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Our project on Biodiesel production optimization from Mahua Oil
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Optimization of Biodiesel preparation by enzymatic transesterification using Mahua oil and
study on utilization of glycerol into Bioethanolby
S. Mozhiarasu1* & B.Aswin Kumar*
*Madha Engineering College1Research Associate, Bio Globe
Scientific Park
To study about different trans-esterification
methods To optimize the reaction conditions for
enzymatic method To study ethanol production using waste
glycerol
OBJECTIVE
Biodiesel consists of Fatty acid alkyl esters It can be produced by transesterification of
Triglycerides and alcohol in the presence of catalyst.
Introduction
Major Methods of Transesterification
Alkali mediated Method
Acid mediated method
Enzymatic Method
1. Mahua oil
o Next to sugarcane, Mahua flowers or fruit pulp are the most important source of raw materials for fermentation and production of alcohol and vinegar.
o Mahua oil seed cake can be used as manure and as substrate for Lipase production
o Seeds containing 20 to 50% fatty oil
Low Cost Feed Stock
Take 1 ml of the reaction mixture at each interval and
10 ml of neutralized Iso propyl alcohol is added
2-3 drops of phenolphthalein solution is added
Then titrated against 0.1N NaOH solution
Appearance of Pale pink color is the end point
Lipase AssayHydrolysis Activity :µmole oleic acid /ml subsample =
([(ml NaOH for sample − ml NaOH for blank) × N × 1000]/quantity of sample)
/282.5
One unit (IU) of lipase (hydrolysis) was defined as the amount of enzyme
releasing one μmol fatty acid equivalent per minute under the assay
conditions.Esterification Activity:
µmole oleic acid /ml subsample = ([(ml NaOH for blank− ml NaOH for
sample) × N × 1000]/quantity of sample) /282.5
One unit (IU) of lipase( esterfication) was defined as the amount of enzyme
consumed one μmol fatty acid equivalent per minute under the
assay conditions.
Take 50 ml conical flask, in which add 5 g of
Mahua Oil and add 40 ml of water Then the reaction started by adding 5ml of
phosphate buffer(pH 8.0) containing enzyme of concentration (0.6 mg/ml)
The reaction mixture is kept at 100 RPM in a rotary shaker
Then for every 5 minutes the reacting mixture is assayed titer metrically.
Hydrolase activity
Esterase Activity
Take 50 ml of flat bottomed flask with stopper, in which add (1:1 mol/mol) of Methanol:lauric acid,i.e., (1g of MeOH : 9.32g of Lauric acid). Then add 35 ml of Hexane.
Then heated at 43oC at 200 RPM until the fatty acid gets melted down.
Then the reaction started by adding 5ml of phosphate buffer containing enzyme of concentration (0.6 mg/ml)
Then for every 20 minutes the reacting mixture is assayed titer metrically.
HYDROLASE ACTIVITY
ESTERASE ACTIVITY
Factors influencing production of biodiesel
Temperature pH
Stirring MeOH :Oil Buffer/Water concentration Enzyme concentration Stepwise addtion
1g oil+ 0.5N NaOH at 60oC for
30 minutes
Neutralized with 2mL of 0.5 N HCl
then 5mL of Diethyl ether was
added
Bottom layer diluted two fold
with ethanol water
CONVERSION ASSAYEstimation of glycerides present in the form of unconverted oil in the prepared ester. Total glycerides in the oil and unconverted was done in terms of glycerol.Modified method described in P.K.Gupta et. al 2007
1ml of sample + 1.2 ml 10mM sodium periodate prepared with 10 ml equal volume of 4 M ammonium acetate and 1.6 M acetic acid
, Shaken for 30 seconds
Then add 1.2 ml of 0.2 M Acetyl acetone solution prepared with prepared with 10 ml equal volume of 4 M ammonium acetate and
1.6 M acetic acid and heated at 70oC for minute
Then OD was measured at 410 nm
Glycerol Assay
As described in bondiolliet.al
Glycerol equivalent converted = Total glycerol present in oil –(Total glycerol present in saponified biodiesel sample – Glycerol present in biodiesel sample (before saponified)
Theoretical biodiesel yield (T) = 3 x Moles of glycerol present in oil
Actual biodiesel (A) = 3 x Moles of Glycerol equivalent converted – moles of FFA present in the diluted sample.
