kg collides with a wall
and rebounds as in figure. The initial and final velocities of the car are vi=-15 m/s and vf = 2.6 m/s, respectively. If the collision lasts for 0.15 s, find
(a) the impulse delivered to the car due to the collision (b) the size and direction of the average force exerted on the car
How Good Are the Bumpers? In a crash test, a car of mass 1.5103 kg collides with a wall
and rebounds as in figure. The initial and final velocities of the car are vi=-15 m/s and vf = 2.6 m/s, respectively. If the collision lasts for 0.15 s, find
(a) the impulse delivered to the car due to the collision (b) the size and direction of the average force exerted on the car
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/1064.2
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smkgsmkg
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)/1025.2()/1039.0(4
44
CONSERVATION OF MOMENTUM
• To accelerate an object, a force must be applied. • The force or impulse on the object must come
from outside the object.
• EXAMPLES : The air in a basketball, sitting in a car and pushing on the dashboard or sitting in a boat and blowing on the sail don’t create movement.
• Internal forces like these are balanced and cancel each other.
• If no outside force is present, no change in momentum is possible.
The Law of Conservation of Momentum
• In the absence of an external force, the momentum of a system remains unchanged.
• This means that, when all of the forces are internal (for EXAMPLE: the nucleus of an atom undergoing . radioactive decay, . cars colliding, or . stars exploding the net momentum of the system before and after the event is the same.
Conservation of Momentum• In an isolated and closed
system, the total momentum of the system remains constant in time. – Isolated system: no external forces– Closed system: no mass enters or
leaves– The linear momentum of each
colliding body may change– The total momentum P of the
system cannot change.
Conservation of Momentum• Start from impulse-momentum
theorem
• Since
• Then
• So
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if vmvmtF 111121
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QUESTIONS• 1. Newton’s second law states that if no net force is
exerted on a system, no acceleration occurs. Does it follow that no change in momentum occurs?
• No acceleration means that no change occurs in velocity of momentum.
• 2. Newton’s 3rd law states that the forces exerted on a cannon and cannonball are equal and opposite. Does it follow that the impulse exerted on the cannon and cannonball are also equal and opposite?
• Since the time interval and forces are equal and opposite, the impulses (F x t) are also equal and opposite.
• ELASTIC COLLISIONS
• INELASTIC COLLISIONS
COLLISIONS
Momentum transfer from one Object to another .
Is a Newton’s cradle like the one Pictured here, an example of an elastic or inelastic collision?
Problem Solving #1• A 6 kg fish swimming at 1 m/sec swallows a 2 kg fish
that is at rest. Find the velocity of the fish immediately after “lunch”.
• net momentum before = net momentum after
• (net mv)before = (net mv)after
• (6 kg)(1 m/sec) + (2 kg)(0 m/sec) = (6 kg + 2 kg)(vafter)
• 6 kg.m/sec = (8 kg)(vafter)
• vafter = 6 kg.m/sec / 8 kg
• 8 kg• vafter = ¾ m/sec
vafter =
Problem Solving #2• Now the 6 kg fish swimming at 1 m/sec swallows a 2
kg fish that is swimming towards it at 2 m/sec. Find the velocity of the fish immediately after “lunch”.
• net momentum before = net momentum after
• (net mv)before = (net mv)after
• (6 kg)(1 m/sec) + (2 kg)(-2 m/sec) = (6 kg + 2 kg)(vafter)
• 6 kg.m/sec + -4 kg.m/sec = (8 kg)(vafter)
• vafter = 2 kg.m/sec / 8 kg
• 8 kg• vafter = ¼ m/sec
vafter =
Problem Solving #3 & #4• Now the 6 kg fish swimming at 1 m/sec swallows a 2
kg fish that is swimming towards it at 3 m/sec. • (net mv)before = (net mv)after
• (6 kg)(1 m/sec) + (2 kg)(-3 m/sec) = (6 kg + 2 kg)(vafter)
• 6 kg.m/sec + -6 kg.m/sec = (8 kg)(vafter)
• vafter = 0 m/sec
• Now the 6 kg fish swimming at 1 m/sec swallows a 2 kg fish that is swimming towards it at 4 m/sec.
• (net mv)before = (net mv)after
• (6 kg)(1 m/sec) + (2 kg)(-4 m/sec) = (6 kg + 2 kg)(vafter)
• 6 kg.m/sec + -8 kg.m/sec = (8 kg)(vafter)
• vafter = -1/4 m/sec
The Archer An archer stands at rest on frictionless ice and fires a 0.5-kg
arrow horizontally at 50.0 m/s. The combined mass of the archer and bow is 60.0 kg. With what velocity does the archer move across the ice after firing the arrow?
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Types of Collisions• Momentum is conserved in any collision• Inelastic collisions: rubber ball and hard ball
– Kinetic energy is not conserved– Perfectly inelastic collisions occur when the objects
stick together
• Elastic collisions: billiard ball– both momentum and kinetic energy are conserved
• Actual collisions– Most collisions fall between elastic and perfectly
inelastic collisions
Collision between two objects of the same mass. One mass is at rest.
Collision between two objects. One not at rest initially has twice the mass.
Collision between two objects. One at rest initially has twice the mass.
Simple Examples of Head-On Collisions
(Energy and Momentum are Both Conserved)
vmp
vmp
Collision between two objects of the same mass. One mass is at rest.
Example of Non-Head-On Collisions
(Energy and Momentum are Both Conserved)
If you vector add the total momentum after collision,you get the total momentum before collision.
