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1 Devesh agrawal

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Page 1: Phase diagram

1

Devesh agrawal

Page 2: Phase diagram

Chapter 3: The Structure of Crystalline Solids 2

Page 3: Phase diagram

Chapter 3: The Structure of Crystalline Solids 3

A solid solution forms when, as the solute atoms are added to the host materials, the crystal structure is maintained, and no new structures are formed.

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Chapter 3: The Structure of Crystalline Solids 4

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Chapter 3: The Structure of Crystalline Solids 5

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Chapter 3: The Structure of Crystalline Solids 6

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Chapter 3: The Structure of Crystalline Solids 7

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Hume-Rothery (1899-1968) was a metallurgist who studied the alloying of metals. His research was conducted at Oxford University where in 1958, he was appointed to the first chair in metallurgy.

His research led to some simple and useful rules on the extent to which an element might dissolve in a metal . The rules that he derived are paraphrased here. The rules are still used widely. For example, the miscibility gap in Au-Ni is correlated with the fact that the lattice parameter of Au is 1.15 times that of Ni, thus acting maximally according to Hume-Rothery .

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Chapter 3: The Structure of Crystalline Solids 9

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Chapter 3: The Structure of Crystalline Solids 10

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Chapter 3: The Structure of Crystalline Solids 11

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Chapter 3: The Structure of Crystalline Solids 12

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Chapter 3: The Structure of Crystalline Solids 13

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Chapter 3: The Structure of Crystalline Solids 14

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Chapter 09: Phase Diagram 15

Introduction

Phase Diagrams are road maps

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Chapter 09: Phase Diagram 16

Component: Pure metals/compounds of which an alloy is

composed

System: Alloy system, e.g., Iron-Carbon alloy system,

copper-nickel alloy system

Solid solutions

- Substitutional

- Interstitial

Page 17: Phase diagram

Chapter 09: Phase Diagram 17

Solubility Limit: Max concentration of solute atoms that

may dissolve in the solvent to form a solid solution.

-The solubility limit of sugar in water depends on the

temperature of water. At 20degree C, maximum solubility

of sugar in water is 65%.

Phases: Homogenous portion of a system that has uniform

physical and chemical properties.

-Every pure material is considered to be a phase, e.g.

solid, liquid and gas phase

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Chapter 09: Phase Diagram 18

If more than one phase is present in a given system, each will have its own distinct properties and boundary separating the phases will exist across which there will be discontinuous and abrupt change in physical and chemical characteristicsSubstance can exist in two or more polymorphic forms (having FCC and BCC structure) each have separate phase and different properties. Sugar water example, sugar water syrup solution is one phase and solid sugar is another

Page 19: Phase diagram

Chapter 09: Phase Diagram 19

Source: William Callister 7th edition, chapter 09, page 254, figure 9.1

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Chapter 09: Phase Diagram 20

Each phase has different phase physical properties

Microstructure

•Characterized by number of phases, proportions and the

manner of distribution of phases.

•Depends on: Alloying elements, concentrations, heat

treatment (temp, heating/cooling rate etc.)

Page 21: Phase diagram

Chapter 09: Phase Diagram 21

Free energy : It is function of the internal energy of a system

and also the randomness of atoms/molecules

Equilibrium : A system is at equlibrium,if its free energy is

at a minimum under some specified combination of Temp,

Pressure and Composition

Phase equilibrium : Phase is equilibrium if it is constant

with time in the phase characteristics of a systems. It refers,

when more than one phase are present in system.

Isomorphous: Complete solubility in both liquid and solid

states.

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Chapter 09: Phase Diagram 22

Non-equilibrium state/Metastable: State of equilibrium

is never reached since the rate of approach to equilibrium

is very slow. This state may persist indefinitely,

experiencing only slight and almost imperceptible

changes as time progresses

Equilibrium phase diagram

•Represents the relationships between temperature and

compositions, and the quantities of phases in equilibrium

Page 23: Phase diagram

Chapter 3: The

Structure of Crystalline

Solids23

Gibbs Phase Rule

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Chapter 3: The

Structure of Crystalline

Solids24

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Chapter 3: The

Structure of Crystalline

Solids25

Unary Phase Diagram (Pressure-temperature diagram for Water)

The simplest phase diagrams are pressure-temperature diagrams of a single simple substance, such as water. The axes correspond to the pressure and temperature. The phase diagram shows, in pressure-temperature space, the lines of equilibrium or phase boundaries between the three phases of solid, liquid, and gas.

Page 26: Phase diagram

Chapter 3: The

Structure of Crystalline

Solids26

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Chapter 3: The

Structure of Crystalline

Solids27

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Chapter 3: The

Structure of Crystalline

Solids28

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Chapter 09: Phase Diagram 29

Binary Isomorphous Systems

Source: William Callister 7th edition, chapter 09, page 259, figure 9.3 a&b

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Chapter 09: Phase Diagram 30

Three kinds of infomation:

•What Phases are present at particular temp and comp.

