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INSTITUT KEMAHIRAN MARA LUMUTCERTIFICATION IN COMPUTER ENGINEERING TECHNOLOGY
(NETWORKING)
NAME: MUHAMMAD FAKHRUL RADZI BIN JAFFER@JAFFAR
IC NO : 950418-08-5371
MATRIX NO: 1401119
SESION : JULY-DISEMBER 2014
SEMESTER: 2
LECTURER: ENCIK MOHD SHUKRI BIN MUHAMMAD HUSIN
KFC 2044 NETWORK FUNDAMENTAL
MUHAMMAD FAKHRUL RADZI BIN JAFFER@JAFFAR
2
NO INDEX PAGE
1 IP ADDRESS CLASSES CALCULATION 3-5
2 PROBLEM 1 6-7
3 PROBLEM 2 8-9
4 PROBLEM 3 10-11
5 PROBELM 4 12-13
6 PROBLEM 5 14-15
7 PROBLEM 6 16-17
8 SUBNETTING CALCUTION 18
9 PROBLEM 1 18-19
10 PROBLEM 2 20-21
11 PROBLEM 3 22-23
12 PROBLEM 4 24-25
13 PROBLEM 5 26-27
14 PROBLEM 6 28-29
KFC 2044 NETWORK FUNDAMENTAL
MUHAMMAD FAKHRUL RADZI BIN JAFFER@JAFFAR
3
IP ADDRESS
STEP OF IP ADDRESS CLASSES CALCULATION
TASK 1 : FOR GIVEN IP ADDRESS DETERMINE NETWORK INFORMATION
GIVEN: IP ADDRESS : 172.25.114.250NETWORK MASK : 255.255.0.0(/16)
FIND:NETWORK ADDRESS :172.25.0.0NETWORK BROADCAST :172.25.255.255TOTAL NUMBER OF HOST BITS :66534NUMBER OF HOST : 16
STEP 1
TRANSLATE HOST IP ADDRESS AND NETWORK MASK INTO BINARY NOTATION
FORMULA
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 1
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 1OCTET 1 1 0 1 0 1 1 1 0OCTET 2 0 0 0 1 1 0 0 1OCTET 3 0 1 1 1 0 0 1 0OCTET 4 1 1 1 1 1 0 1 0
BINARY NUMBER
LET
KFC 2044 NETWORK FUNDAMENTAL
MUHAMMAD FAKHRUL RADZI BIN JAFFER@JAFFAR
4
OCTET 1 128 + 32 + 8 + 4 = 172OCTET 2 16 +8 + 1 25OCTET 3 64 + 32 + 16 + 2 114OCTET 4 128 + 64 + 32 + 16 + 8+ 2 250
NETWORK MASK
FORMULA27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 1
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 1OCTET 1 1 1 1 1 1 1 1 1OCTET 2 1 1 1 1 1 1 1 1OCTET 3 0 0 0 0 0 0 0 0OCTET 4 0 0 0 0 0 0 0 0
BINARY NUMBER
LET OCTET 1 128 + 64 + 32 + 16 + 8 + 2 + 1 = 255OCTET 2 128 + 64 + 32 + 16 + 8 + 2 + 1 = 255OCTET 3 0 = 0OCTET 4 0 = 0
STEP 2
KFC 2044 NETWORK FUNDAMENTAL
MUHAMMAD FAKHRUL RADZI BIN JAFFER@JAFFAR
5
DETERMINE THE NETWORK ADDRESS
IP ADDRESS172 25 114 250
10101100 00011001 0111001 11111010
NETWORK MASS
225 225 0 0
11111111 11111111 00000000 00000000
NETWORK ADDRESS
172 25 0 0
10101100 00011001 00000000 00000000
STEP 3DETERMINE THE BROADCAST ADDRESS FOR THE NETWORK ADDRESS
NETWORK ADDRESS
172 25 0 0
10101100 00011001 00000000 00000000
MASK
255 255 0 0
11111111 11111111 00000000 00000000
BROADCAST
172 25 255 255
10101100 00011001 11111111 11111111
