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SCHOLASTIC APTITUDE TEST (SAT) PREP

Scholastic Aptitude Test (SAT)

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Scholastic Aptitude Test (SAT). PREP. Practice problems Version 3. SAT. ( 1 + 1 ) ÷ 1 = 5 3 2 3 + 5 ÷ 1 = 15 2 8 • 2 = 16 15 1 15. SAT. x 2 – 2 x when x = – 2 ? (– 2 ) 2 – 2 (– 2 ) = 4 + 4 = 8. SAT. x = 96 60 160 - PowerPoint PPT Presentation

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Page 1: Scholastic  Aptitude  Test (SAT)

SCHOLASTIC APTITUDE TEST (SAT)

PREP

Page 2: Scholastic  Aptitude  Test (SAT)

PRACTICE PROBLEMS

VERSION 3

Page 3: Scholastic  Aptitude  Test (SAT)

1. ( 1 + 1 ) ÷ 1 = 5 3 2

(A) 18

(B) 14

(C) 415

(D) 12

(E) 16 15

( 1 + 1 ) ÷ 1 =

5 3 2

3 + 5 ÷ 1 =

15 2

8 • 2 = 16

15 1 15

(E) 1615

SAT

Page 4: Scholastic  Aptitude  Test (SAT)

2. x 2 – 2 x when x = – 2 ?

(A) – 8

(B) – 4

(C) 0

(D) 4

(E) 8

x 2 – 2 x when x = – 2 ? (– 2 ) 2 – 2 (– 2 ) =4 + 4 = 8

(E) 8

SAT

Page 5: Scholastic  Aptitude  Test (SAT)

3. Kate read 96 pages in 2 hours and 40 minutes. What was Kate’s average rate of pages per hour?

(A) 24

(B) 30

(C) 36

(D) 42

(E) 48

x = 96 60 160

x = 96 • 60 160

x = 6 • 60 10

x = 6 • 6 = 36

(C) 36

SAT

Page 6: Scholastic  Aptitude  Test (SAT)

4. For how many integer values of x will 7/8 be greater than ¼ and less than 1/3 ?

(A) 6

(B) 7

(C) 12

(D) 28

(E) Infinite many

1 > 7 > 1 3 x 4

( 1 > 7 > 1 ) 12 x 3 x 4 4 x > 84 > 3 x _______________________________________________________________________________________

4 (22) > 84 > 3 (22) --- 88 > 84 > 66

4 (23) > 84 > 3 (23) --- 92 > 84 > 69

4 (24) > 84 > 3 (24) --- 96 > 84 > 72

4 (25) > 84 > 3 (25) --- 100 > 84 > 75

4 (26) > 84 > 3 (26) --- 104 > 84 > 78

4 (27) > 84 > 3 (27) --- 108 > 84 > 81

(A) 6

SAT

Page 7: Scholastic  Aptitude  Test (SAT)

5. What is the average (arithmetic mean) of 2 x + 5, 5 x – 6 , – 4 x + 2 ?

(A) x + 1 3

(B) x + 1

(C) 3 x + 1 3

(D) 3 x + 3

(E) 3 x + 3 1 3

2 x + 5 5 x – 6– 4 x + 2 3 x + 1

3 x + 1 = x + 1 3 3

(A) x + 1 3

SAT

Page 8: Scholastic  Aptitude  Test (SAT)

7. In this triangle, what is the degree measure of angle B ?

(A) 45

(B) 60

(C) 65

(D) 75

(E) 80

< B + < C + < A = 180⁰

< B + 45⁰ + 70⁰ = 180⁰

< B + 115⁰ = 180⁰

< B = 180⁰ – 115⁰ = 65⁰

(C) 65⁰

SAT

45⁰BC

A

70⁰

Page 9: Scholastic  Aptitude  Test (SAT)

8. For all x ≠ 0, x2 + x2 + x2 = x2

(A) 3

(B) 3 x

(C) x2

(D) x3

(E) x4

x2 + x2 + x2 = x2

3 x2 = 3 x2

(A) 3

SAT

Page 10: Scholastic  Aptitude  Test (SAT)

8. For all x ≠ 0, x2 + x2 + x2 = x2

(A) 3

(B) 3 x

(C) x2

(D) x3

(E) x4

x2 + x2 + x2 = x2

3 x2 = 3 x2

(A) 3

SAT

Page 11: Scholastic  Aptitude  Test (SAT)

9. The equation x2 = 5x – 4 has how many distinct real solutions ?

(A) 0

(B) 1

(C) 2

(D) 3

(E) Infinitely many

x2 = 5 x – 4 x2 – 5 x + 4 = 0

( x – 4 ) ( x – 1 ) = 0

x = 4 or 1 (C) 2

SAT

Page 12: Scholastic  Aptitude  Test (SAT)

10.Which of the following sets of numbers has the property that the sum of any two numbers in the set is also a number in the set ?

