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d) Determinar la deflexión en el centro del tramo 4-5
Empleando el método de Castigliano:
M 4a=(28.357+Q2 )X−40.81−2.5 X 2→∂M∂Q
=X /2
Mab=(28.357+Q2 )X−40.81−2.5 X 2−5(x−3)→∂M∂Q
=X /2
M 5 c=(26.643+Q2 )X−33.100−2.5 X2→ ∂M∂Q
=X /2
M cb=(26.643+Q2 )X−33.100−2.5 X2−5(x−3)→∂M∂Q
=X /2
δb=δcl (45 )= 13.24 EI
∫0
3 (28.357 X−40.81−2.5 X2 ) Xdx2
+ 13.24 EI
∫3
4.5 (28.357 X−40.81−2.5 X2−5 ( x−3 )) Xdx2dx
+¿ 13.24 EI
∫0
3 (26.643 X−33.100−2.5 X2 ) Xdx2
+ 13.24 EI
∫3
4.5 (26.643 X−33.100−2.5 X2−5 ( x−3 ) ) Xdx2
+¿¿¿
δb=δcl (45 )=56.28212/EI ↓
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