NUMBER OF HOST BITS (n) : 16TOTAL NUMBER OF HOST : 2n - 2 USE THE FORMULA TO CALCULATE
KFC 2044 NETWORK FUNDAMENTAL
MUHAMMAD FAKHRUL RADZI BIN JAFFER@JAFFAR
6
= 216 - 2= 65 536 - 2= 65 534
TASK 2 : CHALLENGE
PROBLEM 1
HOST IP ADDRESS 172.30.1.33NETWORK MASK 255.255.0.0NETWORK ADDRESS 172.30.0.0NETWORK BROADCAST ADDRESS 172.30.255.255TOTAL NUMBER OF HOST BITS 65535NUMBER OF HOSTS 16 NETWORK ADDRESS
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 1 CALCULATE NETWORK ADDRESS
1 0 1 0 1 1 0 0 128 + 32 + 8 + 4 172
0 0 0 1 1 1 1 0 16 + 8 + 4 + 2 30
0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0
AND THE ANSWER NETWORK ADDRESS IS 172.30.0.0
KFC 2044 NETWORK FUNDAMENTAL
MUHAMMAD FAKHRUL RADZI BIN JAFFER@JAFFAR
7
NETWORK BROADCAST ADDRESS
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 1 CALCULATENETWORK
BROADCAST ADDRESS
1 0 1 0 1 1 0 0 128 + 32 + 8 + 4 = 172
0 0 0 1 1 1 1 0 16 + 8 + 4 + 2 + 1 30
1 1 1 1 1 1 1 1128 + 64 + 32 + 16 +
8 + 4 + 2 + 1 255
1 1 1 1 1 1 1 1128 + 64 + 32 + 16 +
8 + 4 + 2 + 1 255
AND THE ANSWER NETWORK BROADCAST ADDRESS IS 172.30.255
USE THE FORMULA N=16
= 2n-2= 216 = 65536 - 2 = 65 534 NUMBER OF HOST BITS = 16
TASK 2 PROBLEM 2
KFC 2044 NETWORK FUNDAMENTAL
MUHAMMAD FAKHRUL RADZI BIN JAFFER@JAFFAR
8
HOST IP ADDRESS 172.30.1.33NETWORK MASK 255.255.255.0NETWORK ADDRESS 172.30.1.0NETWORK BROADCAST 172.30.1.255TOTAL NUMBER OF HOST BITS 254NUMBER OF HOSTS 8
NETWORK ADDRESS
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 1 CALCULATE NETWORK ADDRESS
1 0 1 0 1 1 0 0 128 + 32 + 8 + 4
172
0 0 0 1 1 1 1 0 16 + 8 + 4 + 2 30
0 0 0 0 0 0 0 1 1 1
0 0 0 0 0 0 0 0 0 0
THE ANSWER NETWORK ADDRESS IS 172.30.1.0
NETWORK BROADCAST
KFC 2044 NETWORK FUNDAMENTAL
MUHAMMAD FAKHRUL RADZI BIN JAFFER@JAFFAR
9
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 1 CALCULATE NETWORK BROADCAST
1 0 1 0 1 1 0 0 128 + 32 + 8 + 4 172
0 0 0 1 1 1 1 0 16 + 8 + 4 + 2 30
0 0 0 0 0 0 0 0 1 1
1 1 1 1 1 1 1 1128 + 64 + 32 + 16 + 8 + 4 + 2 +
1255
AND THE ANSWER NETWORK BROADCAST ADDRESS IS 172.30.1.255
USE THE FORMULA N = 8
= 2n - 2= 28 = 256 - 2 = 254
NUMBER OF HOST = 8
TASK 2KFC 2044 NETWORK FUNDAMENTAL
MUHAMMAD FAKHRUL RADZI BIN JAFFER@JAFFAR
10
PROBLEM 3
HOST IP ADDRESS 192.168.10.234NETWORK MASK 255.255.255.0NETWORK ADDRESS 192.168.10.0NETWORK BROADCAST ADDRESS 192.168.10.255TOTAL NUMBER OF HOST BITS 254NUMBER OF HOSTS 8
NETWORK ADDRESS
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 1 CALCULATENETWORK ADDRESS
