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Seminarski rad
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7/16/2019 Vuca i Sinski Saobracajni Sistemi-primer-Ana Maria-1
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1. , , Rmin (m)
1.1.
,
.
( ) 1000 m.
.
:
[]l
)0H1H(1000ki
=
H1 H0
l
6. 7. 52
:
6. 52 ( )
.
-
daN/t
5 5 5
I I 5
I I 3
5 5 5
6. 7.
52
: iu = 5 5 daN/t.
6. 7.
52
: ip = 5
1.2. Rmin (m)
4.1.
Rmin (m) :
1
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Rmin (m)
. 700
2500 3000
300
1600
. 1600
600
.
2000
Rmin = 300 m - .
1.3. im [daN/t]
,
, .
1.1. 6. 52
; ; - .
: im= 5 [daN/t]
2. ( )
.
.
:
( ) .
:
W () ;
Wd
Wpov .
2.1. () W
:
2
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;
.
1435 [mm]
2.1.1. W
:
[ ]daN0343355,007848,0102 2vvWOL ++=
[ ]daN191,76500343355,05007848,0102 2 =++=OL
W
)daN(lmolwolW = :
[ ]tdaNwol
/60,1120
76,191
m
W
l
ol ===
:
Wol [daN/t]
ml 461. 52
10. (
, ), I 1 (
) : ml= 120 tv [km/h]
2.1.2. Wok
:
)(daNQwW OKOK =
:
w ( ) [ ]daN/t
2
10
v
007,0k38v
80
2,2okw
+++=
( ) [ ]daN/t2,2710
50007,0032,0
3850
802,2
2
=
++
+=
okw
k ( ) , 8.
9. 52, k= 0.032.
v [m/h]
Q praztov QQQ +=
52 11., III (
)
3
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tovqtovntovQ =
tovq
tovn
20 x as + 5 x :
Q = q = (22,0 + 58,5) 20+ (11,5 + 29,0) 5= 1812,5 t
prazprazprazqnQ =
prazq
prazn .
.
2.1.3.
Q = Qtov + Qpraz= 1812,5 + 0 = 1812,5 t
v[km/h]
10 20 30 40 50
wol[daN/t]
0,89 0,98 1,13 1,33 1,60
Wol[daN]
106,22 117,30 135,26 160,08 191,76
wok
[daN/t]0,57 0,98 1,37 1,80 2,27
Wok[daN]
1037,35 1770,25 2491,33 3259,53 4106,96
Q[t] 1812,5
ml[t] 120
Wo[daN]
1143,57 1887,55 2626,59 3419,60 4298,72
Q = 1812.5 [t]. :
[ ]daNokWolWWO +=
[ ]daN3,489157,461573,275oW =+=
2.2.
,
:
Wi
Wr
Wt
, .
4
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2.2.1. Wi
:
giQmW uli += )(
: ml- 461, ml = 120 t 2.1.1.
Q , Q = 1812,5 t a 2.1.2.
iu , 1.1.
iu = 5 (1 = 1 daN/t) iu = 5 [daN/t ]
g ,g= 9,81 m/s2
Wi= (ml+ Q ) iu g= (120 + 1812,5) 5 9,81 = 97789,13 N = 9778,91 [daN ]
.
5
9779 [daN].
2.2.2. WR
:
[ ]daN/t55
650
=R
wR
R , 1.2,R = 300 m
65,255300
650=
=Rw [daN / t ]
:
WR = (ml + Q) wR = (120 + 1812,5 ) 2,65 = 5137,06 [daN]
2.2.3.
() . :
( )daNv
k
LW t
t
2
1015
=
2.2.4.
:
Wp = Wi + WR + Wt= 9779 + 5137,06 + 0= 14916,06 [daN]
5
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:
Wm = im ( ml+ Q ) = 5 ( 120 + 1812,5) =9662,5 [daN]
im , im = 5 daN/t 1.3.
,
, .
.
, , .
3.
. ,
.
,
. .
F o Fa (
).
:
[ ]Nglm310aF a
=
ml 461, ml= 120 t 2.1.1.
g , g= 9,81 m/s2
() :
:
v3413
9509,0
a ++=
:
R10,1500
R55,1250
aar ++
=
:
6
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2
1000
ui1aai
=
3.1.
v [km/h] 0 10 20 30 40 50
a 0,32 0,30 0,29 0,28 0,27 0,26
Fa[kN] 376,73 358,39 342,38 328,28 315,77 304,59
ar 0,28 0,26 0,25 0,24 0,23 0,22
Far [kN] 324,53 308,74 294,94 282,80 272,02 262,39
ai 0,32 0,30 0,29 0,28 0,27 0,26
Fai[kN] 376,71 358,37 342,36 328,26 315,75 304,57
ml [t] 120
4.
Fo ,
, (Fo
).
Fo
:
4.1. Fo Fa ( )
Fo W
lolmokmomlo mwiQwiWimQWF +++=++= )()()(
4.2. Pi
461 52,
10. I 1 Pi = 5100kW.
4.3. Po
Po :
Po = 0.8 Pi = 0.8 5100 = 4080 [kW]
4.4. Fo
Fo :
[ ]kNv
P
F
o
o 76,29350
4080
6,36,3===
Po = 4080 [kW], , 4.3.
7
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3,6 .
v = 50 [km/h], .
4.5. Fo Fa
Fa = 304,59 [kN], , 3.1.
Fo = 293,76 [kN], 50
km/h, 4.4.
Fo Fa
( Fa
Fo) .
4.6. W
:
W = (Q + ml) im + Wo = (1812,5 + 120) 5 + 4298,72 = 13961,22 [daN] = 139,61 [kN]
ml 461, ml=120 t 2.1.1.
Q , Q = 1812,5 t 2.1.2.
im , im = 5 daN/t 1.3.
