Chapter 2: Principles of X-Ray Fluorescencensl/Lectures/phys10262/art-chap2-1.pdfChapter 2:...

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Chapter 2: Principles of Radiography, X-Ray Absorption, and X-Ray Fluorescence

• X-ray fluorescence is amethod to understand thechemical and elementalconstituency of the artifacts

There is a multitude of applications:Analysis of coins, or metal materials,pottery techniques,paper & paintings.

• Radiography is a method to study invisible details, cracks, joints, in different archaeological artifacts

• Radiography is the firstsurvey technique;

• X-ray fluorescence ison-site analysis technique

The Value of Art and Paintings

Investment in Analytical Techniques

X-ray facilities as quick testing tool

Electron Beam

Tungsten ormolybdenum

2.1. Physics of X-ray Sources

bremsstrahlung

characteristic X-rays

K-lines

Emax

Characteristic X-rays: Ex = h·ν = h·c/λ = ΔEkin = Ekin(i)-Ekin(f)

Bremsstrahlung: Emax=Ekin(i)

EK=RH·(Z-1)2 ·(1-1/4)

X-ray beamThe X-ray energy distribution is characterized byBremstrahlung and characteristic lines dependingon anode material and electron energy. The use of filters originates a quasi-monochromatic x-rays beam.

Quasi monochromatic x-rays

Low energy x-rays are absorbed in filter material

X-ray absorptionThe effect of X-ray radiography, depends on the absorption (transmission) probability of X-rays through sample matter and the photographic plate to generate an image. The image results from the difference in X-ray absorption probabilities which is defined by the “absorption coefficient μ for a particular material!

deIdI ⋅−⋅= μ0)(

μ is in units [1/cm]

Often tabulated as μ/ρ [cm2/g] with ρbeing the density of the material [g/cm3]

0

0.2

0.4

0.6

0.8

1

1.2

0 1 2 3 4 5 6

thickness

inte

nsity transmitted intensity

absorbed intensity

X-ray absorption mechanism

λ~1/E

As higher energy as less absorption

X-rays absorption in matter increases with decreasing energy

Absorption: μ ~ σ ~ E-3.Absorption edges indicate additional excitation of electrons from the next inner shell (M,L,K).

M-edge

L-edge

K-edge

K-edge

IncomingX-ray photon

Absorption edgesThe absorption edges correspond to the ionization energies for electrons from the inner shells of the atom: K=edge, L-edge, M-edge ...

K-edge: EK= (Z-1)2·13.6L-edge: EL= (Z-σL)2·13.6·1/4M-edge: EM= (Z-σM)2·13.6·1/9

Absorption edges for each element can be found in tabulations e.g.http://www.csrri.iit.edu/mucal.html

Data for Zn; Z = 30atomic weight = 65.3800; density = 7.14000 g/cm3

K-edge: 9.65900 keV L-edges: 1.19600, 1.04400, 1.02100 keV M-edge: 0.139000 keV

Data for Pb; Z = 82 atomic weight = 207.210; density = 11.3400 g/cm3

K-edge: 88.0060 keV L-edges: 15.8600, 15.1980, 13.0350 keV M-edge: 3.85000 keV

2.2. Radiography with X-raysClassical technique (photography) only with high energyphotons (X-rays). X-ray sensitive film or photomultiplier.

Material has no (or reduced) opacity for X-rays, can beused for depth profiling and material structure analysis.

X-rays partly absorbed

Image fromtransmittedx-rays

J. Lang & A. Middleton; Radiography of Cultural Material; Butterworth Heinemann, Oxford 1997; Library # N 8558 .R33 1997

X-ray tube

painting

photo-plate

The Virgin and the Child

The cradle at the back of the panel appears as grid structure on the X-radiograph. To improve the image, the spaces in the cradle were filled with a resin with an X-ray opacity similar to that of the wooden cradle.

Workshop of Dirck BoutsNetherland, c. 1420-1475Oil on wood, 30.5 x 21.6 cm

X-ray energies

I d I e ndi

i( ) = ⋅ = ⋅− ⋅ ∑0 0

μ μ σ

X-rays need energy to pass through the material to be analyzed and to reach the detector or photographic plate. X-rays had insufficient energy to pass through the wood.