1 1 0 0 0 0 0 0 128 + 64 192
1 0 1 0 1 0 0 0 128 + 32 + 8 168
0 0 0 0 1 0 1 0 8 + 2 10
0 0 0 0 0 0 0 0 0 0
ANSWER THE NETWORK ADDRESS IS 192.168.10.0
NETWORK BROADCAST
KFC 2044 NETWORK FUNDAMENTAL
MUHAMMAD FAKHRUL RADZI BIN JAFFER@JAFFAR
11
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 1 CALCULATE NETWORK BROADCAST
1 1 0 0 0 0 0 0 128 + 64 192
1 0 1 0 1 0 0 0 128 + 32 + 8 168
0 0 0 0 1 0 1 0 8 + 2 10
1 1 1 1 1 1 1 1128 + 64 + 32 + 16 + 8 + 4 + 2 + 1
255
ANSWER THE NETWORK BROADCAST IS 192.168.10.255
USE THE FORMULA N = 8
= 2n - 2 = 28 = 256 - 2 = 254
NUMBER OF HOST = 8
TASK 2
KFC 2044 NETWORK FUNDAMENTAL
MUHAMMAD FAKHRUL RADZI BIN JAFFER@JAFFAR
12
PROBLEM 4
HOST IP ADDRESS 172.17.99.71NETWORK MASK 255.255.0.0NETWORK ADDRESS 172.17.0.0NETWORK BROADCAST ADDRESS 127.17.255.255TOTAL NUMBER OF HOST BITS 65 534NUMBER OF HOSTS 16
NETWORK ADDRESS
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 1 CALCULATE NETWORK ADDRESS
1 0 1 0 1 1 0 0 128 + 32 + 8 + 4
172
0 0 0 1 0 0 0 1 16 + 1 17
0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0
ANSWER THE NETWORK ADDRESS IS 172.17.0.0
NETWORK BROADCAST
KFC 2044 NETWORK FUNDAMENTAL
MUHAMMAD FAKHRUL RADZI BIN JAFFER@JAFFAR
13
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 1 CALCULATE NETWORK BROADCAST
1 0 1 0 1 1 0 0 128 + 32 + 8 + 4
172
0 0 0 1 0 0 1 0 16 + 1 17
1 1 1 1 1 1 1 1 128 + 64 + 32 + 16 + 8 + 4 + 2 + 1
255
1 1 1 1 1 1 1 1 128 + 64 + 32 + 16 + 8 + 4 + 2 +1
255
ANSWER THE NETWORK BROADCAST IS 172.17.255
USE THE FORMULA N = 16
= 2n - 2= 216 = 65536 -2 65534
NUMBER OF HOST BITS = 16
TASK 2
KFC 2044 NETWORK FUNDAMENTAL
MUHAMMAD FAKHRUL RADZI BIN JAFFER@JAFFAR
14
PROBLEM 5
HOST IP ADDRESS 192.168.3.219NETWORK MASK 255.255.0.0NETWORK ADDRESS 192.168.0.0NETWORK BROADCAST ADDRESS 192.168.255.255TOTAL NUMBER OF HOST BITS 65 534NUMBER OF HOSTS 16
NETWORK ADDRESS
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 1 CALCULATENETWORK
BROADCAST
1 1 0 0 0 0 0 0 128 + 64 + 192
1 0 1 0 1 0 0 0 128 + 32 + 8 168
0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0
ANSWER THE NETWORK ADDRESS IS 192.168.0.0
KFC 2044 NETWORK FUNDAMENTAL
MUHAMMAD FAKHRUL RADZI BIN JAFFER@JAFFAR
15
NETWORK BROADCAST
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 1 CALCULATENETWORK
BROADCAST
1 1 0 0 0 0 0 0 128 + 64 + 8 192
1 0 1 0 1 0 0 0 128 + 32 + 8 168
1 1 1 1 1 1 1 1128 + 64 + 32 + 16 + 8 + 4 + 2 + 1
255
1 1 1 1 1 1 1 1128 + 62 +
