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LECTURE 5Learning ObjectivesTo apply division algorithmTo apply the Euclidean algorithm
Algorithms• An algorithm is a systematic procedures (instructions) for
calculation.
• Algorithms are basic to computer programs. Essentially, a program implements one or more algorithms. Therefore, algorithmic complexity is important.
• In this Lecture, we will study a few algorithms:• Division algorithm• Euclidean algorithm• Primality testing
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Activity 1Card 1
8 9
10 11
12 13
14 15
Card 2
4 5
6 7
12 13
14 15
Card 3
2 3
6 7
10 11
14 15
Card 4
1 3
5 7
9 11
13 15
Pick a integer between 0 to 15Is it on Card A?Is it on Card B?Is it on Card C?Is it on Card D?
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Activity 2• Write a set of instructions (algorithms) to write all the
integers from 0 to 10.
RMIT University; Taylor's College
Algorithm example 1• Step 1: Set• Step 2: • Step 3: • Step 4:, stop• Step 5: Go to Step 2
The Division Algorithm
The Division Algorithm• For any integer , we can represent a in the form of
where .
• a – integer• b – integer > 0• q – quotient • r – remainder
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• The process of expressing a in this way is the application of the division algorithm
• Essentially this says that we can divide one integer by another if the latter is positive, and that we get a quotient and a remainder
Algorithms
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• Write the following integers in the form of
1.
2.
3.
The Division Algorithm
The Division Algorithm• If a > 0, then
(floor of a/b)• Example: a = 31, b = 7
• So a = bq + r gives 31 = 7 ∙ 4 + 3• Given a, b:
b
aq
4428571.47
34
7
31
q
b
aq bqar
Valid input requires a, b to be integers and b > 0
The Euclidean Algorithm
Factors (or Divisors) and MultipleLet a, b and c be integers. • Suppose that ab = c. .
• We say that c is a multiple of a and of b.• Also, a and b are divisors or factors of c.
• Example: • 15 is the multiple of 3 and of 5.• 3 and 5 are divisors (factors) of 15.
Common Factor
Let m, n be positive integers.
• A positive integer q is a common factor or common divisor of m and n if it divides (is a divisor, or factor, of) both of them
• Examples: 1. What is the common factor for 16 and 242. What is the common factor for 15 and 30
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Common Multiple• A positive integer p is a common multiple of m and n if it is a
multiple of both of them
• Examples: 1. Which of the following is the common multiple of 3 and 6?
1. 152. 183. 244. 27
2. Which of the following is the common multiple of 4 and 9?1. 362. 543. 724. 108
Greatest Common Divisor (GCD)
Let m, n be positive integers.
• The GCD (greatest common divisor) of m and n is the greatest number which is a common divisor of both of them
• It’s also called the highest common factor or HCF
Example 1
What is the GCD of 18 and 24?
gcd (18, 24) = 6?
There is a systematic procedure for getting the GCD.It’s the Euclidean algorithm.
Least Common Multiple• Given integers m and n, their least common multiple (LCM) is the
smallest number which is a multiple of them both
• Examples: 1. What is the LCM of 8 and 6?
2. What is the LCM of 3 and 4?
),gcd(),(
nm
nmnmlcm
The least common multiple of 2 positive integers equals
their product divided by their greatest common
divisor
Euclidean Algorithm
• We can get the gcd by using the Euclidean algorithm.
• This involves repeated application of the division algorithm: a = bq + r
• Euclidean Algorithm
11
11
3221
211
10
nnn
nnnn
rqr
rrqr
rrqr
rrqb
rbqa
When the remainder becomes zero, we look back to the previous remainder, rn+1.
This must be the gcd of a and b.
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Example 2
gcd (96, 22) = ?
96 = 4 ∙ 22 + 8
22 = 2 ∙ 8 + 6
8 = 1 ∙ 6 + 2
6 = 3 ∙ 2
The last nonzero remainder was 2. Therefore, gcd (96, 22) = 2.
10562
2296
)22,96gcd(
2296)22,96(
lcm
No remainder
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Example 3
gcd (63, 256) = ?
256 = 4 ∙ 63 + 4
63 = 15 ∙ 4 + 3
4 = 1 ∙ 3 + 1
3 = 3 ∙ 1
The last nonzero remainder was 1. Therefore, gcd (63, 256) = 1.
