Perhitungan Kuda Kuda

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    PERHITUNGAN GORDING

    1 DATA PERENCANAAN

    Jarak Gording = 1.22 m

    Jarak kuda - kuda = 4 m

    Jarak batang tarik (trekstang) = 1.3333333m

    Jenis penutup atap = Genteng

    Sudut kuda - kuda = 35

    2 DAA !"#$%& ' 15.5.2.4*5

    + = 11 kg,m A& AJA

    A = 13./ 0m2

    = 5.2 0m3

    = 1/. 0m3

    % = 4/

    % = //.2 0m4

    3 DATA PEMBEBANAN

    eban genteng = 5

    (termasuk usuk dan reng)

    eban gording = 11 kg,m

    Dipakai ' 15.5.2.4*5

    4 BEBAN MATI

    eban genteng = 1 kg,m

    (6arak gording .genteng)

    eban Gording = 11 kg,m2kg,m

    !enambung (17) = .2 kg,m

    /.2 kg,m

    5 BEBAN HIDUP

    eban peker6a dan a8at (!) = 15 kg

    6 BEBAN ANGIN

    = 25

    9oe:sien angin tekan == .3

    9oe:sien angin ;isap = -.4

    < tekan = koe tek. angin 6.gordin

    = .3

    = /.15 kg,m

    < ;isap = koe tek. angin 6.gordin

    = -.4

    o

    0m4

    kg,m2

    >D&

    ekanan angin , m2 kg,m2

    .2 ? - .4

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    = -12.2 kg,m

    7 REAKSI PEMBEBANAN ARAH X

    a. Akibat Beba Mati

    "@ =

    = .5 /.2

    = 12/.5 kg

    ma =

    = .125 /.2

    = /.5 kg m

    b. Akibat Beba Hi!"#

    "@ =

    = .5 15

    = 245.5 kg

    ma =

    = .25 15

    = .4 kg m

    0. Akibat Beba A$i

    "@ =

    = .5 /.15

    = 1.3 kg

    ma =

    = .125 /.15

    = 1.3 kg m

    % REAKSI PEMBEBANAN ARAH &

    a. Akibat Beba Mati

    "@ =

    = .5 /.2

    = 3.2 kg

    ma =

    = .125 /.2

    = 1./ kg m

    b. Akibat Beba Hi!"#

    "@ =

    = .5 15 = 5.3 kg

    ma =

    = .25 15

    = 2. kg m

    ' KOMBINASI PEMBEBANAN

    = 1.2 >D& B 1.

    1,2 >D&

    'os ? &

    1, >D&

    Sin ? &2

    1,2 >&&

    'os ? &

    1,4 >&&

    Sin ? &

    1,2 < tekan &

    1, < tekan &2

    1,2 >D&

    Sin ? &,3

    1, >D&

    Sin ? &,32

    1,2 >&&

    Sin ? &,3

    1,4 >&&

    Sin ? &,3

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    = 1/.3 B 13.

    = 21.323 kg m

    = 21323.54 C mm

    = 1.2 >D& B 1.

    = 12.11 B 45.

    = 5. kg m

    = 5.4/2 C mm

    1( KONTRO) TEGANGAN

    PPBBi 1'%4

    = 2132.354

    5.2

    = 4.

    = /3.3

    = /3.3 E i6in

    11 KONTRO) )ENDUTAN

    Be*!a+a*ka PPBBi 1'%4, Ha- 1(6 Pa+a- 15.1 A/at 1

    % = 21 pa

    1,25.& = 1. 0m

    + =

    = 4./ kg,m

    = .4/ kg,0m

    + =

    = 45.4 kg,m= .454 kg,0m

    ! =

    = 122./ kg

    = 1.22/ kg,0m

    ! =

    = . kg= . kg,0m

    Me$0it"$ -e!"ta $*!i$

    = 5 B 134 % . % 4 % . %

    = 5 .4/ 25B

    34 21 4/

    =.13

    14152.32B

    12/

    kg,0m2

    ma(i6in) =

    >D&

    'os ?

    >D&

    Sin ?

    >&&

    'os ?

    >&&

    Sin ?