•Determination of phase compositions( in term of

concentration of compoents) Using Tie Line or Isotherm.

To determine the composition (in wt% Ni and Cu) for

both the alpha and liquid phase for 35wt%Ni-65 wt%Cu at

1250 C. Composition of liquid phase is 32 wt% Ni and

composition of alpha phase is 43 wt%Ni.

•percentages/fractions of phases (Phase Amount) at

equilibrium.

Page 31: Phase diagram

Chapter 09: Phase Diagram 31

73%0.7332433543W

L

27%0.2732433235W

Where, WL: weight/mass fraction of liquid

At 1250°C and Co=35% Ni

Page 32: Phase diagram

Chapter 09: Phase Diagram 32

Lever Rule (Inverse lever rule)

1.Draw tie-line across the two phase region

2.Locate the overall composition (e.g., Co=35%Ni)

3.To compute the fraction of one phase, take the length of

the tie-line from the overall composition to the opposite

phase boundary and divide by the total tie line length

4.Repeat above procedure for the other phase.

Page 33: Phase diagram

Chapter 09: Phase Diagram 33

•When two phases are present,Sum of their mass fractions must be Equal to unity.---- (1)

•Mass of one of the component (CuOr Ni) that is present in both phasesMust be equal to the mass of that Component in the total alloy- (2)

Where, Cs and C both are same

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Chapter 09: Phase Diagram 34

Lever Rule

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Chapter 09: Phase Diagram 35

Development of microstructures

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Chapter 09: Phase Diagram 36

Development of microstructures(Non Equilibrium Cooling)(

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Chapter 09: Phase Diagram 37

Development of Microstructures

The compositions readjust with changes in temperature.

These changes occur through the process of diffusion.

Because diffusion is time-dependent, much more time is

required, at each temperature for compositional

adjustments. Diffusion rates decrease with temperature. In

reality, cooling rates are so fast that there is little time to

enable equilibrium cooling. Diffusion rate in liquid is

faster than solid

Page 38: Phase diagram

Chapter 09: Phase Diagram 38

•Because of fast cooling, there is a

non-uniform distribution of the two

elements for isomorphous alloys

“Segregation”

In the centre of each grain, the high

melting element solidifies first. At the

periphery, the low melting element

solidifies.

Non-Equilibrium Solidification

Page 39: Phase diagram

Chapter 09: Phase Diagram 39

Coring

Cored Structure: Concentration contours

•Undesirable less than optimal properties due to

inhomogeneity.

•Coring is eliminated by a homogenization Heat

treatment. At a temperature below the solidus point for the

composition; atomic diffusion causes homogenization.

Page 40: Phase diagram

Chapter 09: Phase Diagram 40

Mechanical Properties of Isomorphous Alloys

Source: William Callister 7th edition, chapter 09, page 268, figure 9.6

Page 41: Phase diagram

Chapter 09: Phase Diagram 41

•Solid solution hardening or an increase in strength and

hardness by the addition of the other component

•At an intermediate composition, the curve (TS Vs Comp)

passes through a maximum

Mechanical Properties of Isomorphous Alloys

Page 42: Phase diagram

Chapter 09: Phase Diagram 42

Binary eutectic systems

Page 43: Phase diagram

Chapter 09: Phase Diagram 43

Binary eutectic systems Continue …..

:Solid Solution of Ag in Cu-Rich solvent

:Solid solution of Cu in Ag-Rich solvent

Technically, : Pure Cu

: Pure Ag

Below BEG, only limited solid solubility takes place

Page 44: Phase diagram

Chapter 09: Phase Diagram 44

CEA: (solid) solubility limit for Ag in – phase (Cu-Rich)

HGF: Solubility limit for Cu in -phase (Ag-Rich)

CBA is between /(+) and /(+L) phase regions

•Max. at 7.9% Ag (780°C)

Binary eutectic systems Continue …..

•Decrease to zero at 1085°C (Melting point of pure Cu)

Page 45: Phase diagram

Chapter 09: Phase Diagram 45

For –phase CB: solvus line: /(+)

AB: Solidus line: /(+L)

General Rule: Single phase regions are always separated

from each other by a two phase region that consists of two

single phases that it separtes.

Binary eutectic systems Continue …..

Page 46: Phase diagram

Chapter 09: Phase Diagram 46

Prepare similar notes for -phase region

HGF is between

For -phase

HG: Solvus line and GF: Solidus line

Binary eutectic systems Continue …..