128,161
25663
)256,63gcd(
25663)256,63(
lcm
No remainder
Extension to the Euclidean Algorithm
• If d = gcd(m, n) then d can be expressed as a linear combination
d = xm + ynof m and n, where x and y are integers
• To find x and y, we work back through the steps of the Euclidean algorithm from bottom to top
Example 4• It can be shown that gcd(22, 96) = 2:
96 = 4 ∙ 22 + 822 = 2 ∙ 8 + 68 = 1 ∙ 6 + 2
6 = 3 ∙ 2• Now we want to express 2 as a linear combination 2 = x(22) + y(96). We use the
second-last line to make 2 the subject of the equation:2 = 8 – 1 ∙ 6
• Next we use the third-last line to express 6 in terms of 22 and 8, substituting this into the equation we’ve just produced:
2 = 8 – 1 ∙ 6= 8 – 1 ∙ (22 – 2 ∙ 8)
= 8 – 1 ∙ 22 + 1 ∙ 2 ∙ 8= 3 ∙ 8 – 1 ∙ 22
Example 4 (cont.)• Finally we use the fourth-last line to express 8 in terms of 96 and 22,
substitution this into our most recent equation
2 = 3 ∙ 8 – 1 ∙ 22
2= 3 ∙ (96 – 4 ∙ 22) – 1 ∙ 22
2= 3 ∙ 96 – 3 ∙ 4 ∙ 22 – 1 ∙ 22
2= 3 ∙ 96 – 13 ∙ 22
x=3, y=-4
Example 5It can be shown that the gcd of 63 and 256 equals 1:
256 = 4 ∙ 63 + 463 = 15 ∙ 4 + 34 = 1 ∙ 3 + 1
3 = 3 ∙ 1Then we work upwards from the second-last line, as follows:
1 = 4 - 1 ∙ 3= 4 – 1 ∙ (63 – 15 ∙ 4)= 4 - 1 ∙ 63 + 1 ∙ 15 ∙ 4
= 16 ∙ 4 – 1 ∙ 63= 16 ∙ (256 – 4 ∙ 63) – 1 ∙ 63= 16 ∙ 256 – 64 ∙ 63 - 1 ∙ 63
= 16 ∙ 256 – 65 ∙ 63• So 1 = 16 ∙ 256 – 65 ∙ 63.
• In this example, 63 and 256 are relatively prime.
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Prime Numbers• A prime number is an integer ≥ 2 which has no factors
except itself and 1• Prime numbers: 2, 3, 5, 7, …
• Prime numbers play a vital role in coding and cryptography
• We say two positive integers are relatively prime (in relation to each other) if their gcd equals 1• So 63 and 256 are relatively prime (to each other), even though
neither of them is a prime number
http://news.bbc.co.uk/2/hi/science/nature/1693364.stm, accessed 1st September 2009
BBC News (online) dated 5th December 2001
Prime Number• How do you determine a prime number?
• PrinciplePrime number is an integer that is only divisible by 1 and the integer itself.
• If an integer is divisible by integers other than 1 and itself, it is not a prime number.
• Example:Is 357 a prime number?Is 271 a prime number?
Prime Number• Is 357 a prime number?
• Solution:is 357 a prime number?
•357 is not divisible by 2.
• 119357 is divisible by 3, it is not a prime number.
Prime Number• Is 271 a prime number?
• Solution:•
271 is not divisible by 2.
• 271 is not divisible by 3.
• 271 is not divisible by 5
• …Continue to divide 271 by all the odd integers. We find that 271 is not divisible by any integer.
• Conclusion: 271 is prime number.
Prime Number• Algorithm to determine a prime number.
• Assignt = an integer to be tested,d= integer as divisor
• Step 1: Set d = 2• Step 2: if t mod d = 0, then t is not a prime number. Stop.• Step 3: Set d = 3• Step 4: if t mod d = 0, then t is not a prime number. Stop.• Step 5: d = d + 2• Step 6: if go to step 4• Step 7: t is a prime number.
Activity 3• Write down the first ten prime numbers.
• 2• 3• 5• 7• 11• 13• 17• 19• 23• 29
The End
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Prime Number• Algorithm to determine the first 10 prime numbers.
• Assignt = an integer to be tested,d = integer as divisor
• Step 1: Set t = 2• Step 2: Set d = 2• Step 3: Do step 4 to step if d < t. Else, t is a prime number. Go to Step
.• Step 4: if t mod d = 0, then t is not a prime number. Stop.• Step 5: Set d = 3• Step 4: if t mod d = 0, then t is not a prime number. Stop.• Step 5: d = d + 2• Step 6: if go to step 4• Step 7: t is a prime number.
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