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• 7/25/2019 Mathcad - Aplicatia 1

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Aplicatia 1

Dimensionare : DL avand Cg-F amonte.

1. Configuratie, date de baza :

- Incarcatura hidraulica raportata la proiectia orizontala a ML: iH 1 m

3

h m2

- Viteza medie in modul : V 3mm

s

- Nr.Reynolds al miscarii : Rey 50.0

2. Se adopta ML din placi PP conform fisei anexate : tip ML FS 41.50 avandcaracteristici :

e 44mm:= 60deg:= h 15mm:=

Ased 11m

2

m3

:=

3. Volumul de ML necesar :

As Ased ML= iH.0.9

1

m3

h m2

:=

AsQ

iH.

1800

1620

m

2=:=

ML

As

Ased

163.64

147.27

m

3=:=

Q 450l

s:=

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4. Configuratie DL :- bazin de forma patrata- dotari cu sisteme constructive de fixare nodul, jgheaburi de colectare

Se adopta configuratia din schema urmatoare :

15 1.00 15 1.00 15 1.00 15

20

1.

25

25

20

30

2

3

4

1

1.

25

30

25

20

2

1

3

60

1.Modul lamelar

2.Jgheaburi colectoare apa

decantata (inox)

3.Galerii distributie apa floculata

4.Grinzi pereti b.a. 15 x 1500mm

20

- siruri de module lamelare amplasate intre grinzi :

latime b 1.0m:=

n b iM hM ML=

hM 1.25m:=

n 11:=

iM

ML

n b hM

11.901

10.711

m=:=

- 11 randuri de modul b = 1.0m , hM= 1.25 m

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Latimea DL :

ngrinzi

n 1 10=:= bgrinda

150mm:=

B n b ngrinzibgrinda+ 12.5 m=:=

Lungimea (din conditia forma patratica) :

L B 12.5 m=:=

Volumul efectiv de ML :

n 11= b 1 m=

hM 1.25 m= L 12.5 m=

VML n b hM L 171.875 m3

=:=

Aria de limpezire :

Ased 11m

2

m3

:=

AL AsedVML 1.891 103

m2

=:=

Incarcarea hidraulica efectiva :

Q 450 l

s=

iHQ

AL

0.857 m

h=:= < 1 m/h

Decantorulva avea 12.5 m x 12.5 m si va fi prevazut cu :

- 11 randuri cu b = 1.0m , L = 12.5m , hM= 1.25m , = 60o

- 10 grinzi perete 15 x 12.5 cm cu hg= 1.25m

- 10 jgheaburi fixate pe grinzi bj= 15cm, hj = 23cm

- 10 galerii distributie Apa Floculata fixate de grinzi : 15x23cm

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5.

60

1.

00

15

1.

00

15

1.

00

15

1.

00

15

1.

00

5.60

- 10 jgheaburi bj 15cm:= hj 23cm:= iR 1%:=

Aj bj hj 0.035m2

=:= nj1

90:=

Pj bj 2 hj+ 0.61 m=:=

Rh

Aj

Pj

0.057m=:=

Cj1

nj

Rh

m

16

55.76=:=

qcap AjCjRh

miR

m

s 45.75

l

s=:= >

Q

n 1 45

l

s= / jgheab

- jgheburile sunt prevazute cu deversori triunghiulari :

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100

50

90

Galerii distributie apa floculata

15 x 23 cm fixata la partea inferioara a grinzilor perete

5.60

11

15

2

0

debit distribuit pe galerie

qdist

Q 10% Q+

n 1 49.5

l

s=:=

debit calcul sistem cu debit uniform distribuit qcqdist

224.75

l

s=:=

Ag bjhj 0.035m2

=:= L 12.5 m=

vg

qc

Ag

0.717m

s=:=

hr i L= ---> hr

vgs

m

2

m

Cj2

RhL 0.0366 m=:=

pentru realizarea distributiei uniforme : horificiu 10 hr>

Aleg orificiu 12mm 0.6:=

Aorificiu

40.012

2 m

2113.097 mm

2=:=

horificiu 0.1m:=

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qorificiu Aorificiu 2 g horificiu 0.095l

s=:=

Nrorificii

qdist

qorificiu

520.87=:= ---> 522 orificii

522

2261= orificii 12mm la 4.78cm pe fiecare latura

Concentrator de namol

CN4.

00

2.2

0

L 12.5 m= B 12.5 m=

VCN L B 4.0 m 625 m3

=:=

Cantitatea de namol acumulata / zi :

m3

:= SU

KN Q CAB CAD( ) 19440kg

zi=:= SU

N 1040:= CNC 0.03kg

zi:=

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VN

KN

CNC N 623.08=:= > 625 m3

S-a considerat concentratia in suspensii a apei brute 500 gSU/m

3

;Namolul in exces se va elimina din CN : 1 data / 12 h.

Recircularea namolului

Pentru realizarea unui continut in suspensii optim in floculator (

>1500gSU/m3) se va prelua namolul concentrat din CN si se va introduce in R

QNR 10% Q 162

m3

h=:=

1+1EP cu turatie variabila q = 30 - 70 m3/h , Hp= 5m , P=2kW.

Pompele se vor amplasa in galeria inferioara intre Floculator siConcentratorul de namol : bgal= 1.5m , Hg= 4.0m , conducta de refulare PEID

Dn 150mm.

Coagulare - Floculare

Q 27 m

3

min=

1. Amestec si reactie rapida

tR

1

2

1:=

Vnec. Q t R 27

54

m

3=:= Aleg Vnec 54m

3:=

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3.0

0

2.00

NR

AB

Aria = 3m2... 4m2

K 30m0.5

s0.5

kg0.5

:=

PGRR

K

2

Vnec 15000 W=:= ---> P 15kW:=

Aleg 1 El.Agit de 15kW

2. Floculator

tF. 15min:= GF 100s 1

:=

VF Q t F. 405 m3

=:= ha 3 m=

AF

VF

3

1

m 135 m

2=:= ---> 12m x 12.5m

VeF 12m 12.5 m ha 450 m3

=:=

tF

VeF

Q16.667 min=:=

PF

GF

K

2

VeF 5000 W=:= 5000

12416.67=

Aleg 12 El.Agit x 450W ( 2 pe fiecare culoar )

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NRAB

2.

00

2.00 2.00 2.00 2.00

6.00

5.

60

Given

0.165 0.41 12.5 2 9.81 hd

3

2=

Find hd( ) 0.037522668394505493359

hd 0.0375m 3.75 cm=:=

11

CF

CCD CD = cota apei in DLhd

galerii distributie AF

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CF CCD 3.75cm=

3.75cm

5

7

cm+ 8.8

10.8

cm=

CD CCD11

12

cm:=

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h hr:=

zi day:=