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Airflow for drying Resistance to airflow Resistance of grain to airflow Pressure drop due to: Energy loss due to friction & turbulence To overcome this: 1. High pressure at inlet plenum chamber 2. Create a vacuum at the exit

Resistance to airflow · 2019-02-16 · Airflow for drying Resistance to airflow Resistance of grain to airflow Pressure drop due to: Energy loss due to friction & turbulence To overcome

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Airflow for dryingResistance to airflow

Resistance of grain to airflowPressure drop due to:Energy loss due to friction & turbulenceTo overcome this: 1. High pressure at inlet plenum chamber2. Create a vacuum at the exit

Perdition by two math models

Pressure drop depends on

• Rate of airflow

• Surface and shape characteristics of the product

• The number, configuration and size of voids

• The variability of the product size

• Depth of the product bed

Semi-log plotsAirflow Vs. Pressure drop per unit depth

Mathematical modeling

∆𝑝′ =𝑎𝑄𝑎

2

𝑙𝑛(1+𝑏𝑄𝑎)1

𝑄𝑎 =exp[A+B*ln∆𝑝′ +C (ln∆𝑝′ )2 -------2

𝑄𝑎= air flow rate m3/s.m2 ∆𝑝′= pressure drop

per unit depth Pa/mHukill & Shredd - 1955

Constants

Pressure drop calculation for Rice(Calderwood, 1973)

• SCM- Shredd Curve Multiplier

• Eq-1 – “a” multiply by SCM

• Eq-2 – replace Δp‘ by Δp‘/SCM

• See next slide for SCM values

Static pressure drop is also affected by the moisture content of the grain and available fines

• Corn 12% MC, fines (FM) 0-20% (passing through 4.76 mm sieve)

• Airflow rate 0.076-0.38 m3/m2.s

• ∆𝑝′ = 𝐶1𝑄𝑎 + 𝐶2𝑄2𝑎+ 𝐶3𝑄𝑎(𝐹𝑀)

• C1= 436.67

• C2 = 7363.04

• C3 = 225.26 (Haque et al 1978)

Effect of moisture on Δp’

• Δp’=AQa+B(Qa)2+-CMQa

• M- Moisture content w.b. as a percentage• Insert table 6.6

SI

Resistance of perforated metal to airflow

• Δp=10-6/9 [Qa/εQf]2

• ε –Void space in grain% (decimal)• Q

f– opening in floor % (decimal)

Pressure losses in ducts

• Pressure loss is due to :

• 1. Friction

• 2.restriction to air (Fittings)

• 3.Change in direction

• 4. Enlargement or contraction of crossectional area

• Total pressure at any point of a duct = static pressure + Velocity pressure

• Static pressure – force perpendicular to the duct wall – independent of air velocity

• Velocity pressure (head) – depends of movement and density of air (m of air)

• V2/2g (V–m/s, g – acceleration of gravity-ms-2)

• In Pa = V2/2g (1.20)(9.81) = [v/1.29]2

• 1.20 – air density kg/m3

Fans fitted directly to the plenum

• Vey low air flow velocity- velocity pressure is assumed as 0

• Total pressure = static pressure

• Fans connected to the plenum with a duct:

• Pressure loss in the duct is due to friction loss (dynamic losses)- due to surface friction

• Dynamic losses are due to cross section changes or direction of flow changes

• Total pressure at the fan= total pressure at the plenum + pressure loss at the duct

• Static pressure at the fan = total pressure –velocity pressure

• Grain drying systems are designed based on the static pressure

Pressure loss – straight ducts

• Eg. Temperature range 9-31 oC

• Insert 6-6A friction loss chart

• Different diameters & flow rates

Temp & elevation correction chart

Use temperature KTandHeight multiplier KEto extrapolate the values of the above chart

Pressure losses in Elbows

• Pressure loss in Elbow

• ΔpT= C(V/1.29)2

• C- pressure loss coefficient

• Or use table values by the supplier

• Insert table 6-8

Changers in cross sectional area

• Change may be abrupt or gradual (empirical equations)

• Expansion of Area

• ΔpT= C1(V1/1.29)2

• Area reduction

• ΔpT= C2(V2/1.29)2

• Insert fig 6-8

Fans

Air movement by an axial fan

Velocity of an air duct can be calculated as follows using the measured velocity pressure data

Fan performance measurements

Distance to get a uniform air flow velocity

Example

Fan laws

fa2/ fa1 = (DPT2/ DPT1)1/2 = (Wfi2/Wfi2)1/3

Combined flow and power equation

Typical fan performance Characteristics curve

At 50% free delivery air flow

End