14
MATHEMATICS PAPER 2 Section A No. Marking Scheme Marks 1. a) b) Note: ( QUR ) correctly shaded, award 1 mark. 1 2 3 2 x + y = 55 or equivalent or 3x + 2y = 145 or equivalent 3x + 3y = 165 or equivalent OR x = 55 – y or equivalent (1) 1 1 P Q R P Q R

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MATHEMATICS PAPER 2

Section A

No. Marking Scheme Marks

1.a)

b)

Note:( QUR ) correctly shaded, award 1 mark.

1

2 3

2x + y = 55 or equivalent or 3x + 2y = 145 or equivalent

3x + 3y = 165 or equivalent

OR

x = 55 – y or equivalent (1)

OR

y

x

=

11(2)−1(3 )

13

12

145

55

(2)

x = 35 y = 20

1

1

1,1 4

P

Q

R

Q

PR

SULIT 1449/1& 1449/2

3. 0762 xx 017 xx

x = -7, x = 14d

111

1

44.

a)

b) tan θ = 13

8

θ = '[email protected] 00

1

1

1 3

5. a)

b)

0 – 2y – 18 = 0

y = − 9Note :Accept answer without working award 2 marks.

m PN = 2

1

(from equation) or m PN = 018

)9(0

= 2

1

7 = 2

1

(4) + c

y = 2

1

x + 5

1

1

1

1

1 5

®JPN PERAK_MOCKTEST 2 2015 SULIT

T

U

R

Q

P

S

V

12 cm

16 cm

5 cmθ

2

SULIT 1449/1& 1449/2

6 a)

b)

c)

1

2 × 6 × 18

54

1(9 15) 18

215

14

2

5 or 14.4

14 × t or

1

2 ( t + t – 6 ) 18

13.5

1

1

1

1

1

1 6

7 a)

b)

c)

(i) False(ii) True

Implication 1: If sin θ =0.5, then θ =30°Implication 2 : If θ =30° ,then sin θ = 0.5

3608

or 45°

11

11

1 5

8.a)

b)

n = - 3

Note : 1

(6 ) (3 )−(−5 )(−4 ) * (matrix) seen award 1 mark

( 1 125 105)( x

y )=( 784830)

( xy )= 1

(1 ) (105 )−(1 )(25) ( 105 −1−25 1 )( 78

4830) x = 42 , y = 36

2

1

1

1,1 6

®JPN PERAK_MOCKTEST 2 2015 SULIT

3

SULIT 1449/1& 1449/2

9

7

22

3 3 7

7

22

3 ¿ 3 3 or 2

1

3

4

7

22

3 3 3

7

22

3 3 7 ─ ( 7

22

3 3 3 + 2

1

3

4

7

22

3 3 3)

56.57 or 7

396

or 56 7

4

1

1

1

1 4

10a)

b)

180 222 5

360 7

or

60 222 2.5

360 7

equivalent

180 22 60 222 5 2 2.5

360 7 360 7

+5 + 2.5 + 2.5 or equivalent

28.33 or

3328

100 or

2833

100

2180 22

5360 7

or

260 222.5

360 7

or equivalent

2180 22

5360 7

+

260 222.5

360 7

18 6

2

or equivalent

18.56 or

1418

25 or

464

25

1

1

1

1

1

1 6

11.a) Outcome of Box Q

Kesudahan Kotak Q

A B C

Out

com

e of

Box

PK

esud

ahan

Kot

ak P 1 (1,B) (1,C)

2 (2,A) (2,B) (2,C)

3 (3,A) (3,B)

4 (4,A) (4,B)

Note:2

®JPN PERAK_MOCKTEST 2 2015 SULIT

4

SULIT 1449/1& 1449/2

b)

1. Accept 2 mistakes for 1 mark.2. Accept without brackets.

i){(1,B) , (2,B) , (3,B) , (4,B)}

12

4

or equivalent.

ii)

{(1,A) , (1,B) , (1,C) , (2,C) , (3,A) , (3,B) , (3,C) , (4,C)}

12

8

or equivalent.

1

1

1

16

®JPN PERAK_MOCKTEST 2 2015 SULIT

5

SULIT 1449/1& 1449/2

12 a)

b)

c)

d)

y = 11, y = - 5

Note:

1) if points are correctly marked on the graph2) the curve passes exactly through the points.