I. The set of even integersII. The set of odd integersIII. The set of prime numbers

(A) I only

(B) III only

(C) I and II only

(D) I and III only

(E) I, II, and III

1 + 3 = 4 Ex where odd integers doesn’t work

3 + 5 = 8 Ex where prime doesn’t work

2 + 4 = 6 Even Integers does work

(A) I only

SAT

Page 13: Scholastic  Aptitude  Test (SAT)

11.Bob’s average (arithmetic mean) score after 4 tests is 89. What score on the 5th test would bring Bob’s average up to exactly 90?

(A) 90

(B) 91

(C) 92

(D) 93

(E) 94

89 x 4 = 356 90 x 5 = 450

So, the difference between the 2 gives us the total needed to average 90

450 – 356 = 94(F) 94

SAT

Page 14: Scholastic  Aptitude  Test (SAT)

12.The price s of a sweater is reduced by 25% for a sale. After the sale, the reduced price is increased by 20%. Which of the following represents the final priceo f the sweater ?

(A) 1.05 s

(B) .95 s

(C) .90 s

(D) .85 s

(E) .80 s

Sale price is 25 % off or .75 s

Post sale price is increased by 20 %

The increase = .75 s x .2 = .15 s

Then we add .75 s + .15 s = 90 s

(C) .90 s

SAT

Page 15: Scholastic  Aptitude  Test (SAT)

13. How many distinct prime factors does the number 36 have ?

(A) 2

(B) 3

(C) 4

(D) 5

(E) 6

362 x 182 x 3 x 62 x 3 x 2 x 3

(A) 2

SAT

Page 16: Scholastic  Aptitude  Test (SAT)

15. If the area of a triangle is 36 and its base is 9, what is the length of the altitude to that base?

(A) 2

(B) 4

(C) 6

(D) 8

(E) 12

AT = 1 hb = 36 2 1 h (9) = 36 2 h (9) = 36 2 h = 36 • 2 9 h = 8

(D) 8

SAT

Page 17: Scholastic  Aptitude  Test (SAT)

15.Let a be defined for all positive integers a by the equation a = a – a If x = 3, what is the value of x ? 4 6

(A) 18

(B) 28

(C) 36

(D) 40

(E) 54

If a = a – a 4 6 x = x – x 4 6If x = 3 3 = x – x 4 612 (3 = x – x ) 4 636 = 3 x – 2 x

36 = x

(C) 36

SAT

Page 18: Scholastic  Aptitude  Test (SAT)

16. Betty has q quarters, d dimes, n nickels and no other coins in her pocket. Which of the following represents the total number of coins in Joan’s pocket ?

(A) q + d + n

(B) 5q + 2d + n

(C) .25q + .10d + .05n

(D) (25 + 10 + 5) (q + d + n )

(E) 25q + 10d + 5n

This is a “TRAP” question:The problem only asks for the total # of coins, NOT the total value of coins, which is what you are lead to think.

(A) q + d + n

SAT

Page 19: Scholastic  Aptitude  Test (SAT)

17. Which of the following is an equation for the graph above ?

(A) y = –2 x + 1

(B) y = x + 1

(C) y = x + 2

(D) y = 2 x + 1

(E) y = 2 x + 2

The slope is 2 and the y-intercept is 2, so the answer is y = 2 x + 2

(E) y = 2 x + 2

SAT

Page 20: Scholastic  Aptitude  Test (SAT)

18.If an integer is divisible by 6 and 9, then the integer must be divisible by which of the following ?

I. 12II. 18III. 36

(A) I only

(B) II only

(C) I and II only

(D) II and III only

(E) I, II, and III

Prime factors of 6 are 2 x 3, so any # divisible should have at least one 2 and one 3 as factors

Prime factors of 9 are 3 x 3, so any # divisible should have at least two 3’s as factors

Any # divisible by both should have at least one 2 and two 3’s and the first possibility is 2 x 32 or 18

12 and 36 require two 2’s in its prime factorization

12 doesn’t have a 2nd prime factor of 336 does work in some cases by NOT all, such as the most obvious one, 6 x 9 or 54.

