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Predavanje12 zlatni presek

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? ?

. .

b

b

a+b a = = a b . . .

b

a+b a = = a b

b a 1+ = a b

1+

1

=

1=

1

2 1 = 0

a 1+ 5 = = = 1.61803398 b 2

. .

a = = 1.61803398 b .

1 = 0.61803398 =

1

. .

AF AD 1 + 5 = = = 1.61803398 = AD DF 2 . .

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1 :

! . .

.

. .

1=

1

; 1 : . 1 .

. .

1=

1

. 1 . .

. .

1

.

. .

.1

. .

.

. .

.

. .

F1=1, F2=1, Fn = Fn 1 + Fn 2

{Fn } = {1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, }.Fn , kad n . Fn 1

F

. .

. .

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