Graph :Axes are drawn in the correct direction with uniform scale. in the range −3.5 x 3.5 and 15 y 17.

All 7 points and 2 points* are correctly marked

Smooth curve and continuously in range of − 3.5 x 3.5 with no straight line part and passing through all the correct 9 points.

Note:(i)7 @ 8 points are correctly plotted, award 1 mark

(ii)Other scale used, deduct 1 mark.

(i) 5.4 y 5.5

(ii) 3.3 x 3. 4

Straight line y = 5x 5 correctly drawn and meet the curve.

The equation y = 5x 5 award 1 mark

The value of x : 3.2 x 3.3 0.6 x 0.7

Note:

(i) The value of x obtained by calculation, no markaward.

1,1

1

2

1

1

1

2

11

12

®JPN PERAK_MOCKTEST 2 2015 SULIT

Section B6

SULIT 1449/1& 1449/2

®JPN PERAK_MOCKTEST 2 2015 SULIT

33 8y x x

y = 5x 5

-15

-20

-4

-10

-5

10

20

5

30

15

25

y

4

x

-3 -2 1 32-1 O

7

SULIT 1449/1& 1449/2

13(a)(i)

(ii)

(b)(i)

(ii)

(1,7)(2,4) seen/ marked award 1

(-5,-5)(-4,2) seen/ marked award 1

P – Reflection in the line y = -1Q – Enlargement, scale factor = 2, centre (0,-7)

x + 16.5 = 22x3x = 16.5

x = 5.5

2

2

23

2

1 12

14 (a)Class Interval Midpoint Frequency

I 65 - 69 67 2II 70 - 74 72 3III 75 - 79 77 5IV 80 - 84 82 9V 85 - 89 87 7VI 90 - 94 92 3VII 95 - 99 97 1

Class interval : (II to VII) all correct Midpoint : (I to VII) all correct Frequency : (I to VII) all correct

Note : 5 or 6 frequency are correct, award 1 mark

(b)

30

)197()392()787()982()577()372()267(

or 30

2455

81.83 or

581

6 or

491

6

112

2

1

®JPN PERAK_MOCKTEST 2 2015 SULIT

8

SULIT 1449/1& 1449/2

(c) Histogram Axes drawn in the correct direction with uniform scales. x-axis is labelled by midpoints / class boundaries / class intervals.

All 7 bars are correctly drawn Complete histogram

Note: 5 or 6 bars are correctly drawn, award 1 mark.

(d) Modal Class = 80 – 84Note:

1. Accept any reasonable information.2. Do not accept information without histogram.

11

2

1 12

15 (a)Plan:The shape must be right with the rectangles. All lines must be fully drawn.

2 cm

3 cm

6 cm

Measurement must be accurate to 0.2 cm and all angles at rectangle vertex = 90o 1

Note: Correct shape drawn award 1 mark only

3

®JPN PERAK_MOCKTEST 2 2015 SULIT

9

SULIT 1449/1& 1449/2

b) i

b) ii

Elevation X:The shape must be right with the half of a circle. All lines must be fully drawn.

1 cm

2 cm4 cm

1 cm

1 cm3 cm

2 cm

5 cm

Measurement must be accurate to ±0.2 cm and all angles at rectangle vertex = 90o ±1Note: Correct shape drawn award 1 mark only

Elevation Y:The shape must be right with the rectangles. All lines included the dotted lines must be shown completely.

1 cm

1 cm

1 cm

2 cm

6 cm

Note: Correct shape drawn award 1 mark only

4

5

12

16

a)

R (60 S, 160W)Note : 60S or 160 W award 1 mark

1

1

2

®JPN PERAK_MOCKTEST 2 2015 SULIT

10

SULIT 1449/1& 1449/2

b)

c) i)

ii)

60 60

3600

800 4.5

3600

o60 cos

3600

Note: Using Cos 60º award 1 mark

6060

3600

Cos 20 or 120 20

100W

1

1

1

1

2

1

112

THE END OF MARKING SCHEME

®JPN PERAK_MOCKTEST 2 2015 SULIT

11

SULIT 1449/1& 1449/2

No 14.

®JPN PERAK_MOCKTEST 2 2015 SULIT

Marks

10

9

67 72 87 9792 8277

0

8

7

3

2

4

6

1

5

Frequency

12