CHAPTER TWO REVIEW. QUESTION ONE Is the relation a function? Why or why not?

CHAPTER TWO REVIEW

QUESTION ONE

Is the relation a function? Why or why not?

QUESTION ONE

Is the relation a function? Why or why not?No, (2,2) and (2,1) havethe same input, but different outputs. For a function, each input can only have one output.It does not pass the vertical line test.

Q UESTION TWO

Is the relation a function? Why or why not?

(1,2), (2,3), (3,4), (4,5), (5,6)

Q UESTION TWO

Is the relation a function? Why or why not?

(1,2), (2,3), (3,4), (4,5), (5,6)

Yes, for each input, there is exactly one output.

QUESTION THREE

Find the domain and range of the relation.

(5,0),(8,3), (1,3), (-5,2), (3,8)

QUESTION THREE

Find the domain and range of the relation.

(5,0),(8,3), (1,3), (-5,2), (3,8)

Domain: -5, 1, 3, 5, 8

Range: 0, 2, 3, 8

QUESTION FOUR

Given f(x) = -2x – 4 and g(x) = -x – 6.Find f(2) + g(-6)

QUESTION FOUR

Given f(x) = -2x – 4 and g(x) = -x – 6.Find f(2) + g(-6)

f(2) + g(-6) = -8

QUESTION FIVE

Are the lines parallel or perpendicular? Why?

y = 2x + 62x – y = 7

QUESTION FIVE

Are the lines parallel or perpendicular? Why?

y = 2x + 62x – y = 7

The lines are parallel, because the slopes are the same.

QUESTION SIX

Are the lines parallel or perpendicular? Why?

3x + 6y = 12y = 2x + 8

QUESTION SIX

Are the lines parallel or perpendicular? Why?

3x + 6y = 12y = 2x + 8

The lines are perpendicular, because the slopes are negative reciprocals of each other.

QUESTION SEVEN

Write the equation of the line given m = 2 andthrough (3,4) in point-slope form, slope-intercept form and standard form.

QUESTION SEVEN

Write the equation of the line given m = 2 andthrough (3,4) in point-slope form, slope-intercept form and standard form.

(y – 4) = 2(x – 3)y = 2x – 2-2x + y = -2

QUESTION EIGHT

Write the equation of the line through (-4, 6) and perpendicular to y = -2x + 7 in point-slope form, slope-intercept form and standard form.

QUESTION EIGHT

Write the equation of the line through (-4, 6) and perpendicular to y = -2x + 7 in point-slope form, slope-intercept form and standard form.

(y – 6) = ½(x + 4)y = ½ x + 8-½x + y = 8

QUESTION NINE

Given 2y = -4x – 12, find the slope, x-intercept, y-intercept and then graph.

QUESTION NINE

Given 2y = -4x – 12, find the slope, x-intercept, y-intercept and then graph.

Slope is -2x-intercept is (-3,0)y-intercept is (0, -6)

QUESTION TEN

Graph: 2x – 3y > -12

QUESTION TEN

Graph: 2x – 3y > -12

QUESTION ELEVEN

Graph: y = |x – 4| + 2

QUESTION ELEVEN

Graph: y = |x – 4| + 2

QUESTION TWELVE

Graph: 4y = -2x - 8

QUESTION TWELVE

Graph: 4y = -2x - 8

QUESTION THIRTEEN

Graph: y ≥ -4 x - 2

QUESTION THIRTEEN

Graph: y > -4 x - 2

QUESTION FOURTEENAt the beginning of week 7, the math teacher has 250 pencils. At the beginning of week 10, the teacher has 220 pencils.

a)Write an equation to model the number of pencils the teacher has after x weeks.

b)How many pencils will the teacher have after 18 weeks?

QUESTION FOURTEENAt the beginning of week 7, the math teacher has 250 pencils. At the beginning of week 10, the teacher has 220 pencils.

a)Write an equation to model the number of pencils the teacher has after x weeks.

y= -10x +320

b)How many pencils will the teacher have after 18 weeks?

140 pencils

RETEST REVIEWQUESTION ONE

Solve and graph: -16 < -3x – 5 < 4

RETEST REVIEWQUESTION ONE

Solve and graph: -16 < -3x – 5 < 4

−3<x<

113

−3

113

RETEST REVIEWQUESTION TWO

Solve and graph: -3|4x – 1| - 6 = -9

RETEST REVIEWQUESTION TWO

Solve and graph: -3|4x – 1| - 6 = -9

x = 0,

12

0

12