32 +16 + 8 + 4 + 2 + 1
255
ANSWER THE NETWORK BROADCAST IS 192.168.255.255
USE THE FORMULA N = 16 = 2n - 2
= 216 = 65 534
NUMBER OF HOST = 16
TASK 2
KFC 2044 NETWORK FUNDAMENTAL
MUHAMMAD FAKHRUL RADZI BIN JAFFER@JAFFAR
16
PROBLEM 6
HOST IP ADDRESS 192.168.3.219NETWORK MASK 255.255.255.224NETWORK ADDRESS 192.168.3.192NETWORK BROADCAST ADDRESS 192.168.3.223TOTAL NUMBER OF HOST BITS 30NUMBER OF HOSTS 5
NETWORK ADDRESS
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 1 CALCULATE NETWORK ADDRESS
1 1 0 0 0 0 0 0 128 + 64 192
1 0 1 0 1 0 0 0 128 + 32 + 16 + 8 168
0 0 0 0 0 0 1 1 2 + 1 3
1 1 0 0 0 0 0 0 128 + 64 192
ANSWER THE NETWORK ADDRESS IS 192.168.3.192
NETWORK BROADCAST
KFC 2044 NETWORK FUNDAMENTAL
MUHAMMAD FAKHRUL RADZI BIN JAFFER@JAFFAR
17
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 1 CALCULATE NETWORK BROADCAST
1 0 1 0 0 0 0 0 128 + 32 192
1 0 1 0 1 0 0 0 128 + 32 + 8 168
0 0 0 0 0 0 1 1 2 + 1 3
1 1 0 1 1 1 1 1128 + 64 + 16 + 8 + 4 +
2 + 1223
ANSWER THE NETWORK BROADCAST IS 192.168.3.223
USE THE FORMULA N= 5
= 2n-2
= 25 = 32 - 2 = 30
NUMBER OF HOST = 5
STEP OF SUBNETING CALCULATION
KFC 2044 NETWORK FUNDAMENTAL
MUHAMMAD FAKHRUL RADZI BIN JAFFER@JAFFAR
18
TASK 1 : FOR GIVEN IP ADDRESS AND SUBNET MASK , DETERMINE SUBNET INFORMATION GIVEN :
HOST IP ADDRESS 172.25.114.250 NETWORK MASK 255.255.0.0 (/16)SUBNET MASK 255.255.255.192 (/26)
FIND : PROBLEM 1
NUMBER OF SUBNET BITS 10
NUMBER OF SUBNETS 210=1024 SUBNETS
NUMBER OF HOST BITS PER SUBNET 6 BITS
NUMBER OF USABLE HOST PER SUBNET 26 = 64 -2 = 62 HOSTS PER SUBNET
SUBNET ADDRESS FOR THIS IP ADDRESS 172.25.114.192
IP ADDRESS OF FIRST HOST ON THIS SUBNET 172.25.114.193
IP ADDRESS OF LAST HOST ON THIS SUBNET 172.25.114.254
BROADCAST ADDRESS FOR THIS SUBNET 172.25.114.255
HOST IP 172 30 1 33KFC 2044 NETWORK FUNDAMENTAL
MUHAMMAD FAKHRUL RADZI BIN JAFFER@JAFFAR
19
ADDRESS
IP ADDRESS 10101100 00011110 00000001 00100001
SUBNET MASK X 11111111 11111111 11111111 11111100
SUBNET ADDRESS
10101100 00011110 00000001
00100000
SUBNET ADDRESS FOR
THIS IP ADDRESS =
172 25 114 192
172.25.114.192
IP ADDREES OF FIRST HOST = 172.30.1.33
192 +
62 HOST
IP ADDRESS OF LAST HOST CALCULATION
= 254IP ADDRESS OF LAST HOST = 172.30.1.34
NETWORK BROADCAST = 172.30.1.255
TASK 1
KFC 2044 NETWORK FUNDAMENTAL
MUHAMMAD FAKHRUL RADZI BIN JAFFER@JAFFAR
MULTIPLE
ANSWER
20
PROBLEM 2
HOST IP ADDRESS 172.30.1.33
SUBNET MASK 255.255.255.252
NUMBER OF SUBNET BITS 14