Page 47: Phase diagram

Chapter 09: Phase Diagram 47

Three two-phase regions: +L, +L and +

E: Eutectic invariant point

CE: 71.9 wt% Ag

Cu-Ag system: TE: 780°C

Binary eutectic systems Continue …..

Page 48: Phase diagram

Chapter 09: Phase Diagram 48

Binary Eutectic systems Continue …..

Eutectic Reaction:

Liquid Solid 1 + Solid 2

L +

L(CE) (C E) + (C E)

At E,

Page 49: Phase diagram

Chapter 09: Phase Diagram 49

Binary Eutectic systems Continue …..

For Cu-Ag system,

L(71.9 wt% Ag) (7.9 wt% Ag) + (91.2 wt% Ag)

Page 50: Phase diagram

Chapter 09: Phase Diagram 50

Binary Eutectic systems Continue …..

Solidus line at 780°C: Eutectic isotherm

Phase volume fractions represent proportions seen in the

microstructure; so they can be estimated from

microstructures, and the mechanical properties can be

estimated as well.

Page 51: Phase diagram

Chapter 09: Phase Diagram 51

Source: William Callister 7th edition, chapter 09, page 271, figure 9.8

Binary Eutectic systems Continue …..

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Chapter 09: Phase Diagram 52

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Chapter 09: Phase Diagram 53

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Chapter 09: Phase Diagram 54

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Chapter 09: Phase Diagram 55

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Chapter 09: Phase Diagram 56

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Chapter 09: Phase Diagram 57

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Chapter 09: Phase Diagram 58

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Chapter 09: Phase Diagram 59

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Chapter 09: Phase Diagram 60

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Chapter 09: Phase Diagram 61

Page 62: Phase diagram

62

Temperature Dependence of Transformation Rate

For the recrystallization of Cu, since

rate = 1/t0.5

rate increases with increasing temperature

• Rate often so slow that attainment of equilibrium state not possible!

Adapted from Fig. 11.11, Callister & Rethwisch 3e.(Fig. 11.11 adapted from B.F. Decker and D. Harker, "Recrystallization in Rolled Copper", Trans AIME, 188, 1950, p. 888.)

135C 119C 113C 102C 88C 43C

1 10 102 104

Page 63: Phase diagram

63

Transformations & Undercooling

• For transf. to occur, must cool to below 727°C (i.e., must “undercool”)

• Eutectoid transf. (Fe-Fe3C system): + Fe3C0.76 wt% C

0.022 wt% C6.7 wt% C

Fe 3

C (

cem

entit

e)

1600

1400

1200

1000

800

600

4000 1 2 3 4 5 6 6.7

L

(austenite)

+L

+Fe3C

+Fe3C

L+Fe3C

(Fe) C, wt%C

1148°C

T(°C)

ferrite

727°C

Eutectoid:Equil. Cooling: Ttransf. = 727ºC

T

Undercooling by Ttransf. < 727C

0.7

6

0.0

22

Adapted from Fig. 10.28,Callister & Rethwisch 3e. (Fig. 10.28 adapted from Binary Alloy Phase Diagrams, 2nd ed., Vol. 1, T.B. Massalski (Ed.-in-Chief), ASM International, Materials Park, OH, 1990.)

Page 64: Phase diagram

64

The Fe-Fe3C Eutectoid Transformation

Coarse pearlite formed at higher temperatures – relatively soft

Fine pearlite formed at lower temperatures – relatively hard

• Transformation of austenite to pearlite:

Adapted from Fig. 10.15, Callister & Rethwisch 3e.

pearlite growth direction

Austenite ()grain boundary

cementite (Fe3C)

Ferrite ()

• For this transformation, rate increases with [Teutectoid – T ] (i.e., T).

Adapted from Fig. 11.12, Callister & Rethwisch 3e.

675°C (T smaller)

0

50

y (%

pea

rlite

)600°C

(T larger)650°C

100

Diffusion of C during transformation

Carbon diffusion

Page 65: Phase diagram

65

Adapted from Fig. 11.13,Callister & Rethwisch 3e. (Fig. 11.13 adapted from H. Boyer (Ed.) Atlas of Isothermal Transformation and Cooling Transformation Diagrams, American Society for Metals, 1977, p. 369.)

Generation of Isothermal Transformation Diagrams

• The Fe-Fe3C system, for Co = 0.76 wt% C• A transformation temperature of 675°C.

