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Relational Query Languages Query languages: Allow manipulation and retrieval of data from a database. Relational model supports simple, powerful, declarative QLs with precise semantics: Strong formal foundation based on logic. Allows for much optimization. Query Languages != programming languages!

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Page 1: Relational Query Languages - cise.ufl.edu. Relational Model_SQL... · Relational Query Languages •Query languages: Allow manipulation and retrieval of data from a database. •Relational

Relational Query Languages

• Query languages: Allow manipulation and retrieval of data from a database.

• Relational model supports simple, powerful, declarative QLs with precise semantics:

– Strong formal foundation based on logic.

– Allows for much optimization.

• Query Languages != programming languages!

Page 2: Relational Query Languages - cise.ufl.edu. Relational Model_SQL... · Relational Query Languages •Query languages: Allow manipulation and retrieval of data from a database. •Relational

Preliminaries

• A query is applied to relation instances, and the result of a query is also a relation instance.

– Schemas of input and output relations for a query are determined by query

• Since each operation returns a relation, operations can be composed! (Algebra is “closed”.)

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Formal Relational Query Languages

• Two mathematical Query Languages and one “real” QL language (i.e., SQL)

– Relational Algebra: More operational, very useful for representing execution plans.

– Relational Calculus/SQL: Lets users describe what they want, rather than how to compute it. (Non-operational, declarative.)

Page 4: Relational Query Languages - cise.ufl.edu. Relational Model_SQL... · Relational Query Languages •Query languages: Allow manipulation and retrieval of data from a database. •Relational

The SQL Query Language

• To find all 18 year old students, we can write:

• To find just names and logins

– replace the first line:

SELECT S.name, S.login

….

SELECT * FROM Students S WHERE S.age=18

sid name login age gpa

53666 Jones jones@cs 18 3.4

53688 Smith smith@ee 18 3.2

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Querying Multiple Relations

• What does the following query compute?

SELECT S.name, E.cid FROM Students S, Enrolled E WHERE S.sid=E.sid AND E.grade=“A”

S.name E.cid

Smith Topology112

sid cid grade

53831 Carnatic101 C

53831 Reggae203 B

53650 Topology112 A

53666 History105 B

Given the following instances of Enrolled and Students:

we get:

sid name login age gpa

53666 Jones jones@cs 18 3.4

53688 Smith smith@eecs 18 3.2

53650 Smith smith@math 19 3.8

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What is an “Algebra”

• Mathematical system consisting of:

– Operands --- variables or values from which new values can be constructed.

– Operators --- symbols denoting procedures that construct new values from given values.

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What is Relational Algebra?

• An algebra whose operands are relations or variables that represent relations.

• Operators are designed to do the most common things that we need to do with relations in a database.

– The result is an algebra that can be used as a query language for relations.

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Roadmap on RA

• Core relational algebra (set semantics)

• Bag semantics

• Extended relational algebra: additional operators

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Core Relational Algebra

• Union, intersection, and difference. – Usual set operations, but require both

operands have the same relation schema.

• Selection: picking certain rows.

• Projection: picking certain columns.

• Products and joins: compositions of relations.

• Renaming of relations and attributes.

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Page 10: Relational Query Languages - cise.ufl.edu. Relational Model_SQL... · Relational Query Languages •Query languages: Allow manipulation and retrieval of data from a database. •Relational

Union, intersection, and difference

• R1 := R2 UNION R3

• R1 := R2 INTERSECT R3

• R1 := R2 DIFFERENCE R3

• R1 Schema? Data?

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Selection

• R1 := SELECTC (R2)

– R1: Schema? Data?

– C is a condition (as in “if” statements) that refers to attributes of R2.

– R1 is all those tuples of R2 that satisfy C.

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Example

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Relation Sells: bar beer price Joe’s Bud 2.50 Joe’s Miller 2.75 Sue’s Bud 2.50 Sue’s Miller 3.00

JoeMenu := SELECTbar=“Joe’s”(Sells): bar beer price Joe’s Bud 2.50 Joe’s Miller 2.75

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Projection

• R1 := PROJL (R2)

– L is a list of attributes from the schema of R2.

– R1 is constructed by looking at each tuple of R2, extracting the attributes on list L, in the order specified, and creating from those components a tuple for R1.

– Eliminate duplicate tuples, if any.

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Example

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Relation Sells: bar beer price Joe’s Bud 2.50 Joe’s Miller 2.75 Sue’s Bud 2.50 Sue’s Miller 3.00

Prices := PROJbeer,price(Sells): beer price Bud 2.50 Miller 2.75 Miller 3.00

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Product

• R3 := R1 R2

– Schema of R3 is the attributes of R1 and then R2, in order.

– But beware attribute A of the same name in R1 and R2: use R1.A and R2.A.

– Pair each tuple t1 of R1 with each tuple t2 of R2.

– Concatenation t1t2 is a tuple of R3.

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Example: R3 := R1 R2

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R1( A, B ) 1 2 3 4 R2( B, C ) 5 6 7 8 9 10

R3( A, R1.B, R2.B, C ) 1 2 5 6 1 2 7 8 1 2 9 10 3 4 5 6 3 4 7 8 3 4 9 10

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Theta-Join

• R3 := R1 JOINC R2

– Take the product R1 R2.

