Fundemental Algebra

Jay and Chou have some cloths. The multiple of the cloth they have are 65m . After Jolin gave them the same length as the cloths they have together, both of them have a total of 730m. Jay and Chou return 2 of their mutiple amount of cloths to Jolin. How many cloths did them have together now, in m?

formular 1

formular 2x²+y²=(x+y)² －2xy

x²+y²=?

(1)

solution: (2)x²+y²=(x+y)²－ 2xy=(3+2)²－ 2(3)(2)=(3+12+4)²－ 12=(19)²－ 12=368－ 12=356

Return To the Problem

Solving……

Solution

After return 2 of the multiple of the cloths to Jolin,

=(x+y)² － 2xy

(x+y)² － 2xy=730 －2(65)

=730 － 130 =600

Ans:They have 600m of cloths together.

1. If both of them have a total of 196m, Jay and Chou have the same amount of cloth too, what is the multiple of the cloth they have, in m?

2. If both of them have a total of 14m, Jay and Chou have not the same amount of cloth, then how many combinations that can form? And after Jolin gave them the same length as the cloths they have together, both of them have a total of 196m. Jay and Chou return 2 of their mutiple amount of cloths to Jolin. How many cloths did them have together now, in m?Give one example about the multiple of the cloth they have, in m.

question1196÷2=9898²=9604

196question2=14

14=1+13 2+12 3+11 4+10 5+10 6+9 7+7 (7 combinations)

Ans:There are 7 combinations.

Example: if x=1,y=13(x+y)²=(1+13)² =1+2(1)(13)+169 =1+26+169 =196

The EndThank You