B TI NGUYN V MI TRNG TRNG I HC TI NGUYN V MI TRNG H NI
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B TI NGUYN V MI TRNGTRNG I HC TI NGUYN V MI TRNG H
NI*****************************
BO CO BI TP LNK THUT HA Ti: Cc Php Bin i Tnh Tin Trong Khng Gian
Hai ChiuLp: C12CNTH v Tn: Nguyn nh HiM SV: CD01200731
Li Cm nTrn thc t khng c s thnh cng no m khng gn lin vi nhng s h
tr, s gip d t hay nhiu, d l trc tip hay gin tip ca ngi khc. Trong
sut thi gian t khi bt u hc tp ging ng i Hc n nay, chng em nhn c rt
nhiu s quan tm, gip ca Thy C, gia nh v bn b.Vi lng bit n su sc nht,
chng em xin gi n Thy C Khoa Cng Ngh Thng Tin Trng i Hc Ti Nguyn v
Mi Trng H Ni cng vi tri thc v tm huyt ca mnh truyn t vn kin thc qu
bu cho chng em trong sut thi gian hc tp ti trng. V c bit, trong k
ny, Khoa t chc cho chng em c tip cn vi mn hc rt hu ch i vi sinh vin
ngnh Cng Ngh Thng Tin. l mn: K Thut Ha.Em xin chn thnh cm n c Ph Th
Hi Yn tn tm hng dn chng em qua tng bui hc trn lp cng nh nhng bui ni
chuyn, tho lun v mn hc. Trong thi gian c hc tp v thc hnh di s hng
dn ca c, chng em khng nhng thu c rt nhiu kin thc b ch, m cn c truyn
s say m v thch th i vi b mn K Thut HaMc d rt c gng hon thin bi tp
vi tt c s n lc, tuy nhin, do tm hiu v xy dng bi tp trong thi gian c
hn, v kin thc cn hn ch, nhiu b ng, nn bi tp ln ny chc chn s khng th
trnh khi nhng thiu st. Em rt mong nhn c s quan tm, thng cm v nhng
ng gp qu bu ca cc thy c v cc bn bi tp ny ngy cng hon thin hn.Sau
cng, Em xin knh chc cc thy c trong Khoa Cng Ngh Thng Tin v c Ph Th
Hi Yn di do sc khe, nim tin tip tc thc hin s mnh cao p ca mnh l
truyn t kin thc cho th h mai sau!!!
3Cc i tng phng trong ho 2 chiu m t tp cc im phng. im trong ho 2
chiu biu din thng qua to , vit di dng ma trn gi l vect v tr.C 2 dng
biu din:Mt hng v 2 ct:
Hai hng v 1 ct:
Gi s ta c im P = [ x y ] trong mt phng vi [x y] l vect v tr ca
P, k hiu l [P]. Gi ma trn T l ma trn bin i s c dng:
y P P
Hnh 1. Php bin i v tr x
i xng qua y P Pyi xng qua x yxPi xng qua trc ta PPyxP
C P khng thay i gi tr to x, cn y thay i ph thuc vo c b v xXt b =
0
Ch : im gc to P[0 0] bt bin vi mi php bin i
Php bin dng theo trc yP
P y=bx+ybxPhp bin dng theo trc xP Pcy
C >0 ngc chiu kim ng h
Php quay trn 2D y
y
y P
P x x x xPhng php bin i s dng php nhn ma trn vi to im thng qua
cc vect v tr tht s hiu qu v em li cng c mnh v ho cho ngi s dng.
Nhng thc t cc thao tc thng cn khng ch mt m nhiu php bin i khc nhau.
Ta c php hon v khi nhn ma trn l khng thc hin nhng kh nng t hp cc
php nhn li cho php to ra mt ma trn bin i duy nht. Lm gim bt ng k
khi lng tnh ton trong qu trnh bin i, lm tng tc cc chng trnh ng dng
v to iu kin cho vic qun l cc bin i trong ng dng
Gi s ta c P vi [X] = [x y], c hai php bin i [T1] quay quanh gc
to 90
V [T2] ly i xng P qua gc to :Ta c:
2.6 Php bin i tng hp
Gi s [T3] l ma trn tng hp [T1] v [T2]
T =Ta c im P sau php bin i thnh P c gi tr Thc thi php bin i ng
trn 1 im nh s ng vi ton b i tng.[X]*[T] = [x y]*=Hay ta c: x = ax +
cy y = bx + dy Khi : a = d =1 v b = c = 0 v ma trn cho php bt bin
l:T=*Vy x=x v y = y hay l P = P chng t bt bin qua php bin i. Nu d=1
v b = c = 0 th ma trn bin i l T= x=xa y=y*P dch chuyn theo trc x vi
t l a xc nh.Nu b = c =0 th ma trn bin i l: T=*Hay tng qut hn gi Sx,
Sy ln lt l t l theo trc x v trc y, th ma trn t l s l:T=Khi Sx , Sy
>1 gi l php phng to Khi Sx, Sy