NUMBER OF SUBNETS 214 = 16384
NUMBER OF HOST BITS PER SUBNET 4 BIT
NUMBER OF USABLE HOSTS PER SUBNET 22 =4-2 = 2 HOST PER SUBNET
SUBNET ADDRESS FOR THIS IP ADDRESS 172.30.1.32
IP ADDRESS OF FIRST HOST ON THIS SUBNET
172.30.1.33
IP ADDRESS OF LAST HOST ON SUBNET 172.30.1.34
BROADCAST ADDRESS FOR THIS SUBNET 172.30.1.35
KFC 2044 NETWORK FUNDAMENTAL
MUHAMMAD FAKHRUL RADZI BIN JAFFER@JAFFAR
21
MOST IP ADDRESS
172 30 1 33
IP ADDRESS 10101100 00011110 00000001
001000001
SUBNET MASK X 11111111 11111111 11111111 11111100
SUBNET ADDRESS
10101100 00011110 00000001
001000000
SUBNET ADDRESS FOR
THIS IP ADDRESS
172 30 1 32
172.30.1.32
IP ADDRESS OF FIRST HOST= 172.30.1.33
32 +
2 HOSTS
IP ADDRESS OS LAST HOST CALCULATION
= 34IP ADDRESS OF LAST HOST= 172.30.1.34
BROADCAST ADDRESS = 172.30.1.255
KFC 2044 NETWORK FUNDAMENTAL
MUHAMMAD FAKHRUL RADZI BIN JAFFER@JAFFAR
MULTIPLE
ANSWER
22
TASK 1
PROBLEM 3
HOST IP ADDRESS 192.192.10.234
SUBNET MASK 255.255.255.0
NUMBER OF SUBNET BIT 8
NUMBER OF SUBNETS 28 =256
NUMBER OF HOST BITS PER SUBNET 8 BITS
NUMBER OF USEABLE HOSTS PER SUBNET 28 = 256-2 = 254 HOSTS PER SUBNET
SUBNET ADDRESS FOR THIS IP ADDRESS 192.192.10.0
IP ADDRESS OF FIRST HOST ON THIS SUBNET 192.192.10.1
IP ADDRESS OF LAST HOST ON SUBNET 192.192.10.254
BROADCAST ADDRESS FOR THIS SUBNET 192.192.10.255
KFC 2044 NETWORK FUNDAMENTAL
MUHAMMAD FAKHRUL RADZI BIN JAFFER@JAFFAR
23
HOST IP ADDRSS
192 192 10 234
IP ADDRESS 11000000 11000000 00001010 11101010
SUBNET MASK
X 11111111 11111111 11111111 00000000
SUBNET ADDRESS
11000000 11000000 000001010 00000000
SUBNET ADDRESS FOR THIS IP ADDRESS
192 192 10 0
192.192.10.0
IP ADDRESS OF FIRST HOST= 192.192.10.1 0+
254 HOSTS
IP ADDRESS OF LAST CALCULATION
= 254IP ADDRESS OF LAST HOST= 192.192.10.254
BROADCAST ADDRESS = 192.192.10.255
KFC 2044 NETWORK FUNDAMENTAL
MUHAMMAD FAKHRUL RADZI BIN JAFFER@JAFFAR
MULTIPLE
ANSWER
24
TASK 1
PROBLEM 4
HOST IP ADDRESS 172.17.99.71
SUBNET MASK 255.255.0.0
NUMBER OF SUBNETS BITS 0
NUMBER OF SUBNETS 20 = 1
NUMBER OF HOST BITS PER SUBNET16
NUMBER OF USABLE HOSTS PER SUBNET 216 65536 - 2 = 65534 HOSTS PER SUBNET
SUBNETS ADDRESS FOR THIS IP ADDRESS 172.17.0.0
IP ADDRESS OF FIRST HOST ON THIS SUBNET
172.17.0.1
IP ADDRESS OF LAST HOST ON SUBNET 172.17.255.254
BROADCAST ADDRESS FOR THIS SUBNET 172.17.255.255
KFC 2044 NETWORK FUNDAMENTAL
MUHAMMAD FAKHRUL RADZI BIN JAFFER@JAFFAR
25
HOST IP ADDRESS
172 17 99 71
IP ADDRESS 1O1O1100 00010001 0110001101000111