More absorption with dmore absorption with ρ

30% reducedtransmission through wood>50% reducedtransmissionin heavy metalpaint content.

energy [keV]

0.1

1

10

100

1000

10000

0 100 200 300 400 500 600

µ c

oeffi

cien

t

carboncadmiumlead

X-ray absorption coefficient

0

0.2

0.4

0.6

0.8

1

1.2

0 100 200 300 400 500 600

energy [keV]

Tran

smis

sion

I(d

)/I0

Cadmium (0.1cm)wood (2cm)canvas (0.2cm)Lead (0.1cm)

X-ray transmission

Details of the FaceSome pigments, including lead white and lead-tin yellow, contain elements of high atomic weight. These colors will absorb X-rays, will locally block the blackening of the film, and will appear as light areas in the X-radiograph. Here, lead white was locally applied in the under-modeling of the Virgin's face, on the ridge of the nose, on the upper lip, and in the eye sockets. Other pigments and cracks absorbed the X-rays to a lesser extent, and thus appear dark on the X-radiograph.

Choice of Energy

The optimum energy for X-ray beams depend on interaction cross section and on the nature (density) of material. The differences in attenuation coefficients should be maximized by choice of energy.

Z=48 CadmiumZ=51 Antimony

Z=79 GoldZ=29 Copper

Co-Au,Cd,Sb

Portrait of a Man, 1541

The X-radiograph of Portrait of a Man reveals that the white paint for the collar extends under the area that is now black.

The join between two boards shows up as a light area in the X-radiograph because the boards had come apart and were glued together using an adhesive mixed with lead white.

Master of the 1540sNetherland, 1540-1551Oil on wood, 40.3 x 35 cm

Analysis of pastdamage & repair

Lead in the Portrait of a Man Suppose you have an X-ray source with an intensity of I0. Calculate the difference in absorption for the dPb= 0.1 cm layer of white lead based paint with an attenuation coefficient of μPb=22.6 cm-1 versus the absorption in the doil/canvas= 0.3 cm thick layers of canvas and oil paint with an attenuation coefficient μC=0.21cm-1.

I d I e I e I

I d I e I e I

Pbd

Cd

Pb Pb

C C

( ) .

( ) .

.

.

= ⋅ = ⋅ = ⋅

−= ⋅ = ⋅ = ⋅

-

− ⋅ −

− ⋅ −

0 02 26

0

0 00 063

0

0104

0 94

μ

μ

only 10% o f the x rays pass through the lead -paint layer!

94% of the x rays pass through the canvas -oil paint layer!

Vermeer’s Woman with a String of Pearls

Covered wall-hangingtile structure of the floordetails of the chair

1660-1665

Another Vermeer

Vermeer van Delft; The woman with the balance

LOOKING INSIDE A WORK OF ARTThe Thinker by Auguste Rodin,France 1880

The sculpture is extremely frontal, with most of its weight projecting forward. Such an imbalance is anchored by a lead counterweight placed in the interior of the base. In the x-radiograph, the lead anchor is visible as a white mass at the back of the base. Also visible in the x-radiograph are iron armatures inside the sculpture. Seen as curling gray forms, the armatures were used to hold internal core material in place during casting.

Get the right energy!

To get difference in intensity:

I dI d

eCu

Pb

dPb Cu( )( )

( )= − ⋅μ μ

high energy x-rays are required to penetrate massive metal material

For calculation of attenuation coefficients m see:http://www.csrri.iit.edu/mucal.html

Reconstruction of Art

Ornate iron cross of unknown origin from around the mid-17th century. Traces of gold on the surface indicate that the cross was once gilt. X-ray radiography reveals original design and guided the restoration process.

before after

X-ray radiograph

Back to the value of paintings

Summary X-ray radiography

Radiography is a powerful tool with a wide range of applications. Its usefulness is mainly based on the differences in material densities which affects the x-ray attenuation coefficients. This determines the x-ray opacity for heavy metal or high density material compared to low density material like paper. The method gives only qualitative differences on photo-screen, it is a tool for first investigation, a detailed analysis requires more sophisticated studies.

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