    + . &FPx . L

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    = .13 1.1 B

    = .211 B .1

    = .21 0m

    = 5 B 134 % . % 4 % . %

    = 5 .454 533333333.33333B

    34 21 //.2

    =.13

    345/.434/1B

    232

    = .13 1.1 B

    = .242 B .1

    = .24 0m

    +e0i$$a 2

    = .45 B .

    = .15

    = .32 0m

    aka 2

    = .32 0m E :6in = 1.

    + . &,3F ! . &,3

    = HI B I

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    PPIUG 1'%3

    TABE) BAA

    B

    B PPBBi 1'%4

    PPIUG 1'%3

    )RD 0a- 4

    25 1.22

    25 1.22

    x

    y

    px

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    Akibat Beba Mati

    .1/ 4

    .54 1

    .1/ 4

    .54 4

    4

    1

    Akibat Beba Mati

    .54 1.3333333

    .54 1.

    .54 1.3333333

    .54 1.3333333

    >&& B . > 1 U =

    qy

    4.5 mM

    D

    Dx ma

    41,57

    2 Mx m

    15,59

    22.25

    qx

    4.5 mM

    D

    Dx

    14

    2 M

    2

    22.25

    p

    yx

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    B 14.4 2 U =

    3 U =

    U =

    >&& 4 U =

    5 U =

    U =

    B 5.4/

    1/.

    B 2/2./3

    = 1 HARUS DI CEK OK

    1 1.22/ 4

    4 21 4/

    .235/.251432

    12/

    kg,0m2

    kg,0m215.00

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    .2 .

    1 . 21333333.3333333

    4 21 //.2

    .21354445./32335

    232

    .2 .1

    HARUS DI CEK OK0m

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    Akibat Beba Hi!"#

    Akibat Beba Hi!"# Akibat Be

    Kombinasi beban Arah x Arah y

    1.4 D = 127.196311 14.13

    =

    g

    x =

    kgm

    4.5

    py

    M

    D

    0.17

    0.34

    0.68 p

    Mpx max =

    17,02 kgm

    Dpx max =

    34,05 kg

    max =

    ,31 kg

    max =

    4,78 kgm

    4.5

    px

    M

    D

    0.51

    2.05

    4,10 p

    Mpx max =

    51,07 kgm

    Dpx max =

    200,48 kg

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    1.2 D + 0.5 L = 152.043642 26.4533452

    1.2 D + 1.6 L = 246.683754 58.0000492

    1.2 D + 1.6 L + 0.8 = 261.323754 58.0000492

    1.2 D + 1.3 + 0.5 L = 175.833642 26.4533452

    0.9 D + 1.3 = 193.616462 46.3679191

    0.9 D - 1.3 = -30.0783483 -28.1970176

    tegangan tekan max =-637,38 kg/cm2

    7.50 tegangan tarik max =

    +637,38 kg/cm2

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    a A$i

    qangin tiup

    4.5 mM

    D

    Dx tiup max

    = 34,05 kg

    2 Mx tiup max =

    17,02 kgm

    22,42

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    PERHITUNGAN BATANG TARIK TREKSTANG8

    1 REAKSI PEMBEBANAN KE ARAH SUMBU X

    "@ beban mati = 12/.5 kg

    "@ beban ;idup = 245.5 kg

    "@ beban angin = 1.3 kg B

    "@t = 35.5 kg

    9 KOMBINASI PEMBEBANAN

    " = 1.2 >D& B 1. >&& B . >

    = 155. B 3/3.1/ B 14.4

    = 53.54 kg

    3 DIMENSI TREKSTANG

    = "

    A

    A = "

    = 35.5

    14

    = .2

    d = 4 A

    = 4 .23.14

    = .5 0m bu8atkan

    K . 0m = mm

    0m2

    A = 1,4 d2

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    1 Pebebaa t*ek+ta$

    !ma = + .& B ! n =

    n

    dengan

    + = beban merata ara; & = 6arak antar kuda - kuda

    n = 6um8a; pembagian trekstang

    ! = beban ;idup

    maka

    !ma = + .& B !

    n

    = 25/.51 B .4

    3

    = .524 B .4

    = 12.54 kg

    2 Dimensi trekstang

    ,

    = 1.22 , 3

    = .4

    = ar0an .41

    = 33.2

    = .55 = .31

    aka " = n . !ma

    = 3 12.54

    .55

    = /2/./5 kg

    &uas dimensi trekstang

    = 14

    A = "

    = /2/.//

    14

    = .4

    d = 4 A

    = ./ dibu8atkan

    tan ? =

    ?o

    sin ? 0os ?

    sin ?