Collisions Summary• In an elastic collision, both momentum and kinetic
energy are conserved• In an inelastic collision, momentum is conserved but
kinetic energy is not. Moreover, the objects do not stick together
• In a perfectly inelastic collision, momentum is conserved, kinetic energy is not, and the two objects stick together after the collision, so their final velocities are the same
• Elastic and perfectly inelastic collisions are limiting cases, most actual collisions fall in between these two types
• Momentum is conserved in all collisions
More about Perfectly Inelastic Collisions
• When two objects stick together after the collision, they have undergone a perfectly inelastic collision
• Conservation of momentum
• Kinetic energy is NOT conserved
fii vmmvmvm )( 212211
21
2211
mm
vmvmv iif
An SUV Versus a Compact An SUV with mass 1.80103 kg is travelling eastbound at +15.0
m/s, while a compact car with mass 9.00102 kg is travelling westbound at -15.0 m/s. The cars collide head-on, becoming entangled.
(a) Find the speed of the entangled cars after the collision.
(b) Find the change in the velocity of each car.
(c) Find the change in the kinetic energy of the system consisting of both cars.
(a) Find the speed of the entangled cars after the collision.
fii vmmvmvm )( 212211
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smvkgm
i
i
/15,1000.9
/15,1080.1
22
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smv f /00.5
An SUV Versus a Compact
(b) Find the change in the velocity of each car.
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smvkgm
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An SUV Versus a Compact
smvvv if /0.2022
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(c) Find the change in the kinetic energy of the system consisting of both cars.
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An SUV Versus a Compact
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More About Elastic Collisions• Both momentum and kinetic energy
are conserved
• Typically have two unknowns• Momentum is a vector quantity
– Direction is important– Be sure to have the correct signs
• Solve the equations simultaneously
222
211
222
211
22112211
2
1
2
1
2
1
2
1ffii
ffii
vmvmvmvm
vmvmvmvm
Elastic Collisions• A simpler equation can be used in place of the KE
equation
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222
211
222
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2
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21
211 iffi vvmvvm
ffii vmvmvmvm 22112211
ffii vmvmvmvm 22112211
Summary of Types of Collisions• In an elastic collision, both momentum and kinetic
energy are conserved
• In an inelastic collision, momentum is conserved but kinetic energy is not
• In a perfectly inelastic collision, momentum is conserved, kinetic energy is not, and the two objects stick together after the collision, so their final velocities are the same
iffi vvvv 2211 ffii vmvmvmvm 22112211
ffii vmvmvmvm 22112211
fii vmmvmvm )( 212211
Problem Solving for 1D Collisions, 1• Coordinates: Set up a
coordinate axis and define the velocities with respect to this axis– It is convenient to make your
axis coincide with one of the initial velocities
• Diagram: In your sketch, draw all the velocity vectors and label the velocities and the masses
Problem Solving for 1D Collisions, 2• Conservation of
Momentum: Write a general expression for the total momentum of the system before and after the collision– Equate the two total
momentum expressions– Fill in the known values
ffii vmvmvmvm 22112211
Problem Solving for 1D Collisions, 3• Conservation of Energy:
If the collision is elastic, write a second equation for conservation of KE, or the alternative equation– This only applies to perfectly
elastic collisions
• Solve: the resulting equations simultaneously
iffi vvvv 2211
One-Dimension vs Two-Dimension
Two-Dimensional Collisions• For a general collision of two objects in two-
dimensional space, the conservation of momentum principle implies that the total momentum of the system in each direction is conserved
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vmvmvmvm
vmvmvmvm
22112211
22112211
Two-Dimensional Collisions• The momentum is conserved in all directions• Use subscripts for
– Identifying the object– Indicating initial or final values– The velocity components
• If the collision is elastic, use conservation of kinetic energy as a second equation– Remember, the simpler equation can only be used
for one-dimensional situations
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fxfxixix
vmvmvmvm
vmvmvmvm
22112211
22112211
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Glancing Collisions
• The “after” velocities have x and y components• Momentum is conserved in the x direction and in the
y direction• Apply conservation of momentum separately to each
direction
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vmvmvmvm
vmvmvmvm
22112211
22112211
Problem Solving for Two-Dimensional Collisions, 3
• Conservation of Energy: If the collision is elastic, write an expression for the total energy before and after the collision– Equate the two expressions– Fill in the known values– Solve the quadratic equations
• Can’t be simplified
Problem Solving for Two-Dimensional Collisions, 4
• Solve for the unknown quantities– Solve the equations simultaneously– There will be two equations for inelastic
collisions– There will be three equations for elastic
collisions• Check to see if your answers are
consistent with the mental and pictorial representations. Check to be sure your results are realistic
Collision at an Intersection A car with mass 1.5×103 kg
traveling east at a speed of 25 m/s collides at an intersection with a 2.5×103 kg van traveling north at a speed of 20 m/s. Find the magnitude and direction of the velocity of the wreckage after the collision, assuming that the vehicles undergo a perfectly inelastic collision and assuming that friction between the vehicles and the road can be neglected. ??,/20,/25
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Collision at an Intersection
??,/20,/25
105.2,105.1 33
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cos)( fvcvfxvcfxcxf vmmvmvmp
cos)1000.4(/1075.3 34fvkgsmkg
smkgvmvmvmp viyvviyvciycyi /1000.5 4
sin)( fvcvfyvcfycyf vmmvmvmp
sin)1000.4(/1000.5 34fvkgsmkg
Collision at an Intersection
??,/20,/25
105.2,105.1 33
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4
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4
MOMENTUM VECTORS• Momentum can be analyzed by using vectors• The momentum of a car accident is equal to the
vector sum of the momentum of each car A & B before the collision.
A
B
MOMENTUM VECTORS (Continued)
• When a firecracker bursts, the vector sum of the momenta of its fragments add up to the momentum of the firecracker just before it exploded.
• The same goes for subatomic elementary particles. The tracks they leave help to determine their relative mass and type.
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