(B) II only

SAT

Page 21: Scholastic  Aptitude  Test (SAT)

19. In this figure, O is the center of the circle and P, O, and Q are collinear. If < ROQ measures 50⁰, what is the degree measure of <RPQ ?

(A) 20

(B) 25

(C) 30

(D) 35

(E) 40

< POR =180⁰ – 50 ⁰ = 130 ⁰PO = OR (all radii are =) < RPQ = <PRO (base <‘s of Isosceles are =)and < QPR + <PRO = 50 ⁰ < RPQ =25

(B) 25

SAT

QOP

R

50⁰?

Page 22: Scholastic  Aptitude  Test (SAT)

20.A wooden cube with volume 64 is sliced in half horizontally,. The two halves are then glued together to form a rectangle solid which is not a cube. What is the surface area of this new solid?

(A) 128

(B) 112

(C) 96

(D) 56

(E) 48

E3 = 4 x 4 x 4 = 64Two rectangle solids 4 x 4 x 2, when glued 2 x 4 x 8Then Top and Bottom = 8 x 4 = 32 or 64 totalThen Front and Back = 8 x 2 = 16 or 32 totalThen two sides = 4 x 2 = 8 or 16 total

(B) 112

SAT

64

E3 = 4 x 4 x 4 = 64

2

2

44

24

4 4

Grand total of 6 sides = 64 + 32 + 16 = 112

Page 23: Scholastic  Aptitude  Test (SAT)

21.A drawer contains 6 blue socks, 12 black socks and 15 white socks. If one sock is chosen at random, what is the probability that it will be black?

(A) 14

(B) 13

(C) 38

(D) 12

(E) 58

6 blue12 black15 white32 Total

Black 12 = 3Total 32 8

(C) 38

SAT

Page 24: Scholastic  Aptitude  Test (SAT)

22.Danielle drives from here home to the store at an average speed of 40 miles per hour. She returns home along the same route at an average speed of 60 miles per hour. What is her average speed, in miles per hour, for her entire trip ?

(A) 45

(B) 48

(C) 50

(D) 52

(E) 55

This is a TRAP question ! We are NOT given enough information to use a distance formula. So we need to improvise by selecting a distance that is easy to work with. Since we have speeds of 40 and 60 mph, why not use a multiple of both, such as, 120

Distance = rate x time(going trip) 120 = 40 t where t = 3 hours(return trip) 120 = 60 t where t = 2 hours Now 240 = 5 r, where r = 48 miles per hour

(A) 48

SAT

Page 25: Scholastic  Aptitude  Test (SAT)

23. What is the area of a right triangle if the length of one leg is a and the length of the hypotenuse is c ?

(A) ac 2

(B) ac – a2

2

(C) a3 + c3

2

(D) a c2– a2

2

(E) a2 + c2

c2 = a2 + b2

c2 – a2 = b2

√ c2 – a2 = b

AT = ½ h b

A = 1 a ( √ c2 – a2 ) 2

SAT

c2

b2

a2

(D)

Page 26: Scholastic  Aptitude  Test (SAT)

24. In ∆ PRS, RT is the altitude to side PS and QS is the altitude to side PR. If RT = 7, PR – 8 and QS = 9, what is the length of PS ?

(A) 5 1 7

(B) 6 2 9

(C) 7 7 8

(D) 10 2 7

(E) 13 4 9

AT = ½ h b

Using altitude QS and side PR = ½ • 9 • 8 = 36

Using altitude RT with side PS = ½ • 7 • PS = 36

7 PS = 36 then, PS = 36 • 2 = 10 2 2 7 7

(D) 10 2 7

SAT

P

Q

R

ST

Page 27: Scholastic  Aptitude  Test (SAT)

25.There are 3 routes from River City to Bayville.There are 4 routes from Bayville to Eagles Mere.There are 3 routes from Eagles Mere to Twin Peaks.If a driver must pass through Bayville, and Eagles Mere exactly once, how many possible ways are there to go from River City to Twin Peaks.

(A) 6

(B) 10

(C) 12

(D) 24

(E) 36

River City1 2 3 [ 3 ]

xBayville1 2 3 4 [ 4 ] x Eagles Mere1 2 3 [ 3 ] = Twin Peaks [ 36 ]

(E) 36

SAT