    = " , A

    ?

    A = 1,4 d2

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    = 1.( : ; 1(

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    3 b;

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    PERHITUNGAN KUDA < KUDA

    1 DATA PEMBEBANAN

    entang kuda2 = 1.5 m

    Jarak kuda2 (&k) = 4 m

    Jarak gording = 2 m

    Sudut kemiringan atap = 35

    !enutup atap = Genteng

    erat penutup atap = 5 PPIUG 1'%3

    eban gording = 11 kg,m TABE) BAA

    B37

    $ = 24 pa SNI 9((9

    $u = 3 pa

    = 21

    9 MENGHITUNG BEBAN

    BEBAN MATI

    erat atap = 4 kg

    (+ &k & gording)

    erat gording = 44 kg

    (+ &k) B

    444 kg

    !enambung (17) = 44.4 kg B SNI 9((9

    +t 4.4 kg

    . ati ara; = 4. kg

    . ati ara; = 2.13 kg

    BEBAN HIDUP

    eban peker6a L a8at = 1 kg

    . Midup ara; = 1./2 kg

    . Midup ara; = 5.3 kg

    BEBAN ANGIN

    = 25 )RD 0a- 4

    9oe:sien angin tekan =

    = .3

    9oe:sien angin ;isap = -.4

    < tekan = koe tek. angin &k &.gording

    = .3 25

    o

    kg,m2

    kg,0m2

    ekanan angin , m2 kg,m2

    .2 ? - .4

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    = kg

    < ;isap = koe tek. angin &k &.gording

    = -.4 25

    = - kg

    . Angin ara; = 4/.15 kg

    . Angin ara; = 34.41 kg

    AC A"AM N A"AM O Kbia+i #ebebaa

    . A% 4. 2.13 Ara; = 5.4 =

    . M%DP! 1./2 5.3 Ara; = 455.4 =

    . ACG%C 4/.15 34.41

    Pe*0it"$a #a=a$ beta$ k"!a < k"!a

    Gambar Auto0ad

    Tabe- #a=a$ bata$ k"!a < k"!a

    N. A 8 H 8 > 8 D 8

    1 1. 1.5 .5 2.12

    2 1. 1.5 1.5 2.

    3 1. 1.5 2.25 2.

    4 1. 1.5 1.5 2.12

    5 1. 1.5 .5

    1. 1.5

    Co atang arik atang ekan

    A1

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    A2

    A3

    A4

    A5

    A

    M1

    M2M3

    M4

    M5

    M

    Q1

    Q2

    Q3

    Q4

    Q5

    D1D2

    D3

    D4

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    4 2

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    4 2

    kg

    4 kg

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    Be*at +e!i*i k"!a < k"!a !itak+i* ) ? 5 8

    6arak kuda2 ma = 2 kg

    = 54.25 kg

    = 2.13 kg

    Be*at +e!i*i #e"t"# ata# $ete$8

    simpu8 tenga; menerima beban

    = 4 kg

    simpu8 pun0ak menerima beban

    = 4/ kg

    simpu8 tepi menerima beban

    = 2 kg

    Beba akibat $*!i$

    tiap simpu8 menerima beban= 44

    tiap simpu8 menerima beban

    =

    Beba be*$"a

    tiap simpu8 menerima beban

    = 1 kg

    Beba tia# +i#"- akibat beba ati !a be*$"a

    !2 = !3 = !5 = !

    5/.25 kg = kg

    !1 = !

    415.13 kg = 45 kg

    !4

    .25 kg = kg

    tiap simpu8 tenga;menerima beban

    tiap simpu8 tepimenerima beban