40
Stoichiometry Calculations with Chemical Formulas and Equations Chapter 3 BLB 12 th

Stoichiometry Calculations with Chemical Formulas and Equations

  • Upload
    oliana

  • View
    193

  • Download
    1

Embed Size (px)

DESCRIPTION

Stoichiometry Calculations with Chemical Formulas and Equations. Chapter 3 BLB 12 th. Expectations. Balance chemical equations. g ↔ moles ↔ molecules ↔ atoms Find empirical and molecular problems. Calculate amounts of reactants and products. Calculate theoretical and percent yield. - PowerPoint PPT Presentation

Citation preview

Page 1: Stoichiometry Calculations with Chemical Formulas and Equations

StoichiometryCalculations with Chemical Formulas and

EquationsChapter 3 BLB 12th

Page 2: Stoichiometry Calculations with Chemical Formulas and Equations

Expectations Balance chemical equations. g ↔ moles ↔ molecules ↔ atoms Find empirical and molecular problems. Calculate amounts of reactants and products. Calculate theoretical and percent yield.

Page 3: Stoichiometry Calculations with Chemical Formulas and Equations

StoichiometryQuantity relationships based on

chemical equations3 Main Concepts:1. Chemical formula – molar ratio of

atoms2. Chemical equations – molar ratio of

compounds3. Law of Conservation of Mass:

mass of reactants = mass of products

Page 4: Stoichiometry Calculations with Chemical Formulas and Equations

3.1 Chemical EquationsComponents: reactants → products Physical states (s, l, g, aq) Reaction conditions (heat Δ, light, solvents, etc.) Coefficients determine molar ratios. The number

of moles of each type of atom must be the same on each side.

Balancing: By inspection Use coefficients; don’t change chemical formulas

Page 5: Stoichiometry Calculations with Chemical Formulas and Equations

Coefficients vs. Subscripts

Page 6: Stoichiometry Calculations with Chemical Formulas and Equations

Fe2S3(s) + HCl(aq) → FeCl3(s) + H2S(g)

KClO3(s) → KCl(s) + O2(g)

HNO3(l) + P4O10(s) → (HPO3)3(l) + N2O5(g)

Page 7: Stoichiometry Calculations with Chemical Formulas and Equations

3.2 Some Simple Patterns of Chemical Reactivity

Combination and Decompositioncombination: A + B → C

4 Fe(s) + 3 O2(g) → 2 Fe2O3(s)

decomposition: C → A + B2 NaN3(s) → 2 Na(s) + 3 N2(g)

Page 8: Stoichiometry Calculations with Chemical Formulas and Equations

3.2 Some Simple Patterns of Chemical Reactivity

Combustion burning of a fuel in the presence of

oxygen products of complete combustion: CO2,

H2O exothermic (produces heat)

Page 9: Stoichiometry Calculations with Chemical Formulas and Equations

Molecular view of methane combustion

Page 10: Stoichiometry Calculations with Chemical Formulas and Equations

3.2 Some Simple Patterns of Chemical Reactivity

CombustionC3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O(g)

2 CH3OH(g) + 3 O2(g) → 2 CO2(g) + 4 H2O(g)

Each C atom in fuel produces 1 mol CO2

Each H atom in fuel produces ½ mol H2O

Page 11: Stoichiometry Calculations with Chemical Formulas and Equations

3.3 Formula WeightsFormula and Molecular Weights (amu)

formula weight – generalmolecular weight – moleculesformula unit weight – ionic compound

- sum of the atomic masses of each atom in chemical formula

Page 12: Stoichiometry Calculations with Chemical Formulas and Equations

% Composition

% composition by mass Mass of one type of atoms over mass of all

atoms

%100wholepartpercent

Page 13: Stoichiometry Calculations with Chemical Formulas and Equations
Page 14: Stoichiometry Calculations with Chemical Formulas and Equations

3.4 Avogadro’s Number and the Mole

Word association:pair –dozen –case –ream –

Page 15: Stoichiometry Calculations with Chemical Formulas and Equations

amu impractical for lab use (too small) Avogadro’s number: 6.0221421 x 1023

mol-1 The number of atoms in exactly 12 g of

12C For conversions: 6.022 x 1023 ?/mol, where

? can equal atoms, molecules, ions, etc. 1 mole = Avogadro’s number of

anything molar mass – mass in grams of one

mole of a substance, which is equal to the atomic mass in amu; g/mol

3.4 Avogadro’s Number and the Mole

Page 16: Stoichiometry Calculations with Chemical Formulas and Equations

Atoms & compounds have different masses, thus the mass of 1 mole of atoms & compounds are different.