100

50

01 102 104

T = 675°C

y,

% tr

ansf

orm

ed

time (s)

400

500

600

700

1 10 102 103 104 105

0%pearlite

100%

50%

Austenite (stable) TE (727C)Austenite (unstable)

Pearlite

T(°C)

time (s)

isothermal transformation at 675°C

Consider:

Page 66: Phase diagram

66

• Eutectoid composition, C0 = 0.76 wt% C• Begin at T > 727°C• Rapidly cool to 625°C• Hold T (625°C) constant (isothermal treatment)

Adapted from Fig. 11.14,Callister & Rethwisch 3e. (Fig. 11.14 adapted from H. Boyer (Ed.) Atlas of Isothermal Transformation and Cooling Transformation Diagrams, American Society for Metals, 1997, p. 28.)

Austenite-to-Pearlite Isothermal Transformation

400

500

600

700

0%pearlite

100%

50%

Austenite (stable)TE (727C)

Austenite (unstable)

Pearlite

T(°C)

1 10 102 103 104 105

time (s)

Page 67: Phase diagram

67

10 103 105

time (s)10-1

400

600

800

T(°C)Austenite (stable)

200

P

B

TE

0%

100%

50%

A

A

Bainite: Another Fe-Fe3C Transformation Product • Bainite: -- elongated Fe3C particles in -ferrite matrix -- diffusion controlled • Isothermal Transf. Diagram,

C0 = 0.76 wt% C

Adapted from Fig. 11.18, Callister & Rethwisch 3e.

Adapted from Fig. 11.17, Callister & Rethwisch 3e. (Fig. 11.17 from Metals Handbook, 8th ed., Vol. 8, Metallography, Structures, and Phase Diagrams, American Society for Metals, Materials Park, OH, 1973.)

Fe3C(cementite)

5 m

(ferrite)

100% bainite

100% pearlite

Page 68: Phase diagram

68

• Spheroidite: -- Fe3C particles within an -ferrite matrix -- formation requires diffusion -- heat bainite or pearlite at temperature

just below eutectoid for long times -- driving force – reduction

of -ferrite/Fe3C interfacial area

Spheroidite: Another Microstructure for the Fe-

Fe3C System

Adapted from Fig. 11.19, Callister & Rethwisch 3e. (Fig. 11.19 copyright United States Steel Corporation, 1971.)

60 m

(ferrite)

(cementite)

Fe3C

Page 69: Phase diagram

69

• Martensite: -- (FCC) to Martensite (BCT)

Adapted from Fig. 11.22, Callister & Rethwisch 3e. (Fig. 11.22 courtesy United States Steel Corporation.)

Adapted from Fig. 11.21, Callister & Rethwisch 3e.

Martensite: A Nonequilibrium Transformation Product

Martensite needlesAustenite

60

m

xx x

xx

xpotential C atom sites

Fe atom sites

Adapted from Fig. 11.23, Callister & Rethwisch 3e.

• Isothermal Transf. Diagram

• to martensite (M) transformation.. -- is rapid! (diffusionless) -- % transf. depends only on T to

which rapidly cooled

10 103 105 time (s)10-1

400

600

800

T(°C)Austenite (stable)

200

P

B

TE

0%

100%50%

A

A

M + AM + A

M + A

0%50%90%

Page 70: Phase diagram

70

(FCC) (BCC) + Fe3C

Martensite Formationslow cooling

tempering

quench

M (BCT)

Martensite (M) – single phase

– has body centered tetragonal (BCT) crystal structure

Diffusionless transformation BCT if C0 > 0.15 wt% C

BCT few slip planes hard, brittle

Austenite Ferrite + Cementite = Pearlite

Tempered Martensite

Page 71: Phase diagram

71

Phase Transformations of AlloysEffect of adding other

elementsChange transition temp.

Cr, Ni, Mo, Si, Mn

retard + Fe3C

reaction (and formation of

pearlite, bainite)

Adapted from Fig. 11.24, Callister & Rethwisch 3e.

Page 72: Phase diagram

Chapter 09: Phase Diagram 72

Page 73: Phase diagram

Chapter 09: Phase Diagram 73

Problem:

For Pb-Sn system at 150°C, calculate relative amounts of

each phase by (a) Mass fraction (b) Volume fraction

0.6711994099

CC

CCW

n(a)Solutio

gm/cm 7.3:ρgm/cm 11.2:ρ

:Given

αβ

1βα

Page 74: Phase diagram

Chapter 09: Phase Diagram 74

Problem: Continue ….

33

33

αβ

α1β

cm 4.52gm/cm 7.3

gm 33)(

v

cm 5.98gm/cm 11.2

gm 67)(

v

Fraction Volume (b) Solution

0.3311991140

CC

CCW

1-0.67=0.33

Page 75: Phase diagram

Chapter 09: Phase Diagram 75

0.434.525.98

4.52vv

vV

0.574.525.98

5.98vv

vV

Fraction Volume

βα

ββ

βα

αα

Problem: Continue ….

Vα is volume fraction of the alpha phase, Vα and Vβ denote the volumes of the respective phases in the alloy.