– Then apply SELECTC to the result.

– C can be any boolean-valued condition.

• Why called Theta-Join?

– Common form of boolean condition:

A B, where is =, <, etc.

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Example

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Sells( bar, beer, price ) Bars( name, addr ) Joe’s Bud 2.50 Joe’s Maple St. Joe’s Miller 2.75 Sue’s River Rd. Sue’s Bud 2.50 Sue’s Coors 3.00 BarInfo := Sells JOIN Sells.bar = Bars.name Bars

BarInfo( bar, beer, price, name, addr ) Joe’s Bud 2.50 Joe’s Maple St. Joe’s Miller 2.75 Joe’s Maple St. Sue’s Bud 2.50 Sue’s River Rd. Sue’s Coors 3.00 Sue’s River Rd.

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Natural Join

• A frequent type of join connects two relations by:

– Equating attributes of the same name, and

– Projecting out one copy of each pair of equated attributes.

• Called natural join.

• Denoted R3 := R1 JOIN R2.

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Example

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Sells( bar, beer, price ) Bars( bar, addr ) Joe’s Bud 2.50 Joe’s Maple St. Joe’s Miller 2.75 Sue’s River Rd. Sue’s Bud 2.50 Sue’s Coors 3.00 BarInfo := Sells JOIN Bars

BarInfo( bar, beer, price, addr ) Joe’s Bud 2.50 Maple St. Joe’s Milller 2.75 Maple St. Sue’s Bud 2.50 River Rd. Sue’s Coors 3.00 River Rd.

Page 21: Relational Query Languages - cise.ufl.edu. Relational Model_SQL... · Relational Query Languages •Query languages: Allow manipulation and retrieval of data from a database. •Relational

Renaming

• The RENAME operator gives a new schema to a relation.

• R1 := RENAMER1(A1,…,An)(R2) makes R1 be a relation with attributes A1,…,An and the same tuples as R2.

• Simplified notation: R1(A1,…,An) := R2.

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Page 22: Relational Query Languages - cise.ufl.edu. Relational Model_SQL... · Relational Query Languages •Query languages: Allow manipulation and retrieval of data from a database. •Relational

Example

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Bars( name, addr ) Joe’s Maple St. Sue’s River Rd.

R( bar, addr ) Joe’s Maple St. Sue’s River Rd.

R(bar, addr) := Bars

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Building Complex Expressions

• Combine operands and operators with parentheses and precedence rules.

• Three notations, just as in arithmetic:

1. Sequences of assignment statements.

2. Expressions with several operators.

3. Expression trees.

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Sequences of Assignments

• Example: R3 := R1 JOINC R2 can be written:

R4 := R1 R2

R3 := SELECTC (R4)

• Create temporary relation names.

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Expressions in a Single Assignment

• Example: the theta-join R3 := R1 JOINC R2 can be written: R3 := SELECTC (R1 R2)

• Precedence of relational operators:

1. [SELECT, PROJECT, RENAME] (highest).

2. [PRODUCT, JOIN].

3. INTERSECTION.

4. [UNION, DIFFERENCE]

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Expression Trees

• Leaves are operands --- either variables of relations or constant relations.

• Interior nodes are operators, applied to their child or children relation(s).

• Example: R3 := SELECTC (R1 R2)

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Example

• Using the relations Bars(name, addr) and Sells(bar, beer, price), find the names of all the bars that are either on Maple St. or sell Bud for less than $3.

• Sequence of assignment?

• Complex expression?

• Expression tree?

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As a Tree:

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Bars Sells

SELECTaddr = “Maple St.” SELECTprice<3 AND beer=“Bud”

PROJECTname

RENAMER(name)

PROJECTbar

UNION

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Example 2

• Using Sells(bar, beer, price), find the bars that sell two different beers at the same price.

• Sequence of Assignments? Expression? Expression Tree?

• Strategy:

– Use renaming to define a copy of Sells, called S(bar, beer1, price)

– Use natural join of Sells and S such that the bar sells both beers at this price.

– Resulting schema (bar, beer, beer1, price) 49

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The Tree

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Sells Sells

RENAMES(bar, beer1, price)

JOIN

PROJECTbar

SELECTbeer != beer1

Page 31: Relational Query Languages - cise.ufl.edu. Relational Model_SQL... · Relational Query Languages •Query languages: Allow manipulation and retrieval of data from a database. •Relational

Summary: Schemas for Results

• Union, intersection, and difference: the schemas of the two operands must be the same, so use that schema for the result.

• Selection: schema of the result is the same as the schema of the operand.

• Projection: list of attributes in L tells us the schema.

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Page 32: Relational Query Languages - cise.ufl.edu. Relational Model_SQL... · Relational Query Languages •Query languages: Allow manipulation and retrieval of data from a database. •Relational

Summary: Schemas for Results

• Product: schema is the attributes of both relations.

– Use R.A, etc., to distinguish two attributes named A.

• Theta-join: same as product.

• Natural join: union of the attributes of the two relations.

• Renaming: the operator tells the schema.

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