3.4 Avogadro’s Number and the Mole

Page 17: Stoichiometry Calculations with Chemical Formulas and Equations

Conversions: g → mol divide by molar mass mol → g multiply by molar mass

Abbreviations: mole – molmolarity – M

3.4 Avogadro’s Number and the Mole

Page 18: Stoichiometry Calculations with Chemical Formulas and Equations

Practice with Avogadro’s # & the Mole

Page 19: Stoichiometry Calculations with Chemical Formulas and Equations

3.5 Empirical Formulas from Analyses

Empirical formula – smallest whole number ratio of atoms

Molecular formula – actual ratio of atoms in a compound; multiple of the empirical formula; must know molar mass of compound

Use % composition to find formula

Problems

Page 20: Stoichiometry Calculations with Chemical Formulas and Equations

A once-used gasoline additive contains 49.5% C, 3.2% H, 22.0% O, and 25.2% Mn. Determine the emipirical formula of this compound.

Page 21: Stoichiometry Calculations with Chemical Formulas and Equations

Azulene, a hydrocarbon, contains 93.71% C. Its molar mass is ~128 g/mol. Determine the emipirical and molecular formulas for azulene.

Page 22: Stoichiometry Calculations with Chemical Formulas and Equations

3.5 Empirical Formulas from AnalysesSummary:

% data → grams Grams → moles Moles → molar ratio → empirical

formula Empirical formula → molecular

formula

Page 23: Stoichiometry Calculations with Chemical Formulas and Equations

3.5 Empirical Formulas from Analyses

Combustion analysis 1 mol C in fuel → 1 mol CO2

2 mol H in fuel → 1 mol H2O

Problems

Page 24: Stoichiometry Calculations with Chemical Formulas and Equations

The combustion of propane, a hydrocarbon, produces 2.641 g CO2 and 1.442 g H2O. Determine the emipirical formula of propane.

Page 25: Stoichiometry Calculations with Chemical Formulas and Equations

3.6 Quantitative Information from Balanced Equations

3 Main Concepts:1. Chemical formula – molar ratio of

atoms2. Chemical equations – molar ratio

of compounds3. Law of Conservation of Mass:

mass of reactants = mass of products

Page 26: Stoichiometry Calculations with Chemical Formulas and Equations

What’s balanced in a balanced equation?

Page 27: Stoichiometry Calculations with Chemical Formulas and Equations

Stoichiometry ProblemsUse these 4 steps as a guide: (p. 97) Write & balance chemical equation. Convert to moles. Apply molar ratio. Convert from moles to quantity

desired (mass, volume, etc.)

Page 28: Stoichiometry Calculations with Chemical Formulas and Equations

Stoichiometry Problems

Page 29: Stoichiometry Calculations with Chemical Formulas and Equations

How many grams of CaCl2 is produced from taking 2 antacid tablets, each containing 500. mg of CaCO3?

CaCO3(s) + 2 HCl(aq) → CO2(g) + H2O(l) + CaCl2(s)

Page 30: Stoichiometry Calculations with Chemical Formulas and Equations

From Sample Exercise 3.16, p. 98

Page 31: Stoichiometry Calculations with Chemical Formulas and Equations

How many grams of HCl are needed to react with 1000 mg of CaCO3?

CaCO3(s) + 2 HCl(aq) → CO2(g) + H2O(l) + CaCl2(s)

Page 32: Stoichiometry Calculations with Chemical Formulas and Equations
Page 33: Stoichiometry Calculations with Chemical Formulas and Equations

3.7 Limiting Reactants Limiting reactant – reactant that is

completely consumed; limits the amount of product that can be formed

Theoretical yield – calculated yield of a product based on limiting reactant

Percent yield

100%yieldltheoreticayieldalexperimentyield%

Page 34: Stoichiometry Calculations with Chemical Formulas and Equations

78. Calculate the theoretical yield (in grams) of NO when 2.00 g of NH3 react

with 2.50 g of O2. NH3(g) + O2(g) → NO(g) + H2O(g)

Page 35: Stoichiometry Calculations with Chemical Formulas and Equations

Silver metal reacts with elemental sulfur according to the reaction below. If 2.0 g each of

silver and sulfur react, what is the theoretical yield (in grams) of silver(I) sulfide? How many

grams are left over? 16 Ag(s) + S8(s) → 8 Ag2S(s)

Page 36: Stoichiometry Calculations with Chemical Formulas and Equations

How many grams are left over? 16 Ag(s) + S8(s) → 8 Ag2S(s)

Page 37: Stoichiometry Calculations with Chemical Formulas and Equations

84. When hydrogen sulfide gas is bubbled into a solution of sodium hydroxide, the reaction forms sodium sulfide and water. How many grams of sodium sulfide are formed if 1.25 g of hydrogen sulfide is bubbled into a solution containing 2.00 g of sodium hydroxide, assuming that the sodium sulfide is made in 92.0% yield?

Page 38: Stoichiometry Calculations with Chemical Formulas and Equations
Page 39: Stoichiometry Calculations with Chemical Formulas and Equations

When 0.750 g iron(III) chloride hydrate is heated, 0.300 g of steam is produced. What is

the value of x ?

FeCl3·x H2O(s) → FeCl3(s) + x H2O(g)Δ

Page 40: Stoichiometry Calculations with Chemical Formulas and Equations