SUBNET MASK X 11111111 11111111 00000000 00000000
SUBNET ADDRESS
10101100 00010001 0000000100000000
SUBNET ADDRESS FOR
THIS IP ADDRESS
172 17 0 0
172.17.0.0
IP ADDRESS OF FIRST = 172.17.0.1
0+
254 HOSTS
IP ADDRESS OF LAST HOST CALCULATION
= 254IP ADDRESS OF LAST HOST = 172.17.255.254
BROADCAST ADDRESS = 192.192.10.255
KFC 2044 NETWORK FUNDAMENTAL
MUHAMMAD FAKHRUL RADZI BIN JAFFER@JAFFAR
MULTIPLE
ANSWER
26
TASK 1
PROBLEM 5
HOST IP ADDRESS 192.168.3.219
SUBNET MASK 255.255.255.0
NUMBER OF SUBNET BIT 8
NUMBER OF SUBNET 28 = 256
NUMBER OF HOST BITS PER SUBNET 8 BITS
NUMBER OF USABLE MOSTS PER SUBNET 28 = 256 - 2 = 254 HOSTS PER SUBNET
SUBNET ADDRESS FOR THIS IP ADDRESS 192.168.3.0
IP ADDRESS OF FIRST HOST ON THIS SUBNET
192.168.3.1
IP ADDRESS OF LAST HOST ON SUBNET 192.168.3.254
BROADCAST ADDRESS FOR THIS SUBNET 192.168.3.255
HOST IP ADDRESS
192 168 3 219
KFC 2044 NETWORK FUNDAMENTAL
MUHAMMAD FAKHRUL RADZI BIN JAFFER@JAFFAR
27
IP ADDRESS 11000000 10101000 0000001111011011
SUBNET MASK X 11111111 1111111 11111111 00000000
SUBNET ADDRESS
11000000 10101000 0000001100000000
SUBNET ADDRESS FOR
THIS IP ADDRESS
192 168 3 0
192.168.3.0
IP ADDRESS OF FIRST HOST = 192.168.3.1 0
+254
IP ADDRESS OF LAST HOST CALCULATION
= 254IP ADDRESS OF LAST HOST
=192.168.3.254
BROADCAST ADDRESS = 192.192.10.255
TASK 1
PROBLEM 6KFC 2044 NETWORK FUNDAMENTAL
MUHAMMAD FAKHRUL RADZI BIN JAFFER@JAFFAR
MULTIPLE
ANSWER
28
HOST IP ADDRESS 192.168.3.219
SUBNET MASK 255.255.255.0
NUMBER OF SUBNET BIT 14
NUMBER OF SUBNET 214 =16384 SUBNET
NUMBER OF HOST BITS PER SUBNET 14
NUMBER OF USABLE HOSTS PER SUBNET 22 =4-2 = 2 HOSTS PER SUBNET
SUBNET ADDRESS FOR THIS IP ADDRESS 192.168.3.216
IP ADDRESS OF FIRST HOST THIS SUBNET 192.168.3.217
IP ADDRESS OF LAST HOST THIS SUBNET 192.168.3.218
BROADCAST ADDRESS FOR THIS SUBNET 192.168.3.219
HOST IP ADDRESS 172 168 3 219
IP ADDRESS 11000000 10101000 00000011 11011011
KFC 2044 NETWORK FUNDAMENTAL
MUHAMMAD FAKHRUL RADZI BIN JAFFER@JAFFAR
MULTIPLE
29
SUBNET MASK X 11111111 11111111 11111111 11111100
SUBNET ADDRESS 11000000 10101000 00000011 11011000
SUBNET ADDRESS FOR THIS IP ADDRESS
192 168 3 216
192.168.3.216
IP ADDRESS OF FIRST HOST = 192.168.3.217
216+
2 HOSTS
IP ADDRESS OF LAST HOST CALCULATION
= 218IP ADDRESS OF LAST HOST =192.168.3.218
BROADCAST ADDRESS = 192.192.10.255
KFC 2044 NETWORK FUNDAMENTAL
MUHAMMAD FAKHRUL RADZI BIN JAFFER@JAFFAR
ANSWER
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