Wo = 4298,72 [daN], , 2.1.3.
4.7. Fo > W
W= 13961,22 [daN] = 139,61 [kN], , 4.6.
Fo = 293,76 [kN], 50
km/h, 4.4.
Fo >W
(
) . 461 .
4.8. R Z
Z
, :
Z = Fva = Fo max,
:
8
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Fo W > 0.
5.
:
[ ]kWvFo
oP4080
6,3
5076,293
6,3=
=
=
v = 70 [km/h], .
Fo = 293,76 [kN], 50
km/h, 4.4.
6.
6.1. Fvk
Fvk :
Fvk= Fo - Wol= 293,76 1,91 = 291,85 kN
Wol , Wol = 191,76 [daN] = 1,91 [kN],
2.1.3.
Fo = 293,76 [kN], 50
km/h, 4.4.
6.2. Z
Z :
Z = Fo W [kN]
50 km/h, Q= 1812 t,
10.
W = Q im + Wo = 1812,5 5 + 4298,72 = 13361,22 daN = 133,61 kN
.
Fo = 293,76 [kN], 50
km/h, 4.4.
Z = Fo - W= 293,76 133,22 = 160,54 [kN]
7.
9
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:
Ameh = Fo l 10 = 293,76 98,500 10 = 28935360 Nm = 289353,60 daNm
l= 98,5km, l , 4.1
Fo = 293,76 [kN], 50
km/h, 4.4.
8.
:
( ) ( )[ ]2/54,05
05,289759
54,160
1102sm
Qml
WFoa ==
++
=
, = 0.47.
Fo = 293,76 [kN], 50
km/h, 4.4.
W= 133,22 [kN], .
ml 461, ml= 120 (t) 2.1.1.
Q Q = 1812,5 (t)
2.1.2.
9.
. :
( ) ( ) [ ] [ ]kNm81,2852280Nm93,2852280816,3
10
2
704,102647,01
6,3
10
2
vQ1 2
32
2
32
maxEk ==+=+=
- , = 0.47.
Q 1812,4 (t), 2.1.2.
v , v = 50 [km/h].
:
Fk= Q ip - Wo = 1812,5 5 4298,72 = 4763,78 [daN] = 47,63 [kN]
ip , ip = 5 = 5[daN], 1.1.
10
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Wo 50 km/h, Wo = 4763,78 [daN],
2.1.3.
Q 1812,5 t,. 2.1.2.
9.1. Bk
Bk :
Bk = ik Q = 10kpkgQ= 10 0,109 72 0,7 9,81 1812,5 = 9767796,41 [N] = 976,77 [kN]
, = 0,109.
pk , = 72%
, = 0,7
Q 1812,5 t,. 2.1.2.
10.
, .
:
( ) ( )tmiokw
lmmiolwoFmaxQ
+
+=
Fo = 293,76 [kN], 50
km/h, 4.4.
ml 461, ml= 120 2.1.1.
im , im= 5 daN/t 1.3.
wol = 1,60 [daN/t], 461
v = 50 km/h.wok= 2,27 [daN/t], v = 50 km/h.
( ) ( )t
iw
miwFQ
mok
lmolo 41,102637,18
2,18855
1537,3
120152,29-209,3
max==
+
+=
+
+=
7 52
461 () 1900 [t] 100 [km/h].
7 52
im = 5 [daN/t] ; . ; , (50 km/h), 2990 [t].
11
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7 52 461
im= 5 [daN/t], ,
.
461 850 [kN]
. 3000[t].
12
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11.
Fo = f (V)
(Fo)
0
100
200
300
400
500
0 10 20 30 40 50 60 70 80
v (km/h)
Fo(kN)
[ ]kNv
Po6.3Fo =
V [km/h] 0 10 20 30 40 50 60 70
Fo [kN] 418,04 209,02 139,35 104,51 83,61 69,67 59,72
Fa = f (V)
(Fa)
0
100
200
300
400
0 10 20 30 40 50 60 70 80
v (km/h)
Fa(
kN)
[ ]kNgml10Fa a3 =
v [km/h] 0 10 20 30 40 50 60 70
Fa[kN] 376,73 358,39 342,38 328,28 315,77 304,59 294,54 285,46
Wol = f (V)
13
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(Wol)
0
50
100
150
200
250
300
0 10 20 30 40 50 60 70 80
v (km/h)
Wol(daN)
[ ]daNv0343355.0v07848.0102Wol 2++=
V [km/h] 0 10 20 30 40 50 60 70
Wol [daN] 102 106.218
117.30
3
135.25
6
160.07
6
191.76
2
230.31
6
275.737
Wok = f (V)
(Wok)
0
500
1000
1500
2000
2500
3000
3500
0 10 20 30 40 50 60 70 80
v (km/h)
Wok(daN)
[ ]daNQwW OKOK = ( ) [ ]daN/t10
v007,0k
38v
802,2w
2
OK
+++
=
V [km/h] 10 20 30 40 50 60 70
Wok [daN] 413.721 745.668 1108.107 1523.907 1981.287 2555.784 3184.335
14
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Wo = f (V)
(Wo)
0
1000
2000
3000
4000
0 10 20 30 40 50 60 70 80
v (km/h)
Wo(daN)
[ ]daNWolWokWo +=
V [km/h] 10 20 30 40 50 60 70
Wo [daN] 749,626
1281,51
4
1861,49
42527,56
3300,32
5
4192,75
55208,172
(Wol)
(Wok)
(Wo)
0
1000
2000
3000
4000
0 20 40 60 80
v (km/h)
Wol;Wok;Wo
(daN)
15
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1. 52
, 1991
2. 4.1 2011/2012
3. -
4. . " " 2012.
5. . " " 2012.
16