Series/Parallel Circuits

Series/Parallel CircuitsI1

+

-V R2 R3

I2 I3

IT

R1

Series/Parallel Circuit 1.Reduce the Parallel Branches into

One Series Resistor.2.This resistor is called an

Equivalent Resistance.3. Do this for all the Parallel Paths.

4. Do your calculation on the Series Circuit.

}1

R23

1R2

1R3

= +

1R23

14

14= +

R23 = 2Ω

+

-V=10v R3 =4Ω

R1=8Ω

R2=4Ω

Block

+

-V=10v

R1=8Ω

R23=2Ω

R23 is an equivalent resistor to

R2 and R3.RT= R1 + R23

RT= 8Ω + 2Ω = 10Ω

Comp R I VR1

R2

R3

R23

Total

8Ω4Ω4Ω

10v

IT = V/ RT

IT = 10v / 10ΩIT = 1AIT = I1 = I23 = 1A

V1 = I1 X R1

V1 = 1A X 8ΩV1 = 8v

V23 = I23 X R23

V23 = 1A X 2ΩV23 = 2v

}+

-V=10v

R1=8Ω

R23=2Ω V23 = 2v

V2 = V3 = 2v

V2 = V3 = 2v

I2 = V2 / R2

I2 = 2v / 4ΩI2 = 0.5A

I3 = V3 / R3

I3 = 2v / 4ΩI3 = 0.5A

+

-V=10v R3 =4Ω

R1=8Ω

R2=4Ω

+

-V=60v

R1= 10kΩ

R2= 15kΩR3= 30kΩ

R5 =

24kΩ

R4=24kΩ

R6= 3kΩ

R1= 10kΩ

R2= 15kΩR3= 30kΩ

1R 123

1R1

1R2

= +1

R3

+

1R 123

110

115

= +1

30

+

1R 123

110

115

= +1

30

+

1R 123

330

230

= +1

30

+

1R 123

630

=

R123 306

= 5kΩ =

R123 5kΩ =

+

-V=60v R5 =

24kΩ

R4=24kΩ

R6= 3kΩ

R123= 5kΩ

R5 =

24kΩ

R4=24kΩ

1R 45

1R4

1R5

= +

1R 45

124

124

= +

1R 45

224=

R45 242

= 12kΩ =

R45 12kΩ =

V=60v

R6= 3kΩ

R123= 5kΩ

+

- R45=12kΩ

RT= R123 + R45 + R6

RT= R123 + R45 + R6

RT= 5kΩ + 12kΩ + 3kΩ

RT= 20kΩ

IT =60v

20kΩ

IT =ET

RT

IT = 3mA

V=10v

R6= 3kΩ

R123= 5kΩ

+

- R45=12kΩIT = 3mA

V123 = I123 X R123

= 3mA X 5kΩV123 = 15v

V45 = I45 X R45

=3mAX 12kΩV45 = 36v

V6 = I6 X R6

= 3mA X 3kΩ

V6 = 9v

I1 =E1

R1

=10v10kΩ

I1 = 1mA

I2 =E2

R2

=15v10kΩ

I2 = 1.5mA

I3 =E3

R3

=15v30kΩ

I3 = 0.5mA

I4,5 =E4

R4

=36v24kΩ

I4,5 = 1.5mA

I6 =E6

R6

=9v3kΩ

I3 = 3mA