%Yield = (A / T) x 100
Yield %
Enzymatic Transesterification
Reaction mixture: Reaction mixture consist of Oil-MeOH ratio : 50 g : 6.4 g ( 1:1
mol/mol)Enzyme : 0.5% (w/w) mixed with 5 ml
of phosphate bufferReaction Time: 7 hrsRPM : 100 RPM in Rotary
Shaker
Effect Of Temperature
Effect Of pH of Buffer
Variable analysed by Taguchi method
Factor Level 1 Level 2 Level 3 Level 4
Oil : MeOH(mol:mol) 1:1 1:1.5 1:2 1:2.5
Buffer(w/w) 5% 10% 15% 20%
Enzyme
Concentration(w/w)
0.25% 0.5% 0.75% 1%
Mixing rate (RPM) 25 50 75 100
Stepwise
addition(mol/hr)
0.5 0.625 0.75 0.875
Taguchi L16 ArrayRun no Oil: MeOH Buffer Enzyme RPM Stepwise addition
1 1 1 1 1 1
2 1 2 2 2 2
3 1 3 3 3 3
4 1 4 4 4 4
5 2 1 2 3 4
6 2 2 1 4 3
7 2 3 4 1 2
8 2 4 3 2 1
9 3 1 3 4 2
10 3 2 4 3 1
11 3 3 1 2 4
12 3 4 2 1 3
13 4 1 4 2 3
14 4 2 3 1 4
15 4 3 2 4 1
16 4 4 1 3 2
Nominal is Best approach:
S/Nt = -10 log (yi2/ Si
2)y = Performance measure. i = Experiment number Si = Standard deviation for experiment.
∆= Maximum-Minimum
Optimum S/N ratio = Average S/N + ∑ (Factor effects of all factors).
S/N Ratio
Run No Factors Yield % S/N Ratio
Oil:MeOH Buffer % Enzyme % RPM Stepwise
addition
1. 1:1 5 0.25 25 0.5 18.88 23.4150
2. 1:1 10 0.5 50 0.625 34.88 26.3702
3. 1:1 15 0.75 75 0.75 73.95 34.3278
4. 1:1 20 1 100 0.875 70.62 34.5848
5. 1:1.5 5 0.5 75 0.875 27.72 27.3281
6. 1:1.5 10 0.25 100 0.75 86.80 38.0741
7. 1:1.5 15 1 25 0.625 37.60 29.8802
8. 1:1.5 20 0.75 50 0.5 61.48 34.3221
9. 1:2 5 0.75 100 0.625 29.65 25.7016
10. 1:2 10 1 75 0.5 71.28 35.0764
11. 1:2 15 0.25 50 0.875 66.05 35.4496
12. 1:2 20 0.5 25 0.75 16.38 24.9106
13. 1:2.5 5 1 50 0.75 24.63 28.5860
14. 1:2.5 10 0.75 25 0.875 11.27 20.8652
15. 1:2.5 15 0.5 100 0.5 44.03 30.4517
16. 1:2.5 20 0.25 75 0.625 69.30 34.6736
EXPERIMENTAL RESULTS
4321
32
30
28
26
244321 4321
4321
32
30
28
26
244321
Oil: MeOHM
ean o
f SN r
atios
Buffer Amount Enzyme Amount
Mixing Rate Stepwise addition Rate of MeOH
Signal-to-noise: Nominal is best (10*Log10(Ybar**2/s**2))
4321
60
50
40
30
20
4321 4321
4321
60
50
40
30
20
4321
Oil: MeOH
Mean o
f M
eans
Buffer Amount Enzyme Amount
Mixing Rate Stepwise addition Rate of MeOH
Level Oil: MeOH Buffer Conc.Enzyme
Conc.RPM
Stepwise addition rate of
MeOH
1 29.67 26.26 32.90 24.77 30.82
2 32.40 30.10 27.27 31.18 29.16
3 30.28 32.53 28.80 32.85 31.47
4 28.64 32.12 32.03 32.20 29.56
Delta 3.76 6.27 5.64 8.08 2.32
Rank 4 2 3 1 5
Response Table for S/N Ratios
Source DF SS MS F P
Oil: MeOH 3 584 195 0.28 0.840
Buffer Conc. 3 2470 823 1.52 0.260
Enzyme Conc. 3 1918 639 1.09 0.392
RPM 3 3846 1282 3.00 0.073
Stepwise addition rate of
MeOH3 163 54 0.07 0.973
Total 15 8981
ANOVA table for all the factors
OPTIMIZED VALUE
Temperature (oC) ` - 35pH of Buffer - 7.0Oil:MeOH (mol:mol) - 1:1.5Buffer amount (w/w) - 15%Enzyme amount (w/w) - 0.25%Mixing Rate (RPM) - 100Stepwise addition (mol/h) - 0.5
optimum values were tested and yield% were calculated and it was found that 89.32 ± 2.4% yield was obtained after 7 hrs of reaction time
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