L5 Zener Effect,Voltage Regulator,Half Wave Rectifier

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    DC Analysis Representation of diode into three models

    Ideal case model 1 with V= 0

    Piecewise linear model 2 with Vhas a given value

    Piecewise linear model 3 with Vand forward resistance, rf

    Recall-Lecture 4

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    Diode AC equivalent model

    During analysis, must perform DC analysis first tocalculate ID in order to obtain rd

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    DC ANALYSIS

    DIODE = MODEL 1 ,2

    OR 3

    CALCULATE DC

    CURRENT, ID

    CALCULATE

    rd

    AC ANALYSIS

    DIODE = RESISTOR,

    rd

    CALCULATE AC

    CURRENT, id

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    Electronics ECE 1231

    BREAKDOWN VOLTAGE

    The breakdown voltage is a function of the doping concentrations

    in the n- and p-region of the pn junction.

    Large doping concentrations result in smaller break-down voltage.

    Reverse biased voltage ET

    The electric field may become large enough for the covalent bond

    to break, causing electron-hole pairs to be created.

    So, electrons from p-type are swept to n-region by the electric

    field and holes from the n-type are swept to the p-region

    The movement will create reverse biased current known as the

    Zener Effect .

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    Electronics ECE 1231

    Zener Effect and Zener Diode

    The applied reverse biased voltage cannot increase without limit since at

    some point breakdown occurs causing current to increase rapidly.

    The voltage at that point is known as the breakdown voltage, VZ

    Diodes are fabricated with a specifically design breakdown voltage and are

    designed to operate in the breakdown region are called Zener diodes. Circuit

    symbol of the Zener diode:

    Such a diode can be used as a constant-voltage

    reference in a circuit.

    The large current that may exist at breakdowncan cause heating effects and catastrophic failure

    of the diode due to the large power dissipated in

    the device.

    Diodes can be operated in the breakdown region

    by limiting the current to a value within the

    capacities of the device.

    NOTE:When a Zener diode is reverse-

    biased, it acts at the breakdown region,

    when it is forward biased, it acts like a

    normal PN junction diode

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    Electronics ECE 1231

    Avalanche Effect

    While these carriers crossing the space-charge

    region, they also gain enough kinetic energy.

    Hence, during collision with other atoms, covalent

    bond is broken and more electron-holes pairs are

    created, and they contribute to the collision process

    as well. Refer to figure below

    e

    he

    atom

    e

    h

    atom

    Electron with

    high kineticenergy

    e

    h

    atom

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    Chapter 3

    Diode Circuits

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    VoltageRegulator

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    A voltage regulator supplies constant voltage to a load.

    Voltage Regulator - Zener Diode

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    The breakdown voltage of a Zener

    diode is nearly constant over a wide

    range of reverse-bias currents.

    This make the Zener diode useful ina voltage regulator, or a constant-

    voltage reference circuit.

    1. The zener diode holds

    the voltage constant

    regardless of the current

    2. The load

    resistor

    sees a

    constantvoltage

    regardless

    of the

    current

    3. The remainder

    of VPSdrops

    across Ri

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    A Zener diode is connected in a voltage regulator circuit. It is given that VPS

    = 20V, the Zener

    voltage, VZ= 10V, R

    i= 222 and P

    Z(max)= 400 mW.

    a. Determine the values of IL, I

    Zand IIif RL= 380 .

    b. Determine the value of RLthat will establish PZ(max)= 400 mW in the diode.

    Example

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    For proper function the circuit the following conditions must be satisfied the following

    conditions.

    1. The power dissipation in the Zener diode is less than the rated value

    2. When the power supply is a minimum, VPS(min), there must be minimum current in

    the zener diode IZ(min), hence the load current is a maximum, IL(max),

    3. When the power supply is a maximum, VPS(max), the current in the diode is a

    maximum, IZ(max), hence the load current is a minimum, IL(min)

    AND Or, we can write

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    For general thumb of rule for design this circuit is, so from the last Equation

    Maximum power dispassion in the Zener diode is

    EXAMPLE 1 (Example 3.3 from textbook)

    Design a Zener diode voltage regulator circuit as shown

    in Figure . Consider voltage regulator is used to powerthe cell phone at 2.5 V from the lithium ion battery,

    which voltage may vary between 3 and 3.6 V. The

    current in the phone will vary 0 (off) to 100 mA(when

    talking).

    simple Zener diode voltage

    regulator circuit

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    Solution:

    The stabilized voltage VL= 2.5 V, so the Zener diode voltage must be VZ= 2.5 V. The

    maximum Zener diode current is

    The maximum power dispassion in the Zener diode is

    The value of the current limiting resistance is

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    Example 2

    Range of VPS: 10V14V

    RL= 20100

    VZ= 5.6VFind value of Riand calculate the maximum power rating of the diode

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    Rectifier

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    Rectifier Circuits

    A dc power supply is required to bias all electronic circuits.

    A diode rectifier forms the first stage of a dc power supply.

    Diagram of an Electronic Power Supply

    Rectificationis the process of converting an alternating(ac)

    voltage into one that is limited to one polarity.

    Rectification is classified as half-waveor full-waverectifier.

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    Rectifier Parameters

    Relationship between the number of turns of a

    step-down transformer and the input/output

    voltages

    The peak inverse voltage (PIV) of the diode is the peak value of the voltage

    that a diode can withstand when it is reversed biased

    Duty Cycle: The fraction of the wave cycleover which the diode is conducting.

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    i

    vD

    V

    V

    Equation of VOand current when diode is conducting

    Vs< V, diode off, open circuit, no

    current flow,Vo = 0V

    Vs> V, diode conducts, current flows,

    Vo = Vs

    V

    Vp

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    Vs< V, diode off, open circuit, no current flow,Vo = 0V

    Vs> V, diode conducts,current flows and Vo = Vs V

    Vs = Vpsin t

    Notice that the

    peak voltage of Vo

    is lower

    Vs >V

    V

    Vp